Steam enters a steady-flow adiabatic nozzle with a low inlet velocity (assume ~0 m/s) as a saturated vapor at 6 MPa and expands to 1.2 MPa.

a. Under what conditions is the velocity from this nozzle maximized?
b. Determine the maximum exit velocity of the steam, in m/s.

Answer:

[tex]F_r = 40.01N[/tex]

Explanation:

Given

Let the two forces be [tex]F_1\ and\ F_2[/tex]

[tex]F_1 = 80N[/tex]

[tex]F_2 = 70N[/tex]

[tex]\theta = 150\deg[/tex]

Required

Determine the resultant force [tex]F_r[/tex]

This will be solved using parallelogram law of resultant force.

The equation is:

[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2cos\theta[/tex]

Substitute values for [tex]F_1[/tex], [tex]F_2[/tex] and [tex]\theta[/tex]

[tex]F_r^2 = 80^2 + 70^2+ 2 * 70 * 80 * cos\ 150[/tex]

[tex]F_r^2 = 6400 + 4900 + 11200* cos\ 150[/tex]

[tex]F_r^2 = 6400 + 4900 + 11200* -0.8660[/tex]

[tex]F_r^2 = 6400 + 4900 - 9699.2[/tex]

[tex]F_r^2 = 1600.8[/tex]

Take the square root of both sides

[tex]F_r = \sqrt{1600.8[/tex]

[tex]F_r = 40.01N[/tex]

Hence, the resultant force is 40.01 N

Answer:

UI Design

Explanation:

Answer:Size reduction

Cooling

Mixing

Explanation:

Answer:

Step 1: State your null and alternate hypothesis. ...

Step 2: Collect data. ...

Step 3: Perform a statistical test. ...

Step 4: Decide whether the null hypothesis is supported or refuted. ...

Step 5: Present your findings.

Answer:

Compressed air systems usually consist of the following components:

compressor.

air cooler.

air receiver tank.

filter.

dryer.

condensate trap.

distribution system

Answer:

Compressed air systems usually consist of the following components:

compressor.

air cooler.

air receiver tank.

filter.

dryer.

condensate trap.

distribution system

Explanation:

Compressed air systems usually consist of the following components:

compressor.

air cooler.

air receiver tank.

filter.

dryer.

condensate trap.

distribution system

Answer:

Yes

Explanation:

Because your installing something

The powder metallurgy process that would be used to produce a fully dense component is Hot Isostatic Pressing. The correct option is a.

Hot isostatic pressing is a process used to consolidate metal powder or to remove defects in solids such as pores, voids, and internal cracks, densifying the material to 100% of its theoretical density.

Hot Isostatic Pressing (HIP) is a process used to densify powders, cast and sintered parts, and steels and superalloys in a furnace at high pressure and temperatures ranging from 900 to 1250°C.

To provide isotropic properties and 100% densification, the gas pressure acts uniformly in all directions.

Hot Isostatic Pressing is the powder metallurgy process that would be used to create a fully dense component.

Thus, the correct option is a.

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Answer:

[tex]V_{rms}=6\sqrt2\ V[/tex]

Explanation:

Given that,

The maximum voltage of an alternating current, [tex]V_{max}=12\ V[/tex]

We need to find the highest Vrms that can be supplied to this component while staying below the voltage limit.

Let rms voltage in terms of peak voltage is given by :

[tex]V_{rms}=\dfrac{V}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\times \dfrac{\sqrt2}{\sqrt2}\\\\=\dfrac{12\sqrt2}{2}\\\\=6\sqrt2\ V[/tex]

Hence, the required rms voltage is [tex]6\sqrt2\ V[/tex].

Answer:

6282 kJ

Explanation:

Given that:

The mass (m) = 15 kg

The specific latent heat of ice fusion [tex]h_{fg}_{ice}[/tex] = 335 kJ/kg

The specific heat capacity of water = 4.19 kJ/kg.c

The initial temperature of the ice [tex]T_i[/tex]= 0° C

The final temperature of the water [tex]T_f[/tex] = 20° C

To find the needed amount of heat to convert 0° C ice to 20° C of water.

To do that, we need to find the latent heat required for the phase change from 0° C ice to 0° C water, then the heat required to convert  0° C water to 20° C water.

Heat required = [tex]m \times h_{fg}_{ice}+ m \times c_{water} \times \Delta T[/tex]

Heat required = (15 × 335) + (15 × 4.19) × (20 - 0)

Heat required = 5025 + 62.85 × 20

Heat required = 5025 + 1257

Heat required = 6282 kJ

Answer:

The Process of printing

Explanation:

hope this helps :)

Answer:

A. Ability to correct system maintenance issues

Explanation:

As a systems engineer, you will be responsible for a range of tasks, including management of IT systems, working with software developers to design and document new system architecture, and testing and implementing processes to improve the efficacy of existing systems.

Answer:

need more information about the question

Answer:

recombinant human growth

Explanation:

Answer:

recombinant human growth

Explanation:

yes

Answer:

Explanation:

Your 3-B Annual Credit Reports & Scores with Enhanced Credit Report Monitoring.

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The credit building options that I think  is the easiest method that you can see yourself doing is Secured credit cards.

Secured credit cards are known to be a type of card that are said to be backed by a specific refundable security deposit.

This kind of deposit is known to limit or lower the lender's risk and thus makes it better for people who do not have credit or when they do not  qualify for that type of credit. This credit option is easier to get when compared to unsecured cards, as it does not need a lot of requirement.

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Answer:

Explanation:

The material rate of removal is the total amount of material removed per unit time during any operation. The material rate of removal is usually given by the formula

Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where

Radial Depth of Cut, RDOC = 25 mm

Axial depth of cut, ADOC = 200 mm

Feed rate, FR = 25 mm/min

On multiplying all together, we will then have our Material Rate of Removal, which is

MRR = 25 mm * 200 mm * 25 mm/min

MRR = 125000 mm³/min

Or we convert it to cm³/min and have

MRR = 125000 mm³/min ÷ 1000

MRR = 125 cm³/min

Answer:

No.

Explanation:

[tex]P_r[/tex] = Power rating = 1 W

R = Resistance = [tex]350\ \Omega[/tex]

V = Voltage = [tex]24\ \text{V}[/tex]

Power is given by

[tex]P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{24^2}{350}\\\Rightarrow P=1.65\ \text{W}[/tex]

[tex]1.65\ \text{W}>1\ \text{W}[/tex]

So

[tex]P>P_r[/tex]

Hence, the resistor is not operating within its power rating.

This question is incomplete, the complete question is;

Determine the design moment strength (ϕMn) for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb = 18 ft). Report the result in kip-ft.

Use Fy=50 ksi and assume Cb=1.0 (if needed).

Answer: the design moment strength for the W21x73 steel beam is 566.25 f-ft

Explanation:

Given that;

section  W 21 x 73 steel beam;

now from the steel table table for this section;

Zx = Sx = 151 in³

also given that; fy = 50 ksi and Cb = 1.0

QMn = 0.9 × Fy × Zx

so we substitute

QMn = 0.9 × 50 × 151

QMn = 6795 k-inch

we know that;

12inch equals 1 foot

so

QMn = 6795 k-inch / 12

QMn = 566.25 f-ft

Therefore the design moment strength for the W21x73 steel beam is 566.25 f-ft

Answer:

D

Explanation:

An ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.

Solenoids may be characterized as a coil of wire that is usually in a cylindrical form and carries a current that acts like a magnet. Due to this, a migratory core is drawn into the coil when a current flows, and that is utilized especially as a switch or control for a mechanical device.

Similarly, an ignition coil also represents an example of a solenoid because it also consists of a coil of wire and carries a current that acts like a magnet. While the concept of the transformers is different as it stores a huge amount of electric current and spread it accordingly.

Therefore, an ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.

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Answer:

Answer:B

Explanation:

Solution :

Given :

k = 0.5 per day

[tex]$C_s = 10 \ mg/L \ ; \ \ Q_s= 40 \ m^3/s$[/tex]

[tex]$C_{sw} = 100 \ ppm \ ; \ \ Q_{sw}= 0.5 \ m^3/s$[/tex]

Volume, V [tex]$= 200 \ m^3$[/tex]

Now, input rate = output rate + KCV ------------- (1)

Input rate  [tex]$= Q_s C_s + Q_{sw}C_{sw}$[/tex]

                [tex]$=(40 \times 10) + (0.5\times 100)$[/tex]

                [tex]$= 2 \times 10^5 \ mg/s$[/tex]

The output rate [tex]$= Q_m C_{m}$[/tex]

                          = ( 40 + 0.5 ) x C x 1000

                          [tex]$=40.5 \times 10^3 \ C \ mg/s$[/tex]

Decay rate = KCV

∴[tex]$KCV =\frac{0.5/d \times C \ \times 200 \times 1000}{24 \times 3600}$[/tex]

            = 1.16 C mg/s

Substituting all values in (1)

[tex]$2 \times 10^5 = 40.5 \times 10^3 \ C+ 1.16 C$[/tex]

C = 4.93 mg/L

Answer:

The fluid velocity V = 1.98 ft/s

Explanation:

From the information given:

The fluid velocity can be determined from the head-loss [tex]h_L[/tex] of a laminar pipe and it is expressed as:

[tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]

where;

f = frictional factor ; l = length; D = diameter; V= fluid velocity and g = acceleration due to gravity.

And;

[tex]f = \dfrac{64}{Re}[/tex]

For fluid movement in a laminar flow, the Reynolds number (Re) is usually lesser than 2100.

Given that:

Re = 1508 < 2100   ( laminar flow)

Then;

[tex]f = \dfrac{64}{1508}[/tex]

f = 0.04244

Also;

the head-loss [tex]h_L[/tex] = 6.2 ft

frictional force f = 0.04244

length = 20-ft

acceleration due to gravity (g) = 32.2 ft/s²

Replacing all the values into the equation [tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]; the fluid velocity is:

[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.1 \times \dfrac{1}{12} \times 2\times 32.2}[/tex]

[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.53667}[/tex]

6.2 × 0.53667 = 0.04244 × 20 × V²

3.327354  = 0.8488 × V²

[tex]V^2= \dfrac{3.327354} { 0.8488}[/tex]

[tex]V^2=3.92[/tex]

[tex]V = \sqrt{3.92}[/tex]

V = 1.98 ft/s

In addition to bandages and gauze, it's recommended that a first aid kit also contain scissors. The correct option is D.

First aid is the initial and urgent care given to anyone who has either a small or significant disease or injury, with the goal of preserving life, preventing the condition from getting worse, or assisting in the healing process.

First aid is the initial and urgent care given to anyone who has either a small or significant disease or injury, with the goal of preserving life, preventing the condition from getting worse, or assisting in the healing process.

A first aid kit normally contains :

1. plasters

2. scissors

3. bandages

4. antiseptic ointments or lotions

5. basic medicines

6. gauzes

Anyone who has been hurt in an accident or has been injured can receive quick and basic medical care with the help of these materials.

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Answer:

18.77 A

Explanation:

To solve this we use the energy balance equation, that is:

[tex]E_{in}-E_{out}=\Delta E_{sys}\\\\Q_{in}+W_{in}+W_{out}=\Delta U\\\\Q_{in}+W_{in}=\Delta U\\\\But\ W_{in}=Voltage(V)*Current(I)*change\ in\ time(\Delta t)=VI\Delta t,\Delta U=m(h_2-h_1)\\\\Given\ that\ m=15kg,V=110\ V,\Delta t=6\ min = (6*60\ s)=360\ s,Q_{in}=20.67\ kJ/kg*15\ kg=310.05\ kJ=310050\ J\\\\From\ table: At\ P_1=280kPa, h_1=249.71\ kJ/kg=249710\ J/kg;At\ P_2=280kPa \ and\ T_1=75^oC,P_2=319.95\ kJ/kg=319950\ J/kg\\\\Substituting:\\\\310500+(110*360*I)=15(319950-249710)\\\\[/tex]

[tex]39600I=1053600-310500\\\\39600I=743100\\\\I=18.77\ A[/tex]

Solution :

Given :

h = 2 cm

Diameter of the tube , d = 1 mm

Diameter of the hose, D = 6 mm

Between 1 and 2, by applying Bernoulli's principle, we get

As point 1 is just below the free surface of liquid, so

[tex]$P_1=P_{atm} \text{ and} \ V_1=0$[/tex]

[tex]$\frac{P_{atm}}{\rho g}+\frac{v_1^2}{2g} +h = \frac{P_2}{\rho g}$[/tex]

[tex]$\frac{101.325}{1000 \times 9.81}+0.02 =\frac{P_2}{\rho g}$[/tex]

[tex]$P_2 = 111.35 \ kPa$[/tex]

Therefore, 111.325 kPa is the gas supply pressure required to keep the water from leaking back into the tube.

Velocity at point 2,

[tex]$V_2=\sqrt{\left(\frac{111.135}{\rho g}+0.02}\right)\times 2g$[/tex]

   = 1.617 m/s

Flow of water,  [tex]$Q_2 = A_{tube} \times V_2$[/tex]

                               [tex]$=\frac{\pi}{4} \times (10^{-3})^2 \times 1.617 $[/tex]

                               [tex]$1.2695 \times 10^{-6} \ m^3/s$[/tex]

Minimum air flow rate,

[tex]$Q_2 = Q_3 = A_{hose} \times V_3$[/tex]

[tex]$V_3 = \frac{Q_2}{\frac{\pi}{4}D^2}$[/tex]

[tex]$V_3 = \frac{1.2695 \times10^{-6}}{\pi\times 0.25 \times 36 \times 10^{-6}}$[/tex]

    = 0.0449 m/s

b). Reynolds number in hose,

[tex]$Re = \frac{\rho V_3 D}{\mu} = \frac{V_3 D}{\nu}$[/tex]

υ for water at 25 degree Celsius is [tex]$8.9 \times 10^{-7} \ m^2/s$[/tex]

υ for air at 25 degree Celsius is [tex]$1.562 \times 10^{-5} \ m^2/s$[/tex]

[tex]$Re_{hose}=\frac{0.0449 \times 6 \times 10^{-3}}{1.562 \times 10^{-5}}$[/tex]

           = 17.25

Therefore the flow is laminar.

Reynolds number in the pipe

[tex]$Re = \frac{V_2 d}{\nu} = \frac{1.617 \times 10^{-3}}{8.9 \times 10^{-7}}$[/tex]

                = 1816.85, which is less than 2000.

So the flow is laminar inside the tube.

Answer:

Explanation:

The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include

Being proactive

Starting anything with the end in mind

First things first

Always thinking towards a win-win situation

Seeking initially to understand, then going on to want to be understood

Synergize, and lastly

Growing

Answer:

Biochemistry

Explanation:

Hope this helps :)

Answer:

Biochemistry

Have an amazing day!

Answer:

The answer is "[tex]\bold{175000 \ \frac{lbs}{in^2}}[/tex]"

Explanation:

The formula for the max value of UTS:

[tex]= \frac{F}{A} \\\\= \frac{175\ ton}{ 2 \ in^2} \\\\= \frac{350000}{2}\\\\[/tex]

Max UTS:

[tex]\to 175000 \ \frac{lbs}{in^2}[/tex]