Please help me thank you

The molecular formula of the compound is P₂O₅.

To determine the molecular formula for a compound with the given percent compositions, we can assume a certain mass for the compound and calculate the number of moles for each element based on its percentage. Then, we can determine the simplest whole-number ratio of the elements to find the molecular formula.

Let's assume a mass of 100 grams for the compound. From the given percent compositions, we have 43.7 grams of phosphorus (P) and 56.3 grams of oxygen (O).

Next, we calculate the moles of each element using their molar masses. The molar mass of phosphorus (P) is 30.97 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.

The moles of phosphorus can be calculated as:

moles of P = mass of P / molar mass of P = 43.7 g / 30.97 g/mol ≈ 1.41 mol

The moles of oxygen can be calculated as:

moles of O = mass of O / molar mass of O = 56.3 g / 16.00 g/mol ≈ 3.52 mol

Now, we find the simplest whole-number ratio of the elements by dividing the moles of each element by the smallest number of moles (1.41 mol in this case):

P:O ≈ 1.41 mol / 1.41 mol : 3.52 mol / 1.41 mol ≈ 1:2.5

Since we need whole-number ratios, we can multiply both numbers by 2 to get a whole number for oxygen:

P:O ≈ 2:5

Therefore, the molecular formula of the compound is P₂O₅.

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Answer: b. Aluminum

Explanation:

Frist count all the electrons in the given model. You will get there is 13 electrons. The number of electrons in an element is equivalent to the number of protons in an element. Using a periodic table look for the element that has the equivalent amount of protons. You find that Aluminum has 13 protons, so it is the element shown in the diagram.

Answer:

the answer is 57.03%

Explanation:

%yield= ((practical yield)/(theoretical yield))×100%

Answer:

136.2295 grams of Ar

Explanation:

Simply multiply the moles by the grams. 3.41x39.95=136.2295.

The most accurate statement about signal transmissions among the given options is:

a) All signals in transmission will lose clarity with distance.

When a signal is transmitted over a distance, it can experience various types of degradation or attenuation. Factors such as distance, interference, noise, and the medium through which the signal travels can all contribute to a reduction in the clarity or quality of the signal. This means that as the distance between the source and receiver increases, the signal may become weaker, distorted, or prone to interference, resulting in a loss of clarity.

Answer:

Explanation:

Solution 1:

In this solution, copper(II) carbonate (CuCO3) reacts with sodium oxide (Na2O) to form copper(II) oxide (CuO), sodium carbonate (Na2CO3), and carbon dioxide (CO2). The water (H2O) does not participate in the reaction and remains unchanged.

Solution 2:

In this solution, copper(II) carbonate (CuCO3) reacts with sodium oxide (Na2O) to form copper(II) hydroxide (Cu(OH)2) and sodium bicarbonate (NaHCO3). Carbon dioxide (CO2) and water (H2O) are also formed in the reaction.

Nature has provided us numerous gifts such as air, water, land, sunlight, minerals, plants, and animals. All these gifts of nature make our earth a place worth living. Existence on Earth would not be possible without any of these. Now, while these natural resources are present on Earth in plenty. Unfortunately, the necessity of most of these has increased extremely over the centuries due to growth in the human population.

To preserve nature in your day-to-day life:

Reduce waste: Avoid single-use items and recycle materials like paper, plastic, glass, and metal.

Conserve water: Use water wisely, fix leaks, and consider collecting rainwater.

Save energy: Opt for energy-efficient appliances and turn off lights and electronics when not in use.

This is only the tip of the iceberg. You could also help in massive projects to rid the ocean of all waste (I'm talking about TheOceanCleanup, search it up), or do something more small, like helping out in your local community.

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The pH of the resulting solution after mixing 50 mL of 0.180 M [tex]NH_{3}[/tex] with 5 mL of 0.360 M HBr is approximately 11.56.

To calculate the pH of the resulting solution after mixing NH3 and HBr, we need to consider the reaction between NH3 (ammonia) and HBr (hydrobromic acid).

First, let's write the balanced chemical equation for the reaction:

[tex]NH_{3} + HBr - > NH_{4+} + Br-[/tex]

We can see that [tex]NH_{3}[/tex] acts as a base and HBr acts as an acid, forming the ammonium ion ([tex]NH_{4+}[/tex]) and bromide ion (Br-).

Next, we'll determine the initial moles of NH3 and HBr:

Moles of NH3 = concentration (M) × volume (L) = 0.180 M × 0.050 L = 0.009 mol

Moles of HBr = concentration (M) × volume (L) = 0.360 M × 0.005 L = 0.0018 mol

Since NH3 and HBr react in a 1:1 ratio, NH3 will be completely consumed, and we'll be left with 0.009 - 0.0018 = 0.0072 mol of NH4+ ions.

Now, let's calculate the concentration of NH4+ ions in the final solution:

Volume of the final solution = 50 mL + 5 mL = 55 mL = 0.055 L

Concentration of NH4+ ions = moles / volume = 0.0072 mol / 0.055 L = 0.131 M

Next, we need to calculate the pOH of the solution using the Kb of ammonia:

[tex]Kb = [NH_{4+}][OH-] / [NH_{3}][/tex]

Since the concentration of NH4+ is equal to the concentration of OH- in this case, we can rewrite the equation:

[tex]Kb = [OH-]^2 / [NH3]\\[OH-] = sqrt(Kb * [NH3]) = sqrt(1.77*10^-5 * 0.131) = 3.62*10^-3 M[/tex]

Now, we can calculate the pOH:

[tex]pOH = -log10([OH-]) = -log10(3.62*10^-3) = 2.44[/tex]

Finally, we can calculate the pH using the equation:

pH = 14 - pOH = 14 - 2.44 = 11.56

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Answer:

Approximately 4.678 moles

Explanation:

150/32.065 (atomic weight of S)

Answer:

4.677 Moles

Explanation:

150g / 32.07g = 4.677268475 moles

Distillation and chromatography are separation techniques in chemistry. Distillation separates liquid mixtures based on boiling points.

While chromatography separates components based on differential interactions with a stationary and mobile phase. Distillation is used for liquids with distinct boiling points, while chromatography is versatile for complex mixtures.

Distillation depends on heating and condensing vapors, while chromatography involves the movement of components through a stationary phase. Both techniques have diverse applications in various fields of science.

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The following for the substance, statement  1) It will also change from a solid to a liquid at 24 degrees Celsius while the solid loses energyis the only accurate statement among the given options.

Based on the information provided, we can determine the following statements to be true for the substance with a freezing point of 24 degrees Celsius:

When a substance reaches its freezing point, it transitions from a solid to a liquid state. This transition occurs as the solid loses energy and its particles gain enough kinetic energy to break the intermolecular forces holding them in a fixed arrangement.

2) It will also change from a solid to a liquid at 24 degrees Celsius while the solid gains energy.

This statement is incorrect. The process of transitioning from a solid to a liquid occurs as the solid loses energy, not gains energy. The particles in the solid state require a reduction in energy to break their fixed positions and transition into the more mobile liquid state.

3) It will also change from a solid to a gas at 24 degrees Celsius while the solid loses energy.

This statement is incorrect. The transition from a solid to a gas is known as sublimation and occurs when the solid directly converts into a gas without passing through the liquid state. It typically happens at temperatures above the substance's boiling point, not its freezing point. Therefore, at 24 degrees Celsius, it is unlikely for the substance to change from a solid to a gas.

4) It will also change from a solid to a gas at 24 degrees Celsius while the solid gains energy.

This statement is incorrect for the same reasons explained above. The transition from a solid to a gas generally occurs at temperatures above the substance's boiling point, not at its freezing point. Additionally, the process requires the solid to gain energy, not lose energy.

In summary, statement 1 is the only accurate statement among the given options.The correct statement is 1.

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The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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Answer:

Explanation:

To find the concentration of hydroxide ions ([OH-]) in an aqueous solution, we can use the relationship between hydrogen ion concentration ([H+]) and hydroxide ion concentration in water at 25 °C, which is given by the equation:

[H+] x [OH-] = 1.0 x 10^-14

Given that the hydrogen ion concentration ([H+]) is 5.7 x 10^-10 (derived from the H* concentration provided), we can rearrange the equation to solve for [OH-]:

[OH-] = (1.0 x 10^-14) / [H+]

[OH-] = (1.0 x 10^-14) / (5.7 x 10^-10)

[OH-] ≈ 1.754 x 10^-5

Therefore, the concentration of hydroxide ions ([OH-]) in the given aqueous solution is approximately 1.754 x 10^-5.

A. Cell reaction:[tex]2 Cd^2+(aq) + 2 Cr(s) - > 2 Cd(s) + 2 Cr^2+(aq) ; E^0cell = -0.51 V[/tex]

B. Cell reaction: [tex]2 Fe^2+(aq) + Br2(g) - > 2 Fe(s) + 2 Br^-(aq) ; E^0cell = +1.507[/tex]

Let's calculate the standard cell potential, E^0cell, for each pair of half-reactions and write the balanced equations for the overall cell reactions:

A. Half-reactions:

[tex]Cd^2+(aq) + 2e^- - > Cd(s) (E^0 = -0.403 V)\\Cr^2+(aq) + 2e^- - > Cr(s) (E^0 = -0.913 V)[/tex]

To calculate the standard cell potential, we subtract the reduction potential of the anode (oxidation half-reaction) from the reduction potential of the cathode (reduction half-reaction).

[tex]E^0cell = E^0cathode - E^0anode\\E^0cell = (-0.913 V) - (-0.403 V) = -0.51 V[/tex]

The balanced equation for the overall cell reaction is obtained by multiplying the half-reactions by coefficients to ensure that the number of electrons transferred is the same:

[tex]2 Cd^2+(aq) + 2 Cr(s) - > 2 Cd(s) + 2 Cr^2+(aq)[/tex]

B. Half-reactions:

[tex]Fe^2+(aq) + 2e^- - > Fe(s) (E^0 = -0.447 V)\\Br2(g) + 2e^- - > 2 Br^-(aq) (E^0 = +1.06 V)\\E^0cell = E^0cathode - E^0anode\\E^0cell = (+1.06 V) - (-0.447 V) = +1.507[/tex]V

The balanced equation for the overall cell reaction is:

[tex]2 Fe^2+(aq) + Br2(g) - > 2 Fe(s) + 2 Br^-(aq)[/tex]

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To determine the volume of the balloon at an altitude of 8.70 km, we will use the combined ideal gas law, which relates the pressure, volume, and temperature of a gas.

The combined ideal gas law is a mathematical relationship that relates the pressure, volume, and temperature of a gas. This law is a combination of Boyle's, Charles', and Gay-Lussac's laws, and is used to describe the behavior of gases under ideal conditions.

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \frac{P_1\times V_1}{T_1}=\frac{P_2\times V_2}{T_2} } \end{gathered}$} }[/tex]

Where:

First, we'll convert the temperatures to Kelvin by adding 273 to the Celsius values:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{T_1=21.9 \ ^{\circ}C+273 = 294.9 \ K} \end{gathered}$} }[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{T_2=-35.1 \ ^{\circ}C+273 = 237.9 \ K} \end{gathered}$} }[/tex]

The clear formula is:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\dfrac{P_1\times V_1\times T_2}{P_2\times T_1} } \end{gathered}$}}[/tex]

Where:

Substituting the known values into the formula, we get:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{(759\not{mmHg}\times879 \ L\times237.9\not{k}) }{281\not{mmHg}\times294.9\not{k} } } \end{gathered}$} }[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\dfrac{158717601.9 \ L}{82866.9 } } \end{gathered}$} }[/tex]

[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2\approx1915.33 \ L } \end{gathered}$} }}[/tex]

As per the given details, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.

Based on the provided information, we can match the metals to the methods used to extract them as follows:

Sodium - Extracted by electrolysis of a molten ionic compound.

Magnesium - Extracted from its oxide by reduction with carbon.

Carbon - Not a metal, so it doesn't apply in this context.

Metal E - Extracted from its oxide by reduction with hydrogen.

Iron - Removed from earth as metal itself.

Hydrogen - Not a metal, so it doesn't apply in this context.

Copper - Not a metal D or E, so it doesn't apply in this context.

Matching the metals to the extraction methods:

Sodium - extracted by electrolysis of a molten ionic compound.

Magnesium - extracted from its oxide by reduction with carbon.

Metal D - extracted from its oxide by reduction with hydrogen.

Metal E - removed from earth as metal itself.

Iron - removed from earth as metal itself.

Therefore, Metal D is extracted from its oxide by reduction with hydrogen, and Metal E is removed from the earth as the metal itself.

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Answer:

The substance which is used for white washing is Calcium oxide . Calcium oxide when reacted with water produces Calcium hydroxide(Lime water).

Explanation:

Answer:

0.877 mL

Explanation:

The box's density would be the ratio of the mass of the box and its volume
which is, (23.23/26.5) mL
or, 0.8766 mL
We must round this down to 3 significant figures,
which will be 0.877 mL

1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Answer: Therefore, the concentration of hydroxide ions [OH-] in the given solution is 4.0 x 10⁻¹⁹M.

We know that In an aqueous solution Kw is the ionization constant of water.

Kw = [H3O⁺][OH⁻]

[OH⁻] = [tex]\frac{Kw}{[H3O^+]}[/tex]--------------------------------------(a)

Kw = ionization constant of water

[H3O⁺]= the concentration of hydronium ions

[OH⁻]  =  the concentration of hydroxide ions

Kw = 1x10⁻¹⁴M²-------------------(i)

[H3O⁺]= 2.5 x 10⁴M------------------(ii)

[OH⁻]  = ?    

NOW Putting values in  (i) and (ii) in equation (a)

[OH⁻] = [tex]\frac{1 X 10^-^1^4}{2.5 X 10^4}[/tex]

[OH⁻] =  4.0 x 10⁻¹⁹M

Explanation:

To calculate the number of SO₂ molecules in 1.28 moles of SO₂, we need to use Avogadro's number

Avogadro's number =  6.022 × 10²³ molecules per mole.

First, we'll calculate the number of molecules in 1 mole of SO2:

1 mole of SO₂ = 6.022 × 10²³ molecules.

Then, we'll multiply this value by the number of moles of SO₂ given (1.28 moles):

Number of molecules = 1.28 moles × (6.022 × 10²³ molecules/mole)

Calculating this, we get:

Number of molecules = 7.70176 × 10²³molecules

Answer:

(If you like this answer i would appreciate if u give brainliest but otherwise, i hope this helped ^^)

Explanation:

White washing is a traditional technique where a mixture or solution is applied to surfaces to give them a white appearance. The substance 'X' mentioned in your question could refer to various materials or chemicals commonly used in white washing. Some common substances used for white washing include lime, chalk, or a combination of lime and water.

Lime is a key component in many white washing solutions. It is derived from heating limestone or chalk, which produces calcium oxide (quicklime). Quicklime is then slaked with water to produce calcium hydroxide (slaked lime). The slaked lime is mixed with water to form a white wash solution.

Chalk, when ground into a fine powder, can also be used as a whitening agent in white wash solutions. The chalk particles are mixed with water to form a paste or solution.

Both lime and chalk-based white wash solutions provide a thin, breathable coating that adheres to surfaces and helps protect them while giving a white appearance. The solution can be applied to various surfaces, including walls, fences, and even trees or structures in the outdoors.

It's important to note that the specific recipe for white wash solutions may vary depending on regional preferences and desired effects. Additionally, the application techniques and preparations may differ based on the surface being treated.

A chemical symbol is to an element as a chemical formula is to a **compound**.

A chemical symbol is a one- or two-letter designation of an element. For example, the symbol for oxygen is O. A chemical formula is a combination of chemical symbols that shows the elements in a compound and the relative proportions of those elements. For example, the chemical formula for water is H2O, which means that water is made up of two hydrogen atoms and one oxygen atom.

So, a chemical symbol is a short way of representing an element, while a chemical formula is a short way of representing a compound.

The column 1 has the value of Isotope, column 2 has the value of mass in atomic mass units, and column 3 has the value of abundance and the average atomic mass of strontium is 87.47 amu.

To calculate the average atomic mass of strontium using the given information, we need to multiply the mass of each isotope by its abundance and then sum up these values. Here's the calculation:

Isotope | Mass (amu) | Abundance

^84Sr | 83.913428 | 0.56%

^86Sr | 85.909273 | 9.86%

^87Sr | 86.908902 | 7.00%

^88Sr | 87.905625 | 82.58%

To find the average atomic mass, we multiply each isotope's mass by its abundance (in decimal form) and sum up the values:

Average atomic mass = ([tex]Mass of ^{84Sr}[/tex] × [tex]Abundance of^{84Sr}[/tex]) + ([tex]Mass of ^{86Sr}[/tex]× [tex]Abundance of^{86Sr}[/tex]) + ([tex]Mass of ^{87Sr}[/tex] × [tex]Abundance of^{87Sr}[/tex]) + ([tex]Mass of ^{88Sr}[/tex] × [tex]Abundance of^{88Sr}[/tex])

Average atomic mass = (83.913428 amu × 0.0056) + (85.909273 amu × 0.0986) + (86.908902 amu × 0.0700) + (87.905625 amu × 0.8258)

Calculating this expression yields:

Average atomic mass = 0.469901638 + 8.468098826 + 6.08462314 + 72.44409075

= 87.466714354 amu

Rounding the result to two decimal places, the average atomic mass of strontium is approximately 87.47 amu.

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