Answer:
No.
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible. You could have 100°+100°+100°+60° quadrilateral or whatever. As long as it's inner angles add up to 360°, it is possible.
Answer:
[tex]\boxed{\mathrm{It \: is \: not \: an \: empty \: set}}[/tex]
Step-by-step explanation:
A quadrilateral with 3 obtuse angles is possible.
A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.
Let’s say three angles are measuring 91 degrees in a quadrilateral.
91 + 91 + 91 + x = 360
x = 87
The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.
please help and please show your work
Answer:
The volume of all 9 spheres is 301.6 [tex]in^3[/tex]
Step-by-step explanation:
Notice that three of the identical spheres fit perfectly along the 12 in side box, therefore we know that the diameter of each is 12 in/3 = 4 in.
Then the radius of each sphere must be 2 inches (half of the diameter). Now that we know the radius of each sphere, we use the formula for the volume of a sphere to find it:
[tex]V=\frac{4}{3} \pi R^3\\V=\frac{4}{3} \pi (2\,in)^3\\V=\frac{4}{3} \pi\, 8\,\,in^3\\V=\frac{32}{3} \pi\,\,in^3[/tex]
Now, the total volume of all nine spheres is the product of 9 times the volume we just found:
[tex]V_{all \,9}=9\,*\frac{32}{3} \pi\,\,in^3\\V_{all \,9}=96 \pi\,\,in^3\\V_{all \,9}\approx \,301.6\,\,in^3[/tex]
Write the given differential equation in the formL(y) = g(x),where L is a linear differential operator with constant coefficients. If possible, factor L. (Use D for the differential operator.)y'' − 3y' − 28y = x − 2
Answer:
L(y) = g(x)
[tex]y = C_{1} e^{-4 x} + C_{2} e^{7 x} + \frac{1}{(-28)}(( x + (\frac{ -3 (1) }{28} )) + \frac{1}{14}[/tex]
Step-by-step explanation:
Step(i):-
Given differential equation
y'' − 3 y' − 28 y = x − 2
Operator form ( D² - 3 D - 28 )y = x -2
f( D ) y = Ф(x)
Auxiliary equation
f( m ) = m² - 3 m - 28
⇒ m² - 3 m - 28 =0
⇒ m² - 7 m +4 m - 28 =0
⇒ m ( m -7 ) + 4 ( m -7) =0
⇒ (m + 4)( m -7) =0
⇒ m = -4 and m =7
Complementary function
[tex]y_{c} = C_{1} e^{-4 x} + C_{2} e^{7 x}[/tex]
Step(ii):-
Particular integral
[tex]P.I = y_{p} = \frac{1}{f(D)} (x-2)[/tex]
[tex]= \frac{1}{D^{2}- 3 D - 28 } (x)-2\frac{1}{D^{2} - 3 D - 28} e^{0 x} )[/tex]
[tex]= \frac{1}{(-28)(1 - (\frac{D^{2}-3 D) }{-28} )} (x) + \frac{1}{0-0-28} X 2[/tex]
[tex]= \frac{1}{(-28)}( 1 + (\frac{D^{2} -3 D) }{28} )^{-1} (x) + \frac{1}{14}[/tex]
( 1 + x )⁻¹ = 1 - x + x² - x³ +.....
we use notation [tex]D = \frac{dy}{dx}[/tex]
[tex]= \frac{1}{(-28)}( 1 + (\frac{D^{2} -3 D) }{28} )+ (\frac{D^{2} -3 D) }{28})^{2} +.....) (x) + \frac{1}{14}[/tex]
Higher degree terms will be neglected
D(x) =1
D²(x) =0
[tex]= \frac{1}{(-28)}(( x + (\frac{ -3 (1) }{28} )) + \frac{1}{14}[/tex]
The particular integral
[tex]y_{p} = \frac{1}{(-28)}(( x + (\frac{ -3 (1) }{28} )) + \frac{1}{14}[/tex]
Conclusion:-
General solution of given differential equation
[tex]y = y_{c} + y_{p}[/tex]
[tex]y = C_{1} e^{-4 x} + C_{2} e^{7 x} + \frac{1}{(-28)}(( x + (\frac{ -3 (1) }{28} )) + \frac{1}{14}[/tex]
Let X have a binomial distribution with parametersn = 25and p. Calculate each of the following probabilities using the normal approximation (with the continuity correction) for the casesp = 0.5, 0.6, and 0.8and compare to the exact binomial probabilities calculated directly from the formula forb(x; n, p).(Round your answers to four decimal places.)(a)P(15 ≤ X ≤ 20)
Answer:
The answer is explained below
Step-by-step explanation:
We have the following formulas:
from binomial distibution: P (X = x) = (nCx) * (p) x * (1-p) n-x
from normal distribution: P (X <= x) = (x-np) / sqrT (np (1-p))
Now, n = 25 and p (0.5, 0.6, 0.8), we replace in the formulas and we are left with the following table:
P P(15<=X<=20) P(14.5<=X<=20.5)
0.5 0.2117 is less than 0.2112
0.6 0.5763 is less than 0.5685
0.8 0.5738 is greater than 0.5957
The calculation of each of the probabilities should be shown below.
Calculation of probabilitiesFollowing formulas should be used
from binomial distibution: P (X = x) = [tex](nCx) \times (p) x \times (1-p) n-x[/tex]
from normal distribution: P (X <= x) =[tex](x-np) \div \sqrt T (np (1-p))[/tex]
Since, n = 25 and p (0.5, 0.6, 0.8),
So, the probabilities are:
P P(15<=X<=20) P(14.5<=X<=20.5)
0.5 0.2117 is less than 0.2112
0.6 0.5763 is less than 0.5685
0.8 0.5738 is greater than 0.5957
learn more about probability here: https://brainly.com/question/15944614
A study conducted at a certain college shows that "53%" of the school's graduates find a job in their chosen field within a year after graduation. Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating. 0.989 0.978 0.927 0.167 0.530
Answer:
0.989
Step-by-step explanation:
For each graduate, there are only two possible outcomes. Either they find a job in their chosen field within a year after graduation, or they do not. The probability of a graduate finding a job is independent of other graduates. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
A study conducted at a certain college shows that "53%" of the school's graduates find a job in their chosen field within a year after graduation.
This means that [tex]p = 0.53[/tex]
6 randomly selected graduates
This means that [tex]n = 6[/tex]
Probability that at least one finds a job in his or her chosen field within a year of graduating:
Either none find a job, or at least one does. The sum of the probabilities of these outcomes is 1. So
[tex]P(X = 0) + P(X \geq 1) = 1[/tex]
We want [tex]P(X \geq 1)[/tex]
So
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{6,0}.(0.53)^{0}.(0.47)^{6} = 0.011[/tex]
So
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.011 = 0.989[/tex]
In 2010, there were 32 million people over 65 years of age out of a population of 307 million. By 2050, it is estimated that there will be 88 million people over 65 years of age out of a population of 434 million. Would your chances of meeting a person over 65 at random be greater in 2010 or 2050? Explain.
Answer:
2050
Step-by-step explanation:
Year 2010
The number of people over 65 years of age =32 million
Total population = 307 million.
P(meeting a person over 65 at random in 2010)
[tex]=\dfrac{32 \text{ million}}{307\text{ million}} \\\\=0.1042[/tex]
Year 2050
The number of people over 65 years of age =88 million
Total population = 434 million.
P(meeting a person over 65 at random in 2050)
[tex]=\dfrac{88\text{ million}}{434\text{ million}} \\\\=0.2028[/tex]
Conclusion: Since 0.2028 is greater than 0.1042, the chances of meeting a person over 65 at random will be greater in 2050
Bryson hopes to win a three-day vacation in a drawing that is being held at his office. He purchased 40 raffle tickets. There were 500 raffle tickets sold. What is the theoretical probability of Bryson winning the trip?
Answer:
The probability would be 40 / 500 = 0.08.
Any help would be appreciated
Let I (x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements. (a) Jerry does not have an Internet connection. (b) Rachel has not chatted over the Internet with Chelsea. (c) Jan and Sharon have never chatted over the Internet. (d) No one in the class has chatted with Bob. (e) Sanjay has chatted with everyone except Joseph. (f) Someone in your class does not have an Internet connection. (g) Not everyone in your class has an Internet connection. (h) Exactly one student in your class has an Internet connection. (i) Everyone except one student in your class has an Internet connection. (j) Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class. (k) Someone in your class has an Internet connection but has not chatted with anyone else in your class. (l) There are two students in your class who have not chatted with each other over the Internet. (m) There is a student in your class who has chatted with everyone in your class over the Internet. (n) There are at least two students in your class who have not chatted with the same person in your class. (o) There are two students in the class who between them have chatted with everyone else in the class
Answer:
Step-by-step explanation:
L(x) means that Student X has an internet connection
C(x,y) means that students X and Y have chatted over the internet
The domain for variables X and Y comprise all students in your class. We now use quantifiers or algebraic functions to express each of the statements:
(A) Jerry does not have an internet connection
L(x) = 0
Where X represents Jerry
(B) Rachel has not chatted over the internet with Chelsea
C(x,y) = 0
Where X and Y represent Rachel and Chelsea
(C) Jan and Sharon have never chatted over the internet
L(x) + L(y) = 0
Where X and Y represent Jan and Sharon. If they have NEVER chatted over (the question didn't say they have never "with each other", it says they have never chatted at all) the internet, then they've probably never had an internet connection!
(D) No one in the class has chatted with Bob
Let Y represent Bob and X1, X2, ..., Xn represent everyone else in the class.
The value of Y is not significant here (because it is raised to the power of zero and that makes it equal to 1 and when 1 is multiplied by any X value, the X value or student remains the same) but we have to put it, to represent Bob.
The quantifier here is C (X1Y°, X2Y°, X3Y°, ..., XnY°)
Use the given probability value to determine whether the sample results could easily occur by chance, then form a conclusion. A study of the effect of seatbelt use in head-on passenger car collisions found that drivers using a seatbelt had a 64.1% survival rate, while drivers not using a seatbelt had a 41.5% survival rate. If seatbelts have no effect on survival rate, there is less than a 0.0001 chance of getting these results. What do you conclude?
Answer:
As the P-value is very low, we can conclude that there is enough evidence to support the claim that the survival rate is significantly higher when the seatbelt is used.
Step-by-step explanation:
We have a hypothesis test that compares the survival rate using the seatbelt versus the survival rate not using it.
The claim is that the survival rate (proportion) is significantly higher when the seatbelt is used.
Then, the null hypothesis is that the seatbelts have no effect (both survival rates are not significantly different).
The P-value is the probabilty of the sample we have, given that the null hypothesis is true. In this case, this value is 0.0001.
This is very low, what gives enough evidence to claim that the survival rate is significantly higher when the seatbelt is used.
When f=2 and g=8,n=4. if n varies jointly with f and g, what is the constant of variation ?
1/4
1/2
4
64
Answer:
[tex](A) \dfrac{1}{4}[/tex]
Step-by-step explanation:
If n varies jointly with f and g, we write:
[tex]n \prop fg\\$Introducing the constant of variation, k$\\n=kfg\\When f=2, g=8 and n=4\\4=k \times 8 \times 2\\4=16k\\$Divide both sides by 16\\k = 4\div 16\\k=\dfrac{1}{4} \\\\$The constant of variation is \dfrac{1}{4}[/tex]
The correct option is A.
The constant of variation = 1/4 , Option A is the correct answer.
What is Constant of variation ?The ratio between two variables in a direct variation or the product of two variables in an inverse variation.
In the direct variation equations = k and y = kx,
and the inverse variation equations xy = k and y = , k is the constant of variation.
if n varies jointly with f and g
n ∝ fg
n = kfg
f=2
g=8
n=4
The constant of variation will be
4 = k *2*8
k= 1/4
Therefore Option A is the correct answer.
To know more about Constant of Variation
https://brainly.com/question/11928182
#SPJ5
what is the sum of the 3rd and 5th square numbers????
Answer:
40
Step-by-step explanation:
as 1st sq no is.4 and 2nd sq no. is 36
and their sum is =4+36
=40.....ans
4) What is the present value of $4000 received at the
end of the year for the next 3 years, with a discount
rate of 8%?
Answer:
$11040
Step-by-step explanation:
first of all the question says that $4000 were earned in a year and asks for what the new vale would be after the next 3 years with a discount rate of 8%.
If 1 year=$4000,then 3 years=$12000
100%-8%=92% (this happens because there is still a remaining amount that still has a cost to it),so 12000*92%=$11040
Answer: The answer is 33333.33
Step-by-step explanation:
Find the value of x and the value of y.
A r= 15, y = 10/3
B. r=20, p=10/3
C. x=20/3, y = 513
D. r=15, y =53
Answer:
Step by step solution:
The height of a triangle is 6 times its base. The area of the triangle is 192 square
centimeters. Find the base and the height of the triangle.
Base
Height
Answer:
base: 8 cm
height: 48cm
Step-by-step explanation:
Let the base of the triangle = b.
You know that the formula for the area of a triangle is 1/2(b)(h), where b is the base and h is the height. So just substitute:
1/2(b)(h) = 192 replace the height with 6b, because it is 6 times the base
1/2(b)(6b) = 192
1/2(6b^2) = 192 multiply both sides by 2 to remove the 1/2
6b^2 = 384 now divide both sides by 6 to remove the 6
b^2 = 64
b = 8
6(8) = 48 = height
If Rob had average monthly expenses of $940.21 and his expenses in April were $945.50 and his expenses in May were $875.13, what were his expenses in June?
Answer:
$1000
Step-by-step explanation:
If we assume that the given average applies to April, May, and June expenses, then we can use the formula for average to find June's expenses.
average expenses = (April +May +June)/3
940.21 = (945.50 +875.13 +June)/3
(3)(940.21) = 1820.63 +June
2820.63 -1820.63 = June = 1000.00
Rob's expenses in June were $1000.00.
The personnel department of a large corporation wants to estimate the family dental expenses of its employees to determine the feasibility of providing a dental insurance plan. A random sample of 12 employees reveals the following family dental expenses (in dollars). See Attached Excel for Data. Construct a 97% confidence interval estimate for the average family dental expenses for all employees of this corporation.
The data cited is in the attachment.
Answer: 308.2±106.4
Step-by-step explanation: To construct a confidence interval, first calculate mean (μ) and standard deviation (s) for the sample:
μ = Σvalue/n
μ = 308.2
s = √∑(x - μ)²/n-1
s = 147.9
Calculate standard error of the mean:
[tex]s_{x} = \frac{s}{\sqrt{n} }[/tex]
[tex]s_{x}[/tex] = [tex]\frac{147.9}{\sqrt{12} }[/tex]
[tex]s_{x}[/tex] = 42.72
Find the degrees of freedom:
d.f. = n - 1
d.f. = 12 - 1
d.f. = 11
Find the significance level:
[tex]\frac{1-0.97}{2}[/tex] = 0.015
Since sample is smaller than 30, use t-test table and find t-score:
[tex]t_{11,0.015}[/tex] = 2.4907
E = t-score.[tex]s_{x}[/tex]
E = 2.4907.42.72
E = 106.4
The interval of confidence is: 308.2±106.4, which means that dental insurance plan varies from $201.8 to $414.6.
At a department store, Kendra has a debt greater than $25.00. Which could be Kendra’s balance? A.Negative 32 dollars B.Negative 22 dollars C.Negative 19 dollars D.Negative 11 dollars
Answer:
A. Negative 32 dollars
Step-by-step explanation:
Kendra has a debt. Doubt means that the balance is Negative.
If the debt is greater than 25 USD . Kendra's debt has to be more negative than 25 . Amoung all other numbers only debt 32 is more negative than 25.
Answer:
I think it would be 32
Step-by-step explanation:
So she can pay the debt off
In a recent study on world happiness, participants were asked to evaluate their current lives on a scale from 0 to 10, where 0 represents the worst possible life and 10 represents the best possible life. The mean response was 5.6 with a standard deviation of 2.6. (a) What response represents the 85th percentile? (b) What response represents the 62nd percentile? (c) What response represents the first quartile?
Answer:
a) 8.2962
b) 6.3956
c) 3.845
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 5.6, \sigma = 2.6[/tex]
(a) What response represents the 85th percentile?
This is X when Z has a pvalue of 0.85. So X when Z = 1.037.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.037 = \frac{X - 5.6}{2.6}[/tex]
[tex]X - 5.6 = 2.6*1.037[/tex]
[tex]X = 8.2962[/tex]
(b) What response represents the 62nd percentile?
This is X when Z has a pvalue of 0.62. So X when Z = 0.306.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.306 = \frac{X - 5.6}{2.6}[/tex]
[tex]X - 5.6 = 2.6*0.306[/tex]
[tex]X = 6.3956[/tex]
(c) What response represents the first quartile?
The first quartile is the 100/4 = 25th percentile. So this is X when Z has a pvalue of 0.25, so X when Z = -0.675.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.675 = \frac{X - 5.6}{2.6}[/tex]
[tex]X - 5.6 = 2.6*(-0.675)[/tex]
[tex]X = 3.845[/tex]
P(x)=3x² + 4x³-8+x⁴-7x Degree; Type; Leading coefficent;
Answer:
Degree: 4; Type: quartic; Leading coefficient: 1
Step-by-step explanation:
An experiment is designed to test whether operator A or operator B gets the job of operating a new machine. Each operator is timed on 75 independent trials involving the performance of a certain task on the machine. If the sample means for the 75 trials differ by more than 5 seconds, the operator with the smaller mean gets the job. Otherwise, the experiment is considered to end in a tie. Suppose the standard deviations of times for both operators are assumed to be 2 seconds. What is the probability that operator A gets the job even though both operators have equal ability
Answer:
The probability that operator A gets the job even though both operators have equal ability is 0.0001.
Step-by-step explanation:
We are given that an experiment is designed to test whether operator A or operator B gets the job of operating a new machine. If the sample means for the 75 trials differ by more than 5 seconds, the operator with the smaller mean gets the job.
Suppose the standard deviations of times for both operators are assumed to be 2 seconds.
The z score probability distribution for the two-sample normal distribution is given by;
Z = [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1}+\frac{\sigma_2^{2} }{n_2} } }[/tex] ~ N(0,1)
where, [tex]\bar X_1[/tex] = sample mean for operator A
[tex]\bar X_2[/tex] = sample mean for operator B
[tex]\sigma_1[/tex] = standard deviations of times for operator A = 2 seconds
[tex]\sigma_2[/tex] = standard deviations of times for operator B = 2 seconds
[tex]n_1=n_2[/tex] = sample of independent trials for both operators = 75
Now, the probability that operator A gets the job even though both operators have equal ability is given by = P([tex]\bar X_1 -\bar X_2[/tex] > 5 seconds)
P([tex]\bar X_1 -\bar X_2[/tex] > 5 sec) = P( [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1}+\frac{\sigma_2^{2} }{n_2} } }[/tex] > [tex]\frac{5-0}{\sqrt{\frac{2^{2} }{75}+\frac{2^{2} }{75} } }[/tex] )
= P(Z > 15.31) = 1 - P(Z [tex]\leq[/tex] 15.31)
= 1 - 0.9999 = 0.0001
As in the z table, the highest critical value for x is given for x = 4.40 so we will take this value's probability area for x = 15.31.
(−p 2 +4p−3)(p 2 +2)
Answer:
[tex]-p^4+4p^3-5p^2+8p-6[/tex]
I hope this help you :)
Find the equation of the line passing through the points 3, 3 and 4, 5
Answer:
[tex]y=2x-3[/tex]
Step-by-step explanation:
The equation of a line is:
[tex]y = mx+b[/tex]
m is the slopeb is the y-intercept[tex]m=\frac{5-3}{4-3}[/tex]
[tex]m=\frac{2}{1}[/tex]
[tex]m=2[/tex]
[tex]y=2x+b[/tex]
[tex](3, \: 3)[/tex]
[tex]y=mx+b[/tex]
[tex]3=2 \times 3+b[/tex]
[tex]b=3-(2)(3)[/tex]
[tex]b=-3[/tex]
[tex]y=2x+-3[/tex]
Answer:
y - 3 = 2(x - 3)
Step-by-step explanation:
Please use parentheses to indicate points: the points 3, 3 and 4, 5 should be written as (3, 3) and (4, 5).
As we move from the first point to the second, x increases by 1 and y increases by 2. Thus, the slope of the line connecting these two points is m = rise / run = 2 / 1 = m = 2
Using the point-slope formula y - k = m(x - h), we obtain:
y - 3 = 2(x - 3)
The heights of 10 year old children has a normal probability distribution with mean of 54.6 inches and standard deviation of 5.7 inches. What is the approximate probability that a randomly selected 10-year old child will be more than 51.75 inches tall? Group of answer choices 0.69 0.31 0.62 0.67 0.93
Answer:
a) 0.69
The probability that a randomly selected 10-year old child will be more than 51.75 inches tall
P(X>51.75 ) = 0.6915
Step-by-step explanation:
Step(i):-
Given mean of the Population = 54.6 inches
Given standard deviation of the Population = 5.7 inches
Let 'X' be the random variable of normal distribution
Let 'X' = 51.75 inches
[tex]Z = \frac{x-mean}{S.D} = \frac{51.75-54.6}{5.7} = -0.5[/tex]
Step(ii):-
The probability that a randomly selected 10-year old child will be more than 51.75 inches tall
P(X>51.75 ) = P(Z>-0.5)
= 1 - P( Z < -0.5)
= 1 - (0.5 - A(-0.5))
= 1 -0.5 + A(-0.5)
= 0.5 + A(0.5) (∵A(-0.5)= A(0.5)
= 0.5 +0.1915
= 0.6915
Conclusion:-
The probability that a randomly selected 10-year old child will be more than 51.75 inches tall
P(X>51.75 ) = 0.6915
What is the equation of the line through (1,6) and (0,2)
Answer:
y=4x+2
Step-by-step explanation:
To find the slope of a line, you would do y₂-y₁/x₂x₁
This would be 2-6/0-1...
So your answer would be -4/-1
After simplifying, your slope is 4.
To write this in slope-intercept form, that would be y=4x+2
1. John is 10 cm taller than Peter. Peter is h cm tall.Which of these is John's height? A)10h B) 10 ⎼ h C) h ⎼10 D)h+10 2. Savitri has a sum of Rs x. She spent Rs1000 on grocery, Rs500 on clothes and Rs400 on education and received Rs200 as a gift. How much money (in Rs) is left with her? A) x–1700 B) x–1900 C) x+ 200 D) x–2100. 3. Monais 'x' years old. Her father's age is 6 years more than 3 times Mona's age. Which one of these gives her father's age? A) (6x+ 3) years B) (3x+ 6) years C) (3x+ 6x) years D) (x+ 3+6) years
Answer:
D
Step-by-step explanation:
because he is 10cm taller than h cm so
John h=10+h
Expand 2x(5x-2)
Help please ?
Answer: 10x^2 - 4x
Step-by-step explanation:
To expand, you are not simplifying, so multiplying out is the answer here. To do this, use the distributive property. The distributive property in this case means that if you are multiplying one number by a whole expression inside parenthesis, multiply the one number by each term in the expression:
2x(5x - 2)
= 2x(5x) + 2x(-2)
= 10x^2 - 4x
The product of the expression is equivalent to -
10x² - 4x.
What is expression?In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine order of operations and other aspects of logical syntax.Given is the expression as follows -
2x(5x - 2)
The given expression is -
2x(5x - 2)
10x² - 4x
Therefore, the product of the expression is equivalent to -
10x² - 4x.
To solve more questions on expression evaluation, visit the link below -
brainly.com/question/1041084
#SPJ5
Solve for x. whats the solutions from least to greatest. 4x^2 + 48x + 128 = 0
Answer:
[tex]\boxed{\sf \ \ \ x = -8 \ or \ x = -4 \ \ \ }[/tex]
Step-by-step explanation:
Hello,
[tex]4x^2+48x+128=0\\<=> 4(x^2+12x+32)=0\\<=> x^2+12x+32=0\\<=> (x+6)^2 - 36 + 32= 0\\\\<=> (x+6)^2-4=0\\<=> (x+6+2)(x+6-2)=0\\<=> (x+8)(x+4) = 0\\<=> x = -8 \ or \ x = -4[/tex]
vouch, i confirm that -8, -4 are the answers
Estimate the quotient by rounding the expression to relate to a one-digit fact. Explain your thinking in the space below. a. 432 ÷ 73 ___________ b. 1,275 ÷ 588 ___________
Answer:
5 remainder 50 and 2 remainder 100
Step-by-step explanation:
432 /73
432=400
73=70
70/400 = 005 Remainder 50
1275=1300
588=600
1300/600=2 remainder 100
Estimations are used to get the approximated value of an expression.
The estimate of 432 ÷ 73 is 5.714The estimate of 1,275 ÷ 588 is 1.667[tex]\mathbf{(a)\ 432 \div 73}[/tex]
Round up to 1 digit
[tex]\mathbf{432 \div 73 \approx 400 \div 70}[/tex]
Divide
[tex]\mathbf{432 \div 73 \approx 5.714}[/tex]
Hence, the estimate of 432 ÷ 73 is 5.714
[tex]\mathbf{(b)\ 1275 \div 588}[/tex]
Round up to 1 digit
[tex]\mathbf{ 1275 \div 588 \approx 1000 \div 600}[/tex]
Divide
[tex]\mathbf{ 1275 \div 588 \approx 1.667}[/tex]
Hence, the estimate of 1,275 ÷ 588 is 1.667
Read more about estimates at:
https://brainly.com/question/24586443
4 - (-5) + 04−(−5)+0
Answer:
18
Step-by-step explanation:
4 - (-5) + 04 - (- 5)+0
Negative times negative cancels.
4 + 5 + 4 + 5 + 0
Add the terms.
9 + 9 + 0
= 18
Answer:
Step-by-step explanation:
4-(-5)+04-(-5)+0
4+5+04+5+0
14+04
if you meant 0.4 then, it would be 14.4
if you mean 04 then, it would be 18
i need help on this. anyone ?
Answer:
Read below
Step-by-step explanation:
To copy a segment, you have to open your compass to the length of the given segment. The instructions say to have an endpoint at R, so, with the compass open to the length of the given line segment, place one end of the compass at R and draw an arc that intersects the line that R lies on. This new segment is congruent to the given segment.
I hope this helps!
