This is the accurate statement out of all the ones offered because adsl offers asymmetric digital subscriber, hence neither next nor fext are a problem to service providers having same wavelength.
Asymmetric digital subscriber line, or ADSL, is a form of digital subscriber line technology that offers an asymmetric data path while providing a symmetric digital subscriber path for next and next. As a result, neither of these companies will offer ADSL services. ADSL is a digital method that uses PCM to sample analogue signals digitally. Pulse code modulation, or PCM-PCM, is a technique for digitally converting a single analogue signal into a digitally sampled signal.
When packets from A to B take a different path than other packets, this is known as asymmetric routing. In physics, the wavelength is the length over which a periodic wave repeats, or its spatial period. It is the separation between consecutive equivalent points on a wave that are in the same phase. Is called as wavelength.
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consider that the ball travels one revolution of its path in t second. what is the speed of the ball in terms of l, r, and t?
The speed of the ball in term of l, r, t is given as,
l = r/t
Where, l is the speed of the ball, r is the distance travel by the ball and t is the time to complete one revolution.
Every day, each of us makes a trip to a different location and covers a distance along the way. But from the perspective of physics, distance is something that takes into account a variety of things.A ball is moving consistently translationally. The ball moves down the path at a constant pace and can follow a straight or round path. The speed of the ball is constant and has the same magnitude and direction for every component.
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What are the 7 stages of mitosis in order?.
There are five phases namely, prophase, prometaphase, metaphase, anaphase and telophase. Final cell division after telophase, cytokinesis is regarded as the sixth phase of mitosis.
Mitosis begins with the prophase.
Chromosomes gather and are made visible. Centrosomes are the origin of spindle fibres.Nucleolus dissolves as nuclear envelope disintegrates.
Second stage of mitosis is known as prometaphase. Chromosomes continue to compact. Centrosomes travel in the direction of their opposite poles as mitotic spindle microtubules attach to kinetochores.
Third phase is metaphase. Each chromosome is in the centre.
The fourth stage is known as anaphase. Sister chromatids which were previously bound together by cohesin proteins, separate and are drawn in opposite directions.
The fifth stage is called telophase. The nuclear envelope material that surrounds each set of chromosomes decondenses as the chromosomes arrive at opposite poles.
The last stage of mitosis is known as cytokinesis. In animal cells, the daughter cells are divided by a cleavage furrow.
The splitting of cytoplasm into two distinct daughter cells happen in plant cells.
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what is the angular velocity (in rad/s) of a 62.0 cm diameter tire on an automobile traveling at 90.5 km/h? (enter the magnitude.)
The angular velocity is 55.6rads/s.
What is angular velocity?
The rotation rate of an object, or how quickly it revolves or rotates in relation to another point, is measured vectorially as angular velocity. Angular velocity is simply the rate of rotation or revolving around an axis of an object.
What is magnitude?
Magnitude serves as the common denominator for both vector and scalar quantities. Their definition states that scalar quantities are those that have only magnitude.
Using the second relationship in v = r, vr = v r, and knowing v and r, we can get the angular velocity. To calculate the angular velocity, we will use the formula = vr. = v r.
If an object's radius is r, its linear speed is v, and its angular velocity is measured in radians per second, then v = r.
Substituting the values, in the formula
=62.0cm*90.5
V=55.6
Therefore, the angular velocity is 55.6rads/s.
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What happens to gravitational potential energy of mass increases?.
Gravitational potential energy increases as weight and height increases.
Potential energy is stored or conserved energy in a material or object. The amount of stored energy depends on the arrangement, organization, and state of the object or substance.
You might think of it as energy with the "potential" to be productive. Any changes to the object's position, configuration, or status will result in the release of any stored energy.
For instance, in order to compress a spring, energy is required, but what happens to that energy once the spring has been broken It is impossible to generate or destroy energy because it can only transform from one form to another.
The kinetic energy that was used to compress our spring has now been converted to potential energy
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The required subject matter expertise or background for an evaluator is documented in the exercise evaluation plan.
It is accurate to say that the exercise assessment plan includes information on the required subject matter competence or background for an evaluator.
What is exercise?The second law of physics applies to strengthening exercises. One kind of strength can be created by moving a heavy object with little acceleration. This may be seen in the powerlifting discipline, where competitors attempt to perform the deadlift, squat, and bench press with the greatest amount of weight. The third rule of motion, which states that "for every action there is an equal and opposite reaction," is connected to running in the article "The Truth about Running."
Why is exercise related to force?The homeostasis of the internal environment is impacted by exercise. Muscle contractions during activity produce heat and force. Therefore, engaging in physical activity uses mechanical energy. The body's reserves of energy will be depleted by the energy that is produced. There is an equal and opposite reaction to every action. This becomes the SAID principle—Specific Adaptations to Imposed Demands—when it is applied to exercise science. In other words, the body will adjust (respond) to the training strategy (action).
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What is the primordial heat?.
The intrinsic heat energy generated via evaporation in a planet throughout its initial several million years of evolution is referred to as primordial heat.
The interior heat energy generated via dispersion in a planetary during its initial few million years of existence is known as primordial heat. The primary sources of primordial heat were accretional energy (the energy deposited based on the forecasted planetesimals) as well as differentiation energy.
The heat lost mostly by Earth as it cools from its initial formation has been referred to as primordial heat.
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What are some similarities between solar energy production and photosynthesis?.
Solar energy and plants Photosynthesis is a process that turns solar energy into chemical energy in plants and other living things. To produce energy, both rely on sunlight.
Describe energy in plain terms.Energy is the capacity to perform labor, according to scientists. Because of the ability to transform energy from one form to another and use it to accomplish tasks, modern civilisation is feasible.
Which energy kinds are there?Chemical, electrical, radiant, mechanical, thermal, nuclear, and other six main types of energy exist. Additional kinds, such as electrochemical, acoustic, electromagnetic, and others, may be discussed in other studies.
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HURRY PLEASE
Two different bumper designs are shown here.
Recall that if the colliding objects have hard surfaces, the collision is elastic. Based on this description, which bumper design is more likely to result in an elastic collision? Predict how this bumper design will change the force that car 2 experiences during the collision.
The design that has the metal bar would increase the chances of an elastic collision and lead to an increase of the velocity of the car after collision.
What is elastic collision?We know that an elastic collision is one in which there is a conservation of the kinetic energy of the momentum. Recall that the colliding particles would have to constitute a closed system such that there is no loss in the momentum of the objects that are colliding.
We have two designs of the bumpers of the cars. We know that the balloon design would have more tendency to have this car stick to the other car and create an inelastic Collison.
However, with the metal bar design, there is less tendency that the cars would stick together after collision and we would have an elastic collision. The effect of this is that velocity of the car 2 may increase after the collision.
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how will you know that the pressure of your system is equalized and that it is okay to record an initial and/or final volume?
when the burets' and the funnel's meniscus are at a same height. The system will be under equal pressure at this moment. This will equalize the pressure in your system.
And that it is acceptable to record the first and/or last volume. In contrast to an articular disc, which completely divides a joint cavity, a meniscus is a crescent-shaped fibrocartilaginous anatomical structure. meniscus are found in the knee, wrist, sternoclavicular, acromioclavicular, and temporomandibular joints in humans; they may also be found in other joints in other animals.
The force perpendicular to an object's surface that is delivered per unit area over that force is known as pressure.
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What is the wavelength of a wave with a speed of 12 m/s and a frequency of 3 Hz?.
Answer:
[tex] \huge{ \boxed{4 \: m}}[/tex]
Explanation:
The wavelength of the wave given it's speed and frequency can be found by using the formula
[tex] \lambda = \frac{v}{f}\\ [/tex]
where v is the speed
f is the frequency
From the question
v = 12 m/s
f = 3 Hz
We have;
[tex] \lambda = \frac{12}{3} = 4 \\ [/tex]
We have the final answer as
4 mhow far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.6 m/s ?
Given
coefficient of kinetic Friction μ(k) = 0.1
Initial speed u = 3.6
Friction is present so it tries to stop to the object and stops it completely after moving certain displacement let say s
maximum deceleration provided by friction is
a(max) = μ(k) * g
= 0.1 * 3.6
using equation of motion
v² - u² = 2as
where,
v = final velocity
u = initial velocity
a = acceleration
s = displacement
(0)² - (3.6)² = 2 * (-0.36) * s
s = 18 m
Therefore, the displacement will be 18 m
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in considering the earth-moon orbital system, complete the following statements: the earth has the same strength gravitational pull on the moon than moon has on the earth, because of newton's 3rd law . the acceleration of the moon is less than the earth's acceleration.
The statement ' the earth has the same strength gravitational pull on the moon than the moon has on the earth, is because of Newton's 3rd law. The acceleration of the moon is less than the earth's acceleration' is true.
According to Newton's third law of motion, there is an equal and opposite reaction to every force. Hence, according to Newton's third law, the force with which the moon pulls the earth is equal and opposite to the force with which the earth pulls the moon. The force that is exerted by the earth on the moon will be called as the gravitational pull.
However, the acceleration of the earth is more as compared to that of the moon. This is because the earth travels a larger distance as compared to than of the moon. Hence, the statement above is true.
The question will correctly be written as:
The earth has the same strength gravitational pull on the moon than moon has on the earth, because of Newton's 3rd law. the acceleration of the moon is less than the earth's acceleration. true or false
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Find the Fermi energy ef for a three-dimensional relativistic electron gas in which the energy of the electrons is given by = p?c? + m²c4. Take the non-relativistic limit of your expression for ef and comment on the result.
The non-relativistic limit of your expression for Fermi energy (ef) is shown in the figure below please convey to that figure.
The Fermi energy is the energy difference between the highest and lowest occupied single-particle states in a quantum system of non-interacting fermions at absolute zero temperature. The lowest occupied state in a Fermi gas is supposed to have no kinetic energy, in contrast to the lowest occupied state in a metal, which is frequently thought to represent the bottom of the conduction band. The term "Fermi energy" is frequently used to refer to the Fermi level, a different but closely related concept (also called electrochemical potential). At least in the context of this article, the Fermi level and Fermi energy differ significantly from one another: The Fermi level is defined at any temperature, but the Fermi energy is only stated at absolute zero. The Fermi level is a total energy level made up of both kinetic energy and potential energy (often corresponding to a kinetic energy). Even in complex interacting systems in thermodynamic equilibrium, the Fermi level is well defined, while the Fermi energy can only be specified for non-interacting fermions.
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How does visible light differ from ultraviolet and infrared on the electromagnetic spectrum.
The major difference between ultraviolet and visible light is that UV has a wavelength of 10-400 nm, while visible light has a wavelength of 400–700 nm and infrared has a wavelength of 700 nm–1 mm.
What are the differences between visible light, ultraviolet and infrared on electromagnetic spectrum?Compared to red light, infrared radiation has longer waves, a lower frequency, and less energy. Although ultraviolet light has shorter wavelengths that of blue or violet light, it moves more quickly and has a higher energy content per photon than visible light. In other words, their wavelengths are different.Infrared electromagnetic radiation (EMR) has wavelengths longer than that of visible light, whereas ultraviolet electromagnetic radiation (EMR) has a wavelength starting at 10 nanometers (nm). Visible light refers to the region of the electromagnetic spectrum which is visible to the human eye.Infrared waves have longer wavelengths than visible light, which allows them to pass through dense gas and dust clouds in space with less absorption and scattering. Thus, infrared light can reveal celestial objects that optical telescopes are unable to see in visible light.Know about electromagnetic spectrum at:
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the period of the object attached to a spring is tt . how much time does the object need to move from the equilibrium position to half the amplitude?
The time period for this given SHM, when it moves from equilibrium position to half the amplitude will be T/12.
When the objects starts from the mean position, the equation for displacement is given by x = Asin(wt).
where, x= displacement from the mean position, A= amplitude, w= angular frequency, t= time, T= time period of the object.
Substituting the values in x = Asin(wt).
We get: A/2 = A sin (wt)
1/2 = sin(wt)
wt = π/6
(2π/T)t = π/6
[since, sin(π/6)=1/2 and w=2π/t ]
Therefore, (time) t = T/12
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What is the gravitational acceleration on Planet Y if there is an increase in gravitation potential energy equal to 352 J when a 8.27 kg is lifted 15.43 m? (1 point) 0 27.6) O 188.66 ) 2.763 42.560 44917.35)
The gravitational acceleration on the planet Y will be 59.52 m/[tex]s^{2}[/tex].
Given,
Gravitational potential energy, [tex]P_{E}[/tex] = 352 J
Mass of an object, m = 8.27 kg
Lifted to the height, R = 15.43 m
Gravitational potential energy at the height R can be calculated as:
[tex]P_{E}[/tex] = - [tex]\frac{GMm}{r}[/tex]
As GM = gR^2
Potential energy will be -mgR
and for r = R, Potential energy will be - (mgR)/2
m = mass of the object (8.27 kg)
So, [tex]P_{E}[/tex] = - (mgR)/2
Now to calculate g (gravitational acceleration), g =-([tex]P_{E}[/tex]×2)/mR
=(-352×2)/8.27×1.43
g = 59.52 m/[tex]s^{2}[/tex]
Hence, gravitational acceleration on the planet Y will be 59.52 m/[tex]s^{2}[/tex].
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Which of following is not a polynomial?.
Out of the following option A, option B and option D are not polynomials.
A ) x² + 1 / x,
This can be written as x² + x⁻¹.
Since the exponent of the variable in second term is negative, it is not a polynomial.
B ) 2 x² - 3 √ x + 1,
This can be written as 2 x² - 3 x ^ 1 / 2 + 1.
Since the exponent of the variable in second term is rational, it is not a polynomial.
C ) x³ - 3 x + 1.
This is a polynomial because all the exponentials are positive whole numbers.
D ) 2 x ^ 3 / 2 - 5 x.
Since the exponent of the variable in first term is rational, it is not a polynomial.
Therefore, option A, B and D are not polynomials.
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A man wishes to pull a crate 15m across a rough floor by exerting a force of 100 n. The coefficient of kinetic friction is 0. 25. For the man to do the least work, the angle between the force and the horizontal should be:.
For the least amount of work, the exerting a force angle from horizontal is 76 degree.
How do you compute the angle between exerting the force and the horizontal plane?Fcosθ−μN=maFcosθ−μN=ma
N+Fsinθ−mg=0N+Fsinθ−mg=0
(Unless Fsin>mgFsin>mg)
The angle is measured from the horizontal, and N is the upward normal force to the surface.
Work is defined as force times distance in the direction of motion... or a shift in energy. You want the man to do the work... guess: whole work. So attempt to accelerate the box (madmad) and against friction (NdNd).
So, how about this:
Minimizing force reduces effort for the same distance. As a result, we want the vertical component of force to be equal to and opposite to the weight. Any higher, and there is extra work propelling the box upwards.
This entirely removes friction, leaving only madness.
θ=sin−1[mg/F]
θ=sin−1[mg/F]
W=Fdcosθ+μNd
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a car is traveling at $$50 mi/hr when the brakes are fully applied, producing a constant deceleration of $$22 ft per sq sec. what is the distance (in feet) covered before the car comes to a stop? be mindful of the units being used in this problem
The distance (in feet) covered before the car comes to a stop is 122.2 ft
It is given that
initial speed of car = u = 50 mi/hr
deceleration = - 22 m/s^2
final speed = v = 0 m/s
We have to find the distance
Applicable kinematic equation is
v^2 - u^2 = 2as
50 mph x 1760 x 3/3600 = 73.333 fps
0^2 - (73.333)^2 = 2*(-22)*s
s = (73.333)^2/44
s = 122.2 ft
Hence, distance (in feet) covered before the car comes to a stop is 122.2 ft
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a single rectangular slit of width of 50 is illuminated by red light with a wavelength of 600 nm. a screen is placed a certain distance behind the slit so that the central bright band of the diffractio pattern is 18 mm wide
A single rectangular slit of width of 50 is illuminated by red light with a wavelength of 600 nm and a screen is placed a certain distance behind the slit so that the central bright band of the diffraction pattern is 18 mm wide then the width of slit is 1.667 mm .
How is the width calculated?Given ,
λ = 600 × 10⁻⁹
D = 50
d = 18 mm
The position of central maxima in the diffraction pattern is
w = Dλ / d
∴ w = (50 × 600 × 10⁻⁹ ) / (18 × 10⁻³ )
∴ w = 30000 × 10⁻⁹ / 18 × 10⁻³
∴ w = 30 × 10⁻⁶ / 18 × 10⁻³
∴ w = 1.667 × 10⁻³
∴ w = 1.667 mm
Hence, the width of the central bright fringe of the diffraction pattern will be 1.667 mm.
What is the central bright band of diffraction?The width of the central diffraction peak is found to be inversely proportional to the slit width. Increasing the width magnitude a decreases the angle θ at which the intensity first goes to zero, narrowing the central band.Reducing the width of the slit also increases the angle θ and widens the central band. The width and spacing of the bright bands on the screen behind the slit depend on the distance between the slit and the screen.Therefore, the light intensity distribution becomes diffracted light.
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How will the weight and mass of a rover on Mars compare to its weight and mass on Earth?.
The mass of a frame or object on the surface of the Earth is similar to its mass on the floor of Mars. this is because the composition and the quantity of count in that body or object remain the same.
Wm=mgm=500×3.seventy one=1855 N. W m = m g m = 500 × 371 = 1855 N . Calculating R, the ratio of weights of the rover on Mars to its weight on the planet R=WmWe=18554905=0.38.
This is due to the fact weight is the dimension of the pressure of gravity on an object. although the individual could incorporate an identical quantity of depending, their weight might most effectively be 38% of their weight in the world. this is because the force of gravity is lower on Mars.
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What is a substance
a 6.00 gg bullet is fired horizontally into a 1.20 kgkg wooden block resting on a horizontal surface. the coefficient of kinetic friction between block and surface is 0.200. the bullet remains embedded in the block, which is observed to slide 0.200 mm along the surface before stopping. (a) What was teh initial speed of the bullet?
(b) What kind of collision took place between the bullet and the block? Explain your answer comparing the values of the kinetic energy before and after the collision.
(c) Calculate the impulse of the block from the moment just after the impact to his final position. Analyze the result.
The initial speed of the bullet should be 159.32 m/s.
What was the initial speed of the bullet?Let the initial speed of the bullet be V.
Momentum will be conserved after bullet hits the block . If v₁ be the common velocity of bullet block system
6.00 x 10⁻³ x V + 0 = ( 6 x 10⁻³ + 1.2 ) v₁
= ( 6 + 1200 ) x 10⁻³ v₁
v₁ = (6 / 1206 ) x V
1 / 201 V
Now the moving bullet - block system faces friction force and ultimately they come to rest , so
Kinetic energy of bullet block system = work done by friction
Kinetic energy of bullet block system =
1/2 x ( 6 + 1200 ) x 10⁻³ x ( 1 / 201 V )²
work done by friction
= frictional force x displacement
μ mg x d ( μ is coefficient of friction of surface , m is mass of the bullet block system and d is displacement )
0.16 x ( 6 + 1200 ) x 10⁻³ x 9.8 x .2
= 38.592 x 9.8 x 10⁻³
1/2 x ( 6 + 1200 ) x 10⁻³ x ( 1 / 201 )² V ² =
= 38.592 x 9.8 X 10⁻³
V² = 25382.65
V = 159.32 ms⁻¹
What kind of collision took place and calculate the impulse of the block?The impulse of the friction force produced by the surface during the impact is disregarded when we apply conservation of momentum to the collision. This makes sense given that the force is far less than the forces that the bullet and block will exert on one another when they collide. The block moves after the collision and is affected by this force, which removes all of the kinetic energy.
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While standing on frictionless ice, you (mass 65.0 kg ) toss a 4.50g rock with initial speed 12.0m/s . The rock is 15.2 m from you when it lands. Take the axis on the ice surface in the horizontal direction of the motion of the rock. Ignore the initial height of the toss. At what angle did you toss it? How fast are you moving? (cm/s)
While standing on frictionless ice, you (mass 65.0 kg ) toss a 4.50g rock with initial speed 12.0m/s.At 37.8 degrees angle did you toss it.
Back to including the slide. The range equation is
Eq1: 15.2 - Vs*t = 12^2/g*sin(2A) (t is the time of flight in all this) Conservation of momentum gives
Eq2: 65Vs = 4.5*v*cos(A) or Vs = 0.8308*cos(A)
Vertical velocity at the turnover point is 0 = Vi + at = 12*sin(A) - gt/2 or Vertical velocity Eq3: t = 2.45*sin(A)
initial speed=12.0m/s
Sub eq3 into eq1 to get
15.2 - 2.45*Vs*sin(A) = 14.7*sin(2A)
Sub eq2 in for Vs Vertical velocity:
15.2 - 2.45*0.8308*cos(A)*sin(A) = 14.7*sin(2A)
15.2 - 2*sin(A)*cos(A) = 14.7*sin(2A) a bit of a roundoff here to get the 2
15.2 - sin(2A) = 14.7*sin(2A)
15.2 = 15.7*sin(2A)
sin(2A) = 0.97
A = 37.8 degrees
To get the speed of the person, you would just use eqn2.
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what factor(s) determine the speed of wind-blown waves in deep ocean? what factor(s) determine the speed of tsunami wave?
The speed of a tsunami depends on the depth of the water it is traveling through. The deeper the water; the faster the tsunami.
What is windspeed?
In meteorology, wind speed, also known as wind flow speed, is a fundamental atmospheric quantity brought on by air shifting from a state of high to low pressure, frequently as a result of temperature changes. Nowadays, an anemometer is frequently used to measure wind speed.
What is tsunami?
A tsunami is a set of waves brought on by a disturbance. Similar to the ripples created when a stone is thrown into a pond, a tsunami can be produced by a disturbance that moves the water vertically (a sudden drop or a sudden rise).
Three factors influence the formation
Windspeed;
Length of time the wind has blown over a given area; and
Distance of open water that the wind has blown over (called fetch).
The speed of a tsunami depends on the depth of the water it is traveling through. The deeper the water; the faster the tsunami. As the water depth decreases, the tsunami slows. The tsunami's energy flux, which is dependent on both its wave speed and wave height, remains nearly constant.
Therefore, the speed of a tsunami depends on the depth of the water it is traveling through. The deeper the water; the faster the tsunami.
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promotes glomerular hypertension and hyperfiltration caused by efferent arteriolar vasoconstriction and also promotes systemic hypertension.
Angiotensin II promotes glomerular hypertension and hyperfiltration caused by efferent arteriolar vasoconstriction and also promotes systemic hypertension.
What is Angiotensin II ?A drug called angiotensin II is used to treat hypotension brought on by septic shock or other types of distributive shock. It is marketed as Giapreza, a synthetic vasoconstrictor peptide that is equivalent to the human hormone angiotensin II.The muscle walls of tiny arteries contract as a result of angiotensin II, raising blood pressure. Additionally, angiotensin II causes the release of aldosterone from your adrenal glands and an antidiuretic hormone from your pituitary gland.The primary RAS effector molecule is angiotensin II. It raises blood pressure, encourages the renal tubuli to retain sodium and water, and prompts the adrenal gland to secrete aldosterone.To learn more about Angiotensin refer :
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In the figure, a broad beam of light of wavelength 610 nm is incident at 90? on a thin, wedge-shaped film with index of refraction 1.45. An observer intercepting the light transmitted by the film sees 10.0 bright and 9.00 dark fringes along the length of the film. By how much does the film thickness change over this length?
The film thickness change over by dL = 1.99 um.
Thomas Young proposed that the superposition principle applies to light, which is a wave. His ability to demonstrate that light may interfere both positively and negatively was his biggest experimental achievement. An updated version of Young's experiment, which only differs in the source of light from the original experiment, uniformly illuminates two parallel slits in an otherwise opaque surface. The light passing through the two apertures can be seen on a distant screen. When the slit widths are substantially more than the light's wavelength, the laws of geometrical optics are upheld and the light creates two shadows and two illuminated zones on the screen.
There are 10 bright fringes
2nLa= (ma + 0.5)W
2nLb = (mb + 0.5)W
mb = ma + 9
2nLb - 2nLa = 9W
Dark fringes = 9
dL = 9 × 610nm/(2 × 1.45)
Thickness film changes by dL = 1.99 um
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a 10.0-kg dog is running with a speed of 5.00 m/s. what is the minimum magnitude of the work required to stop the dog in 2.40 s?
An 10.0-kg dog is moving at a pace of 5.00 meters per second. The amount of work that must be done to halt its dog in 2.40 seconds must be at least 125 joules.
What is a work?Whenever an object is transported over a length by an external force, at least a portion of that force must be applied in the plane of the displacement. In physics, this is referred to as work.
What are the three categories of physics work?The three categories below can be used to categorize the kinds of labor that are done. The three sorts are good work, negative collaborate, and zero work. The type of work that is performed depends on the connection between force and displacement. When a force is used and an item is pushed in that direction, positive work is produced.
Briefing:Work is equal to force times distance.
Work done = kinetic energy
Kinetic energy is equal to 1/2 mv2 or 1/2 10*5² or 5 *25.
= 125 joules
Hence, work done is 125 joules.
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first make a substitution and then use integration by parts to evaluate the integral. (use c for the constant of integration.) x ln(5 x) dx
∫xln(5+x)dx
u = ln(5+x) , dv = xd
du = (1/5+x)dx , v = x2/2
∫xln(5+x)dx = ln(5+x).x2/2 -∫ x2/2 .1/5 dx
=x2ln(5+x)/2 - 1/2 ∫[(x-5) + 25/5+x] dx
=x2ln(5+x)/2 - 1/2 (x2/2 - 5x + 25ln[5+x]) + c
=1/2 (x2 - 25) ln(5+x) - 1/4.x2 +5/2.x+c
In calculus, and more generally in mathematical analysis, integration by parts or partial integration is a process that finds the integral of a product of functions in terms of the integral of the product of their derivative and antiderivative
Integration by parts is a special method of integration that is often useful when two functions are multiplied together, but is also helpful in other ways
∫ udvdx dx = uv − ∫ vdu dx dx. This is the formula known as integration by parts.
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A plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy. Which organelle is most likely damaged?.
The chloroplast of the cell is most likely damaged if the plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy.
The chloroplast is the structure inside the leaf cell that is known for capturing light energy from the sun.
This light energy is then used to make food that has chemical energy. If a plant cell has a damaged chloroplast or the chloroplast is removed, then it will no longer be able to trap the light energy. As a result, the process of photosynthesis will not occur in the plant cell. The plant cell will not be able to make the chemical energy required for functioning.
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