Answer:
R = 1.699 × [tex]10^{4}[/tex]
Explanation:
given data
height H = 1.70 m
time is t = 11.1 s
to find out
radius r of Earth
solution
we get here cosθ so
cos(θ) = R ÷ (R+1.70) ................1
here θ = 360 × 11.1 ÷ (24×60×60)
θ = 0.04625
so put here value in eq 1
cos(0.04625) = R ÷ (R+1.70)
so radius R will be
0.9999 = R ÷ (R+1.70)
1.6999 + 0.999 R = R
R = 1.699 × [tex]10^{4}[/tex]
A person weighing 785 Newtons on the surface of the Earth would weigh 47 Newtons on the surface of Pluto. What is the magnitude of the gravitational acceleration on the surface of Pluto?
Answer:
3.72 N / kg .
Explanation:
The weight of the object can be calculated using the expression below
Weight = mg
Weight= 785 Newtons
M = mass
g= acceleration due to gravity on Earth is 9.8 m/s² .
So, substitute the values we have,
So on Earth . . .
785 N = m x 9.8
mass= 785/9.8
=80.1kg
We can calculate when on On Mars, as
Weight= mg
298N= 80.1 kg x g( on Mars)
Acceleration of gravity of that Mars =
298 N/ 80.1
= 3.72 N / kg .
Hence, the magnitude of the gravitational acceleration on the surface of Pluto is 3.72 N / kg .
An asteroid with a mass of 3.5x10kg is 26,000m from a second asteroid with a
mass of 3.0x1012 kg.
Calculate the gravitational force between the two asteroids.
Answer:
F₁₋₂ = 1.036*10⁻⁵ [N]
Explanation:
In order to solve this problem, we must use the law of universal gravitation, which can be defined by means of the following expression.
[tex]F_{1-2}=G*\frac{m_{1}*m_{2}}{d^{2} }[/tex]
where:
F₁₋₂ = Force among the two bodies [N]
G = Universal gravity constant = 6.67 *10⁻¹¹ [N*m²/kg²]
m₁ = mass of the first body = 3.5*10 [kg]
m₂ = mass of the second body = 3*10¹² [kg]
d = separation distance = 26000 [m]
Now replacing:
[tex]F_{1-2}=6.67*10^{-11}*\frac{3.5*10*3*10^{12} }{26000^{2} } \\F_{1-2}=1.036*10^{-5}[N][/tex]
On a horizontal surface is located
an object of mass 20 kg and it is observed that
To set it in motion, a
80 N force, whereas if the object is
in motion, only one
40 N force, to keep it at speed
constant. Determine the values of the coefficients
static and kinetic friction, respectively.
(g = 10 m / s2).
A) 0.32; 0.11
B) 0.36; 0.15
C) 0.40; 0.2
D) 0.45; 0.22
By Newton's second law, the net vertical force acting on the object is 0, so that
n - w = 0
where n = magnitude of the normal force of the surface pushing up on the object, and w = weight of the object. Hence n = w = mg = 196 N, where m = 20 kg and g = 9.80 m/s².
The force of static friction exerts up to 80 N on the object, since that's the minimum required force needed to get it moving, which means the coefficient of static friction µ is such that
80 N = µ (196 N) → µ = (80 N)/(196 N) ≈ 0.408
Moving at constant speed, there is a kinetic friction force of 40 N opposing the object's motion, so that the coefficient of kinetic friction ν is
40 N = ν (196 N) → ν = (40 N)/(196 N) ≈ 0.204
And so the closest answer is C.
(Note: µ and ν are the Greek letters mu and nu)
At highway speeds, a particular automobile is capable of an acceleration of about 1.6 m/s. At
this rate, how long does it take to accelerate from 36 m/s to 50 m/s? (8.8 s)
Proof please
Answer:
8.8s
Explanation:
Given parameters:
Acceleration = 1.6m/s²
Initial velocity = 36m/s
Final velocity = 50m/s
Unknown:
Time taken for the acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time;
Acceleration = [tex]\frac{Final velocity - initial velocity }{time taken }[/tex]
Insert the parameters and solve for time taken;
1.6 = [tex]\frac{50 - 36}{t}[/tex]
1.6t = 14
t = 8.8s
A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 4.0 m/s, skates by with the puck. After 2.80 s, the first player makes up his mind to chase his opponent. If he accelerates uniformly at 0.14 m/s2, determine each of the following:
a. How long does it take him to catch his opponent?
b. How far has he traveled in that time?
Answer:
a)[tex]t=59.817652833125294s \approx 59.8s[/tex]
b)[tex]D_1=894.01m[/tex]
Explanation:
From the question we are told that
Speed of opposing player [tex]V_2=4.0m/s[/tex]
First player chase his opponent after[tex]t=2.80t[/tex]
Acceleration of first player [tex]a=0.14 m/s2[/tex]
Let time of catch be [tex]t_c[/tex]
a)Generally the Equation for distance covered is mathematically given as follows
Distance to catch First opponent
[tex]D_1=\frac{1}{2}(0.14)t^2[/tex]
[tex]D_1=0.07t^2[/tex]
Distance to covered Second opponent
[tex]D_2=(2.8+t)*4[/tex]
Generally when first opponent catch the second opponent it is represented mathematically as
[tex]D_2=D_1[/tex]
[tex]0.07t^2=(2.8+t)*4[/tex]
[tex]0.07t^2=11.2+4t[/tex]
[tex]0.07t^2-4t-11.2[/tex]
[tex]t=59.817652833125294s \approx 59.8s[/tex]
b)Generally the the total time traveled by the first opponent is mathematically given as
[tex]D_1=\frac{t^2}{4}[/tex]
[tex]D_1=\frac{59.8^2}{4}[/tex]
[tex]D_1=894.01m[/tex]
The total amount of force exerted on an object is called
Balanced
Unbalanced
Force
Net Force
Answer:
net force
Explanation:
net force is the total amount of force exerted on an object.
In downtown Chicago, the east-west blocks are 400 ft long while the north-south blocks are 280 ft long. Because of the many one-way streets, it can be challenging to get around. Veronica starts at the corner of Dearborn and Ohio Streets. She drives four blocks north to Superior, two blocks east to Wabash, then a block south to get to her destination at Wabash and Huron.
Required:
What is the straight-line distance from her starting point?
Answer:
The answer is "1160 ft".
Explanation:
Using the Pythagoras theorem:
[tex]\to a= 280 \times 3= 840\\\\\to b= 400 \times 2= 800\\\\[/tex]
[tex]\bold{\to y^2= a^2+b^2}\\\\[/tex]
[tex]=840^2 +800^2\\\\= 705600+640000\\\\=1345600\\\\=1160 \ ft\\[/tex]
[tex]\to y=1160 \ ft[/tex]
importance of choke coil?
Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.
Explanation:
Which of the following is a pure substance?
Two cars, initially at rest and 5 km apart at t=0 , simultaneously move toward each other. Car A travels at a constant speed of 55 km/hour, while car B travels at a constant speed of 12 km/hour. How long will it take care from t=0 for car A to meet car B?
Select one:
a. 24.5 s
b. 490 s
c. 245 s
d. 268 s
e. None of the above.
Answer:
d. 268 s
Explanation:
Constant Speed Motion
An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.
Expressed in a simple equation, we have:
[tex]\displaystyle v=\frac{d}{t}[/tex]
Where
v = Speed of the object
d = Distance traveled
t = Time taken to travel d.
From the equation above, we can solve for d:
d = v . t
And we can also solve it for t:
[tex]\displaystyle t=\frac{d}{v}[/tex]
Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.
The time it will take for them to meet is:
[tex]\displaystyle t=\frac{5}{67}[/tex]
t = 0.0746 hours
Converting to seconds: 0.0746*3600 = 268.56
The closest answer is d. 268 s
Explaining How Temperature
Does sound travel faster in a warm room or a cold room?
Explain your answer.
Intro
Do
Answer:
Explanation:
Sample Response: Sound travels faster in a warm room because temperature affects the speed of a wave. In a warm room, the particles of air move faster and have higher chances of bumping into each other, which then increases the instances of energy transfer.
Which heat related illness requires immediate medical attention
Answer:
Heat stroke
Explanation:
Heat Stroke is the most serious heat-related illness and requires immediate medical attention.
Answer:
Heat Stroke is the most serious heat-related illness and requires immediate medical attention. Symptoms include: confusion, fainting, seizures, very high body temperature and hot, dry skin or profuse sweating. CALL 911 if a coworker shows signs of heat stroke.
Explanation:
I HOPE THIS HELPS * pls mark me brainliest }
A toy car rolls down a straight inclined track and its speed increases steadily. At the moment when the car reaches the flat surface at the base of the track, its speed remains constant. Which statement best explains why the speed of the car remains the same when it reaches the flat surface
Answer:
Due to same gravity.
Explanation:
The speed of the car remains the same when it reaches on the flat surface because the gravity is same at every step of flat surface while on the other hand, the speed of car speed increases steadily on the inclined plane due to gravity of the earth. So we can say that speed of the car remains the same on the flat surface due to same gravitational force.
Chirag, a champion weightlifter, raises 259 kg of weights a distance of 2.40 m. How much work is done by Brutus lifting the weights?
622 J
6090 J
2540 J
0 J
How much work is done by Chirag holding the weights above his head?
622 J
6090 J
2540 J
0 J
1.
6090 J
2.
622 J
I bet so~
A tire spinning at 5m/s uniformly accelerates to 10 m/s in five seconds. Its radius is 10 cm. Through what angle will pebble stuck in the tire revolve during this interval?
20 cm and 9 cm 30 cm is the distance for 5 mins so it will be 20 cm
pls explain why
two cars start a trip of 200 km at the same time. the first car travels at 90 km/h and the second at 110 km/h. how much more time in minutes does it take for the slower car to reach its destination?
Answer:
5
Explanation:
give thanks pls
what is mechanics physics
1) Should I take vitamin D supplements in the winter?
A prospector finds himself holding his bag of gold and standing in the middle of a large pond of frictionless ice. Use the Law of Conservation of Momentum to explain how he can get to the side before he freezes
Answer:
Explanation:
He can not walk on the ice because ice is frictionless . But he can move to shore or side using law of conservation of momentum . He will throw the bag of gold towards the side opposite to shore . This will create a motion in himself in opposite direction according to law of conservation of momentum.
Let m and M be mass of bag and prospector , v and V be velocity created in bag and prospector after throw of bag . Initially , both bag and prospector were at rest so initial momentum = 0 . Final momentum of both = mv - MV .
negative sign is due to their opposite motion .
According to law of conservation of momentum
MV - mv = 0
MV = mv
In this way he can create motion in himself to move to side .
What happens to the molecules of a substance when it changes phase?
When it comes to phase shifts or phase change the greater the intermolecular interactions are the closer the molecules are to one another.
What is phase change?A phase change occurs when matter transitions from one state to another (solid, liquid, gas, plasma). When enough energy is provided to the system (or when a significant quantity is removed), as well as when the pressure on the system is adjusted, these changes occur.Any two phases of matter can undergo phase transitions.All phase shifts are accompanied by an energy shift.Isothermal phase shifts occur in all cases.Temperature changes can cause substances to change phase often. Most substances are solid at low temperatures; as the temperature rises, they become liquid; and at even higher temperatures, they become gaseous.To Know more about Phase change here
https://brainly.com/question/14327191
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Which is an example of current electricity?
Determine the torque caused by the cable pulling horizontally on the inclined drawbridge. The force the cable exerts on the bridge is 5000N and the bridge length is 8 m.
Answer:
[tex]\tau=20000\ Nm[/tex]
Explanation:
Given that,
The force the cable exerts on the bridge is 5000N
The length of the bridge is 8 m
We need to find the torque caused by the cable pulling horizontally on the inclined draw bridge. The torque acting on it is given by :
[tex]\tau=Fr[/tex]
Putting all the values,
[tex]\tau=5000\ N\times 8\ m\\\\=20000\ Nm[/tex]
So, the required torque is 20000 Nm.
The moment of inertia of a lever is 50 kg m^2 with a mass of 2 kg. What is the
radius?
Answer:
huh
Explanation:
3.7. A dog searching for a bone walks 3.50 m south, then 8.20 m at an angle 23.1 degrees north of east, and finally 15.0 m west. (a) What is the magnitude of the dog’s total displacement? (b) What is the direction of the dog’s total displacement where directly east is taken as zero degrees and counter-clockwise is positive?
Answer:
Explanation:
We shall represent displacement of dog in vector form , in terms of i , j , i representing east and j representing north .
Dog travels 3.5 m south .
Displacement D₁ = - 3.5 j
then dog travels 8.2 m , 23.1 degree north of east
Displacement D₂ = 8.2 cos23.1 i + 8.2 sin23 j
D₂ = 8.2 cos23.1 i + 8.2 sin23.1 j
= 7.54 i + 3.22 j
Third displacement
D₃ = - 15i
Total displacement = D₁ + D₂ + D₃
= - 3.5 j + 7.54 i + 3.22 j -15i
= - 7.46 i - 0.28 j
Magnitude of displacement = √ ( 7.46² + .28²)
= √(55.65 + .08 )
= 7.46 m
b ) Direction of displacement
If Ф be angle , displacement makes with west direction
TanФ = .08 / 55.65 = .00143
Ф = .082 degree south of west or almost west .
From east , this angle = 180 + .082 = 180.082 , counterclockwise .
PLEASE HELP!!!! What are 3 ways that machines can make doing work easier? (thats the whole question)
Answer:
Machines reduce the time of work hence reducing the rate of doing work ( power ).
Machines e.g pulleys carry heavy loads with a less and reasonable effort.
Machines e.g generators induce current in a limited amount of time
Answer:
they can do work easier for an example a car a car make things easier by going some were far it can also be used to help people travel instead of a plane it can also be used for carriying things like a boat. (you can put it in a diffrent way)
Explanation:
hope it helps! :)
In part C of the lab, when two wires are in parallel, so that the current flows in the same direction inside them, the directions of the magnetic fields in the region between the two wires are
Answer:
the magnetic field between the two wires is zero
Explanation:
given wire the magnetic field is circular with the direction given by the fingers of the right hand.
As the two wires have the same direction of the current, the fields are circular rotating in an anticlockwise direction, therefore in the region between the two wires each field has the opposite direction of movement and they cancel out.
In summary the magnetic field between the two wires is zero
A 2000-kg car moving with a speed of 20 m/s collides with and sticks to a 1500-kg car at rest at a stop sign. Show that because momentum is conserved in the rest frame, momentum is also conserved in a reference frame moving with a speed of 10 m/s in the direction of the moving car.
Answer:
13.33m/s
Explanation:
Given data
m1= 2000kg
u1= 20m/s
m2= 1500kg
u2= 0m/s
v1= 10m/s
Required
The speed of the sticks
We know that from the expression for the conservation of momentum
m1u1+m2u2= m1v1+m2v2
2000*20+1500*0=2000*10+1500*v2
40000=20000+1500v2
collect like terms
40000-20000= 1500v2
20000= 1500v2
v2= 20000/1500
v2= 13.33 m/s
Hence the velocity of the sticks is 13.33m/s
When you mix two substances, the heat gained by one substance is equalto the heat lost by the other substance. Suppose you place 125 g of aluminum ina calorimeter with 1,000 g of water. The water changes temperature by 2 °C andthe aluminum changes temperature by â74.95 °C.
Required:
a. Water has a known specific heat capacity of 4.184 J/g °C. Usethe specific heat equation to find out how much heat energy the watergained (q).
b. Assume that the heat energy gained by the water is equal to the heat energy lost by the aluminum. Use the specific heat equation to solve for the specific heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)
Answer:
A) 8,368 J
B) 0.893 J/gºC
Explanation:
A)
The heat gained by the water can be obtained solving the following equation:[tex]q_{g} = c_{w} * m * \Delta T (1)[/tex]
where cw = specific heat of water = 4.184 J/gºCm= mass of water = 1,000 gΔT = 2ºC Replacing these values in (1) we get:[tex]q_{g} = c_{w} * m * \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)[/tex]
B)
Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative: -8,368 J.Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:[tex]q_{l} = c_{Al} * m_{Al} * \Delta T (3)[/tex]
⇒ [tex]-8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)[/tex]
[tex]c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)[/tex]
Answer:
A: the heat gained is 8368 J (8.368 KJ)
B: 0.893 J/g°C
Explanation:
A:
q = ?
m = 1000 g
C = 4.184 J/g°C
△T = 2°C
q = mc△T
q = (1000g) (4.184 J/g °C) (2 °C)
q = 8368 J
B:
q = mc△T
---------------
△T △T
c = q / m△T
c = - 8368 J / (125 g) (-74.95 °C)
c = 0.893 J/g°C
I need an expert in physics for help
A child pulls a wagon at a constant velocity of 4.0 m/s for 4.0 minutes along a level sidewalk. The child does this applying a 22 N force to the wagon handle, which is inclined at 35 ° to the sidewalk as shown below. How much work does the child do on the wagon ?
288 k J
8.7 kJ
17.3 kJ
2.3 kJ
Answer:
288kj
Explanation:
