In order to avoid slipping in the shop, your footwear should have proper tread. The correct option is D.
What is slipping?Slipping is an action of falling or sliding down due to a lack of friction between the surfaces. This occurs when both surfaces coming into contact are smooth or frictionless.
During rainy seasons, due to rain everywhere the chances of slipping increase, the slippers slip on mud or water. Vehicles also slip down on roads.
To avoid slipping, wear proper shoes. The shoes that have a good grip are less to slip. The tires are given with tread, which increases the grip on the road. Tread-on shoes or slippers are also good. Wear tread full shoes. It can avoid slipping and accidents.
Thus, the correct option is D. Have proper tread.
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You are designing a critical component to be installed in a chemical plant, where corrosion resistance and high temperature performance are critical. As a result, a fully dense material is required. Because of the materials used in the system, the part can only be produced by powder metallurgy. Which powder metallurgy process would you use to produce a fully dense component?a) Hot Isostatic Pressing b) Sinter then Metal Injection Molding c) Cold Isostatic Pressing d) Press and Sinter Processes e) Metal Injection Molding
Answer:
Yes
Explanation:
Because your installing something
The powder metallurgy process that would be used to produce a fully dense component is Hot Isostatic Pressing. The correct option is a.
What is Hot Isostatic Pressing?Hot isostatic pressing is a process used to consolidate metal powder or to remove defects in solids such as pores, voids, and internal cracks, densifying the material to 100% of its theoretical density.
Hot Isostatic Pressing (HIP) is a process used to densify powders, cast and sintered parts, and steels and superalloys in a furnace at high pressure and temperatures ranging from 900 to 1250°C.
To provide isotropic properties and 100% densification, the gas pressure acts uniformly in all directions.
Hot Isostatic Pressing is the powder metallurgy process that would be used to create a fully dense component.
Thus, the correct option is a.
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Ideal gas helium flows through the inlet of an isentropic nozzle with a velocity of 25 m/s, and the exit flow is at 100 kPa, 300 K, and has a velocity of 250 m/s. a. Determine the inlet temperature. b. Determine the inlet pressure. c. Determine the area ratio between inlet and exit
Answer:
a. The inlet temperature is approximately 305.232 K
b. The inlet pressure is approximately 452.0108 kPa
c. The area ratio between the inlet and exit is approximately 2.2509
Explanation:
a. From the energy equation related to the question, we have;
[tex]C_p \cdot (T_i - T_e) = \dfrac{1}{2} \cdot \left (v_e^2 - v_1^2 \right)[/tex]
Where;
[tex]C_p[/tex] = The specific heat capacity for helium = 5.913 kJ/(kg·K)
[tex]T_i[/tex] = The inlet temperature
[tex]T_e[/tex] = The exit temperature = 300 K
[tex]v_i[/tex] = The inlet velocity = 25 m/s
[tex]v_e[/tex] = The exit velocity = 250 m/s
Therefore, we have;
[tex]T_i= \dfrac{ \dfrac{1}{2} \cdot \left (v_e^2 - v_1^2 \right)}{C_p} + T_e = \dfrac{ \dfrac{1}{2} \times \left (250^2 - 25^2 \right)}{5.913 \times 1000} + 300 \approx 305.232[/tex]
The inlet temperature = [tex]T_i[/tex] ≈ 305.232 K
b. From the following equation for the critical pressure, for helium, we have;
[tex]\dfrac{P_c}{P_i} = \left (\dfrac{2}{n + 1} \right ) ^{\dfrac{n}{n - 1} } = 0.487[/tex]
Where;
[tex]P_c[/tex] = The critical pressure = 2.26 atm for helim
[tex]P_i[/tex] = The inlet pressure
n = The polytropic constant
We have;
[tex]\dfrac{2.26 \ atm}{P_i} = 0.487[/tex]
[tex]\therefore P_i = \dfrac{2.26 \ atm}{0.487} \approx 4.641 \ atm[/tex]
The inlet pressure, [tex]P_i[/tex] ≈ 4.641 atm ≈ 452.0108 kPa
c. The inlet to exit pressure ratio is given as follows;
[tex]P_e = \dfrac{A_i \times T_e \times v_i}{A_e \times T_i \times v_e} \times P_i[/tex]
Therefore, we have;
[tex]\dfrac{A_i}{A_e} = \dfrac{P_e \times T_i \times v_e}{ T_e \times v_i \times P_i} = \dfrac{100 \times 305.232 \times 250}{ 300 \times 25 \times 452.0108} = 2.2509[/tex]
The area ratio between the inlet and exit, [tex]A_i/A_e[/tex] ≈ 2.2509.
Given these observed times (in minutes) for five elements of a job, determine the observed time (OT) for each element. Note: Some of the elements occur only periodically. (Round your answers to 2 decimal places.) CYCLE Element 1 2 3 4 5 6 1 1.2 1.2 1.2 1.2 1.2 - 2 - .7 - .7 - 0.7 3 2.2 2.2 2.2 3.2 2.2 2.2 4 3.2 - - 4.2 - - 5 0.7 .7 1.2 0.7 0.7 0.7
Answer:
Following are the solution to this question:
Explanation:
[tex]CYCLE[/tex]
[tex]Element \ \ \ \ \ \ 1\ \ \ \ \ \ 2 \ \ \ \ \ \ 3 \ \ \ \ \ \ 4 \ \ \ \ \ \ 5 \ \ \ \ \ \ 6 \ \ \ \ \ \ Average[/tex]
[tex]1 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 1.2 1.2 \ \ \ \ \ \ - \ \ \ \ \ \ 1.2\\\\[/tex]
[tex]2 \ \ \ \ \ \ - \ \ \ \ \ \ .7 \ \ \ \ \ \ - \ \ \ \ \ \ .7 \ \ \ \ \ \ - \ \ \ \ \ \ 0.7 \ \ \ \ \ \ 0.7 \\\\3 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 3.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.36\\\\[/tex]
[tex]4 \ \ \ \ \ \ 3.2 \ \ \ \ \ \ - \ \ \ \ \ \ - \ \ \ \ \ \ 4.2 \ \ \ \ \ \ - \ \ \ \ \ \ - \ \ \ \ \ \ 3.7\\\\5 \ \ \ \ \ \ 0.7 \ \ \ \ \ \ .7 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 0.7 \ \ \ \ \ \ 0.7\ \ \ \ \ \ 0.7\ \ \ \ \ \ 0.78[/tex]
[tex]Element \ \ \ \ \ \ \ \ \ \ \ \ Observed \ time \\\\1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1.2\\\\2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.7\\\\3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2.36\\\\4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3.7\\\\5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.78[/tex]
Electricians will sometimes call ______ "disconnects" or a "disconnecting means."
A) Two-pronged plugs
B) Electrical cords
C) Switches
D) Three-pronged plugs
(This is for my Automotive class)
Answer:
C.switches
Explanation:
If a machine guard is missing or needs repair, you should ______________.
A) Ignore it
B) Immediately remove that machine from service
C) Continue using the machine
D) Tell someone when you get around to it
(This is for my Automotive class)
Answer:B
Explanation:
For a soil, cohesion is 15 kN/sq.M, unit weight is 20 kN/cu.M and the factor of safety is 1.5 along with stability number of 0.05. The safe maximum height of slope is *
Answer:
10 m
Explanation:
The Soil Cohesion is the force that holds together molecules or like particles within a soil.
The unit weight of a soil mass is the ratio of the total weight of soil to the total volume of soil.
The stability number (Sn) is given by the formula:
[tex]S_n=\frac{C_m}{\gamma *H}[/tex]
Given that:
Cohesion = C = 15 kN/m², Factor of safety = FOS = 1.5, unit weight = γ = 20 kN/m³, H = maximum height, Sn = 0.05. Hence:
[tex]C_m=\frac{C}{FOS}\\\\S_n=\frac{C}{\gamma *FOS *H}\\\\H= \frac{C}{\gamma *FOS *S_n}\\\\Substituting:\\\\H=\frac{15}{20*1.5*0.05} \\\\H=10\ m[/tex]
calculate the touque developed by a motor whose spindle is rotating at 1500 rev/min and developing a power of 1.80W
Answer:
n=1500/60 to get , it into rev/sec
W=2πn = 50π
T=P*W=1.8 *50π=282.74 N.M
Explanation:
Rod of steel, 200 mm length reduces its diameter (50 mm) by turning by 2 mm with feed speed 25 mm/min. You are required to calculate the metal removal rate (MRR)
Answer:
125 cm³/min
Explanation:
The material rate of removal is usually given by the formula
Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where
Radial Depth of Cut = 25 mm
Axial depth of cut = 200 mm
Feed rate = 25 mm/min
On multiplying all together, we will then have
MRR = 25 mm * 200 mm * 25 mm/min
MRR = 125000 mm³/min
Or we convert it to cm³/min and have
MRR = 125000 mm³/min ÷ 1000
MRR = 125 cm³/min
discuss 7 habits of highly effective people and how important are ethics in today's society
Answer:
Explanation:
The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include
Being proactive
Starting anything with the end in mind
First things first
Always thinking towards a win-win situation
Seeking initially to understand, then going on to want to be understood
Synergize, and lastly
Growing
A heat exchanger is used to recover waste heat from an industrial furnace and use it to heat pressurized water. The heat exchanger consists of a tube bank with a square 10 x 10 array of thin-walled smooth tubes (total of 100 tubes). The tubes are aligned in-line with a transverse pitch, ST = 50 mm. Each tube is 25 mm in diameter and 4 m long. Water passes through each tube at a flow rate of 0.025 kg s-1, so the total flow rate through all 100 tubes is 2.5 kg s-1. The exhaust gas is in cross-flow over the tubes, with an upstream velocity of 5.0 m s-1 and total flow rate of 2.25 kg s-1. The exhaust gas has properties similar to air. The inlet temperatures of the water and exhaust gas are 300 K and 800 K, respectively. (a) What is the overall heat transfer coefficient between the water and the gas? (b) What are fluid outlet temperatures? As a first approximation, assume the water flow through the tubes is fully developed and turbulent, with an estimated bulk mean temperature of 350 K. Use a mean temperature of 600 K and properties of air to represent the exhaust gases. Please comment on the accuracy of these assumptions after you obtain your results, but you do not need to repeat any calculations.
Answer:
Explanation:
ok this is as test dont cheat i d
Steam enters a steady-flow adiabatic nozzle with a low inlet velocity (assume ~0 m/s) as a saturated vapor at 6 MPa and expands to 1.2 MPa.
a. Under what conditions is the velocity from this nozzle maximized?
b. Determine the maximum exit velocity of the steam, in m/s.
This happens as a result of a gain in kinetic energy at the expense of a decrease in enthalpy brought on by gas expansion as air passes through the diverging region of the nozzle.
What velocity from this adiabatic nozzle maximized?A nozzle is a tool used to change the characteristics of a fluid flow as it leaves a confined chamber or conduit, particularly to enhance velocity. The reciprocal of the nozzle length, pressure, and the square root of the nozzle diameter all increase air velocity.
A nozzle needs to be made to expand steam from 500 PA at 210 °C to 100 kPa at a rate of 0.1 kg/s. In order to reach critical or sonic conditions (i.e., choked flow) at its throat, the flow is accelerated when a nozzle is used.
Therefore, The steam's specific volume at the nozzle's exit is determined to be 1.4 m3/kg and its velocity at that point to be 700 m/s.
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A hubbing press has capasity of 175tons. If the workpice ia a copper alloy part with a 2in^2 projected area, what is the strongest alloy that can be hubbed?
Answer:
The answer is "[tex]\bold{175000 \ \frac{lbs}{in^2}}[/tex]"
Explanation:
The formula for the max value of UTS:
[tex]= \frac{F}{A} \\\\= \frac{175\ ton}{ 2 \ in^2} \\\\= \frac{350000}{2}\\\\[/tex]
Max UTS:
[tex]\to 175000 \ \frac{lbs}{in^2}[/tex]
Naomi needs to test an application that will be accessed by multiple users simultaneously. She is planning to use LoadRunner to test the performance of the application. How can a testing tool such as LoadRunner help her with performance testing?
A.
by using a large number of testers
B.
by increasing the number of test cases
C.
by automating your test cases
D.
by creating a number of virtual users
Give some examples of ethical issues that have an impact on the software engineering domain.
A gas stream (A) of 15.0 mol% H2, and the balance N2, is to be mixed with another gas stream
(B) containing 40.0 mol% H2, and the balance N2, to produce 100 kg/h of a 25 mol% H2, and the
balance N2 gas stream (C).
(a) Draw and fully label a flowchart of the mixing process.
(b) Calculate the average molecular weight of the product stream (C).
(c) Calculate the molar flow rates of the product stream (C) in kmol/h.
(d) Calculate the required flow rates of the feed mixtures A and B in kmol/h.
Answer:
A gas stream and other points are discussed below in details.
Explanation:
The method flow chart is displayed above.
B)Mole fraction of H2 in stream C=25%=0.25
Mole fraction of N2 in steams C=1-Mole fraction of H2=1-0.25=0.75
Average molecular weight of stream C=Mole fraction of H2*Molecular weight of H2+ Mole fraction of N2*Molecular weight of N2=0.25*2 kg/kmol+0.75*28 kg/kmol=21.5 kg/kmol
C) Mass flow rate of product C=100 kg/h
Molar flow rate of product C=Mass flow rate /Molecular weight=100 kg/h/21.5 kg/kmol=4.6512 kmol/h
D) Apply overall mole balance
Mole in=Mole out
Mole in=Mole of A+Mole of B=A+B
Let mole of A=A kmol/h
Mole of B=B kmol/h
Mole out=Mole of C stream=4.6512 kmol/h
A+B=4.6512 eq.1
Apply hydrogen mole balance
Mole of H2 in=Mole of H2 in A stream+ Mole of H2 in B stream=0.15 A+0.4 B
Mole of H2 out=Mole of H2 in C stream=0.25*4.6512=1.1628 kmol/h
1.1628 =0.15 A+0.4 B eq.2
Multiply eq.1 by 0.15
0.69768=0.15 A+0.15 B eq.3
Subtract eq.3 from eq.2
0.25 B=0.46512
B=1.86048 kmol/h
Substitute in eq1.
A=4.6512-1.86048=2.79042 kmol/h
Molar flow rate of A=2.79042 kmol/h
A molar flow rate of B=1.86048 kmol/h
"Well, this is a fine how-do-you-do. I come all the way over here to introduce my friends, R.W. and Melvin, to y'all and y'all actin' like y'all ain't got no manners at all. Yeah, ole R.W. and Melvin," he said, rolling the Simmses' names slowly off his tongue to bring to our attention that he had not bothered to place a "Mister" before either, "they been mighty fine friends to me. Better than any of y'all. Look, see here what they give me." Proudly he tugged at the suit coat. "Pretty nice stuff, eh? Everything I want they give me 'cause they really likes me. I'm they best friend." —Roll of Thunder, Hear My Cry, Mildred D. Taylor What do T. J.’s actions indicate?
A. He dislikes that his old friends never bought him things.
B. He is showing off his new friends’ generosity.
C. He feels sorry that his old friends do not have nice things.
D. He is angry about the way his old friends treated him.
Answer:
B. He is showing off his new friends’ generosity.
Explanation:
Answer: B He is showing off his new friends' generosity
Explanation: 2020 EDGE is correct with B
A(94,0,14) B(52,56,94) C(10,6,48) D(128,64,10)
The goal of the assignment is to apply methods of transforming orthogonal projections to solving metric problems.
The coordinates of four points ABCD are given (see next table). Determine the following values by transforming projection planes:
• 1. The size of the dihedral angle at the edge AB.
• 2. The shortest distance between ribs DA and BC.
• 3. Distance from vertex D to plane ABC.
• 4. Natural size of triangle ABC.
An example how to complete the task is shown after the table
9514 1404 393
Answer:
see below
Explanation:
We presume the drawing you want is contained in the figure you attached. The true sizes are identified with corresponding numbers.
Without your example, or your given methods of transforming projections, it is difficult to tell exactly how you want to compute the various distances or sizes.
In order to avoid slipping in the shop, your footwear should ___________.
(This is for my automotive class by the way)
Answer:
good shoes
Explanation:
yes
In addition to bandages and gauze, it's recommended that a first aid kit also contain ___________.
A) Portable eyewash bottles
B) Tweezers
C) A finger splint
D) Scissors
In addition to bandages and gauze, it's recommended that a first aid kit also contain scissors. The correct option is D.
What is First aid?First aid is the initial and urgent care given to anyone who has either a small or significant disease or injury, with the goal of preserving life, preventing the condition from getting worse, or assisting in the healing process.
First aid is the initial and urgent care given to anyone who has either a small or significant disease or injury, with the goal of preserving life, preventing the condition from getting worse, or assisting in the healing process.
A first aid kit normally contains :
1. plasters
2. scissors
3. bandages
4. antiseptic ointments or lotions
5. basic medicines
6. gauzes
Anyone who has been hurt in an accident or has been injured can receive quick and basic medical care with the help of these materials.
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Proper ventilation is required when welding, so that you don't ____________.
A) Breathe in dangerous fumes
B) Cause an area to smell like smoke
C) Overheat
D) Burn yourself
(This is for my Automotive class)
15 kg of ice at 0°C is heated to water of temperature 20°C. What is the amount of heat required if the specific latent heat of ice fusion is 335 kJ/kg and the specific heat capacity of water is 4.19kJ/kg/°C?
Answer:
6282 kJ
Explanation:
Given that:
The mass (m) = 15 kg
The specific latent heat of ice fusion [tex]h_{fg}_{ice}[/tex] = 335 kJ/kg
The specific heat capacity of water = 4.19 kJ/kg.c
The initial temperature of the ice [tex]T_i[/tex]= 0° C
The final temperature of the water [tex]T_f[/tex] = 20° C
To find the needed amount of heat to convert 0° C ice to 20° C of water.
To do that, we need to find the latent heat required for the phase change from 0° C ice to 0° C water, then the heat required to convert 0° C water to 20° C water.
Heat required = [tex]m \times h_{fg}_{ice}+ m \times c_{water} \times \Delta T[/tex]
Heat required = (15 × 335) + (15 × 4.19) × (20 - 0)
Heat required = 5025 + 62.85 × 20
Heat required = 5025 + 1257
Heat required = 6282 kJ
5. (20 points) Identify and resolve (via forwarding) all the data hazards in the MIPS pipeline for the following sequence of MIPS instructions. Insert pipeline bubbles as necessary if forwarding cannot completely solve the data hazards. You may use multi-cycle pipeline representation to show the forwarding and bubbles. sub $4, $1, $3 sw $4, 0($2) lw $1, 0($2) add $1, $3, $4
Answer:
a
Explanation:
Type the correct answer in the box. Spell all words correctly.
Who focuses on planning a long-term business?
focus on planning a long-term business.
Reset
Next
Explanation:
A business man who really focus on victory achieved through a right procedure will focus on long-term planning.
Let us understand what a short-term and long-term planning is.
Short-term will plan only for two-three years. But a long-term plan will look for future five years income projection, plan of expansion, bigger goals, etc.
A business man is the person who take risks and achieve more. A victory can be achieved in many ways one is taking bigger risks, next is focusing on long-term plans
If this is wrong, give me the answer choices so I know what's right or wrong. I'll edit the question if given to me.
What is the base unit that is divided in an engineering scale?
An engineering scale is based on unit increments of a/n ____.
Explanation:
The most often used architect's scale is 1/4" = 1'-0". The basic unit of measure for metric scales is the millimeter (mm). Drafting scales are either open-divided or full-divided.
I really have no clue if this is right or not because, well, I'm not an expert.
If this is wrong, don't hesitate to report my answer if it's wrong.
A journeyman electrician with 16 years experience on-the-job was removing metal fish
tape from a hole at the base of a metal light pole. It was raining during the course of the
work. The fish tape became energized, electrocuting him. What could have been done to
prevent this accident? Select all that apply.
Explanation:
1. Ensure all circuits are de-energized before beginning work (29 CFR 1926.416(a)(3)).
2. Controls to be deactivated during the course of work on energized or de-energized
equipment or circuits must be tagged (29 CFR 1926.417(a)).
3. Employees must be instructed to recognize and avoid unsafe conditions associated with
their work (29 CFR 1926.21(b)(2)).
Rod of steel, 200 mm length reduces its diameter (50 mm) by turning by 2 mm with feed speed 25 mm/min. You are required to calculate the metal removal rate (MRR)
Answer:
Explanation:
The material rate of removal is the total amount of material removed per unit time during any operation. The material rate of removal is usually given by the formula
Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where
Radial Depth of Cut, RDOC = 25 mm
Axial depth of cut, ADOC = 200 mm
Feed rate, FR = 25 mm/min
On multiplying all together, we will then have our Material Rate of Removal, which is
MRR = 25 mm * 200 mm * 25 mm/min
MRR = 125000 mm³/min
Or we convert it to cm³/min and have
MRR = 125000 mm³/min ÷ 1000
MRR = 125 cm³/min
in mining auxiliary operations are the supplementry steps that support the production cycle . elucidate the auxiliary operations of underground mining?
Answer:
The answer is below
Explanation:
The mining auxiliary operations in underground mining involve various activities that are important for a successful mining operation particularly in the areas of productive operating conditions.
The activities involved in the auxiliary operations in underground mining include the following: ventilation, haulage, drainage, power supply, lighting, delivery of compressed air, water, supplies to the working sections, and communications.
A light commercial building located in Philadelphia, Pa has construction and use characteristics much like a residence and design heating load of 120,000 Btu/h and cooling of 60,000 Btu/h. Determine the following: (a) Heating energy requirement, Btu(b) Gallons of No. 2 fuel oil/year, assuming efficiency of the furnace is 75 %(c) Cubic feet of natural gas/year(d) kWh of electricity for cooling for air conditioner with SEER of 8.5 using degree day method.(6 points)
Answer:
b
Explanation:
A fruit juice is being heated in an indirect heat exchanger using steam as a heating medium. The product flows through the heat exchanger at a rate of 1000 kg/h and the inlet temperature is 30 oC. Determine the quantity of steam required to heat the product to 100 oC when only latent heat of vaporization (2230.2 kJ/kg) from steam at 110oC is used for heating. The specific heat of the product is 4 kJ/(kg oC).
Answer:
The appropriate response will be "125.55 kg/hr".
Explanation:
The given values are:
Rate of heat exchanger,
m = 1000 kg/h
Inlet temperature,
T = 30°C
Specific heat,
[tex]c_p[/tex] = 4 kJ/(kg°C)
Now,
The heat taken by juice from steam will be:
⇒ [tex]Q=mc_p(\Delta T)[/tex]
On substituting the values, we get
⇒ [tex]=1000\times 4(100-30)[/tex]
⇒ [tex]=280000 \ kJ/hr[/tex]
The heat given by the steam to juice will be:
⇒ [tex]Q=m\times L[/tex]
On substituting the values, we get
⇒ [tex]=m\times 125.55[/tex]
On equating both the heat values, we get
⇒ [tex]280000=m\times 2230.2[/tex]
⇒ [tex]m=\frac{280000}{2230.2}[/tex]
⇒ [tex]m=125.55 kg/hr[/tex]
The user manual states an accuracy of 0.1% of the reading for a tachometer (an instrument measuring the rotation speed of a shaft or disk, as in a motor or other machine) with an analog display dial graduated in 5 revolutions per minute (rpm) increments. Estimate the design stage uncertainty at 5000 rpm.
Answer: the design stage uncertainty is ±5.6 rpm
Explanation:
Given that;
machine with an analog display dial graduated in 5 revolutions per minute (rpm) increments; Q = 5 rpm
now lets calculate zero order uncertainty in this machine
⇒ ± 1/2Q = 1/2(5) = ± 2.5 rpm
given that accuracy is 0.1% of reading
0.1% of 5000 rmp = 0.1/100 × 5000 = 5 rpm
now the design stage uncertainty at 5000 rpm will be;
⇒ √((5)² + (2.5)²)
= √(25 + 6.25)
= √ 31.25
= ±5.59 ≈ ±5.6 rpm
Therefore the design stage uncertainty is ±5.6 rpm
