Biology College

Please answer the following 4 questions regarding genetics.

Please Answer The Following 4 Questions Regarding Genetics.

Answers

Answer 1

Answer:

1. Carol is heterozygous for hemophilia. Her husband does not carry the allele for hemophilia. What is the probability that they will have a daughter with hemophilia? A son with hemophilia?

Solution:

Since Carol is heterozygous for hemophilia, she has one X chromosome with the hemophilia allele and one X chromosome without the hemophilia allele. Her husband, who does not carry the allele, has one X chromosome without the allele and one Y chromosome.

The probability that they will have a daughter with hemophilia is 0, as the daughter would need to inherit the hemophilia allele from both parents, which is not possible in this case.

The probability that they will have a son with hemophilia is 50%, as the son will inherit the hemophilia allele from Carol (who passes one of her X chromosomes to her son) and the Y chromosome from his father.

2. Jake suffers from red-green colorblindness. He married Janet who is not colorblind nor a carrier. What is the probability that they will have a daughter with color blindness? A son with colorblindness?

Solution:

Jake suffers from red-green colorblindness, which means he has a recessive allele for the condition on his X chromosome. Janet is not colorblind nor a carrier, which means she has two normal X chromosomes.

The probability that they will have a daughter with color blindness is 0, as the daughter would need to inherit the recessive allele for color blindness from both parents, which is not possible in this case.

The probability that they will have a son with color blindness is 50%, as the son will inherit the recessive allele for color blindness from Jake (who passes his X chromosome to his son) and a normal copy of the X chromosome from Janet.

3. William suffers from hemophilia. He married Sandra who is a carrier of the trait. What is the probability they will have a son with the disorder?

Solution:

William has hemophilia, which means he has a recessive allele for hemophilia on his X chromosome. Sandra is a carrier of the trait, which means she has one normal X chromosome and one X chromosome with the hemophilia allele.

The probability that they will have a son with hemophilia is 50%, as the son has a 50% chance of inheriting the hemophilia allele from Sandra (who passes one of her X chromosomes to her son) and a 50% chance of inheriting the Y chromosome from William.

4. Which of the following could be the parents of a colorblind female?

a) A normal male and a normal female (not a carrier)

b) A normal male and a female carrier

c) A colorblind male and a normal female (not a carrier)

d) A colorblind male and a female carrier

Solution:

A colorblind female can only occur if she inherits the recessive allele for color blindness onboth of her X chromosomes. Therefore, the only possible parents of a colorblind female are a colorblind male and a female carrier (option d).

Option a is not possible because both parents are normal and do not carry the color blindness allele. Option b is not possible because the female carrier would need to pass on the recessive allele for color blindness to the daughter, which is not possible as the daughter would inherit a normal X chromosome from the father. Option c is not possible because a normal female cannot carry the recessive allele for color blindness.

Hope this helps!

Answer 2

For any recessive disease to occur it is necessary that both the recessive alleles are expressed in the individual. 1) probability of a hemophilic daughter is 0  and a son is 50%. 2) Probability of a color-blind son is 50% and a daughter is 0. Hemophilic son - 50 %. 4) Option D is correct.

1) The probability that they will have a hemophilic daughter is zero. This is because to express the hemophilic trait one allele of the trait must be inherited from both the parents, but here the mother is a carrier while the father does not carry any allele for the disease.

The probability that they will have a hemophilic son is 50%. This is because he will inherit an X chromosome from his mother who is a carrier of the disease and one Y chromosome from his father.

2) The likelihood of having a color-blind daughter is 0 because the daughter would have to inherit the color-blind recessive allele from both parents.

The likelihood of having a color-blind son is 50% because the son inherits the color-blind recessive allele from Jake (through his X chromosome) and the normal X chromosome from Janet.

3) The likelihood of having a hemophiliac son is 50% because the son inherits 50% of the hemophilia gene from Sandra (passing one of her X-chromosomes to the son) and 50% of the Y-chromosome gene from William.

4) A colorblind woman can only become a colorblind woman if she has a recessive gene for color blindness in both her X-chromosomes. So, the only parents of a female who is colorblind are male and female carriers of the recessive gene.

To learn more about probability, refer to the link:

https://brainly.com/question/30034780

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