please guys I need all the help

The solution of the equation x²-30 x+225=400 is x = 15 and x = -15. We can solve the equation by subtracting 400 from both sides and then factoring the left side. We have:

x²-30 x+225-400 = 400-400

=> x²-30 x-175 = 0

=> (x-25)(x+7) = 0

This means that either x-25 = 0 or x+7 = 0. Solving for x, we get x = 25 or x = -7.

However, we need to check our solutions to make sure that they satisfy the original equation. When we substitute x = 25, we get 25² - 30 x 25 + 225 = 625 - 750 + 225 = 0, which satisfies the original equation. When we substitute x = -7, we get (-7)² - 30 x (-7) + 225 = 49 + 210 + 225 = 584, which does not satisfy the original equation.

Therefore, the only solution of the equation is x = 25.

To check our solution, we can substitute x = 25 back into the original equation. We have:

x²-30 x+225=400

=> (25)²-30 x(25)+225=400

=> 625-750+225=400

=> 0=400

As we can see, the solution satisfies the original equation.

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The statement that is true about the diagram include the following:

A. ΔCAB ≅ ΔDAB by SSS.

In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.

Additionally, the lengths of three (3) pairs of corresponding sides or corresponding side lengths are proportional to the lengths of corresponding altitudes when two (2) triangles are similar.

Based on the side, side, side (SSS) similarity theorem, we can logically deduce the following congruent and similar triangles:

ΔCAB ≅ ΔDAB

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a-1 ROP ≈ 25.48 gallons

a-2 Days of Supply ≈ 11.51 days

b-1 Order Size ≈ -4.52 gallons

b-2 P(stockout) ≈ 65%

c the probability that the dairy will run out of walnut fudge ice cream before the shipment arrives is 100%.

a-1. ROP (Reorder Point):

The formula for ROP is ROP = (Z * σL) + d, where Z is the Z-value corresponding to the desired service level, σL is the standard deviation of demand during lead time, and d is the average demand during lead time.

Mean demand (μ) = 21 gallons per week

The standard deviation of demand (σ) = 3.5 gallons per week

Service level (SL) = 90% (which corresponds to a Z-value of 1.28 for a normal distribution)

ROP = (Z * σL) + d

ROP = (1.28 * 3.5) + 21

ROP ≈ 25.48 gallons (rounded to 2 decimal places)

a-2. Days of Supply at ROP:

Average demand per day (d_avg) = μ / 7 (since the dairy is open 7 days a week)

Days of Supply = ROP / d_avg

Days of Supply ≈ 25.48 / (21 / 7)

Days of Supply ≈ 11.51 days (rounded to 2 decimal places)

b-1. Order Size for Fixed-Interval Model:

The formula for order size in a fixed-interval model is Order Size = R - (d_avg * T), where R is the reorder point, d_avg is the average demand per day, and T is the order interval in days.

Reorder Point (R) = ROP calculated in part a-1 = 25.48 gallons

Average demand per day (d_avg) = μ / 7 = 21 / 7 = 3 gallons per day

Order interval (T) = 10 days

Order Size = R - (d_avg * T)

Order Size = 25.48 - (3 * 10)

Order Size ≈ 25.48 - 30

Order Size ≈ -4.52 gallons (rounded to the nearest whole number)

Note: The calculated order size is negative, which means no order is needed for the given conditions.

b-2. Probability of Stockout in Fixed-Interval Model:

The formula for the probability of stockout in a fixed-interval model is P(stockout) = 1 - [1 - P(daily stockout)]^T, where P(daily stockout) is the probability of stockout on any given day.

P(daily stockout) = 1 - SL = 1 - 0.9 = 0.1 (from the desired service level)

Calculating:

P(stockout) = 1 - [1 - P(daily stockout)]^T

P(stockout) = 1 - [1 - 0.1]^10

P(stockout) ≈ 0.6513 (rounded to the nearest whole percent)

P(stockout) ≈ 65% (rounded to the nearest whole percent)

c. Probability of Running Out Before Shipment Arrives:

To calculate the probability of running out before the shipment arrives, we need to use the cumulative distribution function (CDF) of the normal distribution.

Given:

Lead time = 2 days

Demand during the lead time (d_L) = 2 gallons

Calculating:

Probability of Running Out = P(X > d_L)

Probability of Running Out = P(X > 2), where X follows a normal distribution with μ and σ provided

Probability of Running Out = 1 - P(X ≤ 2)

Probability of Running Out ≈ 1 - P(Z ≤ (2 - μ) / σ), using standardization

Probability of Running Out ≈ 1 - P(Z ≤ (2 - 21) / 3.5)

Probability of Running Out ≈ 1 - P(Z ≤ -5.29)

Probability of Running Out ≈ 1 - 0

Probability of Running Out ≈ 1

Therefore, the probability that the dairy will run out of walnut fudge ice cream before the shipment arrives is 100%.

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The solution of the given Linear equation y/2 - 7=5  is y=24

We have provided an equation

y/2-7= 5

In order to find the value of y from the given equation, we have to multiply 2 on both sides of the equation so that we can eliminate the fraction

2(y/2-7)=2×5

Solving the above equation we obtain:

2×y/2 - 2×7 = 2×5

Simplifying the above equation:

y - 14 = 10

Now add 14 on both sides of the equation  so that we can  separate the y term in the given equation:

y -14 +14= 10+14

Solving the above equation we get:

y = 10+14

y = 24

Therefore, the required solution of the given equation y/2-7=5 is

y=24

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Nathalie made 44 necklaces last month.

Let's solve the problem step by step:

Let's assume that Nathalie made x necklaces last month. According to the problem, Aaron made 14 fewer necklaces than Nathalie, so Aaron made (x - 14) necklaces.

The total number of necklaces made by Nathalie and Aaron is given as 74. So we can write the equation:

x + (x - 14) = 74

Combining like terms, we get:

2x - 14 = 74

Adding 14 to both sides of the equation:

2x = 74 + 14

2x = 88

Dividing both sides by 2:

x = 44

Therefore, Nathalie made 44 necklaces last month.

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When Pc = $1, the budget constraint is C + 0.25S = 12. The graph will have a horizontal intercept at C = 12 and a vertical intercept at S = 48.

When Pc = $2, the budget constraint is 2C + 0.25S = 12. The graph will have a horizontal intercept at C = 6 and a vertical intercept at S = 48.

When Pc = $3, the budget constraint is 3C + 0.25S = 12. The graph will have a horizontal intercept at C = 4 and a vertical intercept at S = 48.

Let's start with Pc = $1:

Since Susan has $12 to spend, we can express her budget constraint as follows:

Pc * C + PS * S = M

$1 * C + $0.25 * S = $12

To find the maximum number of cups of coffee, C, we'll set S = 0 and solve for C:

$1 * C + $0.25 * 0 = $12

C = 12

Similarly, to find the maximum number of spoonfuls of sugar, S, we'll set C = 0 and solve for S:

$1 * 0 + $0.25 * S = $12

S = 48

Next, let's consider Pc = $2:

Using the same process, we can find the maximum values of C and S:

$2 * C + $0.25 * S = $12

Setting S = 0, we find:

$2 * C + $0.25 * 0 = $12

C = 6

Setting C = 0, we find:

$2 * 0 + $0.25 * S = $12

S = 48

Finally, let's consider Pc = $3:

$3 * C + $0.25 * S = $12

Setting S = 0, we find:

$3 * C + $0.25 * 0 = $12

C = 4

Setting C = 0, we find:

$3 * 0 + $0.25 * S = $12

S = 48

Now, let's plot these budget constraints on a graph with C (number of cups of coffee) on the horizontal axis and S (number of spoonfuls of sugar) on the vertical axis.

css

Copy code

        |

   48   |    A

        |

        |

   24   |

        |

        |

   12   |           B

        |

        |

    0   |__|__|__|__|__|__|__|__|__|__|

        0  4  6  12 16 20 24 28 32 36 40

Here, point A represents the budget constraint for Pc = $1 (C + 0.25S = 12), and point B represents the budget constraint for Pc = $2 (2C + 0.25S = 12). The curve starts at (12, 0) and slopes downwards.

Since the third budget constraint for Pc = $3 (3C + 0.25S = 12) intersects the previous two budget constraints, we'll draw a dotted line to represent it:

css

Copy code

        |

   48   |    A

        |    |

        |   /

   24   |  /

        | /

        |/

   12   |           B

        |

        |

    0   |__|__|__|__|__|__|__|__|__|__|

        0  4  6  12 16 20 24 28 32 36 40

To find Susan's optimal bundle on each budget constraint, we'll look for the point of tangency (highest indifference curve) between the budget constraint and the indifference curves. Unfortunately, without additional information about Susan's preferences, we can't determine her exact preferences and optimal bundle.

Note: The graph above is a basic representation of Susan's price consumption curve, but it may not be perfectly accurate due to limitations in text-based formatting.

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Answer: 2 hours and 42 minutes < 0.1 days 8370 seconds < 3 hours 138 minutes

Step-by-step explanation: 1 hour = 60 minutes, 60 seconds = 1 minute, 1 day = 24 hours

2 hours and 42 minutes is 2×60 minutes + 42 minutes = 162 minutes

0.1 day 8370 seconds is 0.1×24 hours and 8370/60 minutes = 2.4 hours and 139.5 minutes = 2×60 minutes + 0.4×60minutes + 139.5 minutes=283.5 minutes

3 hours and 138 minutes is 3×60 minutes + 138 minutes = 328 minutes

Hence,

2 hours and 42 minutes < 0.1 days 8370 seconds < 3 hours 138 minutes

Null Hypothesis (H₀): The mean weight of the flounder is less than or equal to grams.

Alternate Hypothesis (H₁): The mean weight of the flounder is greater than grams.

In this scenario, the scientists want to perform a hypothesis test to determine the strength of evidence regarding the mean weight of a certain species of flounder being greater than a certain value (let's call it "grams").

The appropriate null and alternative hypotheses can be stated as follows:

Null Hypothesis (H₀): The mean weight of the flounder is equal to or less than grams.

Alternate Hypothesis (H₁): The mean weight of the flounder is greater than grams.

In symbol form:

H₀: μ ≤ grams

H₁: μ > grams

The null hypothesis (H₀) represents the assumption that there is no significant difference between the mean weight of the flounder and the specified value (grams). The alternative hypothesis (H₁) suggests that there is evidence to support that the mean weight of the flounder is greater than grams.

During the hypothesis testing process, the scientists will collect a sample of flounder and perform statistical calculations to determine whether the evidence supports rejecting the null hypothesis in favor of the alternative hypothesis.

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To evaluate (f+g)(-4) and (g*f)(2), we substitute the given values of x into the functions f(x) and g(x), perform the respective operations, and compute the results.

First, let's evaluate (f+g)(-4). We substitute x = -4 into the functions f(x) and g(x). For f(x), we have f(-4) = -3((-4)-2)² - 1 = -3(-6)² - 1 = -3(36) - 1 = -108 - 1 = -109. For g(x), we have g(-4) = (2(-4) + 3) / (-4 + 5) = (-8 + 3) / 1 = -5.

To find (f+g)(-4), we add the results of f(-4) and g(-4): (-109) + (-5) = -114.

Next, let's evaluate (g*f)(2). We substitute x = 2 into the functions f(x) and g(x). For f(x), we have f(2) = -3((2)-2)² - 1 = -3(0)² - 1 = -3(0) - 1 = -1. For g(x), we have g(2) = (2(2) + 3) / (2 + 5) = (4 + 3) / 7 = 7/7 = 1.

To find (g*f)(2), we multiply the results of g(2) and f(2): (1) * (-1) = -1.

In conclusion, (f+g)(-4) = -114 and (g*f)(2) = -1, according to the given functions f(x) and g(x). By substituting the values of x into the functions, performing the respective operations, and computing the results, we obtain these values.

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The probability of a student taking neither math nor science can be calculated by subtracting the probability of taking either math or science, or both, from 1.

P(taking neither math nor science) = 1 - P(taking math) - P(taking science) + P(taking both math and science)

P(taking neither math nor science) = 1 - (95/147) - (73/147) + (52/147)

P(taking neither math nor science) ≈ 0.119

In this problem, we are given the total number of students in the class (147) and the number of students taking math (95), science (73), and both math and science (52).

To find the probability of a student taking neither math nor science, we need to consider the students who are not taking math or science. This can be done by subtracting the probability of taking either math or science, or both, from 1.

The probability of taking math is 95 out of 147 students, so P(taking math) = 95/147.

Similarly, the probability of taking science is 73 out of 147 students, so P(taking science) = 73/147.

The probability of taking both math and science is 52 out of 147 students, so P(taking both math and science) = 52/147.

To calculate the probability of taking neither math nor science, we subtract the sum of the probabilities mentioned above from 1:

P(taking neither math nor science) = 1 - P(taking math) - P(taking science) + P(taking both math and science)

P(taking neither math nor science) = 1 - (95/147) - (73/147) + (52/147)

P(taking neither math nor science) ≈ 0.119

Therefore, the probability of a randomly selected student taking neither math nor science is approximately 0.119 or 11.9%.

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Given the values P = $120,000 (principal), r = 5.5% (interest rate), t = 20 (time in years), and m = 2 (compounding periods per year), we can calculate the future value using the compound interest formula.

The formula for compound interest is A = P * (1 + r/m)^(m*t), where A is the future value. By substituting the provided values into the formula, we can determine the future value after 20 years with semi-annual compounding. To find the future value, we can use the compound interest formula: A = P * (1 + r/m)^(m*t)

Given P = $120,000, r = 5.5%, t = 20 years, and m = 2 (compounding periods per year), we can calculate the future value as follows: A = $120,000 * (1 + 0.055/2)^(2*20). Simplifying the expression inside the parentheses: A = $120,000 * (1 + 0.0275)^(40)
Evaluating the exponent: A = $120,000 * (1.0275)^40

By calculating the value of (1.0275)^40, we can determine the future value after 20 years with semi-annual compounding.

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In a competitive market, we need to graph the market demand and supply curves and determine the equilibrium quantity. The equilibrium quantity represents the quantity at which the demand and supply curves intersect.

To sketch the supply and demand curves, we first need to gather information on the market demand and supply. The demand curve represents the quantity of ventilators that the four hospitals are willing to purchase at different prices, while the supply curve represents the quantity of ventilators that the four producers are willing to sell at different prices.

Using the multipoint drawing tool, we can plot the market demand curve based on the data provided for the hospitals. Label this line as 'Demand'. Next, using the same tool, we can plot the market supply curve based on the data provided for the producers. Label this line as 'Supply'.

The equilibrium quantity is determined at the point where the demand and supply curves intersect. It represents the quantity of ventilators that will be sold in the market. To find this point, we identify the quantity at which the demand and supply curves meet on the graph.

By following the instructions and accurately plotting the demand and supply curves, we can determine the equilibrium quantity of ventilators sold in the market.

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The tax rate on the business office was 0.08. To calculate the tax rate, we divide the property taxes by the value of the property.

In this case, the property taxes were $2160 and the value of the property was $270,000. Therefore, the tax rate is 0.08.

Tax rate = Property taxes / Value of property

= $2160 / $270,000

= 0.08

The first step is to divide the property taxes by the value of the property. This gives us a decimal value of 0.08.

The second step is to convert the decimal value to a percentage by multiplying it by 100%. This gives us the final answer of 8%.

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The standard form of function f(x) = 4(x + 6)² + 5 can be written as:

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2.

The quadratic function is given below.

[tex]f(\text{x}) = 4(\text{x} + 6)^2+ 5[/tex]

Convert the equation into a standard form. Then we have

[tex]\rightarrow f(\text{x}) = 4(\text{x} + 6)^2+ 5[/tex]

[tex]\rightarrow f(\text{x}) = 4(\text{x}^2 + 12\text{x} + 36)+ 5[/tex]

[tex]\rightarrow f(\text{x})=4\text{x}^2+48\text{x}+144+5[/tex]

[tex]\rightarrow\bold{f(x)=4x^2+48x+149}[/tex]

Thus, the standard form of function f(x) = 4(x + 6)² + 5 is written by f(x) = 4x² + 48x + 149.

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To determine the number of smaller boxes that would contain the same amount of cereal as a larger box, we set the expressions representing the cereal content equal to each other. Solving the equation, we find that 15 smaller boxes are required to match the cereal quantity in the larger box.

To find the number of smaller boxes that equal the same amount of cereal in a larger box, we need to equate the two expressions and solve for n.

Setting the expressions equal to each other:

10 + 6.3n = 7 + 6.5n

Simplifying the equation:

6.3n - 6.5n = 7 - 10

-0.2n = -3

Dividing both sides by -0.2:

n = -3 / -0.2

n = 15

Therefore, 15 smaller boxes would equal the same amount of cereal as the larger box.

The problem states that the expressions 10 + 6.3n and 7 + 6.5n represent the amount of cereal in the new larger box. The variable n represents the number of smaller boxes.

To find how many smaller boxes are equivalent to the larger box, we need to set the two expressions equal to each other and solve for n. This equation represents the balance between the amount of cereal in the larger box and the combined amount of cereal in the smaller boxes.

By simplifying the equation and solving for n, we find that 15 smaller boxes are needed to equal the same amount of cereal as the larger box.

This means that if the cereal manufacturer wants to package the same amount of cereal as the larger box, they would need to use 15 smaller boxes instead. This calculation helps the manufacturer determine the number of smaller boxes needed to maintain the same quantity of cereal while changing the box size.

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The trigonometric ratio of cosX can be expressed as a fraction and as a decimal to the nearest hundredth.

In triangle XYZ, where angle X is involved, we can determine the value of cosX by considering the given side lengths of the triangle.

Given: XY = 15, YZ = 9, XZ = 12

To find the value of cosX, we use the cosine function, which relates the adjacent and hypotenuse sides of a right triangle.

Formula: cosX = adjacent / hypotenuse

In this case, the adjacent side is YZ and the hypotenuse is XZ. Therefore, the ratio cosX can be written as:

cosX = YZ / XZ

To express the ratio as a fraction, we substitute the given values:

cosX = 9 / 12

Simplifying the fraction, we get:

cosX = 3 / 4

Thus, the ratio cosX can be expressed as the fraction 3/4.

To find the decimal value of cosX, we divide the numerator (3) by the denominator (4):

cosX ≈ 0.75 (rounded to the nearest hundredth).

Therefore, the ratio of cosX as a fraction is 3/4, and as a decimal, it is approximately 0.75.

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Question:Express ratio as a fraction and as a decimal to the nearest hundredth. cosX. In  triangle XYZ right angled at Z with XY = 15, YZ = 9, XZ = 12

The amount of inventory that Baryla can hold is **$16.1 million**.

The inventory turnover ratio is calculated as sales / inventory. To maintain an inventory turnover ratio of at least 5.6, Baryla's inventory must be no more than $90 million / 5.6 = $16.1 million.

Calculation:

```

sales = $90 million

gross profit margin = 35%

inventory turnover ratio = 5.6

inventory = sales / inventory turnover ratio = $90 million / 5.6 = $16.1 million

```

**b. Currently, some of Baryla's inventory includes $1.5 million of outdated and damaged goods that simply remain in inventory and are not salable. What inventory turnover ratio must the good inventory maintain in order to achieve an overall turnover ratio of at least 5.6 (including the unsalable items)?**

The good inventory must maintain an inventory turnover ratio of **9.4 times** in order to achieve an overall turnover ratio of at least 5.6.

The overall inventory turnover ratio is 5.6, and the unsalable inventory is $1.5 million. This means that the good inventory is $90 million - $1.5 million = $88.5 million.

The good inventory must maintain an inventory turnover ratio of $88.5 million / 5.6 = **9.4 times** in order to achieve an overall turnover ratio of at least 5.6.

overall inventory turnover ratio = 5.6

unsalable inventory = $1.5 million

good inventory = $90 million - $1.5 million = $88.5 million

good inventory turnover ratio = $88.5 million / 5.6 = 9.4 times

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The robot has three possible safe routes to the charging station, given that it must avoid the bomb at (2,1).

To calculate the number of routes, we can use combinatorics. The robot needs to move a total of 3 steps to reach the charging station, 2 steps to the north and 1 step to the east. We can represent these steps as a combination of N's (for north) and E's (for east).

The possible combinations are:

1. NNE: The robot moves north twice and then east once.

2. NEN: The robot moves north, then east, and finally north again.

3. ENN: The robot moves east, then north, and finally north again.

Therefore, there are three possible safe routes for the robot to reach the charging station.

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The minimum value of y occurs when x is at its maximum, which is infinity in this case. Similarly, the maximum value of y occurs when x is at its minimum, which is -2. Therefore, the range of the function is (-∞, 9(-2) - 2] or (-∞, -20].

The range of the function y = 9x - 2, where x > -2, can be determined by finding the minimum and maximum values of y for the given domain.

To find the minimum and maximum values of y, we substitute the respective values of x into the function. When x is infinity, y = 9(infinity) - 2, which is also infinity. When x is -2, y = 9(-2) - 2, which simplifies to -20. Hence, the range of the function is (-∞, -20].

In summary, the range of the function y = 9x - 2, where x > -2, is (-∞, -20]. The minimum value of y is -20, and there is no maximum value as it goes to infinity.

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The equation of tangent plane is -x + 2x - 1 = 0

Given,

r = < u² , 8usinv , ucosv >

Here,

r = < u² , 8usinv , ucosv >

Differentiate partially with respect to u and v,

[tex]r_{u}[/tex] = < 2u , 8sinv , cosv >

[tex]r_{v}[/tex] = < 0, 8ucosv , -4sinv >

Substitute u = 1 and v = 0

[tex]r_{u}[/tex] = < 2, 0 , 0 >

[tex]r_{v}[/tex] = < 0 , 8 , 0 >

Now,

N = [tex]r_{u}[/tex] × [tex]r_{v}[/tex]

N = [tex]\left[\begin{array}{ccc}i&j&k\\2&0&1\\0&8&0\end{array}\right][/tex]

N = -8i -j(0) +16k

N = < -8 , 0 , 16 >

Tangent plane

-8x + 16z + d = 0

Coordinates of tangent plane : <1, 0 ,1>

Substitute the values in the equation,

-8(1) + 16 (1) + d = 0

d = -8

Substitute in the tangent plane equation,

-8x + 16z - 8 = 0

-x + 2x - 1 = 0

Thus equation of tangent plane: -x + 2x - 1 = 0

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The place value of the digit 6 when it is moved one place to the left in the number 18,564 is the hundreds place.

To determine the place value of the digit 6 when it is moved one place to the left in the number 18,564, we need to understand the concept of place value in our number system.

In the given number, 18,564, each digit represents a specific place value based on its position. Starting from the rightmost digit, the place values increase by powers of 10 as we move towards the left.

Let's analyze the number 18,564 to find the place value of the digit 6 when it is moved one place to the left.

1. Write down the number: 18,564

2. Identify the digit 6: It is located in the thousands place (the fourth digit from the right).

3. Move the digit 6 one place to the left: This means we need to divide the number by 10. The resulting number is 1,856.4 (since the decimal point moves along with the digits).

4. Determine the new place value of the digit 6: After moving the digit one place to the left, the digit 6 now occupies the hundreds place (the third digit from the right) in the number 1,856.4.

Therefore, the place value of the digit 6 when it is moved one place to the left in the number 18,564 is the hundreds place.

In summary, when the digit 6 is moved one place to the left in the number 18,564, its new place value becomes the hundreds place in the resulting number 1,856.4.

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To simplify the expression[tex]³√(7x) / ³√(5y²),[/tex] we can combine the radicals and rationalize the denominator. First, we notice that both the numerator and the denominator have the same index, which is ³√(cube root).

Therefore, we can combine the two radicals into a single radical by dividing the indices and keeping the base. This gives us ³√((7x)/(5y²)). Next, to rationalize the denominator, we multiply both the numerator and the denominator by the cube root of the denominator, which is ³√(5y²). This results in

[tex](³√((7x)/(5y²))) * (³√(5y²))/(³√(5y²))[/tex]. Simplifying the expression, we get [tex]³√((7x * 5y²)/(5y² * 5y²)),[/tex]which simplifies to [tex]³√((35xy²)/(25y⁴)).[/tex]  [tex]³√((35xy²)/(25y⁴)).[/tex]

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The Conjecture is that the sum of the measures of the angles of a polygon with n sides is equal to (n-2) times 180 degrees.

When we consider a polygon, we can divide it into (n-2) triangles by drawing diagonals from one vertex to the other non-adjacent vertices. Each triangle has an interior angle sum of 180 degrees. Since there are (n-2) triangles in a polygon with n sides, the total sum of the interior angles would be (n-2) times 180 degrees.

Therefore, the conjecture suggests that the sum of the measures of the angles of a polygon with n sides is equal to (n-2) times 180 degrees.

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The quadratic equation x² + 6x - 7 = 0 has two real solutions: x = 1 and x = -7. To evaluate the discriminant of the quadratic equation x² + 6x - 7 = 0, we can use the formula:

Discriminant (D) = b² - 4ac

In this equation, a = 1, b = 6, and c = -7. Substituting these values into the discriminant formula, we have:

D = (6)² - 4(1)(-7)

  = 36 + 28

  = 64

The discriminant is 64.

Now, let's analyze the number of solutions based on the value of the discriminant:

1. If the discriminant (D) is positive (D > 0), the quadratic equation has two distinct real solutions.

2. If the discriminant (D) is zero (D = 0), the quadratic equation has one real solution (a repeated root).

3. If the discriminant (D) is negative (D < 0), the quadratic equation has no real solutions but two complex (imaginary) solutions.

In this case, the discriminant is positive (D = 64), which means the quadratic equation x² + 6x - 7 = 0 has two distinct real solutions.

The exact solutions can be found by applying the quadratic formula:

x = (-b ± √D) / (2a)

Substituting the values a = 1, b = 6, c = -7, and D = 64, we get:

x = (-6 ± √64) / (2 * 1)

 = (-6 ± 8) / 2

Simplifying, we have:

x₁ = (-6 + 8) / 2 = 1

x₂ = (-6 - 8) / 2 = -7

Therefore, the quadratic equation x² + 6x - 7 = 0 has two real solutions: x = 1 and x = -7.

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The cost of each nail polish in the problem given is $3.5

Using the parameters given, we can set up our equation thus :

Hence, cost of each bag would be :

Which can be simplify written as

All bags cost = 7(5 + 4x)

133 = 35 + 28x

133 - 35 = 28x

98 = 28x

x = 3.5

Therefore, each nail polish cost $3.5

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a) If x represents the number of phones produced and sold, an expression for cell production's weekly total cost, C is 13,000 + 19.50x.

b) An expression for the total revenue, R is 65.50x.

c) The expression for Cell Pro's weekly profit, P is 65.50x - 13,000 + 19.50x or 46x - 13,000.

The total cost expression involves the fixed cost and the variable cost.

While the fixed cost remains constant in total over a relevant period, the variable cost varies in total but remains constant per unit.

Weekly fixed cost for rent, utilities, and equation = $3,000

Labor and material costs (variable) per phone = $16.50

Let the number of phones produced per week = x

a) Total cost, C = 13,000 + 19.50x

Selling price per unit = $65.50

b) Total revenue, R = 65.50x

c) Profit, P = 65.50x - 13,000 + 19.50x

or P = 46x - 13,000

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Cell Pro makes cell phones and has weekly costs of $3000 for rent, utilities, and equipment plus labor and material costs of $16.50 for each phone it makes.

(a) If x represents the number of phones produced and sold, write an expression for Cell Pro's weekly total cost C.

(b) If Cell Pro sells the phones to dealers for $65.50 each, write an expression for the weekly total revenue R for the phones R=

(c) Cell Pro's weekly profit P is the total revenue minus the total cost. Write an expression for Cell Pro's weekly profit.

Science allows us to make quantitative predictions by describing phenomena using scientific models. The first phenomena to be quantitatively described by scientific models were those related to motion and celestial bodies.

In the early days of scientific inquiry, the study of motion and celestial bodies played a crucial role in the development of quantitative descriptions. Scientists like Galileo Galilei and Sir Isaac Newton made significant contributions in this area. They formulated mathematical equations and laws that accurately described the motion of objects on Earth and the movement of celestial bodies in space.

By carefully observing and conducting experiments, scientists were able to develop mathematical models that quantitatively described the behavior of objects in motion. For example, Newton's laws of motion provided a framework for predicting the position, velocity, and acceleration of objects based on the forces acting upon them. Similarly, Kepler's laws of planetary motion allowed astronomers to predict the motion of planets and other celestial bodies with great precision.

Through the quantitative descriptions of motion and celestial phenomena, scientists were able to establish the foundation of scientific inquiry and pave the way for further advancements in various fields of study. These early models provided a framework for making predictions and understanding the underlying principles governing the natural world.

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The solution to the system of equations is x = 0 and y = -1.

To solve the system of equations:

y = x² - 2x - 1

y = -x² - 2x - 1

We can set the two equations equal to each other since they both equal to y:

x² - 2x - 1 = -x² - 2x - 1

x² - 2x - 1 + x² + 2x + 1 = 0

Combine like terms:

2x² = 0

Divide both sides by 2:

x² = 0

Taking the square root of both sides:

x = 0

Now, substitute the value of x back into one of the original equations

y = (0)² - 2(0) - 1

y = -1

So, the solution to the system of equations is x = 0 and y = -1.

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It's essential to analyze the specific table and pattern to determine the correct expression for calculating s(n).

To find the expression for the values of s(n) in the given table, we need to identify a pattern or relationship between the input variable (n) and the corresponding output variable (s(n)).

Without the specifics of the table or the values provided, it is difficult to give an exact expression. However, I can provide you with a general formula that can be used to calculate the values of s(n) in a table if there is a consistent pattern:

s(n) = f(n)

In this expression, f(n) represents the function or mathematical operation that relates the input variable (n) to the output variable (s(n)). The specific form of f(n) will depend on the pattern observed in the table.

For example, if the numbers in the table follow a linear sequence, the expression may involve multiplication and addition:

s(n) = a * n + b

Where 'a' and 'b' are constants that determine the slope and intercept of the linear relationship.

If the numbers in the table follow a geometric sequence, the expression may involve exponentiation:

s(n) = a * r^n

Where 'a' is the initial term and 'r' is the common ratio.

It's essential to analyze the specific table and pattern to determine the correct expression for calculating s(n).

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To write 8% as a decimal, you can divide it by 100: 8% = 8/100 = 0.08 (decimal). To write 8% as a percent, you simply express it as a whole number with the '%' symbol: 8% (percent)

To write 8% as a decimal, you divide it by 100 because percent means "per hundred." So, you take the value of 8 and divide it by 100:

8% = 8/100

Simplifying the fraction, you get 0.08. Therefore, 8% as a decimal is equal to 0.08.

To express 8% as a percent, you simply write it as a whole number followed by the '%' symbol. In this case, 8% (percent) represents the value of 8 parts out of 100, or 8 per hundred.

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