PLEASE HELP!!! how do i do this, i don’t understand how to do these

PLEASE HELP!!! How Do I Do This, I Dont Understand How To Do These

Answers

Answer 1
56.33 grams of iron will produce 80.6 grams of ferric oxide13.55 grams of hydrogen will produce 76.8 grams of ammonia gas.

How to calculate mass stoichiometrically?

Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

QUESTION 5:

According to question 5, 4 moles of iron reacts with 3 moles of oxygen gas to produce 2 moles of ferric oxide.

56.33 grams of iron is equivalent to 1.01 moles

This means that 1.01 moles of iron will produce 0.51 moles of ferric oxide.

Mass of ferric oxide = 0.51 × 159.69 = 80.6 grams.

QUESTION 6:

According to question 6, 3 moles of hydrogen gas reacts with 1 mole of nitrogen gas to produce 2 moles of ammonia.

13.55 grams of hydrogen is equivalent to 6.78 moles

This means that 6.78 moles of hydrogen will produce 4.52 moles of ammonia

Mass of ammonia = 4.52 × 17 = 76.8 grams.

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Related Questions

using the rules for naming molecular compounds described in the introduction, what is the name for the compound n2cl4 ?

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Answer:

Dinitrogen Tetrachloride

Explanation:

The compound N2Cl4 is made up of two nitrogen atoms and four chlorine atoms, so it is a molecular compound.

To name molecular compounds, we use prefixes to indicate the number of each type of atom in the compound. The prefix for two is "di", and for four is "tetra". Therefore, the name of N2Cl4 would be dinitrogen tetrachloride.

the outer most shell of an atom is called the valane shell. the number of electrons in this shell determines ________.

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the chemical properties of the atom.

How many grams of hydrogen are present in 10.05 grams of water?

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In water (H2O), there are two atoms of hydrogen (H) and one atom of oxygen (O) per molecule. The atomic mass of hydrogen is approximately 1.008 g/mol and the molecular mass of water is approximately 18.015 g/mol.

To calculate the grams of hydrogen in 10.05 grams of water, we need to first determine the number of moles of water present:

moles of water = mass of water / molecular mass of water

moles of water = 10.05 g / 18.015 g/mol

moles of water = 0.5575 mol

Since there are two hydrogen atoms in each molecule of water, the number of moles of hydrogen is twice the number of moles of water:

moles of hydrogen = 2 x moles of water

moles of hydrogen = 2 x 0.5575 mol

moles of hydrogen = 1.115 mol

Finally, we can calculate the grams of hydrogen by multiplying the number of moles of hydrogen by the atomic mass of hydrogen:

grams of hydrogen = moles of hydrogen x atomic mass of hydrogen

grams of hydrogen = 1.115 mol x 1.008 g/mol

grams of hydrogen = 1.12352 g

Therefore, there are approximately 1.12352 grams of hydrogen present in 10.05 grams of water.

What is hydrogen?

Hydrogen is a chemical element with the symbol H and atomic number 1. It is the lightest and most abundant element in the universe, constituting roughly 75% of all baryonic mass. Hydrogen is a colorless, odorless, and tasteless gas that is highly flammable.

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Which of the following exhibits the correct orders for both atomic radius and ionization energy, respectively? (smallest to largest) A. F, S, O, and O, S, FB. S, O, F, and F, O, SC. F, O, S, and S, O, FD. S, F, O, and S, F, O E. none of these

Answers

The atomic radius of an atom is the distance between the centre of the nucleus and the valence shell of electrons. The correct order of atomic radius and ionization energy is F, O, S, and S, O, F. The correct option is C.

What is ionization energy?

The minimum amount of energy required to remove most loosely bound electron from an isolated gaseous atom of that element in the ground state is called  ionization energy.

Along a period  ionization energy increases and decreases down the group. The atomic radius generally increases down a group and decreases along a period.

Here 'F' has high ionization energy and it has low atomic radius.

Thus the correct option is C.

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