Subtract 5y^2 + 3y + 11 from 4y^2 + 7 - 6y.

show steps please i know the answer but i need the steps :/

Answers

Answer 1

Answer:

I got -y^2 - 9y -4 (I hope it helps)

Step-by-step explanation:

4y^2 - 5y^2= -y^2

7-11= -4

-6y + -3y= -9y

-y^2 -9y -4


Related Questions

12 out of 52 cards in a deck are face cards. What percentage of cards in a deck are face cards, to the nearest whole percent?

Answers

its too late but 23.08 so I'm sorry I took so long

What is the slope of the line?​

Answers

Answer:

Slope = 3/4

Step-by-step explanation:

sorry it’s late. Pls give brainliest.

Is linear or nonlinear?

Answers

Answer:

Linear

Step-by-step explanation:

-3 |-2•4 | =





.........

Answers

Answer:

-24

Step-by-step explanation:

I WILL GIVE YOU BRAINLY PLSS

2.2x – 3.408 ≥ 29.504
A. x ≤ 12
B. x ≥ 12
C. x ≥ 14.96
D. x ≤ 14.96

PLSS SHOW YOUR WORK PLSS

Answers

Answer:

d

Step-by-step explanation:

a) Which of these numbers is 8 less than -15?
7
-7
23
-23
A
B
с
D

Answers

-7 the answer is -7 yes

Answer:

-7

Step-by-step explanation:

y because i know so

help me with this and ill give you brainliest

Answers

Answer:

C

Step-by-step explanation:

Trust me on this one

The perimeter of the rectangular pool is 80 feet.The length of the pool is 10 feet more than twice of the width.Find the length and the width of the pool.Find the length and the width of the pool.

Answers

Width= 10
Length= 30

Explanation: photo

what is the area of 20 and 15

Answers

300 is your answer remember area is l•w
300 areas, length times width

BRAINEST IF YOU GET THSI RIGHT

Answers

Solution :

[tex] \sf \dfrac{6x+4}{3} = \dfrac{5x-5}{8}[/tex]

By cross multiply, we get

[tex] \sf : \implies (6x+4) \times 8 = (5x-5) \times 3[/tex]

[tex] \sf : \implies 48x+32 = 15x-15[/tex]

[tex] \sf : \implies 48x+32 - 15x + 15= 0[/tex]

[tex] \sf : \implies 33x + 47 = 0[/tex]

[tex] \sf : \implies 33x = -47[/tex]

[tex] \sf : \implies x = \dfrac{- 47}{33}[/tex]

Therefore, answer is [tex] \sf x = \dfrac{- 47}{33}[/tex]

ANSWER:

x=-47/33

EXPLANATION:

[tex]\frac{6x+4}{3} =\frac{5x-5}{8} \\\\24(\frac{6x+4}{3} =\frac{5x-5}{8})\\\\48x+32=15x-15\\\\48x+32-32=15x-15-32\\\\48x-15x=-47+15x-15x\\\\33x=-47\\\\x=-\frac{47}{33}x[/tex]

Which statement is true about the equation (see picture)
A. It has no solution.
B. It has one solution.
C. It has two solutions.
D. It has infinitely many solutions.

Answers

Simplify
2/4z + 1 = 2/4z + 1
Answer: D. Infinite solutions

Answer:

D would be your answer

Step-by-step explanation:

Simplify :)

Please answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!

Answers

Answer:

146

Step-by-step explanation:

can anyone help me please? thanks ^^

Answers

Answer:

Yes; they are congruent

SSS

Step-by-step explanation:

Here, we want to check if the given triangles are congruent

From what we have, we can see that all three sides are marked for both triangles

So the sides of the triangles are income

So therefore, the triangles are congruent by SSS

Please help me solve m<1 !!​

Answers

Step-by-step explanation:

Sum of angles in a triangle = 180°

Hence Angle 1 = 180° - 24° - 37° = 119°.

Hi I need to figure if this is a function?

Answers

Answer:

no it is not a function

Step-by-step explanation:

function- for every input there is only one output

(1,7),(2,13),(3,13) it has two 13 so it is not a function

The diagonals of rhombus ABCD intersect at E. Given that m∠CAD=20° and CE=4, find the m∠CDA.

Answers

Given :

The diagonals of rhombus ABCD intersect at E.

∠CAD = 20°.

To Find :

The angle ∠CDA.

Solution :

We know, diagonals of a rhombus bisects each other perpendicularly.

So, ∠DEA = 90°.

In triangle ΔEAD :

∠EAD + ∠AED + ∠EDA = 180°

20° + 90° + ∠EDA = 180°

∠EDA = 70°

Now, we know diagonal of rhombus also bisect the angle between two sides .

So, ∠CDA = 2∠EDA

∠CDA = 2×70°

∠CDA =140°

Therefore, ∠CDA is 140°.

Marion is twice as old as judy. Six years agot Marion was three times as old as judy was then. Find the age of each girl now.

Pls show work, I will give brainliest

Answers

9514 1404 393

Answer:

  Marion is 24, Judy is 12

Step-by-step explanation:

Let j represent Judy's age now. 6 year ago, the relation was ...

  3(j -6) = (2j) -6

  3j -18 = 2j -6 . . . . . eliminate parentheses

  j = 12 . . . . . . . . . . . add 18-2j

  2j = 24 . . . . . . . . . Marion's age now

Judy is 12; Marion is 24.

Question 12 (1 point)
If linel is parallel to line m, solve for x and name the angle relationship:
(9x - 33)
(5x + 3)

Answers

it’s b
solve :
9x - 33 = 5x + 3
-5x -5x
4x - 33 + 3
+ 3 -3
4x = 36
/4 /4 (divided by 4)

x = 9

Find the value of x round to the nearest tenth FIRST ANSWER GETS BRAINIEST

Answers

Answer: answer is 19.2

a squared + b squared = c2  

81 + 289 = 370

square root of 370 = 19.235

answer is 19.2

Answer:

Step-by-step explanation:

[tex]x = \sqrt{ {17}^{2} + {9}^{2} } = \sqrt{289 + 81} = \sqrt{370 } [/tex]=19.2

A model house has a scale of 3 cm : 6 m.
If the model house is 9 cm wide, then how
wide is the real house?

Answers

It is going to be 18 because 9/18 is going to equal 3/6. Or both of them will equal 1/2

What is the length of the line segment whose endpoints are (-1,5) and (3,-3)? Round your answer to the nearest tenth.

Answers

Answer:

4√5

Step-by-step explanation:

The length=√(3--1)²+(-3-5)²

l=√(4)²+(-8)²

l=√16+64

l=√80=4√5

three times a number, less 4 is
2

Answers

Answer:

2

Step-by-step explanation:

In ΔPQR, \overline{PR} PR is extended through point R to point S, \text{m}\angle QRS = (4x-15)^{\circ}m∠QRS=(4x−15) ∘ , \text{m}\angle RPQ = (x+1)^{\circ}m∠RPQ=(x+1) ∘ , and \text{m}\angle PQR = (x-2)^{\circ}m∠PQR=(x−2) ∘ . Find \text{m}\angle RPQ.m∠RPQ.

Answers

Answer:

Step-by-step explanation:

Notice that, the angle QRS is external to the triangle and adjacent to the angle PRQ. According to the theorem of a external/adjacent angle, we have: m∠QRS = m∠PQR + m∠RPQ, where PQR and RPQ are internal angles.

From the hypothesis, we have:

m∠QRS =(10x−12)∘(10x−12)

m∠PQR = (3x+20)∘(3x+20)

m∠RPQ=(3x−8)∘(3x−8)

Using the first equation and replacing the hypothesis:

m∠QRS = m∠PQR + m∠RPQ

(10x−12)∘(10x−12) = (3x+20)∘(3x+20) + (3x−8)∘(3x−8)

Multiplying and applying the remarkable identity:

Then, we use a calculator to find the roots, which are:

In this case, we will see what root is the right one.

Now, we replace it into m∠QRS =(10x−12)∘(10x−12), because we need to find m∠QRS.

m∠QRS =(10x−12)∘(10x−12) = (10(4.7) - 12) (10(4.7) - 12) = (35) (35) = 1225

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

if you are doing deltamath

The area of a rectangle is represented by the expression 16m - 24. Which expression shows a factored version of the Area, one that shows the length and the width.
A | 8(2m+3)
B | 8(2+3m)
C | 8(2-3m)
D | 8(2m-3)

Answers

Answer:

The espression 8(2m - 3) shows the length and the width of the rectangle ⇒ D

Step-by-step explanation:

Let us find the greatest common factor of 16 and 24

∵ 16 = 1 × 16, 2 × 8, 4 × 4

∴ The factors of 16 are 1, 2, 4, 8, 16

∵ 24 = 1 × 24, 2 × 12, 3 × 8, 4 × 6

∴ The factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24

→ Find the common factors of 16 and 24

∵ The common factor of 16 and 24 are 1, 2, 4, 8

∵ The greatest one is 8

The greatest common factor of 16 and 24 is 8

→ Take 8 as a common factor from 16m and 24

∵ 16m ÷ 8 = 2m

∵ 24 ÷ 8 = 3

∴ 16m - 24 = 8(2m - 3)

The espression 8(2m - 3) shows the length and the width of

   the rectangle

Anyone? need help ASAP will mark as brainlist

Answers

C. 154 cm

Explanation
The formula would be 1/4•pi•14squared which equals 153.93804. The rounded answer would be 154

PLEASE HELP WILL AWARD BRAINLIEST TO BEST ANSWER!!!

Answers

Answer:

See below

Step-by-step explanation:

[tex] In\: \triangle AKL, \:\\ AK = 9,\: \\m\angle K = 90\degree, \: \\m\angle A= 60\degree \\

\therefore m\angle L = 30\degree\\

By \:30°-60°-90° \:\triangle \:theorem:\\

AK = \frac{1}{2} \times AL\\(SIDE\: OPPOSITE \:TO \:30\degree) \\\\

9 = \frac{1}{2} \times AL\\\\

AL = 9\times 2\\\\

\huge\red{AL = 18}\\\\

KL = \frac{\sqrt 3}{2} \times AL\\(SIDE\: OPPOSITE \:TO \:60\degree) \\\\

KL = \frac{\sqrt 3}{2}\times 18\\\\

KL = 9\times \sqrt 3\\\\

\huge\purple{KL = 9\sqrt 3}\\\\

P(\triangle AKL) = AK + KL + AL\\

P(\triangle AKL)= 9 + 9\sqrt 3+18\\

\huge\orange{P(\triangle AKL)=(27 + 9\sqrt 3) \: units} \\\\

A(\triangle AKL) = \frac{1}{2} \times KL\times AK\\

A(\triangle AKL) = \frac{1}{2} \times 9\sqrt 3\times 9\\

A(\triangle AKL) = \frac{81\sqrt 3}{2} \\

\huge\pink{A(\triangle AKL) = 40.5\sqrt 3\: units^2} [/tex]

what expression is equivalent to 5 to the -3rd power

Answers

Answer: 1/125

Step-by-step explanation:

Flip the exponent over into a fraction if it is to the negative power. Then do the same as you usually would to find out that it is 5^3 under a fraction.

Answer:

0.008

Step-by-step explanation:

that is what the internet said

Aisha is a cyclist. She rode 3 ¾ miles in ⅓ hours. A. How fast was she going in miles per hour?

Answers

Answer:

11 1/4 miles per hour

Step-by-step explanation:

Put the mixed number in improper form to make it easier. You get 15/4 miles in 1/3 hours. You want the miles for 1 hour. So you multiply 15/4 miles by 3 to get 45/4 miles, or 11 1/4 miles per hour

please answer (NOT A MULTIPLE CHOICE ANSWER)

In ΔOPQ, \text{m}\angle O = (6x-14)^{\circ}m∠O=(6x−14) ∘ , \text{m}\angle P =(2x+16)^{\circ}m∠P=(2x+16) ∘ , and \text{m}\angle Q = (2x+8)^{\circ}m∠Q=(2x+8) ∘ . Find \text{m}\angle Q.m∠Q.

Answers

Answer:

you are incorrect it is actually 107 degrees

Step-by-step explanation:

identify the domain and range of the function input 1,3,5,7 output 8,7,6,5

Answers

Answer:

Domain = 1,3,5,7

Range = 8,7,6,5

Step-by-step explanation:

We need to identify the domain and range of the function: input 1,3,5,7 output 8,7,6,5

Domain of function:

For any function domain is set of input values.

Range of function:

For any function range is set of output values.

So, for the given function we have : input 1,3,5,7 output 8,7,6,5

Domain = 1,3,5,7 (set of input values is domain of function)

Range = 8,7,6,5 (set of output values is range of function)

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