Si Guadalupe tiene una masa de 50de kg cuánto pesa en el planeta tierra (g=9.8m/s

The average salary of 26 employees is 3750.

The average pay is calculated by dividing the sum of all employee salaries for a company or sector by the total number of employees. It serves as a gauge of the typical pay for workers in a given category.

The average salary of 25 workers in a factory is 2500. This means that the total salary of all 25 workers is 2500 * 25 = 62500.

The salary of the manager is 35000. This means that the total salary of all 26 employees is 62500 + 35000 = 97500.

The average salary of 26 employees is 97500 / 26 = 3750.

Therefore, the average salary of 26 employees is 3750.

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Answer:

1/2

Step-by-step explanation:

In a deck of cards, there are 13 hearts and 13 diamonds

13+13 = 26 hearts or diamonds

P( hearts or diamonds) = numbers of hearts or diamonds / total

                                       =26/52

                                       = 1/2

The solutions to the equation 2x² − 8x + 7 = 0 are x = 2.71 and x = -1.29.

The quadratic formula is:

x = (-b ± √(b² - 4ac)) / 2a

In this case, we have:

a = 2

b = -8

c = 7

Substituting these values into the quadratic formula, we get:

x = (-(-8) ± √((-8)² - 4(2)(7))) / 2(2)

x = (8 ± √(64 - 56)) / 4

x = (8 ± √8) / 4

x = (8 ± 2√2) / 4

x = 2 ± √2

x = 2.71 and x = -1.29

Therefore, the solutions to the equation 2x² − 8x + 7 = 0 are x = 2.71 and x = -1.29.

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The expression 2¹⁰ - 1 is not a prime number. Because it has more than two factors.

Given that:

Expression, 2¹⁰ - 1

A prime number is a positive integer having exactly two factors which are 1 and the number itself. Any number that does not follow this is termed a composite number.

The value of the expression is given as,

⇒ 2¹⁰ - 1

⇒ 1,024 - 1

⇒ 1,023

The factor of 1,023 is given as,

1,023 = 3 x 11 x 31

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The smallest positive integer n such that t [tex]$\sqrt[4]{56 \cdot n}$[/tex]  is an integer is 686.

We have to find the smallest positive integer n such that [tex]$\sqrt[4]{56 \cdot n}$[/tex] is an integer

To find the smallest positive integer n such that  [tex]$\sqrt[4]{56 \cdot n}$[/tex]   is an integer, we need to determine the factors of 56 and find the smallest value of n that, when multiplied by 56, results in a perfect fourth power.

The prime factorization of 56 is:

56 = 2³ × 7

The prime factors of 56 need to be raised to multiples of 4.

Therefore, we need to determine the smallest value of n that includes additional factors of 2 and 7.

To make the expression a perfect fourth power, we need to raise 2 and 7 to the power of 4, which is 2⁴ × 7⁴

The smallest value of n that satisfies this condition is:

n = 2 × 7³ = 2× 343 = 686

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The area of the shaded portion of the circle is 329.8 units squared.

The area of the shaded region can be found by subtracting the area of the right triangle from the area of the circle.

Therefore,

area of the triangle = 1 / 2 bh

where

Therefore,

area of the triangle = 1 / 2 × 7 × 24

area of the triangle = 168 / 2

area of the triangle = 84 units²

Area of the circle = πr²

let's find the radius of the circle using Pythagoras's theorem,

√24²- 7² = diameter

diameter = √576 - 49

diameter = √527

diameter = 22.9564805665

diameter = 22.96 units

Therefore,

radius = 22.96 / 2 = 11.48 units

Hence,

Area of the circle = 3.14 × 11.48²

Area of the circle = 413.821856

Area of the circle = 413.82 units²

Therefore,

area of the shaded region = 413.82 - 84

area of the shaded region = 329.8 units²

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The solution to all the algebra expressions are:

28) 2³/₁₆

29) 6000

30) 132

28) The area of the rectangle formed by Shana's rug is given by the expression:

Area = Length * Width

Thus:

Area = 2⁵/₈ * ⁵/₆

= ²¹/₈ * ⁵/₆

= 35/16

= 2³/₁₆

29) We are given the number 2641.

Now, from right:

1 is in the units place

4 is in tens place

6 is in hundreds place

2 is in thousands place

If we switch 2 and 6, we will have:

6241 and as such 6 represents 6000

30) The expression is given as:

90 + 7 * (7 - 1)

Using PEMDAS order of operation gives us:

90 + 7(6)

= 90 + 42

= 132

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Answer:

$851, 786, 151, 000

Step-by-step explanation:

N =  A (1 + increase) ^n

Where N is future amount, A is initial amount, increase is percentage increase/decrease, n is number of mins/hours/days/months/years.

290 is our A value, increase is 8% (0.08), n is the number of years (2018 - 2004 = 14).

N =  290 (1 + 0.08) ^14

= 290 (1.08)^14

= $851, 786, 151, 000

volume of the sphere is 113.1

Answer:

Arithmetic sequence is [tex]a_n=-10n+5[/tex]

93rd term is -925

Step-by-step explanation:

Each subsequent term is decreased by 10 and the first term is -5, so we can generate an arithmetic sequence:

[tex]a_n=a_1+(n-1)d\\a_n=-5+(n-1)(-10)\\a_n=-5-10n+10\\a_n=-10n+5[/tex]

So, the 93rd term would be:

[tex]a_{93}=-10(93)+5=-930+5=-925[/tex]

The probability of not rolling a 2 or a 5 on a 6-sided number cube is 2/3, or about 0.67 when expressed as a decimal.

The probability of rolling a 2 or a 5 on a 6-sided number cube is 2 out of 6 or 1/3, because there are two favorable outcomes (rolling a 2 or a 5) out of six possible outcomes.

The probability of not rolling a 2 or 5 is the complement of this probability.

In probability, the complement of an event is 1 minus the probability of that event.

So, to find the probability of not rolling a 2 or a 5, subtract the probability of rolling a 2 or 5 from 1.

That is, 1 - 1/3 = 2/3.

Therefore, the probability of not rolling a 2 or a 5 on a 6-sided number cube is 2/3, or about 0.67 when expressed as a decimal.

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The reference angle of -210 is 30 degrees and the sketch of the angle is attached

From the question, we have the following parameters that can be used in our computation:

Angle = 210 degrees

Rewrite as

θ = 210 degrees

The above angle is in the third quadrant

So, we subtract 180 degrees from it to calculate the reference angle

Using the above as a guide, we have the following:

Reference angle = 210 - 180

Evaluate the difference

Reference angle = 30 degrees

Hence, the reference angle is 30 degrees and the sketch of the angle is added as an attachment

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The solution to the inequality expression -7x + 13 ≥ 41 is x ≤ -4

From the question, we have the following parameters that can be used in our computation:

-7x13_>41

Express properly

So, we have

-7x + 13 ≥ 41

Subtract 13 from both sides of the inequality

So, we have

-7x + 13 - 13 ≥ 41 - 13

Evaluate the difference

-7x ≥ 28

Divide both sides of the inequality by -7

x ≤ -4

Hence, the solution to the inequality expression is x ≤ -4

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The measure of angle RQT is 138⁰.

The measure of angle RQS is  48⁰.

The value of arc MN is calculated by applying intersecting chord theorem, which states that the angle at tangent is half of the arc angle of the two intersecting chords.

The measure of angle RQT is calculated as follows;

m∠RQT = 180 - ( QR ) ( sum of angles on a straight line)

m∠RQT = 180 -  42⁰

m∠RQT = 138⁰

The measure of angle RQS is calculated as follows;

since line QS is the diameter of the circle, angle RQS must a right angle.

so angle SQT = 90 degrees.

m∠RQS = m∠RQT - m∠SQT

m∠RQS = 138 - 90

m∠RQS = 48⁰

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The solution to each of the equations include the following:

a) x = 25

b) x = 5.

c) x = 6.

d) x = -1.

e) x = 10

f) x = 17

g) x = 3

h) x = 15

i) x = -4

j) x = 0

k) x = 15

l) x = 5

m) x = 13/3.

In this scenario and exercise, you are required to provide a solution to each of the given equations as follows;

Part a.

By subtracting 16 from both sides of the equation, we have:

x + 16 = 41

x + 16 - 16 = 41 - 16

x = 25

Part b.

By collecting like terms and evaluating, we have:

9x – 45 + 4x – 16 = 4

13x = 4 + 45 + 16

13x = 65

x = 5,

Part c.

By collecting like terms and evaluating, we have:

2x – 3 + x – 35 = 2 – 9x – 4

6x = 36

x = 6

Part d.

3 · (x – 2) + 9 = 0

3x - 6 + 9 =0

x = -1

Part e.

8x + 7 – 2x + 5 = 4x + 12 – (x – 30)

x = 10

Part f.

x + (x + 2) = 36

x = 17

Part g

2 · (3x – 2) – (x + 3) = 8

x = 3

Part h

2 · (13 + x) = 41 + x

x = 15

Part i

2 · (x – 3) – 3 · (4x – 5) = 17 – 8x

x = -4

Part j

4x – 3 · (1 – 3x) = –3

x = 0

Part k

4 · (2x) – 3 · (3x – 5) = 12x – 180

x = 15

Part l

6 – x = 4 · (x – 3) – 7 · (x – 4)

x = 5

Part m

3 · (2x – 6) – [(x – (3x – 8) + 2) – 1] = 2 – (3 – 2x)

6x - 18 - [(x – 3x + 8 + 2 – 1] = -1 + 2x

6x - 18 + 2x - 9 = -1 + 2x

6x = 26

x = 13/3

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Complete Question:

Solve the following equations:

The predicted weight for an infant with a foot length of 9 centimeters is 4 kilograms.

Therefore, the correct answer is: B) 7.

To determine the predicted weight of an infant with a foot length of 9 centimeters, we can refer to the given line model that represents the relationship between body weight and foot length for a group of infants.

From the line model, we can observe that the weight increases as the foot length increases.

Looking at the provided data, we see that the weights corresponding to foot lengths are given as:

Foot length (cm): 0, 2, 4, 6, 8, 10, 12, 14

Weight (kg): 14, 12, 10, 8, 6, 4, 2, 0

By examining the pattern, we can deduce that the weight decreases by 2 kilograms for every increase of 2 centimeters in foot length.

Therefore, to find the predicted weight for a foot length of 9 centimeters, we can subtract 2 kilograms from the weight corresponding to a foot length of 10 centimeters.

Weight for 10 cm - 2 kg = 4 kg

Thus, the predicted weight for an infant with a foot length of 9 centimeters is 4 kilograms.

Therefore, the correct answer is: B) 7

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Answer:

24x

Step-by-step explanation:

a) Bekele should deposit approximately Br. 4,071.56 at the end of every quarter to meet the objective of the down payment.

b)  we find that the monthly mortgage payment should be approximately Br. 3,421.91.

c)  we find that the total interest paid on the mortgage is approximately Br. 422,288.60.

d)  we find that the total amount paid over the entire period of the mortgage is approximately Br. 1,231,487.60.

a) To determine how much Bekele should deposit at the end of every quarter to meet the objective of the down payment, we can use the sinking fund formula. The formula for the future value of a sinking fund is:

FV = P * ((1 + r/n)^(n*t) - 1) / (r/n)

Where:

FV is the future value or the down payment amount (Br. 100,000),

P is the periodic deposit we need to find,

r is the annual interest rate (10% or 0.10),

n is the number of compounding periods per year (4, since it is compounded quarterly),

and t is the number of years (5).

Plugging in the values into the formula, we can solve for P:

100,000 = P * ((1 + 0.10/4)^(4*5) - 1) / (0.10/4)

Simplifying the equation, we have:

100,000 = P * (1.025^20 - 1) / 0.025

Now, we can solve for P:

P = 100,000 * 0.025 / (1.025^20 - 1)

Calculating the value, we find that Bekele should deposit approximately Br. 4,071.56 at the end of every quarter to meet the objective of the down payment.

b) To determine the amount of the monthly mortgage payment to discharge the mortgage within 30 years, we can use the formula for the monthly mortgage payment (PMT) of an amortizing loan:

PMT = (P * r) / (1 - (1 + r)^(-n))

Where:

P is the principal amount of the loan (Br. 400,000, obtained by subtracting the down payment from the total cost),

r is the monthly interest rate (12% divided by 12 months, or 0.01),

and n is the total number of monthly payments (30 years multiplied by 12 months, or 360).

Plugging in the values into the formula, we can calculate the monthly mortgage payment:

PMT = (400,000 * 0.01) / (1 - (1 + 0.01)^(-360))

Using a calculator or spreadsheet, we find that the monthly mortgage payment should be approximately Br. 3,421.91.

c) To calculate the total interest paid on the mortgage, we can subtract the principal amount from the total amount paid over the entire period. The principal amount is Br. 400,000, and the total amount paid over the entire period can be obtained by multiplying the monthly mortgage payment by the total number of payments (360).

Total interest paid = (Monthly mortgage payment * Total number of payments) - Principal amount

Total interest paid = (3,421.91 * 360) - 400,000

Using a calculator, we find that the total interest paid on the mortgage is approximately Br. 422,288.60.

d) The total amount paid over the entire period of the mortgage can be calculated by multiplying the monthly mortgage payment by the total number of payments:

Total amount paid = Monthly mortgage payment * Total number of payments

Total amount paid = 3,421.91 * 360

Using a calculator, we find that the total amount paid over the entire period of the mortgage is approximately Br. 1,231,487.60.

Therefore, Bekele will need to deposit approximately Br. 4,071.56 at the end of every quarter to meet the down payment, make monthly mortgage payments of Br. 3,421.91, pay a total of approximately Br. 422,288.60

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Answer:

With the Pay-As-You-Go Calling Plan, licensed users can call out to numbers located in the country/region where their Microsoft 365 license is assigned to the user based on the user's location, and to international numbers in 196 countries/regions. Unlimited incoming minutes are included.

The correct answer is (a) a bacteria culture triples in size every day describes a exponential function.

We have,

A relation is a function if it has only One y-value for each x-value.

The growth of a population, bacteria culture, or puppy can be modeled by an exponential function if the growth rate is proportional to the current size.

In other words, if the growth rate is constant, then the growth can be modeled by an exponential function.

Out of the three situations given, option (i) is the only one that has a constant growth rate, since the bacteria culture triples in size every day. This means that the growth rate is constant at 200% per day.

Option (iii) has a growth rate that is not constant but increases every year, so it is not best modeled by an exponential function.

Option (ii) also has a growth rate that is not constant, since A plant grows by 1 inch every 4 days regardless of its current height.

Therefore, the correct answer is (a) a bacteria culture triples in size every day describes a exponential function.

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Using the interval 25 - 30 income, the recommended monetary range for the monthly rental budget for the mechanic is $841.75 and $1,010.10.

Mathematically, the range is the lowest and highest value.

The range may also refer to the difference between the highest value and the lowest value in a data set.

The mechanic's hourly pay rate = $32.50

Hours worked per week = 35 hours

Federal and state taxes = 21%

Savings = 5%

Gross pay for the month = $4,550 ($32.50 x 35 x 4)

Federal and state taxes = $955.50 ($4,550 x 21%)

Savings = $227.50  ($4,550 x 5%)

Net Pay = $3,367 ($4,550 - $955.50 - $227.50)

Lower bounds of the interval = 25

Upper bounds of the interval = 30

Recommended range for monthly rental budget = $841.75 (3,367 x 25%) and $1,010.10 ($3,367 x 30%)

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Answer:

8

Step-by-step explanation:

First, you need to find the cost of one video. We know that the cost of 1 video is equal to 4 times the cost of each song. So we will take the cost of a song $1.25 and multiply by four.

$1.25(4) = $5

So if one video costs $5, we now need to find the cost of 12 videos because we need to know how many songs you can purchase after you purchase 12 videos.

12($5) = $60

Now that we know that you have spent $60 on your videos, we need to figure out how many songs you can purchase now that we know you have $10 remaining of the initial $70. To do this, we will divide $10 by $1.25

$10/$1.25 = 8

With $70, given that you have already purchased 12 videos, you can also purchase 8 songs.

Answer and Explanation:

First, we can find the factored areas of the circle (the non-shaded area) and the rectangle (which includes the shaded and non-shaded areas).

We can use the rule:

if [tex]x^2 + cx + d = (x + a)(x + b)[/tex], then [tex]c = a + b[/tex] and [tex]d = a \cdot b[/tex].

__

[tex]A_\circ = \dfrac{x+1}{x^2 + 6x + 8}[/tex]

[tex]\boxed{A_\circ = \dfrac{x+1}{(x + 2)(x + 4)}}[/tex]

__

[tex]A_\square = \dfrac{x+1}{x^2 - 6x -16}[/tex]

[tex]\boxed{A_\square = \dfrac{x+1}{(x+2)(x-8)}}[/tex]

Since we want to subtract the area of the circle from the area of the rectangle, we need them to have a common denominator.

We can achieve this by multiplying the area of the circle by [tex]\dfrac{(x-8)}{(x-8)}[/tex] and the area of the rectangle by [tex]\dfrac{(x+4)}{(x+4)}[/tex] because then both fractions will have the denominator [tex](x+2)(x+4)(x-8)[/tex].

[tex]A_\circ = \dfrac{(x+1)(x-8)}{(x + 2)(x + 4)(x-8)}[/tex]

[tex]A_\square = \dfrac{(x+1)(x+4)}{(x+2)(x-8)(x+4)}[/tex]

Now that they have a common denominator, we can subtract them to get the area of the shaded region.

[tex]A_\text{shaded} = A_\square - A_\circ[/tex]

[tex]A_\text{shaded} = \left(\dfrac{(x+1)(x+4)}{(x + 2)(x + 4)(x-8)}\right) - \left(\dfrac{(x+1)(x-8)}{(x+2)(x+4)(x-8)}\right)[/tex]

Now, we can foil out the numerators of each fraction and combining like terms.

[tex]A_\text{shaded} = \left(\dfrac{x^2 + 5x + 4}{(x + 2)(x + 4)(x-8)}\right) - \left(\dfrac{x^2 - 7x - 8}{(x+2)(x+4)(x-8)}\right)[/tex]

↓ rewriting as one fraction ... [tex]\dfrac{x}{y} - \dfrac{z}{y} = \dfrac{x-z}{y}[/tex]

[tex]A_\text{shaded} = \dfrac{ (x^2 + 5x + 4) - (x^2 - 7x - 8)}{(x + 2)(x + 4)(x-8)}[/tex]

↓ distributing the negative

[tex]A_\text{shaded} = \dfrac{x^2 + 5x + 4 - x^2 + 7x + 8}{(x + 2)(x + 4)(x-8)}[/tex]

↓ grouping like terms

[tex]A_\text{shaded} = \dfrac{(x^2 - x^2) + (5x + 7x) + (4 + 8)}{(x + 2)(x + 4)(x-8)}[/tex]

↓ combining like terms

[tex]\boxed{A_\text{shaded} = \dfrac{12x + 12}{(x + 2)(x + 4)(x-8)}}[/tex]

Answer:

 (a) Parallelogram

  (c) Rhombus

Step-by-step explanation:

You want the names applicable to a quadrilateral with diagonals that bisect each other and bisect the vertex angles.

When the diagonals of a quadrilateral bisect each other, that quadrilateral is a parallelogram. With two pairs of parallel sides, the figure cannot be a trapezoid.

When both diagonals bisect the vertex angles, the quadrilateral is a rhombus.

The diagonals of a rectangle or square are congruent. The given figure labels the diagonals differently, so we cannot assume they are congruent. Hence the figure is not necessarily a rectangle or square.

The figure shown is a parallelogram that is a rhombus.

__

Additional comment

The figure doesn't have the crossing of diagonals marked as right angles, but they are. Segments 's' and 'x' are each altitudes of their respective isosceles triangles, so they must meet at right angles.

The relations shown in this figure can be used to prove a quadrilateral is a parallelogram and/or rhombus. That can be handy sometimes.

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The value of the angle U from the calculation is 88 degrees.

The sine rule can be applied in a variety of situations, such as determining a triangle's unknown side lengths or angles. The sine rule can be used to locate the missing side or angle if you know the lengths of two sides and the measure of an angle (not necessarily the included angle).

By the use of the sine rule;

u/Sin U = w/Sin W

Thus;

76/Sin U = 71/Sin 69

Sin U = 76Sin 69/71

U = Sin-1 (76Sin 69/71)

U = 88 degrees

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Answer:

[tex]\huge\boxed{\sf 1.8 \times 10^3}[/tex]

Step-by-step explanation:

Quotient means "to divide".

[tex]\displaystyle = \frac{4.68 \times 10^6}{2.6 \times 10^3} \\\\\underline{\sf Exponent \ rule:}\frac{a^m}{a^n} = a^{m-n}\\\\= 1.8 \times 10^{6-3}\\\\= 1.8 \times 10^3\\\\\rule[225]{225}{2}[/tex]

Answer:

[tex]b=-\frac{1}{2}, \frac{2}{7}[/tex]

Step-by-step explanation:

Starting from this equation [tex]14b^2-2= -3b[/tex]

We can rewrite it to a quadratic equation:

[tex]14b^2+3b-2= 0[/tex]

Factoring this equation gives us:

[tex](7b-2)(2b+1)=0[/tex]

Now because its a quadratic formula, we have to answers:

[tex](7b-2) = 0\\7b=2\\b=\frac{2}{7}[/tex]

or

[tex](2b+1)=0\\2b=-1\\b=-\frac{1}{2}[/tex]

Answer:

ratio of tomato to other ingredients

Step-by-step explanation:

Answer:

Step-by-step explanation:

To find the values of the given expressions, we first need to find the values of t and b, which are the roots of the equation 2x² + 3x - 1 = 0.

Using the quadratic formula, we can solve for x:

x = (-b ± √(b² - 4ac)) / (2a)

For our equation, a = 2, b = 3, and c = -1. Plugging in these values, we can calculate t and b:

t = (-3 + √(3² - 4(2)(-1))) / (2(2))

t = (-3 + √(9 + 8)) / 4

t = (-3 + √17) / 4

b = (-3 - √(3² - 4(2)(-1))) / (2(2))

b = (-3 - √(9 + 8)) / 4

b = (-3 - √17) / 4

Now, let's calculate the values of the given expressions:

(a) t² + b²

Substituting the values of t and b:

(t² + b²) = ((-3 + √17) / 4)² + ((-3 - √17) / 4)²

= (9 - 6√17 + 17) / 16 + (9 + 6√17 + 17) / 16

= (35 + 12√17) / 16 + (35 - 12√17) / 16

= 70 / 16

= 35 / 8

(b) (t - b)²

Substituting the values of t and b:

(t - b)² = ((-3 + √17) / 4 - (-3 - √17) / 4)²

= (2√17)²

= 4(17)

= 68

(c) (2 + 1/b²)(b² + 1/t²)

Substituting the values of t and b:

(2 + 1/b²)(b² + 1/t²) = (2 + 1/((-3 - √17) / 4)²)((-3 - √17) / 4)² + 1/((-3 + √17) / 4)²)

= (2 + 16 / (3 + √17)²)((-3 - √17) / 4)² + 16 / (3 - √17)²)

= (2 + 16 / (3 + √17)²)((-3 - √17) / 4)² + 16 / (3 - √17)²)

The final expression cannot be further simplified without knowing the exact values of √17.

The domain and range for the function shown in the graph above include the following:

D. D: [-∞, ∞]

    R: [-10, ∞]

In Mathematics and Geometry, a domain refers to the set of all real numbers (x-values) for which a particular function (equation) is defined.

In Mathematics and Geometry, the horizontal portion of any graph is used to represent all domain values and they are both read and written from smaller to larger numerical values, which simply means from the left of any graph to the right.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = [-∞, ∞] or all real numbers.

Range = [-10, ∞] or y ≥ -10

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