(A)The acceleration of the boys is 6 m/s² and 4 m/s², respectively.
(B)The speeds they will reach after 0.10 s are 0.6 m/s and 0.4 m/s, respectively.
(C)The boy who did the pushing does not affect the outcome in terms of acceleration and speed.
To solve this problem, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. The formula is given by F = ma, where F is the net force, m is the mass, and a is the acceleration.
(a) To find the acceleration of each boy, we can use the formula a = F/m. Let's calculate:
For the boy with a mass of 60 kg:
a1 = F/m1 = 360 N / 60 kg = 6 m/s²
For the boy with a mass of 90 kg:
a2 = F/m2 = 360 N / 90 kg = 4 m/s²
Therefore, the acceleration of the first boy is 6 m/s², and the acceleration of the second boy is 4 m/s².
(b) To find the speed reached by each boy after 0.10 s, we can use the equation v = u + at, where v is the final velocity, u is the initial velocity (assumed to be 0 m/s as they were standing), a is the acceleration, and t is the time. Let's calculate:
For the first boy:
v1 = 0 + (6 m/s²)(0.10 s) = 0.6 m/s
For the second boy:
v2 = 0 + (4 m/s²)(0.10 s) = 0.4 m/s
Therefore, the first boy will reach a speed of 0.6 m/s, and the second boy will reach a speed of 0.4 m/s after 0.10 s.
(c) It does not matter which boy did the pushing. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. When one boy pushes the other, the force experienced by each boy is equal in magnitude but opposite in direction. Therefore, the acceleration and speed reached by each boy will be determined by their respective masses and the force applied, regardless of which boy did the pushing.
For more such information on: acceleration
https://brainly.com/question/460763
#SPJ8
How did the brightness of the bulbs differ between the simple circuit, series circuit, and parallel circuit
In a simple circuit with only one bulb connected to a battery, the brightness of the bulb will be determined by the voltage supplied by the battery and the resistance of the bulb. A higher voltage will result in a brighter bulb, assuming the resistance remains constant.
In a series circuit, where multiple bulbs are connected in a single path, the total voltage of the battery is divided among the bulbs. Each bulb experiences the same current, but the voltage across each bulb decreases as more bulbs are added. As a result, the brightness of each bulb in a series circuit will be dimmer compared to when it is connected alone in a simple circuit.
In a parallel circuit, each bulb is connected to the battery in its own separate path. Each bulb receives the full voltage of the battery, and the brightness of each bulb in a parallel circuit will be the same as when it is connected alone in a simple circuit. Therefore, the bulbs in a parallel circuit will be brighter compared to those in a series circuit.
To summarize:
In a simple circuit, the brightness of the bulb depends on the voltage supplied by the battery. In a series circuit, the brightness of each bulb is dimmer compared to a simple circuit due to the division of voltage. In a parallel circuit, the brightness of each bulb is the same as in a simple circuit because each bulb receives the full voltage.To learn more about resistance visit: https://brainly.com/question/25997303
#SPJ11
If 5800 J of work is done when a person pushes a refrigerator weighing 720 N across a floor where the force of friction between the refrigerator and the floor is 480 N, how far is the refrigerator going to move? (Make sure to put the correct unit on your answer. ) *
Work done when a person pushes a refrigerator Here are the steps to solve the problem:Refrigerators work on the second law of thermodynamics. In the process of refrigeration, unwanted heat is taken from one place and discharged into another. The common refrigerator which we have in our homes, works on the principle of evaporation.
1. Work done = Force × DistanceorDistance = Work done / Force
2. Force = Weight - Frictional force
3. Substitute the given values in the formulas above and solve the equation.1.
Work done = 5800 JForce = Weight - Frictional force= 720 N - 480 N= 240 NDistance = Work done / Force= 5800 J / 240 N= 24.2 mThus, the refrigerator is going to move 24.2 meters. The unit of distance is meter (m).
Therefore, the correct answer is 24.2 m.
To learn more about refrigerator here
https://brainly.com/question/13002119
#SPJ11
A spring is attached to the ceiling of an elevator with a block mass of 3 kg hanging from it. If the diplacement of the spring is 0.4 m while the elevator is at rest, what is the displacement of the spring when the elevator begins accelerating upward at a rate of 2 m/s2 g
The displacement of the spring when the elevator begins accelerating upward at a rate of 2 m/s² is approximately 0.48 meters in the downward direction.
To determine the displacement of the spring when the elevator begins accelerating upward, we need to consider the forces acting on the system.
When the elevator is at rest, the force exerted by the spring is balanced by the gravitational force on the block. We can set up the following equation:
k * x₀ = m * g
Where:
k is the spring constant
x₀ is the initial displacement of the spring (0.4 m)
m is the mass of the block (3 kg)
g is the acceleration due to gravity (approximately 9.8 m/s²)
Rearranging the equation, we can solve for the spring constant:
k = (m * g) / x₀
Substituting the values:
k = (3 kg * 9.8 m/s²) / 0.4 m
k ≈ 73.5 N/m
Now, let's consider the situation when the elevator starts accelerating upward at a rate of 2 m/s².
The net force acting on the block-spring system can be calculated as:
F_net = m * (g + a)
Where:
a is the acceleration of the elevator (2 m/s²)
The force exerted by the spring is given by Hooke's Law:
F_spring = -k * x
Where:
x is the displacement of the spring
At equilibrium, these forces are balanced:
F_net = F_spring
Therefore, we can write:
m * (g + a) = -k * x
Substituting the known values:
3 kg * (9.8 m/s² + 2 m/s²) = -73.5 N/m * x
3 kg * 11.8 m/s² = -73.5 N/m * x
35.4 N = -73.5 N/m * x
To solve for x, we can rearrange the equation:
x = (35.4 N) / (-73.5 N/m)
x ≈ -0.48 m
To know more about accelerating refer here
https://brainly.com/question/2303856#
#SPJ11
A resistor and a capacitor are connected in series to an ideal battery of constant terminal voltage. At the moment contact is made with the battery, the voltage across the capacitor is
When a resistor and a capacitor are connected in series to an ideal battery of constant terminal voltage, the voltage across the capacitor is zero at the moment contact is made with the battery.
What happens when a capacitor and a resistor are connected in series? Capacitors and resistors are often used in combination to build a wide range of electronic circuits. When a capacitor and a resistor are connected in series, the overall impedance of the circuit is affected, as is the overall circuit behavior. When a capacitor and a resistor are connected in series, the total impedance of the circuit is determined by their combined impedances. This total impedance will affect the overall behavior of the circuit, causing it to react in certain ways to different frequencies of input.
Learn more about capacitor:
brainly.com/question/21851402
#SPJ11
The charge on each plate of a capacitor has a magnitude of 6. 7*10^-9 C when the electric field between the plates is 29,000 V/m. If the plate separation is 3. 5*10^-4 m, what is the capacitance of the capacitor?
The charge on each plate of a capacitor has a magnitude of 6.7 × 10⁻⁹ C when the electric field between the plates is 29,000 V/m. If the plate separation is 3.5 × 10⁻⁴ m, 2.31 × 10⁻¹⁶ F is the capacitance of the capacitor
The capacitance of a capacitor can be calculated based on the charge on each plate, the electric field between the plates, and the plate separation. In this case, the charge on each plate is given as 6.7 × 10⁻⁹ C, the electric field is 29,000 V/m, and the plate separation is 3.5 × 10⁻⁴ m. The capacitance (C) of a capacitor is given by the formula:
[tex]C = Q / V[/tex]
where Q is the charge on each plate and V is the voltage or electric field between the plates. In this case, the charge on each plate is 6.7 × 10⁻⁹ C and the electric field is 29,000 V/m. Therefore, we can calculate the capacitance as follows:
C = (6.7 × 10⁻⁹ C) / (29,000 V/m)
Simplifying the expression, we can divide the charge by the electric field:
C = 2.31 × 10⁻¹⁶ F
Therefore, the capacitance of the capacitor is 2.31 × 10⁻¹⁶ Farads.
Learn more about capacitance here
https://brainly.com/question/32243099
#SPJ11
A force F of 10N is pushing horizontally a box for 2 meters. Determine the work done by the force F on the box. When needed, include the units in your answer to receive credit. Determine the work done by the force of gravity acting on box.
The work done by the force F on the box is 20 Joules. The work done by the force of gravity on the box is zero Joules.
The work done by a force is calculated using the formula: work = force × distance × cos(θ), where θ is the angle between the force and the displacement. In this case, the force F of 10N is pushing horizontally, so the angle θ between the force and the displacement is 0 degrees (cos(0) = 1). Therefore, the work done by the force F is 10N × 2m × cos(0) = 20 Joules.
The force of gravity acts vertically downward, perpendicular to the horizontal displacement. Since the displacement and force are perpendicular (θ = 90 degrees), the cosine of 90 degrees is zero (cos(90) = 0). Consequently, the work done by the force of gravity on the box is zero Joules.
learn more about force click here;
brainly.com/question/30507236
#SPJ11
How many of the large, Galilean satellites are in synchronous rotation around Jupiter (always turning the same face toward Jupiter)?
All four of the Galilean satellites are in synchronous rotation around Jupiter, always turning the same face toward Jupiter.
The inner solar system does not, however, include analogs for all of the Galilean moons' characteristics. For instance, all four of the Galilean satellites rotate synchronously as a result of Jupiter's tidal influence, ensuring that one face of each satellite is always pointed toward the parent planet.
While even Mercury's orbit is not synchronous, only Mercury among the terrestrial planets is substantially impacted by the tidal force of the Sun. The development of Jupiter and the Galilean satellites, according to many scientists, may have really resembled on a minor scale the development of the Sun and the inner planets. Studying the Galilean moon system might thus help us gain important knowledge about the processes that gave rise to the planet we live in.
Learn more about Satellites here:
https://brainly.com/question/28103637
#SPJ4
A rectangular loop of wire with sides 0. 152 and 0. 548 m lies in a plane perpendicular to a constant magnetic field (see part a of the drawing). The magnetic field has a magnitude of 0. 615 T and is directed parallel to the normal of the loop's surface. In a time of 0. 168 s, one-half of the loop is then folded back onto the other half, as indicated in part b of the drawing. Determine the magnitude of the average emf induced in the loop
The magnitude of the average emf induced in the loop is 1.13 V.
Electromotive force (EMF) is a measurement of energy produced by a battery or a generator. The electric potential difference between two points that drives an electric current through a circuit is the electromotive force (EMF). The average emf induced in the loop can be calculated using the formula below; avg EMF = B*A* (θ2 − θ1)/t where: avg EMF = average EMFB = magnetic field strength A = area of the loopθ2 and θ1 = the angles between the area vector and the magnetic field direction in the final and initial orientations of the loop, respectively.t = time taken to rotate the loop The solution to this problem is as follows: Given the length and breadth of the rectangle are 0.152 m and 0.548 m, respectively. The area of the rectangle can be calculated as; A = l × b = 0.152 m × 0.548 m = 0.083296 m²The magnetic field strength, B = 0.615 The loop is rotated by 180°, so θ2 − θ1 = πThe time taken to rotate the loop, t = 0.168s Using the formula for the average emf induced in the loop, we have; avgEMF = B*A* (θ2 − θ1)/t = 0.615 T × 0.083296 m² × π/0.168 s = 1.13 V Therefore, the magnitude of the average emf induced in the loop is 1.13 V.
Learn more about emf here:
https://brainly.com/question/30893775
#SPJ11
Normal day muscle contraction and a physical activity muscle contraction
Muscle contraction occurs during both normal day-to-day activities and physical activity. However, the intensity and duration of the contractions differ between the two scenarios.
Muscle contraction is a fundamental process that enables movement in organisms, including humans. During a normal day, muscle contraction is relatively mild and occurs in response to routine activities such as walking, breathing, and even maintaining posture.
These contractions are not very intense and do not last for extended periods as they are efficient and optimized for regular use.
On the other hand, during physical activity, muscle contraction is much more demanding and frequent.
This is because physical activity requires the body to exert an increased effort, leading to an increase in muscle activation.
This increased muscle activity may be coupled with other changes such as alterations in heart rate, oxygen uptake, and metabolism.
Physical activity muscle contractions are therefore more intense and sustained, leading to greater energy expenditure and often causing fatigue.
In conclusion, muscle contraction is vital in enabling movement, and it occurs in both normal day-to-day activities and physical activity. However, the intensity and duration of the contractions differ between the two scenarios.
Normal day-to-day activities involve mild and efficient contractions, while physical activity requires more demanding and prolonged contractions.
Learn more about metabolism here.
https://brainly.com/questions/15464346
#SPJ11
A 5 kg plant falls from a window and strikes the ground below with a speed of 6 m/s. Neglecting air resistance, what was the gravitational potential energy of the plant relative to the ground before it fell?
Gravitational energy or gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity.
Mass of plant is given as, m = 5 kg, Speed of plant before it hit the ground, v = 6 m/s and Acceleration due to gravity, g = 9.8 m/s². To calculate the gravitational potential energy of the plant relative to the ground before it fell, we will use the formula for gravitational potential energy.
Gravitational potential energy = mgh, Where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the ground (relative to a chosen reference level).When the plant is at rest on the window sill, its height above the ground is equal to h.
The initial potential energy of the plant is, Gravitational potential energy = mgh. Since the plant fell to the ground from the window, the height of the plant is equal to zero. Therefore, the initial potential energy is equal to the kinetic energy when the plant hits the ground. This can be represented as follows, Gravitational potential energy = Kinetic energy, 1/2mv²= 1/2 × 5 kg × (6 m/s)²= 90 J. Therefore, the gravitational potential energy of the plant relative to the ground before it fell was 90 J
Learn more about gravitational potential energy:
brainly.com/question/15896499
#SPJ11
An electron traveling through a wire in an electric circuit experiences a constant force of 6 multiply 10-19 N, always in the direction of its motion. How much work is done on the electron by this force as it travels through 0.4 m of the wire?
The work done on the electron by the constant force as it travels through 0.4 m of the wire is 2.4 × 10^-19 J.
What is the amount of work done on the electron by the constant force?When a force acts on an object and causes it to move in the direction of the force, work is done. Work is defined as the product of the magnitude of the force and the displacement of the object in the direction of the force.
In this case, the electron experiences a constant force of 6 × 10^-19 N in the direction of its motion. The electron travels through a distance of 0.4 m along the wire.
To calculate the work done, we use the formula:
[tex]work = force * distance * cos(\theta)[/tex]
where, theta is the angle between the force and displacement vectors.
In this case, the force and displacement are in the same direction, so cos(theta) = 1.
Substituting the given values into the formula, we have:
[tex]work = (6 * 10^-19 N) * (0.4 m) * (1)\\= 2.4 * 10^-19 J[/tex]
Therefore, the work done on the electron by the constant force as it travels through 0.4 m of the wire is 2.4 × 10^-19 J.
Learn more about Work
brainly.com/question/10958878
#SPJ11
Which structures senses straight line (linear) accelerations of the head, as might occur when riding in an elevator or holding your head at a particular angle with respect to gravity (like bent over to tie a shoe)?
The structures responsible for sensing straight-line (linear) accelerations of the head are the otolith organs located within the inner ear. The otolith organs consist of two structures: the utricle and the saccule. These organs contain small calcium carbonate crystals called otoliths, which are attached to hair cells.
When the head experiences linear acceleration, such as when riding in an elevator or tilting the head, the otolith organs detect the changes in the position of the otoliths due to gravity.
This displacement of the otoliths stimulates the hair cells, triggering nerve impulses that are sent to the brain. The brain then interprets these signals to perceive the direction and magnitude of the linear acceleration.
By sensing changes in head position with respect to gravity, the otolith organs play a crucial role in maintaining balance, posture, and spatial orientation.
To know more about otolith organs, refer here:
https://brainly.com/question/32417343#
#SPJ11
An electric oven is rated at 2000 W. Work out how long it would take to transfer 50 kJ of energy
To transfer 50 kJ of energy using an electric oven rated at 2000 W, it would take 25 seconds.
The power rating of an electric oven is given as 2000 W, which means it can transfer 2000 Joules of energy per second. To calculate the time it takes to transfer a certain amount of energy, we can use the formula:
[tex]time = energy / power[/tex]
Given that the energy to be transferred is 50 kJ and the power of the electric oven is 2000 W, we can substitute these values into the formula to find the time.
Given that we want to transfer 50 kJ of energy, we convert it to Joules by multiplying it by 1000, resulting in 50,000 J. We then divide this energy by the power of the electric oven, which is 2000 W. The result is 25 seconds.
Therefore, it would take 25 seconds to transfer 50 kJ of energy using the 2000 W electric oven.
Learn more about energy here
https://brainly.com/question/29518208
#SPJ11
Explain how the temperature of the earth is maintained and how it’s affected by other factors (6 marks)
The Earth's temperature is maintained through a delicate balance of natural processes and various factors. The greenhouse effect, solar radiation, albedo, oceanic heat distribution, and human activities
The temperature of the Earth is maintained through a combination of natural processes and the delicate balance of various factors. The primary factor that influences the Earth's temperature is the presence of an atmosphere, which acts as a protective blanket around the planet. The atmosphere plays a crucial role in regulating the amount of heat that is absorbed and radiated by the Earth.
Greenhouse Effect: The greenhouse effect is a natural process where certain gases in the atmosphere, such as carbon dioxide (CO2), water vapor, methane, and nitrous oxide, trap a portion of the outgoing heat radiation from the Earth's surface. These gases act like a blanket, allowing sunlight to penetrate but preventing some of the heat from escaping back into space. This phenomenon helps to keep the Earth warm and habitable. However, human activities have led to an increase in greenhouse gas emissions, intensifying the greenhouse effect and contributing to global warming.
Solar Radiation: The Sun is the primary source of heat for the Earth. Solar radiation, composed of visible light, ultraviolet (UV) radiation, and infrared (IR) radiation, reaches the Earth's surface. The Earth absorbs a portion of this incoming radiation, which warms the planet. The remaining radiation is reflected back into space.
Albedo: Albedo refers to the reflectivity of the Earth's surface. Different surfaces have varying abilities to reflect or absorb solar radiation. For example, ice and snow have high albedo, reflecting a significant portion of sunlight back into space. In contrast, dark surfaces like forests and oceans have low albedo, absorbing more solar radiation and contributing to warming. Changes in land cover, such as deforestation or melting ice caps, can alter the Earth's albedo and affect temperature patterns.
Oceanic Heat Distribution: The oceans play a crucial role in redistributing heat around the Earth. Ocean currents, such as the Gulf Stream, transfer warm water from the equator towards the poles, helping to moderate temperatures and maintain climate patterns. Changes in oceanic circulation can influence regional and global temperature variations.
Human Activities: Human activities, particularly the burning of fossil fuels, deforestation, and industrial processes, have significantly contributed to the increase in greenhouse gas concentrations in the atmosphere. This enhanced greenhouse effect amplifies the natural warming process, leading to global warming and climate change.
The Earth's temperature is maintained through a delicate balance of natural processes and various factors. The greenhouse effect, solar radiation, albedo, oceanic heat distribution, and human activities all play significant roles in influencing the Earth's temperature. Understanding these factors and their interactions is crucial for addressing climate change and ensuring the long-term sustainability of our planet.
To know more about Greenhouse visit:
https://brainly.com/question/27537929
#SPJ11
A 7 kg rock has been dropped from a high cliff and experiences a force of air resistance of 7 N. What is the acceleration of the rock
The acceleration of the rock is approximately 8.8 m/s².
To find the acceleration of the rock, we need to consider the net force acting on it. In this case, the net force is the difference between the force of gravity and the force of air resistance.
The force of gravity acting on the rock can be calculated using the equation F = mg, where m is the mass of the rock (7 kg) and g is the acceleration due to gravity (approximately 9.8 m/s²).
F_gravity = (7 kg) × (9.8 m/s²) = 68.6 N
The net force can be determined by subtracting the force of air resistance from the force of gravity: Net force = F_gravity - F_air resistance = 68.6 N - 7 N = 61.6 N
Finally, we can calculate the acceleration using Newton's second law, F = ma, where F is the net force and m is the mass of the rock: 61.6 N = (7 kg) × a
Solving for a, we find: a = 61.6 N / 7 kg ≈ 8.8 m/s²
Therefore, the acceleration of the rock is approximately 8.8 m/s².
To know more about acceleration, refer here:
https://brainly.com/question/30660316#
#SPJ11
If passenger comfort requires that the acceleration should be no greater in magnitude than 0.30 g , what distance is required to stop the car if its speed is initially 10 m/s (roughly 20 mi/h )
The distance required to stop the car, with an initial speed of 10 m/s and a maximum acceleration of 0.30 g, is approximately 33.06 meters.
Explanation:
To calculate the distance required to stop the car, we can use the following kinematic equation:
v^2 = u^2 + 2as
Where:
v = final velocity (0 m/s, as the car comes to a stop)
u = initial velocity (10 m/s)
a = acceleration
s = distance
Rearranging the equation to solve for s, we have:
s = (v^2 - u^2) / (2a)
Substituting the values into the equation:
s = (0^2 - 10^2) / (2 * 0.30 * 9.8)
s = -100 / 5.88
s ≈ 33.06 meters
The distance required to stop the car, with an initial speed of 10 m/s and a maximum acceleration of 0.30 g, is approximately 33.06 meters. This ensures passenger comfort by limiting the acceleration magnitude to 0.30 g, preventing excessive jolts or discomfort during braking. It is important for car manufacturers and designers to consider such factors to ensure passenger safety and comfort while optimizing braking performance.
To know more about acceleration ,visit:
https://brainly.com/question/1980605
#SPJ11
What is the relative humidity of a parcel of air that has a specific humidity of 10 g/kg and a maximum humidity of 25 g/kg
The relative humidity of a parcel of air can be determined by comparing its specific humidity to its maximum humidity. The relative humidity of the air parcel is 40%.
In this case, the parcel of air has a specific humidity of 10 g/kg and a maximum humidity of 25 g/kg. By calculating the ratio of specific humidity to maximum humidity and multiplying by 100%, we can determine the relative humidity of the air parcel.
The specific humidity of air refers to the amount of water vapor present in a unit mass of air. In this case, the specific humidity is given as 10 g/kg, meaning there are 10 grams of water vapor for every kilogram of air.
The maximum humidity, also known as the saturation specific humidity, represents the maximum amount of water vapor the air can hold at a given temperature. Here, the maximum humidity is stated as 25 g/kg, indicating that the air can hold a maximum of 25 grams of water vapor per kilogram of air at its current temperature.
To calculate the relative humidity, we divide the specific humidity by the maximum humidity and multiply by 100%: Relative Humidity = (Specific Humidity / Maximum Humidity) * 100%. Plugging in the given values, we have (10 g/kg / 25 g/kg) * 100% = 40%. Therefore, the relative humidity of the air parcel is 40%.
Learn more about humidity here: brainly.com/question/30672810
#SPJ11
If a star is receding (moving away from us) at a speed of 0.8% of the speed of light, at what wavelength would a spectral line with a laboratory wavelength of 543 nm be observed
The observed wavelength of the spectral line from the receding star would be approximately 543.004 nm.
To calculate the observed wavelength of a spectral line from a star that is receding at a given speed, we can use the formula for the Doppler effect in light:
λ_obs = λ_lab * (1 + v/c)
Where:
λ_obs is the observed wavelength
λ_lab is the laboratory wavelength
v is the velocity of the star (0.8% of the speed of light)
c is the speed of light in a vacuum
Given:
λ_lab = 543 nm (or 543 × 10^-9 meters)
v = 0.8% of c = 0.008c (where c is approximately 3 × 10^8 meters per second)
Substituting the values into the formula:
λ_obs = (543 × 10^-9 meters) * (1 + 0.008)
Calculating the value:
λ_obs ≈ 543.004 × 10^-9 meters
To know more about wavelength refer here
https://brainly.com/question/31143857#
#SPJ11
If the bolt is subjected to a compressive force of P = 21.1 kN, determine the average normal stress in the steel The 10-mm-diameter steel bolt in (Fiqure 1) is surrounded by a bronze sleeve . The outer diameter of this sleeve is 20 mm, and its inner diameter is 10 mm. Est 200 GPa, Br = 100 GPa. Express your answer to three significant figures and include appropriate units Figure 1 #1 of 1 MPa Submit My Answers Give Up Incorrect; One attempt remaining; Try Again Not quite. Check through your calculations; wrong number of significant figures ,you may have made a rounding error or used the 10 mm Part B 20 mm If the bolt is subjected to a compressive force of P = 21.1 kN, determine the average normal stress in the bronze Express your answer to three significant figures and include appropriate units u-Value Units
The average normal stress in the bronze sleeve is approximately 89,564.1 Pa (or 89.6 kPa) to three significant figures.
To determine the average normal stress in the steel and bronze components, we can use the formula for stress:
Stress = Force / Area
a) Average normal stress in the steel bolt:
Given:
Diameter of the steel bolt = 10 mm
First, we need to calculate the area of the steel bolt:
Area = π * (diameter/2)^2
Area = π * (10 mm / 2)^2
Area = π * (5 mm)^2
Area = 78.54 mm^2
Now, let's calculate the average normal stress in the steel bolt using the compressive force:
Stress = Force / Area
Stress = 21.1 kN / 78.54 mm^2
To convert the stress to the appropriate units, we need to convert kilonewtons (kN) to newtons (N) and millimeters (mm^2) to square meters (m^2):
Stress = (21.1 kN * 1000 N/kN) / (78.54 mm^2 * (10^-6 m^2/mm^2))
Stress = 268,216.4 N/m^2
The average normal stress in the steel bolt is approximately 268,216.4 Pa (or 268.2 MPa) to three significant figures.
b) Average normal stress in the bronze sleeve:
Given:
Outer diameter of the bronze sleeve = 20 mm
Inner diameter of the bronze sleeve = 10 mm
First, we need to calculate the area of the bronze sleeve:
Area = π * (outer diameter/2)^2 - π * (inner diameter/2)^2
Area = π * (20 mm / 2)^2 - π * (10 mm / 2)^2
Area = π * (10 mm)^2 - π * (5 mm)^2
Area = 235.62 mm^2
Now, let's calculate the average normal stress in the bronze sleeve using the compressive force:
Stress = Force / Area
Stress = 21.1 kN / 235.62 mm^2
To convert the stress to the appropriate units, we need to convert kilonewtons (kN) to newtons (N) and millimeters (mm^2) to square meters (m^2):
Stress = (21.1 kN * 1000 N/kN) / (235.62 mm^2 * (10^-6 m^2/mm^2))
Stress = 89,564.1 N/m^2
The average normal stress in the bronze sleeve is approximately 89,564.1 Pa (or 89.6 kPa) to three significant figures.
Note: The units used are in Pascal (Pa), which is equivalent to N/m^2.
learn more about stress here:
https://brainly.com/question/30261790
#SPJ11
While carrying a heavy box, a boy walks horizontally across a room at a constant speed. True or False: The boy is doing no work on the box.
While carrying a heavy box, a boy walks horizontally across a room at a constant speed is
False.
When the boy carries a heavy box across the room, he is indeed doing work on the box. Work, in the context of physics, is defined as the transfer of energy resulting from the application of force over a distance. In this case, the boy exerts a force on the box to move it horizontally across the room.
Even though the boy is moving at a constant speed, work is still being done because work is the product of force and displacement. In this scenario, the boy's applied force is directed horizontally, and the box moves horizontally as well, resulting in a displacement. Thus, work is being done by the boy on the box.
Click the below link, to learn more about constant speed:
https://brainly.com/question/24909693
#SPJ11
Interstellar space, far from any stars, is filled with a very low density of hydrogen atoms (H, not H2). The number density is about 1 atom/cm3 and the temperature is about 3 K. (a) Estimate the pressure in interstellar space. Give your answer in Pa and in atm. (b) What is the rms speed of the atoms
The rms speed of the hydrogen atoms in interstellar space is approximately 1.2 x 10^3 m/s.In interstellar space, the pressure can be estimated using the ideal gas law, which states that pressure (P) is equal to the product of the number density (n), Boltzmann's constant (k), and the temperature (T). Given that the number density is 1 atom/cm^3 and the temperature is 3 K, we can calculate the pressure as follows:
P = n * k * T
P = (1 atom/cm^3) * (1 cm^3/10^-6 m^3) * (1.38 x 10^-23 J/K) * (3 K)
P ≈ 4.14 x 10^-23 J/m^3
To convert this to pascals (Pa), we use the conversion factor 1 J/m^3 = 1 Pa:
P ≈ 4.14 x 10^-23 Pa
To convert this to atmospheres (atm), we use the conversion factor 1 atm = 1.01325 x 10^5 Pa:
P ≈ 4.08 x 10^-28 atm
(b) The root mean square (rms) speed of the hydrogen atoms can be calculated using the equation:
v_rms = √(3kT/m)
Where k is Boltzmann's constant, T is the temperature, and m is the mass of a hydrogen atom. The mass of a hydrogen atom is approximately 1.67 x 10^-27 kg. Plugging in the values:
v_rms = √(3 * 1.38 x 10^-23 J/K * 3 K / 1.67 x 10^-27 kg)
v_rms ≈ 1.2 x 10^3 m/s
Therefore, the rms speed of the hydrogen atoms in interstellar space is approximately 1.2 x 10^3 m/s.
To learn more about interstellar space click here: brainly.com/question/30631889
#SPJ11
The rms speed of the hydrogen atoms in interstellar space is approximately 1.2 x 10^3 m/s.In interstellar space, the pressure can be estimated using the ideal gas law, which states that pressure (P) is equal to the product of the number density (n), Boltzmann's constant (k), and the temperature (T). Given that the number density is 1 atom/cm^3 and the temperature is 3 K, we can calculate the pressure as follows:
P = n * k * T
P = (1 atom/cm^3) * (1 cm^3/10^-6 m^3) * (1.38 x 10^-23 J/K) * (3 K)
P ≈ 4.14 x 10^-23 J/m^3
To convert this to pascals (Pa), we use the conversion factor 1 J/m^3 = 1 Pa:
P ≈ 4.14 x 10^-23 Pa
To convert this to atmospheres (atm), we use the conversion factor 1 atm = 1.01325 x 10^5 Pa:
P ≈ 4.08 x 10^-28 atm
(b) The root mean square (rms) speed of the hydrogen atoms can be calculated using the equation:
v_rms = √(3kT/m)
Where k is Boltzmann's constant, T is the temperature, and m is the mass of a hydrogen atom. The mass of a hydrogen atom is approximately 1.67 x 10^-27 kg. Plugging in the values:
v_rms = √(3 * 1.38 x 10^-23 J/K * 3 K / 1.67 x 10^-27 kg)
v_rms ≈ 1.2 x 10^3 m/s
Therefore, the rms speed of the hydrogen atoms in interstellar space is approximately 1.2 x 10^3 m/s.
To learn more about interstellar space click here: brainly.com/question/30631889
#SPJ11
A rocket is launched and travels straight up at a constant velocity of 750 mph. An observer is 1.5 miles away watching the launch. How fast is the distance from the observer to the rocket increasing when the rocket is 2 miles high
The distance from the observer to the rocket is increasing at a rate of 1000 mph.
To find the rate at which the distance from the observer to the rocket is increasing, we can use the concept of relative velocity. Since the rocket is traveling straight up at a constant velocity of 750 mph and the observer is stationary, the only motion that affects the distance between them is the vertical motion of the rocket.
At the moment when the rocket is 2 miles high, we can consider a right-angled triangle formed by the observer, the rocket, and the height of the rocket. The distance from the observer to the rocket forms the hypotenuse of this triangle, and the height of the rocket is one of the perpendicular sides. We can use the Pythagorean theorem to relate these quantities:
(distance from observer to rocket)² = (height of rocket)² + (horizontal distance)²
Let's call the distance from the observer to the rocket D, the height of the rocket H, and the horizontal distance X. We are given that D = 1.5 miles and H = 2 miles. We need to find the rate at which D is changing when H is 2 miles.
Differentiating both sides of the equation with respect to time, we get:
2 * D * dD/dt = 2 * H * dH/dt + 2 * X * dX/dt
Since the observer is stationary, the horizontal distance X remains constant. Also, the rocket is traveling straight up, so dX/dt = 0. Therefore, the equation simplifies to:
D * dD/dt = H * dH/dt
Plugging in the known values, we have:
1.5 * dD/dt = 2 * dH/dt
Now, solving for dD/dt, we find:
dD/dt = (2 * dH/dt) / 1.5
Since the rocket is traveling at a constant velocity of 750 mph, the rate at which the height of the rocket is changing, dH/dt, is also 750 mph. Substituting this value, we get:
dD/dt = (2 * 750 mph) / 1.5
dD/dt = 1500 mph / 1.5
dD/dt = 1000 mph
Therefore, the distance from the observer to the rocket is increasing at a rate of 1000 mph.
Learn more about Relative velocity
brainly.com/question/29655726
#SPJ11
a car and a dump truck are involved in an accident and crash into each other. which one will have the greatest magnitude
Both the car and truck will experience the equal magnitude of force during the collision.
According to Newton's Third Law of Motion, the forces experienced by the truck and the car after a collision are equal and opposing.
Due to the automobile's lighter weight and smaller size compared to the truck, the damage brought on by the accident can be more severe for the car.
The car will, sustain far greater damage. This is due to the car's inability to withstand as much exertion as the truck can. They would both feel the same force in the event of a collision between two cars, but the smaller vehicle would be far less able to withstand it, which would cause it to be damaged.
To learn more about Newton's Third Law, click:
https://brainly.com/question/974124
#SPJ4
Wagon one moving 3.00m/s has a mass of 1.50 kg. It collides elastically with wagon two moving -1.00 m/s. Wagon two has a mass of 2 kg. After the collision wagon one is moving at -1.57 m/s. What is the final velocity of wagon two
The final velocity of wagon two (v₂') can be calculated by using this value and solving for v₂' using algebraic manipulation .So, v₂' = (2.50 kg m/s - 1.50 kg m/s x (-1.57 m/s))/2.00 kg= 1.93 m/s Hence, the final velocity of wagon two is 1.93 m/s.
Given values: Velocity of wagon one (v₁) = 3.00 m/s Mass of wagon one (m₁) = 1.50 kg Velocity of wagon two (v₂) = -1.00 m/s Mass of wagon two (m₂) = 2.00 kg Velocity of wagon one after collision (v₁') = -1.57 m/s Since the collision between wagon one and wagon two is elastic, momentum and energy of both wagons are conserved. The momentum of wagon one before the collision can be calculated using the formula:
momentum = mass x velocity
So, momentum of wagon one before the collision = m₁ v₁ = 1.50 kg x 3.00 m/s = 4.50 kg m/s The momentum of wagon two before the collision can be calculated using the formula: momentum = mass x velocity So, momentum of wagon two before the collision = m₂ v₂ = 2.00 kg x (-1.00 m/s) = -2.00 kg m/s The total momentum before the collision can be calculated by adding the momenta of both wagons before the collision. So, the total momentum before the collision = 4.50 kg m/s - 2.00 kg m/s = 2.50 kg m/s The total momentum after the collision can be calculated by adding the momenta of both wagons after the collision.
So, the total momentum after the collision = m₁ v₁' + m₂ v₂' The final velocity of wagon two (v₂') can be calculated by using this value and solving for v₂' using algebraic manipulation. So, v₂' = (2.50 kg m/s - 1.50 kg m/s x (-1.57 m/s))/2.00 kg= 1.93 m/s Hence, the final velocity of wagon two is 1.93 m/s.
To learn more about velocity visit below link
https://brainly.com/question/18084516
#SPJ11
Two skydivers of different masses jump from a plane. Explain how their falls compare, including the effects of gravity, mass, and air resistance
Both skydivers will experience the same acceleration due to gravity. This is because the gravitational force acting on the skydivers is proportional to their mass
When skydiving, the fall experience is heavily influenced by gravity, air resistance, and mass. The differences in mass result in a change in terminal velocity and same acceleration due to gravity. The more massive skydiver will have a higher terminal velocity than the less massive one. A higher terminal velocity means that the more massive skydiver will fall faster than the less massive skydiver. However, they will both experience the same acceleration due to gravity of 9.81 m/s2. The reason for this is that the force of gravity acting on the skydivers is proportional to their mass. The more massive the skydiver, the more force they will experience. Therefore, both skydivers will experience the same acceleration due to gravity. The mass of an object determines its gravitational force. An object with more mass will have a greater gravitational force than an object with less mass. Air resistance is the force that opposes the motion of an object through the air. It is proportional to the velocity of the object. Therefore, the faster an object moves through the air, the greater the air resistance it experiences. A skydiver with a greater mass will have a higher terminal velocity and will fall faster than a skydiver with a smaller mass. .
learn more about gravitational force Refer: https://brainly.com/question/29190673
#SPJ11
A long solenoid has 500 turns per meter and cross-sectional area 4.0 cm^2. The current in its windings is increasing at 100 A/s. Find the flux through the wire loop as a function of the current I.
The flux through the wire loop as a function of the current I is given by `Φ = 8 x 10⁻⁸ I Wb`.
The magnetic field in a long solenoid is provided by the formula: `B = μ₀nI`, where `B` is the magnetic field, `n` is the number of turns per unit length, `I` is the current in the solenoid windings, and `μ₀` is the permeability of free space.
The magnetic flux through a wire loop of area `A` in a magnetic field `B` is given by the formula: `Φ = B A cosθ` where `θ` is the angle between the normal to the loop and the magnetic field direction.I
n this case, the number of turns per unit length `n = 500`, the cross-sectional area `A = 4.0 cm² = 4.0 x 10⁻⁴ m²`, and the current `I` is increasing at `100 A/s`.
Therefore, the magnetic field `B` in the solenoid is given by:`B = μ₀nI` `= (4π x 10⁻⁷ T m/A) (500 turns/m) I``= 2 x 10⁻⁴ I T`The flux through the wire loop as a function of the current `I` is given by:`Φ = B A cosθ``= (2 x 10⁻⁴ I) (4.0 x 10⁻⁴ m²) cos(0)``= 8 x 10⁻⁸ I Wb`Hence, the flux through the wire loop as a function of the current I is given by `Φ = 8 x 10⁻⁸ I Wb`.
To know more about flux refer here:
https://brainly.com/question/15655691#
#SPJ11
+40v
ww
50
ww
12 0
ww
60
150
AM
60
200
ww
80 Q
For the circuit shown on the left
A. determine the equivalent resistance R
B. determine the total current in the circuit for
What physics concepts are needed to solve this problem? Write terms and definitions for each one
Answer: To solve the problem, several physics concepts are needed. Here are the terms and their definitions:
Resistance (R): Resistance is a measure of how much a material or component opposes the flow of electric current. It is measured in ohms (Ω) and determines the amount of voltage drop across a component for a given current.
Equivalent Resistance: Equivalent resistance refers to the combined or total resistance of multiple resistors connected in a circuit. It is determined using specific formulas or techniques, such as series or parallel resistor combinations.
Current (I): Current is the flow of electric charge in a circuit. It is measured in amperes (A) and represents the rate of flow of charge through a conductor. Current is the same at all points in a series circuit and splits at junctions in a parallel circuit.
Series Circuit: A series circuit is a circuit configuration where components (such as resistors) are connected one after the other, creating a single pathway for current to flow. In a series circuit, the total resistance is the sum of individual resistances, and the current remains the same throughout the circuit.
Parallel Circuit: A parallel circuit is a circuit configuration where components are connected side by side, providing multiple pathways for current to flow. In a parallel circuit, the voltage across each component is the same, and the reciprocal of the total resistance is the sum of the reciprocals of individual resistances.
Voltage (V): Voltage, also known as electric potential difference, is the driving force that pushes electric charges through a circuit. It is measured in volts (V) and determines the flow of current in a circuit. Voltage can be calculated using Ohm's Law, which states that V = I × R, where V is voltage, I is current, and R is resistance.
Ohm's Law: Ohm's Law relates voltage (V), current (I), and resistance (R) in a circuit. It states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to the resistance of the conductor. Mathematically, Ohm's Law is expressed as V = I × R or I = V / R or R = V / I.
To solve the given problem, you would need to apply these concepts to determine the equivalent resistance (R) of the circuit and calculate the total current (I) flowing through it. The problem does not provide a specific circuit diagram, so the circuit's arrangement and connections would need to be inferred or further specified to solve it accurately.
Consider a circular wheel rolling (no slip) along a flat surface. The wheel has radius 0.1 m and is rotating clockwise at 2 rad/s. What is the magnitude, in m/s2, of the absolute acceleration vector (in the earth-fixed reference frame) for the point at the bottom of the wheel that makes contact with the surface
The magnitude of the acceleration for the point at the bottom of the wheel that makes contact with the surface is 0.4 m/s²
For a body in rotational motion, the magnitude for angular acceleration a is given by a = rω², where r = radius of rotation and ω = angular speed.
Given: the radius of the wheel, r = 0.1 m
the angular speed of the wheel, ω = 2 rad/s
The magnitude of the angular acceleration, a is given by rω².
a = rω² = 0.1× 2² = 0.4 m/s²
Therefore, the magnitude of the acceleration is 0.4 m/s².
To know more about rotational motion, click here:
https://brainly.com/question/32375321
#SPJ4
Charges Q1 and Q2 exert repulsive forces of 16 N on each other. What is the repulsive force in Newtons when their separation is decreased so that their final separation is 68 % of their initial
The repulsive force between charges Q1 and Q2 will be 8 N when their separation is decreased so that their final separation is 68% of their initial separation.
To calculate the repulsive force between charges Q1 and Q2, we can use Coulomb's Law. Coulomb's Law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
Let's denote the initial separation as d1 and the final separation as d2, where d2 = 0.68 * d1. The initial force is given as 16 N.
Using Coulomb's Law, we can express the force as:
F = (k * |Q1 * Q2|) / d^2
where k is the electrostatic constant.
We can rewrite the equation as:
F = (k * |Q1 * Q2|) / (d1^2)
To find the force at the final separation, we substitute d2 into the equation:
F2 = (k * |Q1 * Q2|) / (d2^2)
Since we want to find the force when the final separation is 68% of the initial separation, we have:
d2 = 0.68 * d1
Substituting this into the equation, we have:
F2 = (k * |Q1 * Q2|) / ((0.68 * d1)^2)
We can simplify this equation to:
F2 = (0.68^2) * [(k * |Q1 * Q2|) / (d1^2)]
Given that F1 (initial force) is 16 N, we can equate the two equations:
F2 = (0.68^2) * F1
Calculating the value, we find:
F2 = (0.68^2) * 16 N
F2 ≈ 8 N
Therefore, the repulsive force between charges Q1 and Q2 is 8 N when their separation is decreased to 68% of their initial separation.
To know more about repulsive force refer here:
https://brainly.com/question/30656894#
#SPJ11
The two speakers of a boom box are 35.0 cm apart. A single oscillator makes the speakers vibrate in phase at the same frequency 2.00 kHz. At what angles, measured from the perpendicular bisector of the line joining the speakers would a distant observer hear maximum sound intensity
Measured from the perpendicular bisector of the line joining the speakers, a distant observer will hear maximum sound intensity at an angle of 28.1°.
The formula used to calculate the angles, measured from the perpendicular bisector of the line joining the speakers would a distant observer hear maximum sound intensity is given by θ = sin⁻¹ (mλ / d) where m is an integer, λ is the wavelength of the sound wave, d is the distance between the two speakers, and θ is the angle from the perpendicular bisector of the line joining the speakers.
The distance between the two speakers of a boom box is 35.0 cm and the frequency is 2.00 kHz. We can calculate the wavelength of the sound wave using the formula v = λf where v is the velocity of the wave, λ is the wavelength, and f is the frequency. The velocity of sound is approximately 343 m/s, or 34,300 cm/s. Therefore, the wavelength is:
λ = v / f = 34,300 cm/s / 2,000 Hz = 17.15 cm
The maximum sound intensity will be heard along the perpendicular bisector of the line joining the speakers, which is at an angle of 0°. The next maximum will be at an angle θ given by θ = sin⁻¹ (mλ / d), where m = 1. Substituting the values we get:
θ = sin⁻¹ (1 × 17.15 cm / 35.0 cm) = 28.1°
Therefore, a distant observer would hear maximum sound intensity at an angle of 0° along the perpendicular bisector of the line joining the speakers and at an angle of 28.1° from the perpendicular bisector of the line joining the speakers.
Learn more about sound intensity here: https://brainly.com/question/30658768
#SPJ11
