In how many ways can you give three baseball tickets, three soccer tickets, and three opera tickets, all general admission, to nine friends?

The area of the circle r = 6sin(θ) in polar coordinates is 9π square units.

To calculate the area of the circle r = 6sin(θ) in polar coordinates, we can integrate the expression for the area of an infinitesimal sector of the circle, which is:

dA = (1/2) [tex]r^2[/tex] dθ

Integrating this expression over the limits of θ from 0 to π, we obtain:

A = ∫₀[tex]^\pi[/tex] (1/2) [tex]r^2[/tex] dθ

Substituting r = 6sin(θ), we get:

A = ∫₀[tex]^\pi[/tex] (1/2) (6sin(θ)[tex])^2[/tex]dθ

Simplifying, we have:

A = 18 ∫₀[tex]^\pi[/tex] [tex]sin^2[/tex] (θ) dθ

Using the identity [tex]sin^2[/tex](θ) = (1/2) - (1/2)cos(2θ), we can rewrite the integral as:

A = 18 ∫₀[tex]^\pi[/tex] [(1/2) - (1/2)cos(2θ)] dθ

Evaluating this integral, we get:

A = 18 [(θ/2) - (1/4)sin(2θ)] from 0 to π

Substituting the limits of integration, we get:

A = 18 [(π/2) - (1/4)sin(2π)] - 18 [(0/2) - (1/4)sin(2(0))]

Simplifying, we have:

A = 18 [(π/2) - 0] - 18 [(0) - 0]

A = 18 (π/2)

Therefore, the area of the circle r = 6sin(θ) in polar coordinates is 9π square units.

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If he wants to maintain the same level of confidence (95%), his new sample size should be 400. This means that his margin of error will be plus or minus 9. It's important to note that the margin of error is affected by both the sample size and the level of confidence.

To cut the margin of error in half, Bob should increase his sample size. The margin of error is related to the sample size by the formula:

Margin of Error = Z * (Standard Deviation / sqrt(Sample Size))

Here, Z represents the Z-score associated with the desired confidence level (95% in this case). To halve the margin of error, the sample size should be increased by a factor of 4. This is because when you divide the margin of error by 2, you need to compensate by multiplying the denominator by 4 to maintain equality.

So, if Bob's current sample size is 100, he should increase it to:

New Sample Size = 100 * 4 = 400

By using a sample size of 400, Bob can cut his margin of error in half while maintaining the same 95% confidence level.

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Answer:the answer is 89 for f(x) = x. g(x) if g(x) = f(x) + 7?

Ravi used a total of 51 yards of fabric for the shirt, 38 yards of green fabric, and 13 yards of red fabric.

Ravi used 38 yards of green fabric and 13 yards of red fabric to make a shirt. To find out the total yards of fabric used, you can simply add the two amounts together.
38 yards (green fabric) + 13 yards (red fabric) = 51 yards of fabric So, Ravi used a total of 51 yards of fabric for his shirt, Ravi made a shirt using 38 yards of green fabric and 13 yards of red fabric. how many yards of fabric

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If A fair coin is tossed 27 times, in 134,217,349 outcomes do at most 25 heads occur. So, correct option is D.

To solve this problem, we need to use the binomial distribution, which gives us the probability of getting a certain number of successes (heads in this case) in a fixed number of independent trials (coin tosses).

Let p be the probability of getting a head in one toss, which is 1/2 for a fair coin. Then, the probability of getting k heads in n tosses is given by the binomial probability formula:

P(k) = (n choose k) * p^k * (1-p)^(n-k)

where (n choose k) is the binomial coefficient, which represents the number of ways to choose k items out of n without regard to order, and is given by:

(n choose k) = n! / (k! * (n-k)!)

Now, to find the number of outcomes where at most 25 heads occur, we need to add up the probabilities for k = 0, 1, 2, ..., 25:

P(at most 25 heads) = P(0) + P(1) + P(2) + ... + P(25)

We can calculate each of these probabilities using the binomial probability formula, and then add them up to get the total probability.

Alternatively, we can use the cumulative distribution function (CDF) of the binomial distribution, which gives us the probability of getting k or fewer heads in n tosses.

Then, we can subtract the probability of getting exactly 26 or 27 heads from this total to get the probability of getting at most 25 heads. The formula for the binomial CDF is:

F(k) = sum(i=0 to k) [(n choose i) * p^i * (1-p)^(n-i)]

Using a calculator, we can find that the number of outcomes where at most 25 heads occur is approximately 134,217,349, which is option (d).

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The given argument "all humans are 2 legged, chirpy is 2 legged, therefore chirpy is a human" is not valid because there could be other creatures, apart from humans, that are also 2 legged.

This is a logical fallacy where one assumes that if a condition is true, then the consequent must also be true. However, this does not necessarily hold true because there could be multiple reasons for the consequent to be true.

In this case, the argument assumes that because all humans are 2 legged and chirpy is 2 legged, chirpy must be a human. However, this argument overlooks the fact that there could be other creatures, apart from humans, that are also 2 legged.

For instance, birds, kangaroos, and even some primates are 2 legged but are not human. Hence, the argument fails to establish a conclusive relationship between the premises and the conclusion.

To prove that an argument is valid, we must ensure that the conclusion necessarily follows from the premises. In this case, the argument does not meet this criterion. Therefore, it is not valid. It is essential to exercise caution when making assumptions, and we must consider all possible scenarios before making a conclusion.

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Complete question is:

Determine whether the following argument is valid and explain how you know.

All humans are 2 legged, chirpy is 2 legged, therefore chirpy is a human

Answer:

[tex]\huge\boxed{\sf c = 8\ cm}[/tex]

Step-by-step explanation:

According to intersecting chords theorem, if two chords intersect, then the product of the two parts of one chords is equal to the product of others.

So,

11 × c = 10 × 8.8

11c = 88

c = 88/11

[tex]\rule[225]{225}{2}[/tex]

Answer:

Sure, I can help you with that. To make a graph, you need to follow these steps:

- Select a graph or diagram template that suits your data and purpose. In this case, you can use a line graph or a scatter plot to show the relationship between the number of shirts and the total cost.

- Add your data or information to the template. You can type in the numbers manually or upload an existing spreadsheet file.

- Add icons or illustrations from the library if you want to make your graph more appealing and informative.

- Customize your graph by changing the colors, fonts, labels, axes, legends, titles, and other elements. You can also apply different styles and themes to your graph.

- Download, share or print your graph as you wish. You can also embed it in other documents or presentations.

Here is an example of a line graph that shows the total cost of buying shirts for 0 through 15 shirts:

```markdown

# Total Cost of Buying Shirts

```code

| Number of Shirts | Total Cost ($) |

|------------------|----------------|

| 0                | 0              |

| 1                | 10             |

| 2                | 20             |

| 3                | 30             |

| 4                | 40             |

| 5                | 50             |

| 6                | 60             |

| 7                | 70             |

| 8                | 80             |

| 9                | 90             |

| 10               | 100            |

| 11               | 99             |

| 12               | 108            |

| 13               | 117            |

| 14               | 126            |

| 15               | 135            |

```

$$

y = \begin{cases}

10x & \text{if } x \leq 10 \\

9x + (10 - x) & \text{if } x > 10

\end{cases}

$$

a line graph with number of shirts on the x-axis and total cost on the y-axis

```

Answer:

-2

Step-by-step explanation:

-6 - (-5 + 3) / 2

(-6 — -2) /2

-4/2 = -2

AR(1) model has a stationary, Zero-mean process with exponentially decaying autocorrelation and a variance that depends on the variance of the noise term. The variance of the model is [tex]\sigma ^2e / 0.36.[/tex]

The AR(1) model given is:

yt = 0.8yt-1 + et

where {et: t = 1, 2, ...} is an i.i.d. sequence with a mean of zero and variance of σ^2e.

To better understand this model, we can look at its properties:

Stationarity: For this AR(1) model to be stationary, we require that the absolute value of the AR(1) coefficient, 0.8, be less than 1. Since 0.8 < 1, the model is stationary.

γk = Cov(yt, yt-k)

Using the formula for the covariance of an AR(1) model, we have[tex]γk = (0.8)^k * σ^2e / (1 - (0.8)^2)[/tex]

Thus, the ACF for this model decays exponentially with lag k, indicating that past values of y are highly correlated with each other.

Mean: Since the model is stationary, we can calculate its mean by setting yt = yt-1 = ... = y0 = μ, and solving for μ:

μ = 0.8μ

Solving for μ, we get μ = 0, indicating that the mean of the model is zero.

Variance: We can calculate the variance of the model by using the formula for the variance of an AR(1) model:

[tex]Var(yt) = \sigma ^2e / (1 - (0.8)^2)[/tex]

Thus, the variance of the model is σ^2e / 0.36.

Overall, this AR(1) model has a stationary, zero-mean process with exponentially decaying autocorrelation and a variance that depends on the variance of the noise term.

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The total number of votes cast in the city was 7864.

Given that there were 2949 no votes, which corresponds to 3 parts of the ratio.

Assume that the total number of votes as x. According to the given information, the ratio of yes votes to no votes is 5 to 3. This means that for every 5 yes votes, there are 3 no votes.

Set up the equation as given:

3 parts = 2949 votes

1 part = 2949 votes / 3

1 part = 983 votes

Now, since the ratio of yes votes to no votes is 5 to 3,  a total of 5 + 3 = 8 parts.

Total number of votes = 8 parts × 983 votes per part

Total number of votes = 7864 votes

Therefore, the total number of votes cast was 7864.

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The given initial value problem represents a second-order linear homogeneous differential equation, where coefficient of derivative is 1 and the coefficient of first derivative is 0. current I(t) in LC series as a function of time t circuit is = [tex](-8/19)cos(19t) + (27/19)sin(19t) for 0 ≤ t ≤ 2π.[/tex]

Thus, the characteristic equation of the differential equation is given by [tex]λ^2 + 361 = 0[/tex]. Solving the characteristic equation, we get two complex roots [tex]λ = ±19i.[/tex]

Therefore, the general solution of the differential equation is given by I(t) = [tex]c1cos(19t) + c2sin(19t)[/tex], where c1 and c2 are constants determined by the initial conditions. Differentiating the general solution with respect to t, we get [tex]I'(t) = -19c1sin(19t) + 19c2cos(19t).[/tex]

Using the initial condition I'(0) = 27, we get 27 = 19c2. Therefore, c2 = 27/19. Now, to determine c1, we need to use the initial condition I(0) = 1 and the given function g(t).

When [tex]0 ≤ t ≤ 2π, g(t) = 135sin(3t)[/tex]. Therefore, we have[tex]I(0) = c1cos(0) + c2sin(0)[/tex] = c1 = 1 - c2 = 1 - 27/19 = -8/19. Thus, the current I(t) in LC series circuit is given by [tex]I(t) = (-8/19)cos(19t) + (27/19)sin(19t) for 0 ≤ t ≤ 2π.[/tex]

When t > 2π, g(t) = 0 and the current will continue to oscillate with the same frequency and amplitude, but with different initial conditions determined by the values of I(2π) and I'(2π).

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P(X<=16) = 1 - P(X>16)

= 1 - (P(X=17) + P(X=18) + ... + P(X=20))

= 0.998

This is a binomial distribution problem, where we have a fixed number of trials (20 patients), each trial can have one of two outcomes (recover or not recover), and the Probability of success (recovering) is 0.8. We can use the binomial probability formula to solve each part of the problem:

P(X=k) = (n choose k) * p^k * (1-p)^(n-k)

where:

P(X=k) is the probability of getting k successes

n is the total number of trials

k is the number of successes we want to find the probability for

p is the probability of success for each trial

(1-p) is the probability of failure for each trial

(n choose k) is the binomial coefficient, which is the number of ways to choose k successes out of n trials.

Using this formula, we can solve each part of the problem:

Probability that exactly 14 recover:

P(X=14) = (20 choose 14) * (0.8)^14 * (0.2)^6

= 0.214

Probability that at least 14 recover:

P(X>=14) = P(X=14) + P(X=15) + P(X=16) + ... + P(X=20)

To calculate this, we can use a binomial cumulative distribution table or calculator, or we can use the complement rule:

P(X>=14) = 1 - P(X<14)

= 1 - (P(X=0) + P(X=1) + ... + P(X=13))

= 1 - ((20 choose 0) * (0.8)^0 * (0.2)^20 + (20 choose 1) * (0.8)^1 * (0.2)^19 + ... + (20 choose 13) * (0.8)^13 * (0.2)^7)

= 0.993

Probability that at least 14 but not more than 18 recover:

P(14<=X<=18) = P(X=14) + P(X=15) + ... + P(X=18)

To calculate this, we can use a binomial cumulative distribution table or calculator, or we can subtract the probabilities of getting fewer than 14 and more than 18:

P(14<=X<=18) = P(X>=14) - P(X>=19)

= 0.993 - (P(X=19) + P(X=20))

= 0.007

Probability that at most 16 recover:

P(X<=16) = P(X=0) + P(X=1) + ... + P(X=16)

To calculate this, we can use a binomial cumulative distribution table or calculator, or we can use the complement rule:

P(X<=16) = 1 - P(X>16)

= 1 - (P(X=17) + P(X=18) + ... + P(X=20))

= 0.998

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Answer:

The component form of the vector that translates the top - 1 ... 2. Translate rhombus EFGH 2 units to the left, 4 units down, and plot it.

Step-by-step explanation:

P.S i am emo

A basis for the subspace is {{1,0,-3/8}, {0,1,-3/8}}. This can be answered by the concept from Sets.

To find a basis of the subspace of R3 defined by the equation −3x1−3x2−8x3=0, we can first rearrange the equation as x3 = (-3/8)x1 - (3/8)x2.

Then we can rewrite the subspace as Span{{1,0,-3/8}, {0,1,-3/8}} since these two vectors span the subspace of solutions to the equation.

Therefore, a basis for the subspace is {{1,0,-3/8}, {0,1,-3/8}}.

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The particular solution is y = (5/2)t + 9/(5t+6) and this equation is separable since we can write it as:
dy/dt = 5/(5t+6)

Multiplying both sides by (5t+6) gives:
(5t+6)dy/dt = 5

Integrating both sides with respect to t gives:
∫(5t+6)dy = ∫5 dt

Simplifying the integrals gives:
(5/2)t^2 + 6t + C1 = 5t + C2

where C1 and C2 are constants of integration. Solving for y gives:
y = (5/2)t + (C2 - C1 - 6)/(5t+6)

To find the particular solution that satisfies the initial condition y(0) = 2, we substitute t = 0 and y = 2 into the equation above:
2 = (5/2)*0 + (C2 - C1 - 6)/(5*0+6)

Simplifying gives:
C2 - C1 - 6 = 15

Substituting this value of C2 - C1 into the equation for y gives the particular solution:
y = (5/2)t + 9/(5t+6)

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It will take (18,000 - Y) ÷ X minutes to drain the pool so that it holds less than Y gallons of water .

To solve this problem, we need to use a simple formula:

Time = Amount of Water ÷ Rate of Drain

We know that the amount of water in the pool is 18,000 gallons. We also know that the pump drains the pool at a certain rate, which is not given in the question. Therefore, we need to find out the rate of drain first.

Let's say that the pump drains the pool at a rate of X gallons per minute. This means that in one minute, X gallons of water will be drained from the pool. Therefore, the amount of water left in the pool after one minute of draining will be:

18,000 - X

Similarly, after two minutes of draining, the amount of water left in the pool will be:

18,000 - 2X

We can continue this pattern to find the amount of water left in the pool after any given number of minutes of draining.

Now, we need to find out how many minutes it will take to drain the pool so that it holds less than Y gallons of water. Let's say that Y is the given amount of water.

We can set up an equation using the formula above:

Time = Amount of Water ÷ Rate of Drain

Time = (18,000 - Y) ÷ X

Simplifying this equation, we get:

Time = 18,000 ÷ X - Y ÷ X

Time = (18,000 - Y) ÷ X

Therefore, it will take (18,000 - Y) ÷ X minutes to drain the pool so that it holds less than Y gallons of water.

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The measure of angle ZR is approximately 52.3 degrees to the nearest tenth of a degree.

In a triangle, the amount of the three inside points is 180 degrees. Utilizing the Law of Cosines, we can find the proportion of point R utilizing the given sides:

cos(R) = ([tex]4.3^2 + 6.5^2 - 8.9^2[/tex])/(2 * 4.3 * 6.5)

cos(R) = - 0.312

R = arc cos(- 0.312)

R = 107.5 degrees (adjusted to the closest tenth)

Accordingly, the proportion of point ZR is basically 180 - (90 + R) = 82.5 degrees (adjusted to the closest tenth).Utilizing the Law of Cosines, we can see that the biggest point in the triangle is at vertex S, which estimates roughly 119.5 degrees.

Point R is inverse the side of length 6.5 inches and point Z is inverse the side of length 4.3 inches. The point ZR is the contrast between 180 degrees and the amount of points Z and R. This computation provides us with a proportion of roughly 82.5 degrees.

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The complete question is:

In ARST, r = 4.3 inches, s = 8.9 inches and t=6.5 inches. Find the measure of ZR to the nearest 10th of a degree.

The expression that can be express in the form  (ax + b)(ax - b), are x² - 9 and  9x² - 4.

The expression that can be written in the form (ax + b)(ax - b), where a and b are integers can be represented as follows:

Therefore,

The expression should be able to be express in the form as follows:

(ax + b)(ax - b)

x² - 9 = (x - 3)(x + 3)

Therefore,

(x - 3)(x + 3) = x² + 3x - 3x - 9

x² + 3x - 3x - 9  = x² - 9

Therefore,

(x - 3)(x + 3) = x² - 9

9x² - 4 = (3x + 2)(3x - 2)

(3x + 2)(3x - 2) = 9x² - 6x + 6x - 4

9x² - 6x + 6x - 4 = 9x² - 4

Therefore, the expression are x² - 9 and  9x² - 4

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The measure of the inscribed angle in each case as required in the task content are;

It follows from the task content that the measure of the indicated angles are to be determined.

On this note, Recall that opposite angles of a cyclic quadrilateral are supplementary. In essence, it follows that the sum of the measures of opposite angles of cyclic quadrilaterals equals 180°.

Therefore;

1. m<P + 97° = 180°.

m<P = 83°.

2. m<R + 105° = 180°

m<R = 75°

and

m<S + 84° = 180°.

m<S = 96°.

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The function f(x) = 8 - x^3/8 is a polynomial function of degree 3.

To see why, note that a polynomial function is a function of the form f(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0, where n is a non-negative integer and a_n, a_{n-1}, ..., a_1, a_0 are constants (coefficients). In this case, we have:

f(x) = 8 - x^3/8

= 8 - (1/8)x^3

= 0x^4 + 0x^3 + (-1/8)x^2 + 0x + 8

Thus, we can write f(x) as a polynomial function with degree 3, since the highest power of x that appears is x^3.

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The perimeter of the cafe is calculated to be equal to 190 feet.

A plane shape is a two dimensional figure and its perimeter is the total distance around its outer boundary. It is the sum of the lengths of all its sides.

By careful observation, the cafe have the following lengths at:

left side = 15 + 7 + 16 = 38ft

right side = 3 + 15 + 28 = 46ft

top side = 40 + 3 + 15 = 58ft

bottom side = 48ft

The perimeter of the cafe = 38ft + 46ft + 58ft + 48ft

The perimeter of the cafe = 190 ft.

Therefore, the perimeter of the cafe is calculated to be equal to 190 feet.

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The stem-and-leaf plot is a useful way to visualize the distribution of the data and to identify any patterns or outliers. We can write the stems on the left-hand side of the plot and the leaves on the right-hand side. Stem and leaf plot : [tex]2 | 2 23 | 2 3 3 9 94 | 2 95 | 2 86 | 07 | 0[/tex]

To construct a stem-and-leaf plot for the given data, we can use the following steps: Identify the stems and leaves: We can use the tens digit as the stem and the ones digit as the leaf. Order the data: We can list the data in ascending order. Separate the data into stems and leaves:

The first column of the plot shows the stems, which are the tens digits of the data. The second column shows the leaves, which are the ones digits of the data.

For example, the first row of the plot shows that McGwire hit 22 home runs in one year. The second row shows that he hit 32, 33, and 39 home runs in different years, and so on.

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The integral with numerical integration is, 19.246.

To solve the integral numerically, we can use the trapezoidal rule or Simpson's rule. Here, we will use Simpson's rule. The formula for Simpson's rule for integrating a function f(x) over an interval [a,b] is:

[tex]\int_a^b f(x) dx[/tex] = (b-a)/6 * [f(a) + 4f((a+b)/2) + f(b)]

In this case, our integral is:

[tex]\int_0^{\pi/2} \int_2^5 r^3 sin(\theta) dr d\theta[/tex]

We can rewrite the integrand as a function of r and θ:

f(r,θ) = r³ sin(θ)

Using Simpson's rule, we can approximate the integral as:

[tex]\int_0^{\pi/2} \int_2^5 r^3 sin(\theta) dr d\theta[/tex]≈ (π/4)/3 * [(2³ sin(0) + 2³ sin(5))/2 + 4(3³ sin(π/4) + 3³ sin(3π/4))/2 + 2(5³ sin(π/2) + 5³ sin(π/2))/2]

Simplifying this expression, we get:

[tex]\int_0^{\pi/2} \int_2^5 r^3 sin(\theta) dr d\theta[/tex] ≈ 19.246

Therefore, the final answer is approximately 19.246.

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a) The probability that she gets all 5 serves in is 0.066 (rounded to three decimal places).
b) The probability she gets exactly 4 serves in is 0.278 (rounded to three decimal places).
c) The probability she gets at least 3 serves in is 0.822 (rounded to three decimal places).
d) The probability that there are no more than 4 serves in is 0.934 (rounded to three decimal places).

a) The probability that she gets all 5 serves in is (0.66)^5 = 0.196. (rounded to three decimal places as needed)
b) The probability she gets exactly 4 serves in is (5 choose 4) * (0.66)^4 * (0.34)^1 = 0.387. (rounded to three decimal places as needed)
c) The probability she gets at least 3 serves in is the sum of the probabilities of getting exactly 3, exactly 4, or all 5 serves in:
(5 choose 3) * (0.66)^3 * (0.34)^2 + (5 choose 4) * (0.66)^4 * (0.34)^1 + (0.66)^5 = 0.751. (rounded to three decimal places as needed)
d) The probability that there are no more than 4 serves in is the sum of the probabilities of getting 0, 1, 2, 3, or 4 serves in:
(0.34)^5 + 5 * (0.66)^1 * (0.34)^4 + (5 choose 2) * (0.66)^2 * (0.34)^3 + (5 choose 3) * (0.66)^3 * (0.34)^2 + (5 choose 4) * (0.66)^4 * (0.34)^1 = 0.921. (rounded to three decimal places as needed)
a) The probability that she gets all 5 serves in is 0.066 (rounded to three decimal places).
b) The probability she gets exactly 4 serves in is 0.278 (rounded to three decimal places).
c) The probability she gets at least 3 serves in is 0.822 (rounded to three decimal places).
d) The probability that there are no more than 4 serves in is 0.934 (rounded to three decimal places).

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The boat is approximately 4.12 miles from the marina and its direction is northeast. To head directly back to the marina, the boat must sail southwest.

To determine the boat's distance from the marina and the direction to head back, we'll use the Pythagorean theorem and some trigonometry.

After sailing 3 miles north and 2 miles northeast, the boat's total displacement is a right-angled triangle with legs of 3 miles (north) and 2√2 miles (east). The hypotenuse represents the straight-line distance back to the marina.

Using the Pythagorean theorem, distance^2 = (3^2) + (2√2)^2 = 9 + 8 = 17. So, the distance is √17 ≈ 4.12 miles.

To find the direction, we'll calculate the angle formed by the northward displacement and the straight-line path back to the marina. Using tangent, tan(angle) = (2√2)/3. The angle is arctan(2√2/3) ≈ 49.1 degrees.

So, the boat is approximately 4.12 miles from the marina and must sail 49.1 degrees west of south to head directly back to the marina.

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Answer:

D

Step-by-step explanation:

If we use a different method and divide the big number by the small ones (ex. 54÷45=1.2, 72÷60=1.2) to end up and find that the big triangle is scaled up by 1.2 then we can divide the bug triangles length by 1.2 to get the answer 50.

The best prediction about the scoops of ice cream the college will need, obtained using percentages is the option;

The college will have about 1,440 students who prefer ice cream

A percentage is a presentation of a number as a fraction of one hundred.

The preference for the sample of 25 students indicates;

81 likes Ice cream

9 like Candy

72 like Cake

36 like Pie

27 prefer Cookies

Based on the above numbers, the percentage of the students who prefer ice cream indicates;

(81/225) × 100 = 36%

The number of students that prefer ice cream in 4,000 is therefore;

36% × 4000 = 1440 students prefer ice cream

The statement that is the best prediction about the scoops of ice cream the college will need is the fourth statement;

Learn more on percentages here; https://brainly.com/question/11642822

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Answer:

All options

Step-by-step explanation:

To open a bank account you first need to know which type of account you will open, for example, correct account or savings account. The Social Security card is also required so that the bank has access to your financial history for analysis. Moreover, it is important to compare the different services offered by banks to reduce costs and open the account in the one that suits you best.