The mass of a science textbook is 1. 15 kilograms. The mass of a history textbook is 980 grams. Rami makes a stack of 4 science textbooks and a stack of 5 history textbooks.



Part A:



Write < or > to compare the masses of the stacks of textbooks.



Mass of History Textbooks


?


Mass of Science Textbooks



Part B:



By how much mass do the stacks of textbooks differ? Enter your answer in kilograms. Complete the explanation of how to find the difference.



The mass of a science textbook is 1. 15 kg. So, 4 science textbooks would have a mass of 4 × 1. 15 kg =


kg. The mass of a history textbook is 980 g =


kg. So, 5 history textbooks would have mass of


kg. The difference of the masses is


kg.


The mass of a science textbook is 1. 15 kilograms. The mass of a history textbook is 980 grams. Rami makes a stack of 4 science textbooks and a stack of 5 history textbooks.



Part A:



Write < or > to compare the masses of the stacks of textbooks.



Mass of History Textbooks


?


Mass of Science Textbooks



Part B:



By how much mass do the stacks of textbooks differ? Enter your answer in kilograms. Complete the explanation of how to find the difference.



The mass of a science textbook is 1. 15 kg. So, 4 science textbooks would have a mass of 4 × 1. 15 kg =


kg. The mass of a history textbook is 980 g =


kg. So, 5 history textbooks would have mass of


kg. The difference of the masses is


kg

The value of c is 1.6.

To find the value of c in the density function f(y), we need to ensure that the density function satisfies the properties of a probability density function. The total area under the density function should be equal to 1.

Since f(y) represents a density function, the integral of f(y) over its entire domain should be equal to 1.

Let's calculate the integral of f(y) over the given intervals:

∫[−1,0] 0.2 dy = 0.2y ∣[−1,0] = 0.2(0 - (-1)) = 0.2

∫[0,1] (0.2 + cy) dy = 0.2y + c/2 * y^2 ∣[0,1] = (0.2 + c/2) - (0.2) = c/2

For the density function to be valid, the total integral should be equal to 1. Therefore, we can set up the equation:

0.2 + c/2 = 1

Simplifying the equation:

c/2 = 1 - 0.2

c/2 = 0.8

c = 0.8 * 2

c = 1.6

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The expected cost for the store per customer who purchases the protection plan is $45. This means that, on average, the store expects to incur a cost of $45 for each customer who buys the plan. To analyze the cost and risk for the electronics store, we can calculate the expected value, which takes into account both the probability of an event and the associated cost.

In this case, the store charges customers $125 for the protection plan, and the probability of a customer needing a replacement is 3%. The cost of a replacement for the store is $1,500.

The expected value (EV) can be calculated as follows:

EV = (Probability of an event) * (Cost of the event)

EV = (0.03) * ($1,500)

EV = $45

Therefore, the expected cost for the store per customer who purchases the protection plan is $45. This means that, on average, the store expects to incur a cost of $45 for each customer who buys the plan.

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The probability of event B for the condition of  A and B are mutually exclusive events and probability of A = 0.70 is given by option a. cannot be larger than 0.30.

If events A and B are mutually exclusive,

It means that they cannot occur at the same time.

In other words, if event A happens, event B cannot happen, and vice versa.

P(A) = 0.70, this means that the probability of event A occurring is 0.70.

Since events A and B are mutually exclusive, they cannot occur together.

Therefore, the probability of event B occurring, P(B), must be 0.

The probability of an event that cannot happen is always 0.

Therefore, for the probability of event B correct answer is option a. cannot be larger than 0.30.

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The position of Michael's hands relative to the surface of the water is 2.3 meters below the surface, calculated by adding the distance between his feet and the surface (0.5 meters) to the distance between his hands and his feet (1.8 meters).

To determine the position of Michael's hands relative to the surface of the water, we need to calculate the vertical distance between his hands and the surface. Given that his feet are 0.5 meters above the surface and his hands are 1.8 meters below his feet, we can add these distances together to find the total vertical distance.

The vertical distance from Michael's hands to his feet is 1.8 meters + 0.5 meters = 2.3 meters. This means that Michael's hands are 2.3 meters below the surface of the water.

In conclusion, the position of Michael's hands relative to the surface of the water is 2.3 meters below the surface.

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If working adults aged 22-25 spend an average of $14.27 a day on food with a standard deviation of $2.25, then Jeremy would spend approximately $23.27 per day if his expenditure is 4 standard deviations above the average.

To calculate how much Jeremy spends per day, we need to find a value that is 4 standard deviations above the average.

Mean (average) = $14.27

Standard deviation = $2.25

To find the amount Jeremy spends per day, we multiply the standard deviation by 4 and add it to the mean:

Jeremy's daily spending = Mean + (4 * Standard deviation)

Jeremy's daily spending = $14.27 + (4 * $2.25)

Jeremy's daily spending = $14.27 + $9.00

Jeremy's daily spending = $23.27

Therefore, Jeremy spends approximately $23.27 per day, rounded to 2 decimal places.

The concept used to solve the problem is based on the standard deviation and the number of standard deviations above the mean.

In statistics, the standard deviation measures the amount of variation or dispersion in a dataset. It tells us how spread out the data points are from the mean.

To find Jeremy's daily spending, we are given the average daily spending ($14.27) and the standard deviation ($2.25). Since Jeremy's spending is described as 4 standard deviations above the average, we need to multiply the standard deviation by 4 to get the amount.

By multiplying the standard deviation ($2.25) by 4, we obtain the additional amount Jeremy spends above the average. Adding this to the mean ($14.27) gives us Jeremy's daily spending of $23.27.

This approach allows us to calculate the value of Jeremy's spending based on the average, standard deviation, and the given number of standard deviations above the mean.

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Angie computing the correlation between the intelligence test scores and the household incomes in a large sample of American adults will most likely yield a positive correlation.

What is correlation?

Correlation refers to the statistical association between two variables. It is used to determine the extent to which one variable is related to another variable. The correlation coefficient ranges from -1 to +1, with a coefficient of -1 indicating a perfect negative correlation and a coefficient of +1 indicating a perfect positive correlation.

What is positive correlation?

A positive correlation exists between two variables when both variables move in the same direction. When one variable increases, the other variable also increases. When one variable decreases, the other variable also decreases.In this situation, it's fair to suggest that there is a positive correlation between intelligence test scores and household incomes. In general, people with higher intelligence scores are more likely to be employed in high-paying jobs, resulting in higher household incomes. Therefore, Angie should find a positive correlation between the two variables.

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Based on the F(2,30) value of 5.00, and assuming equal sample sizes across conditions, there were 10 participants in each condition.

The notation F(df between, df within) represents the F-value in an ANOVA test, where the numerator degrees of freedom (df between) refer to the number of groups minus one, and the denominator degrees of freedom (df within) refer to the total sample size minus the number of groups. In this case, F(2,30) = 5.00 indicates that there were three groups or conditions (df between = 2) and a total of 33 participants (df within = 30 + 3 = 33).

Assuming equal sample sizes across conditions, we need to divide the total sample size (33) by the number of conditions (3) to find the number of participants in each condition. Therefore, 33 participants divided into 3 conditions would result in approximately 11 participants per condition. However, since the answer choices provided are whole numbers, we need to select the closest whole number option. In this case, the answer is B. 11, as it is the closest option to the average of 11 participants per condition.

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The number of passengers who travel on subways in American cities each day is significantly higher than the number of passengers who fly American commercial aviation.

Subways serve as a vital mode of transportation in American cities, providing an efficient and cost-effective means of commuting for millions of people. On any given day, the number of passengers using subways surpasses the number of passengers flying on American commercial airlines.

Subway systems are heavily utilized in major cities such as New York, Chicago, Washington D.C., and San Francisco, where they play a crucial role in alleviating traffic congestion and offering a convenient alternative to private vehicles. These underground rail networks enable commuters to navigate through urban areas swiftly and avoid the challenges associated with driving or relying on other forms of transportation.

The extensive reach of subway systems, combined with their affordability and accessibility, contributes to their high passenger volume. Many individuals, including residents, tourists, and daily commuters, choose subways as their primary mode of transportation due to their reliability, frequency of service, and the ability to avoid traffic delays.

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Constructing 95% and 99% confidence intervals for the mean amount of garbage per bin for all bins in the city. Don't use 68/95/99.7 rule; instead use R to compute the quantities such as quantiles are:

a) 51.592 b) 54.008 c) 51.213 d) 54.387

Here, we have,

a) lower limit of 95% interval

Lower limit = 52.8 - (1.96) (3.9/sqrt 40) = 51.592

b) upper limit of 95% interval

upper limit = 52.8 + (1.96) (3.9/sqrt 40) = 54.008

c) lower limit of 99% interval

Lower limit = 52.8 - (2.576) ( 3.9 / sqrt 40)= 51.213

d) upper limit of 99% interval

Upper limit = 52.8 + (2.576) ( 3.9 / sqrt 40) = 54.387

Hence, Constructing 95% and 99% confidence intervals for the mean amount of garbage per bin for all bins in the city. Don't use 68/95/99.7 rule; instead use R to compute the quantities such as quantiles are:

a) 51.592 b) 54.008 c) 51.213 d) 54.387

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The probability of observing fewer than half of 12 individuals covering their mouth when sneezing is approximately 0.9947.

(a) Let X represent the number of individuals who do not cover their mouth when sneezing among 12 randomly selected individuals. Then X has a binomial distribution with parameters n = 12 and p = 0.287.P(X = 6) can be calculated by using the binomial probability formula: P(X = k) = (n C k) * p ^k * (1-p)^(n-k)where (n C k) represents the binomial coefficient, which is the number of ways to choose k items from n items. Thus ,P(X = 6) = (12 C 6) * (0.287)^6 * (1-0.287)^(12-6)≈ 0.2046 (rounded to four decimal places).

(b) To find P(X < 4), we can use the cumulative distribution function (CDF) of the binomial distribution:

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)P(X = k) = (n C k) * p ^k * (1-p)^(n-k) Thus , P(X < 4) = (12 C 0) * (0.287)^0 * (1-0.287)^(12-0) + (12 C 1) * (0.287)^1 * (1-0.287)^(12-1) + (12 C 2) * (0.287)^2 * (1-0.287)^(12-2) + (12 C 3) * (0.287)^3 * (1-0.287)^(12-3)≈ 0.0079 (rounded to four decimal places)(e) Yes, it would be surprising if fewer than half of 12 individuals covered their mouth when sneezing, because the expected number of individuals who do not cover their mouth when sneezing among 12 randomly selected individuals is 12 * 0.287 ≈ 3.444, which is less than half of 12.

So observing fewer than half of 12 individuals covering their mouth when sneezing would be an unusual event.

The probability of observing fewer than half covering their mouth can be calculated as P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)P(X = k) = (n C k) * p ^k * (1-p)^(n-k)

Thus ,P(X < 6) = (12 C 0) * (0.287)^0 * (1-0.287)^(12-0) + (12 C 1) * (0.287)^1 * (1-0.287)^(12-1) + (12 C 2) * (0.287)^2 * (1-0.287)^(12-2) + (12 C 3) * (0.287)^3 * (1-0.287)^(12-3) + (12 C 4) * (0.287)^4 * (1-0.287)^(12-4) + (12 C 5) * (0.287)^5 * (1-0.287)^(12-5)≈ 0.9947 (rounded to four decimal places)

Therefore, the probability of observing fewer than half of 12 individuals covering their mouth when sneezing is approximately 0.9947.

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The problem requires us to calculate the probability that three of the five even numerical denominations are represented twice, one of the three face cards appears twice, and a second face card appears once.

To solve the problem, we need to determine the number of possible hands that meet the criteria and divide it by the total possible hands that can be dealt from the deck. We will begin by counting the total number of ways nine cards can be dealt from a 52-card deck. We will use the combination formula, which is:

nCr = n! / r! (n - r)!,

where n is the total number of items and r is the number of items chosen.

Here, n = 52 and r = 9. nCr = 52C9 = 52! / 9! (52 - 9)! = 4,104,398,535.

This is the total number of possible hands that can be dealt from the deck. Now, we will count the number of ways to choose the cards that meet the criteria. We will divide this by the total number of hands to get the probability of the event. We will choose the five even numerical denominations first. There are five even numbers, and we need three of them to be repeated twice. Therefore, we need to choose three of the five, which can be done in 5C3 = 10 ways. Once we have selected the three even numbers, we can select two of them to be repeated twice in 3C2 = 3 ways. The remaining four cards can be selected from the deck in 44C4 ways. Next, we will choose the face cards. We need two face cards, one of which is repeated twice. There are three face cards, and we need to choose two of them, which can be done in 3C2 = 3 ways. One of the two chosen cards can be repeated twice in two ways. The last card can be chosen from the remaining 46 cards in 46 ways. The total number of ways to choose the cards that meet the criteria is the product of all the above combinations, i.e., 10 × 3 × 44C4 × 3 × 2 × 46. Therefore, the probability of the event is:

P(event) = (10 × 3 × 44C4 × 3 × 2 × 46) / 52C9= 0.0000532 (rounded to four decimal places)

The formula for the probability that three of the five even numerical denominations are represented twice, one of the three face cards appears twice, and a second face card appears once, is P(event) = (10 × 3 × 44C4 × 3 × 2 × 46) / 52C9 = 0.0000532 (rounded to four decimal places).

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The sale price of a fishing rod is $28.16.

A fishing supply store buys fishing rods for $11 and sells them at a markup of 220%.

One day, they decide to put the rods on sale and mark them down by 20%.

Let's find the selling price of the fishing rod:

Selling price = Cost price + Markup of 220%

markup = (220/100) * 11

markup = $24.20

Selling price = $11 + $24.20

Selling price = $35.20

Now, applying a discount of 20%, we get

Discount on selling price = (20/100) * 35.20

Discount on selling price = $7.04

Therefore, the sale price of a fishing rod after a 20% discount is:

Sale price = Selling price - Discount on selling price

Sale price = $35.20 - $7.04

Sale price = $28.16

Hence, After putting the rod on sale and mark them down by 20% the sale price of a fishing rod is $28.16.

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The term "Additional" specifies the additional number of users within the same household that can be included for $3 per month.

A music-streaming service charges $9 per month for a single user. Additional users within the same household can be added for $3 per month. Here, the term "Additional" refers to the extra number of users that can be added with a monthly subscription charge of $3 for the music streaming service. Hence, the term "Additional" specifies the additional number of users within the same household that can be included for $3 per month.

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The given information indicates that the number of cheeseburgers sold was twice the number of hamburgers sold.

Let the number of hamburgers sold on Saturday be x

Therefore, the number of cheeseburgers sold = 2x

Total number of hamburgers and cheeseburgers sold = x + 2x = 3x

As per the question: "On Saturday, a local hamburger shop sold a combined total of hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the number of hamburgers sold."

Hence, the equation formed is: 2x + x = 3x

Therefore, hamburgers sold on Saturday = x = 1x

Hence, the local hamburger shop sold x hamburgers on Saturday. Therefore,  the number of hamburgers sold on Saturday is x which is equivalent to 1x or x/1.

Therefore the given information indicates that the number of cheeseburgers sold was twice the number of hamburgers sold.

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This promotion is a non-price determinant of demand that would cause the demand curve for shoes to shift rightward.

The demand curve for shoes would shift rightward, and the promotion is a non-price determinant of demand.

A determinant of demand is anything that affects the willingness or ability of consumers to purchase a good or service. The following are some of the determinants of demand:

Price of the commodity income of the consumer price of related products taste and preferences of the consumer's population and demographics, consumer expectations, advertising and promotional activities.

Therefore, if a large store advertised that if you buy a pair of shoes next week, you would get the second pair half price, the demand curve for shoes would shift rightward.

This promotion is an example of advertising and promotional activities.

Because of the promotion, consumers will be willing to buy more shoes, resulting in an increase in demand.

If the promotion is effective, the store will sell more shoes, increasing its revenue.

In conclusion, this promotion is a non-price determinant of demand that would cause the demand curve for shoes to shift rightward.

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a) The probability P(XB - XA ≥ 0.2) under the condition that μA = μB is 0.5. b)  The sample averages for machine A and B (4.5 and 4.7 ounces, respectively) are only a point estimate of the population means.

a. To use the Central Limit Theorem (CLT), we can approximate the difference between the sample averages,[tex]X_B - X_A,[/tex] as a normal distribution. Under the condition that μA = μB, we can assume a common population mean (μ) for both machines.

The difference in sample means, [tex]X_B - X_A,[/tex] follows a normal distribution with a mean of μB - μA and a standard deviation of σ/sqrt(n), where σ is the population standard deviation and n is the sample size.

In this case, σ = 1 ounce and n = 36.

The difference [tex]X_B - X_A\geq 0.2[/tex] can be rewritten as [tex]X_B - X_A-0.2\geq 0.[/tex]

Now, we can calculate the z-score corresponding to this inequality:

[tex]z = (X_B - X_A - 0.2) / (\sigma/\sqrt{n} )\\z = (4.7 - 4.5 - 0.2) / (1/\sqrt{36} )\\z = 0 / (1/6)\\z = 0[/tex]

To find the probability[tex]P(X_B - X_A)\geq 0.2,[/tex] we need to calculate the probability that a standard normal distribution is greater than or equal to 0.

P(Z ≥ 0) = 0.5

Therefore, the probability [tex]P(X_B - X_A)\geq 0.2[/tex] under the condition that μA = μB is 0.5.

b. Based on the information given, we cannot strongly support the conjecture that the two population means for the two machines are different. The sample averages for machine A and B (4.5 and 4.7 ounces, respectively) are only a point estimate of the population means. To make a conclusion about the population means, we would need to conduct hypothesis testing and analyze the statistical significance of the difference between the sample means. The experiments alone cannot provide strong evidence to support the conjecture of different population means for the two machines.

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The estimation of the population average family expenditure on entertainment on the sample average expenditure of 900 families is an example of inferential statistics.

Inferential statistics is a branch of statistics that helps in understanding the relationship between a sample and the population. It involves using sample data to make predictions, inferences, and decisions about a population. The estimation of the population average family expenditure on entertainment on the sample average expenditure of 900 families involves estimating the population parameters based on a sample. Here, we are using the sample mean of 900 families to estimate the population mean. This is an example of inferential statistics since we are trying to infer information about the population based on the sample. In conclusion, estimating the population average family expenditure on entertainment based on the sample average expenditure of 900 families is an example of inferential statistics.

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The p-value of the test statistic is approximately 0.0156, suggesting robust evidence that the LSATBoost preparation service increases the average LSAT score by at least 5 points.

To test the hypothesis, we will conduct a one-sample t-test.

Null hypothesis (H₀): The average increase in LSAT score is less than 5 points.

Alternative hypothesis (H₁): The average increase in LSAT score is greater than or equal to 5 points.

Sample mean (x) = (132 + 140 + 139 + 135 + 127 + 127 + 135 + 138 + 140 + 125 + 134 + 133 + 139 + 129 + 130 + 138 + 129 + 136 + 136 + 131) / 20 = 134.35

Sample standard deviation (s) = √[((132 - 134.35)² + (140 - 134.35)² + ... + (131 - 134.35)²) / (20 - 1)] = 8.081

Sample size (n) = 20

Hypothesized mean (μ₀) = 5

Calculate the test statistic:

t = (x - μ₀) / (s / √n)

t = (134.35 - 5) / (8.081 / √20)

t ≈ 17.433

Degrees of freedom (df) = n - 1 = 20 - 1 = 19

Using the t-distribution table or a calculator, we find that the p-value for a one-tailed t-test with 19 degrees of freedom and a test statistic of 17.433 is approximately 0.0156.

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To find the average rate of change of the function f(x) = (x - 2)3 over the interval -2 ≤ x ≤ 4, we need to calculate the difference in function values at the endpoints of the interval and divide it by the difference in x-values.

This will give us the average rate of change to the nearest hundredth.

The average rate of change of a function over an interval is given by the formula: (f(b) - f(a)) / (b - a), where a and b are the endpoints of the interval. In this case, a = -2 and b = 4. Evaluating the function at these points, we have:

f(-2) = (-2 - 2)3 = (-4)3 = -64,

f(4) = (4 - 2)3 = (2)3 = 8.

Substituting these values into the formula, we get:

Average rate of change = (8 - (-64)) / (4 - (-2)) = 72 / 6 = 12.

Therefore, the average rate of change of the function f(x) = (x - 2)3 over the interval -2 ≤ x ≤ 4 is 12 to the nearest hundredth.

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Given the image of the situation: Image text: A person is standing at point A looking up to the top of a radar tower located at point B. The distance from point A to point B is 150 feet. Angle 4 is formed by the horizontal line and the line from the person to the top of the radar tower.

Angle 4 is also formed by the horizontal line and the line from the top of the radar tower to the person. What is the description of angle 4 as it relates to the situation below?

The description of angle 4 as it relates to the situation below is: angle 4 is the angle of elevation from the person to the radar tower (a).Explanation: An angle of elevation is the angle formed by a horizontal line and a line of sight that is directed upward.

Therefore, in this situation, Angle 4 is the angle of elevation from the person to the radar tower. Angle 4 is the angle between the line of sight from the person to the top of the radar tower and the horizontal line drawn through the person.

Hence, the answer is option (a). Therefore, option (a) is the correct description of angle 4 as it relates to the situation in the given image.

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The answers are:

a. population standard deviation σ = 0.1 ounce

b. standard deviation of the sampling distribution sx = 0.0268 ounce.

Given,

Sample size = n = 15

Mean weight = 2 ounces

Standard deviation = s = 0.12 ounces

Population standard deviation = σ = 0.1 ounces

The formula to calculate the standard deviation of the sampling distribution of the sample mean is given as:

σx = σ/√n

Where, σx is the standard deviation of the sampling distribution of the sample mean.

σ is the population standard deviation.

n is the sample size.

Now, substitute the given values in the above formula:

σx = 0.1/√15

σx ≈ 0.0268

So, the standard deviation of the sampling distribution of the sample mean is σx = 0.0268.

Therefore, the answers are:

a. σ = 0.1 ounce

b. σx = 0.0268 ounce.

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a) The probability of obtaining at least 2 correct answers, we sum up the individual probabilities:

P(X ≥ 2) = P(X = 2) + P(X = 3) + ... + P(X = 10)

b) The mean of X is 2 and the variance of X is 8/5.

(a) To find the probability that the student obtains at least 2 correct answers, we need to calculate the probabilities of getting exactly 2, 3, 4, ..., 10 correct answers, and then sum them up.

The probability of getting exactly k correct answers out of 10 questions, where k ranges from 2 to 10, can be calculated using the binomial probability formula:

P(X = k) = (10 choose k) * (1/5)^k * (4/5)^(10-k)

where (10 choose k) represents the number of ways to choose k correct answers out of 10 questions.

To find the probability of obtaining at least 2 correct answers, we sum up the individual probabilities:

P(X ≥ 2) = P(X = 2) + P(X = 3) + ... + P(X = 10)

(b) To find the mean and variance of X, we can use the properties of the binomial distribution. The mean (μ) of a binomial distribution is given by:

μ = n * p

where n is the number of trials and p is the probability of success in each trial. In this case, n = 10 (number of questions) and p = 1/5 (probability of guessing the correct answer).

μ = 10 * (1/5) = 2

The variance (σ^2) of a binomial distribution is given by:

σ^2 = n * p * (1 - p)

σ^2 = 10 * (1/5) * (1 - 1/5) = 8/5

Therefore, the mean of X is 2 and the variance of X is 8/5.

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The difference of two polynomials is just another polynomial that represents the result of subtracting one polynomial from another.

Let's say we have two polynomials: f(x) and g(x). We're told that their difference is 2x² - 8.

This means we can write:

f(x) - g(x) = 2x² - 8

Now, we just need to come up with two polynomials that satisfy this equation.

f(x) = 3x² - 2x + 1

g(x) = 3x² + 2x + 9

Now, let's check that their difference is indeed 2x² - 8

:f(x) - g(x) = (3x² - 2x + 1)  

Let's try:- (3x² + 2x + 9)= 3x² - 2x + 1 - 3x² - 2x - 9

= -4x - 8

= 2(x² - 4)

= 2x² - 8

So we see that these two polynomials do indeed have a difference of 2x² - 8.

When we subtract two polynomials, we simply subtract the corresponding coefficients of each term.

For example, if we have:

f(x) = 4x³ + 2x² - x - 5

g(x) = 2x² - x + 3

Then the difference between these two polynomials is:

f(x) - g(x) = (4x³ + 2x² - x - 5) - (2x² - x + 3)

= 4x³ + 2x² - x - 5 - 2x² + x - 3

= 4x³ + x² - 8

So the difference of two polynomials is just another polynomial that represents the result of subtracting one polynomial from another.

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The complete question is:

Come up with your own example that satisfies the following statement:

Give an example that satisfies the following:

The difference of two polynomials 2x²-8

The completed area model describing how to divide 368 by 8 can be presented as follows;

[tex]{}[/tex]           ___40____________6_____

8     [tex]{}[/tex]            320             |         48

    [tex]{}[/tex]        _______________________

          [tex]{}[/tex]      368 ÷ 8 = 46

An area model visually represents mathematical concepts to improve the understanding of such concepts by students. Mathematical model that can be demonstrated using an area model includes division and multiplication.

The division and multiplication of two numbers can be displayed visually using a rectangular area model, where, the divisor is the width of the  rectangle and the quotient is the length of the rectangle.

The area model for the division of 368 by 8 can be presented as follows;

368 = 320 + 48

368/8 = (320 + 48)/8 = 40 + 6

Therefore, the area model can be presented as follows;

   ×         [tex]{}[/tex] 40                   6                  

8   [tex]{}[/tex]          320                  48

      [tex]{}[/tex]    368 ÷ 8 = 46

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The probability that all 7 graduates selected at random received a starting salary of $60,000 or more is , 0.0065

This is a binomial probability problem where we have a sample of size 7 and want to find the probability that all 7 graduates received a starting salary of $60,000 or more.

We know that 40% of mathematics graduates received a starting salary of $60,000 or more,

So, the probability of any one graduate receiving a salary of $60,000 or more is 0.4.

Using the binomial probability formula, we can calculate the probability as follows:

P(X = 7) = (n choose X) pˣ (1-p)ⁿ⁻ˣ

where n is the sample size, x is the number of graduates who received a starting salary of $60,000 or more, p is the probability of success (i.e., receiving a salary of $60,000 or more), and (n choose X) is the number of ways to select X graduates out of n.

So in this case, we have:

n = 7, X = 7 and p = 0.4

Plugging into the formula, we get:

P(X = 7) = (7 choose 7) 0.4⁷ (1-0.4)⁷⁻⁷

P(X = 7) = (1) 0.4⁷ (0.6)⁰

P(X = 7) = 0.0065

Therefore, the probability that all 7 graduates selected at random received a starting salary of $60,000 or more is , 0.0065

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The probability that none of the 10 randomly selected MIS graduates from UIUC make above $48,861 in their first job is (0.47)^10, which can be calculated using the binomial probability formula.

To find the probability that none of the 10 graduates make above $48,861, we raise the probability of an individual not making above $48,861 to the power of 10 (since we want all 10 to not make above that amount) and multiply it by the total number of combinations for selecting 10 graduates out of the total population.

Using the binomial probability formula, the probability that none of the 10 graduates make above $48,861 can be calculated as:

[tex]P(X = 0) = C(10, 0) * (0.47)^0 * (1 - 0.47)^{10-0}[/tex]

where C(10, 0) represents the number of combinations of selecting 0 graduates out of 10.

Simplifying the equation, we find:

[tex]P(X = 0) = (1) * (1) * (0.47)^{10}[/tex]

Therefore, the probability that none of the 10 randomly selected MIS graduates from UIUC make above $48,861 in their first job is [tex](0.47)^{10}[/tex].

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The Referee should prevent Fencer X from using the unmarked mask until it undergoes inspection.

When a fencer arrives at the strip with a mask that does not bear the marks of the preliminary inspection, the Referee has a responsibility to intervene. The mask must be inspected before it can be used in the competition. Fencing equipment undergoes a preliminary inspection to ensure it meets safety standards and regulations.

This inspection includes verifying that the mask has the necessary marks, indicating that it has been checked for compliance. By not allowing Fencer X to use the unmarked mask until it undergoes inspection, the Referee upholds fair play and ensures the safety of all participants.

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It takes 5 x 10² seconds for the light to reach Earth from the sun.

Given that Earth is 93 million miles from the sun and the speed of light, c, is about 186,000 miles per second. We need to use the equation,

d = rt,

where d is the distance, r is the rate, and t is the time taken.

Then we can substitute the given values and calculate the time taken. So,

t = d/r

where d = 93 million miles,

r = 186,000 miles/second

Therefore,

t = (93 x 10⁶) miles/ (186,000 miles/second)

t = 500 seconds or

t = 5 x 10² seconds

Hence, it takes 5 x 10² seconds to reach Earth from the sun.

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Answer: squares

Step-by-step explanation: square is a basically a rectangle

Lance is using a strategy called "letter combination analysis" to solve the anagram MAHLTGIRO. This strategy involves examining the available letters and identifying common combinations or sequences that can form words.

An anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once. For example, the word anagram itself can be rearranged into nag a ram, as well as the word binary into brainy and the word adobe into abode.

Players place their words in front of them, where everyone can read them. Upon making a word, a player draws another letter to try and make another word. If they can't, they put their letter face up with any others that are face up in the center and draw another to conceal in hand.

Lance is using a strategy called "letter combination analysis" to solve the anagram MAHLTGIRO. This strategy involves examining the available letters and identifying common combinations or sequences that can form words. In this case, Lance is specifically focusing on the combination "TH" and attempting to create words using this combination.

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