This happens as a result of a gain in kinetic energy at the expense of a decrease in enthalpy brought on by gas expansion as air passes through the diverging region of the nozzle.
What velocity from this adiabatic nozzle maximized?A nozzle is a tool used to change the characteristics of a fluid flow as it leaves a confined chamber or conduit, particularly to enhance velocity. The reciprocal of the nozzle length, pressure, and the square root of the nozzle diameter all increase air velocity.
A nozzle needs to be made to expand steam from 500 PA at 210 °C to 100 kPa at a rate of 0.1 kg/s. In order to reach critical or sonic conditions (i.e., choked flow) at its throat, the flow is accelerated when a nozzle is used.
Therefore, The steam's specific volume at the nozzle's exit is determined to be 1.4 m3/kg and its velocity at that point to be 700 m/s.
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Which is a better hydraulic cross section for an open channel: one with a small or a large hydraulic radius?
If a machine guard is missing or needs repair, you should ______________.
A) Ignore it
B) Immediately remove that machine from service
C) Continue using the machine
D) Tell someone when you get around to it
(This is for my Automotive class)
Answer:B
Explanation:
A hubbing press has capasity of 175tons. If the workpice ia a copper alloy part with a 2in^2 projected area, what is the strongest alloy that can be hubbed?
Answer:
The answer is "[tex]\bold{175000 \ \frac{lbs}{in^2}}[/tex]"
Explanation:
The formula for the max value of UTS:
[tex]= \frac{F}{A} \\\\= \frac{175\ ton}{ 2 \ in^2} \\\\= \frac{350000}{2}\\\\[/tex]
Max UTS:
[tex]\to 175000 \ \frac{lbs}{in^2}[/tex]
Determine the design moment strength for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb
This question is incomplete, the complete question is;
Determine the design moment strength (ϕMn) for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb = 18 ft). Report the result in kip-ft.
Use Fy=50 ksi and assume Cb=1.0 (if needed).
Answer: the design moment strength for the W21x73 steel beam is 566.25 f-ft
Explanation:
Given that;
section W 21 x 73 steel beam;
now from the steel table table for this section;
Zx = Sx = 151 in³
also given that; fy = 50 ksi and Cb = 1.0
QMn = 0.9 × Fy × Zx
so we substitute
QMn = 0.9 × 50 × 151
QMn = 6795 k-inch
we know that;
12inch equals 1 foot
so
QMn = 6795 k-inch / 12
QMn = 566.25 f-ft
Therefore the design moment strength for the W21x73 steel beam is 566.25 f-ft
discuss 7 habits of highly effective people and how important are ethics in today's society
Answer:
Explanation:
The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include
Being proactive
Starting anything with the end in mind
First things first
Always thinking towards a win-win situation
Seeking initially to understand, then going on to want to be understood
Synergize, and lastly
Growing
Water vapor at a rate of 40,000 kg/h and at 8 MPa and 500 C enters an adiabatic turbine and leaves the turbine at 40 kPa as saturated vapor. The rate of entropy generation for this turbine is close to,
Answer:
M(dot)= 40000 kg/h Pressure= 8Mpa and T= 500C If its adiabatic then you know that it loses no heat or Q(dot) =0 You have a turbine which drives a shaft producing work for the other systems.We want to find entropy production of alpha.Type the correct answer in the box. Spell all words correctly.
A genetically engineered hormone, , can treat Mary’s child for growth hormone deficiencies by stimulating body growth and increasing muscle mass.
Answer:
recombinant human growth
Explanation:
Answer:
recombinant human growth
Explanation:
yes
Select three mechanical processes used in the manufacturing phase of engineering.
Drying
Mixing
Cooling
Crystallization
Size reduction
Food packaging
Answer:Size reduction
Cooling
Mixing
Explanation:
In addition to bandages and gauze, it's recommended that a first aid kit also contain ___________.
A) Portable eyewash bottles
B) Tweezers
C) A finger splint
D) Scissors
In addition to bandages and gauze, it's recommended that a first aid kit also contain scissors. The correct option is D.
What is First aid?First aid is the initial and urgent care given to anyone who has either a small or significant disease or injury, with the goal of preserving life, preventing the condition from getting worse, or assisting in the healing process.
First aid is the initial and urgent care given to anyone who has either a small or significant disease or injury, with the goal of preserving life, preventing the condition from getting worse, or assisting in the healing process.
A first aid kit normally contains :
1. plasters
2. scissors
3. bandages
4. antiseptic ointments or lotions
5. basic medicines
6. gauzes
Anyone who has been hurt in an accident or has been injured can receive quick and basic medical care with the help of these materials.
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_____ refers to the knowledge and skills necessary to manage, control, and work with hazardous materials and pollutants.
the term applied to the chemistry of the body
Answer:
Biochemistry
Explanation:
Hope this helps :)
Answer:
Biochemistry
Have an amazing day!
a 1-w, 350-ω resistor is connected to 24 v. Is this resistor operating within its power rating?
Answer:
No.
Explanation:
[tex]P_r[/tex] = Power rating = 1 W
R = Resistance = [tex]350\ \Omega[/tex]
V = Voltage = [tex]24\ \text{V}[/tex]
Power is given by
[tex]P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{24^2}{350}\\\Rightarrow P=1.65\ \text{W}[/tex]
[tex]1.65\ \text{W}>1\ \text{W}[/tex]
So
[tex]P>P_r[/tex]
Hence, the resistor is not operating within its power rating.
15 kg of ice at 0°C is heated to water of temperature 20°C. What is the amount of heat required if the specific latent heat of ice fusion is 335 kJ/kg and the specific heat capacity of water is 4.19kJ/kg/°C?
Answer:
6282 kJ
Explanation:
Given that:
The mass (m) = 15 kg
The specific latent heat of ice fusion [tex]h_{fg}_{ice}[/tex] = 335 kJ/kg
The specific heat capacity of water = 4.19 kJ/kg.c
The initial temperature of the ice [tex]T_i[/tex]= 0° C
The final temperature of the water [tex]T_f[/tex] = 20° C
To find the needed amount of heat to convert 0° C ice to 20° C of water.
To do that, we need to find the latent heat required for the phase change from 0° C ice to 0° C water, then the heat required to convert 0° C water to 20° C water.
Heat required = [tex]m \times h_{fg}_{ice}+ m \times c_{water} \times \Delta T[/tex]
Heat required = (15 × 335) + (15 × 4.19) × (20 - 0)
Heat required = 5025 + 62.85 × 20
Heat required = 5025 + 1257
Heat required = 6282 kJ
Which process made making copies of technical drawings easier?
In the nineteenth century, the process of ___________
helped professionals quickly create copies of technical drawings.
Answer:
The Process of printing
Explanation:
hope this helps :)
(20 points) A 1 mm diameter tube is connected to the bottom of a container filled with water to a height of 2 cm from the bottom. Air flows from the tube into the liquid and creates spherical bubbles with diameter about the diameter of the tube (1 mm). Everything is at 298 K. The tube is short but is connected to a much longer 2 m long hose that is 6 mm in diameter. The hose is connected to the gas supply. If there is no gas flow the water will leak into the tube and into the supply hose. When gas flows the water is blocked from entering the tube and bubbling starts. State all assumptions in answering the following questions. (a) What should be the minimum air flow rate and the gas supply pressure to keep the water from leaking back into the tube? (b) Is the flow in the hose laminar or turbulent? Is the flow in the tube laminar or turbulent?
Solution :
Given :
h = 2 cm
Diameter of the tube , d = 1 mm
Diameter of the hose, D = 6 mm
Between 1 and 2, by applying Bernoulli's principle, we get
As point 1 is just below the free surface of liquid, so
[tex]$P_1=P_{atm} \text{ and} \ V_1=0$[/tex]
[tex]$\frac{P_{atm}}{\rho g}+\frac{v_1^2}{2g} +h = \frac{P_2}{\rho g}$[/tex]
[tex]$\frac{101.325}{1000 \times 9.81}+0.02 =\frac{P_2}{\rho g}$[/tex]
[tex]$P_2 = 111.35 \ kPa$[/tex]
Therefore, 111.325 kPa is the gas supply pressure required to keep the water from leaking back into the tube.
Velocity at point 2,
[tex]$V_2=\sqrt{\left(\frac{111.135}{\rho g}+0.02}\right)\times 2g$[/tex]
= 1.617 m/s
Flow of water, [tex]$Q_2 = A_{tube} \times V_2$[/tex]
[tex]$=\frac{\pi}{4} \times (10^{-3})^2 \times 1.617 $[/tex]
[tex]$1.2695 \times 10^{-6} \ m^3/s$[/tex]
Minimum air flow rate,
[tex]$Q_2 = Q_3 = A_{hose} \times V_3$[/tex]
[tex]$V_3 = \frac{Q_2}{\frac{\pi}{4}D^2}$[/tex]
[tex]$V_3 = \frac{1.2695 \times10^{-6}}{\pi\times 0.25 \times 36 \times 10^{-6}}$[/tex]
= 0.0449 m/s
b). Reynolds number in hose,
[tex]$Re = \frac{\rho V_3 D}{\mu} = \frac{V_3 D}{\nu}$[/tex]
υ for water at 25 degree Celsius is [tex]$8.9 \times 10^{-7} \ m^2/s$[/tex]
υ for air at 25 degree Celsius is [tex]$1.562 \times 10^{-5} \ m^2/s$[/tex]
[tex]$Re_{hose}=\frac{0.0449 \times 6 \times 10^{-3}}{1.562 \times 10^{-5}}$[/tex]
= 17.25
Therefore the flow is laminar.
Reynolds number in the pipe
[tex]$Re = \frac{V_2 d}{\nu} = \frac{1.617 \times 10^{-3}}{8.9 \times 10^{-7}}$[/tex]
= 1816.85, which is less than 2000.
So the flow is laminar inside the tube.
What is the step in which you are testing your hypothesis
Answer:
Step 1: State your null and alternate hypothesis. ...
Step 2: Collect data. ...
Step 3: Perform a statistical test. ...
Step 4: Decide whether the null hypothesis is supported or refuted. ...
Step 5: Present your findings.
Rod of steel, 200 mm length reduces its diameter (50 mm) by turning by 2 mm with feed speed 25 mm/min. You are required to calculate the metal removal rate (MRR)
Answer:
Explanation:
The material rate of removal is the total amount of material removed per unit time during any operation. The material rate of removal is usually given by the formula
Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where
Radial Depth of Cut, RDOC = 25 mm
Axial depth of cut, ADOC = 200 mm
Feed rate, FR = 25 mm/min
On multiplying all together, we will then have our Material Rate of Removal, which is
MRR = 25 mm * 200 mm * 25 mm/min
MRR = 125000 mm³/min
Or we convert it to cm³/min and have
MRR = 125000 mm³/min ÷ 1000
MRR = 125 cm³/min
A piston–cylinder device contains 15 kg of saturated refrigerant-134a vapor at 280kPa. A resistance heater inside the cylinder with a value of 110V is used to transfer heat of 20.67kJ/kg to the refrigerant at constant pressure for 6min. Determine the current supplied if the final temperature is 75℃
Answer:
18.77 A
Explanation:
To solve this we use the energy balance equation, that is:
[tex]E_{in}-E_{out}=\Delta E_{sys}\\\\Q_{in}+W_{in}+W_{out}=\Delta U\\\\Q_{in}+W_{in}=\Delta U\\\\But\ W_{in}=Voltage(V)*Current(I)*change\ in\ time(\Delta t)=VI\Delta t,\Delta U=m(h_2-h_1)\\\\Given\ that\ m=15kg,V=110\ V,\Delta t=6\ min = (6*60\ s)=360\ s,Q_{in}=20.67\ kJ/kg*15\ kg=310.05\ kJ=310050\ J\\\\From\ table: At\ P_1=280kPa, h_1=249.71\ kJ/kg=249710\ J/kg;At\ P_2=280kPa \ and\ T_1=75^oC,P_2=319.95\ kJ/kg=319950\ J/kg\\\\Substituting:\\\\310500+(110*360*I)=15(319950-249710)\\\\[/tex]
[tex]39600I=1053600-310500\\\\39600I=743100\\\\I=18.77\ A[/tex]
An ignition coil is an example of a. A. Step-up transformer. B. Step- down transformer. C. Relay.
D. Solenoid.
Answer:
D
Explanation:
An ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.
What is Solenoid?Solenoids may be characterized as a coil of wire that is usually in a cylindrical form and carries a current that acts like a magnet. Due to this, a migratory core is drawn into the coil when a current flows, and that is utilized especially as a switch or control for a mechanical device.
Similarly, an ignition coil also represents an example of a solenoid because it also consists of a coil of wire and carries a current that acts like a magnet. While the concept of the transformers is different as it stores a huge amount of electric current and spread it accordingly.
Therefore, an ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.
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What’s are the preventive strategies for workplace violence
Which of these credit building options do you personally think is the easiest method that you can see yourself doing? Explain your reasoning.
Answer:
Explanation:
Your 3-B Annual Credit Reports & Scores with Enhanced Credit Report Monitoring.
Trusted by Millions
The credit building options that I think is the easiest method that you can see yourself doing is Secured credit cards.
What is the Secured credit cards?Secured credit cards are known to be a type of card that are said to be backed by a specific refundable security deposit.
This kind of deposit is known to limit or lower the lender's risk and thus makes it better for people who do not have credit or when they do not qualify for that type of credit. This credit option is easier to get when compared to unsecured cards, as it does not need a lot of requirement.
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A
AMINO BORCY
Two forces of 80 N and 70 N act simultaneously at a point Find the resultant force. if the
Angle between them is 150 dgree
Answer:
[tex]F_r = 40.01N[/tex]
Explanation:
Given
Let the two forces be [tex]F_1\ and\ F_2[/tex]
[tex]F_1 = 80N[/tex]
[tex]F_2 = 70N[/tex]
[tex]\theta = 150\deg[/tex]
Required
Determine the resultant force [tex]F_r[/tex]
This will be solved using parallelogram law of resultant force.
The equation is:
[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2cos\theta[/tex]
Substitute values for [tex]F_1[/tex], [tex]F_2[/tex] and [tex]\theta[/tex]
[tex]F_r^2 = 80^2 + 70^2+ 2 * 70 * 80 * cos\ 150[/tex]
[tex]F_r^2 = 6400 + 4900 + 11200* cos\ 150[/tex]
[tex]F_r^2 = 6400 + 4900 + 11200* -0.8660[/tex]
[tex]F_r^2 = 6400 + 4900 - 9699.2[/tex]
[tex]F_r^2 = 1600.8[/tex]
Take the square root of both sides
[tex]F_r = \sqrt{1600.8[/tex]
[tex]F_r = 40.01N[/tex]
Hence, the resultant force is 40.01 N
Which one of the following skills is a software engineer specializing in system support expected to possess?
ability to correct system maintenance issues
ability to direct traffic between devices
ability to develop user programming
ability to recommend system upgrades
Answer:
A. Ability to correct system maintenance issues
Explanation:
As a systems engineer, you will be responsible for a range of tasks, including management of IT systems, working with software developers to design and document new system architecture, and testing and implementing processes to improve the efficacy of existing systems.
A lake is fed by a polluted stream and a sewage outfall. The stream and sewage wastes have a decay rate coefficient (k) of 0.5/day (1st order units). Assuming complete mixing and no other water losses or gains, what is the steady-state pollutant concentration as mg/L in the lake? Incoming Stream: C = 10 mg/L, Q = 40 m^3/s Sewage Outfall: C = 100 ppm, Q = 0.5 m^3/s Lake: V= 200 m^3
Solution :
Given :
k = 0.5 per day
[tex]$C_s = 10 \ mg/L \ ; \ \ Q_s= 40 \ m^3/s$[/tex]
[tex]$C_{sw} = 100 \ ppm \ ; \ \ Q_{sw}= 0.5 \ m^3/s$[/tex]
Volume, V [tex]$= 200 \ m^3$[/tex]
Now, input rate = output rate + KCV ------------- (1)
Input rate [tex]$= Q_s C_s + Q_{sw}C_{sw}$[/tex]
[tex]$=(40 \times 10) + (0.5\times 100)$[/tex]
[tex]$= 2 \times 10^5 \ mg/s$[/tex]
The output rate [tex]$= Q_m C_{m}$[/tex]
= ( 40 + 0.5 ) x C x 1000
[tex]$=40.5 \times 10^3 \ C \ mg/s$[/tex]
Decay rate = KCV
∴[tex]$KCV =\frac{0.5/d \times C \ \times 200 \times 1000}{24 \times 3600}$[/tex]
= 1.16 C mg/s
Substituting all values in (1)
[tex]$2 \times 10^5 = 40.5 \times 10^3 \ C+ 1.16 C$[/tex]
C = 4.93 mg/L
You are designing a critical component to be installed in a chemical plant, where corrosion resistance and high temperature performance are critical. As a result, a fully dense material is required. Because of the materials used in the system, the part can only be produced by powder metallurgy. Which powder metallurgy process would you use to produce a fully dense component?a) Hot Isostatic Pressing b) Sinter then Metal Injection Molding c) Cold Isostatic Pressing d) Press and Sinter Processes e) Metal Injection Molding
Answer:
Yes
Explanation:
Because your installing something
The powder metallurgy process that would be used to produce a fully dense component is Hot Isostatic Pressing. The correct option is a.
What is Hot Isostatic Pressing?Hot isostatic pressing is a process used to consolidate metal powder or to remove defects in solids such as pores, voids, and internal cracks, densifying the material to 100% of its theoretical density.
Hot Isostatic Pressing (HIP) is a process used to densify powders, cast and sintered parts, and steels and superalloys in a furnace at high pressure and temperatures ranging from 900 to 1250°C.
To provide isotropic properties and 100% densification, the gas pressure acts uniformly in all directions.
Hot Isostatic Pressing is the powder metallurgy process that would be used to create a fully dense component.
Thus, the correct option is a.
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list the major parts in a shop's air supply system
Answer:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
Answer:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
Explanation:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
who designs each page or screen with which a user interacts?
Answer:
UI Design
Explanation:
A fluid flows though a horizontal 0.1 inch diameter pipe. When the Reynold number is 1508, the head loss over a 20-ft length of the pipe is 6.2 ft. Determine the fluid velocity.
Answer:
The fluid velocity V = 1.98 ft/s
Explanation:
From the information given:
The fluid velocity can be determined from the head-loss [tex]h_L[/tex] of a laminar pipe and it is expressed as:
[tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]
where;
f = frictional factor ; l = length; D = diameter; V= fluid velocity and g = acceleration due to gravity.
And;
[tex]f = \dfrac{64}{Re}[/tex]
For fluid movement in a laminar flow, the Reynolds number (Re) is usually lesser than 2100.
Given that:
Re = 1508 < 2100 ( laminar flow)
Then;
[tex]f = \dfrac{64}{1508}[/tex]
f = 0.04244
Also;
the head-loss [tex]h_L[/tex] = 6.2 ft
frictional force f = 0.04244
length = 20-ft
acceleration due to gravity (g) = 32.2 ft/s²
Replacing all the values into the equation [tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]; the fluid velocity is:
[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.1 \times \dfrac{1}{12} \times 2\times 32.2}[/tex]
[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.53667}[/tex]
6.2 × 0.53667 = 0.04244 × 20 × V²
3.327354 = 0.8488 × V²
[tex]V^2= \dfrac{3.327354} { 0.8488}[/tex]
[tex]V^2=3.92[/tex]
[tex]V = \sqrt{3.92}[/tex]
V = 1.98 ft/s
An alternating current is supplied to an electronic component with a rating that it be used only for voltages below 12 V. What is the highest Vrms that can be supplied to this component while staying below the voltage limit
Answer:
[tex]V_{rms}=6\sqrt2\ V[/tex]
Explanation:
Given that,
The maximum voltage of an alternating current, [tex]V_{max}=12\ V[/tex]
We need to find the highest Vrms that can be supplied to this component while staying below the voltage limit.
Let rms voltage in terms of peak voltage is given by :
[tex]V_{rms}=\dfrac{V}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\times \dfrac{\sqrt2}{\sqrt2}\\\\=\dfrac{12\sqrt2}{2}\\\\=6\sqrt2\ V[/tex]
Hence, the required rms voltage is [tex]6\sqrt2\ V[/tex].
What is a shop air compressor
Answer:
need more information about the question
