The sign below advertises a sale on canned tomatoes.
SALE
Canned Tomatoes $1.
Limit 8 cans per customer
Mrs. Gonzalez wants to buy 10 cans at the sale price.
Which expression represents the number of cans by
which she will exceed the limit?
O 10-8
O8-10
O8+2
O 10+ 2

Answers

Answer 1
The answer is A: 10-8
Why? Because if the limit for the number of cans at the sale price is 8 and Mrs. Gonzalez wants to buy 10 she will go 2 over the allowed limit. And the expression 10-8 = 2 cans.

Check:
We can check this by adding 2+8 which equals 10

Hoped this helped :)

Related Questions

Boyd spins a spinner with sections labeled A-H a total of 96 times. The letter A comes up 12 times. What is the relative frequency of A as a percent?​

Answers

The relative frequency of A is 12.5% when expressed as a percentage. This means that out of the 96 spins, A appeared 12 times, accounting for approximately 12.5% of the total spins. Relative frequency allows us to compare the occurrence of a specific event (in this case, A coming up) to the total number of events (the total spins), giving us a sense of its proportion in the data set.

To find the relative frequency of A as a percent, we need to divide the number of times A comes up by the total number of spins, and then multiply by 100 to express it as a percentage.

Given that the spinner was spun a total of 96 times, and A came up 12 times, we can calculate the relative frequency of A as follows:

Relative frequency of A = (Number of times A comes up / Total number of spins) x 100

Relative frequency of A = (12 / 96) x 100

Simplifying the calculation:

Relative frequency of A = 0.125 x 100

Relative frequency of A = 12.5%

The relative frequency of A is 12.5% when expressed as a percentage.

This means that out of the 96 spins, A appeared 12 times, accounting for approximately 12.5% of the total spins. Relative frequency allows us to compare the occurrence of a specific event (in this case, A coming up) to the total number of events (the total spins), giving us a sense of its proportion in the data set.

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2. The distance between the school and Reena's house is 1 km 480 m. Every
day she walks both ways. What distance does she cover in 6 days of a week?

Answers

Answer: To find the total distance Reena covers in 6 days of a week, we need to consider the distance between her school and house for a single round trip and then multiply it by 6.

Given that the distance between the school and Reena's house is 1 km 480 m, we can add the distance for a one-way trip to get the total round trip distance.

Total round trip distance = 1 km 480 m + 1 km 480 m = 2 km 960 m

Now, to find the distance covered by Reena in 6 days, we multiply the round trip distance by 6:

Total distance covered in 6 days = 2 km 960 m * 6

Converting the distance to meters for easier calculation:

2 km 960 m = 2960 m

Total distance covered in 6 days = 2960 m * 6

Calculating the total distance covered:

Total distance covered in 6 days = 17760 m

Therefore, Reena covers a total distance of 17,760 meters (or 17.76 kilometers) in 6 days of a week.

A group of students volunteered to help a fruit farm owner pick fruits. The total number of bananas and Lychees they picked was 384. The total number of bananas and mangos was 258. The number of mangos was
4
7
of Lychees. How many bananas were there?

Answers

The number of bananas is 90.

Let's assume the number of bananas is represented by 'B', the number of lychees is represented by 'L', and the number of mangos is represented by 'M'.

From the given information, we have the following equations:

B + L = 384  (equation 1)

B + M = 258  (equation 2)

M = (4/7) * L  (equation 3)

To solve for the number of bananas, we need to eliminate the variables 'L' and 'M' from the equations. We can do this by substituting equation 3 into equation 2:

B + (4/7) * L = 258

To simplify this equation, we can multiply through by 7:

7B + 4L = 1806  (equation 4)

Now we can solve equations 1 and 4 simultaneously. We can multiply equation 1 by 4 and equation 4 by -1 to eliminate 'L':

4B + 4L = 1536  (equation 5)

-7B - 4L = -1806  (equation 6)

Adding equations 5 and 6, we get:

-3B = -270

B = 90

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which of the following are the missing steps to complete the equation when solving for x? 2× -6= 4(×+2) 2×-6= 4×+8 ×=-7 a. the addition of the 4× variable from one side to move the × to one side and the subtraction of the 6 to the other side of the equation so × is on one side and the other variable is the other side of the equal sign. b. the multiplication of the 4x variable from one side to move the x to one side​

Answers

The missing step a is the addition of the 4x variable from one side and the subtraction of the 6 to the other side of the equation to isolate x.

The missing steps to complete the equation when solving for x in the equation 2x - 6 = 4(x + 2) are as follows:

a. The addition of the 4x variable from one side to move the x to one side and the subtraction of the 6 to the other side of the equation so x is on one side and the other variable is on the other side of the equal sign.

The correct choice is a. This step involves distributing the 4 to both terms inside the parentheses, resulting in 2x - 6 = 4x + 8. To isolate the x variable, we need to move all the x terms to one side and the constant terms to the other side. Subtracting 4x from both sides gives -6 = 2x + 8. Finally, subtracting 8 from both sides yields -14 = 2x. Dividing both sides by 2 gives x = -7.

Choice b is incorrect because multiplying the 4x variable is not necessary or involved in this particular equation.

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Sixty men can build a wall in 40days but though they begin the work together, 55 men quit every ten days. The Time needed to build the wall is?​

Answers

It would take 370 days to build the wall with the given conditions.

If 60 men can build a wall in 40 days, then the total man-days required to build the wall is:

60 men x 40 days = 2400 man-days

However, 55 men quit every ten days, which means that after 10 days, there are only 60 - 55 = 5 men left to work on the wall. After 20 days, there are only 5 - 55 = -50 men left, which means that the remaining 5 men cannot work any faster than they were already working. Therefore, we can assume that the remaining 5 men complete the wall on their own.

The number of man-days required for the first 10 days is:

60 men x 10 days = 600 man-days

The number of man-days required for the second 10 days is:

5 men x 10 days = 50 man-days

The total number of man-days required for the first 20 days is:

600 man-days + 50 man-days = 650 man-days

The remaining work can be completed by the 5 men in:

2400 man-days - 650 man-days = 1750 man-days

Therefore, the total time needed to build the wall is:

20 days + 1750 man-days / 5 men = 20 + 350 days = 370 days

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In witch quadrant is the point(-10,-1)?

Answers

Answer:

quadrant IV

Step-by-step explanation:

quadrant I - (+,+)

quadrant II - (-,+)

quadrant III - (+,-)

quadrant IV - (-,-)

Prove the trigonometric identity
(tan x + cot x)/(csc x * cos x) = sec^2 x​

Answers

Answer:

[tex]\dfrac{\tan x + \cot x}{\csc x \cos x}=\sec^2 x[/tex]

[tex]\boxed{\dfrac{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}{\dfrac{1}{\sin x} \cdot \cos x}}=\sec^2 x[/tex]

[tex]\boxed{\dfrac{\dfrac{\sin^2 x}{\sin x\cos x} + \dfrac{\cos^2 x}{\sin x \cos x}}{\dfrac{\cos x}{\sin x}}}=\sec^2 x[/tex]

[tex]\boxed{\dfrac{\dfrac{\sin^2 x+\cos^2 x}{\sin x\cos x}}{\dfrac{\cos x}{\sin x}}}=\sec^2 x[/tex]

[tex]\boxed{\dfrac{\dfrac{1}{\sin x\cos x}}{\dfrac{\cos x}{\sin x}}}=\sec^2 x[/tex]

[tex]\boxed{\dfrac{1}{\sin x\cos x} \cdot \dfrac{\sin x}{\cos x}}=\sec^2 x[/tex]

[tex]\dfrac{1}{\cos^2x}=\sec^2x[/tex]

[tex]\sec^2x=\sec^2x[/tex]

Step-by-step explanation:

Given trigonometric identity:

[tex]\dfrac{\tan x + \cot x}{\csc x \cos x}=\sec^2 x[/tex]

[tex]\textsf{Use the identities\;\;$\tan x = \dfrac{\sin x}{\cos x}$\;,\;$\cot x=\dfrac{\cos x}{\sin x}$\;\;and\;\;$\csc x=\dfrac{1}{\sin x}$}:[/tex]

[tex]\boxed{\dfrac{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}{\dfrac{1}{\sin x} \cdot \cos x}}=\sec^2 x[/tex]

Simplify the denominator and make the fractions in the numerator like fractions:

[tex]\boxed{\dfrac{\dfrac{\sin^2 x}{\sin x\cos x} + \dfrac{\cos^2 x}{\sin x \cos x}}{\dfrac{\cos x}{\sin x}}}=\sec^2 x[/tex]

[tex]\textsf{Apply\;the\;fraction\;rule\;\;$\dfrac{a}{b}+\dfrac{c}{b}=\dfrac{a+c}{b}$\;to\;the\;numerator}:[/tex]

[tex]\boxed{\dfrac{\dfrac{\sin^2 x+\cos^2 x}{\sin x\cos x}}{\dfrac{\cos x}{\sin x}}}=\sec^2 x[/tex]

[tex]\textsf{Use\;the\;identity\;\;$\sin^2x+\cos^2x=1$}:[/tex]

[tex]\boxed{\dfrac{\dfrac{1}{\sin x\cos x}}{\dfrac{\cos x}{\sin x}}}=\sec^2 x[/tex]

[tex]\textsf{Apply\;the\;fraction\;rule\;\;$\dfrac{a}{\frac{b}{c}}=a \cdot \dfrac{c}{b}$}:[/tex]

[tex]\boxed{\dfrac{1}{\sin x\cos x} \cdot \dfrac{\sin x}{\cos x}}=\sec^2 x[/tex]

Cancel the common factor sin x, and apply the exponent rule aa = a² to the denominator:

[tex]\dfrac{1}{\cos^2x}=\sec^2x[/tex]

[tex]\textsf{Use the identity\;\;$\dfrac{1}{\cos x}=\sec x$}:[/tex]

[tex]\sec^2x=\sec^2x[/tex]

Answer:

The proof of the trigonometric identity:

We can start by expanding the numerator and denominator. In the numerator, we can use the trigonometric identities tan x = sin x / cos x and cot x = cos x / sin x.

In the denominator, we can use the trigonometric identity csc x = 1 / sin x. This gives us:

[tex]\frac{(tan x + cot x)}{(csc x * cos x) } = \frac{(\frac{sin x }{ cos x}) + (\frac{cos x }{sin x)}}{(\frac{1}{ sin x}) * cos x}[/tex]

`We can then cancel the sin x terms in the numerator and denominator. This gives us:

[tex]\frac{(tan x + cot x)}{(csc x * cos x) } = \frac{1 + 1}{(\frac{1 }{sin x}) * cos x}[/tex]

We can then multiply the numerator and denominator by sin x. This gives us:

[tex]\frac{(tan x + cot x)}{(csc x * cos x) } = \frac{sin x + sin x}{\frac{1 }{cos x}}[/tex]

We can then simplify the expression. This gives us:

[tex]\frac{(tan x + cot x)}{(csc x * cos x) } = \frac{2sin x}{\frac{1 }{cos x}} = \frac{2sin x}{cos x} = 2tan x[/tex]

Finally, we can use the trigonometric identity tan^2 x = sec^2 x - 1 to get:

[tex]2tan x =\frac{ 2tan^2 x }{ (sec^2 x - 1)}[/tex]

This gives us the following identity:

[tex]\frac{(tan x + cot x)}{(csc x * cos x) } = sec^2 x[/tex]

This completes the proof of the trigonometric identity.

If sin x=3/5 and x is in the second quadrant, find the value of cosx.

Answers

The cos x = adjacent side / hypotenuse = -4/5.Hence, the value of cos x is -4/5.

Given that sin x = 3/5 and x is in the second quadrant. We need to find the value of cos x.

To solve this problem, we will use the trigonometric identity.Sin²x + Cos²x = 1.We know sin x, which is in the second quadrant. Let's construct a right-angled triangle to find the value of cos x.

In the second quadrant, the value of sin x is positive, while the value of cos x is negative. This means that the adjacent side of the triangle is negative. In this case, we can label the adjacent side as -4 and the hypotenuse as 5.

Using the Pythagorean theorem, we can solve for the opposite side.

Opposite side = √(hypotenuse² - adjacent side²)

Opposite side = √(5² - (-4)²)

Opposite side = √(25 - 16)

Opposite side = √9

Opposite side = 3

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at the movies three candy bars and two sodas cost $14.00. Four candy bars and three sodas cos $19.50. How much is the soda?

Answers

The cost of a soda is $2.50. By solving the system of equations formed from the given information, the value of S is determined to be 2.50.

To find the cost of the soda, let's set up a system of equations using the given information. Let's assume the cost of a candy bar is represented by 'C' and the cost of a soda is represented by 'S.'

From the first statement, we can write the equation:

3C + 2S = 14.00 ----(Equation 1)

From the second statement, we can write the equation:

4C + 3S = 19.50 ----(Equation 2)

To solve the system of equations, we can use a method called substitution. Rearranging Equation 1, we get:

S = (14.00 - 3C) / 2

Substituting this expression for S into Equation 2, we have:

4C + 3((14.00 - 3C) / 2) = 19.50

Simplifying this equation, we get:

4C + (42.00 - 9C) / 2 = 19.50

8C + 42.00 - 9C = 39.00

-C + 42.00 = 39.00

-C = 39.00 - 42.00

-C = -3.00

C = 3.00

Now we can substitute the value of C back into Equation 1 to find the value of S:

3(3.00) + 2S = 14.00

9.00 + 2S = 14.00

2S = 14.00 - 9.00

2S = 5.00

S = 5.00 / 2

S = 2.50

Therefore, the cost of a soda is $2.50.

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Jamar's Social Security benefit at full retirement age will be $1,876.00 per month. Determine how much his monthly benefit will be reduced if he begins collecting 46 months early.

$415.65
$453.37
$489.76
$501.15

Answers

If Jamar begins collecting 46 months early , his monthly benefit will be reduced is C. $489.76

To calculate the reduction in Jamar's monthly Social Security benefit if he begins collecting 46 months early, we need to consider the reduction factor for early retirement.

As of my knowledge cutoff in September 2021, for individuals who start collecting Social Security benefits before reaching full retirement age, the reduction factor is approximately 0.00556 (0.56% per month).

To calculate the reduction, we multiply the number of months by the reduction factor and then multiply that by the full retirement benefit amount:

Reduction = (Number of Months Early * Reduction Factor) * Full Retirement Benefit

Given:

Number of Months Early = 46

Full Retirement Benefit = $1,876.00 per month

Reduction Factor = 0.00556

Plugging in the values into the formula, we have:

Reduction = (46 * 0.00556) * $1,876.00

Reduction ≈ 0.25576 * $1,876.00

Reduction ≈ $479.82

Therefore, the monthly benefit reduction if Jamar begins collecting 46 months early would be approximately $479.82. Among the answer choices provided, the closest option is $489.76. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Jamar's Social Security benefit at full retirement age will be $1,876.00 per month. Determine how much his monthly benefit will be reduced if he begins collecting 46 months early.

A. $415.65

B. $453.37

C. $489.76

D. $501.15

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Is it true that m is parallel to line n? Please help

Answers

Answer:

B

Step-by-step explanation:

Line m has a slope of -2, -4

Line n has a slope of -3, -5

Find the value of X.

Answers

Answer:

  x = 30

Step-by-step explanation:

You want external segment x of a secant with a total length of 45 from a point where another secant has external length 27 and total length 50.

Secant relations

The product of the external length and the total length of each secant is the same:

  45x = 50(27)

  x = 50(27)/45

  x = 30

<95141404393>

This data is from a sample. Calculate the mean, standard deviation, and variance. Suggestion: use technology. Round answers to two decimal places.

x
22.8
49.8
17.5
44.1
33.2
20.6
43.2
37.7


Mean =


Standard Deviation =


Variance =


Ooops - now you discover that the data was actually from a population! So now you must give the population standard deviation.

Population Standard Deviation =

Answers

1. Mean = 33.61

2. Standard Deviation = 11.3284

3. Variance = 128.33

What are the mean, standard deviation, and variance?

The given data are: [tex]22.8, 49.8, 17.5, 44.1, 33.2, 20.6, 43.2, 37.7[/tex]

To get mean, we will sum up all the numbers and divide by the total count. The mean is:

= (22.8 + 49.8 + 17.5 + 44.1 + 33.2 + 20.6 + 43.2 + 37.7) / 8

= 268.9 / 8

= 33.62

Standard Deviation: [tex]\sqrt((22.8 - 33.61)^2 + (49.8 - 33.61)^2 + (17.5 - 33.61)^2 + (44.1 - 33.61)^2 + (33.2 - 33.61)^2 + (20.6 - 33.61)^2 + (43.2 - 33.61)^2 + (37.7 - 33.61)^2) / 8[/tex]

= [tex]\sqrt{128.3336}[/tex]

= 11.3284420818

= 11.3284

Variance = (Standard Deviation)^2

Variance = [tex]11.3284 ^2[/tex]

Variance = 128.33264656

Variance = 128.33.

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The machinery in a cereal plant fills 350 g boxes of cereal. The specifications for the machinery permit for a certain amount of fill tolerance. It is found that the weights of filled cereal boxes are normally distributed with a mean of 350 g and a standard deviation of 4 g. What is the probability that a box of cereal is under filled by 5 g or more?

Answers

There is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.

To find the probability that a box of cereal is underfilled by 5 g or more, we need to calculate the probability of obtaining a weight measurement below 345 g.

First, we can standardize the problem by using the z-score formula:

z = (x - μ) / σ

Where:

x = the weight value we want to find the probability for (345 g in this case)

μ = the mean weight (350 g)

σ = the standard deviation (4 g)

Substituting the values into the formula:

z = (345 - 350) / 4 = -1.25

Next, we can find the probability associated with this z-score using a standard normal distribution table or a statistical calculator.

The probability of obtaining a z-score less than -1.25 is approximately 0.1056.

However, we are interested in the probability of underfilling by 5 g or more, which means we need to find the complement of this probability.

The probability of underfilling by 5 g or more is 1 - 0.1056 = 0.8944, or approximately 89.44%.

Therefore, there is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.

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USE A MODEL New City's public works is putting together a fireworks
presentation to celebrate the Fourth of July. They will be launching fireworks at
different heights. The path of one of the fireworks is defined by the equation
h₁ = -16t² + 90t + 120, with t in seconds and h, in feet.
a. The equation provides the height the firework is above the ground at any time
between when it is launched and when it hits the ground. What does 120
represent in the context of the situation?
b. Write the equation that models when the firework will hit the ground. Solve
the equation. Round to the nearest hundredth. nam
c. How high is the firework when it is at its highest point? How long did it take to ans
get to this point? Round to the nearest hundredth. Explain.
d. Without graphing the equation, use the information from parts a, b, and c to
describe what the graph would look like. Explain.
to exarman
e. Write and solve an equation for the times at which the firework reaches a
height of 200 feet. Round to the nearest tenth.
pries
radius of

Answers

a)The number 120 represents the initial height of the firework, in feet.

b)The firework will hit the ground after 3.75 seconds or 12.25 seconds.

c)The firework is 200 feet high when it is at its highest point.

d)The graph of the equation would be a parabola.

e)The firework will reach a height of 200 feet after 3 seconds or 10 seconds.

a. The equation provides the height the firework is above the ground at any time between when it is launched and when it hits the ground.

b. The equation that models when the firework will hit the ground is given by:

[tex]t = (90 ± √(90² - 4 * -16 * 120)) / (-32)[/tex]

Solving for t, we get:

t = 3.75 or 12.25

c. The firework is at its highest point when t = 7.5 seconds. At this point, the height of the firework is given by:

[tex]h₁ = -16(7.5)² + 90(7.5) + 120[/tex]

h₁ = 200

d.The parabola would open downwards, because the coefficient of t² is negative. The parabola would have a maximum point at t = 7.5 seconds, where the height of the firework is 200 feet.

e. The equation for the times at which the firework reaches a height of 200 feet is given by:

[tex]-16t² + 90t + 120 = 200[/tex]

Solving for t, we get:

t = 3 or 10

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please help meeeeeeeee

Answers

Answer:

[tex]\textsf{2.2.1)} \quad \sf True[/tex]

[tex]\textsf{2.2.2)} \quad T_n=3n+2[/tex]

Step-by-step explanation:

A numeric pattern is a sequence of numbers that follows a consistent rule or pattern, where each term is related to the previous term in a specific way. These patterns can involve simple operations like addition or multiplication, and they help us understand how numbers behave and make predictions.

From observation of the given diagram, the number of black dots in each figure is:

Figure 1:  5 black dotsFigure 2:  8 black dotsFigure 3:  11 black dots

Each figure has 3 more black dots than the previous figure. Therefore, the pattern is an example of a numeric pattern since the common difference between terms is 3.

As there is a common difference between terms, the sequence is arithmetic. Therefore, to determine the nth term for the number of black dots, we can use the general formula for an arithmetic sequence:

[tex]\boxed{\begin{minipage}{8 cm}\underline{General form of an arithmetic sequence}\\\\$T_n=a+(n-1)d$\\\\where:\\\phantom{ww}$\bullet$ $T_n$ is the nth term. \\ \phantom{ww}$\bullet$ $a$ is the first term.\\\phantom{ww}$\bullet$ $d$ is the common difference between terms.\\\phantom{ww}$\bullet$ $n$ is the position of the term.\\\end{minipage}}[/tex]

Given that the first term is a = 5 and the common difference is d = 3, substitute these values into the formula and simplify:

[tex]T_n=5+(n-1)3[/tex]

[tex]T_n=5+3n-3[/tex]

[tex]T_n=3n+2[/tex]

Therefore, the equation for the nth term for the number of black dots is:

[tex]\boxed{T_n=3n+2}[/tex]

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.


Note: figure not drawn to scale.

Clay's oat barn has an air vent in the shape of a rectangular prism lengthwise through the barn. Clay is able to use the entire volume of the barn, except for the air vent, to store oats. He has decided to fill the barn to capacity to be prepared for the upcoming winter and planting season.

Clay called the Farmers CO-OP and ordered
cubic feet of oats.

Answers

The ratio of the scaled area to the actual area of the patio is 0.1389 square feet : 320 square feet or 1 : 2306.56

What is a scale factor?

A scale factor is defined as the ratio between the scale of a given original object and a new object,

We have,

The actual dimensions of the patio are 20 feet by 16 feet.

The scale factor is 1 inch to 4 feet,

This means that 1 inch on the scale drawing represents 4 feet in reality.

So the dimensions of the scale drawing are:

20 feet x (1/4) = 5 inches (length on scale drawing)

16 feet x (1/4) = 4 inches (width on scale drawing)

The area of the actual patio is:

= 20 feet x  16 feet

= 320 square feet

The area of the scale drawing is:

= 5 inches x 4 inches

= 20 square inches

The ratio of the area of the scaled drawing to the actual area of the patio is: 20 square inches : 320 square feet

To simplify this ratio, we need to convert both values to the same units.

Converting the area of the scale drawing to square feet:

= 20 square inches x  (1/144) square feet/square inch

= 0.1389 square feet

So the ratio of the area of the scaled drawing to the actual area of the patio is:

0.1389 square feet : 320 square feet

Or, in simplified form:

1 : 2306.56

Thus,

The ratio of the scaled area to the actual area of the patio is 0.1389 square feet : 320 square feet or 1 : 2306.56

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You borrow $25,000 at an interest rate of 5.2% compounded monthly and your monthly payment is $231.49.

What is the principal amount remaining on the loan after 2 months?

Answers

The principal amount remaining on the loan after 2 months is approximately $24,718.74.

How to solve for the principal

Principal = $25,000 (Initial loan amount)

Interest Rate = 5.2% per year (compounded monthly)

Monthly Interest Rate = 5.2% / 12 months = 0.052 / 12 = 0.004333 (approx.)

Monthly Payment = $231.49

Number of Periods = 2 months

Now, let's substitute these values into the formula:

[tex]Principal Remaining = $25,000 * (1 + 0.004333)^2 - $231.49 * (((1 + 0.004333)^2) - 1) / 0.004333[/tex]

Calculating the equation:

Principal Remaining ≈ $24,718.74

Therefore, the principal amount remaining on the loan after 2 months is approximately $24,718.74.

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Find the Interpret the mean absolute deviation of the data 1/4,5/8,3/8,3/4,1/2

Answers

The mean absolute deviation (MAD) for the given data is 1/20. This means that, on average, each data point in the set differs from the mean by 1/20.

To find the mean absolute deviation (MAD) of a set of data, we need to calculate the average difference between each data point and the mean of the data set. Here's how we can calculate it for the given data:

Step 1: Find the mean (average) of the data set.

Mean = (1/4 + 5/8 + 3/8 + 3/4 + 1/2) / 5 = 2/5

Step 2: Calculate the difference between each data point and the mean.

Differences: |1/4 - 2/5|, |5/8 - 2/5|, |3/8 - 2/5|, |3/4 - 2/5|, |1/2 - 2/5|

Step 3: Calculate the absolute value of each difference.

Absolute Differences: 1/20, 1/40, 1/40, 1/20, 1/10

Step 4: Find the average of the absolute differences.

MAD = (1/20 + 1/40 + 1/40 + 1/20 + 1/10) / 5 = 1/20

The MAD provides a measure of the average amount of variation or dispersion in the data set. In this case, a MAD of 1/20 indicates that the data points are relatively close to the mean, with most values falling within 1/20 of the mean value.

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Paul is selling $2 raffle tickets for his baseball team. He needs to sell at least $230 worth of tickets to earn a team jacket. If he has already sold $50 worth of tickets, how many more raffle tickets, x, does Paul need to sell to earn a team jacket?

Answers

To determine how many more raffle tickets Paul needs to sell, we can subtract the amount he has already sold from the minimum amount required to earn the team jacket.

Amount Paul needs to sell = Minimum amount required - Amount already sold

Amount Paul needs to sell = $230 - $50

Amount Paul needs to sell = $180

Since each raffle ticket costs $2, we can divide the amount Paul needs to sell by the price of each ticket to find the number of tickets he needs to sell.

Number of tickets Paul needs to sell = Amount Paul needs to sell / Price per ticket

Number of tickets Paul needs to sell = $180 / $2

Number of tickets Paul needs to sell = 90

Therefore, Paul needs to sell 90 more raffle tickets to earn a team jacket.

the table shows the number of minutes of exercise for each person. Compare and contrast the measures of variation for boh weeks.

Answers

By comparing and contrasting measures of variation, you can gain insights into the consistency or Variability of exercise durations across the two weeks.

To properly compare and contrast the measures of variation for both weeks, we would need access to the table or data that provides the number of minutes of exercise for each person. However, without the specific data, it is not possible to provide a detailed analysis. Nevertheless, I can provide you with an explanation of measures of variation and how they can be used to compare and contrast data sets.

Measures of variation, such as range, variance, and standard deviation, are statistical measures that provide insights into the spread or dispersion of a dataset. They help us understand how the individual values in a dataset deviate from the central tendency, such as the mean or median.

Range: The range is the simplest measure of variation and is calculated by subtracting the minimum value from the maximum value in a dataset. It provides an understanding of the spread of the data, but it is influenced heavily by outliers.

Variance and Standard Deviation: Variance and standard deviation measure the average squared deviation from the mean. They provide a more robust measure of dispersion by considering the deviations of each value from the mean. A smaller variance or standard deviation indicates less dispersion in the data.

To compare and contrast measures of variation for both weeks, you would calculate the range, variance, or standard deviation for each week and then compare the results. If the measures of variation are similar for both weeks, it indicates that the exercise durations have similar levels of dispersion. If one week has a larger range, variance, or standard deviation, it suggests greater variability in exercise durations during that week compared to the other.

By comparing and contrasting measures of variation, you can gain insights into the consistency or variability of exercise durations across the two weeks. However, to provide a more specific analysis, it would be necessary to have access to the actual data or table of exercise minutes for each person in both weeks.

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HELPPPPPPPPPPPPPPPPPPPP
Find all values of n for which the equation has one real solution.
8s = –(n–3)s2–9
Write your answer starting with n, followed by an equals sign or inequality symbol (for example, n<5). Reduce all fractions.

Answers

The equation has one real solution when n = 43/9.

To find the values of n for which the equation has one real solution, we need to analyze the discriminant of the quadratic equation. The discriminant is the expression inside the square root of the quadratic formula and determines the nature of the solutions.

In this case, the equation is:

8s = -(n-3)s^2 - 9

To analyze the discriminant, we consider the quadratic equation in the form of as^2 + bs + c = 0. Comparing it with our equation, we have a = -(n-3), b = 8, and c = -9.

The discriminant (D) can be calculated using the formula D = b^2 - 4ac. Substituting the values, we get:

D = 8^2 - 4*(-(n-3))*(-9)

D = 64 - 36(n-3)

D = 64 + 36(3 - n)

D = 64 + 108 - 36n

D = 172 - 36n

For the equation to have one real solution, the discriminant must be equal to zero, D = 0. So, we have:

172 - 36n = 0

36n = 172

n = 172/36

n = 43/9

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Im so confused rn help please

Answers

The expression for the area of the trapezoid in this problem is given as follows:

A = 27a³b² square units.

How to obtain the area of the trapezoid?

The area of a trapezoid is given by half the multiplication of the height by the sum of the bases, hence:

A = 0.5 x h x (b1 + b2).

The parameters for this problem are given as follows:

h = 3ab, b1 = 7a²b, b2 = 11a²b.

Hence the area is given as follows:

A = 0.5 x 3ab x 18a²b.

A = 27a³b² square units.

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Humanity would achieve in life expectancy of 110 years in approximately

Answers

Humanity would achieve a life expectancy of 110 years in approximately 60 years.

To calculate the number of years it would take for humanity to achieve a life expectancy of 110 years, we need to determine the number of decades required to reach this goal based on the given rate of increase.

In 2009, the life expectancy was about 80 years. From that point, we need to calculate the difference between the current life expectancy and the target life expectancy of 110 years.

110 years - 80 years = 30 years

Since the rate of increase is 5.3 years every decade, we can divide the difference by the rate to determine the number of decades required:

30 years / 5.3 years per decade ≈ 5.66 decades

Since we can't have a fraction of a decade, we need to round up to the nearest whole number. Therefore, it would take approximately 6 decades for humanity to achieve a life expectancy of 110 years.

To calculate the number of years, we multiply the number of decades by 10:

6 decades * 10 years per decade = 60 years

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Pls I’m in need of helppppppp

Answers

Answer:

62) B

63) D

Step-by-step explanation:

62

Angles N and U are congruent.

The sum of the interior angles of a triangle add to 180.

To find N :

180 - 142 - 24 = 14

This means that angle U is also 14

2x - 50 = 14  Add 50 to both sides

2x = 64  Divide both sides by 2

x = 32 This is answer B

63

We know that side NP is congruent to side Su

2x - y = 13  Substitute 32 for x and solve for y

2(32) - y = 13

64 -y = 13  Subtract 64 from both sides

-y = -51  Multiple both sides by -1

y = 51  The answer is D.

Helping in the name of Jesus.

Please give me this by 05/31/23.
It’s due tomorrow

Answers

5(3x+7)-5 = 15x + 35 - 5

6. Answer: C
The 5 should not have been distributed

7. Answer: C
The other options aren’t very relevant in helping you find a common factor

[tex]Solve: 2/5=6/x[/tex]

Answers

Answer:

[tex]x=15[/tex]

Step-by-step explanation:

[tex]\frac{2}{5}=\frac{6}{x}\\\\\mathrm{Multiplying\ }x\mathrm{\ on\ both\ sides,}\\\\\frac{2}{5}(x)=\frac{6}{x}(x)\\\\\mathrm{or,\ }\frac{2x}{5}=6\\\\\mathrm{Multiplying\ '5'\ on\ both\ sides,}\\\\\frac{2x}{5}(5)=6(5)=30\\\\\mathrm{or,\ }2x=30\\\therefore x=15[/tex]

Simplify
-5a²b2
25ab-1
5
-5ab3
a
-563
-5a

Answers

Hello!

you just want the result then:

it's the first answer.

100 pts !!! Only clear answers pls! Someone please help with these 7 geometry questions

Answers

11.) The missing length of the triangle = 16.8ft.

12.) Solved

13.) The missing height of the triangle would be = 6.5cm.

14.) The length of the base would be =21.4in

15.) The height of the trapezoid = 15km

16.) The length of the other side of the trapezium = 17ft

17.) The diameter of the circle = 22m.

18.) The perimeter of the square = 76ft.

How to calculate the value of the missing part of the triangle?

To calculate the value of the missing part of the triangle, the formula that should be used is the Pythagorean formula and this is given as follows:

For 11.)

C² = a²+b²

where

c = 18.2ft

a = 7ft

b= ?

That is;

b² = 18.2²-7²

= 331.24-49

= 282.24

b =√282.24

= 16.8

For 13.)

The area of the triangle = 45.5cm²

The base = 14cm

The height = x

But the formula for area of triangle= 1/2 base×height

That is;

45.5=1/2×14×h

h = 45.5/7

= 6.5

For 14.)

To calculate the value of the base length, the area of parallelogram should be used. The formula for the area of parallelogram = base×height.

where:

area = 160.5in²

height = 7.5in

base = ?

base = 160.5/7.5

= 21.4in

For 15.)

The area of a trapezium = ½(a+b)h

where:

a = 23

b = 29

h = ?

Area = 390

That is:

390 = 1/2×(23+29)×h

h = 390/26

= 15km

For 16.)

The area of trapezium = 1/2(a+b)h

a = 12ft

b = ?

h = 4ft

area = 58ft²

58 = 1/2(12+b)×4

b = 58-34/2

= 17ft

For 17.)

The area of the circle = πr²

area = 380.13m²

π= 3.14

380.13= 3.14× r²

r² = 380.13/3.14

= 121.0605095

r. =√121.0605095

= 11m

diameter = 2r = 2×11 = 22m

For 18.)

The area of square= a²

area= 361

a= ?= side length

a= √361

= 19

perimeter = 4×19 = 76ft

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Does anyone know the answer??

Answers

Answer:

yeah

Step-by-step explanation:

need to find the value of x

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