please help find the measure of the angle indicated ​

Answer:

Let x = number of dimes

y = number of quarters

Equation 1 is then x + y = 100, that one is easy.

Now you have to worry about values of each, and since a dime is $0.10 and a quarter is $0.25, that means that the number of each times their respective dollar amounts has to add up to the total dollar amount.

Equation 2 is then 0.1x + 0.25y = 14.05

To rewrite for clarity you have:

x + y = 100 (1)

0.1x + 0.25y = 14.05 (2)

Now you can solve this any number of ways, I'm going to use addition by multiplying both sides of equation 1 by -1/10 and then adding it to equation 2.

-0.1x - 0.1y = -10

0.1x + 0.25y = 14.05

0.15y = 4.05

don't let the decimals trip you up, that's the same as

15y = 405

y = 27 quarters

Now use that value in the original equation 1 to get

x = 100 - 27 = 73 dimes

To check use the values in the equation 2

$0.1*(73) + $0.25*(27) = $14.05

$7.30 + $6.75 = $14.05

Answer:

Below

Step-by-step explanation:

Since S = πr², then r=√{S/π)=2.3942

Answer:

1053.7$

Step-by-step explanation:

750$ x 12%= 90

first year: 750 + 90 = 840

840$ x 12%= 100.8$

second year: 840+ 100.8= 940.8

940.8$ x 12%= 112.896

third year (now)= 940.8+ 112.896 = 1053.696$

Answer:

Not a function.

Step-by-step explanation:

Due to the fact that an element from the first set of components is associated with one and only one element from the other. In this case, as it is a circumference, the elements match with more than one element of the other set. I'll give you an example.

Note: I've tried to keep it as simple as possible, and I'm not natively English so I don't really know how some things are mentioned, but I've also made a picture representation and I think it simplifies.

Answer:

O 7x2 + 3y2 - 4x

.........

[tex]\qquad \qquad\huge \underline{\boxed{\sf ᴀɴsweʀ}}[/tex]

The Correct choice is ~ A

[tex]\qquad \sf  \dashrightarrow \: 7 {x}^{2} + 3 {y}^{2} - 4x[/tex]

[tex]\large \boxed{ \mathrm{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

[tex]\sf  \dashrightarrow \:(12 {x}^{2} - 11y { }^{2} - 13x) - (5 {x}^{2} - 14y { }^{2} - 9x)[/tex]

[tex]\sf  \dashrightarrow \:12 {x}^{2} - 11y { }^{2} - 13x- 5 {x}^{2} + 14y { }^{2} + 9x[/tex]

[tex] \sf  \dashrightarrow \: 12 {x}^{2} - 5 {x}^{2} - 11y { }^{2} + 14 {y}^{2} - 13x + 9 [/tex]

[tex]\sf  \dashrightarrow \: 7 {x}^{2} + 3 {y}^{2} - 4x[/tex]

Answer:

The probability of an event happening is desired outcome/sample space.

For our sample space, it’s just the number of numbers: 20.

The outcome you want has some overlap: 6. 12. 18. So, we’ll subtract these as they fit both criteria.

Even numbers: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20 (10 numbers)

Multiples of 3: 3, 6, 9, 12, 15, 18 (6 numbers)

Pr(A or B) = Pr(A) + Pr(B) - Pr(overlap, also known as A intersect B)

Pr(even or mult. of 3) = 10/20 + 6/20 - 3/20 (the overlap)

= 13/20.

So, there is a 65% of you picking an even number or a multiple of three.

Step-by-step explanation:

Hopes this helps. <3

Answer:

70 minutes which is 1 hour and 10 minutes

Answer:

25 minutes I believe. . .

Answer:

1. Acute

2. Obtuse

3. Isosceles

Answer:

6 hours you're welcome owo

The value of x is 10.

By the converse of the side-splitter theorem;

If  [tex]\rm \dfrac{JK}{KL}[/tex] then, KM||JN.

If a line is parallel to one side of the triangle and intersects the other 2 sides, it divides the sides proportionally.

If a line is drawn parallel to one side of the triangle, then it divides the other two sides in the same ratio.

KM || JN

[tex]\rm \dfrac{JK}{KL}= \dfrac{NM}{ML}\\\\[/tex]

Where JK = x-5, KL = x-3, NM = x, and KL = x+4.

Substitute all the values in the equation

[tex]\rm \dfrac{JK}{KL}= \dfrac{NM}{ML}\\\\ \dfrac{x-5}{x-3} = \dfrac{x}{x+4}\\\\(x-5) (x+4) = x(x-3)\\\\x^2+4x-5x-20 = x^2-3x\\\\x^2-x-20-x^2+3x=0\\\\2x-20=0\\\\2x = 20\\\\x = \dfrac{20}{2}\\\\x=10[/tex]

Hence, the value of x is 10.

To know more about the side-splitter theorem click the link given below.

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Answer:

NM/ML

x+4

20

10

Step-by-step explanation:

just did it

-edge 2022

The difference in price per passenger for a group of 16 versus a group of 10 is $26.25.

Given

A group of friends chartered a deep-sea fishing boat out of Destin, FL.

The graph below represents the total cost, in dollars, of the trip as a function of the number of people going.

The group is trying to determine what the price difference would be per passenger if 10 of them go on the trip versus if 16 of them go on the trip.

An equation between two variables that gives a straight line when plotted on a graph.

The group of 16 people would cost $2,500, so it would be $156.25 for each person.

The group of 10 people would cost 1,300 (I got this from going to 10 on the chart then following it up to the line), so it would be $130 per person.

Then, $156.25 - $130 = $26.25

Hence, the difference in price per passenger for a group of 16 versus a group of 10 is $26.25.

To know more about the Linear equation click the link given below.

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Using an exponential function, it is found that 242.5 mg of radium will be left after the 40 days.

The exponential function for the amount of a decaying substance is modeled by:

[tex]A(t) = A(0)e^{-kt}[/tex]

In which:

In this problem, the half-life is of 100 days, hence:

[tex]A(100) = 0.5A(0)[/tex]

Which is used to find k.

[tex]A(t) = A(0)e^{-kt}[/tex]

[tex]0.5A(0) = A(0)e^{-100k}[/tex]

[tex]e^{-100k} = 0.5[/tex]

[tex]\ln{e^{-100k}} = \ln{0.5}[/tex]

[tex]-100k = \ln{0.5}[/tex]

[tex]k = -\frac{\ln{0.5}}{100}[/tex]

[tex]k = 0.0069314718[/tex]

Then, the equation is:

[tex]A(t) = A(0)e^{-0.0069314718t}[/tex]

He started with 320 mg of radium, hence [tex]A(0) = 320[/tex], and the equation is:

[tex]A(t) = 320e^{-0.0069314718t}[/tex]

After 40 days, the amount left is:

[tex]A(40) = 320e^{-0.0069314718(40)} = 242.5[/tex]

242.5 mg of radium will be left after the 40 days.

You can learn more about exponential functions at https://brainly.com/question/25537936

[tex]3(x^2-8x)=0\implies x^2-8x=\cfrac{0}{3}\implies x^2-8x=0 \\\\\\ \stackrel{\textit{common~factoring}}{x(x-8)=0} \implies \begin{cases} \boxed{x=0}\\[-0.5em] \hrulefill\\ x-8=0\\ \boxed{x=8} \end{cases}[/tex]

Answer:

y+what ever the angle inside=180 since its on a line

180-128=52

52+z+x=180since thats always the angles of a triangle added up

52+91+x=180

add

143+x=180

-143

x=37

Hope This Helps!!!

Answer:

125 inches cubed

Step-by-step explanation:

volume= height*width*length

5*5*5=125

Step-by-step explanation:

1a.

[tex](2 {p}^{2} )^{3} = {2}^{3} {p}^{6} = 2p \times 2p\times 2p\times p\times p\times p[/tex]

(2p^2)^3 without exponents will represent 2p being multiplied by 2p 2 times and by p 3 times.

1b. Solve:

Include exponent outside parenthese:

[tex]{2}^{3} {p}^{2 \times 3} [/tex]

[tex]8 {p}^{6} [/tex]

8p^6 is your answer for part B.

Answer:

x = 6(x - 2)

Step-by-step explanation:

His age now is x.

His age 2 years ago was x - 2.

x = 6(x - 2)

15, 75, 90; right

===================================================

Explanation:

The ratio 1:5:6 scales up to x:5x:6x for some positive real number x.

The three interior angles are x, 5x and 6x. For any triangle, the interior angles always add to 180.

x+5x+6x = 180

12x = 180

x = 180/12

x = 15

So,

The triangle has angles of 15, 75 and 90 degrees.

Because we have a 90 degree angle, this is a right triangle.

Note how 15+75+90 = 180 to help confirm the answer.

Answer:

-5w-20 is equivalent to (3w-8)-4 (2w+3)

Answer:

8 pizzas

Step-by-step explanation:

If 1/5 was remaining, the hoard consumed 4/5 of all the pizza.

(4/5)*(10 pizzas) = 8 pizzas

Answer:

2 pizzas

Step-by-step explanation:

[tex]\frac{10}{1}[/tex]*[tex]\frac{1}{5}[/tex]=[tex]\frac{10}{5}[/tex]

then divided 5 by 10 and it equals 2 pizzas.

Answer:

A, C, F

Step-by-step explanation:

JK is proportional to PQ, so that would be 8/x. Then, JL is proportional to PR, which would be 10/5. So, the answer is: 8/x = 10/5

Then, C would also be correct as KL is proportional to QR, and JK is proportional to PQ.

Finally, F is correct as JK to KL is proportional to PQ to QR, as JK is proportional to PQ, and KL is proportional to QR.

Answer:

2. w = -3

4. c = -2

6. r = 7

8. n = 4

Step-by-step explanation:

It's hard to read the photo, but I'll try.

2.

[tex] 2^{w + 4} \times 2^{4w + 6} = 2^{2w + 1} [/tex]

On the left side, you have a product of 2 powers with the same base.

Give the same base and add the exponents, as in the rule

[tex] a^m \times a^n = a^{m + n} [/tex]

You get on the left side 2 to the sum of the exponents.

[tex] 2^{w + 4 + 4w + 6} = 2^{2w + 1} [/tex]

Simplify the long exponent on the left side.

[tex] 2^{5w + 10} = 2^{2w + 1} [/tex]

Now we have another rule we can use. If two powers are equal, and their bases are equal, then the exponents must be equal.

Here, 2 to the power 5w + 10 equals 2 to the power 2w + 1. Since both bases are 2 and are equal, then the exponents must be equal.

5w + 10 = 2w + 1

Subtract 2w from both sides. Subtract 10 from both sides.

3w = -9

Divide both sides by 3.

w = -3

4.

[tex] \dfrac{1}{5} = 5^{2c + 3} [/tex]

We need to write the left side as a power of 5. Then we equate the exponents like we did in problem 2.

Recall the rule:

[tex] a^{-n} = \dfrac{1}{n} [/tex]

Apply this rule to the left side in reverse.

[tex] 5^{-1} = 5^{2c + 3} [/tex]

Now we have two powers that are equal, both having the same base, 5, so the exponents must be equal.

2c + 3 = -1

2c = -4

c = -2

6.

[tex] 216 = 6^{2r - 11} [/tex]

This is the same idea as problem 4. Write the left side as a power of 6.

[tex] 6^3 = 6^{2r - 11} [/tex]

[tex] 2r - 11 = 3 [/tex]

[tex] 2r = 14 [/tex]

[tex] r = 7 [/tex]

r = 7

8.

[tex] 4^{n} \times 4^{2n - 9} = 64 [/tex]

This problem is similar to problem 2.

[tex] 4^{n + 2n - 9} = 4^3 [/tex]

[tex] 4^{3n - 9} = 4^3 [/tex]

3n - 9 = 3

3n = 12

n = 4

7x is the GCF of the polynomial.

Polynomial is an algebraic expression that consists of variables and coefficients. Variable are called unknown. We can apply arithmetic operations such as addition, subtraction, etc. But not divisible by variable.

Given

21x + 56xy is a polynomial.

The GCF to factor the polynomial.

21x + 56xy is a polynomial.

Take 7x common from the polynomial. we have

21x + 56xy

7x (7 + 8y)

Thus, 7x is the GCF of the polynomial.

More about the polynomial link is given below.

https://brainly.com/question/17822016