Potassium sulfate has a solubility of 15g/100g water at 40 Celsius. A solution is prepared by adding 39.0g of potassium sulfate to 225g water, carefully heating the solution, and cooling it to 40 Celsius. A homogeneous solution is obtained. Is this solution saturated, unsaturated, or supersaturated? The beaker is shaken and precipitation occurs. How many grams of potassium sulfate would you except to crystallize out?please help me to understant this

Answers

Answer 1

Answer:

5.25 grams of potassium sulfate will get crystallize out.

Explanation:

Solubility of potassium sulfate at 40 °C = 15 g/100 g

This means that at 40 °C 15 g of potassium sulfate will get completely dissolved in 100 of water.

39.0 g of potassium sulfate to 225 g water, carefully heating the solution.

Amount of potassium sulphate will get dissolve in 225 g of water at 40 °C will be:

[tex]\frac{15g}{100g}[/tex] × 225 = 33.75g

Amount of potassium sulfate precipitated out by the solution:

= 39.0 g-33.75 g = 5.25 g

At 40 °C 5.25 g of potassium sulfate will get precipitate out from the solution which means that solution is saturated.

Saturated solution are solution in which solute is dissolved in maximum amount. Further addition of solute results in precipitation of solute form the solution.

5.25 grams of potassium sulfate will get crystallize out.

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Related Questions

Nail polish remover is something that girls just can't do without. Which of the following has been used as the active ingredient in nail polish remover?
limonene
acetone
methanol
ethanol

Answers

Answer:

Acetone has been used as the active ingredient in nail polish remover.

Because electron delocalization stabilizes a compound, if the only way electrons can be moved is away from the most electroneagtive atom, that is better than no electron delocalization at all.

a. True
b. False

Answers

It’s is false because it is

As electron delocalization stabilizes the compound it is necessary that it takes place for compound to exist , hence the given statement is false.

What is a compound?

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

They have a unique chemical structure held together by chemical bonds .Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.

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Calculate the second ionization energy of the metal M (?Hion2� in kJ/mol) using the following data:


Lattice enthalpy of MO(s), ?Hl� = -2383 kJ/mol

Bond dissociation enthalpy of O2(g) = +498 kJ/mol

First electron affinity of O = -141 kJ/mol

Second electron affinity of O = +744 kJ/mol

Enthalpy of sublimation of M = + 130 kJ/mol

First ionization energy of M = + 267 kJ/mol

Standard enthalpy of formation of MO(s), ?Hf� = -307 kJ/mol

Answers

From the information provided in the question, the second ionization energy of the metal is  578 kJ/mol.

From the question, we have the following information;

Lattice enthalpy of MO(s) = -2383 kJ/mol

Bond dissociation enthalpy of O2(g) = +498 kJ/mol

First electron affinity of O = -141 kJ/mol

Second electron affinity of O = +744 kJ/mol

First ionization energy of M = + 267 kJ/mol

Heat of sublimation of M = + 130 kJ/mol

Standard enthalpy of formation of MO(s) = -307 kJ/mol

Using Hess law of constant heat summation;

ΔHf = ΔHs + BE + ∑IE + ∑EA + U

ΔHs  = Heat of sublimation of metal

ΔHf = Heat of formation MO

BE = Bond energy of O2

∑EA  = sum of electron affinities of Oxygen

∑IE  = Sum of the ionization energies of M

U = Lattice energy of MO

Let the second ionization energy be x

Substituting values;

(-307) = 130 + 498 + (267 + x) + 603 + (-2383)

(-307) = -885 + x

-x =   -885 + 307

-x = -578

x = 578 kJ/mol

The second ionization energy of the metal is  578 kJ/mol.

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Physical change does not produce a nee substance true or false

Answers

Answer:

ooooooooh .,.,.,.,.,.,

Answer:

True

TruePhysical change – A change in the size, shape, color, or state of matter of a substance. No new substance is produced.

PLEASE HELP ME ASAP

Use the equation to answer the question.
4NaCl + 2502 +_____
H2O +______02 →______Na2SO4 + 4HCI
Which numbers balance this equation?
(1 point)
O 2, 1, 2
O 1,2,4
O 2, 1,4
o 1,2,2

Answers

Answer: O 2, 1,4

Explanation:

The box shows the chemical formula for bleach.

Answers

Bleach contains sodium chlorine and oxygen

For the reaction C + O2 = CO2, if 3 grams of carbon react with the oxygen, how many grams of carbon dioxide are produced?

Answers

3gC x 1molC/12.011gC x 1molCO2/1molC x 44.011gCO2/1molCO2

This gives you 10.99267338g CO2

10 g CO2 if it is one sig fig
11.0 g CO2 if it is two sig fig

how many nuetrons are in the nucleous of an atom number of 25?

Answers

Answer:

I believe there are 30

Explanation:

Determine the molarity for each of the following Solution: 98.0 of phosphoric acids H3PO4 in 1.00L of Solution.​

Answers

The molarity of the solution is 0.01.

Brainliest?

p-Nitrobenzaldehyde is more reactive toward nucleophilic additions than pmethoxybenzaldehyde. Explain

Answers

The presence of electron donating methoxy group in  p-methoxybenzaldehyde , makes it less reactive towards  nucleophilic additions.

Nucleophilic addition reactions that involve of p-Nitrobenzaldehyde and p-methoxybenzaldehyde both occur at the C=O functional group. The electron density around the carbonyl is a key factor that controls the reactivity of each compound.

In  p-Nitrobenzaldehyde, the electron withdrawing nitro group decreases the electron density around the carbonyl making it more vulnerable to nucleophilic attack.

In p-methoxybenzaldehyde, the methoxy group donates electrons by resonance towards the carbonyl thereby increasing the electron density around it so that it is less reactive towards nucleophillic addition reaction.

The nucleophilic attack on p-Nitrobenzaldehyde leads to more resonance structures than nucleophilic attack on p-methoxybenzaldehyde.

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6) 0.5 moles of gas is kept at 2.0 L of volume and 0.75 atm of pressure. What is the temperature of the gas in K?

Answers

Answer:

310K

Explanation:

Rearrange PV=nRT to get T=PV/nR

T=(2.0L)(0.75atm)/(0.5mol)(0.08206)

=36.5 or 37

add 273 for K to get

310

as the solar nebula cooled which compounds were the first to condense from a gas to a solid? Rock water ice or metal

Answers

As the solar nebula cooled METAL compounds are the first to condense from a gas to a solid. The solar nebula gave birth to the Solar system.

A solar nebula is a disc-shaped cloud of gases and grain dust, which gave birth to the Sun and planets of the Solar system, approximately 4.6 billion years ago.

The solar nebula is at the beginning a mixture of interstellar gases (hydrogen and helium) and dust grains.

As the solar nebula cools, heavy elements such as metals in the disk condensate into planetesimals.

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How many federal agencies are responsible for managing land resources in the United States?
2
4
ОООО
6
10

Answers

The answer would be 4.

The agencies are:

Department of Agriculture's Forest Service (AFS)

Department of the Interior's Bureau of Land Management (BLM)

Fish and Wildlife Service (FWS)

National Park Service (NPS)

These four agencies cover around 95% of the land and are the only federal agencies.

I learned about these agencies in school.

Magnesium metal burns in air with an intense bright light according to the equation
2 Mg(s) + O2(g) → 2 MgO(s) + 1200 kJ

A.) What is the amount of energy in kJ produced when 4.5 mol of Mg is burned in the presence of excess oxygen?

Answers

The heat produced by 4.5 moles of magnesium when burnt is 2700 kJ.

A thermochemical reaction is a reaction in which the amount of heat lost or gained is included in the reaction equation. The thermochemical reaction equation for the combustion of magnesium is shown as follows;

2 Mg(s) + O2(g) → 2 MgO(s) + 1200 kJ

From the reaction equation;

2 moles of magnesium produced 1200 kJ of heat

4.5 moles of magnesium will produce 4.5 moles × 1200 kJ/2 moles

= 2700 kJ

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Calculate the number of molecules present in 11 moles of H2O.

Answers

Answer:

[tex]11 \times 6.022 \times {10}^{23} \\ = 66.242\times {10}^{23} \: of \: \\ water \: molecules[/tex]

Why did you place each biotic factor in the model where you did?

Answers

Answer:

Biotic and abiotic are the two essential factors responsible for shaping the ecosystem. The biotic factors refer to all the living beings present in an ecosystem, and the abiotic factors refer to all the non-living components like physical conditions (temperature, pH, humidity, salinity, sunlight, etc.) and chemical agents (different gases and mineral nutrients present in the air, water, soil, etc.) in an ecosystem. Therefore, both the abiotic and biotic resources affect survival and reproduction process.

Furthermore, both these components are reliant on each other. Suppose if one of the factors is removed or altered, its repercussions will be faced by the entire ecosystem. Without a doubt, abiotic factors directly affect the survival of organisms. Read on to explore what role do abiotic and biotic resources play in the ecosystem.

The two primary forces influencing the ecosystem are biotic and abiotic. The terms "biotic factors" and "abiotic factors" describe the various living and non-living elements of an ecosystem, respectively.

What is biotic factor ?

A living thing that alters its surroundings is referred to as a biotic factor. Examples of organisms found in a freshwater habitat include algae, fish, amphibians, and aquatic plants. A particular ecosystem is the result of the interaction of biotic and abiotic components.

All living things, including people, fungi, and bacteria as well as animals and plants, are considered to be biotic factors. For each species to reproduce and to meet basic needs like food, the interactions between numerous biotic variables are vital.

Due to the fact that these organisms "create" food using inorganic materials and energy sources, the producers are biotic elements that are crucial to an ecological system. Without them, life might not be able to exist.

Thus, The two primary forces influencing the ecosystem are biotic and abiotic.

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Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid with water

Answers

Answer:

C6H5CO2H (aq) + H2O (l) _C6H5CO2- + H3O

Mechanical waves travel fastest through
A -Solid
B -Liquid
C -Gas
D -Vacuum

Answers

Answer:

A-Solid

Explanation:

Waves travel faster in solids & slowest in gases

Which of the following types of models is generally used to predict long-term events? a. idea model b. physical model c. computer model d. none of the above Please select the best answer from the choices provided A B C D Mark this and return

Answers

Answer:

C

Computer model is generally used to predict long-term events

I hope it helps.

What is your opinion of Latino immigrants in your country?

Answers

Answer:

I believe they deserve to be here.

Explanation:

Calculate the moles of HCl in 15 mL of a 0.50 M solution.

Answers

Explanation:

[tex]\tiny\implies Molarity = \dfrac{no. \: of \: moles \: of \: solute \times 1000}{volume \: of \: the \: solution \: (in \: ml)} [/tex]

[tex]\tiny\implies 0.50 = \dfrac{no. \: of \: moles \: of \: solute \times 1000}{15}[/tex]

[tex]\tiny\implies no. \: of \: moles \: of \: solute \times 1000 = 0.50 \times 15[/tex]

[tex]\tiny\implies no. \: of \: moles \: of \: solute \times 1000 = 7.5[/tex]

[tex]\tiny\implies no. \: of \: moles \: of \: solute = \dfrac{7.5}{1000} [/tex]

[tex]\tiny\implies \bf no. \: of \: moles \: of \: solute = 0.075 \: mol[/tex]

HELP ME OUT PLEASE!!!!!!!!

A chemical reaction in which calcium carbonate (CaCO3) is decomposed (broken down) results in the production of two simpler compounds. (See diagram) What mass of Calcium Carbonate (CaCO3) to the nearest hundredth of a gram, is broken down in this reaction?

A) 28 00g

B) 21979

C) 49.979

D) 50.000​

Answers

Answer:

49.979

Explanation:

Find the mass of 1.220 moles of PH5.

Answers

Answer:

43.93642

Explanation:

Phosphorus P 30.973762 1 86.0061

Hydrogen H 1.00794 5 13.9939

I don't know physics, but I hope this helps :)

(I'm a seventh grader so don't judge if this is wrong please)

4. Use the atomic model to answer the following questions

A. How many protons?

B. How many neutrons?

C. What is the name of this atom?​

Answers

Answer:

´protons: 16

neutrons: 16

name: sulfur

Explanation:

5. Select the answer for both questions ​

Answers

Answer:

engey

Explanation:

How many carbon dioxide molecules and water molecules are needed to make one molecule of glucose?

Answers

Answer:

It takes six molecules of carbon dioxide and six molecules of water to make one molecule of glucose.

. Nhiệt độ ban đầu của 344 g một mẫu sắt là 18,2oC. Nếu mẫu sắt này hấp thụ 2,25 kJ nhiệt lượng thì nhiệt độ cuối của mẫu sắt này là bao nhiêu? (CFe = 0,449 J/g.K).

Answers

Answer:

i can't understand the question

Please help asap chemistry worksheet doesn’t make sense

Answers

Answer:

dog dog im not gon hold u we kinda screwed

Select the container from the figure (Figure 1) that represents the dilution of a 4 % (m/v) KCl solution to each of the following: Figure1 of 1 There is a diagram showing several containers. One container is filled with 4 percent of mass to volume solution of NaCl. Container 1 is filled with a solution in which volume is two times less than the volume of NaCl solution. Container 2 is filled with a solution of a volume two times larger compared to the NaCl solution. Container 3 is filled with a solution of a volume two times larger than the volume of the solution in container 2. Part A 2 % (m/v) KCl

Answers

From the dilution formula, we have that at constant value of the solute, the volume of the solution is inversely proportional to the concentration.

The correct responses are;

Part A: Container 2Part B: Container 3

Reasons:

The given parameters are;

The concentration of the KCl solution = 4% m/v

Taking the solution as solution of KCl

The volume of the solution in container 1 = Two times less than the volume of KCl solution.

[tex]V_{container \, 1} = \displaystyle \mathbf{ \frac{1}{2} \cdot V_{4\% \, solution}}[/tex]

The volume of the solution in container 2 = Two times larger compared to the volume of KCl solution.

[tex]V_{container \, 2} = \mathbf{\displaystyle 2 \times V_{4\% \, solution}}[/tex]

The volume of the solution in container 3 = Two times larger than the container two solution volume.

[tex]V_{container \, 3} = \displaystyle \mathbf{ 2 \times V_{container \, 2}}[/tex]

Therefore;

[tex]V_{container \, 3} = \displaystyle 2 \times 2 \times V_{4\% \, solution} = \mathbf{4 \times V_{4\% \, solution }}[/tex]

Part A Required:

a. To select the container that represent the dilution of the 4% solution to 2%

Solution:

The dilution formula is; C₁·V₁ = C₂·V₂

Therefore;

[tex]\displaystyle V_1 = \mathbf{\frac{C_1 \cdot V_1}{C_2}}[/tex]

C₁ =4%, C₂ = 2%, we get;

[tex]\displaystyle V_1 = \frac{4 \cdot V_1}{2} = 2 \cdot V_1[/tex]

The volume of the container that represents a 2% dilution is container 2

which is filled with a solution of a volume two times larger compared to the

KCl solution.

Part B:

Required:

The container diluted to a 1% m/v KCl solution.

Solution;

Using the dilution formula, we have;

C₁ = 4%, C₂ = 1%

Therefore;

[tex]\displaystyle V_1 = \frac{C_1 \cdot V_1}{C_2}[/tex]

[tex]\displaystyle V_1 = \frac{4 \cdot V_1}{1} = \mathbf{4 \cdot V_1}[/tex]

The volume of the solution is four times the volume of the 4% KCl solution, which is equivalent to the volume in container 3.

Possible parts of the question are;

Select the container that represents the dilution of the 4% (m/v) KCl solution to obtain the solutions that follows;

Part A: a 2% (m/v) KCl solution

Part B: a solution that is a 1% (m/v) KCl solution

Please see attached drawings

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How many grams are 0.300 moles of glucose, C6H12O6?

Answers

Answer:

Explanation:

Firstly, let us calculate the molar mass of the glucose. To find the molar mass we need to add the masses of individual elements which constitute one glucose molecule.

Now, we know that

Molar mass of Carbon C=12gmol−1

Molar mass of Hydrogen H=1gmol−1

Molar mass of oxygen O=16gmol−1

Therefore, Molar Mass of glucose (C6H12O6) can be calculated as shown below

⇒ 6×12+12×1+6×16

⇒72+12+96⇒180gmol−1

Given mass of glucose = 300g

Now, we can calculate the number of moles in given mass of glucose, using the below formula,

Using the Formula numberofmoles=givenmassmolarmass we get

numberofmoles=300180 = 1.7 moles or 2 moles (approx.)

Hence the number of moles present in 300 g of glucose is 1.7 moles or 2 moles approximately.

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