Please help. I don’t know how to solve this as there is no angle provided.

Answer:

Density=10.50kg/m³

Explanation:

[tex]Solution,\\Height(h)=0.5m\\Radius(r)=0.4m\\Now, \\Volume=\pi r^{2} h\\\\Volume=\pi *(0.4m)^{2} *0.5m\\\\Volume=0.251327m^{3} \\\\Again,\\\\Density=\frac{mass}{volume} \\\\Density=\frac{2.640kg}{0.251327} \\\\Density=10.50kg/m^{3}[/tex]

The density of the cylindrical rod is 10.516 kg/m³.

To calculate the density of the cylindrical rod, we can use the formula:

[tex]\rm \[\text{{Density}} = \frac{{\text{{Mass}}}}{{\text{{Volume}}}}\][/tex]

The mass of the rod is given as 2.640 kg. To find the volume, we can use the formula for the volume of a cylinder:

[tex]\rm \[\text{{Volume}} = \pi \times \text{{radius}}^2 \times \text{{height}}\][/tex]

Substituting the given values:

[tex]\[\text{{Volume}} = \pi \times (0.4 \, \text{{m}})^2 \times 0.5 \, \text{{m}}\][/tex]

Calculating the volume:

[tex]\[\text{{Volume}} = \pi \times 0.16 \, \text{{m}}^2 \times 0.5 \, \text{{m}}\]\\\\text{{Volume}} = 0.251 \, \text{{m}}^3\][/tex]

Now we can substitute the mass and volume values into the density formula:

[tex]\[\text{{Density}} = \frac{{2.640 \, \text{{kg}}}}{{0.251 \, \text{{m}}^3}}\][/tex]

Calculating the density:

[tex]\[\text{{Density}} = 10.516 \, \text{{kg/m}}^3\][/tex]

Therefore, the density of the cylindrical rod is 10.516 kg/m³.

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Answer:

5,878,625,370,000 miles or 5.87 Trillion miles

Explanation:

The result: One light-year equals 5,878,625,370,000 miles (9.5 trillion km).

One light-year equals 5,878,625,370,000 miles (9.5 trillion km)

explanation: To find the distance of a light-year, you multiply this speed by the number of hours in a year (8,766).

So, the force of gravity that the asteroid and the planet have on each other approximately

[tex] \boxed{\sf{5.43 \times 10^{10} \: N}} [/tex]

Hi ! Now, I will help to discuss about the gravitational force between two objects. We already know that gravitational force occurs when two or more objects interact with each other at a certain distance and generally orbit each other to their center of mass. For the gravitational force between two objects, it can be calculated using the following formula :

[tex] \boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}} [/tex]

With the following condition :

We know that :

What was asked :

Step by step :

[tex] \sf{F = G \times \frac{m_1 \times m_2}{r^2}} [/tex]

[tex] \sf{F = 6.67 \times 10^{-11} \times \frac{8.4 \cdot 10^8 \times 6.2 \cdot 10^{23}}{(8 \times 10^5)^2}} [/tex]

[tex] \sf{F = \frac{347.374 \times 10^{-11 + 8 + 23}}{64 \times 10^10}} [/tex]

[tex] \sf{F \approx 5.43 \times 10^{20 - 10}} [/tex]

[tex] \boxed{\sf{F \approx 5.43 \times 10^{10} \: N}} [/tex]

So, the force of gravity that the asteroid and the planet have on each other approximately

[tex] \boxed{\sf{5.43 \times 10^{10} \: N}} [/tex]

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Answer:

K = C + 273, so 27°C = 27+273 = 300 K

1 dg = 100 mg, so 20 dg = 20×100 = 2,000 mg

Explanation:

The horizontal and vertical component of vector A is -3 and 0 respectively.

The horizontal and vertical component of vector B is 0 and 3 respectively.

The horizontal and vertical component of vector C is 0 and 6 respectively.

The horizontal and vertical component of vector D is 4 and 0 respectively.

The horizontal and vertical component of vector E is 3.54 and 3.54 respectively.

The horizontal and vertical component of vector F is -3.54 and -3.54 respectively.

The horizontal and vertical component of each vector is calculated as follows;

[tex]A_x = Acos (\theta) = 3 \times cos(180) = -3\\\\A_y = A sin(\theta) = 3 \times sin(180) = 0[/tex]

[tex]B_x = 3 \times cos(90) = 0\\\\B_y = 3 \times sin(90) = 3[/tex]

[tex]C_x = 6 \times cos(90) = 0\\\\C_y = 6 \times sin(90) = 6[/tex]

[tex]D_x = 4 \times cos(0) = 4\\\\D_y = 4 \times sin(0) = 0[/tex]

[tex]E _x = 5 \times cos (45) = 3.54 \\\\E_y = 5 \times sin(45) = 3.54[/tex]

[tex]F_x = 5 \times cos(225) = -3.54\\\\F_y = 5 \times sin(225) = -3.54[/tex]

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Answer: 590 MW

Water flows over a section of Niagara Falls at the rate of 1.2 × 106 kg/s and falls 50 m. How much power is generated by the falling water? = 5.9 × 108 W = 590 MW , where 'MW' represents megawatts.

Explanation:

Explanation:

some car crashes only produce minor injuries because the car crash isn't that bad.

Answer: uhhhhhhhhhhhhhhhhhhhh im responding for points

Explanation:

lololololol sorry

Answer:

laser pointer does not make use of total internal reflection

Answer:

Im Pretty Sure Its 15.7m/s

Explanation:

Hope This Helps tell Me if im wrong

We have that the Force  is mathematically given as

F=170.833N

Question Parameters:

Generally the equation for the Force   is mathematically given as

[tex]F=\frac{T}{d}[/tex]

Therefore

F=41/0.24

F=170.833N

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Up to 230 homes could be heated by the performance of the power plant.

By definitions of energy efficiency ([tex]\eta[/tex]), no unit, and principle of energy conservation, the amount of waste heat rate ([tex]\dot Q_{waste}[/tex]), in megawatts, is equal to the difference between the energy input and the useful output, that is to say:

[tex]\dot Q_{waste} = \left(\frac{1}{\eta} -1\right)\cdot \dot E_{out}[/tex] (1)

Where [tex]\dot E_{out}[/tex] is the useful output, in watts.

According to the statement, an average home uses 70 GJ of energy per year for heating and home heating takes place at a steady rate for half a year, then the number of homes ([tex]n[/tex]), no unit, benefited by the co-generation plant is calculated by this formula derived from physical definition of power:

[tex]n = \frac{\dot Q_{waste}\cdot \Delta t}{Q_{home}}[/tex] (2)

Where:

Now we proceed to find the number of houses: ([tex]\dot E_{out} = 1.9\times 10^{6}\,W[/tex], [tex]\eta = 0.65[/tex], [tex]\Delta t = 1.577\times 10^{7}\,s[/tex], [tex]Q_{home} = 7\times 10^{10}\,J[/tex])

By (1):

[tex]\dot Q_{waste} = \left(\frac{1}{0.65}-1 \right)\cdot (1.9\times 10^{6}\,W)[/tex]

[tex]\dot Q_{waste} = 1.023\times 10^{6}\,W[/tex]

By (2):

[tex]n = \frac{(1.577\times 10^{7}\,s)\cdot (1.023\times 10^{6}\,W)}{7\times 10^{10}\,J}[/tex]

[tex]n = 230.467[/tex]

Up to 230 homes could be heated by the performance of the power plant. [tex]\blacksquare[/tex]

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Answer:

C 2000v its obviously ans because if o is 1000 2 vo is 2000v

Answer:

hydrosphere

Explanation:

the frozen part of the hydrosphere has its own name,the cryosphere

We have that the tension in rope 2 is mathematically given as

the tension in rope 2 is

From the question we are told

A crate hangs from a rope that is attached to a metal ring.

The metal ring is suspended by a second rope that is attached overhead at two points, as shown.

What is the angle if the tension in rope 1 is 0.640 times the tension in rope 2?

Generally the equation for the Tension  is mathematically given as

[tex]Tcos\theta+0.640\theta-T_1=0\\\\Therefore\\\\ZTcos \theta-0.640T=0\\\\Cos=0.32\\\\\theta=71.3\\\\[/tex]

Therefore

the tension in rope 2 is

[tex]\theta=71.3[/tex]

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According to Ptolemy's model, he, too, believed in a geocentric Universe and that the planets and stars were perfect spheres, though Earth itself was not.

He further thought that the movements of the planets and stars must be circular since they were perfect and, if the motions were circular, then they could go on forever.

Shooting stars are very different from comets, although the two can be related. A Comet is a ball of ice and dirt, orbiting the Sun (usually millions of miles from Earth). ... A shooting star on the other hand, is a grain of dust or rock (see where this is going) that burns up as it enters the Earth's atmosphere.

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A wooden log is displaced to a distance of 20m in 10 seconds by applying 500N effort . Calculate the workdone and power...

Solution,

displacement = 20 m

time = 10 sec

force = 500 N

work done = ?

power = ?

Now ,

work done = f × s

= 500 N × 20 m

= 10000 j

Now ,

[tex]power \: = \frac{w}{t} \\ = \frac{10000j}{10sec} \\ = 1000W[/tex]

~nightmare 5474~

The work done and the power is 10000 J and 1000 W respectively.

To calculate the work done by the wooden log, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

To calculate the power, we use the formula below.

Where:

Given:

Substitute the values above into equation 2

Hence, the work done and the power is 10000 J and 1000 W respectively.
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Answer:

1.01m

Explanation:

period of pendulum = 2π√l/g

for length .59 m period is 1.54 s

every 24 hrs period increases by 60s or 1 min

except length rest of the components are constant

so the period becomes 2.54 at 24 hrs

for 2.54, the length is 1.601 m

length to be adjusted is 1.6-.59=1.01m

Carbon cycle shows is the continous movement of carbon in elemental and combined states on earth.

Steps :-

☆ Carbon moves from the atmosphere to plants. ...

☆ Carbon moves from plants to animals. ...

☆ Carbon moves from plants and animals to soils. ...

☆ Carbon moves from living things to the atmosphere. ...

☆ Carbon moves from fossil fuels to the atmosphere when fuels are burned. ...

☆ Carbon moves from the atmosphere to the oceans.

~ Benhemin360

We have that the Velocities is mathematically given as

a)v=2.8e5m/s

b)v_2=3.11e5m/s

From the question we are told

Generally the equation for the workdone   is mathematically given as

a)

[tex]-qEr=0.5m(u/2)^2\\\\Therefore\\\\1.6e-19*19*2.9e-3=0.5*9.1e-31*v^2/4[/tex]

v=2.8e5m/s

b)

applying work

[tex]-qEr=0.5m(u/2)^2\\\\1.6e-19*19*2.9e-3=0.5*9.1e-31(v_2^2-7.75e10)[/tex]

v_2=3.11e5m/s

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Answer:

I literally just learned this last week and if I remember correctly it is Faraday's Law of Induction.

Explanation: Hope this helps also I hope you have/had an amazing day today<3

Answer:

h=4+85*time - 1/2 32*time^2

16time^2-85*time-106=0

use the quadratic formula to solve for time (notice two solutions, one going up, one going back down).

time=(85+-sqrt(85^2+4*16*106) )/32

Explanation:

Recheck my work just in case I'm not good at this type of class but I wanted to help.

a. At maximum height h, the baseball has zero vertical velocity, so that with initial velocity v we have

[tex]0^2-v^2 = -2gh \implies h = \dfrac{v^2}{2g}[/tex]

Given that [tex]v = 30 \frac{\rm m}{\rm s}[/tex], the ball reaches a height of

[tex]h = \dfrac{\left(30\frac{\rm m}{\rm s}\right)^2}{2g} \approx \boxed{46\,\mathrm m}[/tex]

b. At max height, the baseball's vertical velocity is such that

[tex]0=v-gt[/tex]

For [tex]v = 30 \frac{\rm m}{\rm s}[/tex], we find

[tex]gt=30\dfrac{\rm m}{\rm s} \implies t = \dfrac{30\frac{\rm m}{\rm s}}g \implies t \approx 3.1 s[/tex]

which is half the time it spends in the air, making the total time about 6.1 s.

c. We saw in part (a) that

[tex]h = \dfrac{v^2}{2g}[/tex]

If we halve the initial speed and replace [tex]v[/tex] with [tex]\frac v2[/tex], we get

[tex]h = \dfrac{\left(\frac v2\right)^2}{2g} = \dfrac14 \cdot \dfrac{v^2}{2g}[/tex]

which means the max height is reduced by a factor of 1/4.

In part (b), we found the time to max height is

[tex]t = \dfrac{v}{g}[/tex]

and halving the initial speed gives

[tex]t = \dfrac{\frac v2}g = \dfrac12 \cdot \dfrac{v}{g}[/tex]

That is, the time to max height is reduced by a factor of 2 when the speed is halved, and so the overall time in the air is reduced by a factor of 2.

So, the speed when it (the rock) hit the ground is 14 m/s.

Hi ! This question will direct you to the "Free Fall Motion" material. Why is that ? This is because there is a keyword "dropped" which means without initial speed and its named free fall motion. Its little bit of different, when the keyword "thrown", that's not a free fall motion. For the equations of velocity in free fall, follow the following equation:

[tex] \boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}} [/tex] ... (i)

[tex] \boxed{\sf{\bold{v = \sqrt{2 \times g \times (h_1 - h_2)}}}} [/tex] ... (ii)

With the following condition :

Note :

We know that :

What was asked :

Step by step :

[tex] \sf{v = \sqrt{2 \times g \times h}} [/tex]

[tex] \sf{v = \sqrt{2 \times 9.8 \times 10}} [/tex]

[tex] \sf{v = \sqrt{196}} [/tex]

[tex] \boxed{\sf{v = 14 \: m/s}} [/tex]

So, the speed when it (the rock) hit the ground is 14 m/s.

Answer:

Explanation:

When a ball is at its highest point, its acceleration is 0. The only thing pulling it down, is gravity so, the correct option is D. Downwards.

I'm not sure however due to the fact that the arrows on the other options are facing backwards meaning the ball would go backwards; and for the one option the ball is going up. However, the ball isn't going backwards nor up, so it must be D. If I am wrong I greatly apologize.

Answer:

True

Explanation:

In direct current (DC), the electric charge (current) only flows in one direction

So this true