Usando la información contenida en la pregunta, la distancia que recorre la bola hacia arriba es de 15 m.
Velocidad inicial = 20 m / s
Tiempo= 3 s
Aceleración por gravedad = 10 ms-2
Velocidad final = 0 m / s
Usando la ecuación;
h = u t - 1 / 2 g t 2
h = (20 × 3) - 1/2 × 10 × (3) ^ 2
h = 60 - 45
h = 15 m
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You get in your car after work and turn on the radio. What type of communication does the radio use?.
Answer:
Radio waves
Explanation:
The radio operates by the principles of radio wave.
Electromagnetic wave is a type of wave which does not require material medium for its propagation. A radio wave is an example of electromagnetic wave.
The radio operates in the principle of electromagnetic wave because it does not require material medium for its propagation and it has one of the longest frequency of electromagnetic spectrum.
Thus, we can conclude that the radio operates by the principles of radio wave.
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Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an
an unbalanced force of 42 Newtons has been applied?
A 75.60 kg
B 00.04 kg
C 23.33 kg
D 43.80 kg
Answer:
23.33 kgExplanation:
The mass of the object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]
We have the final answer as
23.33 kgHope this helps you
Answer:
[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F=ma[/tex]
The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.
Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².
F= 42 kg*m/s² a= 1.8 m/s²Substitute the values into the formula.
[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².
[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]
[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]
The units of meters per second squared cancel.
[tex]\frac {42 \ kg}{1.8 } =m[/tex]
[tex]23.3333333 \ kg=m[/tex]
Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.
[tex]23.33 \ kg \approx m[/tex]
The mass of the ball is approximately 23.33 kilograms.
An escalator in a busy shopping centre lifts people up from one floor to another. This takes 1.2 MJ every minute. What is the power output of the escalator motor? Give your answer in kW.
An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.
An escalator used to lift people up from one floor to another, exerts a work (w) of 1.2 MJ in 1 minute (t).
In physics, power (P) is the amount of energy (w) transferred or converted per unit time (t).
[tex]P = \frac{w}{t} = \frac{1.2 \times 10^{6} J }{1min} = 1.2 \times 10^{6} W[/tex]
We can convert 1.2 × 10⁶ W to kW using the conversion factor 1 kW = 1000 W.
[tex]1.2 \times 10^{6} W \times \frac{1kW}{1000W} = 1200kW[/tex]
An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.
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How much force is required to move a rock 75m, when using 340J of work?
Answer:
Solution given:
work done=340J
displacement(d)=75m
force[f]=?
we have
work done =Force*displacement
340=Force*75
Force=340/75
Force=4.5N
Given,
Work done = 340 J
Distance = 75 m
Force = work done / distance
Force = 340 / 75
Force = 4.533 Newton (N)
______
RainbowSalt2222
A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to determine the amount of power used?
Answer:
time
Explanation:
power = work done ÷ time
What are the advantages and/or disadvantages of the radiation that technology has had for the human economy?
How are earthquakes at continental plate boundaries different from earthquakes at mid-ocean ridges?
Differences between earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges discussed in the answer.
What is earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges?When plates travel in the same direction and collide, this happens. The thinner, denser, and more flexible oceanic plate dips beneath the thicker, more rigid continental plate when a continental plate meets an oceanic plate. It's known as subduction.
Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction. The continent's undercut rocks start to melt. On occasion, a chain of volcanoes forms as the molten rock rises to the surface and passes through the continent. Nearly 80% of earthquakes happen along convergent borders, when plates are being forced together.
Shallow earthquakes, often less than 30 km deep, occur in small bands adjacent to plate borders along mid-ocean ridges and transform edges. There are earthquakes in subduction zones at various depths, some of which are more than 700 km deep. Because they occur everywhere throughout the subducting slab that stretches beneath the opposing plate, earthquake bands are wider along subduction zones. Wide areas of distributed earthquakes may be associated with collision zones between continents, such as those between the Eurasian plate and the plates to the south of the African, Arabian, and Indian tectonic arcs.
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Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between them tripled. What is the force between the masses?
If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.
What is gravitational force?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Given data:
The gravitational force = 30 N
Mass 1 =m₁
Mass 2=m₂
Distance between charges = R
Condition given:
Mass 1 = 2m₁
Mass 2= 2m₂
Distance between charges = 3R
[tex]\rm F = \frac{Gm_1m_2}{R^2}[/tex]
Case 2;
[tex]\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N[/tex]
Hence, the forces between the masses will be 13..33 N.
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Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.
The sag in the tensioned cable depends on the weight of the cable and
the applied tension.
The clearance midway between the support is approximately 29.34 metersReasons:
The given parameters are;
Height of the towers are; h₁ = 40 m and h₂ = 30 m
Horizontal distance between the towers, l = 300 m
The tension in the conductor, T = 1,590 kg
Weight of the conductor, w = 0.8 kg/m
Required:
The clearance space of the conductor mid-way between the support
Solution:
The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;
[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]
Where;
h = h₂ - h₁ = 40 m - 30 m = 10 m
Which gives;
[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]
The sag at the lowest point is give by the formula;
[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]
Therefore;
[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]
The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m
The distance of the midpoint from the lowest point, x, is therefore;
[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]
Which gives;
[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]
The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34
The clearance midway between the support ≈ 29.34 m
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what are the characteristics of a " team " in hit in volleyball ?
Answer:
A team may contact the ball a total of three (3) times before it is sent over the net.
10C of charge flow through a resistor in 4 seconds. What is the current?
Answer:
Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.
Explanation:
The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps
Given Data
Charge = 10 Columbs
Time = 4 seconds
Current = ?
Current, charge and time RelationshipElectrical current is defined by how much electric charge has been transferred per second, giving the following relationship:
Charge = Current*Time
Rearranging this we get:
Current = Charge/Time
The symbol for charge is Q , it is measured in coulombs (C).
The symbol for current is I , it is measured in amperes (A).
The symbol for time is T, it is measured in seconds (s).
Substituting our given Data into the expression we have
Current = 10/4
Current = 2.5 Amps
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A car travels at 40 mph. what distance will it travel in 3 hours?
Car speed = 40m/ hour
3 hours = 40 × 3 = 120m /hour
Answer:
120
Explanation:
if the car travels 40 in one hour , to find the speed in 3 hours multiply 40 x 3 which will give us 120
Dark matter is inferred to exist because it explains the abundance of helium in the universe today. we can observe its gravitational influence on visible matter. it explains how the expansion of the universe can be accelerating. we see lots of dark patches in the sky
we can observe its gravitational influence on visible matter.
Dark matter is a term used in astrophysics to refer to matter that corresponds to approximately 80% of the matter in the universe.
Dark matter is related to the motion of galaxies because visible matter makes up only a small part of the cluster and the galaxies show signs of being composed mainly of a halo of dark matter concentrated in their center.
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Is mixing mixing sugar and cinnamon a chemical or physical change?
Answer:
It is a physical
Explanation:
The reading on a metronome indicates the number of oscillations per minute. What are the frequency and period of the metronome's vibration when the metronome is set at 180?
Answer:
Period: 1/3= 0.33 seconds.
The frequency and period of the metronome's vibration when the metronome is set at 180 is 3Hz and 0.33 s.
What is the frequency?Frequency is the number of oscillations per second.
The time period is the reciprocal of the frequency.
Given is the metronome set at 180.
The reading of metronome = frequency in seconds = 180 / 60 = 3 Hz
The time period of the metronome's vibration T = 1/3 = 0.33 seconds.
Thus, the frequency and the time period is 3Hz and 0.33 s.
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an electric generator has an 18-cm-diameter, 120-turn coil that rotates at 60 hz in a uniform magnetic field that is perpendicular to the rotation axis.
The magnetic field strength is needed to generate a peak voltage 0.15 T.
The given parameters;
diameter of the coil, d = 18 cmradius of the coil, r = 9 cmnumber of turns, N = 120 turnsfrequency, f = 60 HzPeak voltage, E = 170 VThe area of the coil is calculated as follows;
[tex]A = \pi r^2\\\\A = \pi \times 0.09^2\\\\A = 0.0255 \ m^2[/tex]
The maximum emf induced in the coil is calculated as follows;
[tex]E_{max} = NBA \omega \\\\B = \frac{E_{max}}{NA\omega } \\\\[/tex]
where;
B is the magnetic field strengthω is the angular frequency = 2πf[tex]B = \frac{170 }{120 \times 0.025 \times 2\pi \times 60 } \\\\B = 0.15 \ T[/tex]
Thus, the magnetic field strength is needed to generate a peak voltage 0.15 T.
"Your question is not complete, it seems to be missing the following information";
An electric generator has an 18-cm-diameter, 120-turn coil that rotates at 60 hz in a uniform magnetic field that is perpendicular to the rotation axis.
What magnetic field strength is needed to generate a peak voltage of 170 V?
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What is the orbital period of a spacecraft in a low orbit near the surface of mars? the radius of mars is 3. 4×106m.
Answer:
if not sure sorry hope someone helps u❤️
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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l. amount of liquid
ll. initial mass of the bone
lll. temperature of liquid
A.
l and lll
B.
II and III
C.
ll only
D.
l only
A.l and lll
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In a car race, the average speed of the car was 90 km/hr where the total
covered distance was 450 km.
1. Calculate the average speed of the car in SI unit.
Explanation:
The speedometer of a motor car showed the following speeds in km per hour at the ends of successive intervals of 3 secs. 38.9, 52.8, 64.4. 73.6, 80.9, 86.1, 90.0, 92.5 Plot the velocity – time graph in convenient units and find from the graph, (a) The distance covered while the speed increased from 80
The amount of heat that is needed to raise the temperature of 1
kg of some material by 1°C is called the of the material.
a. specific heat
b. state
c. temperature
d. charge
Answer:
a. specific heat
Explanation:
a. specific heat
What is the number of the of significant figures in 2.50400-.pliz, help me l will mark you the brainest.(⊙_◎)
Answer:
Number of Significant Figures: 6
The Significant Figures are 2 5 0 4 0 0
Explanation:
Non-zero digits are always significant which are in this case 2,5,4, and Any zeros between two significant digits are significant and final zero or trailing zeros are significant therefore making the entire digit significant.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The number of significant figures in 2.50400 is ~
[tex] \boxed{6}[/tex]Physics - Electricity and Magnetism
A ceiling fan operates at three speeds, using 120 V of electricity from the wall. At low speeds, it uses 0.25 A. Calculate the resistance needed to generate that current. Then in 1-2 sentences, describe how the resistance would change at medium and high speeds if larger currents are needed at those speeds. Your answer should include the calculated resistance and a sentence describing your reasoning.
Answer:
480 Ohms for the calculations
Explanation:
For the calculations:
V = 120 and I = 0.25
V = IR
R = V/I
R = 120/0.25
R = 480 Ohms
For the sentences, I am so sorry, I do not have them yet!
I. The resistance which is needed to generate a current of 0.25 Ampere in the ceiling fan is 480 Ohms.
II. Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.
Given the following data:
Voltage = 120 VoltsCurrent = 0.25 AmpereTo calculate the resistance needed to generate that current, we would apply Ohm's law:
Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage (potential difference) applied across the two terminals of the electrical circuit and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
[tex]V=IR[/tex]
Where;
V is the voltage measured in Volts.I is the current measured in Ampere.R is the resistance measured in Ohms.Making R the subject of formula, we have:
[tex]R =\frac{V}{I}[/tex]
Substituting the given parameters into the formula, we have;
[tex]R=\frac{120}{0.25}[/tex]
Resistance, R = 480 Ohms
Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.
In conclusion, the larger the current, the lower the resistance would be at both medium and high speeds.
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what do u guys think of my drawing?
Answer: yess sirrrrrrrr
Explanation:
Answer:
oou I like it! u did a good job ^^
Josh tests an unknown liquid substance using litmus paper. When he compared the used litmus paper to a pH scale, the color matches with a 3.5 of the scale. What kind of substance did Josh test?
Answer:
acid
Explanation:
because ph below 7 is acid
Where does the energy released in a nuclear decay reaction come from
A. Electrons
B. Chemical bonds
C. Positrons
D. The binding energy of the nucleus
what happens to light in an object that is translucent?
Translucent objects allow some light to travel through them. The light does not pass directly through the materials. It changes direction many times and is scattered as it passes through. Therefore, we cannot see clearly through them and objects on the other side of a translucent object appear fuzzy and unclear.
Around the time that _______ burning finishes, the inert core of ________ in very massive stars will collapse and the star will explode as a supernova.
The Sun can explode in a supernova. Around the time that sun (massive star) burning finishes, the inert core of Iron in very massive stars will collapse and the star will explode as a supernova.
When the sun explode, their inert iron cores often collapse into an extremely dense neutron star.
In a massive star, hydrogen fusion in the core is accompanied by other different fusion reactions involving heavier elements.
When the core of a massive star dies during a supernova, The supergiant will explodes as a supernova.
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Plz help ⭐..................
Answer:
where in the world is the image????..
plz help will mark brainliest
Explanation:
The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.
We have to take moments around the pivoted point.
Moment = Force × Perpendicular distance to the force
For the rod to be in equilibrium,
Clockwise moment - Anticlockwise moment = 0
Clockwise moment = Anticlockwise moment
The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm
So 20 cm× 1.2 N produces a Clockwise moment
If Perpendicular distance between pivoted point and 2N load is x,
Anticlockwise moment = x × 2N
20 cm× 1.2N = 2N × x
x = 12 cm
So 2 N load is at 12 from the pivoted point.
From the left edge of the meter ruler, 2N load is at 30-12 cm distance
= 18 cm
Answer: 18 cm
Explanation:
