Please help me asap

This is the rectangular equation described by the parameter equation x = t1/3 and y = t – 4.

Elimination of the parameter means to rewrite the equations in terms of only x and y. To do this, substitute t from one equation into the other equation. Here, the two equations are:x = t1/3 and y = t – 4Substitute t from the first equation into the second equation:y = (x^3) – 4Now the equation is in terms of x and y only.

This is the rectangular equation described by the parameter equation x = t1/3 and y = t – 4.The rectangular equation, y = (x^3) – 4 can be plotted on a graph. It is a cubic equation. The graph will look like a curve that passes through the point (0, -4) and continues to move towards infinity. The graph will be symmetric to the origin because the equation involves an odd power of x.

If the equation involved an even power of x, the graph would be symmetric to the y-axis. The graph will never touch the x-axis or y-axis, it will only approach them.In conclusion, the rectangular equation y = (x^3) – 4 is derived from the two parameter equations, x = t1/3 and y = t – 4. The graph of this equation is a cubic curve that is symmetric to the origin. The curve passes through (0, -4) and approaches the x and y-axes but never touches them.

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The area of the circle with a radius of 5 cm is approximately 78.53975 square centimeters.

To calculate the area of a circle, we need to use the formula A = πr², where A represents the area and r represents the radius of the circle. In this case, the given radius is 5 cm.

Plugging the value of the radius into the formula, we get:

A = π(5 cm)²

Simplifying the equation further, we have:

A = π(25 cm²)

Using the value of π (pi) as approximately 3.14159, we can calculate the area:

A ≈ 3.14159 × 25 cm²

A ≈ 78.53975 cm²

It's important to note that the area of a circle is always expressed in square units, as it represents the amount of space enclosed by the circle.

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Answer:

d. creating

Step-by-step explanation:

Random numbers are useful for creating real words situations that involve chance.

A.being

B.selling

C.modeling

D.creating

Answer:

[tex]h'(1)=4\sec^2(8)[/tex]

[tex]h''(1)=32\sec^2(8)\tan(8)[/tex]

Step-by-step explanation:

Given the following function.  

[tex]h(x)=\tan(4x+4)[/tex]

Find the following:

[tex]h'(1)= \ ??\\\\h''(1)= \ ??\\\\\\\hrule[/tex]

Taking the first derivative of h(x). We will use the chain rule and the rule for tangent.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{The Chain Rule:}}\\\\\dfrac{d}{dx}[f(g(x))]=f'(g(x)) \cdot g'(x) \end{array}\right}\\\\\\\boxed{\left\begin{array}{ccc}\text{\underline{The Tangent Rule:}}\\\\\dfrac{d}{dx}[\tan(x)]=\sec^2(x) \end{array}\right}[/tex]

[tex]h(x)=\tan(4x+4)\\\\\\\Longrightarrow h'(x)=\sec^2(4x+4) \cdot4\\\\\\\therefore \boxed{h'(x)=4\sec^2(4x+4)}[/tex]

Now plugging in x=1:

[tex]\Longrightarrow h'(1)=4\sec^2(4(1)+4)\\\\\\\Longrightarrow \boxed{\boxed{h'(1)=4\sec^2(8)}}[/tex]

Taking the second derivative of h(x). Using the chain rule again and the secant rule.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{The Secant Rule:}}\\\\\dfrac{d}{dx}[\sec(x)]=\sec(x) \tan(x) \end{array}\right}[/tex]

[tex]h'(x)=4\sec^2(4x+4)\\\\\\\Longrightarrow h''(x)=(4\cdot 2)\sec(4x+4) \cdot \sec(4x+4)\tan(4x+4) \cdot 4\\\\\\\therefore \boxed{h''(x)=32\sec^2(4x+4)\tan(4x+4)}[/tex]

Now plugging in x=1:

[tex]\Longrightarrow h''(1)=32\sec^2(4(1)+4)\tan(4(1)+4)\\\\\\\therefore \boxed{\boxed{ h''(1)=32\sec^2(8)\tan(8)}}[/tex]

Thus, the problem is solved.

743 general admission tickets and 304 reserved seat tickets were sold.

Let's solve this problem using a system of equations. Let's assume that x represents the number of general admission tickets sold and y represents the number of reserved seat tickets sold.

According to the given information, we have two equations:

Equation 1: The total number of tickets sold is 1047.

x + y = 1047

Equation 2: The total revenue from ticket sales is $4576.50.

3.50x + 6.50y = 4576.50

Now, we can solve this system of equations.

We can start by multiplying Equation 1 by 3.50 to eliminate x:

[tex]3.50(x + y) = 3.50(1047)\\3.50x + 3.50y = 3664.50[/tex]

Now we have the following system of equations:

[tex]3.50x + 3.50y = 3664.50 (Equation 3)\\3.50x + 6.50y = 4576.50 (Equation 2)[/tex]

By subtracting Equation 3 from Equation 2, we can eliminate x:

[tex](3.50x + 6.50y) - (3.50x + 3.50y) = 4576.50 - 3664.50\\3.00y = 912.00[/tex]

Dividing both sides of the equation by 3.00, we find:

y = 304

Now, substitute the value of y into Equation 1 to find x:

x + 304 = 1047

x = 743

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Answer:

Step-by-step explanation:

x-6y=4

To solve these equations, we can use the elimination method. We want to eliminate one of the variables, either x or y, by multiplying one of the equations by a constant so that the coefficients of one variable will be the same in both equations but with opposite signs. For example, we can multiply the first equation by 4 to get:

-20x - 24y = -128

Then we can add this equation to the second equation to eliminate y:

-20x - 24y + 4x - 6y = -128 + 4

Simplifying this equation gives:

-16x - 30y = -124

Now we can isolate one variable in terms of the other:

-16x - 30y = -124

-16x = 30y - 124

x = (30/(-16))y + (-124/(-16))

x = (-15/8)y + 31/2

We can substitute this expression for x into either of the original equations to solve for y. For example, substituting into the first equation gives:

-5((-15/8)y + 31/2) - 6y = -32

Multiplying by -8 to clear the fractions gives:

75y - 248 - 48y = 256

Simplifying and solving for y gives:

27y = 504

y = 18.67

Then we can substitute this value of y back into our expression for x to find:

x = (-15/8)(18.67) + 31/2

x = -12.25

Therefore, the solution to the system of equations is:

x = -12.25

y = 18.67

Answer:step 4

Step-by-step explanation: I just took the test pookies

Answer:

268.8

Step-by-step explanation:

Let the sides of the base triangle be:

a = 8.8 cm

b = 5.7 cm

c = 6.8 cm

Let h be the length

h = 10.8 cm

The surface area is given by:

[tex]SA = (a + b + c)*l + 2\sqrt{ s(s - a)(s - b)(s - c)}[/tex]

Where

[tex]s = \frac{a + b + c}{2} \\\\= \frac{8.8 + 5.7 + 6.8}{2} \\\\=\frac{21.3}{2} \\\\= 10.65[/tex]

[tex]SA = (a + b + c)*l + 2\sqrt{ s(s - a)(s - b)(s - c)}\\\\= (8.8 + 5.7 + 6.8)*10.8 + 2\sqrt{ 10.65(10.65 - 8.8)(10.65 - 5.7)(10.65 - 6.8)}\\\\= 21.3*10.8 +2\sqrt{ 10.65(10.65 - 8.8)(10.65 - 5.7)(10.65 - 6.8)}\\\\=230.04 + 2\sqrt{ 10.65(1.85)(4.95)(3.85)}\\\\=230.04 + 2\sqrt{ 375.48}\\\\= 230.04 + 2*19.38\\\\=230.04 +38.76\\\\=268.8[/tex]

Answer:

5 + m^3 n^2

----------------------

m^2 n^2

Step-by-step explanation:

To add fractions, we need to get a common denominator:

The common denominator is m^2 n^2.

Multiply the second term by m^2n/ m^2n

m/n * m^2n / m^2 n = m^3n / m^2n^2

Now we can add the two terms

5                               m^3 n^2

------                 + ---------------------------

m^2 n^2                      m^2 n^2

5 + m^3 n^2

----------------------

m^2 n^2

Answer:

D. 2

Step-by-step explanation:

y=mx+b

m is the slope in this case, and by your equation, we can easily see that the answer should be D, with a slope of 2.

Answer:

d.2

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

y=2x+6

m=2

b=6

slope=2

The discount rate is increased by 12%, the new net present value will be approximately Rs. 5514.29.

To determine the net present value (NPV) when the discount rate is increased by 12%, we need to recalculate the NPV using the new discount rate.

Given:

Current NPV = Rs. 6172

Current discount rate = 9%

Increase in discount rate = 12%

To find the new NPV, we can use the formula:

New NPV = Current NPV / (1 + Increase in discount rate)

Calculating the new NPV:

New NPV = 6172 / (1 + 0.12)

New NPV = 6172 / 1.12

New NPV ≈ Rs. 5514.29

Therefore, if the discount rate is increased by 12%, the new net present value will be approximately Rs. 5514.29.

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Answer:

Step-by-step explanation:

To find the value of an investment compounded continuously, we can use the formula:

A = P * e^(rt)

Where:

A is the final amount

P is the principal amount (initial investment)

e is the mathematical constant approximately equal to 2.71828

r is the annual interest rate (as a decimal)

t is the time period in years

In this case, P = $10,000, r = 0.0315 (3.15% expressed as a decimal), and t = 13.

Plugging in the values into the formula, we get:

A = $10,000 * e^(0.0315 * 13)

Calculating the exponential part:

A = $10,000 * e^(0.4095)

Using a calculator or a math software, we can evaluate e^(0.4095) to get approximately 1.506.

A = $10,000 * 1.506

A ≈ $15,060.

Answer:

Ok, Here is your answer

Step-by-step explanation:

To find the percentage of players who played well on the baseball team, we need to divide the number of players who played well by the total number of players and then multiply by 100.

Number of players who played well = 6

Total number of players = 11

Percentage of players who played well = (6/11) x 100%

= 54.55%

Therefore, the answer is 54.55%. Hence, option D, 54.55%, is the correct answer.

Answer:

That's a great point! It's important to continue to encourage others to recycle and to educate people on the benefits of recycling to help achieve that 100% goal.

The percent profit will be 15.5%.The formula used to calculate the percentage profit is:Percentage Profit = (Profit / Cost Price) x 100%.

Let's assume that the retailer has an item with a wholesale price of $100. After a 54% increase in the wholesale price, the new wholesale price is $154.Now, when the retailer provides a 25% discount off the ticket price, the new price of the item becomes: $154 x 75% = $115.5.

The cost of producing the item is $100, but the retailer sells it for $115.5. Hence, the profit made by the retailer is:$115.5 - $100 = $15.5 or 15.5% profit.The percent profit that the retailer will realize is 15.5%. Therefore, the percent profit will be 15.5%.The formula used to calculate the percentage profit is:Percentage Profit = (Profit / Cost Price) x 100%.

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The options that apply are:

A. A list of all questions from the lessons

B. Description of what you need to know or apply

C. Concepts tested

D. Reference column.

The options that are typically included in a table for each unit are:

- A list of all questions from the lessons: This helps in organizing and categorizing the questions based on the specific unit or topic.

- Description of what you need to know or apply: This provides an overview or summary of the key concepts, knowledge, or skills that are covered in the unit.

- Concepts tested: This section highlights the specific concepts or skills that will be tested or assessed in relation to the unit. It helps students understand the focus areas and what they need to prioritize in their learning.

- Reference column: This column may include additional information such as page numbers, section titles, or references to specific resources or materials that are relevant to the unit. It serves as a guide for further exploration or reference.

A brief quiz, on the other hand, is not typically included in a table for each unit. Quizzes are usually separate assessments that are administered to evaluate understanding and mastery of the unit's content.

So, the options that apply are:

- A list of all questions from the lessons

- Description of what you need to know or apply

- Concepts tested

- Reference column

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The area of the triangle is 47.91 units²

When all three sides of the triangle are known we can use Heron's formula. Consider the triangle ABC with sides a, b, and c has shown in the image.

Heron’s formula is:

Area =√s(s−a)(s−b)(s−c)

where,

a, b, c are the side length of the triangle

s is the semi-perimeter. s = (a+b+c)/2

In this case:

Using the knowledge of the radius of a circle. We can say:

a = BC = 3 + 9 = 12 units

b = AC = 5 + 3 = 8 units

c = AB = 5 + 9 = 14 units

s = (a+b+c)/2

s = (12+8+14)/2

s = 34/2

s = 17 units

Area = √s(s−a)(s−b)(s−c)

Area = √17(17−12)(17−8)(17−14)

Area = √17(5)(9)(3)

Area = √2295

Area = 47.91 units²

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The function value for f(g(4)) include the following: f(g(4)) = 6.

In Mathematics and Geometry, a function is a mathematical equation which defines and represents the relationship that exists between two or more variables such as an ordered pair in tables or relations.

By critically observing the table of values of the function f and g shown in the image attached above, we can reasonably infer and logically deduce the following function values:

g(4) = 1

f(g(4)) = f(1)

f(1) = 6.

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Answer:

-5

Step-by-step explanation:

The slope-intercept form of the equation of the line that passes through (-2, -1) and is perpendicular to y + 15 = x + 10 is y = -x - 3.

To find the slope-intercept form of the equation of a line that is perpendicular to a given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope.

The given line equation is y + 15 = x + 10. To rewrite it in slope-intercept form (y = mx + b), we isolate y:

y = x + 10 - 15

y = x - 5.

From this equation, we can see that the slope of the given line is 1.

To find the slope of the line perpendicular to this, we take the negative reciprocal of 1, which is -1.

Now that we have the slope (-1) and a point (-2, -1) that the line passes through, we can use the point-slope form of a line to find the equation.

The point-slope form of a line is given by: y - y1 = m(x - x1), where (x1, y1) is a point on the line.

Plugging in the values (-2, -1) and -1 for x1, y1, and m respectively, we get:

y - (-1) = -1(x - (-2))

y + 1 = -1(x + 2)

y + 1 = -x - 2.

To rewrite this equation in slope-intercept form (y = mx + b), we isolate y:

y = -x - 2 - 1

y = -x - 3.

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Answer:

[tex]\frac{6}{x-5}[/tex]

Step-by-step explanation:

Helping in the name of Jesus.

1) 2a - 100

Substituting the value of a here,

[tex] \rm 2(32) - 100 [/tex]

[tex] \rm 64 - 100 [/tex]

[tex] \rm -36 [/tex]

2) b (-12)

Substituting the value of b here,

[tex] \rm 150 (-12) [/tex]

[tex] \rm -1800 [/tex]

3) 4a + b

Substituting the values of a and b here,

[tex] \rm 4(32) + 150 [/tex]

[tex] \rm 128 + 150 [/tex]

[tex] \rm 278 [/tex]

4) 9b - 2a

Substituting the values of a and b here,

[tex] \rm 9(150) - 2 (32) [/tex]

[tex] \rm 1350 - 64 [/tex]

[tex] \rm 1286 [/tex]

The answers are:

below in [tex]\bold{bold}[/tex]

Work/explanation:

Plug in 32 for a

[tex]\sf{2(32)-100}[/tex]

[tex]\sf{64-100}[/tex]

[tex]\bf{-36}[/tex]

____________

[tex]\sf{b(-12)}[/tex]

[tex]\sf{150\cdot(-12)}[/tex]

[tex]\bf{1,800}[/tex]

____________

[tex]\sf{4a+b}[/tex]

[tex]\sf{4(32)+150}[/tex]

[tex]\sf{128+150}[/tex]

[tex]\bf{278}[/tex]

____________

[tex]\sf{9b-2a}[/tex]

[tex]\sf{9(150)-2(32)}[/tex]

[tex]\sf{1,350-64}[/tex]

[tex]\bf{1,286}[/tex]

____________

Answer:

A, B, E

Step-by-step explanation:

Notice that A, B, and E all maintain their common ratios, while C and D do not.

Answer:

Step-by-step explanation:

Sure, I can help you with that.

The scale of the map is 300 miles / 25 inches = 12 miles / inch.

Therefore, 35 inches on the map would be 35 * 12 = 420 miles.

Here's the calculation:

Code snippet

scale = actual distance / distance on map

12 miles / inch = 300 miles / 25 inches

35 inches * 12 miles / inch = 420 miles

Use code with caution. Learn more

I hope this helps! Let me know if you have other questions.

Answer:

  (b) When a vertical line intersects the graph of a relation more than once, it indicates that for that input there is more than one output, which means the relation is not a function.

Step-by-step explanation:

You want to know why the vertical line test tells us whether the graph of a relation represents a function.

A relation maps a set of inputs to a set of outputs. A function maps a set of unique inputs to a set of outputs. That is, the elements of the input set of a function are not repeated, but appear only once.

On the graph of a relation, the input values are mapped to the horizontal coordinate(s) of the point(s) on the graph. If the relation has repeated input values, then those points will have the same x-coordinate on a graph, and will lie on a vertical line. So, we can conclude ...

When a vertical line intersects the graph of a relation more than once, it indicates that for that input there is more than one output, which means the relation is not a function.

__

Additional comment

You can narrow the choices by considering their vocabulary. The question asks about the graph of a relation. Choices A and D talk about the graph of a function, so can be rejected immediately.

The subject of the question is a vertical line. As you know, a vertical line is of the form x = constant, where an (x, y) ordered pair is an (input, output) pair of a relation. Thus a vertical line will be referring to one input value that is a constant. Choice C talks about "more than one input", which has no relationship to a vertical line. Hence the only choice that makes any sense in the context of the question is B.

A lot of multiple choice questions can be answered appropriately just by considering the way the question and answers are worded.

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This table shows the frequency of each number obtained after throwing the die 35 times

To prepare a frequency table based on the numbers obtained from throwing a die 35 times, we can list the numbers from 1 to 6 and count the frequency of each number.

Numbers: 1, 2, 3, 4, 5, 6

Frequency: 5, 14, 6, 4, 5, 1

Based on the given numbers, the frequency table would look like this:

Number   | Frequency

1                      5

2                     14

3                      6

4                      4

5                      5

6                       1

This table shows the frequency of each number obtained after throwing the die 35 times.

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Using the Law of Cosines with angle 103° and adjacent sides 9 and 6, the remaining side is approximately 12.26 units long.

To find the remaining sides of the triangle, we can use the Law of Cosines. Let's assume that the angle of 103 degrees is opposite side c, and the adjacent sides are a = 9 and b = 6.

The Law of Cosines states:

[tex]c^2 = a^2 + b^2[/tex] - 2ab * cos(C)

Plugging in the known values:

[tex]c^2 = 9^2 + 6^2[/tex] - 2 * 9 * 6 * cos(103°)

Simplifying the equation:

[tex]c^2[/tex] = 81 + 36 - 108 * cos(103°)

Now we need to evaluate cos(103°).

Using a scientific calculator or trigonometric table, we find that cos(103°) ≈ -0.3090.

Substituting the value of cos(103°) back into the equation:

[tex]c^2[/tex] = 81 + 36 - 108 * (-0.3090)

Simplifying further:

[tex]c^2[/tex] = 117 + 33.2724

[tex]c^2[/tex]≈ 150.2724

Taking the square root of both sides:

c ≈ √150.2724

c ≈ 12.26

Therefore, the remaining side (opposite the angle of 103 degrees) is approximately 12.26 units long.

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Answer:

a. The cost at 3% is $46.57 b. The cost at 4% is $49.33 c. The cost at 5% is $52.21

Step-by-step explanation: