The scale on a map is 1 500000
Two towns are 7cm apart on the map.
Work out the actual distance between the towns.
Give your answer in kilometres.

Answers

Answer 1

The actual distance between towns on the map is 350km

What is the ratio?

Ratio is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.

Given;

The scale on the map is 1:5,000,000

Which implies that 1 cm on the map represent 5,000,000 cm in the actual;

Remember that;

1km = 1000m

1m= 100cm

1km= 100000cm

Convert cm to Km;

Divide by 100,000

5,000,000cm= 5,000,000/100,000= 50km

Now 1:5,000,000= 1cm/50km

That means

1 cm on the map represent 50 Km in the actual

So, 7 cm apart on the map

Multiply by 50

7 x 50= 350km

Hence, the answer to this question in kilometers is 350km

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Related Questions

Math expression work

Answers

The given expression is equivalent to the expression -x² + x + 30.

What is the expression?

The expression is the relationship between variables and represented as y = ax + b is an example of a polynomial equation.

Here,
Given expression,
= (5 + x)(6 - x)

Simplifying the expression using distributive property,
= 5 [6 - x] + x [6 - x]
= 30 - 5x + 6x - x²
= -x² + x + 30

Thus, the given expression is equivalent to the expression -x² + x + 30.

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Ozzie Foster deposits $2,000 at the end of each year (ordinary annuity) into an Individual Retirement
Account at Bishop Bank. The account pays 7% compounded annually. a) How much will be in the account in 25 years? b) If Ozzie had deposited the $2,000 at the beginning of each year (annuity due), how much would be in the account in 25 years?

Answers

a) When Ozzie Foster deposits $2,000 at the end of each year,

amount in account after 25 years = $126571.43

b) If Ozzie had deposited the $2,000 at the beginning of each year,

amount in account after 25 years = $135431.43

What is annuity?

An annuity is a financial product that pays out a fixed stream of payments to an individual, primarily used as an income stream for retirees.

Given,

Value of each payment P = $2000

Rate of interest per period in decimal r = 7% = 0.07 per year

Number of years n = 25

a) future value of ordinary annuity

FV = P×((1+r)ⁿ−1) / r

FV = 2000×((1+0.07)²⁵−1) / 0.07

FV = 2000×((1.07)²⁵−1) / 0.07

FV = 2000×(5.43 - 1 )/ 0.07

FV = 2000×4.43/ 0.07

FV = 8860/0.07

FV = $126571.43

b) future value of annuity due

FV = (1+r)P×((1+r)ⁿ−1) / r

FV = (1+0.07) × $2000((1+0.07)²⁵ - 1)/0.07

FV = 1.07 × 2000×((1.07)²⁵−1) / 0.07

FV = 1.07 × 2000×(5.43 - 1 )/ 0.07

FV = 1.07 × 2000 × 4.43 / 0.07

FV = 2140 × 4.43 / 0.07

FV = 9480.2 / 0.07

FV = $135431.43

Hence,

a) $126571.43 is the amount in the account when Ozzie Foster deposits $2,000 at the end of each year.

b) $135431.43 is the amount in the account If Ozzie had deposited the $2,000 at the beginning of each year.

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The test scores for the analytical writing section of a particular standardized test can be approximated by a normal​ distribution, as shown in the figure.

​(a) What is the maximum score that can be in the bottom 5​% of​ scores?

​(b) Between what two values does the middle ​90% of scores​ lie?

the mean is 3.6

the standard deviation is 0.75

Answers

The maximum score that can be in the bottom 5% of scores is 2.64

The middle 90% of scores lie between 2.88 and 4.56.

What is the maximum score that can be in the bottom 5​% of​ scores?

(a) To find the maximum score that can be in the bottom 5% of scores, we need to find the score that corresponds to the 5th percentile of the normal distribution.

Using the mean and standard deviation provided (3.6 and 0.75, respectively), we can use the standard normal table to find that the 5th percentile corresponds to a standard normal score of -1.28. To convert this back to the original scale, we can use the formula:

x = mu + z * sigma

Where

x is the original score, mu is the mean (3.6), z is the standard normal score (-1.28), and sigma is the standard deviation (0.75).

Plugging in the values, we get:

x = 3.6 + (-1.28) * 0.75

x= 2.64

(b)

To find the range of scores that the middle 90% of scores lie between, we need to find the 5th and 95th percentiles of the normal distribution.

Using the mean and standard deviation provided (3.6 and 0.75, respectively), we can use the standard normal table to find that the 5th percentile corresponds to a standard normal score of -1.28 and the 95th percentile corresponds to a standard normal score of 1.28. To convert these back to the original scale, we can use the formula:

x = mu + z * sigma

Where

x is the original score, mu is the mean (3.6), z is the standard normal score, and sigma is the standard deviation (0.75).

Plugging in the values, we get:

x = 3.6 + (-1.28) * 0.75

= 2.88 for the 5th percentile

x = 3.6 + 1.28 * 0.75

= 4.56 for the 95th percentile

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Look at the picture

Answers

the photo is not loading ok this is your photo open this and see now that address now because you are so

In the binomial expression of (1+x)
n
the first three terms are 1+3+4+---. Calculate
the numerical values of n and x, and the values of the fourth term of the expression.

Answers

Answer:

x = 1/3n = 9fourth term = 28/9

Step-by-step explanation:

Given the first three terms of the expansion of (1 +x)^n are 1 +3 +4, you want the values of x and n, and the next term.

Binomial expansion

The first few terms of the binomial expansion of (1 +x)^n are ...

  [tex](1+x)^n=1^n+n\cdot1^{n-1}x+\dfrac{n(n-1)}{2}1^{n-2}x^2+\dfrac{n(n-1)(n-2)}{2\cdot3}1^{n-2}x^3+\dots[/tex]

Comparing terms

Comparing the terms to those given, we have ...

  [tex]nx=3\\\\(nx)((n-1)x)/2=4[/tex]

Expanding the second of these equations, and substituting the first, we get ...

  [tex](nx)(nx -x)=8\qquad\text{multiply by 2}\\\\3(3-x)=8\qquad\text{substitute $nx=3$}\\\\9-8=3x\qquad\text{add $3x-8$}\\\\\boxed{x=\dfrac{1}{3}}\qquad\text{divide by 3}\\\\\dfrac{1}{3}n=3\qquad\text{substitute for $x$ in $nx=3$}\\\\\boxed{n=9}\qquad\text{multiply by 3}[/tex]

Fourth term

Then the fourth term is ...

  [tex]\dfrac{n(n-1)(n-2)}{6}x^3=\dfrac{9\cdot8\cdot7}{6}\cdot\left(\dfrac{1}{3}\right)^3=\boxed{\dfrac{28}{9}}[/tex]

__

Additional comment

Then the expansion is ...

  (1 +1/3)^9 = 1 + 3 + 4 + 28/9 + 14/9 + 14/27 + ...

The n-th term is (11-n)/(3(n-1)) times the term before.

7.4% of what number is $3.33?

Answers

Answer:

Step-by-step explanation:

Answer to this angle question

Answers

Check the picture below.

a train from london to bristol takes 30 km per hour and a train from bristol to london is 50 km per 1 hour when will the two trains meet up.
London to bristol is 100km

Answers

Answer:

In order to find when the two trains will meet up, we can use the concept of relative speed. The relative speed of two trains is the sum of their individual speeds.

In this case, the relative speed is 30 + 50 = 80km/h

Since we know that the distance between London and Bristol is 100km, we can divide the distance by the relative speed to find the time it takes for the two trains to meet up:

100km / 80km/h = 1.25 hours

So, the two trains will meet up in 1.25 hours

Answer:

1 hour 15 minutes

Step-by-step explanation:

Relative Speed

If the two objects are moving in the opposite direction at different speeds, relative speed is the sum of their two speeds:

[tex]v_1+v_2[/tex]

Using the formula:

[tex]\boxed{\sf Time=\dfrac{Distance}{Speed}}[/tex]

Therefore:

[tex]t=\dfrac{d}{v_1+v_2}[/tex]

where:

v₁ is the first body’s speed.v₂ is the second body’s speed.d is the distance between the two bodies.t is the time when the two bodies meet.

Given:

v₁ = 30 km/hv₂ = 50 km/hd = 100 km

Substitute the given values into the formula to find the time at which the two trains meet:

[tex]\implies t=\dfrac{100}{30+50}=\dfrac{100}{80}=1.25\; \sf hours=1\; hour\;15\;mins[/tex]

Therefore, the two trains meet at 1 hour 15 minutes.

Calculate ( – 2 – 3i)^4. Give your answer in a + bi form

Answers

Answer:

-34 - 24i

Step-by-step explanation:

To calculate ( – 2 – 3i)^4, we can use the property that (a + bi)^n = a^n + (n*a^(n-1)b)i + (na^(n-2)*b^2)i^2 + ...

So, ( – 2 – 3i)^4 = (-2 - 3i) * (-2 - 3i) * (-2 - 3i) * (-2 - 3i)

= -2^4 - 2^3 * 3i - 2^2 * 3^2i^2 - 2 * 3^3i^3 - 3^4i^4

= -16 - 24i + 18i^2

= -16 - 24i -18

= -34 - 24i

What is the justification for step 3 in the solution process?

0.8a − 0.1a = a − 2.5
Step 1: 0.7a = a − 2.5
Step 2: -0.3a = -2.5
Step 3: a = 8.3


A.
the division property of equality
B.
the addition property of equality
C.
the subtraction property of equality
D.
combining like terms

Answers

Answer:

Letter A

Step-by-step explanation:

The justification for step 3 in the solution process is the subtraction property of equality. This property states that if two numbers are subtracted from each other on both sides of an equation, the two sides remain equal. In this case, step 3 is subtracting -0.3a from both sides of the equation, which results in a = 8.3.

Answer: A

Step-by-step explanation:

determine the equation of the line, in slope intercept form, that is perpendicular to 4x+2y+18=0 and has a y-intercept of the line 3x-y+8=0

Answers

The slope intercept equation of the line that is perpendicular to 4x+2y+18=0 and has a y-intercept of the line 3x-y+8=0 is x-2y+16=0.

What is equation?

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign. A mathematical phrase with two equal sides separated by an equal sign is called an equation. An example of an equation is 4 + 6 = 10.

Here,

4x+2y+18=0

y=-2x-9

m=-2

m1=1/2

3x-y+8=0

y=3x+8

y-intercept=(0,8)

y=mx+c

y=1/2x+8

2y=x+16

x-2y+16=0

The equation of the line, in slope intercept form, that is perpendicular to 4x+2y+18=0 and has a y-intercept of the line 3x-y+8=0 is x-2y+16=0.

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Below is the graph of a system of two linear equations.

Answers

Answer:

A

Step-by-step explanation:

y + 4 = x is represented in this equation as -3 + 4 = 1

x + y = -6 is represented in this equation as -4 + -2 = -6

"A" fits these equations and the coordinate attached: (-1, -5) matches the point of intersection.

These polygons are congruent. That means all their corresponding parts are equal in measure. Solve for x.

Answers

The measures of x and y in the congruent polygons are:

x = 7

y = 8

What are Congruent Polygons?

Congruent polygons are two or more polygons with the same number of sides and the same length for each side. In other words, they are polygons that have the same shape and size.

Two polygons are congruent if and only if it is possible to superimpose one polygon over the other by using a combination of translation, rotation and reflection. Congruent polygons have the same area and perimeter.

Therefore:

m<E = m<A

Substitute the values:

4y - 4 = 28

4y = 28 + 4

4y = 32

4y/4 = 32/4

y = 8

m<F = m<B

Substitute:

10x + 65 = 135

10x = 135 - 65

10x = 70

10x/10 = 70/10

x = 7

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NO LINKS!!
Part 2: Graph the polygon with the given vertices and its image after the transformation. Label all vertices in both the preimage and image using the correct notation.

4. A(2, 1), B(3, -1), C(4, 2), D(3, 3)
Reflection : in the line x = -1

5. A(2, 3), B(1, 4), C(3, 4)
Rotation: 180° about the origin

6. A(5, -2), B(5, 2), C(3, 1), D(2, -1)
Rotation: 270° about the origin

Answers

Answer:

Question 4:

A' (-4, 1)B' (-4, -1)C' (-6, 2)D' (-5, 3)

Question 5:

A' (-2, -3)B' (-1, -4)C' (-3, -4)

Question 6:

A' (-2, -5)B' (2, -5)C' (1, -3)D' (-1, -2)

Step-by-step explanation:

Question 4

Given vertices of the pre-image:

A = (2, 1)B = (2, -1)C = (4, 2)D = (3, 3)

If the pre-image is reflected in the line x = -1, the transformation rule is:

[tex](x, y) \rightarrow (x-2(x+1), y)[/tex]

Therefore the vertices of the image are:

A' = (2 - 2(2 + 1), 1) = (-4, 1)B' = (2 - 2(2 + 1), -1) = (-4, -1)C' = (4 - 2(2 + 1), 2) = (-6, 2)D' = (3 - 2(2 + 1), 3) = (-5, 3)

Question 5

Given vertices of the pre-image:

A = (2, 3)B = (1, 4)C = (3, 4)

If the pre-image is rotated 180° about the origin, the transformation rule is:

[tex](x, y) \rightarrow (-x,-y)[/tex]

Therefore the vertices of the image are:

A' = (-2, -3)B' = (-1, -4)C' = (-3, -4)

Question 6

Given vertices of the pre-image:

A = (5, -2)B = (5, 2)C = (3, 1)D = (2, -1)

If the pre-image is rotated 270° about the origin, the transformation rule is:

[tex](x, y) \rightarrow (y,-x)[/tex]

If the direction of a rotation is not specified, then it is counterclockwise.

Therefore the vertices of the image are:

A' = (-2, -5)B' = (2, -5)C' = (1, -3)D' = (-1, -2)

It's raining, and Vince and his friends are stuck inside. They decide to play a marble game called Revenge. To start, Vince divides a bag of m marbles evenly among the 3 players. Each player gets 10 marbles.

Answers

The total number of marbles are 30.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Given that, to start, Vince divides a bag of m marbles evenly among the 3 players. Each player gets 10 marbles.

Here, m/3 =10

m=30

Therefore, the total number of marbles are 30.

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Transformed functions

See image below:

Answers

The point corresponding to the transformed function y=f(x/x)+1 is approximately (-4, 4.25), (-2, 2.5), (0, 1), (1, -0.5), (3, 1). 

How to find the point corresponding to the transformed function y = f(x/x) + 1 ?

we need to substitute x/x = 1 for the argument of the function f(x) and add 1 to the result.

Transformed point on point y on f(x) = f(x/x) + 1

(x, f(x)) (x, f(x/x) + 1)

(-4, 5) (-4, f(-2) + 1) ≒ (-4, 4.25)

(-2, 3) (-2, f(-1) + 1) ≈ (-2, 2.5)

(0, 0) (0, f(0) + 1)

= (0, 1)

(1, -2) (1, f(1) + 1) ≈ (1, -0.5)

(3, -4) (3, f(3/3) + 1) ≈ (3, 1)

Note that for the point (-4,5) you have to substitute x/x = -1/2 instead of x/x = 2. This gives x = -8. So the corresponding transformed point is (-4, f(-8) + 1) ≈ (-4, 2.75).

So the point corresponding to the transformed function y=f(x/x)+1 is approximately

(-4, 4.25), (-2, 2.5), (0, 1), (1, -0.5), (3, 1). 

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PLEASE HELPPPPPPPPP!!!!!!!

Answers

Answer:

A 10

Step-by-step explanation:

a proportional relationship is defined as

y = kx

k is the constant of proportionality, because it is constant for this function for any value of x.

it is usually called the slope of the line or rate of change.

these are special lines : lines that go through the origin (0, 0).

and for these lines people often call k the constant of proportionality.

as we can see right in the given equation, this constant of proportionality is 10.

Is the point (-1, 6) on the lines below? y = 5x + 3 y = 2x + 4​

Answers

The point (-1, 6) is on the lines y = 5x + 3 and y = 2x + 4​

How to determine if the points is on the line

From the question, we have the following parameters that can be used in our computation:

Point = (-1, 6)

Also, we have

y = 5x + 3

y = 2x + 4​

Substitute the known values in the above equation, so, we have the following representation

6 = 5(-1) + 3 = -2 -- false

6 = 2(-1) + 4 = 2 --- false

Hence, the point is not one the line

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happy paws charges 21.00 plus 3.50 per hour to keep a dog during the day. Woof watchers charges 10.00 plus 4.75 per hour. Complete the equation and solve it to find for how many hours the total cost of services is equal. Use the variable h to represent the number of hours

Answers

Answer: 8.8 hours

Step-by-step explanation:

To start off, we’ll make an equation that “connects” both companies:

10 + 4.75h = 21 + 3.5h (we put h to represent the number of hours)

Move all similar terms to one side:

4.75h - 3.5h = 21 - 10

Simplify:

1.25h = 11

h = 8.8


I hope this helps!

Sum up the series 2/3+5/9+8/27+11/81+..... to n terms​

Answers

Hope it helps.

If you have any query, feel free to ask.

The lengths of the legs of a right triangle are 7 in. and 2 in.

What is the length of the hypotenuse?


Enter your answer rounded to the nearest tenth

Answers

Answer: To find the length of the hypotenuse of a right triangle, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the lengths of the other two sides. The theorem is written as c² = a² + b², where c is the length of the hypotenuse and a and b are the lengths of the other two sides.

In this problem, we are given that the lengths of the legs of the right triangle are 7 inches and 2 inches. We can substitute these values into the Pythagorean theorem and solve for c, the length of the hypotenuse.

So, we have c² = 7² + 2².

So, c² = 49 + 4

So, c² = 53

Now, we can take the square root of both sides of the equation, since c² = 53, we can say c = √53

To round to the nearest tenth, we look at the digit in the thousandths place (the 3rd digit after the decimal point). Since 3 is greater than or equal to 5, we round up, so c = 7.28, so the hypotenuse is 7.28 inches.

Step-by-step explanation:

Answer:10

Step-by-step explanation: round it together and you get 10

hello , please help !

Answers

Answer:

4,7

Step-by-step explanation:

4,7

12 People fit comfortably in a 5 feet by 11 feet area. Use this value to estimate the size of a crowd that
is 10 feet deep on both sides of the street along a 3-mile section of a parade route.

Answers

Answer:

Step-by-step explanation:

Assuming that there are no sidewalks or other obstructions, the estimated size of the crowd along a 3-mile section of the parade route would be approximately 3,780,400 people. This calculation is based on the assumption that people will be standing shoulder to shoulder and that each person will take up an area of 5 feet by 11 feet. This would mean that for each mile of the parade route, there would be 1,260,800 people standing (12 people x 10 feet x 5280 feet). Multiplying this by 3 gives us 3,780,400 people.

Answer:

12 people fitting in an area of 5*5 = 25 ft². Area of the street: 3 miles = 3*5280 ft = 15840 ft 25 feet on both sides. So, the total area in which the crowd is sparsed is: A = 15840*25*2= 792000 ft². Now we apply the ratio: People over area. Applying cross multiplication: 25x = 12*792000 x = (12*792000)/25 x = 380160

Step-by-step explanation:

Which function is positive for the entire interval [–3, –2]? On a coordinate plane, a curved line with a minimum value of (0, negative 3) crosses the x-axis at (negative 3, 0) and (3, 0), and crosses the y-axis at (0, negative 3). On a coordinate plane, a curved line with a minimum value of (2, negative 3) crosses the x-axis at (negative 1, 0) and (5, 0), and crosses the y-axis at (0, negative 1.5). On a coordinate plane, a curved line with a minimum value of (2, 4) and a maximum value of (0.5, 6), crosses the x-axis at (negative 1.5, 0) and crosses the y-axis at (0, 5). On a coordinate plane, a curved line with a minimum value of (negative 1.75, negative 3.9) and a maximum value of (0, 2), crosses the x-axis at (negative 2.2, 0), (negative 0.75, 0), and (0.75, 0), and crosses the y-axis at (0, 2).

Answers

The function that is positive for the entire interval [-3, -2] is given as follows:

On a coordinate plane, a curved line with a minimum value of (2, negative 3) crosses the x-axis at (negative 1, 0) and (5, 0).

When is a function positive over an entire interval?

A function is positive over an interval if the values of y of the function are above zero for the entire interval.

A function is negative over an interval if the values of y of the function are below zero for the entire interval.

For the function in this problem, we have that:

It is a concave up parabola with roots at x = -1 and x = 5.The minimum value is at x = 2.

As the function is concave up, it is positive to the left of the smaller root at x = -1, that is, positive for all x < -1, hence the correct option.

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True or false ? Not all consumers act according to the classical definition of a rational consumer

Answers

Answer:

this statement is true .............

Joey is making accessories for the soccer team. He uses 876.52 inches of fabric on headbands for 31 players and 3 coaches. He also uses 288.61 inches of fabric on wristbands for just the players. How much fabric was used on a headband and wristband for each player?

Answers

The number of fabric used for headband and wristband for each player is 25.8in and 9.3 in

What is world problem?

Word problem is a verbal description of a problem situation wherein one or more questions are posed, the answers to which can be obtained by the application of mathematical operations.

Represent the number of fabric used on headband by x and the number of fabric used on wristband by y

Therefore;

31x +3x = 876.52

34x = 876.52

divide both sides by 34

x = 876.52/34

x = 25.8 inches

31y = 288.61

dive both sides by 31

y = 288.61/31

y = 9.3 inches

therefore 25.8 inches of fabrics and 9.3 inches of fabrics are used on headband and wristband of each player

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The amount of light reflected up through the top of a
diamond (brilliancy) can be maximized using the ratio between the width of the
diamond and the depth of the diamond. A gemologist has a diamond with a width of
80 millimeters. If x represents the depth of the diamond, then 80/x
represents the
brilliancy ratio y. Describe the reasonable domain and range values. Graph the function.

Answers

The domain and range are (0 , ∞) and (0 , ∞).

What is domain ?

The collection of all potential inputs for a function is its domain. For instance, the domain of f(x)=x2 and g(x)=1/x are all real integers with the exception of x=0.

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

The set of all initial elements in ordered pairs constitutes the domain (x-coordinates). The set of all second items in ordered pairs is the range (y-coordinates).

Given

y = 80 / x

As per the graph the domain and range are

domain : (0 , ∞)

{depth of the diamond > 0 }

range : (0 , ∞)

{ratio > 0}

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An education researcher claims that at most 5% of working college students are employed as teachers or teaching assistant. in random sample of 400 working college students, 6% are employed as teachers or teaching assistants. alpha=0.05,
1. Is there enough evidence to reject the researcher claim?
2. find the critical values and identify the rejection.
3. find the standardized test statistic z
4. decide whether to rejector fail to reject null hypothesis and interpret the decision.

Answers

Answer:

Step-by-step explanation:

Is there enough evidence to reject the researcher claim?

To determine if there is enough evidence to reject the researcher's claim, we can perform a hypothesis test with a null hypothesis of p <= 0.05 (at most 5% of working college students are employed as teachers or teaching assistants) and an alternative hypothesis of p > 0.05 (more than 5% of working college students are employed as teachers or teaching assistants).

Find the critical values and identify the rejection.

For a one-tailed test with a significance level of alpha = 0.05, the critical value for a z-test would be 1.645. This means that if the calculated z-score is greater than 1.645, we would reject the null hypothesis.

Find the standardized test statistic z

To find the standardized test statistic z, we can use the formula:

z = (p-hat - p0) / (sqrt(p0 * (1 - p0) / n))

where p-hat is the sample proportion of working college students employed as teachers or teaching assistants (6%), p0 is the proportion specified in the null hypothesis (5%), and n is the sample size (400).

z = (0.06 - 0.05) / sqrt(0.05 * (1 - 0.05) / 400)

z = 0.1 / 0.015811388300841898

z = 6.317

Decide whether to reject or fail to reject the null hypothesis and interpret the decision.

Since the calculated z-score (6.317) is greater than the critical value (1.645), we can reject the null hypothesis. This means that there is enough evidence

The chart below describes the speed of four painters. Which painter is the fastest?

Answers

Painter D

This because if you divide the sq ft by the number of hours its the highest. Painter A is 200, paintee B is 225, painter c is 120, and painter d is 250.

the ratio of height and length of a store room is 5:4 and the ratio of height and breadth is 2:3. find the area of the floor of the store room if the total area of the four walls of the store room is 2760m^2

Answers

Answer: The area of the floor of the store room is 1080 m^2

Step-by-step explanation:

We can begin by using the information provided about the ratios of the dimensions of the store room to set up a system of equations.

Let's call the height of the store room h, the length l, and the breadth b.

From the first ratio given, we know that:

h/l = 5/4

From the second ratio given, we know that:

h/b = 2/3

We can also use the information about the total area of the four walls to set up another equation.

The total area of the four walls is the sum of the area of the top and bottom walls (length x height) and the area of the two side walls (breadth x height).

So we have:

2lh + 2bh = 2760

We can now use the first two equations to solve for one of the variables in terms of the other two.

We can cross-multiply and simplify the first equation:

l = (4/5)h

We can cross-multiply and simplify the second equation:

b = (3/2)h

We can now substitute these expressions for l and b into the equation for the total area of the four walls:

2(4/5)h^2 + 2(3/2)h^2 = 2760

Solving for h, we get:

h = 30

Now that we know the value of h, we can use the equations l = (4/5)h and b = (3/2)h to find the values of l and b.

l = (4/5)h = (4/5)(30) = 24

b = (3/2)h = (3/2)(30) = 45

Now we have all the information we need to find the area of the floor, which is the product of the length and breadth of the store room

Area of floor = lb = 2445 = 1080 m^2

Explanation: By using the information about the ratios of the dimensions of the store room and the total area of the four walls, we set up a system of equations and used algebra to solve for the height, length and breadth of the store room. With this information, we were able to find the area of the floor of the store room.

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