The reaction time decreases as the temperature increases of the reaction mixture increases.
A sample record of results is:
Temperature (°C) Trial 1 Trial 2 Trial 3 Average25°C 11 seconds 11 seconds 11 seconds 11 seconds40°C 8 seconds 8 seconds 8 seconds 8 seconds60°C 5 seconds 5 seconds 5 seconds 5 seconds80°C 3 seconds 3 seconds 3 seconds 3 secondsWhat is the effect of an increase in temperature on reaction time?An increase in temperature leads to an increase in reaction rate or a decrease in reaction time.
The increase in temperature provides more thermal energy to the reactant molecules, which leads to an increase in the average kinetic energy of the molecules. As a result, more reactant molecules have sufficient energy to overcome the activation energy barrier and undergo successful collisions, leading to an increased reaction rate.
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The pressure of a sample of helium in a 1L container is .988 atm. What is the new pressure if the sample is placed in a 2L container?
Answer:
The new pressure will be 0.494 atm.
Explanation:
We can use the ideal gas law to solve this problem:
PV = nRT
where:
P is the pressureV is the volumen is the number of moles of gasR is the ideal gas constantT is the temperatureWe know that the initial pressure is 0.988 atm, the initial volume is 1 L, and the temperature is constant.
We also know that the final volume is 2 L.
We can solve for the final pressure as follows:
[tex]P_2 = \frac{P_1V_1}{V_2}[/tex]
substituting value
[tex]P_2 = \frac{0.988\: atm*1 L}{2 L}[/tex]
[tex]P_2 = 0.494 atm[/tex]
Therefore, the new pressure will be 0.494 atm.
Which formula represents an isomer of CH3− CH2− COOH?
CH3−C−OH−CH3
CH3−CO−O−CH3
CH3−CO−CO−CH3
CH3−CH2−CO2−CH3
The formula that represents an isomer of CH3−CH2−COOH is D. CH3−CH2−CO2−CH3.
An isomer is a compound that has the same molecular formula but differs in the arrangement or connectivity of its atoms. In this case, the molecular formula is CH3−CH2−COOH, which represents the carboxylic acid called propanoic acid.
Option D, CH3−CH2−CO2−CH3, is an isomer of propanoic acid. It represents methyl propanoate, an ester formed by the reaction of propanoic acid with methanol. In this isomer, the -COOH group of propanoic acid is replaced with -COOCH3 group, indicating the presence of an ester functional group.
Options A, B, and C do not represent isomers of CH3−CH2−COOH. Option A, CH3−C−OH−CH3, represents dimethyl ether, an entirely different compound. Option B, CH3−CO−O−CH3, represents dimethyl carbonate, which also has a different structure. Option C, CH3−CO−CO−CH3, represents a compound known as methyl propanoate, which is not an isomer but the same compound as option D. Therefore, option D is correct.
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