Answer:
The generation of AMP takes place by the reaction involving condensation with Asp and the reaction in which fumarate is release. On the other hand, the generation of GMP takes place at the time of oxidative hydration and during transamination with glutamine. Hence, for AMP option A and D is correct, and for GMP option B and C is correct.
Explanation:
A) The production of arginosuccinate and AMP takes place when condensation of citrulline takes place with aspartic acid. It is an energy-dependent reaction, which results in the hydrolysis of ATP to AMP.
B) The liberation of GMP takes place during the oxidation of amino acids.
C) The production of glutamate and aspartate takes place respectively during the transfer of amino group from glutamine to oxaloacetate, in the process hydrolyzation of GTP takes place to GMP.
D) The formation of arginine and fumarate takes place during the conversion of arginosuccinate, in the process ATP is hydrolyzed and the generation of AMP takes place.
When 2,2-dimethylbutane is subjected to free-radical chlorination, ________ distinct monochlorinated products are possible and ________ of these contain asymmetric carbon atoms.
Answer:
See the explanation
Explanation:
In this case, we have to remember that in the monochlorination products we only have to add one "Cl" with this in mind, we can have several options.
a) 1-chloro-2,2-dimethylbutane
b) (R)-3-chloro-2,2-dimethylbutane
c) (S)-3-chloro-2,2-dimethylbutane
d) 1-chloro-3,3-dimethylbutane
Additionally, from these 4 molecules, we will have 2 enantiomers. (R)-3-chloro-2,2-dimethylbutane and (S)-3-chloro-2,2-dimethylbutane.
See figure 1
I hope it helps!
There four distinct monochlorinated products and two of them contain an asymmetric carbon atom.
Free radicals refers to chemical species that posses an odd number of electrons. An asymmetric carbon atom is a carbon atom that is bonded to four different groups.
When 2,2-dimethylbutane is subjected to free-radical chlorination, four distinct monochlorinated products are possible and two of these contain asymmetric carbon atoms.
The four distinct monochlorinated products are;
1-chloro-2,2-dimethylbutane (R)-3-chloro-2,2-dimethylbutane (S)-3-chloro-2,2-dimethylbutane 1-chloro-3,3-dimethylbutane
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A welding torch produces a flame by burning acetylene fuel in the presence of oxygen. This flame is used to melt a metal. Which energy transformation represents this process? chemical energy into thermal energy potential energy into kinetic energy kinetic energy into electromagnetic energy potential energy into chemical energy
Answer:
chemical energy into thermal energy
Explanation:
The chemical energy is found within the chemical bonds of the acetylene fuel molecules. The amount of energy generated when the fuel is burned in the presence of oxygen is strong (using an exothermic process) and generates a flame.
The flames are warm enough to fuse metal. Melting arises as molecules are excited by the thermal energy, and they start to move rapidly and resolve the metal lattice bonding.
Hence, the first option is correct
Answer:
its a
Explanation:
The complete ionic equation for the reaction of aqueous sodium hydroxide with aqueous nitric acid is
Answer and Explanation:
Sodium hydroxide (NaOH) is a strong base and nitric acid (HNO₃) is a strong acid. That means that they dissociates in water by giving the ions:
NaOH ⇒ Na⁺(ac) + OH⁻(ac)
HNO₃ ⇒ H⁺(ac) + NO₃⁻(ac)
The reaction between an acid and a base is called neutralization. In this case, HNO₃ loses its proton and it is converted in NO₃⁻ (nitrate anion). NaOH loses its hydroxyl anion (OH⁻) by giving Na⁺ cations.
Na⁺ cations with NO₃⁻ anions form the salt NaNO₃ (sodium nitrate); whereas H⁺ and OH⁻ form water molecules. The complete equation is the following:
HNO₃(ac) + NaOH(ac) ⇒ NaNO₃(ac) + H₂O(l)
The ionic equation is:
H⁺(ac) + NO₃⁻(ac) + Na⁺(ac) + OH⁻(ac) ⇄ Na⁺(ac) + NO₃⁻(ac) + H₂O(ac)
If we cancel the repeated ions at both sides of the equation, it gives the following ionic reaction:
H⁺(ac) + OH⁻(ac) ⇄ H₂O(ac)
The density of an object has the equation . If an object has a mass of 85 g and a volume of 92 cm3, what is its density?
Answer:
Explanation:
density = mass / volume = 85 / 92 = 0.92 g/cm3
Answer:
0.92
Explanation:
Please what's the missing minor products? And kindly explain in your own words how they were formed. Thank you!
Answer:
it's a two step elimination reaction
Explanation:
it follows a carbocationic pathway. When carbocation is stable, the equation is favourable, that is, double bond is formed by expelling hydrogen atom.
Tubes through which water flows as it is brought from 0.8 MPa, 150C to 240C at essentially constant pressure in the boiler of a power plant. The total mass flow rate of the water is 100 kg/s. Combustion gases passing over the tubes cool from 1067 to 547C at essentially constant pressure. The combustion gases can be modeled as air as an ideal gas. There is no significant heat transfer from the boiler to its surroundings. Surrounding (dead state) temperature and pressure are given as 25C and 1 atm, respectively. Determine i) the exergetic efficiency of the boiler ii) rate of exergy destruction as kW iii) mass flow rate of the combustion gases as kg/s
Answer:
The correct answer is i) 50.2 % ii) 13440.906 kW and iii) 71.986 kg/s.
Explanation:
In order to find the mass flow rate of the combustion of gases, there is a need to use the energy balance equation:
Mass of water × specific heat of water (T2 -T1)w = mass of gas × specific heat of gas (T2-T1)g
100 × 4.18 × [(240 + 273) - (150 + 273)] = mass of gas × 1.005 × [(1067+273) - (547+273)]
Mass of gas = 71.986 kg/s
The entropy generation of water can be determined by using the formula,
(ΔS)w = mass of water × specific heat of water ln(T2/T1)w
= 100 × 4.18 ln(513/423)
= 80.6337 kW/K
Similarly the entropy generation of water will be,
(ΔS)g = mass of gas × specific heat of gas ln(T2/T1)g
= 71.986 × 1.005 ln (820/1340)
= -35.53 kW/K
The rate of energy destruction will be,
Rate of energy destruction = To (ΔS)gen
= T₀ [(ΔS)w + (ΔS)g]
= (25+273) [80.6337-53.53)
Rate of energy destruction = 13440.906 kW
The availability of water will be calculated as,
= mass of water (specific heat of water) [(T₁-T₂) -T₀ ln T₁/T₂]
= 100 × 4.8 [(513-423) - 298 ln 513/423]
= 13591.1477 kW
The availability of gas will be calculated as,
= mass of gas (specific heat of gas) [(T₁-T₂) - T₀ ln T₁/T₂]
= 71.986 × 1.005 × [(1340-820) - 298 ln 1340/820]
= 27031.7728 kW
The exergetic efficiency can be calculated as,
= Gain of availability / loss of availability
= 13591.1477/27031.7728
= 0.502
The exergetic efficiency is 50.2%.
A student obtained the following data for the rearrangement of cyclopropane to propene at 500 °C. (CH2)3(g)CH3CH=CH2(g) [(CH2)3], M 0.128 6.40×10-2 3.20×10-2 1.60×10-2 time, min 0 14.4 28.8 43.2 (1) What is the half-life for the reaction starting at t=0 min? min What is the half-life for the reaction starting at t=14.4 min? min Does the half-life increase, decrease or remain constant as the reaction proceeds? _________ (2) Is the reaction zero, first, or second order? _______ (3) Based on these data, what is the rate constant for the reaction? min-1
Explanation:
CH2)3(g)CH3CH=CH2(g) [(CH2)3], M time, min
0.128 0
6.40×10-2 14.4
3.20×10-2 28.8
1.60×10-2 43.2
(1) What is the half-life for the reaction starting at t=0 min? min
Half life is the amount of time required for a substance to decay by half of it's initial concentration.
Starting form 0, the initial concentration = 0.128
After 14.4 mins, the final concentration is now exactly half of the initial concentration. This means 14.4 min is the half life starting from t=0min
What is the half-life for the reaction starting at t=14.4 min?
Starting form 14.4min, the initial concentration = 6.40×10-2
After 14.4 mins (28.8 - 14.4), the final concentration is now exactly half of the initial concentration. This means 14.4 min is the half life starting from t=14.4min
Does the half-life increase, decrease or remain constant as the reaction proceeds?
The half life is a constant factor, hence it remains constant as the reaction proceeds.
(2) Is the reaction zero, first, or second order?
Because the half life is independent of the concentration, it is a first order reaction.
In a zero order reaction, the half life Decreases as the reaction progresses; as concentration decreases.
In a first order reaction, the half life Increases with decreasing concentration.
(3) Based on these data, what is the rate constant for the reaction? min-1
The realtionship between the half life and rate onstant is;
k = 0.693 / half life
k = 0.693 / 14.4
k = 0.048125 min-1
When 15.0 mL of a 6.42×10-4 M sodium sulfide solution is combined with 25.0 mL of a 2.39×10-4 M manganese(II) acetate solution does a precipitate form? (yes or no) For these conditions the Reaction Quotient, Q, is equal to .
Answer:
Q = 3.59x10⁻⁸
Yes, precipitate is formed.
Explanation:
The reaction of Na₂S with Mn(CH₃COO)₂ is:
Na₂S(aq) + Mn(CH₃COO)₂(aq) ⇄ MnS(s) + 2 Na(CH₃COO)(aq).
The solubility product of the precipitate produced, MnS, is:
MnS(s) ⇄ Mn²⁺(aq) + S²⁻(aq)
And Ksp is:
Ksp = 1x10⁻¹¹= [Mn²⁺] [S²⁻]
Molar concentration of both ions is:
[Mn²⁺] = 0.015Lₓ (6.42x10⁻⁴mol / L) / (0.015 + 0.025)L = 2.41x10⁻⁴M
[S²⁻] = 0.025Lₓ (2.39x10⁻⁴mol / L) / (0.015 + 0.025)L = 1.49x10⁻⁴M
Reaction quotient under these concentrations is:
Q = [2.41x10⁻⁴M] [1.49x10⁻⁴M]
Q = 3.59x10⁻⁸
As Q > Ksp, the equilibrium will shift to the left producing MnS(s) the precipitate
the options are: ( it can’t be repeated )
1-synthetic polymer
2-natural polymer
3-gamma radiation
4-condensation polymerization
5-addition polymerization
Answer:
3- gamma radiation
Explanation:
Hello,
In the above question, 4 of the options are related to polymerization which are
1. Synthetic polymer
2. Natural polymer
3. Condensation polymerization
4. Addition polymerization.
The first two options are types of polymer that exists while the last two are polymerization techniques.
The odd option here which is "gamma radiation" is a particle which is emitted from radioactive substances during decay. It has no mass and no charge but it is highly penetrating and dangerous to human health.
However,
Synthetic polymers are also known as man made polymers and they exist around us because they're present in materials which we use everyday. An example is polyethylene, nylon-6,6 etc
Natural polymers are compounds which are polymeric in nature (compounds catenating to form a complex molecule). Natrual occurring polymers can be found in proteins and some lipids.
Three elements have the electron configurations 1s2 2s2 2p6 3s2 3p6, 1s2 2s2 2p6 3s2, and
1s2 2s2 2p6 3s2 3p6 4s1. The first ionization energies of the three elements (not in the same order) are 0.4189, 0.7377, and 1.505 MJ/mol. The atomic radii are 1.60, 0.94, and 2.35 .Identify the three elements and match the appropriate values of ionization energy and atomic radius to each configuration.
Explanation:
First element
1s2 2s2 2p6 3s2 3p6
Atomic Number = 18
Element = Argon
Second Element
1s2 2s2 2p6 3s2
Atomic Number = 12
Element = Magnesium
Second Element
1s2 2s2 2p6 3s2 3p6 4s1
Atomic Number = 19
Element = Potassium
In the periodic table;
The general trend is for ionization energy to increase moving from left to right across an element period. It would decrease down the group.
Both Argon and Magnesium are on the same period. Potassium is o the period below.
This leads us to;
Magnesium - 0.7377 MJ/mol
Argon - 1.505 MJ/mol
Potassium - 0.4189 MJ/mol
The atomic radius of atoms generally decreases from left to right across a period. It would increase down the group.
This leads to;
Magnesium - 1.60
Argon - 0.94
Potassium - 2.35
How can hypotheses best be tested?
O by asking questions
O through experimentation
O by forming an opinion
O through technology
Answer:
the second option
Explanation
A solution that is 0.135 M is diluted to make 500.0 mL of a 0.0851 M solution. How many milliliters of the original solution were required? View Available Hint(s) A solution that is 0.135 M is diluted to make 500.0 mL of a 0.0851 M solution. How many milliliters of the original solution were required? 5.74 mL 0.315 mL 793 mL 315 mL
Answer:
315mL
Explanation:
Data obtained from the question include the following:
Molarity of stock solution (M1) = 0.135 M
Volume of stock solution needed (V1) =?
Molarity of diluted solution (M2) = 0.0851 M
Volume of diluted solution (V2) = 500mL
The volume of the stock solution needed can be obtain as follow:
M1V1 = M2V2
0.135 x V1 = 0.0851 x 500
Divide both side by 0.135
V1 = (0.0851 x 500) / 0.135
V1 = 315mL
Therefore, the volume of the stock solution needed is 315mL
What percent of a drug is contained in a mixture of powder consisting of 0.5 kg, containing 0.038% of a drug, and 10 kg, containing 0.043% of a drug?
Answer:
[tex]0.0427~%[/tex]
Explanation:
In this question, we have to start with the calculation of the amount of drug in each powder:
Powder A: Total mass of 0.5 Kg percentage of 0.038%
[tex]0.5~Kg~of~powder\frac{0.038}{100}=0.00019~Kg~of~drug[/tex]
Powder B: Total mass of 10 Kg percentage of 0.043%
[tex]10~Kg~of~powder\frac{0.043}{100}=0.0043~Kg~of~drug[/tex]
The total mass of powder would be:
[tex]10+0.5=10.5~Kg[/tex]
The total mass of drug would be:
[tex]0.0043+0.00019=0.00449~Kg[/tex]
Now we can calculate the percentage:
[tex]\frac{0.0043Kg}{10.5Kg}*100=0.0427%[/tex]
I hope it helps!
A chemist prepares a solution of sodium chloride by measuring out of sodium chloride into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's sodium chloride solution. Be sure your answer has the correct number of significant digits.
Answer:
4.35 mol/L
Explanation:
There is some info missing. I think this is the original question.
A chemist prepares a solution of sodium chloride by measuring out 25.4 grams of sodium chloride into a 100 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's sodium chloride solution. Be sure your answer has the correct number of significant digits.
Step 1: Calculate the moles of sodium chloride
The molar mass of sodium chloride is 58.44 g/mol. The moles corresponding to 25.4 grams of sodium chloride are:
[tex]25.4g \times \frac{1mol}{58.44g} = 0.435mol[/tex]
Step 2: Calculate the liters of solution
We will use the relationship 1 L = 1,000 mL.
[tex]100mL \times \frac{1L}{1,000mL} = 0.100L[/tex]
Step 3: Calculate the concentration of sodium chloride in mol/L
[tex]\frac{0.435mol}{0.100L} =4.35 mol/L[/tex]
On a hot summer day, the density of air at atmospheric pressure at 35.5°C is 1.1970 kg/m3. (a) What is the number of moles contained in 1.00 m3 of an ideal gas at this temperature and
Complete question:
On a hot summer day, the density of air at atmospheric pressure at 35.5°C is 1.1970 kg/m3. (a) What is the number of moles contained in 1.00 m3 of an ideal gas at this temperature and pressure.
Answer:
The number of moles contained by an ideal gas at this temperature and pressure is 41.32 moles.
Explanation:
Given;
density of dry air, ρ = 1.1970 kg/m³
temperature of the air, T = 35.5°C = 273 + 35.5 = 308.5 K
air volume, V = 1 m³
Apply ideal gas law for dry to calculate the air pressure;
[tex]P = \rho R_dT[/tex]
where;
P is the air pressure
ρ is the air density
Rd is gas constant for dry air = 287 J/kg/K
P = 1.197 x 287 x 308.5 = 105,981.78 Pa
(a) Now, determine the number of moles contained by an ideal gas at this temperature and pressure, by applying ideal gas law;
PV = nRT
where;
P is the pressure of the gas (Pa)
V is the volume of the gas (m³)
n is number of gas moles
R is gas constant = 8.314 m³.Pa / mol.K
T is temperature (K)
n = (PV) / (RT)
n = (105,981.78 x 1) / (8.314 x 308.5)
n = 41.32 moles
Therefore, the number of moles contained by an ideal gas at this temperature and pressure is 41.32 moles.
The number of moles of an ideal gas at this temperature and pressure is 41.5 moles.
Given that;
Density of dry air = 1.1970 kg/m3
Pressure of dry air = ?
Temperature of dry air = 35.5°C + 273 = 308.5 K
Hence;
P = Density × gas constant of dry air × Temperature
P = 1.1970 kg/m3 × 287.1 J/Kg/K × 308.5 K
P = 106019 Pa or 1.05 atm
Using the ideal gas equation;
PV = nRT
n = PV/RT
n = 1.05 atm × 1000 L/0.082 atmL/K.mol × 308.5 K
n = 41.5 moles
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An empty beaker is weighed and found to weigh 23.1 g. Some potassium chloride is then added to the beaker and weighed again. The second weight is 24.862 g. What is the mass of the potassium chloride
Answer:Mass of Potassium chloride =1.762g
Explanation:
Mass of empty beaker = 23.100 g
Mass of beaker with Potassium chloride = 24.862g
Mass of Potassium chloride = Final weight - initial weight = Mass of beaker with Potassium chloride - Mass of empty beaker = 24.862-23.100 = 1.762g
Mannoheptulose is a sugar found in avocados. If each C-C bond contains 76 kcal of energy and each C-H bond contains 91 kcal, how many kcal of energy are available through the complete catabolism of this sugar
Answer:
Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal
Explanation:
The molecular formula of mannoheptulose is C₇H₁₄O₇.
The structure is as shown in the attachment below.
Number of C-C bonds present in mannoheptulose = 6
Number of C-H bonds present in mannoheptulose = 8
Since the each C-C bond contains 76 Kcal of energy,
Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal
Also, since each C-H bond contains 91 Kcal of energy;
amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal
Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal
The diagrams show the particles of a substance. The first diagram shows a container filled with a neat, tightly packed array of particles. An arrow points to a second diagram, where the container is full of particles that are not neatly packed. An arrow points to a third container, with a few random particles. Which statement best describes the process that the diagrams show? A solid loses kinetic energy to become a liquid and then becomes a gas. A solid gains kinetic energy to become a liquid and then becomes a gas. A gas loses kinetic energy to become a liquid and then becomes a solid. A gas gains kinetic energy to become a liquid and then becomes a solid.
The correct answer is B. A solid gains kinetic energy to become a liquid and then becomes a gas.
Explanation:
In solids, particles are organized and tightly packed, due to this, they only vibrate, which implies the kinetic energy is quite low (energy related to motion). Additionally, when solids are exposed to heat and they change their state to liquid, the substance obtains kinetic energy and particles move more freely and are not as organized and solids. Also, this increases in gases, in which kinetic energy is high and particles move freely. Thus, in the diagram, the states solid, liquid, and gas are represented and in this, "a solid gains kinetic energy to become a liquid and then becomes a gas."
Answer: b
Explanation:
edge
What is the pH at the equivalence point in the titration of a 20.9 mL sample of a 0.357 M aqueous acetic acid solution with a 0.434 M aqueous barium hydroxide solution? pH =
Answer:
ph is the amount of toxins right
What force is needed to accelerate a truck with mass 2,000 kg at a rate of 5.0
m/s22
O A. 1,000 N
B. 20,000 N
C. 2,000 N
O D, 10,000 14
Answer:
D
Explanation:
[tex]F=ma \\\\F=2000\cdot 5=10,000N[/tex]
Hope this helps!
How many neutrons does the isotope N-14 have?
Answer:
7
Explanation:
N-14 has 7
i looked it up ye ur probably gonna get it right
Answer:
7 protons + 7 neutrons!
Explanation:
Other than the reaction in (b), suggest another reaction which milk of magnesia can undergo.
Write a chemical equation for this reaction.
Answer:
2Ch3cooh + mg(oh)2 --> (ch3coo)2mg + 2h20
Explanation:
Reaction of milk of magnesia with acetic acid.
A solution of milk of magnesia and universal indicator in water is stirred while acetic acid is added. The indicator changes color as the acid is neutralized. As the suspended solid is consumed, the solution becomes clear.
Duncan knows that it takes 36400 cal of energy to heat a pint of water from room temperature to boiling. However, Duncan has prepared ramen noodles so many times he does not need to measure the water carefully. If he happens to heat 0.800 pint of room-temperature water, how many kilojoules of heat energy will have been absorbed by the water at the moment it begins to boil?
Answer:
[tex]\large \boxed{\text{122 000 J}}[/tex]
Explanation:
1. Calculate the energy needed
[tex]\text{Energy} = \text{0.800 pt} \times \dfrac{\text{36 400 cal}}{\text{1 pt}} = \text{ 29 120 cal}[/tex]
2. Convert calories to joules
[tex]\text{Energy} = \text{29 120 cal} \times \dfrac{\text{4.184 J}}{\text{1 cal}} = \textbf{122 000 J}\\\\\text{The water will have absorbed $\large \boxed{\textbf{122 000 J}}$}[/tex]
1.the particles in a_are packed very closely together. 2.the_in a liquid are loosely together. they can flow. 3.in a gas the_between the particles are bigger. if u re genius then answer this question class 4
Answer:
1. Solid
2. Particles.
3. Space.
Explanation:
1. The particles in a solid are packed very closely together. This is the most reason why solid particles have definite shapes of volume. This closeness is as a result of strong intermolecular forces force that exist between the particles. Hence, they can not flow but only vibrates about their mean position. Solids can not be compressed because of the strong intermolecular forces between their particles.
2. The particles of liquid are loosely together. In liquid, the particles are loosely packed and free to move about to certain degree. This is so because the intermolecular force between the particles are not as strong as those within the solid particles. Hence liquid has no definite shape but they have definite volume. They only assume the shape of the container they are poured into. Liquid can no be compressed..
3. In a gas, the space between the particles are bigger. This is so because the intermolecular forces between the particles are negligible i.e very small and so, the gas particles are free to move about and only restricted by the wall of the container they poured into. This negligible intermolecular forces are the reason why gas has no definite shapes and no volume. They can be compressed to fill a particular container.
Determine the theoretical maximum moles of hydroquinone, , that could be produced in this experiment. The reactant, quinone, is the limiting reagent. (To avoid introducing rounding errors on intermediate calculations, enter your answer to four significant figures.)
Reactant mass 23.4g
Product mass 13.0g
Reactant moles 0.2167 mol
Reactant mass 23.4g
Product mass 13.0g
Molar mass C 12.0 g/mol
Molar mass H 1.00 g/mol
Molar mass O 16.0 g/mol
Theoretical maximum moles of hydroquinone:___________
Answer:
Theoretical maximum moles of hydroquinone: 0.2167 mol.
Explanation:
Hello,
In this case, the undergoing chemical reaction is like:
[tex]Quinone\rightarrow Hydroquinone[/tex]
In such a way, since the molar mass of quinone is 108.1 g/mol and it is in a 1:1 molar ratio with hydroquinone, we can easily compute the theoretical maximum moles of hydroquinone by stoichiometry:
[tex]n_{hydroquinone}=23.4g\ quinone*\frac{1mol\ quinone}{108.1 g\ quinone}*\frac{1mol\ hydroquinone}{1mol\ quinone} \\\\n_{hydroquinone}=0.2167mol[/tex]
Clearly, this is the theoretical yield which in grams is:
[tex]m_{hydroquinone}=0.2167mol*\frac{110.11g}{1mol} =23.84g[/tex]
Which allows us to compute the percent yield as well since the obtained mass of the product is 13.0 g:
[tex]Y=\frac{13.0g}{23.84g}*100\%=54.5\%[/tex]
Best regards.
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
1) 17.5ml
2) 35ml
3) 52.5ml
4) 3.0ml
Answer:
1) 17.5 mL
Explanation:
Hello,
In this case, the reaction between sulfuric acid and potassium hydroxide is:
[tex]H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O[/tex]
In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:
[tex]2*n_{acid}=n_{base}[/tex]
And in terms of concentrations and volumes:
[tex]2*M_{acid}V_{acid}=M_{base}V_{base}[/tex]
Thus, we solve for the volume of acid:
[tex]V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL[/tex]
Best regards.
What is the Lewis structure for *OPCl3 and AlCl6^3-? What are their electron/molecular geometry and Ideal Bond Angle ?
Answer:
Here's what I get
Explanation:
1. POCl₃
(a) Lewis structure
Set P as the central atom, with O and Cl atoms directly attached to it.
Electrons available = P + O + 3Cl = 5 + 6 + 3×7 = 11 + 21 = 32
Arrange these electrons to give every atom an octet. Put a double bond between P and O.
You get the structure shown below.
(b) Geometry
There are four bond pairs and no lone pairs about the P atom.
Electron pair geometry — tetrahedral
Molecular geometry — tetrahedral
(c) Ideal bond angles
Tetrahedral bond angle = 109.5°
2. AlCl₆³⁻
(a) Lewis structure
Set Al as the central atom, with the Cl atoms directly attached to it.
Electrons available = Al + 6Cl + 3(-) = 3 + 6×6 +3 = 6 + 36 = 42
Arrange these electrons to give every atom an octet. Assign formal charges.
You get the structure shown below.
(b) Geometry
There are six bond pairs and no lone pairs about the Al.
Electron pair geometry — octahedral
Molecular geometry — octahedral
(c) Ideal bond angles
Axial-equatorial = 90°
Equatorial-equatorial = 120°
Axial-axial = 180°
Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 4.90 g of sulfuric acid and 4.90 g of lead(II) acetate are mixed. Calculate the number of grams of sulfuric acid, lead(II) acetate, lead(II) sulfate, and acetic acid present in the mixture after the reaction is complete .
Answer:
Mass H2SO4 = 3.42 grams
Mass of lead acetate = 0 grams
Mass PbSO4 = 4.58 grams
Mass of CH3COOH = 1.81 grams
Explanation:
Step 1: Data given
Mass of sulfuric acid = 4.90 grams
Molar mass of sulfuric acid = 98.08 g/mol
Mass of lead acetate = 4.90 grams
Molar mass of lead acetate = 325.29 g/mol
Step 2: The balanced equation
H2SO4 + Pb(C2H3O2)2 → PbSO4 + 2CH3COOH
Step 3: Calculate moles
Moles = mass / molar mass
Moles H2SO4 = 4.90 grams / 98.08 g/mol
Moles H2SO4 = 0.0500 moles
Moles lead acetate = 4.9 grams / 325.29 g/mol
Moles lead acetate = 0.0151 moles
Step 4: Calculate the limiting reactant
For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH
The limiting reactant is lead acetate. It will completzly be consumed (0.0151 moles). H2SO4 is in excess. There will react 0.0151 moles. There will remain 0.0500 - 0.0151 = 0.0349 moles
Step 5: Calculate moles of products
For 1 mol H2SO4 we need 1 mol lead acetate to produce 1 mol PbSO4 and 2 moles CH3COOH
For 0.0151 moles lead acetate we'll have 0.0151 moles PbSO4 and 2*0.0151 = 0.0302 moles CH3COOH
Step 6: Calculate mass
Mass = moles * molar mass
Mass H2SO4 = 0.0349 moles * 98.08 g/mol
Mass H2SO4 = 3.42 grams
Mass PbSO4 = 0.0151 moles * 303.26 g/mol
Mass PbSO4 = 4.58 grams
Mass of CH3COOH = 0.0302 moles * 60.05 g/mol
Mass of CH3COOH = 1.81 grams
The first task you are assigned in your summer laboratory job is to prepare a concentrated NaOH stock solution. The molecular weight of NaOH is 40. How many grams of solid NaOH will you need to weigh out to obtain a 500 mL solution that has a concentration of 10 M
Answer:
200g of NaOH
Explanation:
The following data were obtained from the question:
Molar mass of NaOH = 40g/mol
Volume = 500mL
Molarity of NaOH = 10M
Next, we shall determine the number of mole of NaOH present in the solution. This is illustrated below:
Molarity of NaOH = 10M
Volume = 500mL = 500/1000 = 0.5L
Mole of NaOH =...?
Molarity = mole /Volume
10 = mole /0.5
Cross multiply
Mole = 10 x 0.5
Mole of NaOH = 5 moles
Finally, we can convert 5 moles of NaOH to grams. This is illustrated below:
Molar mass of NaOH = 40g/mol
Mole of NaOH = 5 moles
Mass of NaOH =...?
Mole = Mass /Molar Mass
5 = Mass /40
Cross multiply
Mass = 5 x 40
Mass of NaOH = 200g
Therefore, 200g of NaOH is needed to prepare the solution.
Can someone please help me out with this, Thank you
Answer:
liquid to gas, solid to liquid, and solid to gas are endothermic and belongs to first phase
gas to liquid, gas to solid, and liquid to solid are exothermic(heat are released) and belong to last phase
Explanation:
delta H= + delta S = +
this phase is endothermic and there is more randomness in the system
delta H= - and delta S = -
this phase is exothermic and there is less randomness in the system
