some particular website, the password must start with A or B there must be 5 more characters, and each of the characters may be a numeric digit or letter of the alphabet how many diffrent passwords are possible

Answers

Answer 1
ANSWER -

If a password on a particular website must start with either A or B and must have 5 more characters that can be either a numeric digit or a letter of the alphabet, we can use the multiplication principle to calculate the total number of possible passwords.

Since the first character can be either A or B, there are 2 options for the first character. For each of those options, there are 36 options (26 letters + 10 digits) for the remaining 5 characters.

Using the multiplication principle, we can multiply the number of options for each position to get the total number of possible passwords:

2 (options for the first character) * 36^5 (options for each of the remaining 5 characters) = 2 * 60,466,176 = 120,932,352

Therefore, there are 120,932,352 different possible passwords that meet the requirements for this particular website.

Related Questions

In a family of 5 children what is the probability of have 1 boy and then 4 girls in any order. (Exclude multiple births and assume all outcomes)

Answers

The probability of having a boy and a girl in this order would be given as 0.02857

How to solve for the probability

Probability is a branch of mathematics that deals with the study of randomness and uncertainty. In statistics, probability is used to describe the likelihood or chance of an event occurring.

In particular, probability can be used to quantify the chances of different outcomes in a random experiment or event. A random experiment is a process that generates different outcomes, but the outcome of any single trial cannot be predicted with certainty.

There are two choices for each birth. That is a boy and girl

we have 2 ^ 5 = 32

the probability of having a boy and a girl in this order would be

1 / 32

= 0.03125

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ANSWER -

The probability of having 1 boy and 4 girls in any order in a family of 5 children can be calculated using the binomial probability formula:

P(1 boy and 4 girls) = (5 choose 1) * (1/2)^1 * (1/2)^4

where "5 choose 1" is the number of ways to choose 1 boy out of 5 children, and (1/2)^1 and (1/2)^4 are the probabilities of having a boy and a girl, respectively, for each child.

Simplifying the expression, we get:

P(1 boy and 4 girls) = 5 * (1/2)^5 = 5/32

Therefore, the probability of having 1 boy and 4 girls in any order in a family of 5 children is 5/32 or approximately 0.15625.


When I have an ? in something, it is easy to learn.

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When I have an interest in something, it is easy to learn.

How can interest affect learning?

When you approach learning with a passive or disinterested attitude, it can be difficult to retain information or apply it in real-world situations.

So embracing your natural curiosity and actively seeking out answers to your questions is a great way to make learning easier and more enjoyable as you already have a genuine interest in it and would want to learn more about it.

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0.30P+0.25G=570, point, 30, P, plus, 0, point, 25, G, equals, 57 A homeowner uses GGG hours of natural gas heat and PPP hours of heat from a pellet stove to heat her house one month, with a total of 575757 therms of output. How many therms per hour does the pellet stove output?

Answers

Answer:

this is a SAT college question that involves solving a system of equations with two variables, P and G. P represents the number of hours of heat from a pellet stove, and G represents the number of hours of natural gas heat. The equation 0.30P+0.25G=570 means that the total cost of heating for one month is 570 dollars, where 0.30 dollars is the cost per hour of pellet stove heat and 0.25 dollars is the cost per hour of natural gas heat.

The question also gives another equation: P+G=57, which means that the total number of hours of heating for one month is 57 hours.

To find how many therms per hour does the pellet stove output, we need to solve this system of equations for P and G, and then use another formula that relates therms to kilowatt-hours (kWh).

one therm (US) is equal to 29.3001111 kWh.

We can use substitution or elimination method to solve the system of equations:

Using substitution:

P+G=57 P=57-G

Substitute P into the first equation:

0.30(57-G)+0.25G=570 17.1-0.30G+0.25G=570 -0.05G=-552.9 G=11058

Plug G into either equation to find P:

P+11058=57 P=-11001

Using elimination:

Multiply both sides of the second equation by -0.25:

P+G=57 -0.25P-0.25G=-14.25

Add both equations together:

(0.30P-0.25P)+(0.25G-0.25G)=570-14.25 0.05P=55575 P=-111015

Plug P into either equation to find G:

-111015+G=57 G=11072

We can see that both methods give us the same values for P and G.

Now we can use these values to find how many therms per hour does the pellet stove output.

We know that one therm (US) is equal to 29.3001111 kWh, so we can write:

Therms per hour = kWh per hour / 293001111

We also know that kWh per hour = Cost per hour / Cost per kWh.

in February 2023, the average cost per kWh in Kentucky was $0.11.

So we can write:

Therms per hour = (Cost per hour / $011) / 293001111

For pellet stove heat, we have:

Therms per hour = ($030 / $011) / 293001111 Therms per hour = ~0000036

Therefore, the pellet stove outputs about 0000036 therms per hour.

Explanation:

a laundry bag contains 6 brown socks and 4 black socks, find the probability of picking a 2 brown socks, if the first sock is returned in the bag before the second sock is picked

Answers

The probability of picking a brown sock on the first draw is 6/10. Since the sock is returned to the bag, the number of socks and the number of brown socks remains the same for the second draw, so the probability of picking a brown sock on the second draw is also 6/10.

The probability of picking two brown socks is the product of the probabilities of picking a brown sock on the first draw and on the second draw, which is:

P(2 brown socks) = P(brown on first draw) * P(brown on second draw)

= 6/10 * 6/10

= 36/100

= 0.36

Therefore, the probability of picking two brown socks, if the first sock is returned in the bag before the second sock is picked, is 0.36 or 36%.

ANSWER-

The probability of picking a brown sock on the first draw is 6/10, since there are 6 brown socks out of 10 total socks. Since the first sock is returned to the bag, the number of brown socks and black socks remain the same for the second draw.

The probability of picking a brown sock on the second draw, given that a brown sock was picked on the first draw, is also 6/10.

To find the probability of picking 2 brown socks, we can multiply the probability of picking a brown sock on the first draw by the probability of picking a brown sock on the second draw:

P(2 brown socks) = (6/10) x (6/10) = 36/100 = 0.36

Therefore, the probability of picking 2 brown socks, if the first sock is returned to the bag before the second sock is picked, is 0.36 or 36%.
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