Answer:
We should reject H₀ for values of | x₁| > 5,26 |x₁| > 6,12
Step-by-step explanation:
Sample mean μ₀ = 5,7
Sample size n₁ = 24
Sample standard deviation s = 1
Significance level α = 0,05 CI = 95 %
Hypothesis criteria: Valves don´t meet the specification, which means pressure could be higher or lower than nominal
Normal Distribution where n < 30 we should use a two-tail t-student test
degree of freedom df = 24 - 1 = 23
And with df = 23 and α = 0,025 we find in t-tables the value for
t(c) = - 2,0687 ( on the left tail )
Test Hypothesis:
Null Hypothesis H₀ x = μ₀
Alternative Hypothesis Hₐ x ≠ μ₀
To compute t(s)
t(s) = ( x - μ₀ ) / s/√n
t(s) = ( x - 5,7 )*4,80
t(s) = 4,80*x - 27,34
Then for values of t(s) |t(s)| > 2,0687 we have to reject H₀
If we make t(s) = t(c) we find
-2,0687 = 4,8*x - 27,34
x = ( 27,34 - 2,07 ) / 4,8 and on the other tail x = 6,12
x = 5,26
Therefore for values of 5,26 ( under ) and above 6,12 we shoud reject the Null hypothesis
Solve for x. (geometry)
Answer:
x = -6
Step-by-step explanation:
[tex]130 + (x + 56) = 180 \\ x = 180 - 56 - 130 \\ x = 180 - 186 \\ x = - 6[/tex]
A submarine's position is -325 feet. If it descends 98 feet what is its new position?
Answer:
Answer is -483
Step-by-step explanation:
hope this helps
Please answer i need it
Answer:
I think a rhombus
Step-by-step explanation:
if x=2y-5 and z=16y^3, what is z in terms of x
Answer:
z in terms of x is [tex]\mathbf{z=16\left(\frac{x+5}{2}\right)^3}[/tex]
Step-by-step explanation:
We are given:
[tex]x=2y-5\: and\: z=16y^3[/tex]
We need to find z in terms of x
First we can find value of y from x =2y-5
[tex]x =2y-5\\x+5 = 2y\\y=\frac{x+5}{2}[/tex]
Now, we can put value of y in [tex]z=16y^3[/tex] to find z in terms of x
[tex]z=16y^3\\Put\:y=\frac{x+5}{2}\\z=16(\frac {x+5}{2})^3[/tex]
So, z in terms of x is [tex]\mathbf{z=16\left(\frac{x+5}{2}\right)^3}[/tex]
WILL GIVE BRAINLIEST AND 30 POINTS
Omar and Elsa are lions living at the Middleton Zoo. Omar weighs 3 pounds for every 2 pounds Elsa weighs.
If Omar weighs 420 pounds, how much does Elsa weigh?
Answer:
210
Step-by-step explanation:
There are 10 girls for every 12 boys. If there are 50 girls,
how many boys are there?
O a) 60
Ob) 12
O c) 52
d) 62
Answer: A
why does this keep changing to C????
Step-by-step explanation:
10x5 since there are 50 girls
so we would need to multiply 12 by the same number, so the answer is 60.
Brayden bought three 4 for 4 McDouble meals from McDonald’s (4 items for $4). What was his total cost after a 7% sales tax? (HOW DID YOU GET YOUR ANSWER PLEASE SHOW YOUR WORK!!!)
A. 52.90
B. 1.04
C. 12.84
D. 458
E. 5x-8y+7
F. 25.30
Write an equation in slope intercept form for the line that passes through ( 1, 5) with a slope 2
Answer:
y=2x+3
Step-by-step explanation:
Evaluate the function g(x) = -2x2 + 3x - 5 for the input values -2, 0, and 3.
9(-2) = -2(-2)2 + 3(-2) – 5
9(-2) = -2(4) - 6 - 5
g(-2) =-19
g(0) =-5
g(3) =-14
Answer:
g(-2) = -19, g(0) = -5 and g(3) = -14
Step-by-step explanation:
The given function is :
[tex]g(x) = -2x^2 + 3x - 5[/tex] ...(1)
We need to find the function when x = -2,0 and 3.
Put x = -2 in equation (1).
[tex]g(-2) = -2(-2)^2 + 3(-2) - 5\\\\=-19[/tex]
Put x = 0 in equation (1).
[tex]g(0) = -2(0)^2 + 3(0) - 5\\\\=-5[/tex]
Put x = 3 in equation (1).
[tex]g(3) = -2(3)^2 + 3(3) - 5\\\\=-14[/tex]
Hence, g(-2) = -19, g(0) = -5 and g(3) = -14
Look at the pic ! :) 6th grade math
Answer: 2 pounds in each bag
Step-by-step explanation:
12 = pounds of almonds
6 = number of bags
12 / 6 = 2
Answer:
The 12 means it's how many pounds of almonds she has and the 6 means how many bags she has.
Step-by-step explanation:
12 divided by 6 is 2. (Hope this helps!)
Which of the following is a step in simplifying the expression ?
Answer:
the first one is the answer
What is equivalent to 7/8 and don't write 14/16
7/8 is equivalent to 56/64
7.(06.04)
5x + 1/2 y^2
What is the value of the expression above when x = 3 and y = 2? You must show all work and calculations to receive full credit. (4 points)
Answer:
17Step-by-step explanation:
Given expression:
5x + 1/2y²Value of expression when x = 3 and y = 2:
5*3 + 1/2*2² =15 + 2 =17Answer:
5x + 1/2 y² when x = 3 and y = 2
[tex]→\boxed{5x + \frac{1}{2} {y}^{2} } = 5(3) + \frac{1}{2} {(2)}^{2} \\ = 5(3) + \frac{1}{2} (4) \\ = (15 + 2) \\ = \boxed{ 17}✓[/tex]
17 is the right answer.In which quadrant are the following points in
The triangle shown below has an area of 20 units.
Find the missing side.
8.
2
2
units
In the equation 4u - 6 = 24, what is the next step in the equation solving sequence?
Identify and move the coefficient and variable.
Move all numbers without a variable.
Isolate the variable using inverse operations.
Combine like terms.
Answer:
Move all numbers without a variable
Step-by-step explanation:
you want to get the variable by itself so you'll add 6 to both sides of the = sign making it 4u = 30 then you'll divide both sides by 4 making u = 7.5
Write the equation of the line in point-slope form that goes through the point (3, -4) and has a slope of 6. '
3(t+1)=18 solve this probem with work
Answer:
t = 5
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3(t+1)=18
(3)(t)+(3)(1)=18(Distribute)
3t+3=18
Step 2: Subtract 3 from both sides.
3t+3−3=18−3
3t=15
Step 3: Divide both sides by 3.
3t/3 = 15/3
t = 5
what is 5x46+675-39x45 ?
Answer:
-850
Step-by-step explanation:
you do multiplication first, then do the addition
pls help
2688 divided by 96
Answer: 28
Step-by-step explanation:
Answer: 28
Step-by-step explanation: 2688 / 96 = 28
The average number of annual trips per family to amusement parks in the UnitedStates is Poisson distributed, with a mean of 0.6 trips per year. What is the probabilityof randomly selecting an American family and finding the following?a.The family did not make a trip to an amusement park last year.b.The family took exactly one trip to an amusement park last year.c.The family took two or more trips to amusement parks last year.d.The family took three or fewer trips to amusement parks over a three-year period.e.The family took exactly four trips to amusement parks during a six-year period.
Answer:
a) 0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.
b) 0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.
c) 0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.
d) 0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.
e) 0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of sucesses
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Poisson distributed, with a mean of 0.6 trips per year
This means that [tex]\mu = 0.6n[/tex], in which n is the number of years.
a.The family did not make a trip to an amusement park last year.
This is P(X = 0) when n = 1, so [tex]\mu = 0.6[/tex].
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-0.6}*(0.6)^{0}}{(0)!} = 0.5488[/tex]
0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.
b.The family took exactly one trip to an amusement park last year.
This is P(X = 1) when n = 1, so [tex]\mu = 0.6[/tex].
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 1) = \frac{e^{-0.6}*(0.6)^{1}}{(1)!} = 0.3293[/tex]
0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.
c.The family took two or more trips to amusement parks last year.
Either the family took less than two trips, or it took two or more trips. So
[tex]P(X < 2) + P(X \geq 2) = 1[/tex]
We want
[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]
In which
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.5488 + 0.3293 = 0.8781[/tex]
[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.8781 = 0.1219[/tex]
0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.
d.The family took three or fewer trips to amusement parks over a three-year period.
Three years, so [tex]\mu = 0.6(3) = 1.8[/tex].
This is
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 0) = \frac{e^{-1.8}*(1.8)^{0}}{(0)!} = 0.1653[/tex]
[tex]P(X = 1) = \frac{e^{-1.8}*(1.8)^{1}}{(1)!} = 0.2975[/tex]
[tex]P(X = 2) = \frac{e^{-1.8}*(1.8)^{2}}{(2)!} = 0.2678[/tex]
[tex]P(X = 3) = \frac{e^{-1.8}*(1.8)^{3}}{(3)!} = 0.1607[/tex]
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1653 + 0.2975 + 0.2678 + 0.1607 = 0.8913[/tex]
0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.
e.The family took exactly four trips to amusement parks during a six-year period.
Six years, so [tex]\mu = 0.6(6) = 3.6[/tex].
This is P(X = 4). So
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.1912[/tex]
0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.
Probabilities are used to determine the chances of events.
The given parameters are:
[tex]p = 0.6[/tex]
(a) The family did not make a trip to an amusement park last yearThe distribution is given as a Poisson distribution.
So, we have:
[tex]P(x) = \frac{e^{-\mu} \times \mu^x}{x!}[/tex]
Where:
[tex]\mu = np[/tex]
Last year means that:
[tex]n = 1[/tex] --- the number of years.
No trip, means that:
[tex]x = 0[/tex]
So, we have:
[tex]\mu = np[/tex]
[tex]\mu = 1 \times 0.6[/tex]
[tex]\mu = 0.6[/tex]
The probability becomes
[tex]P(x) = \frac{e^{-\mu} \times \mu^x}{x!}[/tex]
[tex]P(0) = \frac{e^{-0.6} \times 0.6^0}{0!}[/tex]
[tex]P(0) = \frac{0.5488 \times 1}{1}[/tex]
[tex]P(0) = 0.5488[/tex]
Hence, the probability that the family did not make a trip to an amusement park last year is 0.5488
(b) The family took exactly one trip to an amusement park last yearThis means that:
x = 1.
So, we have:
[tex]P(x) = \frac{e^{-\mu} \times \mu^x}{x!}[/tex]
[tex]P(1) = \frac{e^{-0.6} \times 0.6^1}{1!}[/tex]
[tex]P(1) = \frac{0.5488 \times 0.6}{1}[/tex]
[tex]P(1) = 0.3293[/tex]
Hence, the probability that the family took exactly one trip to an amusement park last year is 0.3293
(c) The family took two or more trips to amusement parks last yearThis means that:
x = 2,3...
So, we make use of the following complement rule:
[tex]P(x\ge 2) = 1 - P(x < 2)[/tex]
This gives
[tex]P(x\ge 2) = 1 - P(0) - P(1)[/tex]
So, we have:
[tex]P(x\ge 2) = 1 - 0.5488 - 0.3293[/tex]
[tex]P(x\ge 2) = 0.1219[/tex]
Hence, the probability that the family took two or more trips to an amusement park last year is 0.1219
(d) The family took three or fewer trips to amusement parks over a three-year period.For a three-year period, we have:
[tex]n = 3[/tex]
So, the mean of the distribution is:
[tex]\mu = np[/tex]
[tex]\mu = 3 \times 0.6[/tex]
[tex]\mu = 1.8[/tex]
The probability is then represented as:
[tex]P(x \le 3) = P(0) + P(1) + P(2) + P(3)[/tex]
Calculate P(0) to P(3) using:
[tex]P(x) = \frac{e^{-\mu} \times \mu^x}{x!}[/tex]
So, we have:
[tex]P(0) = \frac{e^{-1.8} \times 1.8^0}{0!}[/tex]
[tex]P(0) = \frac{0.1653 \times 1}{1}[/tex]
[tex]P(0) = 0.1653[/tex]
[tex]P(1) = \frac{e^{-1.8} \times 1.8^1}{1!}[/tex]
[tex]P(1) = \frac{0.1653 \times 1.8}{1}[/tex]
[tex]P(1) = 0.2975[/tex]
[tex]P(2) = \frac{e^{-1.8} \times 1.8^2}{2!}[/tex]
[tex]P(2) = \frac{0.1653 \times 3.24}{2}[/tex]
[tex]P(2) = 0.2678[/tex]
[tex]P(3) = \frac{e^{-1.8} \times 1.8^3}{3!}[/tex]
[tex]P(3) = \frac{0.1653 \times 5.832}{6}[/tex]
[tex]P(3) = 0.1607[/tex]
So, we have:
[tex]P(x \le 3) = P(0) + P(1) + P(2) + P(3)[/tex]
[tex]P(x \le 3) = 0.1653 + 0.2975 + 0.2678 + 0.1607[/tex]
[tex]P(x \le 3) = 0.8913[/tex]
Hence, the probability that the family took three or fewer trips to amusement parks over a three-year period is 0.8913
e. The family took exactly four trips to amusement parks during a six-year period.A six-year period means that:
[tex]n = 6[/tex]
So, the mean of the distribution is:
[tex]\mu = np[/tex]
[tex]\mu = 6 \times 0.6[/tex]
[tex]\mu = 3.6[/tex]
The probability is then calculated as:
[tex]P(x) = \frac{e^{-\mu} \times \mu^x}{x!}[/tex]
So, we have:
[tex]P(4) = \frac{e^{-3.6} \times 3.6^4}{4!}[/tex]
[tex]P(4) = \frac{0.0273 \times 167.9616}{24}[/tex]
[tex]P(4) = 0.1911[/tex]
Hence, the probability that the family took exactly four trips to amusement parks over a six-year period is 0.1911
Read more about probabilities at:
https://brainly.com/question/25783392
Based on the table, which city has the highest temperature in January?
City January
Temperature (°C)
New Orleans 7
Philadelphia -4
Phoenix 8
Rochester -8
San Antonio 5
A.
New Orleans
B.
Philadelphia
C.
Phoenix
D.
Rochester
E.
San Antonio
Answer:it’s Phoenix
Step-by-step explanation:
Answer:
C.
Step-by-step explanation:
Can u guys help me please I need a correct answer
Answer:
4 4/7
Step-by-step explanation:
You multiply the n by 7 first because you are cross multiplying. So it would be 7n = 32.
So to simplify you would divide 32 by 7 to get n= 4 4/7
4 4/7 is a mixed number 4 is the whole and 4/7 is the fraction just to clarify
Or as a fraction it would be 32/7
What is the answer please
Answer:
168 ft good luck !
Step-by-step explanation:
What is the slope of the line segment?
A graph is shown. The values on the x axis are 0, 1, 2, 3, 4, and 5. The values on the y axis are 0, 5, 10, 15, 20, and 25. A straight line joining the ordered pairs 0, 0 and 1, 5 and 2, 10 and 3, 15
5
1 over 5
negative 1 over 5
−5
Answer:
The slope is 5
Step-by-step explanation:
divide the change in y by the change in y
you can use two different points for example 1,5 and 3,15
the change in y between these points is 10, the change in x is 2
10/2=5
also since the values of x increase constantly by 1 and it's a continuous line (meaning the domain could be any number between 1 and 3 in this graph) you can calculate only the change in y and that will give you the slope
Is (-4, 2) a solution of 4x + 5y <-7?
Choose 1 answer.
А
Yes
B
No
Answer:
b
Step-by-step explanation:
NO
4/9 + 2/7 simplest form
Answer:
46/63
Step-by-step explanation:
Answer:
46/63
Step-by-step explanation:
4/9 +2/7
4/9*7/7+2/7*9/9
28/63+18/63
46/63
that is the simplest form, no simplifying can be applied
46/63
True Value Hardware ordered 112 rakes. When True Value received the order, 46 rakes were missing. What percent of the order did True Value receive? (round to the nearest 100th)
Answer:
true value received 58.93% or the order.
how fast is a car going if it travels 15 meters in 5 seconds?
The car is traveling 3 meters second
Step-by-step explanation:
you divide 15 by 5 and you get 3
Answer:
3 m/s / 10.714 km/hr
Step-by-step explanation:
15m/5s
3m/1s
3m ÷ 1000 = 0.003 km
1s ÷ 3600 = 0.00028 hr
0.003 km/ 0.00028 hr
=10.714 km/hr approx.
2247 divided by 7. I really don't know the answer. I have to show the work but don't know how to solve the problem
Answer: the answer is 321 :)
Step-by-step explanation:
So, 7/2247
Down below that’s the show your work part. Hope this helps and good luck
