the proportion of dental procedures that are extractions is 0.16. which of the following exemplifies a type i error in this situation? a. we reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16. b. we reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually 0.16. c. we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16. d. we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually 0.16.

Answers

Answer 1

The following exemplifies a type of error in this situation, we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16.

What is dental extraction?

An extraction is a process used to remove a tooth from its socket in the gum. A regular dentist, an oral surgeon, or a periodontist typically performs it. Normal teeth might look different, especially the molars.

Here, we have

The proportion of dental procedures that are extractions is 0.16.

We have to find errors in this situation,

we concluded that we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16.

Hence, the following exemplifies a type of error in this situation, we fail to reject the claim that the proportion of dental procedures that are extractions is 0.16 when the proportion is actually different from 0.16.

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Related Questions

tom is a big green bay packers and aaron rodgers fan. he claims that aaron rodger's average number of touchdowns per game is 2.45. dave (a hardcore bears fan) believes that tom might be inflating rodgers's statistics. from his debut until november 18, 2019, aaron rodgers has played 175 games! dave does not want to look at all of them. he randomly selects 52 games that rodgers played and finds the sample average number of touchdowns to be 1.942 with a standard deviation of 1.42. do a hypothesis test and state your conclusion. use the significance level

Answers

After doing a hypothesis test the conclusion is reject [tex]H_0[/tex] .

Given:

tom is a big green bay packers and aaron rodgers fan. he claims that aaron rodger's average number of touchdowns per game is 2.45. dave (a hardcore bears fan) believes that tom might be inflating rodgers's statistics. from his debut until november 18, 2019, aaron rodgers has played 175 games! dave does not want to look at all of them. he randomly selects 52 games that rodgers played and finds the sample average number of touchdowns to be 1.942 with a standard deviation of 1.42.

here n = 52

σ = 1.42

x = 1.942

μ = 2.45

z = x - μ / σ/√n

= 1.942 - 2.45 / 1.42/√52

= -2.58

p value = 0.0049

[tex]H_0:mean = 2.45[/tex]

[tex]H_a:mean < 2.45[/tex]

Rejection rule:Reject [tex]H_0[/tex] if p value < 0.05

Conclusion Reject [tex]H_0[/tex]

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A juice box is 5 cm long, 3 cm wide and
10 cm tall. The juice is poured into a
glass with a radius of 3 cm.
What is the depth of juice in the glass?
Answer in centimetres to 1 decimal place.

Answers

The depth of the juice in the glass is 5.30cm

Given in the question,

length of juice box = 5cm

width of juice box = 3cm

Height of juice box = 10cm

Volume of juice box = volume of cuboid = length× width× height

= (5)(3)(10)

=(15)(10)

= 150 cm³

This juice then poured into a glass with radius of 3 cm

Glass is of cylindric shape

So, volume of cylinder = πr²h

= π(3)²h

Volume of juice should be equal to volume of glass

=>  π(3)²h = 150 cm³

=> (3.14)(9)h=150

=> h = 150 / (3.14)(9)

h = 150/28.26

h = 5.30cm

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Two boat AandB left a portC at the ame time on different route. B travelled on a bearing of 150 and A travelled on the north ide of B. When A had travelled 8km andB had travelled 10km ,the ditance between the two boat wa found to be 12km. Calculate the bearing ofA, route from C

Answers

The bearing of A route from C is  67.2°.

What is an angle?

An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint. The Latin word "angulus," which means "corner," is the source of the English term "angle." The shared terminus of two rays is known as the vertex, and the two rays are referred to as sides of an angle.

Here, we have

B traveled on a bearing of 150 and A traveled on the north side of B.

To find angle C, we have to use the cosine rule and we get

12² = 8² + 10² - 2 × 8 × 10 × cosC

C = 82.8°

The bearing of A from C will be

= 150° - 82.8°

= 67.2°.

Hence, the bearing of the A route from C is  67.2°.

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How do you determine which table represents a function?.

Answers

We can determine which table represents a function by, verifying each input value's pairing with a single output value.

Define function.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output. Each function has a range, codomain, and domain.

Given,

We can determine which table represents a function by,

Determine whether a table of input and output values constitutes a function. Determine the values for the input and output. Verify each input value's pairing with a single output value. In that case, the table is a function.

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if the pile contains only 15 quarters and only 20 dimes but at least 30 of each other kind of coin, how many collections of 30 coins can be chosen?

Answers

The number of ways to choosing coins with at least 15 quarters and 20 dimes is 4354.

In the given question, if the pile contains only 15 quarters and only 20 dimes but at least 30 of each other kind of coin, then we have to find the collections of 30 coins can be chosen.

Number of coins only of quarters = 15

Number of coins only of dimes = 20

The number of ways to choosing coins with at least 15 quarters and 20 dimes= Total- [tex](^{18}C_{3}+^{13}C_{3})[/tex]

The number of ways to choosing coins with at least 15 quarters and 20 dimes= [tex]^{33}C_{3}-(^{18}C_{3}+^{13}C_{3})[/tex]

Using [tex]^{n}C_{r}=\frac{n!}{r!(n-r)!}[/tex]

The number of ways to choosing coins with at least 15 quarters and 20 dimes= [tex]\frac{33!}{3!(33-3)!}-(\frac{18!}{3!(18-3)!}+\frac{13!}{3!(13-3)!})[/tex]

The number of ways to choosing coins with at least 15 quarters and 20 dimes= [tex]\frac{33!}{3!30!}-(\frac{18!}{3!15!}+\frac{13!}{3!10!})[/tex]

Simplifying

The number of ways to choosing coins with at least 15 quarters and 20 dimes= [tex]\frac{33\times32\times31\times30!}{3\times2\times1\times30!}-(\frac{18\times17\times16\times15!}{3\times2\times1\times15!}+\frac{13\times12\times11\times10!}{3\times2\times1\times10!})[/tex]

The number of ways to choosing coins with at least 15 quarters and 20 dimes= 11×16×31-(3×17×16+13×2×11)

The number of ways to choosing coins with at least 15 quarters and 20 dimes= 5456-(816+286)

The number of ways to choosing coins with at least 15 quarters and 20 dimes= 5456-1102

The number of ways to choosing coins with at least 15 quarters and 20 dimes= 4354

If the pile contains only 15 quarters and only 20 dimes but at least 30 of each other kind of coin, the number of ways to choosing coins with at least 15 quarters and 20 dimes is 4354.

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What is an outlier in 6th grade math?.

Answers

If the data collection contains the given following numbers: 1, 19, 25, 32, 36, 38, 31, 42, 57, 45, and 87 , Here 1 and 87 represents the outlier.

What is characteristics of statistics ?

The important characteristics of the Statistics that are given as follows:

Statistics have always been numerically expressed.

It had an aggregate of all the facts and dataData are to be collected in proper wayIt should be always comparable to one anotherData are collected for a well planned purposeOutliers are the data's most wildly divergent values.

For instance, if the data collection contains the following numbers: 1, 19, 25, 32, 36, 38, 31, 42, 57, 45, and 87

The display of all data and outliers

The numbers 1 and 87, which are at the extreme and are hence outliers in the number line above, may be seen to be at these extremes.

The group outliers are a part of it, but they are not always close to the other group members.

Outliers are a concern as they cause an imbalance in the data set, which is why they are typically eliminated. Furthermore, an error can sometimes cause an outlier to appear in a data collection.

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A boat traveled 27 miles in 2 hrs. At this rate, How many miles will the boat travele in 1/2 hrs

Answers

Answer:

In explanation down below.

Step-by-step explanation:

So if the boat was able to travel 27 miles in 2 hours that means that it traveled 13.5 miles an hour. I think that you want to know how many miles the boat will travel in 1/2 an hour. Which is 6.75.  

1 hour: 13.5 miles

1/2 hour the boat has traveled 6.75 miles.

I hope this helps!!!

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Lacy ha 10 gallon of water. She pour an equal number of gallon of water into each of 3 fih tank. Lacy' blue fih tank already ha 1 third gallon of water in it. How many gallon of water doe lacy blue fih tank ha now? fi

Answers

Lacy's blue fish tank has now 3 2/3 gallons of water.

If Lacy has 10 gallons of water and she pour an equal number of gallons of water into each of her 3 fish tanks, then the amount of water each tank will have is equal to the quotient of 10 divided by 3.

amount of water poured in each tank =  10 gallons / 3

amount of water poured in each tank = 10/3 gallons

If Lacy's blue fish tank already has 1/3 gallon of water in it, then the total amount of water the blue fish tank has is the sum of the two fractions.

Add the initial amount and the amount poured in after.

1/3 + 10/3 = 11/3 =  3 2/3 gallons

Simplifying the fraction, Lacy's blue fish tank has now 3 2/3 gallons of water.

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Jan traveled 260 miles using 8 gallons of gas. What was the car’s miles per quart on this trip?

Answers

Answer:

130 mi/ per quart

Step-by-step explanation:

260 mi/8 gallons =32.5 mi/gallon

1 gallon = 4 quarts, so 32.5 gallons is 130 quarts

What is the distance from the center of the circle C to chord AB?

Answers

Answer:

Step-by-step explanation:

8.5

as a seismologist, janet understands the devastating effects that earthquakes can have. so, she keeps her basement stocked with canned food, like chili. janet buys cans of chili from an online retailer that charges a shipping fee plus the cost of each can of chili. this table shows the relationship between the number of cans of chili janet buys, x, and the total cost (in dollars), y. x (cans) y (dollars) 12 $26.40 44 $56.80 66 $77.70 100 $110 according to the values in the table, do x and y have a proportional relationship?

Answers

As a seismologist, Janet understands the devastating effects that earthquakes can have. so, she keeps her basement stocked with canned food, like chili. This table shows the relationship between the number of cans of chili Janet buys, x, and the total cost (in dollars), y.

[tex]\begin{tabular}{|c|c|c|}\underline{x(cans)}&\underline{y(dollars)} \\12 & \$\ 26.40 \\ 44 & \$\ 56.80 \\ 66 & \$\ 77.70 \\ 100 & \$\ 110 \end{align}[/tex]

According to the values in the table, x and y have not a proportional relationship.

Prove x and y have a proportional relationship

Table

[tex]\begin{tabular}{|c|c|c|}\underline{x(cans)}&\underline{y(dollars)} \\12 & \$\ 26.40 \\ 44 & \$\ 56.80 \\ 66 & \$\ 77.70 \\ 100 & \$\ 110 \end{align}[/tex]

Specifies the gradient (m) in rows 1 and 2

m₁ = [tex]\displaystyle \frac{56.80 - 26.40}{44-12}[/tex]

m₁ = [tex]\displaystyle \frac{30.40}{32}[/tex]

m₁ = [tex]\displaystyle \frac{19}{20}[/tex]

Specifies the gradient (m) in rows 2 and 3

m₂ = [tex]\displaystyle \frac{77.70 - 56.80}{66-44}[/tex]

m₂ = [tex]\displaystyle \frac{20.9}{22}[/tex]

Because the values of m₁ and m₂ are not the same [tex]\displaystyle \frac{19}{20}[/tex] ≠ [tex]\displaystyle \frac{20.9}{22}[/tex], then x and y have not a proportional relationship.

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What is the solution to the system of equations y x 10 2x y 4?.

Answers

The solution to the system of equation is [tex](\frac{14}{3},-\frac{16}{3})[/tex]

What is a system of equations ?

A system of equations is a set of two or more equations with the same variables. A solution to a system of equations is a set of values for the variable that satisfy all the equations simultaneously.

Differentiate between substitution and elimination method.

The major difference between the substitution and elimination method is that the substitution method is the process of replacing the variable with a value, whereas the elimination method is the process of removing the variable from the system of linear equations.

The system of equations are :

y = x - 10 and

2x + y = 4

On solving two equations by using substitution method ,we get

By substituting the value of y in another equation ,we obtain the equation in terms of one variable :

Now, according to the question

⇒ 2x + (x - 10) = 4

⇒ (2x + x) = (4 + 10)

⇒ 3x = 14

⇒ x = 14/3

Further for y ,we substitute obtained value of x in the equation

y = x - 10

Now,

[tex]y = \frac{14}{3}-10[/tex]

  [tex]=\frac{(14-30)}{3}[/tex]

  [tex]= (\frac{-16}{3})[/tex]

  [tex]= - (\frac{16}{3})[/tex]

Hence ,the solution is (x,y) : [tex](\frac{14}{3},-\frac{16}{3})[/tex]

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The line egment i rotated 270 degree clockwie about the origin to form P'Q'. Which tatement decribe P'Q'

Answers

The line segment i rotated 270 degree clockwise about the origin to form P'Q' the statement describe P'Q'. The accurate alternative is (B) P'Q' is same in period to PQ.

That line phase PQ is proven at the co-ordinate grid. The line phase PQ is turned around 270 ranges counter clockwise approximately the foundation to shape P'Q'.We are to pick out the announcement that describes P'Q'.From the graph, we observe that the co-ordinates of factor P are(- 5, 3) and the co-ordinates of Q are (- 1, 3) .So, the period of PQ as calculated the usage of distance system is given byPQ = [tex]sqrt((- 1 + 5) + (- 3 + 3) ) = sqrt(+ )[/tex] = 4 units.We understand that if a factor is turned around 270 ranges counterclockwise, then its co-ordinates modifications as follows:(x, y) -> (y, - x)So, after the rotation, the co- ordinates of P and Q becomes[tex]P(-5,3) P^ (3, 5)G(- 1, 3) Q^ (3,1[/tex].The period of the road phase P'Q' as calculated the usage of distance system isP^ top Q^ top = sqrt([tex](3 - + (1 - ) = sqrt[/tex]= 4 units.Thus, the lengths of PQ and P'Q' are same.

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write a coordinate proof to prove that an arrowhead that is 3 inches long and 1.5 inches wide is an isosceles triangle. (5 points)

Answers

Answer:

(8,2), (12,2),(10,10)

Step-by-step explanation:

any coordinate that means the two sides will have the same length

first, we know that the length is twice the amount of the width

so any coordinate we pick must be twice the length

pick a coordinate that is quite high up ( so we don't get into negatives)

so let's say (10,10)

then we want to go a positive number down - don't want to deal with fractions.

so e.g 8

so 6 down would be (10,2)

then the width is half the length so it has a 4cm wide base

and put an equal amount on each side to the left and the right to get the base co-ordinates

to the left : (8,2)
plus to the right: (12,2)

2+2= make a 4cm base

put these coordinates together and presto! you have coordinated proofs!

which of the following is equivalent to sum from n equals 1 to infinity of 12 times quantity negative five eighths end quantity to the power of n question mark

Answers

The sum of given equation is 96/13.

Given equation is sum from n equals 1 to infinity of 12 times negative five eighths end quantity to the power of n that means

∑ n=1 to ∞ [12(-5/8)ⁿ]

This is in the form of geometric expression

that is an = ar^(n-1)

therefore we get

a = 12 and r = - 5/8

We have to find the sum.

Sum of infinity of the sequence is expressed as

Sum = a / (1-r)

where a  = first term of the series

and r = common ratio between two consecutive terms

Now we will substitute values of a and r in the above equation

Sum = [tex]\frac{12}{1-(-5/8)}[/tex]

        = [tex]\frac{12}{1 + 5/8}[/tex]

        = [tex]\frac{12}{13/8}[/tex]

Sum = [tex]\frac{96}{13}[/tex]

Hence the sum of given equation is 96/13.

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jessica and robert have two young children. they have $7,000 of qualified child care expenses and agi of $22,000 in 2021

Answers

The allowable child and dependent care credit considering their pre-credit tax liability is $0

The following chart illustrates how their authorized child and dependent care credit was calculated:

If the revenue is less than $22,000, the full 22% would be permitted.

However, the eligible kid expense would only be allowed up to $7,000.

Consequently, the sum would be

= $7,000 × 22%

= $1,540

Since there is already a pre-credit tax liability, $0 should be taken into account because there would be no credit.

Due to their pre-credit tax liability, the available child and dependent care credit is therefore $0.

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a wheat farmer has a storage bin that holds 6,846 1/4 cubic feet.if a bushels of wheat fills 11/4 cubic feet, how many bushels cam the storage bin hold

Answers

The storage bin can hold 5477 bushels.

We have total capacity of the storage bin which is given to us in mixed fraction form.

If we convert this into improper fraction, it is equivalent to =27385/4

Now, in the same way ,we have also given that  some amount of wheat already fills which is also given in mixed fraction form.

If we convert this into improper fraction form, it is equivalent to

=5/4

Now, to find the the number of bushels storage bin maximally hold is =(total volume of storage bin)/(Volume of wheat fills)

=>N = (27385/4)/(5/4)

=>N=27385/5

=>N=5477

Hence, total number of bushels which storage bin can hold is 5477.

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a drawer contains 20 socks. 10 are black. 6 are blue. 4 are red. two socks are taken out at random. what is the probability that one is blue and one is red?

Answers

Chance is also referred to as probability and the probability that one is blue and one is red is 4/19

probability = Number of event/Total samples space

If there are 10 black socks,20 white socks,2 red socks, and 6 blue socks in a drawer, the total number of socks will be the sample space

Sample space = 10+20+2+6

Sample space = 38

Total number of blue and red socks is the event

Number of event one blue and one red = 8 blue socks

Chance that the socks is blue = n(E)/n(S)

Chance that the socks is one red and one blue  = 8/38

Chance that the socks is red and blue = 4/19

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in a casino, you play the following game: you choose a number between 1 and 6 and then throw 3 fair six-sided dice. after tossing, for each die showing your chosen number, the casino pays you $1. In order to play this game, you have to pay the casino a stake of S1 Let X denote your net win after one round of gambling (i.e., the payment received from the casino minus your stake) (a) Determine the state space Sx of X (b) Compute the probability mass function px of X (c) Compute the expected value E[X] of X (d) In general, a game is called a fair game if the net win of the gambler is 0 "on average" Is the above game a fair game? If not, what should be the stake of the gambler in order to make this a fair game? Give a reason for your answer.

Answers

By using the concept of probability, it can be calculated that

a) State space S(x) = {-1, 0, 1, 2}

b) The required probability mass function is

    P(X = -1) = [tex]\frac{125}{216}[/tex]

    P(X = 0)  [tex]= \frac{25}{72}[/tex]

    P(X = 1)  [tex]= \frac{5}{72}[/tex]

    P(X = 2)  [tex]= \frac{1}{216}[/tex]

c) Expected value of X  = -0.5

d) the stake of the gambler in  order to make this a fair game is $0.5

What is probability?

Probability gives us the information about how likely an event is going to occur

Probability is calculated by Number of favourable outcomes divided by the total number of outcomes.

Probality of any event is greater than or equal to zero and less than or equal to 1.

Probability of sure event is 1 and probability of unsure event is 0.

a) Let a number n be chosen between 1 and 6

Three fair six sided dice are thrown

The following cases can occur

1) Number n occur on none of the three dice

2) Number n occur on one dice

3) Number n occur on two dice

4) Number n occur on three dice

Let X denote your net win after one round of gambling (i.e., the payment received from the casino minus your stake)

1) X = 0  -1 = -1

2) X = 1 - 1 = 0

3) X = 2 - 1 = 1

4) X = 3 - 1 = 2

State space S(x) = {-1, 0, 1, 2}

b) P(X = -1) = [tex]{3 \choose 0}(\frac{1}{6})^0(\frac{5}{6})^3 = (\frac{5}{6})^3 = \frac{125}{216}[/tex]

    P(X = 0) = [tex]{3 \choose 1})(\frac{1}{6})(\frac{5}{6})^2 = \frac{25}{72}[/tex]

    P(X = 1) = [tex]{3 \choose 2}(\frac{1}{6})^2\frac{5}{6} = \frac{5}{72}[/tex]

    P(X = 2) = [tex]{3 \choose 3}(\frac{1}{6})^3(\frac{5}{6})^0 = \frac{1}{216}[/tex]

    The required probability mass function is

    P(X = -1) = [tex]\frac{125}{216}[/tex]

    P(X = 0)  [tex]= \frac{25}{72}[/tex]

    P(X = 1)  [tex]= \frac{5}{72}[/tex]

    P(X = 2)  [tex]= \frac{1}{216}[/tex]

c) Expected value of X = [tex]-1 \times \frac{125}{216} + 0 \times \frac{25}{72} + 1 \times \frac{5}{72} + 2\times \frac{1}{216}[/tex]

                                      = [tex]\frac{-125 + 0 + 15 +2}{216}\\[/tex]

                                      = [tex]-\frac{108}{125}[/tex]

                                      = -0.5

d) The gambler looses $0.5 on a average

   So this is not a fair game

   Let the stake of the gambler in  order to make this a fair game be t

   By the problem,

   -0.5 + t = 0

     t = 0 + 0.5

     t = $0.5

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Suppoe Jerome read the following number of page each day. Will he meet hi goal of reading at leat 85 page by the end of the day Friday?

Answers

If p = 6, he will not meet his goal.

If p = 7, he will meet his goal.

If p = 8, he will meet his goal.

What is inequality?

In mathematics, "inequality" refers to a relationship between two expressions or values that are not equal to one another.

Here, we have

Jerome has already read 50 pages of a novel and read p pages each day from Monday to Friday.

If Jerome read at least 85 pages by the end of Friday, inequality will be,

50 + 5p ≥ 85

If Jerome reads 6 pages each day,

If p = 6,

Inequality will be,

50 + 5(6) ≥ 85

80 ≥ 85

It's not true.

Hence, he will not meet his goal.

If p = 7,

Inequality will be,

50 + 5(7) ≥ 85

85 ≥ 85

It's true.

Hence, he will meet his goal.

If p = 8,

Inequality will be,

50 + 5(8) ≥ 85

90 ≥ 85

It's true.

Hence, he will meet his goal.

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given the cost information below, if this firm increases its production and sales from 3 to 4 units per day, given a market price of $2,500 per unit, the profit margin

Answers

If the firm increases its production and sales from 3 to 4 units per day, the profit margin increases.

The correct answer option is option B

What is the profit margin?

Total profit = Total revenue - Total cost

Total revenue = number of units × price of each Units

Market price of the commodity = $2,500

At 3 units:

Total profit = Total revenue - Total cost

= (3 × 2500) - $3000

= $7,500 - $3000

Total profit = $4,500

At 4 units:

Total profit = Total revenue - Total cost

= (4 × $2,500) - $4,100

= $10,000 - $4,100

= $5,900

In conclusion, the profit margin when production is increased from 3 to 4 units will also increase.

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Government data show that 26% of the civilian labor force has at least 4 years of college and that 15% of the labor force works as laborers or operators of machines or vehicles. Can you conclude that because (0.26)(0.15) = .039 about 4% of the labor force are college-educated laborers or operators?
(a) Yes, by the multiplication rule
(b) Yes, by conditional probabilities
(c) Yes,bythelawoflargenumbers
(d) No, because the events are not independent
(e) No, because the events are not mutually exclusive
d

Answers

Option (d)- No, because the events are not independent. Hence we can not conclude that because (0.26)(0.15) = 0.039 about 4% of the labor force are college-educated labors or operators.

We have given that government data show that 26% of the civilian labor force has at least 4 years of college and that 15% of the labor force works as laborers or operators of machine or vehicle.

So here,

event A = 26% of civilian labor force hast at least 4 years of college

event B = 15% of the labor force works as laborers or operators of machines or vehicles

Therefore it is observe that both the events are not independent.

Hence we cannot conclude that because (0.26)(0.15) = 0.039 about 4% of the labor force are college-educated laborers or operators.

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What is an equation of the line that passes through the point ( 8 , 2 ) (8,2) and is parallel to the line x + 4 y = 28 x+4y=28?.

Answers

The equation of the line that passes through the point (8,2) and is parallel to the line x+4y = 28 is y = -x/4+4.

According to the question,

We have the following information;

Point thorough which line is passing = (8,2)

Equation of the line:

x+4y = 28

Now, we will convert this equation into the slope-intercept form:

4y = -x+28

Dividing by 4 on both sides of the equation:

y = -x/4+28/4

y = -x/4+7

Slope of the line = -1/4

We know that the following formula is used to find the equation of the line:

(y-y') = m(x-x')

(y-2) = -1/4(x-8)

y-2 = -x/4+2

Adding 2 on both sides:

y = -x/4+4

Hence, the equation of the line that passes through the point (8,2) and is parallel to the line x+4y = 28 is y = -x/4+4.

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Tulip bulbs are sold in packs of 25 or 40
lily buys a pack of 25 and kiki buys in a pack of 40
what is the smallest number of packs they can each buy so they have the same number of bulbs?
show working please, if solve you will be thanks and marked as the brainliest.

Answers

Answer is 8 packs of 25 and 5 packs of 40 for a total of 200

Step by step

The LCM of 25 and 40 is 200.

200/25 = 8
200/40 = 5

Finding LCM

The multiples of 25 are (25, 50, 75, 100, 125, 150, 175, 200) and multiples of 40 are (40, 80, 120, 160, 200)

So the lowest common number is 200

1) Four cards labeled A, B, C, and D are randomly placed in four boxes labeled A, B, C, and D. Each box receives exactly one card.
In how many ways can the cards be placed in the boxes?
_______ ways
2)four cards labeled A, B, C, and D are randomly placed in four boxes labeled A, B, C, and D. Each box receives exactly one card.
Count the number of elements in the event that no box contains a card with the same letter as the box.
________ elements

Answers

If no box has a card with the same letter as the box, then count the number of elements as 24 ways.

Given that,

Four randomly selected cards with the letters A, B, C, and D are placed in the corresponding boxes. There is exactly one card in each box.

We have to find If no box has a card with the same letter as the box, then count the number of elements.

We know that,

What is the permutation?

A permutation is a mathematical calculation that establishes the number of possible arrangements for a given set, taking into account the arrangement's order.

From the given information:

The permutation approach can be used to represent the four cards that are randomly placed in the four boxes and can be used to express the following:

=⁴P₄

Since no box contains a card that begins with the same letter as the box, it follows that

Card A can be inserted into a box four different ways,

Card B three different ways,

Card C two ways, and

Card D one way.

The four cards' permutation can then be calculated as follows:

⁴P₄=4!/0!=4×3×2×1/1=24.

Therefore, If no box has a card with the same letter as the box, then count the number of elements as 24 ways.

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Can some one help me with this urgent?
Hotel Nights Price (in dollars)
A 3 192
B 5 300
C 7 455
Which hotel costs the least per night?

Answers

B costs the less because 300 divided by 5 equals $60 while A costs $64 and C costs $65

8. in the pcr process, if we assume that each cycle takes 5 minutes, how many fold amplification would be accomplished in an hour?

Answers

The answer to the given question is 4096-fold. If it assumed that each cycle in the PCR process takes 5 minutes, then total 4096-fold amplification could be accomplished in an hour.

What are the steps in PCR Amplification?

PCR is based on 3 simple steps needed for any DNA synthesis reaction. Those steps are: denaturation of the template to the single strands; annealing of the primers to every original strand for a new strand synthesis; and development of the new DNA strands from the primers.

In this case, each cycle takes 5 minutes and doubles the DNA.

Thus, in one hour, there would be 60 / 5 = 12 cycles.

So, the DNA would be amplified 212 = 4096-fold.

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rapheal pays 7$ for 1/2 pound of cashews how much would he pay for one pound

Answers

Answer:

$14

Step-by-step explanation:

since there are 2 halves in a pound we just need to multiply 7 by 2

7x2

14

Hopes this helps please mark brainliest

It's $7 for 1/2 a pound so we have to double it to get our answer so...

$14 would be our answer.

[tex]1/2+1/2=1[/tex]

a sector of a circle has a central angle of $100^\circ$. if the area of the sector is $250 \pi$, what is the radius of the circle?

Answers

The required radius of given circle is 30 units.

What is circle and area of its sector?

A circle is a shut two-layered figure wherein the arrangement of the multitude of focuses in the plane is equidistant from a given point called "focus". Each line that goes through the circle shapes the line of reflection evenness. Likewise, it has rotational evenness around the middle for each point.

Area of sector of circle:

Picture result for What is circle and region of its area?

The equation for the region of the area of a circle is(r2) /360where r is the span of the circle and is the point of the area.

According to question:

Angle of sector = 100 degree, area= 250π

Let radius of circle be r

Then,

area of sector = (r^2) /360

250π =  (r2) 100/360

r^2 = 250×360/100

r = √25×36 = 30 units

Thus, radius of the circle is 30units.

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Suppoe the domain of the propoitional functionP (x, y) conit of pair x and y, where x i 1, 2, or 3 and y i 1, 2, or 3. Write out thee propoition uing dijunction and conjunction. A) ∀x∀yP (x, y) b) ∃x∃yP (x, y) c) ∃x∀yP (x, y) d) ∀y∃xP (x, y)

Answers

These are the preposition for the given conditions:

(P(1,1) ∧ P(1,2) ∧ P(1,3)) ∧ (P(2,1) ∧ P(2,2) ∧ P(2,3)) ∧ (P(3,1) ∧ P(3,2) ∧ P(3,3)).

(P(1,1) ∨ P(1,2) ∨ P(1,3)) ∨ (P(2,1) ∨ P(2,2) ∨ P(2,3)) ∨ (P(3,1) ∨ P(3,2) ∨ P(3,3)).

(P(1,1) ∨ P(1,2) ∨ P(1,3)) ∧ (P(2,1) ∨ P(2,2) ∨ P(2,3)) ∧ (P(3,1) ∨ P(3,2) ∨ P(3,3)).

(P(1,1) ∧ P(1,2) ∧ P(1,3)) v (P(2,1) ∧ P(2,2) ∧ P(2,3)) v (P(3,1) ∧ P(3,2) ∧ P(3,3)).

The domain of the propositional P(x, y) consists of pairs x and y, where x is 1, 2, 3 and y is 1, 2, 3.

What are the disjunction and conjunction?

In logic functions, there are two kinds of compound statements. These are referred to as conjunction and disjunction. A conjunction implies that both statements are correct, whereas a disjunction implies that at least one of the statements is correct. A conjunction connects statements with the word "and," whereas a disjunction connects statements with the word "or."

By using disjunction and conjunction we get,

a) ∀x∀y P(x, y) is written as:

(P(1,1) ∧ P(1,2) ∧ P(1,3)) ∧ (P(2,1) ∧ P(2,2) ∧ P(2,3)) ∧ (P(3,1) ∧ P(3,2) ∧ P(3,3)).

b) ∃x ∃y P (x, y) is written as:

(P(1,1) ∨ P(1,2) ∨ P(1,3)) ∨ (P(2,1) ∨ P(2,2) ∨ P(2,3)) ∨ (P(3,1) ∨ P(3,2) ∨ P(3,3)).

c) ∃x∀y P(x, y)  is written as:

(P(1,1) ∨ P(1,2) ∨ P(1,3)) ∧ (P(2,1) ∨ P(2,2) ∨ P(2,3)) ∧ (P(3,1) ∨ P(3,2) ∨ P(3,3)).

d) ∀y∃x P(x, y)  is written as:

(P(1,1) ∧ P(1,2) ∧ P(1,3)) v (P(2,1) ∧ P(2,2) ∧ P(2,3)) v (P(3,1) ∧ P(3,2) ∧ P(3,3)).

Hence, these are the preposition for the given conditions:

(P(1,1) ∧ P(1,2) ∧ P(1,3)) ∧ (P(2,1) ∧ P(2,2) ∧ P(2,3)) ∧ (P(3,1) ∧ P(3,2) ∧ P(3,3)).

(P(1,1) ∨ P(1,2) ∨ P(1,3)) ∨ (P(2,1) ∨ P(2,2) ∨ P(2,3)) ∨ (P(3,1) ∨ P(3,2) ∨ P(3,3)).

(P(1,1) ∨ P(1,2) ∨ P(1,3)) ∧ (P(2,1) ∨ P(2,2) ∨ P(2,3)) ∧ (P(3,1) ∨ P(3,2) ∨ P(3,3)).

(P(1,1) ∧ P(1,2) ∧ P(1,3)) v (P(2,1) ∧ P(2,2) ∧ P(2,3)) v (P(3,1) ∧ P(3,2) ∧ P(3,3)).

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