Physics College

Joanna leaves her home at 11:50 am. She travels 70 miles at an average speed of 13 m/s. At what time does she finish the journey.

Answers

Answer 1

Answer:

Joanna will finish her journey at approximately 2:18 pm.

Explanation:

We can use the formula:

distance = speed x time

to solve this problem.

First, we need to convert the average speed from m/s to miles per hour (mph) so that it is in the same unit as the distance traveled. We can do this by multiplying the speed in m/s by the conversion factor of 2.23694:

average speed = 13 m/s x 2.23694 = 29.08 mph

Now we can plug in the distance and average speed into the formula and solve for time:

distance = speed x time

70 miles = 29.08 mph x time

Solving for time:

time = distance / speed

time = 70 miles / 29.08 mph

time = 2.41 hours

Therefore, Joanna will finish her journey 2.41 hours after she leaves home at 11:50 am.

To find out the finishing time, we can add 2.41 hours to the starting time of 11:50 am using 12-hour clock notation:

11:50 am + 2.41 hours = 2:18 pm (rounded to the nearest minute)

Related Questions

A scuba tank, when fully submerged, displaces 14.4 L
of seawater. The tank itself has a mass of 12.6 kg
and, when "full," contains 4.21 kg
of air. Assuming only a weight and buoyant force act, determine the net force (magnitude) on the fully submerged tank at the beginning of a dive (when it is full of air).

Answers

The net force on the fully submerged scuba tank at the beginning of a dive is 18.484 N upward.

What is the net force on a fully submerged scuba tank at the beginning of a dive?

The net force acting on the fully submerged tank is equal to the difference between its weight and the buoyant force acting on it.

The weight of the tank can be calculated as the product of its mass and the acceleration due to gravity (9.81 m/s²):

weight = mass x gravity

weight = 12.6 kg x 9.81 m/s²

weight = 123.606 N

The buoyant force on the tank is equal to the weight of the seawater displaced by the tank. The displacement volume of the tank is given as 14.4 L. We can convert this to cubic meters, as follows:

1 L = 0.001 m³

14.4 L = 14.4 x 0.001 m³ = 0.0144 m³

The density of seawater is approximately 1025 kg/m³, so the weight of the displaced seawater can be calculated as follows:

weight of displaced seawater =

density x volume x gravity

weight of displaced seawater = 1025 kg/m³ x 0.0144 m³ x 9.81 m/s²

weight of displaced seawater = 142.09 N

Therefore, the buoyant force on the tank is equal to 142.09 N.

The net force on the fully submerged tank can now be calculated as follows:

net force = weight - buoyant force

net force = 123.606 N - 142.09 N

net force = -18.484 N

The negative sign indicates that the buoyant force is greater than the weight of the tank, so there is a net upward force on the tank.

To learn more about buoyant force, visit: https://brainly.com/question/17009786

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