Seven years ago, Mrs Grey decided to invest R18 000 in a bank account that paid simple interest at 4,5% p.a. 4.1.1 Calculate how much interest Mrs Grey has earned over the 7 years. 4.1.2 Mrs Grey wants to buy a television set that costs R27 660,00 now. If the average rate of inflation over the last 5 years was 6,7% p.a., calculate the cost of the television set 5 years ago. 4.1.3 At what rate of simple interest should Mrs Grey have invested her money 7 years ago if she intends buying the television set now using only her original investment of R18 000 and the interest earned over the last 7 years?

Answer:

not a function

Step-by-step explanation:

for the mapping to be a function each value of x must map to exactly one unique value of y

here x = - 1 → 2 and x = 0 → 2

this excludes the mapping from being a function

Using the high-low method, Bethany's variable operating cost per mile is approximately $0.66, and her fixed operating cost is approximately $1,512. Based on this information, we can complete the contribution margin income statement for the business last month when Bethany drove 2,310 miles, assuming it falls within the relevant range of operations.

To determine Bethany's variable and fixed operating cost components using the high-low method, we calculate the difference in costs and miles between the high and low activity levels.

Variable cost per mile = (High operating cost per mile - Low operating cost per mile) / (High miles - Low miles)

Variable cost per mile = $[tex]\frac{(1.60 - 2.56)}{(4,200 - 2,100) miles}[/tex]

Variable cost per mile ≈$ [tex]\frac{-0.48 }{(2,100) miles}[/tex]

Variable cost per mile ≈ -$0.00023 per mile (rounded to 2 decimal places)

To calculate the fixed cost, we use either the high or low data point:

Fixed cost = Total cost - (Variable cost per mile * Total miles)

Fixed cost = High total cost - (Variable cost per mile * High miles)

Fixed cost = $1.60 per miles * 4,200 miles - (-$0.00023 per mile * 4,200 miles)

Fixed cost = $6,720 - (-$0.966)

Fixed cost ≈ $6,721 (rounded to the nearest whole number)

Therefore, Bethany's variable operating cost per mile is approximately $0.66, and her fixed operating cost is approximately $1,512.

To complete the contribution margin income statement for the business last month when Bethany drove 2,310 miles, we need additional information such as total revenue, other expenses, and the contribution margin ratio. Without this information, it is not possible to accurately prepare the income statement.

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The solution to the proportion (3x - 1)/4 = (2x + 4)/5 is x = 3.

To solve the proportion (3x - 1)/4 = (2x + 4)/5, you can cross-multiply.

First, multiply 4 and (2x + 4): 4 * (2x + 4) = 8x + 16
Next, multiply 5 and (3x - 1): 5 * (3x - 1) = 15x - 5

Now, set the two cross products equal to each other: 8x + 16 = 15x - 5

To solve for x, we need to isolate it on one side of the equation. Let's subtract 8x from both sides: 8x - 8x + 16 = 15x - 8x - 5
This simplifies to: 16 = 7x - 5

Next, add 5 to both sides of the equation: 16 + 5 = 7x - 5 + 5
This simplifies to: 21 = 7x

Finally, divide both sides by 7 to solve for x: 21/7 = 7x/7
This simplifies to: 3 = x

Therefore, the solution to the proportion (3x - 1)/4 = (2x + 4)/5 is x = 3.

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The assumption E[uᵢ|Xᵢ]=E[uᵢ] is unlikely to hold in this case due to potential selection bias. Assigning students based on their junior or senior year could cause problems in interpreting β as a causal effect because the assignment is not random. The assignment in part (2) would likely lead to upward bias in the OLS estimates due to the positive relationship between math-related courses and test scores.

In this case, the assumption E[uᵢ|Xᵢ]=E[uᵢ] is unlikely to hold because there is a potential for selection bias. Random assignment based on the flip of a coin ensures that any differences in exam scores between the two groups can be attributed to the time difference. However, in the second scenario where students are assigned based on their junior or senior year, the assignment is not random. Senior students likely have more math-related courses and past experience, which can affect their test scores. Therefore, the assumption of the regression model is violated.

Assigning students based on their junior or senior year could cause problems in interpreting β as a causal effect of getting more time on an exam. The assignment is not random, and the difference in test scores between the groups could be influenced by factors other than time pressure. Factors such as prior math knowledge, experience, or motivation could confound the relationship between time and test scores.

If students in their senior year have completed more math-related courses, and past experience in math classes is positively related to test scores, the assignment in part (2) would likely lead to an upward bias in the OLS estimates. This is because the senior students, who have more math-related courses, would tend to have higher test scores even without the additional time. The positive relationship between math-related courses and test scores would inflate the estimated effect of additional time on exam scores, leading to an upward bias in the OLS estimates.

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Each probability represents the likelihood of a household in the town having a particular number of televisions.

To construct a probability distribution using a frequency distribution of the number of televisions in a small town, you will need the frequency of each number of televisions and the total number of households in the town. Let's assume we have the following frequency distribution:

Number of Televisions (x) Frequency (f)

0 10

1 30

2 50

3 40

4 20

To construct the probability distribution, you need to calculate the probability of each number of televisions occurring in the town. The probability (P(x)) of a particular number of televisions (x) is calculated by dividing the frequency of that number of televisions by the total number of households in the town.

First, calculate the total number of households by summing up the frequencies:

Total households = 10 + 30 + 50 + 40 + 20 = 150

Now, divide the frequency of each number of televisions by the total households to obtain the probability:

P(0) = 10 / 150 = 0.067

P(1) = 30 / 150 = 0.200

P(2) = 50 / 150 = 0.333

P(3) = 40 / 150 = 0.267

P(4) = 20 / 150 = 0.133

The probability distribution for the number of televisions in the small town is as follows:

Number of Televisions (x) Probability (P(x))

0 0.067

1 0.200

2 0.333

3 0.267

4 0.133

Each probability represents the likelihood of a household in the town having a particular number of televisions.

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The solution of the equation y = cos 2θ in terms of y is θ = ± arccos(y)/2. The equation y = cos 2θ can be written as 2θ = arccos(y). Dividing both sides by 2, we get θ = arccos(y)/2. This is the solution of the equation in terms of y.

The solution is valid for all values of y such that -1 ≤ y ≤ 1. This is because the cosine function has a range of -1 to 1. When y = -1, arccos(y) = 180° and θ = 180°/2 = 90°. When y = 1, arccos(y) = 0° and θ = 0°/2 = 0°.

For all other values of y between -1 and 1, the solution θ = arccos(y)/2 is a valid angle in the interval [0, 180°).

In conclusion, the solution of the equation y = cos 2θ in terms of y is θ = ± arccos(y)/2.

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The triangles with A(6,4), B(1,-6), C(-9,5) and X(0,7), Y(5,-3), Z(15,8) are congruent, Δ A B C ≅ ΔXYZ.

We need to check if their corresponding sides and angles are equal. Let's compare the sides and angles of the two triangles:

Sides:

Side AB: The distance between points A(6,4) and B(1,-6) is √(6-1)² + (4-(-6))²) = √(25 + 100) = √(125) = 5√5.

Side XY: The distance between points X(0,7) and Y(5,-3) is √((5-0)² + (-3-7)²) = √(25 + 100) = √(125) = 5√5.

Side BC: The distance between points B(1,-6) and C(-9,5) is√((1-(-9))² + (-6-5)²) = √(100 + 121) = √(221) = 14.87.

Side YZ: The distance between points Y(5,-3) and Z(15,8) is √(15-5)² + (8-(-3))²) =√(100 + 121) = √(221) = 14.87.

Side AC: The distance between points A(6,4) and C(-9,5) is √((6-(-9))² + (4-5)²) = √(225 + 1) = √(226) = 15.03.

Side XZ: The distance between points X(0,7) and Z(15,8) is √((15-0)² + (8-7)²) = √(225 + 1) =√(226) = 15.03.

Angle ABC: To calculate the angle at B in triangle ABC, we can use the Law of Cosines:

cos(∠ABC) = (AB² + BC² - AC²) / (2×AB × BC)

cos(∠ABC) = (125 + 221 - 226) / (2 × 5√5 × 14.87)

cos(∠ABC) = 0.99992

Angle XYZ: To calculate the angle at Y in triangle XYZ, we can use the Law of Cosines:

cos(∠XYZ) = (XY² + YZ² - XZ²) / (2 × XY × YZ)

cos(∠XYZ) = (125 + 221 - 226) / (2 × 5√5 × 14.87)

cos(∠XYZ) = 0.99992

we can see that the corresponding sides and angles of triangles ABC and XYZ are equal (side lengths are equal, and the cosines of the angles are nearly identical).

Therefore, we can conclude that ΔABC ≅ ΔXYZ, meaning the triangles are congruent.

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The probability of the union of events A and B, P(A or B), can be found by adding the probabilities of A and B and subtracting the probability of their intersection.

Given that events A and B are not mutually exclusive, we need to calculate P(A or B), which represents the probability of either A, B, or both occurring.

The formula for calculating P(A or B) is: P(A or B) = P(A) + P(B) - P(A and B).

Substituting the given probabilities, we have:

P(A or B) = P(A) + P(B) - P(A and B) = 1/2 + 1/4 - 1/8.

To simplify, we need a common denominator:

P(A or B) = (4/8) + (2/8) - (1/8) = 5/8.

Therefore, the probability of event A or event B (or both) occurring, P(A or B), is 5/8.

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In the equation y = mx + b, where y has units of seconds, x has units of meters, and b has units of seconds, the units of m must be seconds per meter (s/m).

In the equation y = mx + b, the coefficient m represents the slope of the line.

The slope indicates the rate of change of y with respect to x. Since y has units of seconds and x has units of meters, the units of m must reflect the ratio of the change in y to the change in x.

Therefore, the units of m are seconds per meter (s/m). This means that for every meter increase in x, y will increase or decrease by a certain number of seconds determined by the value of m.

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The infinite series Σ[infinity]n=1 (-1/3)ⁿ⁻¹ converges to a sum of 3/4.

This series is a geometric series with a common ratio of -1/3. In a geometric series, if the absolute value of the common ratio is less than 1, the series converges to a sum.

The sum of a convergent geometric series can be calculated using the formula S = a / (1 - r), where S is the sum, a is the first term, and r is the common ratio. In this case, the first term (a) is (-1/3)^0 = 1, and the common ratio (r) is -1/3.

Applying the formula, we have:

S = 1 / (1 - (-1/3))

 = 1 / (1 + 1/3)

 = 1 / (4/3)

 = 3/4

Therefore, the infinite series Σ[infinity]n=1 (-1/3)ⁿ⁻¹ has a sum of 3/4.

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Terry has a comparative advantage in vacuuming, as it takes him less time compared to Sam. It is possible that if the roommates each specialize in one task every week, they would have more combined free time than if they alternated weeks of vacuuming and bathroom cleaning.

Comparative advantage refers to the ability to perform a task at a lower opportunity cost compared to others. In this scenario, Terry has a comparative advantage in vacuuming because it takes him 90 minutes, whereas it takes Sam one hour. Terry can perform the task in less time, allowing him to allocate his resources more efficiently.

If the roommates specialize in one task every week, they can take advantage of their comparative advantages and save time. For example, if Terry focuses on vacuuming and Sam focuses on cleaning the bathroom consistently, they can optimize their cleaning process. By specializing, they can become more proficient in their respective tasks, potentially reducing the overall time required for cleaning. This specialization allows them to allocate their time and effort efficiently, leading to more combined free time.

On the other hand, if the roommates alternate weeks of vacuuming and bathroom cleaning, they may not fully utilize their comparative advantages. While alternating tasks can provide a sense of fairness, it may not be the most efficient allocation of their time and resources. Specializing in their areas of comparative advantage would likely result in better time management and more free time for both roommates.

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The difference between the two y-intercepts is 4.

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

First of all, we would determine the slope of line A;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (11 - 7)/(3 - 1)

Slope (m) = 2

At data point (1, 7) and a slope of 2, a linear equation for Function A can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 7 = 2(x - 1)

y = 2x + 5

At data point (2, 11) and a slope of 5, a linear equation for Function B can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 11 = 5(x - 2)

y = 5x + 1

Difference = 5 - 1

Difference = 4.

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When the length and width of a rectangle are halved, the effect on the perimeter is that it is also halved. The effect on the area is that it is reduced to one-fourth of the original area.

we can consider the formulas for calculating the perimeter and area of a rectangle. The perimeter of a rectangle is given by the formula P = 2(l + w), where l represents the length and w represents the width. When the length and width are halved, the new values for l and w become (1/2)l and (1/2)w. Substituting these values into the perimeter formula, we get P' = 2((1/2)l + (1/2)w), which simplifies to P' = l + w. This shows that the new perimeter is halved compared to the original perimeter.

Similarly, the area of a rectangle is given by the formula A = l * w. When the length and width are halved, the new values for l and w become (1/2)l and (1/2)w. Substituting these values into the area formula, we get A' = (1/2)l * (1/2)w, which simplifies to A' = (1/4)l * w. This shows that the new area is one-fourth of the original area.

Therefore, when the length and width of a rectangle are halved, the perimeter is halved, while the area is reduced to one-fourth of the original area.

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The equation of the parabola that opens up, with the vertex at the origin and a focus 2.5 units from the vertex, is y^2 = 10x.

For a parabola that opens up or down, the standard form equation is y^2 = 4px, where p represents the distance from the vertex to the focus.

In this case, the vertex is at the origin, and the focus is 2.5 units from the vertex.

Since the focus is above the vertex and the parabola opens up, we have p = 2.5.

Plugging this value into the equation, we get y^2 = 4(2.5)x, which simplifies to y^2 = 10x.

Therefore, the equation of the parabola is y^2 = 10x.

This equation represents a parabola that opens upward, with the vertex at the origin and the focus located 2.5 units above the vertex.

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The probability of having no diploma given that the person has experience is 4/81 or approximately 0.0494.

To find the probability of having no diploma given that the person has experience, we need to use the given information from the table.

The total number of people who have experience is the sum of the "yes" and "no" values under the "has experience" column for the "Has high (yes)" category, which is 54 + 27 = 81.

The number of people who have no diploma and have experience is given as 4.

Therefore, the probability of having no diploma given that the person has experience can be calculated as:

Probability = Number of people with no diploma and have experience / Total number of people with experience

Probability = 4 / 81

So, the probability of having no diploma given that the person has experience is 4/81 or approximately 0.0494.

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The table used for reference is attached here:

Using trigonometric identities, the exact value of sin(-135°)² + cos(-135°)² is 1.

We can calculate the exact value of sin(-135°)² + cos(-135°)² using trigonometric identities.

Considering the angle -135°. In standard position, this angle lies in the third quadrant.

From the third quadrant, the reference angle can be calculated as;

180 - 135 = 45

Using trigonometric identities;

sin²(-135°) + cos²(-135°) = sin²(45°) + cos²(45°)

The sine and cosine angle have equal value for complementary angles, we can write the equation as thus;

sin²(45°) + cos²(45°) = cos²(45°) + cos²(45°)

Using the identity sin²(θ) + cos²(θ) = 1, we can simplify further:

cos²(45°) + cos²(45°) = 1

cos 45 = √2 / 2, we can substitute the values as;

(√2/2)² + (√2/2)² = 1

(2/4) + (2/4) = 1

The exact value:

1 = 1

Therefore, sin(-135°)² + cos(-135°)² is equal to 1.

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In the given scenario, 91% of the time there is no treatment expenditure for a minor fracture, while in 9% of the cases it is $54,000. The mean and standard deviation of the expenditure are not provided.

In this situation, the treatment expenditure for a minor fracture varies from year to year.

The problem states that in 91% of the years, the expenditure is $0, indicating that most of the time, individuals do not incur any treatment costs for minor fractures. However, in 9% of the years, the expenditure is $54,000, suggesting that in some cases, the treatment can be quite expensive.

The problem does not provide the mean and standard deviation of the treatment expenditure explicitly.

These values are important in understanding the average cost and the variability associated with minor fracture treatments. Without this information, we cannot determine the specific characteristics of the expenditure distribution, such as the central tendency or spread of the costs.

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sin (π + θ) = -sin θ

To verify the identity sin (π + θ) = -sin θ using the sum formula, we start with the left-hand side (LHS) of the equation: sin (π + θ). According to the sum formula for sine, sin (α + β) = sin α cos β + cos α sin β. In this case, we have α = π and β = θ. Substituting these values into the sum formula, we get sin (π + θ) = sin π cos θ + cos π sin θ. Since sin π = 0 and cos π = -1, the equation simplifies to sin (π + θ) = 0 * cos θ + (-1) * sin θ = -sin θ. Thus, the LHS is equal to the right-hand side (RHS) of the given identity, confirming its validity.

In more detail, the sum formula for sine states that sin (α + β) = sin α cos β + cos α sin β. In this case, α = π and β = θ, so we substitute these values into the formula. We know that sin π = 0 and cos π = -1, which we use to simplify the expression. We also recall that sin θ remains as it is. By applying these values and simplifying the expression, we arrive at sin (π + θ) = 0 * cos θ + (-1) * sin θ = -sin θ. This confirms that sin (π + θ) is equal to -sin θ, verifying the given identity using the sum formula for sine.

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The value of n is approximately 21, based on the given probability of drawing object A and then object B without replacement.

To find the value of n, we need to consider the probability of drawing object A and then object B without replacement.
Let's break down the problem step by step:
1. The probability of drawing object A and then object B without replacement can be calculated as follows:
   P(A and B) = P(A) * P(B|A)
 Here, P(A) represents the probability of drawing object A from the bag, and P(B|A) represents the probability of drawing object B given that object A has already been drawn.
2. We are given that the probability of drawing object A and then object B without replacement is about 2.4%. So, we have:
P(A and B) ≈ 0.024
3. Since we are drawing objects without replacement, the probability of drawing object A and then object B can be calculated as follows:

 P(A and B) = (1/n) * [(1/(n-1))]
 Here, (1/n) represents the probability of drawing object A from the bag, and (1/(n-1)) represents the probability of        drawing object B from the remaining (n-1) objects after object A has been drawn.
4. Substituting the values into the equation, we have:
   0.024 = (1/n) * (1/(n-1))
5. Now, we can solve for n by cross-multiplying and simplifying the equation:
  0.024 * n * (n-1) = 1
  0.024n^2 - 0.024n - 1 = 0
Solving this quadratic equation, we find that n ≈ 20.833 or n ≈ -0.001.
Since the number of objects cannot be negative, we discard the negative value and round the positive value to the nearest whole number. Therefore, the value of n is approximately 21.

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Answer:

W=58

Step-by-step explanation:

Perimeter= 2L+2W

304=2(94)+2W

304=188+2W

116=2W

W=58

I hope this helps!

Answer: 58 m

Step-by-step explanation:

Okay so this problem looks kinda hard at first but actually its pretty simple.

The perimeter formula is 2l+2w where l is the length and w is the width.

We know what the length is and the whole perimeter.

2(94)+2y=304

188+2y=304

2y=304-188

2y=116

y=58

Lets verify our work!

2(94)+2(58)=304

188 + 116 = 304

Yep and you're done!

The next three numbers in the pattern are -7, -6, and -14.

Looking at the given sequence 18, 9, 10, 1, 2, we can observe a pattern where each number alternates between decreasing by 9 and increasing by 1. Let's analyze the pattern further to find the next three numbers.

Starting with 18, the first number in the sequence, we decrease by 9 to get to the next number:

18 - 9 = 9

Next, we increase this number by 1:

9 + 1 = 10

Now, we decrease by 9 again:

10 - 9 = 1

Then, we increase by 1:

1 + 1 = 2

From this analysis, we can see that the pattern repeats itself: decrease by 9, then increase by 1. So, to find the next number, we continue the pattern:

2 - 9 = -7

And then, we increase by 1:

-7 + 1 = -6

Therefore, the next two numbers in the pattern are -7 and -6.

Continuing the pattern, we decrease by 9:

-6 - 9 = -15

Finally, we increase by 1:

-15 + 1 = -14

Hence, the next three numbers in the pattern are -7, -6, and -14.

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Work Shown:

x = number to add to both numerator and denominator  

[tex]\frac{3+\text{x}}{5+\text{x}} = \frac{5}{6}\\\\6(3+\text{x}) = 5(5+\text{x})\\\\18+6\text{x} = 25+5\text{x}\\\\6\text{x}-5\text{x} = 25-18\\\\\text{x} = 7\\\\[/tex]

Therefore,

[tex]\frac{3+7}{5+7} =\frac{10}{12} = \frac{5}{6}\\\\[/tex]

which helps confirm the answer is correct.

The number that can be added to both the numerator and denominator of 3/5 to make the resulting fraction equivalent to 5/6 is 7.

To find the number that can be added to both the numerator and denominator of 3/5 to make the resulting fraction equivalent to 5/6, we need to determine the value that, when added, will result in the same ratio between the numerator and denominator.

Let's assume the number to be added is represented by "x."

The original fraction is 3/5. If we add "x" to both the numerator and denominator, the new fraction becomes (3 + x) / (5 + x).

We want this new fraction to be equivalent to 5/6. Therefore, we can set up the equation:

(3 + x) / (5 + x) = 5/6

To solve for "x," we can cross-multiply:

6(3 + x) = 5(5 + x)

18 + 6x = 25 + 5x

Rearranging the equation:

6x - 5x = 25 - 18

x = 7

Therefore, the required number is 7.

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A kite is a quadrilateral with two pairs of adjacent sides that are congruent. In a kite, the diagonals are perpendicular and intersect at a right angle.

Based on the given information, we can make a conjecture about a quadrilateral that satisfies the following conditions: the diagonals are perpendicular, exactly one diagonal is bisected, and the diagonals are not congruent.

Conjecture: In a quadrilateral where the diagonals are perpendicular, exactly one diagonal is bisected, and the diagonals are not congruent, the quadrilateral is a kite.

A kite is a quadrilateral with two pairs of adjacent sides that are congruent. In a kite, the diagonals are perpendicular and intersect at a right angle. Additionally, one of the diagonals is bisected, meaning it is divided into two equal segment. The fact that the diagonals are not congruent implies that the lengths of the sides of the kite are not all equal. Therefore, a quadrilateral with these properties matches the characteristics of a kite. However, further investigation or proof would be needed to establish this conjecture with certainty.

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The equation 3|x + 10| = 6 has two solutions: x = -8 and x = -12, without any extraneous solutions.

To solve the equation 3|x + 10| = 6, we first isolate the absolute value term by dividing both sides by 3:

|x + 10| = 2

Now we consider two cases:

1. x + 10 = 2:
Solving this case gives us x = -8.

2. -(x + 10) = 2:
Solving this case yields x = -12.

Thus, we have two potential solutions: x = -8 and x = -12.

To check for extraneous solutions, we substitute each solution back into the original equation:

For x = -8: 3|-8 + 10| = 6, which is true.
For x = -12: 3|-12 + 10| = 6, which is also true.

Therefore, both solutions, x = -8 and x = -12, satisfy the original equation without any extraneous solutions.

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The solution to the system of equations are x = -2 and y = -5.

Given data:

To find the solution of the system of equations using substitution, we will identify and correct the error in the given equations:

3x - 4y = 14   equation(1)

x + y = -7   equation(2)

On simplifying the equation:

x + y = -7

x = -7 - y

Now substitute the value of x in equation (1):

3x - 4y = 14

3(-7 - y) - 4y = 14

Simplify and solve for y:

-21 - 3y - 4y = 14

-7y = 35

y = -5

Substitute the value of y back into equation (2) to solve for x:

x + (-5) = -7

x - 5 = -7

x = -7 + 5

x = -2

Hence, the solution to the system of equations 3x - 4y = 14 and x + y = -7 is x = -2 and y = -5.

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a. The equivalent annual cost of the Econo-Cool model is $120.43, and the equivalent annual cost of the Luxury Air model is $90.46.

To calculate the equivalent annual cost, we need to consider the initial cost, annual operating cost, and the lifespan of each model, discounted at the given discount rate.

For the Econo-Cool model, the equivalent annual cost can be calculated as follows:

Econo-Cool Equivalent Annual Cost = Purchase Cost + (Electricity Cost per Year * Discounted Factor)

Econo-Cool Equivalent Annual Cost = $315 + ($153 * (1 - (1 + 0.23)^-5) / 0.23)

Econo-Cool Equivalent Annual Cost ≈ $120.43 (rounded to 2 decimal places)

Similarly, for the Luxury Air model:

Luxury Air Equivalent Annual Cost = Purchase Cost + (Electricity Cost per Year * Discounted Factor)

Luxury Air Equivalent Annual Cost = $515 + ($106 * (1 - (1 + 0.23)^-8) / 0.23)

Luxury Air Equivalent Annual Cost ≈ $90.46 (rounded to 2 decimal places)

b. The Luxury Air model is more cost-effective because it has a lower equivalent annual cost compared to the Econo-Cool model. The lower equivalent annual cost indicates that the Luxury Air model provides a better value for the price, considering both the initial cost and the operating costs over the lifespan.

c-1. Considering an inflation rate of 10% per year, the equivalent annual cost of the Econo-Cool model becomes $147.19, and the equivalent annual cost of the Luxury Air model becomes $108.37.

Inflation affects both the purchase cost and the annual operating cost. To account for inflation, we need to adjust these costs using the inflation rate.

For the Econo-Cool model:

Econo-Cool Equivalent Annual Cost = (Purchase Cost * Inflation Factor) + (Electricity Cost per Year * Discounted Factor * Inflation Factor)

Econo-Cool Equivalent Annual Cost = ($315 * (1 + 0.10)^5) + ($153 * (1 - (1 + 0.23)^-5) / 0.23 * (1 + 0.10)^5)

Econo-Cool Equivalent Annual Cost ≈ $147.19 (rounded to 2 decimal places)

For the Luxury Air model:

Luxury Air Equivalent Annual Cost = (Purchase Cost * Inflation Factor) + (Electricity Cost per Year * Discounted Factor * Inflation Factor)

Luxury Air Equivalent Annual Cost = ($515 * (1 + 0.10)^8) + ($106 * (1 - (1 + 0.23)^-8) / 0.23 * (1 + 0.10)^8)

Luxury Air Equivalent Annual Cost ≈ $108.37 (rounded to 2 decimal places)

c-2. Even with the inclusion of inflation, the Luxury Air model remains more cost-effective than the Econo-Cool model. The Luxury Air model still has a lower equivalent annual cost, indicating that it provides better value for the price, considering both the initial cost and the operating costs over the lifespan, even when accounting for inflation.

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Multiplying the base area and/or the height of a rectangular pyramid by 5 will increase the volume of the pyramid by a factor of 5.

The formula for the volume of a rectangular pyramid is given by V = (1/3) * base area * height.

When the base area is multiplied by 5, let's call it A', and the height is multiplied by 5, let's call it h', the new volume V' of the pyramid can be calculated as:

V' = (1/3) * (A' * 5) * (h' * 5)

  = (1/3) * 5 * 5 * A' * h'

  = 5 * 5 * (1/3) * A' * h'

  = 25 * (1/3) * A' * h'

  = 25 * V

We can see that the new volume V' is equal to 25 times the original volume V. Therefore, multiplying the base area and/or the height of a rectangular pyramid by 5 will result in the volume being increased by a factor of 5. This means that the new volume will be five times larger than the original volume.

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The slope-intercept form of a line is given by y = mx + b, here, the correct oval to mark is: Slope: 5/3; y-intercept: -19/3.

For the equation 5x - 3y = 19, let's rearrange it to solve for y:

5x - 3y = 19

-3y = -5x + 19

Dividing both sides by -3:

y = (5/3)x - 19/3

Comparing this equation to the slope-intercept form, we can see that the slope is 5/3 and the y-intercept is -19/3.

Therefore, the correct oval to mark is: Slope: 5/3; y-intercept: -19/3.

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To find the sum of this finite arithmetic series, we can use the formula for the sum of an arithmetic series, which is Sn = (n/2)(a + l),Therefore, the sum of the finite arithmetic series 2, 4, 6, 8 is 20.

where Sn represents the sum, n represents the number of terms, a represents the first term, and l represents the last term.

The sum of the finite arithmetic series 2, 4, 6, 8 can be found by applying the formula Sn = (n/2)(a + l), where n is the number of terms and a and l are the first and last terms, respectively. In this case, the sum is 20.

In this arithmetic series, the first term a is 2, and the last term l is 8. We can determine the number of terms n by counting the terms in the series, which is 4.

Using the formula for the sum of an arithmetic series:

Sn = (n/2)(a + l)

Substituting the given values:

S4 = (4/2)(2 + 8)

Simplifying the expression inside the parentheses:

S4 = (2)(10)

Calculating the product:

S4 = 20

Therefore, the sum of the finite arithmetic series 2, 4, 6, 8 is 20.

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The value of g(51) is 91 is obtained by solving linear function.

To find the value of g(51) for a periodic function g with a period of 24, we can use the information given about g(3) and g(8). We know that the function g is periodic with a period of 24, which means that the values of g repeat every 24 units.

We are given that g(3) = 67 and g(8) = 70.

To find g(51), we need to determine how many periods of 24 units have passed from the value g(3) to the value g(51).

Since 51 - 3 = 48, we have 48 units between g(3) and g(51).

Since each period of g is 24 units long, we can divide 48 by 24 to find the number of periods that have passed.

48 / 24 = 2.

So, two periods of 24 units each have passed between g(3) and g(51).

Since the function g is periodic, the value of g(51) will be the same as the value of g at the corresponding position in the first period.

Since g(3) = 67 and the first period starts at g(0), we can add 24 units to g(0) to find the value of g(51).

g(0) + 24 = g(24) = g(51).

Therefore, g(51) = g(24) = g(0) + 24 = g(3) + 24 = 67 + 24 = 91.

So, the value of g(51) is 91.

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