Answer:
The second distance of the sound from the source is 431.78 m..
Explanation:
Given;
first distance of the sound from the source, r₁ = 1.48 m
first sound intensity level, I₁ = 120 dB
second sound intensity level, I₂ = 70.7 dB
second distance of the sound from the source, r₂ = ?
The intensity of sound in W/m² is given as;
[tex]dB = 10 Log[\frac{I}{I_o} ]\\\\For \ 120 dB\\\\120 = 10Log[\frac{I}{1*10^{-12}}]\\\\12 = Log[\frac{I}{1*10^{-12}}]\\\\10^{12} = \frac{I}{1*10^{-12}}\\\\I = 10^{12} \ \times \ 10^{-12}\\\\I = 1 \ W/m^2[/tex]
[tex]For \ 70.7 dB\\\\70.7 = 10Log[\frac{I}{1*10^{-12}}]\\\\7.07 = Log[\frac{I}{1*10^{-12}}]\\\\10^{7.07} = \frac{I}{1*10^{-12}}\\\\I = 10^{7.07} \ \times \ 10^{-12}\\\\I = 1 \times \ 10^{-4.93} \ W/m^2[/tex]
The second distance, r₂, can be determined from sound intensity formula given as;
[tex]I = \frac{P}{A}\\\\I = \frac{P}{\pi r^2}\\\\Ir^2 = \frac{P}{\pi }\\\\I_1r_1^2 = I_2r_2^2\\\\r_2^2 = \frac{I_1r_1^2}{I_2} \\\\r_2 = \sqrt{\frac{I_1r_1^2}{I_2}} \\\\r_2 = \sqrt{\frac{(1)(1.48^2)}{(1 \times \ 10^{-4.93})}}\\\\r_2 = 431.78 \ m[/tex]
Therefore, the second distance of the sound from the source is 431.78 m.
Match each method of transferring electric charge with the correct description
friction
transfer of electric charge without direct
contact
induction
transfer of electric charge by rubbing
conduction
transfer of electric charge by direct contact
The matching of each method of transferring electric charge with the correct description should be explained below.
Matching of transferring electric charge?The friction means the transfer of electric charge via rubbing. The conduction means the transfer of electric charge via the direct contact.
Also, the induction means the transfer of the electric charge without the direct contact.
In this way it should be matched.
Learn more about electric here: https://brainly.com/question/23056096
Answer:
this is the answer that is correct
5. 3 women push a stalled car. Each woman pushes with a 400N force. What is the mass of the car if the car accelerates at 0.85 m/s??
Answer:
470.59 kgExplanation:
The the mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{400}{0.85} \\ = 470.58823...[/tex]
We have the final answer as
470.59 kgHope this helps you
A motorcyclist increases the velocity of his bike from 30.0 meters/second to 55.0 meter/second under a constant acceleration of 5.00 meters/second^2. How long does it take the bike to reach the final velocity?
Answer:
Time, t = 5 seconds.
Explanation:
Given the following data;
Initial velocity = 30m/s
Final velocity = 55m/s
Acceleration = 5m/s²
To find the time, we would use the first equation of motion;
[tex] V = U + at[/tex]
Where;
V is the final velocity. U is the initial velocity. a is the acceleration. t is the time measured in seconds.Making time, t the subject of formula, we have;
[tex] t = \frac{V - U}{a}[/tex]
Substituting into the equation, we have;
[tex] t = \frac{55-30}{5}[/tex]
[tex] t = \frac{25}{5}[/tex]
Time, t = 5 seconds.
Therefore, it would take the bike 5 seconds to reach the final velocity.
Light of wavelength 500 nm illuminates parallel slits and produces an interference pattern on a screen that is 1 m from the slits. In terms of the initial intensity I0, the light's intensity in the interference pattern at a point for which the path difference is 300 nm is
Answer:
this point we have a destructive inference m=1
Explanation:
This is an interference exercise, where the light has two possible states one of constrictive interference
d sin θ = m λ
and another of destructive interference
d sin θ = (m + ½) λ
the term on the left is the difference in trajectory that tells us that it is worth
d sin θ = 300 nm = 300 10⁻⁹ m
We can find what type of interference we have by finding m, which must be an integer
constructive interference
m = d sin θ /λ
let's calculate
m = 300 10⁻⁹ / 500 10⁻⁹
m = 0.6
this value is not possible because m must be an integer
destructive interference
m + ½ = d sin θ /λ
m = d sin θ /λ + ½
m = 0.6 + 0.5
m = 1.1
that can be approximated to m = 1
this value if possible, so at this point we have a destructive inference
When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose another bomb is tested, and 1.5 grams of matter are converted into energy. How many joules of energy are released by the explosion?
Answer:
The value is [tex]E = 1.35 *10^{14} \ J[/tex]
Explanation:
From the question we are told that
The mass of matter converted to energy on first test is [tex]m = 1 \ g = 0.001 \ kg[/tex]
The mass of matter converted to energy on second test [tex]m_1 = 1.5 \ g = 1.5 *10^{-3} \ kg[/tex]
Generally the amount of energy that was released by the explosion is mathematically represented as
[tex]E = m * c^2[/tex]
=> [tex]E = 1.5 *10^{-3} * [ 3.0 *10^{8}]^2[/tex]
=> [tex]E = 1.35 *10^{14} \ J[/tex]
If The density of this stainless steel is7.85 g/cm3,specific heatis 0.5 J/g.K, melting pointis 1673K, heat of fusion s0.260J/kg. How much energy is required to re-melt this tube completely from room temperature
Answer:
[tex]\Delta H=687.4 J[/tex]
Explanation:
Hello!
In this case, for this melting process, we can identify two sub-processes in order to take the stainless steel from solid to liquid:
1. Heat up from 298.15 K to 1673 K.
2. Undergo the phase transition.
Both process have an associated enthalpy as shown below:
[tex]\Delta H_1=1g*0.5\frac{J}{g*K} (1673K-298.15K)=687.4J[/tex]
[tex]\Delta H_2=0.001kg*\frac{0.260J}{kg} =0.00026J[/tex]
Therefore, the required heat is:
[tex]\Delta H=\Delta H_1+\Delta H_2\\\\\Delta H=687.4J+0.00026J\\\\\Delta H=687.4J[/tex]
Notice the problem is not providing neither the mass or volume, that is why we assumed the mass is 1 g; however, it can be changed to the mass you are given.
Best regards!
Which of the following is the best example of Newton’s third law? A. A person riding a bike at a constant speed B. A car accelerating C. Rowing a boat D. An orange rolling off a tray
Answer:
C; Rowing a boat
Explanation:
Hope this helps! :3
Plz mark as brainliest!
A slanted surface used to raise an object is a(n)
Answer:
Inclined Plane
Explanation:
For which object would a geologist use carbon-14 dating to determine age?
The bones of animals
Rocks older than 50,000 years old
Types of Sedimentary rocks
Parts of Volcanic rock
Answer:
B. older than 50,000 years old
hope it helps you
Rocks older than 50,000 years old are objects in which geologists use carbon-14 dating to determine its age.
What is Carbon dating?This is used to determine age by using the decay to nitrogen of radiocarbon (carbon-14).
Older rocks can have its age determined through the use of carbon-14 which is why option B was chosen.
Read more about Carbon dating here https://brainly.com/question/1122575
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An insulating rod is bent into the shape of a quarter-circle having total charge Q distributed uniformly over its length. At the origin, the magnitude of the total electric field due to this charge configuration is E0 and the potential is V0. A second insulating rod is added to the fourth quadrant to complete a semi-circle. This second quarter-circle has charge -Q uniformly distributed. In terms of E0 and V0, determine the total electric field vector and the total potential at the origin due to the semi-circle of charge.
Answer:
E = - 2*E₀*sinθ*i
V = V = 2*E₀*sinθ /r
Explanation:
First situation: a quarter-circle rod produces at the origin
E₀ and V₀
We know that E = K * Q/r and
E = E₀ Q = L*λ Q = 1/4 * 2*π*r*λ Q = (1/2)*π*r*λ
where:
r is the radius of the circle which at the same time is the distance between the rod quarter of the circle and the origin.
λ is the longitudinal density of charge, and
k = 1/4*π*ε₀
Then E₀ = (1/2)* k*π*λ and V₀ = - E₀/Q V₀ = - E₀/r
E₀ = E₀ₓ + E₀y E₀ₓ = E₀*cosθ E₀y = - E₀*sinθ
θ the angle between E₀ and the x-axis
Second situation half of a circle ( first quarter +Q and fourth -Q )
In that configuration, the components in the x-axis cancel each other ( by symmetry) and the y-axis components of +Q and -Q are to be added then
E = Eₓ + Ey but by inspection we find Eₓ = 0 ( the components of the
the electric field produced of the two quarters canceled each other)
and we have to add the two identical y-axis components of the two quarters therefore
E = 2*E₀y
each component of E₀y = - E₀*sinθ
Then the new electric field becomes
E = - 2*E₀*sinθ*i
The new V = - (- 2*E₀*sinθ /r)
V = 2*E₀*sinθ /r
(Note remember that V is a scalar )
4. A box of old textbooks is on the middle shelf in the bookroom 1.3 m from the floor. If the janitor relocates the box to the shelf that is 2.6 m from the floor, how much work does he do on the box. The box has a mass of 10.0 kg.
Answer:
127.53 J
Explanation:
Given that
Height of the floor, h = 1.3 m
Acceleration due to gravity, g = 9.81 m/s²
Mass of the box, m = 10 kg
To find the work done on the box by the janitor, we use the formula for potential energy. Remember that potential energy is actually the energy stored in an object as a result of its position.
P.E = mgh, substituting each parameters for its value, we then have
P.E = 10 * 9.81 * 1.3
P.E = 127.53 J
Therefore, we can conclude that the amount of work done on the box by the janitor is 127.53 J
how many molecules of o2 are in 8.0 g of oxygen?if the o2 molecules were completely split into 9,how many mole of atoms of oxygen would be obtained?
10 POINTS BE FAST
Which statement illustrates how progress in engineering has affected the
natural environment?(please hurry)
A. Modern mining practices provide materials that can be used for
technological advances.
B. Modern mining equipment has improved
the health and safety of
workers.
C. Extracting mineral resources
with modern mining equipment
removes fertile topsoil.
D. Mining companies use modern equipment to extract mineral
resources more efficiently.
hurry please
Answer:
I think it's c or A hopes this help
The pendulum consists of two slender rods AB and OC which each have a mass of 3 kg/m. The thin plate has a mass of 10 kg/m2. Determine the location of the center of mass G of the pendulum, then calculate the moment of inertia of the pendulum about an axis perpendicular to the page and passing through G.
Answer:
the answer is below
Explanation:
The diagram of the problem is given in the image attached.
Mass of rod AB = (0.4 m + 0.4 m) * 3 kg/m = 2.4 kg
Mass of rod OC = (1.5 m) * 3 kg/m = 4.5 kg
Mass of plate = 10 kg/m²[ (π* 0.3²) - (π* 0.1²)] = 2.513 kg
The center of mass is:
[tex]\hat{y}[2.4+2.513+4.5]=(0.75*4.5)+(2.513*0.5)\\\\\hat{y}=0.839\\\\I_{AB}=\frac{1}{12}*2.4*(0.4+0.4)^2= 0.128\ kg/m^2\\\\I_{OC}=\frac{1}{12}*4.5*(1.5)^2= 3.375\ kg/m^2\\\\I_{Gplate}=\frac{1}{2}*(\pi*0.3^2*10)*(0.3)^2-\frac{1}{2}*(\pi*0.1^2*10)*(0.1)^2= 0.126\ kg/m^2\\\\I_{plate}=I_{Gplate}+md^2=0.126+2.513(1.8^2)=8.27\ kg/m^2\\\\I_o=I_{plate}+I_{AB}+I_{OC}\\\\I_{o}=0.128+3.375+8.27=11.773\ kg/m^2 \\\\I_G=I_o-m_{tot}\hat{y}^2\\\\I_G=11.773-(9.413*0.839^2)\\\\I_G=5.147\ kg/m^2[/tex]
Determine the weight of a 5.1 kg scooter that moves with a constant acceleration of 3.0 ms2. (Make sure you use the weight equation: W or Fg = mg)
Answer:
15.3 sorry if i got it wrong
Explanation:
Why do hurricanes develop over oceans?
Question 5 options:
The ocean is affected by the Coriolis effect.
The ocean winds blow from north to south.
The warmer ocean adds water vapor to the air mass.
The ocean currents cause air to move toward the land.
My guess is; The warmer ocean adds water vapor to the air mass.
I'm really sorry if I'm wrong
The warmer ocean adds water vapor to the air mads
Do dwarf planets has several other bodies in their path orbiting the Sun just as they do?
Answer:
No they just orbit the sun
Explanation:
it is difficult to walk on a smooth floor why
Answer:
because theres is not enough friction so it will be super slippery
Explanation:
A person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
Answer:
3.88 × 10^-4 m
Explanation:
Given that a person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?
The total weight = 614 + 85
The total weight = 699N
Let the total area of contact = A
Pressure = Force / A
Substitute all the parameters into the formula
900000 = 699 /A
A = 699 / 900000
A = 7.77 × 10^-4 m
The area of contact between each tire and the ground will be = A/2
That is, 7.77 / 2 = 3.88 × 10^-4 m
Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.
Ist Law: a object continues in a state of
rest or motion unless an external force
applied to it
This image shows an example of
the first law because:
Answer:
Explanation:
This image is the example of Newton's first law of motion because:
As per Newton's first law, football will remain in the state of rest until a player applies an external force by kicking the ball.
And the ball will keep on moving until unless the net of a goal post exerts the external force to stop the ball.
The orbital radius of Venus
is 10.8 x 1010 m. Its rotation
period is 224.7 days. What is its
orbital speed?
A 20 km s-1 C 35 km s-1
B 25 km s-1 D 62 km 5-1
Answer:
v = 35 km/s
Explanation:
Given that,
Orbital radius of Venus, [tex]r=10.8\times 10^{10}\ m=10.8\times 10^{10}\times 10^{-3}=10.8\times 10^{7}\ km[/tex]
The rotation period is, [tex]T = 224.7\ \text{days}=19414080\ s[/tex]
We need to find the orbital speed of the Venus. The formula for the orbital speed is given by :
[tex]v=\dfrac{2\pi r}{T}\\\\v=\dfrac{2\pi \times 10.8\times 10^{7}}{19414080}\\\\=34.95\ km/s[/tex]
or
v = 35 km/s
So, the orbital speed of Venus is 35 km/s.
A source emits sound with a frequency of 18,002 Hz. Both it and an observer are moving toward each other, each with a speed of 130 m/s. What frequency (in Hz) does the observer hear
Answer:
The frequency heard by the observer is 24,830.35 Hz.
Explanation:
Given;
frequency of the source, Fs = 18,002 Hz
speed of the source, Vs = 130
speed of sound in air, V = 343 m/s
Apply Doppler effect, as the source and the observer move closer to each other, the frequency heard by the observer increases because of decrease in distance.
[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\[/tex]
where;
f₀ is the frequency heard by the observer
[tex]f_s = f_o[\frac{v}{v + v_s} ]\\\\18,002 = f_o[\frac{343}{343 + 130} ]\\\\18,002 = f_o(0.725)\\\\f_o = \frac{18,002}{0.725} \\\\f_o = 24,830.35 \ Hz[/tex]
Therefore, the frequency heard by the observer is 24,830.35 Hz.
What are earth crossing asteroids and how do we monitor them
Answer:
Earth-crossing asteroid, asteroid whose path around the Sun crosses Earth's orbit. Two groups of such asteroids—Aten and Apollo asteroids—are distinguished by the size of their orbits and how closely they approach the Sun.
Explanation:
X- rays with a wavelgnth of 0.0700 nm diffract from a crystal. Two adjacne angels of x-ray diffraciton are 45.6 and 21.0 degrees. What is the distance in nm between the atomic planes responsible for the diffraction? (Use 2dcos(θ)=m(λ))
Answer:
0.15 nm
Explanation:
d = Distance between the atomic planes
m = Order
[tex]\theta_{m}[/tex] = First angle = [tex]45.6^{\circ}[/tex]
[tex]\theta_{m+1}[/tex] = Adjacent angle = [tex]21^{\circ}[/tex]
[tex]\lambda[/tex] = Wavelength = 0.07 nm
From Bragg's relation we know
[tex]2d\cos\theta_{m}=m\lambda[/tex]
[tex]2d\cos45.6^{\circ}=m0.07[/tex]
[tex]2d\cos\theta_{m+1}=(m+1)\lambda[/tex]
[tex]2d\cos21^{\circ}=(m+1)0.07\\\Rightarrow 2d\cos21^{\circ}=m(0.07)+0.07[/tex]
So
[tex]2d\cos21^{\circ}=2d\cos45.6^{\circ}+0.07\\\Rightarrow 2d(\cos21^{\circ}-\cos45.6^{\circ})=0.07\\\Rightarrow d=\dfrac{0.07}{2(\cos21^{\circ}-\cos45.6^{\circ})}\\\Rightarrow d=0.14962\ \text{nm}[/tex]
The distance between the atomic planes is 0.15 nm.
A 2.00 kg copper pot is placed on a glass shelf and then one side of the shelf falls so that it becomes angled at 35.0° to the horizontal. The coefficient of static friction between copper and glass is 0.680 and the coefficient of kinetic friction is 0.530. Will the pot slide, and if so, what is its acceleration?
Answer:
Explanation: about 2 Mph when it falls and sorry if I’m wrong
please answer True or false
In two square the server earns a point when the opponent catches the ball.
2. 290 grams of water is to be heated from 24.0% to 100.0°C to make a cup of
tem, how much heat must be added? The specific heat of water is 4.18 J/g•C
Answer:
92127.2 j
Explanation:
Given that :
Mass of water = 290 g
Specific heat of water (C) = 4.18 j/g.C
Initial Temperature (t1) = 24°C
Final temperature (t2) = 100°C
Using the relation :
Q = mCdt
dt = change in temperature =( 100 - 24)° = 76°C
Q = quantity of heat ; C = specific heat capacity;
m = mass of substance
Q = 290 g * 4.18 j/g.C * 76°C
Q = 92127.2 j
Why do you need air resistance in a parachute ?what happens without it?
And
How does air resistance affect acceleration and terminal velocity
Do clouds have respiration
Answer:
yes it also does have but not in the exact form but it does 30 percent of respiration to produce rain
Aner shopping. It took Jacob 18 seconds to push his shopping cart to his car. He was moving at 2 meters per second. His daughter walked beside the cart for one-third of the time it took Jacob to reach his car. How far did Jacob's cart move while his daughter was walking beside Write your answer as a whole number meters
Answer:
I am going to answer you just wait a little bit.
