In the diagram, <4 and <5 are what type of angles?

A. corresponding angles
B. Alternate interior angles
C. Alternate exterior angles
D. Consecutive interior angles

Take the unknown number as 'y'.

=》33% = 33/100

=》1.45 = 145/100

33/100 × y = 1.45

33/100 × y = 145/100

33y = 145/100 × 100/1

33y = 145

y = 145/33

y = 4.39

______

RainbowSalt2222 ☔

4,39

I'm sorry if I'm wrong

Answer:

800 i think

Step-by-step explanation:

Answer:

C would be the answer

Hope this helps!

Answer:

26°

Step-by-step explanation:

90°+64°+x°=180° (Sum of all the angles in a right angled triangle=180°)

154°+x°=180°

x°=180-154°

x°=26°

26:100

..............................

26 percent in simplest form is the fraction 13/50. Since 'percent' means 'per hundred,' 26 percent would be equivalent to the fraction 26/100.

Step-by-step explanation:

yes, if your teacher meant to include the default factors of every positive integer number : 1 and the number itself.

these are the 2 positive integer factors.

if a positive number can only be divided without remainder by 1 or by itself (with result 1), then it is per definition a prime number.

if the number can be divided without remainder by another number, then we are not dealing with a prime number.

but if your teacher did not have these default factors in mind, then no :

example : 15

15 has only 2 factors : 3 and 5.

both are positive integer numbers.

and yet 15 is not a prime number.

but back to my first point, 15 also has formally the factors 1 and 15. so, if we count them too, then we have suddenly 4 factors. and the original statement fits again.

9514 1404 393

Answer:

  2/3

Step-by-step explanation:

The slope is found using the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (-1 -(-7))/(4 -(-5)) = 6/9 = 2/3

The slope of the line is 2/3.

_____

The attached graph shows the equation of the line in point-slope form.

i guess you have copied the wrong question.. it should be somewhat like if tan theta + sec theta = p then find tge value of sin theta...

secθ+tanθ=P

⇒(secθ+tanθ)² = P²

⇒sec² θ+tan² θ+2tanθsecθ=P²

⇒2tan²θ + 1 + 2 sinθ/cos θ = P²

⇒2 sin²θ+ cos²θ+ 2 sinθ total by cos²θ = P²

Applying componendo and dividendo

=> 2sin²θ+ cos²θ+ 2sinθ- cos²θ/ 2sin²θ+ cos²θ+ 2sinθ- cos²θ = p²-1 / p²+1

⇒2sinθ(sinθ+1)/ 2(sinθ+1) = p²-1 / p²+1

=> sinθ = p²-1/ p²+1

Using the normal distribution, it is found that Sue will get a letter grade of B.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem, Sue got a grade of 0.85, hence [tex]z = 0.85[/tex].

A similar problem is given at https://brainly.com/question/25745464

Answer: 32 hours

Step-by-step explanation: 51/6 = 8.5

So, Erica makes 8.5 dollars per hour. 272/8.5 = 32. Thus, Erica will need 32 hours.

Brainliest?

Answer:

We need to find how much more or less the ratio becomes

1.61 / 23 = 0.07

we multiply 0.07 with 1 to make the ratio even and get your answer

1 x 0.07 = 0.07 on the map

Hope this helps

Step-by-step explanation:

Using the independence between an individual's party affiliation and his support of full-body  scans, it is found that:

a) 57 Republicans would be expected to not support the use of full-body scans.

b) 305 Democrats would be expected to support the use of full-body scans.

c) 18 Independents would be expected to not know or not answer.

The independence between an individual's party affiliation and his support of full-body  scans means that no matter the political party, the proportions for each option would be the same.

In the sample, there are 318 + 369 + 450 = 1137 people.

Item a:

[tex]\frac{170}{3} = 56.67[/tex]

Rounding, 57 Republicans would be expected to not support the use of full-body scans.

Item b:

264 + 299 + 351 = 914 people support the use of full-body scans, hence:

[tex]\frac{914}{3} = 304.67[/tex]

Rounding, 305 Democrats would be expected to support the use of full-body scans.

Item c:

16 + 15 + 22 = 53 people do not know or do not answer, hence:

[tex]\frac{53}{3} = 17.67[/tex]

Rounding, 18 Independents would be expected to not know or not answer.

A similar problem is given at https://brainly.com/question/24372153

Answer:

1) No solution

2) Infinitely many solutions

Step-by-step explanation:

1) No solution

0=2 is false.

2) Infinitely many solutions

2=2 is true because both sides are equal, hence, it is an infinite solution.

Hope this helps :)

Answer:

  D, A, B

Step-by-step explanation:

The sign of the leading coefficient always tells you the end behavior on the right: positive = rises; negative = falls.

The degree of the polynomial tells you how the left- and right-end behaviors compare: even = they are the same; odd = they are opposites.

__

A) negative leading coefficient, even degree:

__

B) positive leading coefficient, odd degree:

__

C) negative leading coefficient, odd degree

Answer:

20.5

Step-by-step explanation:

Use Pythagorean theorem,

[tex]x^2 = 14^2 +15^2 \\\\\implies x^2 =421\\\\\implies x =\sqrt{421}\\\\\implies x =20.5[/tex]

Answer: The answer is 8/9

Step-by-step explanation:

Answer:

53/9 or 5 and 8/9

Step-by-step explanation:

5 1/3 + 5/9

we can convert 5 1/3 to a fraction by multiplying 5 times the denominator and adding 1 (the numerator) to it. we get

16/3

we now need to get common denominators. the least common denominators is 9, so we multiply 16/3 by 3/3 and we get:

48/9

now we can add the two:

48/9 + 5/9 = 53/9 or 5 and 8/9

This is quite an interesting problem. I am not sure how high you are in math, but I am going to use calculus I techniques to solve it. First, we need to model an equation. Let P be the total profit and x be every time you increase the cost by $10. If you think about it hard enough you come up with the equation

[tex]P(x)=(200-5x)(250+10x)[/tex]

(200-5x) is the amount of plots you will be able to sell, and (250+10x) is the amount you charge for. So, at x =0

[tex]P(0)=(200-5(0))(250+10(0))=(200)(250)=$50,000[/tex]

This is the initial condition where if we sell 200 plots at $250/plot.

So, this equation makes sense.

Now, let's maximize using the first derivative of the function.

Let's get it into an easily differentiable form.

[tex]P(x)=(200-5x)(250+10x)=-50x^2+2000x-1250x+50000\\=-50x^2+750x+50000[/tex]

From here, differentiate the problem.

[tex]P'(x)=-100x+750[/tex]

Now, set it equal to zero and solve for x.

[tex]P'(x)=-100x+750=0\\x=7.5[/tex]

This a critical point of the function. Let's plug back into the original equation to see what it gives us.

[tex]P(7.5)=(200-5(7.5))(250+10(7.5))=(162.5)(325)=52,812.50[/tex]

You cant sell half a plot, so we need to see what happens if we sell 162 plots and 163 plots, and then compare which one gives us more money.

In order to sell 162 plots

[tex]200-5x=162\\x=7.6[/tex]Plug back into P(x) to see the profit

[tex]P(7.6)=(200-5(7.6))(250+10(7.6))=(162)(326)=52,812[/tex]

Now, do the same for 163 plots

[tex]200-5x=163\\x=7.4\\P(7.4)=(200-5(7.4))(250+10(7.4))=(163)(324)=52,812[/tex]

As we can see, they are the same. So, you can charge either $324 or $326 in rent. But, if your teacher is not looking for a logical answer and you can somehow sell half a plot, you can charge $325 in rent for the maximum profit.

Let [tex]x = \arcsin(y)[/tex], so that

[tex]\sin(x) = y[/tex]

[tex]\tan(x)=\dfrac y{\sqrt{1-y^2}}[/tex]

[tex]dx = \dfrac{dy}{\sqrt{1-y^2}}[/tex]

Then the integral transforms to

[tex]\displaystyle \int_{x=0}^{x=\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \int_{y=\sin(0)}^{y=\sin\left(\frac\pi2\right)} \frac{y}{\sqrt{1-y^2}} \ln(y) \frac{dy}{\sqrt{1-y^2}}[/tex]

[tex]\displaystyle \int_{x=0}^{x=\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy[/tex]

Integrate by parts, taking

[tex]u = \ln(y) \implies du = \dfrac{dy}y[/tex]

[tex]dv = \dfrac{y}{1-y^2} \, dy \implies v = -\dfrac12 \ln|1-y^2|[/tex]

For 0 < y < 1, we have |1 - y²| = 1 - y², so

[tex]\displaystyle \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy = uv \bigg|_{y\to0^+}^{y\to1^-} + \frac12 \int_0^1 \frac{\ln(1-y^2)}{y} \, dy[/tex]

It's easy to show that uv approaches 0 as y approaches either 0 or 1, so we just have

[tex]\displaystyle \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy = \frac12 \int_0^1 \frac{\ln(1-y^2)}{y} \, dy[/tex]

Recall the Taylor series for ln(1 + y),

[tex]\displaystyle \ln(1+y) = \sum_{n=1}^\infty \frac{(-1)^{n+1}}n y^n[/tex]

Replacing y with -y² gives the Taylor series

[tex]\displaystyle \ln(1-y^2) = \sum_{n=1}^\infty \frac{(-1)^{n+1}}n (-y^2)^n = - \sum_{n=1}^\infty \frac1n y^{2n}[/tex]

and replacing ln(1 - y²) in the integral with its series representation gives

[tex]\displaystyle -\frac12 \int_0^1 \frac1y \sum_{n=1}^\infty \frac{y^{2n}}n \, dy = -\frac12 \int_0^1 \sum_{n=1}^\infty \frac{y^{2n-1}}n \, dy[/tex]

Interchanging the integral and sum (see Fubini's theorem) gives

[tex]\displaystyle -\frac12 \sum_{n=1}^\infty \frac1n \int_0^1 y^{2n-1} \, dy[/tex]

Compute the integral:

[tex]\displaystyle -\frac12 \sum_{n=1}^\infty \frac1n \int_0^1 y^{2n-1} \, dy = -\frac12 \sum_{n=1}^\infty \frac{y^{2n}}{2n^2} \bigg|_0^1 = -\frac14 \sum_{n=1}^\infty \frac1{n^2}[/tex]

and we recognize the famous sum (see Basel's problem),

[tex]\displaystyle \sum_{n=1}^\infty \frac1{n^2} = \frac{\pi^2}6[/tex]

So, the value of our integral is

[tex]\displaystyle \int_0^{\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \boxed{-\frac{\pi^2}{24}}[/tex]

[tex]\displaystyle \int \limits_{0}^{ \frac{ \pi}{2} } \tt\tan (x) \ln ( \sin (x))\\ \\\displaystyle \sf{ \implies \: I = \int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin \left( \dfrac{\pi}{2} - x \right) \right) \: dx } \\ \\\displaystyle \sf{ \implies \: I = \int^{ \frac{\pi}{2} }_{0} \: \ln \left( cos(x) \right) \: dx } \\ \\\displaystyle \sf{ \implies \:2I =\int^{ \frac{\pi}{2} }_{0} \:\ln \left( sin(x) \right) \: dx + \int^{ \frac{\pi}{2} }_{0} \: \ln \left( cos(x) \right) \: dx } \\ \\\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin(x) \right) +\ln\left( cos(x) \right) \: dx }[/tex]

[tex]\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin(x) \: cos(x) \right) \: dx } \\ \\\displaystyle\sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( \dfrac{sin(2x)}{2}\right) \: dx } \\ \\\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \:\ln \left( sin(2x) \right)\:dx-\ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx}[/tex]

[tex]\displaystyle\sf{ \implies \: 2I = \dfrac{1}{2} \int^{ \pi}_{0} \: \ln \left( sin(t) \right) \:dt - \ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx} \\ \\\displaystyle\tt{ \implies \: 2I = \dfrac{1}{2} \cdot2 \int^{ \frac{\pi}{2}}_{0} \: \ln \left( sin(t) \right) \: dt - \ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx}[/tex]

[tex]\displaystyle \tt{ \implies \: 2I =\int^{ \frac{\pi}{2}}_{0} \: \ln \left( sin(t) \right) \: dt - \ln(2)\int^{ \frac{\pi}{2} }_{0} \: dx} \\ \\ \displaystyle \tt{ \implies \: 2I = I - \ln(2) \left[x \right] ^{ \frac{\pi}{2} }_{0} } \\ \\ \displaystyle \tt{ \implies \: I = -\ln(2)\left[ \dfrac{\pi}{2} - 0 \right] }[/tex]

[tex]\displaystyle \sf{ \implies \: I = - \dfrac{\pi}{2} \ln(2) }[/tex]

☞︎︎︎Apologies,if incorrect.

Step-by-step explanation:

The text below that are formatted in bold and underlined font are the solutions to the missing boxes in your given problem.  

Given that ∠1, ∠2, ∠3, and ∠4 are formed by two intersecting segments, and that:

∠1 and  ∠2 form a linear pair  

∠2 and ∠3 form a linear pair  

These linear pair relationships suggest that by the Linear Pair Postulate:

∠1 and ∠2 are supplementary.    ⇒  Linear Pair Postulate

∠2 and ∠3 are supplementary.    ⇒  Linear Pair Postulate

m∠2 + m∠ 3 = 180°  ⇒  Definition of supplementary angles.

m∠1 + m∠3  = m∠2 + m∠ 3  ⇒  Substitution Property of Equality.          

m∠1  =  m∠3   ⇒  Subtraction Property of Equality.  

Answer:

You: 3, 6, 9, 12

Friend:4, 8, 12, 16

Step-by-step explanation:

You/Friend ratio is 3/4

Missing numbers:

Numbers:

You      3, 6, 9, 12

Friend  4, 8, 12, 16

Answer:

Step-by-step explanation:

Answer:

A: Walking

Step-by-step explanation:

-It cannot be biking because the constant of proportionality (COP) is 9.5 miles (per hour).

-It cannot be running because the COP is 5 miles (per hour).

-It cannot be swimming because the COP is 4.5 miles (per hour).

he is walking

14 divided by 4 is equivalent to 3.5 the equation being 14/4=3.5 or 3 1/2

Answer:

13:7

Step-by-step explanation:

This ratio would be 13 laptop computers for every 7 desktop computers; 13:7

Answer:

Equation 2 represents the greatest value of x!

Step-by-step explanation:

Let's solve each equation for x.

Equation 1; x = 4.1 (about)

Equation 2: x = 5 (about)

Equation 3: x = 4 (exact)

Equation 4: x = 3 (exact)

Hope this helps. :)

It takes Brian 1.5 hours to get home from school

Speed is the ratio of distance travelled to time taken. It is given by:

Speed = distance / time

Let d represent the distance from their school to the house and t represent the time (hours) it takes Brian to teach home.

For Brian:

4 = d/t

d = 4t

For Scott:

6 = d / (t - 1/2)

d = 6t - 3

4t = 6t - 3

2t = 3

t = 1.5 hours

Therefore it takes Brian 1.5 hours to get home from school

Find out more at: https://brainly.com/question/22889670

Answer:

12% increase compared to last years

Step-by-step explanation: