The enthalpy change for combustion of 15.0 g of ethanol in the chemical reaction is -180.93 kJ.
The enthalpy change for combustion of 15.0 g of ethanol can be calculated using the equation:
ΔH = (ΔH°/mol) × (mol/mass) × mass
Where ΔH° is the standard enthalpy change for the reaction, mol is the number of moles of ethanol, and mass is the mass of ethanol in grams.
Given that the standard enthalpy change for the combustion of ethanol is -555 kJ, the molecular weight of ethanol is 46.0 g/mol, and the mass of ethanol is 15.0 g, we can plug these values into the equation:
ΔH = (-555 kJ/mol) × (1 mol/46.0 g) × (15.0 g)
Simplifying the equation gives:
ΔH = (-555 kJ/mol) × (0.326 mol)
ΔH = -180.93 kJ
Therefore, the enthalpy change for combustion of 15.0 g of ethanol is -180.93 kJ.
Learn more about combustion of ethanol:
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Which of the following excerpts is an analogy?
A. First is the danger of futility, the belief there is nothing one man or one woman can do against the enormous array of the world's ills. . . . (paragraph 2)
B. [A]nd crossing each other from a million different centers of energy and daring, those ripples build a current which can sweep down the mightiest walls of oppression and resistance. . . . (paragraph 4)
C. Few men are willing to brave the disapproval of their fellows, the censure of their colleagues, the wrath of their society. (paragraph 5)
D. [T]hose with the courage to enter the conflict, will find themselves with companions in every corner of the world. (paragraph 6)
Answer:
D is an analogy. In this analogy, the courage to enter the conflict is compared to having companions in every corner of the world.
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Answer:
Pattern is equal to the distance between the slit and screen multiplied by the tangent of the angle.
The goal of ___________ is to focus on summarizing and explaining a specific set of data.
Hello!
The correct answer for the blank is: Descriptive Statistics.
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