Please help me… Solve
|2x+13|-1=6

The girls did break the school's record, and they were 78/5 minutes slower than the record time.

To determine whether the girls broke the school's record, we need to calculate their total time and compare it to the record time.

From the chart, we can see that Barbara's time is 3 minutes, Donna's time is 10 minutes, Cindy's time is 2 minutes, and Nicole's time is 5 minutes.

To calculate the total time, we sum up the individual times:

Total time = Barbara's time + Donna's time + Cindy's time + Nicole's time

= 3 + 10 + 2 + 5

= 20 minutes

The school's record time is given as 2 12/5 minutes. To compare the two times, we need to convert the record time to a common denominator.

[tex]2 12/5 minutes = (2 \times 5 + 12)/5 minutes = 22/5 minutes[/tex]

Now we can compare the total time with the record time:

Total time = 20 minutes

Record time = 22/5 minutes

Since the girls' total time of 20 minutes is less than the record time of 22/5 minutes, we can conclude that they did break the school's record.

To determine how much faster they were, we subtract the total time from the record time:

Record time - Total time = 22/5 - 20

= 22/5 - 100/5

= (22 - 100)/5

= -78/5

The result is -78/5, which means they were 78/5 minutes slower than the record time.

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There is a one-to-one correspondence between the even and odd divisors, we can conclude that an even integer k, not divisible by 4, has the same number of even and odd divisors.

To prove that an even integer k, not divisible by 4, has the same number of even and odd divisors, we can establish a bijection between them.

Let's consider an even integer k. Since k is even, it can be expressed as k = 2n, where n is an integer.

First, let's consider the even divisors of k. An even divisor of k is of the form 2m, where m is an integer. Since k = 2n, we can write the even divisor as 2m = 2n. Simplifying this equation, we get m = n.

Now, let's consider the odd divisors of k. An odd divisor of k is of the form 2m + 1, where m is an integer. Again, we can write this odd divisor as 2m + 1 = 2n. Simplifying this equation, we get m = n - 1/2.

Now, let's establish a bijection between the even and odd divisors. For every even divisor 2m, we can find a corresponding odd divisor 2m + 1, and vice versa. The correspondence is given by the equation m = n for even divisors and m = n - 1/2 for odd divisors.

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Answer:

First 3 positions can be filled in 7C3 ways; last 2 positions can be filled in 6C2 ways.

Evaluate each of these two numbers, and MULTIPLY them to produce the answer.

Step-by-step explanation:

Answer:

The answer is 615.75in .

Answer:

A≈615.75in²

Step-by-step explanation:

A=πr2=π·142≈615.75216in²

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Answer:

Money left over = -$388,600

Step-by-step explanation:

To calculate how much money you have left over from the selling of your home, we need to first calculate the profit you made from selling your home, and then subtract the cost of the new home and the down payment.

Profit from selling the home = selling price - purchase price

Profit = $389,000 - $264,000

Profit = $125,000

Next, we need to subtract the cost of the new home and the down payment:

Cost of new home = $428,000

Down payment = 20% of $428,000 = $85,600

Total cost of new home and down payment = $428,000 + $85,600 = $513,600

Finally, we can calculate how much money you have left over:

Money left over = Profit - (Cost of new home + Down payment)

Money left over = $125,000 - $513,600

Money left over = -$388,600

Since the result is negative, it means you do not have any money left over and you need to cover the difference of $388,600.

Answer:

$39,400

Step-by-step explanation:

Calculate the profit from the sale: Selling price - Original purchase price = $389,000 - $264,000 = $125,000.

Calculate the deposit paid for the new home: 20% of the purchase price = 0.2 x $428,000 = $85,600.

Subtract the deposit paid from the net proceeds of the sale: $125,000 - $85,600 = $39,400 (money left over).

To make the given system dependent, we need to find a value of c that makes the two equations proportional or equivalent. This occurs when the coefficients of x and y in both equations are proportional to each other.

Let's compare the coefficients of x and y in both equations:

For the first equation, 10x + 5y = -5, the ratio of the coefficients is 10/5 = 2.

For the second equation, 6x + 3y = c, the ratio of the coefficients is 6/3 = 2.

To make the system dependent, the ratio of the coefficients must be the same for both equations. Therefore, we need to find a value of c that makes the ratio of coefficients in the second equation equal to 2.

Setting 6/3 equal to 2, we have:

6/3 = 2

Dividing both sides by 2:

2 = 2

The equation 2 = 2 is always true, regardless of the value of c. Therefore, any value of c will make the system dependent, as the lines will coincide.

In conclusion, there is no specific value of c that makes the system dependent. Any value of c will result in a dependent system with coinciding lines.

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The variance of a binomial distribution is np(1-p), so probability of success is 0.9798 (rounded to 4 decimal places).

Using the hypergeometric distribution, the probability of selecting exactly 3 rods that meet the specification is:

P(X=3) = (12 choose 3) * (3 choose 3) / (15 choose 6) ≈ 0.2727

To find the standard deviation of X, we use the formula:

σX = sqrt(np(1-p)/N)

where n is the sample size (6), p is the probability of success (12/15), and N is the population size (15).

σX = sqrt(6 * (12/15) * (3/15)) ≈ 0.925

Using the binomial distribution formula with n = 6 and p = 12/15 = 0.8:

P(X = 3) = (6 choose 3) * (0.8)^3 * (0.2)^3 = 0.27648

The variance of a binomial distribution is np(1-p), so:

σX = sqrt(np(1-p)) = sqrt(60.80.2) = 0.9798 (rounded to 4 decimal places)

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The absolute minimum value of 4 - 6x on an interval, we need to take the derivative of the function does not have an absolute minimum value on the interval (-∞, ∞).

Then, we can plug those critical points and the endpoints of the interval into the original function to find the absolute minimum value.
The derivative of 4 - 6x is -6, which is a constant. Setting it equal to zero, we get -6 = 0, which has no solution. Therefore, there are no critical points.

Next, we need to evaluate the function at the endpoints of the interval. Since no interval is given in the question, we will assume that the interval is the set of all real numbers, denoted by (-∞, ∞).
When x = -∞, we have 4 - 6x = 4 - 6(-∞) = ∞, which is not a finite value. Similarly, when x = ∞, we have 4 - 6x = 4 - 6(∞) = -∞, which is also not a finite value.

Therefore, the function does not have an absolute minimum value on the interval (-∞, ∞).

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The multiplicative rate of change Hal should use in his function is 0.98, representing a 2% decrease annually. The correct answer is B.

In this scenario, we want to represent the value of a $10,000 investment decreasing at 2% annually using an exponential function.

An exponential function is typically represented in the form of f(x) = ab^x, where 'a' is the initial value, 'b' is the multiplicative rate of change, and 'x' is the independent variable.

In our case, the initial value is $10,000, and we want the value to decrease by 2% each year. To incorporate this rate of change into the exponential function, we need to express it as a decimal. Since 2% is equivalent to 0.02, we use 0.98 (1 - 0.02) as the multiplicative rate of change in the function.

Using the equation f(x) = 10,000 * 0.98^x, we can calculate the value of the investment after a certain number of years.

So, in summary, the multiplicative rate of change Hal should use in his function is 0.98, representing a 2% decrease annually. The correct answer is B.

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When a template is created, dummy data is used to verify the formulas in the template.

A template is a pre-designed format or layout that can be used for various purposes, such as creating reports, invoices, or budgets. One of the most important aspects of creating a template is ensuring that all the formulas and calculations used in it are accurate and produce the desired results.

To verify the formulas in a template, dummy data is often used. Dummy data is a set of fictitious or meaningless data that is used to test and verify the functionality of a system or application. In the context of templates, dummy data is used to ensure that the formulas and calculations used in the template are working correctly.

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Check the picture below.

so the parabola looks more or less like so, with a vertex at (-3 , 10) and the directrix above it at -79/8 or namely -9⅞, now, the directrix is just 1/8 of a unit above the vertex, that's our "p" distance, and since the directrix is above the vertex, the parabola is opening downwards and "p" is negative.

[tex]\textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{p~is~negative}{op ens~\cap}\qquad \stackrel{p~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} h=-3\\ k=-10\\ p=-\frac{1}{8} \end{cases}\implies 4(-\frac{1}{8})(~~y-(-10)~~) = (~~x-(-3)~~)^2 \\\\\\ -\cfrac{1}{2}(y+10)=(x+3)^2\implies y+10=-2(x+3)^2\implies \boxed{y=-2(x+3)^2-10}[/tex]

Their bill will increase by $32.99 each month when they make the switch to the unlimited data plan.

To calculate the increase in their monthly bill when switching to the unlimited data plan, we need to compare the costs before and after the switch. Before the switch: Price for 30GB data + unlimited talk and text: $55, Line costs: $19 per line, Taxes: $9.50 per month, Total cost before the switch: $55 + $19 (2 lines) + $9.50 = $102.50 per month.

After the switch: Price for unlimited data + unlimited talk and text: $85, Line costs: $19 per line, Taxes: $12.49 per month, Total cost after the switch: $85 + $19 (2 lines) + $12.49 = $135.49 per month. To determine the increase in their bill, we subtract the total cost before the switch from the total cost after the switch: Increase in bill = Total cost after the switch - Total cost before the switch, Increase in bill = $135.49 - $102.50, Increase in bill = $32.99 per month.

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Without solving for x the exact value of sin(2x) is √99 / 50.

To find the exact value of sin(2x) given that sin(x) = 1/10 and x is in quadrant I, we can use the double-angle identity for sine. The double-angle identity for sine states that sin(2x) = 2sin(x)cos(x).

Given that sin(x) = 1/10, we need to find the value of cos(x) to determine sin(2x). To do this, we can use the Pythagorean identity for cosine, which states that cos^2(x) + sin^2(x) = 1.

Substituting sin(x) = 1/10, we have:

cos^2(x) + (1/10)^2 = 1

cos^2(x) + 1/100 = 1

cos^2(x) = 1 - 1/100

cos^2(x) = 99/100

Taking the square root of both sides (remembering that cos(x) is positive in quadrant I), we have:

cos(x) = √(99/100)

cos(x) = √99 / 10

Now we have the values of sin(x) and cos(x) in quadrant I. We can use the double-angle identity for sine to find sin(2x):

sin(2x) = 2sin(x)cos(x)

sin(2x) = 2 * (1/10) * (√99 / 10)

sin(2x) = √99 / 50

Therefore, the exact value of sin(2x) is √99 / 50.

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The equation in standard form is y = 8x² - 64x + 131.

In Mathematics, the vertex form of a quadratic function is represented by the following mathematical equation:

f(x) = a(x - h)² + k

Where:

Based on the information provided about the vertex (4, 3) and the other points (-4, 131), we can determine the value of "a" as follows:

y = a(x - h)² + k

131 = a(-4 - 4)² + 3

131 - 3 = 16a

128 = 16a

a = 8

Therefore, the required quadratic function in standard form is given by:

y = a(x - h)² + k

y = 8(x - 4)² + 3

y = 8(x² - 8x + 16) + 3

y = 8x² - 64x + 131

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The linear programming problem can be formulated as follows:

Maximize: P = 25x + 40y (profit function)

Subject to:

90x + 160y ≤ 600,000 (manufacturing cost constraint)

x + y ≤ 2,400 (demand constraint)

x, y ≥ 0 (non-negativity constraint)

Maximize: P = 25x + 40y (profit function) - This objective function represents the total profit, which is the sum of the profits from selling model A (25x) and model B (40y).

Subject to: 90x + 160y ≤ 600,000 (manufacturing cost constraint) - This constraint ensures that the total cost of manufacturing model A and model B does not exceed $600,000.

Subject to: x + y ≤ 2,400 (demand constraint) - This constraint ensures that the total number of portable printers produced (model A + model B) does not exceed 2,400 units, which represents the total demand.

Subject to: x, y ≥ 0 (non-negativity constraint) - This constraint ensures that the number of units produced for each model cannot be negative; they must be non-negative values.

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The answer is ⟨y(x) = (-1/27)(5 - 3x)^9 + C, where C is an arbitrary constant⟩.

The given differential equation is:

y' = (5 - 3x)^8

We can separate the variables and integrate both sides:

dy/dx = (5 - 3x)^8

dy = (5 - 3x)^8 dx

Integrating both sides, we get:

∫dy = ∫(5 - 3x)^8 dx

y = (-1/27)(5 - 3x)^9 + C

where C is an arbitrary constant of integration.

Therefore, the general solution of the differential equation is:

y(x) = (-1/27)(5 - 3x)^9 + C

where C is an arbitrary constant.

Hence, the answer is ⟨y(x) = (-1/27)(5 - 3x)^9 + C, where C is an arbitrary constant⟩.

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To determine how many small boxes can fit inside a larger box, we need to calculate the volume of both boxes and then divide the volume of the larger box by the volume of the smaller box.

The volume of the larger box can be calculated by multiplying its dimensions: volume = height * width * length = 16 * 10 * 10 = 1600 cubic inches.

To determine how many small boxes can fit inside, we need the dimensions of the small box. Without this information, we cannot calculate the exact number. However, assuming the small box has dimensions of x inches tall, y inches wide, and z inches long, we can calculate its volume as volume = x * y * z.

Dividing the volume of the larger box by the volume of the small box will give us the number of small boxes that can fit inside: number of small boxes = volume of larger box / volume of small box = 1600 / (x * y * z).

Therefore, to determine the exact number of small boxes that can fit inside the larger box, we need the dimensions of the small box (x, y, z).

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The mean number of televisions per household is approximately 1.93, the variance is approximately 0.7387, and the standard deviation is approximately 0.859.

To find the mean, variance, and standard deviation of the number of televisions per household, we use the formulas:

Mean = Σ(X * P(X))

Variance = Σ[(X - Mean)^2 * P(X)]

Standard deviation = sqrt(Variance)

Using the given probabilities, we can calculate the mean as follows:

Mean = (10.32) + (20.51) + (30.12) + (40.05) = 1.93

To calculate the variance, we first need to calculate the deviations from the mean:

1 - 1.93 = -0.93

2 - 1.93 = 0.07

3 - 1.93 = 1.07

4 - 1.93 = 2.07

Using these deviations and the given probabilities, we can calculate the variance as follows:

Variance = (-0.93^2 * 0.32) + (0.07^2 * 0.51) + (1.07^2 * 0.12) + (2.07^2 * 0.05) = 0.7387

Finally, we can calculate the standard deviation as the square root of the variance:

Standard deviation = sqrt(0.7387) = 0.859

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Answer:

  5√30 ≈ 27.386 square units

Step-by-step explanation:

You want the area of the portion of the plane 5x +2y +z = 10 that lies in the first octant.

The axis-intercepts are found by setting the other variables to zero.

  x-intercept: 5x = 10   ⇒   x = 2

  y-intercept: 2y = 10   ⇒   y = 5

  z-intercept: z = 10

The boundaries of the triangular first-octant portion of the plane will be the lines between these intercepts. The length of each boundary can be found using the distance formula. For example, the length in the X-Y plane will be ...

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

  d = √((0 -2)² +(5 -0)² +(0 -0)²) = √(4+25) = √29

The first attachment shows the other side lengths to be ...

  Y-Z plane: 5√5

  X-Z plane: 2√26

The area of the triangular portion of the plane can be found using Heron's formula. For semi-perimeter s and side lengths a, b, c, the area is ...

  A = √(s(s -a)(s -b)(s -c)) . . . . . . where s = (a+b+c)/2

The second attachment shows the area to be 5√30 ≈ 27.386 square units.

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The approximate value of the surface area is 4.32 square units.

To find the area of the surface, we need to first find the equation of the plane and then determine the portion of the plane that lies in the first octant.

The equation of the plane can be written as:

z = 10 - 5x - 2y

To determine the portion of the plane that lies in the first octant, we need to find the points where the plane intersects the x, y, and z axes. Setting x = 0, y = 0, and z = 0 in the equation of the plane, we get:

z = 10 (when x = 0 and y = 0)

y = 5x (when z = 0 and y = 0)

x = 2 (when z = 0 and x = 0)

The portion of the plane that lies in the first octant is bounded by the x-axis, the y-axis, and the line y = 5x. To find the area of this surface, we can use a double integral:

∬R √(1+f_x^2+f_y^2) dA

where R is the region bounded by the x-axis, the y-axis, and the line y = 5x, and f(x,y) = 10 - 5x - 2y.

Converting to polar coordinates, we have:

x = r cosθ

y = r sinθ

The line y = 5x becomes y = 5r cosθ, and the region R is described by:

0 ≤ r ≤ 2sinθ

0 ≤ θ ≤ π/4

The surface area is then:

A = ∫(0 to π/4) ∫(0 to 2sinθ) √(1+f_r^2+f_θ^2) r dr dθ

Using f(x,y) = 10 - 5x - 2y, we can find:

f_r = -5

f_θ = -2r

So we have:

A = ∫(0 to π/4) ∫(0 to 2sinθ) √(1+25+4r^2) r dr dθ

= ∫(0 to π/4) ∫(0 to 2sinθ) √(29+4r^2) r dr dθ

This integral is difficult to evaluate analytically, but it can be approximated using numerical methods or a computer algebra system.

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The data-set that could be represented by the box and whisker plot is given as follows:

C. 2, 3, 5, 5, 6, 7, 8, 8, 11.

A box and whisker plots shows these five features from a data-set, listed as follows:

The features for the data-set in this problem are given as follows:

The median of the data-set is the 5th element, as the cardinality is of 9, hence we remove the last option also.

As the third quartile is of 8, we have that the mean of the middle elements of the last half is 8, hence option c is correct.

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X is geometrically distributed with a parameter p ∈ (0, 1). The parameter p lies within the interval (0, 1) to ensure that each trial has a non-zero probability of success, and the distribution is well-defined.

For showing that X is geometrically distributed with parameter p, we need to show that P(X=k) = (1-p)^(k-1) * p for all k in N.

Let k be any positive integer. Then,

P(X>k) = P(X>k+j | X>k) * P(X>k) + P(X<=k)      [law of total probability]

       = P(X>j) * P(X>k) + P(X<=k)              [using memory-less property]

       = (1 - P(X<=j)) * P(X>k) + P(X<=k)

       = (1 - ∑P(X=i), i<=j) * ∑P(X=i), i<=k-1 + P(X=k)  

       = P(X=k) + ∑P(X=i), i<j

Since P(X>k) = (1-p)^k for some p in (0,1), we can write

P(X=j+k) = P(X>j) * P(X>k) = (1-p)^j * (1-p)^k = (1-p)^(j+k)

Therefore, we have

P(X=k) + ∑P(X=i), i<j = P(X=k) + ∑(1-p)^(j+i), i<k-j

                       = (1-p)^k + (1-p)^j * ∑(1-p)^i, i<k-j

                       = (1-p)^k + (1-p)^j * ((1-(1-p)^(k-j))/(1-(1-p)))

                       = (1-p)^k + (1-p)^j * (1-(1-p)^(k-j))

                       = (1-p)^(k-1) * p

Hence, we have shown that P(X=k) = (1-p)^(k-1) * p for all k in N, which is the probability mass function of the geometric distribution with parameter p.

To find the parameter p, we use the memory-less property to get

P(X>k+1|X>k) = P(X>1) = p

=> 1 - P(X>k+1|X>k) = 1-p

=> P(X<=k+1|X>k) = 1 - (1-p)^(k+1)

But P(X<=k+1|X>k) = P(X=k+1)/P(X>k), so we have

P(X=k+1)/P(X>k) = 1 - (1-p)^(k+1)

=> p/(1-p) = 1 - (1-p)^(k+1)/ (1-p)^k

=> p = 1/(k+2)

Therefore, X is geometrically distributed with parameter p=1/(k+2).

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Since we need to round the final answer to the next whole number, the required sample size is 544 executives.

To determine the required sample size for the survey, we will use the formula for sample size calculation with a known standard deviation and a desired margin of error:
n = (Z * σ / E)^2
where:
n = required sample size
Z = z-score corresponding to the desired confidence level (98%)
σ = population standard deviation (2.5 hours)
E = margin of error (0.5 hours, which is 30 minutes)
First, we need to find the z-score corresponding to a 98% confidence level. Using the z Distribution Table, we find that the z-score is approximately 2.33.
Now, we can plug in the values into the formula:
n = (2.33 * 2.5 / 0.5)^2
n = (11.65 / 0.5)^2
n = 23.3^2
n ≈ 543.29
Since we need to round the final answer to the next whole number, the required sample size is 544 executives.

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Trace(QpP) is a non-negative integer. In other words, trace(QpP) ≥ 0.

Since trace(PQ) = trace(QpP), we have shown that trace(PQ) ≥ 0, as required.

Since p and q are orthogonal projections, we have p^2 = p and q^2 = q, and p and q are also orthogonal in the sense that p q = q p = 0.

We want to show that trace (PQ) ≥ 0. Let's first expand the expression for the trace of PQ:

trace(PQ) = trace(PQP) = trace(QPP)

Here, we have used the fact that trace(AB) = trace(BA) for any matrices A and B.

Next, let's consider the product QP. Since p and q are orthogonal, their sum p + q is also an orthogonal projection, and we have:

QP = Q(p + q)P = QpP + QqP

Note that QpP is a product of two orthogonal projections, so it is itself an orthogonal projection. Furthermore, since p and q are orthogonal, we have QqP = 0. Therefore, we have:

QP = QpP

Substituting this into the expression for trace(PQ), we get:

trace(PQ) = trace(QpP)

Now, let's consider the eigenvalues of the product Qp. Since p is a projection, its eigenvalues are either 0 or 1. Therefore, the eigenvalues of QpP are also either 0 or 1.

Let λ1, λ2, ..., λn be the eigenvalues of QpP (where n is the dimension of V). Then we have:

trace(QpP) = λ1 + λ2 + ... + λn

Since each eigenvalue is either 0 or 1, we have:

trace(QpP) = number of 1's in the list λ1, λ2, ..., λn

Therefore, trace(QpP) is a non-negative integer. In other words, trace(QpP) ≥ 0.

Since trace(PQ) = trace(QpP), we have shown that trace(PQ) ≥ 0, as required.

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The correct sequence that shows the increasing density of the three phases of water is C) liquid>solid>gas.


- Liquid: In the liquid phase, water molecules are closely packed, but they can still move and slide past each other, resulting in a relatively high density.
- Solid: In the solid phase (ice), water molecules are arranged in a hexagonal lattice structure. This structure has open spaces between the molecules, making it less dense than liquid water.
- Gas: In the gas phase (water vapor), water molecules are widely spaced and move freely, resulting in the lowest density among the three phases.

The increasing density of the three phases of water follows the sequence liquid>solid>gas, which corresponds to option C.

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the conclusion that all people who live in London like it cannot be drawn solely from the given premises.

The conclusion "all people who live in London are people who like it" does not necessarily follow from the given premises.

While it is true that all people who live in London are people who drink tea, and all people who drink tea are people who like it, this does not necessarily mean that all people who live in London like it.

It is possible that there are people who live in London but do not like it, but they still drink tea because it is a cultural norm or for other reasons.

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We will solve the differential equation and find the power series solutions for each problem.

Problem 9: y'' + (sin x)y = 0

Assuming the power series solution: y = a0 + a1x + a2x^2 + ...

Differentiating twice, we have:

y' = a1 + 2a2x + 3a3x^2 + ...

y'' = 2a2 + 6a3x + 12a4x^2 + ...

Substituting these expressions into the differential equation, we get:

2a2 + 6a3x + 12a4x^2 + ... + (sin x)(a0 + a1x + a2x^2 + ...) = 0

Grouping the terms by powers of x, we get:

a0(sin x) = 0

a1(sin x) + 2a2 = 0

a2(sin x) + 6a3 = 0

a3(sin x) + 12a4 = 0

...

From the first equation, we have a0 = 0, since sin(0) = 0. From the second equation, we have a2 = -a1(sin x)/2. From the third equation, we have a3 = -a2(sin x)/6 = a1(sin x)^2/12. From the fourth equation, we have a4 = -a3(sin x)/12 = -a1(sin x)^3/288.

Thus, we have the power series solution:

y = a1x - a1(sin x)^3/288 + ...

This solution is nontrivial, and the ratio of consecutive coefficients is:

-a1(sin x)^3/288 / (a1x) = -(sin x)^3 / (288x)

The ratio approaches zero as x approaches infinity, so the radius of convergence is infinite. Therefore, we expect the solution to be valid for all values of x.

Problem 10: e^xy'' + xy = 0

Assuming the power series solution: y = a0 + a1x + a2x^2 + ...

Differentiating twice, we have:

y' = a1 + 2a2x + 3a3x^2 + ...

y'' = 2a2 + 6a3x + 12a4x^2 + ...

Substituting these expressions into the differential equation, we get:

e^x(2a2 + 6a3x + 12a4x^2 + ...) + x(a0 + a1x + a2x^2 + ...) = 0

Grouping the terms by powers of x, we get:

a0 + (a1 + a0)x + [(2a2 + a1)x^2 + (6a3 + 2a2)x^3 + (12a4 + 6a3)x^4 + ...] = 0

Since the coefficient of x^0 is nonzero, we must have a0 = 0. Then, the coefficient of x^1 gives:

a1 + a0 = 0

a1 = 0

This means that the power series solution is identically zero, which is trivial. Therefore, we cannot form a fundamental set of solutions using power series.

Problem 11: (cos x)y'' + xy' - 2y = 0

Assuming the power series solution: y = a0 + a1x + a2x^2 + ...

Differentiating twice, we have:

y' = a1 + 2a2x + 3a3x

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The simplified expression is 1+14i.

Given that an expression including the complex numbers (-2 + 3i) - (-3 - 11i)

We need to solve the expression,

= (-2 + 3i) - (-3 - 11i)

= -2 + 3i + 3 + 11i

= 1 + 14i

Hence the simplified expression is 1+14i.

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The probability that exactly one girl and two boys will receive awards is 20%, which corresponds to the answer option closest to it, 18%.

Total number of possible outcomes: We have 10 participants in total (6 girls and 4 boys) competing for the three awards. The order in which the awards are given matters. Therefore, the total number of possible outcomes can be calculated using permutations: Total outcomes = P(10, 3) = 10! / (10 - 3)! = 10! / 7! = 10 * 9 * 8 = 720.

Number of favorable outcomes: To calculate the number of favorable outcomes, we need to choose one girl out of six and two boys out of four. Again, the order matters since we are considering first, second, and third place. Favorable outcomes = P(6, 1) * P(4, 2) = 6! / (6 - 1)! * 4! / (4 - 2)! = 6 * 4 * 3 * 2 = 144.

Now, we can calculate the probability: Probability = (Number of favorable outcomes) / (Total number of possible outcomes) = 144 / 720 = 0.2 = 20%.

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The value of the calculated ending balance would be $141.

From the question, we have the following parameters that can be used in our computation:

Starting balance = $80

Checks = 4 at $10 each

Bills = 3 at $7 each

Using the above as a guide, we have the following:

Ending balance = 80 + 4 * 10 + 3 * 7

Evaluate

Ending balance = 141

Hence, the value of the ending balance is $141

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The possible values for |a| are limited to 0, 1, and infinity.

To see why, suppose that |a| is strictly greater than 1. Then by the spectral radius formula, we have that the spectral radius of a is also strictly greater than 1.

Let λ be an eigenvalue of a with maximum absolute value, and let v be a corresponding eigenvector. Then for any positive integer m, we have

|a^m v| = |a^m| |v| = |a|^m |v|,

where the second equality follows from the fact that a is diagonalizable (since it has real entries) and so a^m has the same eigenvectors as a (with eigenvalues raised to the mth power). Thus |a^m v| grows exponentially with m, contradicting the assumption that ak = a for some integer k > 1.

Similarly, if |a| is strictly less than 1, then the spectral radius of a is also strictly less than 1, and the same argument shows that the norm of a^m v decays exponentially with m, again contradicting the assumption that ak = a for some integer k > 1.

Therefore, the only possible values for |a| are 0, 1, and infinity. If |a| = 0, then a is the zero matrix and satisfies ak = a for any k

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