The vertical (top to bottom) parts of periodic table are called groups or

Answer:

This question appear incomplete

Explanation:

This question appear incomplete. However, the significance/functions of the "instruments" mentioned (in the completed question) can be predicted since these "instruments" generally have specialized function.

A thermometer is used to determine the temperature of a substance or an object. The electric heater uses electricity to produce heat (which can be utilized for different purposes). The power supply is used to supply electricity for instruments/appliances that may require electricity to function.

Answer:

210 m/s

Explanation:

We will use this equation for an elastic collision:

In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).

v₁ is 0 m/s since the ball is at rest on the tee.

v₂ is 44 m/s, given in the problem.

v₁ is what we are trying to find.

v₂ is 0 m/s since the ball will be at rest on the ground.

Plug these values into the elastic collision equation:

Simplify this equation.

Get rid of the units.

Multiply the left side of the equation.

Divide both sides by 0.046.

The speed of the ball when it leaves the tee is about 210 m/s.

Answer:

Chromatin is a mass of genetic material composed of DNA and proteins that condense to form chromosomes during eukaryotic cell division. Chromatin is located in the nucleus of our cells . The primary function of chromatin is to compress the DNA into a compact unit that will be less voluminous and can fit within the nucleus.

I hope this helps

Explanation:

Answer: Me again! Chromatin is a complex of DNA and proteins that forms chromosomes within the nucleus of eukaryotic cells. Nuclear DNA does not appear in free linear strands; it is highly condensed and wrapped around nuclear proteins in order to fit inside the nucleus. Chromatin exists in two forms.

Explanation: Hope this helps! Happy Holidays!

Answer:

[tex]\huge\boxed{\sf Time = 10 \ seconds}[/tex]

Explanation:

Given:

Initial Velocity = [tex]\sf V_{i}[/tex] = 8.0 m/s

Final Speed = [tex]\sf V_{f}[/tex] = 28.0 m/s

Acceleration = a = ?

Required:

Time = t = ?

Formula:

[tex]\sf a = \frac{V_{f} - V_{i}}{t}[/tex]

Solution:

[tex]\sf 2 = \frac{28-8}{t} \\\\2 = \frac{20}{t} \\\\t = \frac{20}{2} \\\\t = 10 \ seconds\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

To Find :

The acceleration of the heavier object.

Solution :

Force of gravitation on lighter object by heavier object is :

[tex]F = \dfrac{Gm(4m)}{100^2}[/tex]

Acceleration of lighter object is given by :

[tex]a_s = \dfrac{4Gm}{100^2}\\\\m = \dfrac{50^2}{G}[/tex]          .....1)

Now, acceleration of heavier object when separation between them is 25 km :

[tex]4ma_h = \dfrac{Gm(4m)}{25}\\\\a_h = \dfrac{Gm}{25}[/tex].....2)

Putting value of m in equation 2, we get :

[tex]a_h = \dfrac{G\times 50^2}{G \times 25}\\\\a_h = \dfrac{2500}{25}\\\\a_h = 100\ m/s^2[/tex]

Therefore, the acceleration of the heavier object is​ 100 m/s².

Answer:

69.44kJ

Explanation:

Kinetic energy is expressed as;

KE = 1/2mv^2

m is the mass = 500kg

v is the velocity

Get the velocity;

v = displacement/time

velocity = 2000/120

velcoity = 16.7m/s

Gt the kinetic energy

KE = 1/2 * 500 * 16.7²

KE = 250*277.78

KE = 69,444.4Joules

Since 1000J = 1kJ

69,444.4Joules = 69,444.4/1000

69,444.4Joules = 69.44kJ

Hence the Secretariat's average kinetic energy is  69.44kJ

Answer:C 69.0kJ

Explanation:

Answer:

jsjsjsjsmkskskskksksks

Answer:

a. t = 2.02 s

b. d = 20.2 m

Explanation:

Horizontal Motion

If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The time the object takes to hit the ground can be calculated as follows:

[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]

The time does not depend on the initial speed.

The range or maximum horizontal distance traveled by the object can be calculated by the equation:

[tex]\displaystyle d=v.t[/tex]

The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.

a.

The time taken by the rock to reach the ground is:

[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]

[tex]\displaystyle t=\sqrt{4.0816}[/tex]

t = 2.02 s

b.

The range is:

[tex]\displaystyle d=10\cdot 2.02[/tex]

d = 20.2 m

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ [tex]\angle BCA = (90-30)[/tex]

⇒             [tex]=60^{\circ}[/tex]

then,

⇒ [tex]\angle BAC=(180-45-60)[/tex]

⇒             [tex]=75^{\circ}[/tex]

Now,

The corresponding angle will be:

⇒ [tex]\angle FAC=60^{\circ}[/tex]

⇒ [tex]\angle FAB=70+60[/tex]

⇒             [tex]=135^{\circ}[/tex]

Aspect of F across the AC arm will be:

= [tex]F\times cos(60)[/tex]

On putting the values of F, we get

= [tex]500\times (.5)[/tex]

= [tex]200 \ Newton[/tex]

Component F along the AC (in magnitude) will be:

= [tex]F\times cos(135)[/tex]

= [tex]500\times (-.707)[/tex]

= [tex]-353.5 \ N \[/tex]

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the figure. However, wavelength can be described as the distance between two crests (identical points) of a wave (as illustrated in the picture attached). Thus, a wave with a large/great wavelength must have a long distance between the two crests and has nothing to do with the number of crests/wavelengths since distance between crests could also be small.

Hence, what appears to be the correct option is the last option (Wavelength shown with 1 wavelength stretched over a long distance).

Answer:

Its B.

Explanation:

Im took the exam.

Answer:

750J

Explanation:

Given parameters:

Mass of the object   = 0.15kg

Velocity of the object  = 100m/s

Unknown:

Kinetic energy of the body  = ?

Solution:

The kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;

        K.E  = [tex]\frac{1}{2}[/tex] m v²  

m is the mass of the body

v is the velocity

 Now insert the parameters and solve;

     K.E  = [tex]\frac{1}{2}[/tex]  x 0.15 x 100²   = 750J

Given :

A car slows down from -27.7 m/s to -10.9 m/s while undergoing a displacement of -105 m.

To Find :

The acceleration of the car.

Solution :

We know, by equation of motion :

[tex]2as = v^2 -u^2\\\\a = \dfrac{v^2 -u^2 }{2s}\\\\a = \dfrac{(-10.9)^2 - ( -27.7)^2}{2\times ( -105 )}\\\\a = 3.088\ m/s^2[/tex]

Therefore, acceleration of the car is 3.088  m/s².

Answer:

i cant explain well but the answer is letter b

x-5

Explanation:

dont report me or i will report you too

Answer:

x-5 is the answer

Explanation:

pick her as the brainliest

Answer:

[tex]a=2.4\ m/s^2[/tex]

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]

So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].

Answer:

3.2

Explanation:

I remember taking this quiz and I think that one is correct

Answer:

28 m/s

Explanation:

We can use this constant acceleration kinematic equation to find the speed of this beam as it is dropped from 40 m.

Since the object is dropped vertically downwards, we know that the object is in free-fall.

The acceleration of this object is -g, which is -9.8 m/s² since we are making the positive direction upwards and the negative direction downwards.

The initial velocity is 0 m/s since the object is dropped and starts from rest.

The final velocity is what we are trying to solve for.

The displacement in the y-direction is 40 m.

Now we can see which equation contains these 4 variables:

Plug in the known variables.

Simplify this equation.

Take the square root of both sides.

The speed of the 330 kg beam dropped from 40 m is 28 m/s.

Answer:

Explanation:

Given information :

mass = 330kg

height =40m

v = √2gh

Where ;

g = acceleration due to gravity = 9.8 or 10 m/s

h = height

how much total energy of the beam just as it hits the ground =

mgh

[tex]330\times 10\times 40\\\\\\=132000[/tex]

Speed at which  the beam will hit the ground :

[tex]v = \sqrt{2\times 10\times40} \\\\=\sqrt{800}\\\\=20\sqrt{2}\\\\v=28.28427[/tex]

Answer: What?

Explanation:

Answer:

a.) 600N

b.) 2 m/s^2

Explanation:

a.)

In order to solve for the needed force, you must use Newton's 2nd law which states that a force is equal to mass multiplied by acceleration.

Basically: Force = mass * acceleration ; F = ma

Since both mass and acceleration are already given, just plug them into the formula and solve for force:

Mass = 200kg

Acceleration = 3m/s^2

F = m * a = 200 * 3 = 600kg * m/s^2 = 600N

b.)

In order to find the acceleration, like the hint already says, you need to find the net force first and then use Newton's 2nd law.

To calculate net force:

Since both forces are parallel (affect the same axis) and in opposite directions, you can subtract the two in order to find resultant magnitude. The resultant direction is the direction of the force with the large magnitude.

Net Force: 8N - 4N = 4N

Net Force Direction: since 8N > 4N, the direction is in the same direciton as the 8N force = Left

Finally, you find acceleration using newton's 2nd law, F = ma.

Since you already know mass and net force, plug in to solve for acceleration:

4N = 2kg * a

a = 4 N / 2kg = 2m/s^2

Answer:

(B) the increase in the car's potential energy is 3,660,000 J

Explanation:

Given;

mass of the car, m = 1,000 kg

height through the car was drove, h = 366 m

acceleration due to gravity, g = 10 m/s²

The increase in the car's potential energy is calculated as;

P.E = mgh

P.E = 1000 x 10 x 366

P.E = 3,660,000 J

Therefore, the increase in the car's potential energy is 3,660,000 J

Answer:

A wave with a frequency of 10 Hz and a wavelength of  10 m should have a velocity of 100 meters per second (m/s)

Explanation:

Explanation:

[tex]advantage[/tex]

It is Sensitivity to surface defects. ...

[tex]disadvantage[/tex]

There is a major heat loss during cycling eddy currents due to friction in the magnetic circuit, especially where the core is saturated

Please mark as brainliest answer

Answer:

5000 N

Explanation:

Since F - f = ma, where F = driving force = 5000 N, f = opposing force, m = mass of car and a = acceleration of car.

Since the car is moving with constant velocity, a = 0.

So, F - f = ma

F - f = m(0)

F - f = 0

F = f.

Since F = 5000 N and F = f, f = 5000 N.

So, the opposing force is 5000 N

The opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.

The opposing force can be calculated by the formula,

F - f = ma

Where,

F = driving force = 5000 N,

f = opposing force = ?

m = mass of car = 11000 N

a = acceleration of car

Since, the car is at constant velocity, a = 0.

So,

F - f = m(0)

F - f = 0

F = f.

Therefore, the opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.

To know more about opposing force,

https://brainly.com/question/866413

Answer:

v = 6.06 m/s

Explanation:

In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:

[tex]Centripetal Force = Weight \\\frac{mv^2}{r} = mg\\\\\frac{v^2}{r} = g\\\\v = \sqrt{gr}[/tex]

where,

v = minimum speed of motorcycle at top of the loop = ?

g = acceleration due to gravity = 9.8 m/s²

r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m

Therefore, using these values in equation, we get:

[tex]v = \sqrt{(9.8\ m/s^2)(3.75\ m)}[/tex]

v = 6.06 m/s

Answer:

vibrate

Explanation:

Vocal folds vibrate when excited by aerodynamic phenomena; they are not plucked like a guitar string. Air pressure from the lungs controls the open phase. The passing air column creates a trailing “Bernoulli effect,” which controls the close phase.

hope it helps!!

Answer:

63.8454kgm/s

Explanation:

According to Newton's second law;

Force = mass ×acceleration

Fore = m(v-u)/t

Force = mv-mu/t

MV is the final momentum

mu is the initial momentum = 38kgm/s

Force = 88.3N

Time = 0.338s

Substitute and get mv

88.3 = mv-38/0.338

88.3×0.338 = mv-38

29.8454 = mv-38

MV = 29.8454+34

mv = 63.8454kgm/s

Hence the final momentum is 63.8454kgm/s

Answer:

67.8

Explanation:

im an acellus student, and this is the answer that i got when doing the problem.

Answer: Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation: hope this helps :)

Answer:

3.3

Explanation:

Answer:

To answer your question use the code ICE on here to get your answer works every time for me hope this helps