Two capacitors 6 micro farad and 8 micro farad are connected in parallel. The combination is then connected in series with a 12 V battery and 14 micro farad capacitor. What is the charge on the 6 micro farad capacitor?​

Answer:  Energy can be transferred between objects or systems through various mechanisms such as conduction, convection, radiation, and mechanical work.

In conduction, heat energy is transferred between objects or systems that are in contact with each other through direct molecular collisions. For example, if you heat a metal rod at one end, the heat energy is transferred through the rod to the other end.

In convection, heat energy is transferred between objects or systems through the movement of fluids, such as air or water. For example, when you boil water on a stove, the heat is transferred from the stove to the water through conduction. As the water heats up, it rises to the top of the pot and cooler water flows in to take its place. This process of rising and falling creates a convection current that transfers the heat energy throughout the water.

In radiation, energy is transferred through electromagnetic waves, such as light or infrared radiation. For example, the heat energy from the sun is transferred to the Earth through radiation.

Mechanical work can also transfer energy between objects or systems. For example, when you lift an object off the ground, you are doing work against the force of gravity. The energy you use to do this work is transferred to the object in the form of potential energy.

An example of energy transfer is the use of solar panels to generate electricity. When sunlight hits the solar panels, the energy is transferred through radiation, which creates an electrical current that can be used to power appliances and devices. In this case, the energy is transferred from the sun to the solar panels to the electrical devices.

Explanation: would apreciate a thanks and a brainliest :D

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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The kinetic energy affects when there is an increase in the mass and speed of the object.

When the object is in motion, Kinetic energy is observed. Kinetic energy is the product of the mass and square of the speed of an object. It depends on both the mass and speed of the object.

K.E = 1/2 (mv²), where m is the mass of the object and v is the speed of the object. Thus, the kinetic energy is directly proportional to the mass and speed of the object.

When speed increases two times, the kinetic energy increases by four times. When speed increases 3 times, the kinetic energy increases by 9. If the object has more mass, the kinetic energy also increases, and vice-versa.

Hence, the kinetic energy increases with the increase in mass and speed of the object.

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The ball is moving upwards at 4.9 m, we know its velocity at that point is 9.3 m/s (upwards). Therefore, the ball's average velocity from its starting point to 4.9 m is 9.3 m/s (upwards).

What is Velocity?

Velocity is a measure of an object's speed in a specific direction. It is a vector quantity, which means it has both magnitude (the numerical value of the speed) and direction. The formula for calculating velocity is v = d/t, where v is velocity, d is the distance traveled, and t is the time it took to travel that distance

Assuming the acceleration due to gravity is 9.8 m/[tex]s^{2}[/tex], we can use the kinematic equation:

d = Vit + (1/2)at^2

where:

d = distance traveled (4.9 m)

Vi = initial velocity (0 m/s since the ball was dropped from rest)

t = time (1 s)

a = acceleration (-9.8 m/[tex]s^{2}[/tex] since it's in the opposite direction to the ball's motion)

Solving for Vi, we get:

Vi = (d - (1/2)[tex]at^{2}[/tex])/t

Vi = (4.9 - (1/2)(-9.8)([tex]1^{2}[/tex])/1

Vi = 9.3 m/s (upwards)

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The kinetic energy of a roller coaster cart is at its maximum when the cart has its maximum velocity.

The point in time when this occurs will depend on the specific track and design of the roller coaster. Typically, the maximum velocity of a roller coaster cart is achieved at the bottom of a hill or after descending from a drop.

This is because the potential energy of the cart is converted into kinetic energy as it gains speed due to the force of gravity. As the cart descends, its potential energy decreases while its kinetic energy increases. The maximum kinetic energy is reached when all of the potential energy has been converted into kinetic energy, which occurs at the bottom of the hill or after descending from a drop.

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The position of the image is 30 cm behind the mirror.

According to the mirror formula,

1/f = 1/u + 1/v

where f is the focal length, u is the distance of the object from the mirror, and v is the distance of the image from the mirror.

Substituting the given values, we get:

1/15 = 1/10 + 1/v

Simplifying, we get:

1/v = 1/15 - 1/10 = (2 - 3)/30 = -1/30

Taking the reciprocal on both sides, we get:

v = -30 cm

The negative sign indicates that the image is virtual and located behind the mirror. Therefore, the position of the image is 30 cm behind the mirror.

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The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= [tex]\frac{f2}{f1}[/tex]

Inputting the values provided yields:

frequency ratio = [tex]\frac{576}{320Hz}[/tex] =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by [tex]2^{(4/12)}[/tex]. Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= [tex]\frac{f}{ (f1 /f2 ) }[/tex]=  [tex]\frac{f}{ (f1 / 1.3348) }[/tex]

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: [tex]2^{(7/12)}[/tex] = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × ([tex]2^{(7/12)}[/tex]) × ([tex]2^{(7/12)}[/tex]) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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The correct answer is: Mixtures are classified based on the distribution of particles in them. Is there anything else you would like to know about mixtures?

(a) The centripetal force required to keep the car traveling on the curved road is  4914.15 N.

(b) The coefficient of friction between the car's wheels and the ground must be approximately 0.334

The centripetal force required to keep a car traveling in a curved path is given by the formula:

Fc = (mv^2) / r

where;

Given:

Plugging these values into the formula, we get:

Fc = (1500 kg) (18.1)² / 100 m

Fc = 4914.15 N

The friction force between the car's wheels and the ground provides the centripetal force. The friction force can be calculated using the formula:

f = μN

where;

Since the car is not accelerating vertically, the normal force N is equal to the weight of the car, which is given by:

N = mg

where;

Plugging in the values for m and g, we get:

N = (1500 kg) * 9.8 m/s^2

N = 14700 N

Now we can use the value of the centripetal force calculated earlier to find the coefficient of friction:

4904.38 N = μ * 14700 N

μ = 4914.15 N / 14700 N

μ ≈ 0.334

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Explanation:

Vertical distance  (note conversion to METERS from km for parameters in Q)

750 m = 1/2 at^2           Where a = 9.81 m/s^2

   then t =   12.365 s

Then horizontal distance that must occur in this time frame:

 1000 m = do  + vot  + 1/2 a t^2              ( do and vo = 0 )

               where THIS a is the HORIZONTAL  accel we are looking for

1000  = 1/2 a t^2

2000 = a ( 12.365)^2

a = ~ 13.1  m/s^2

Answer:

Explanation:

I apologize for any plagiarism in my previous answer. Here is a new answer to the question:

(a) The motorcycle needs to cross the canyon safely by landing on the opposite side. Let's call the starting point of the motorcycle as point A and the landing point as point B. The horizontal distance between A and B is 1.00 km, and the vertical distance between them is 0.750 km.

To find the minimum constant acceleration in the x-direction required to cross the canyon safely, we can use the kinematic equation:

d = (1/2)at^2

where d is the horizontal distance between A and B, a is the constant acceleration in the x-direction, and t is the time it takes to cross the canyon.

We also know that the motorcycle is affected by gravity, which causes it to accelerate downwards with an acceleration of g = 9.81 m/s^2.

To cross the canyon safely, the motorcycle needs to land on the opposite side, so we can use the following inequality:

h <= (1/2)gt^2

where h is the vertical distance between A and B.

Substituting the given values, we have:

d = 1.00 km = 1000 m

h = 0.750 km = 750 m

Using the above equations, we can solve for the minimum acceleration required:

750 m <= (1/2) * 9.81 m/s^2 * t^2

1000 m = (1/2) * a * t^2

Solving for t in the first equation, we get:

t = sqrt((2 * h) / g) = sqrt((2 * 750 m) / 9.81 m/s^2) = 12.19 s

Substituting this value of t into the second equation, we get:

a = (2 * d) / t^2 = (2 * 1000 m) / (12.19 s)^2 = 6.96 m/s^2

Therefore, the minimum constant acceleration in the x-direction required to cross the canyon safely is 6.96 m/s^2.

(b) To find the speed at which the motorcycle lands, we can use the equation:

v_f = at

where v_f is the final velocity in the x-direction.

Substituting the given values, we get:

a = 6.96 m/s^2

t = 12.19 s

Therefore, the final velocity of the motorcycle in the x-direction is:

v_f = 6.96 m/s^2 * 12.19 s = 84.85 m/s

Therefore, the motorcycle lands with a horizontal speed of 84.85 m/s.

Answer:

You take the derivative of the velocity equation!

Explanation:

The acceleration basically refers to how the velocity changes over time. To find that, you need to take the derivative of the velocity equation. Comment if you would like me to show you what that looks like. Once you find the derivative you can plug your time value into the equation and get the acceleration at that time!

Answer:

find the rate of change of the velocity equation

The two locations on the x-axis where the electric potential is zero are

x₁ = 1.00 m and x₂ = 1.00 m.

To find the two locations on the x-axis where the electric potential is zero, we can use the formula for the electric potential due to a point charge:

V = kq/r

where V is the electric potential, k is Coulomb's constant (9 x 10⁹ N m²/C²), q is the charge, and r is the distance between the point charge and the location where we want to find the electric potential.

Let's call the unknown distances on the x-axis from the charge at the origin as x₁ and x₂.

The electric potential:

V₁ = k(-3.00 x 10-6 C)/x₁ and V₂ = k(8.00 x 10-6 C)/(2.00 - x2).

The total electric potential at any position on the x-axis is the algebraic sum of the electric potentials owing to the two charges since the electric potential due to each charge is a scalar quantity so,

V = V₁ + V₂

We want to find the two values of x₁ and x₂ that make V = 0. Setting V to zero and rearranging the terms, we get:

k(-3.00 x 10⁻⁶ C)/x₁ + k(8.00 x 10⁻⁶ C)/(2.00 - x₂) = 0

Multiplying both sides by x₁(2.00 - x₂),

-3.00 x 10⁻⁶ (2.00 - x₂) + 8.00 x 10⁻⁶ x₁ = 0

Expanding and rearranging, we get:

8.00 x 10⁻⁶ x₁ = 6.00 x 10⁻⁶ x₂ - 4.00 x 10⁻⁶

x₁ = 1.00 m and x₂ = 1.00 m are the two points where electric potential is zero on x axis  

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The angle at which the light refracts when it moves from air into the crown glass is 23.3°.

Refraction is the bending of light as it passes through a medium with a different density. It occurs due to a change in the speed of light as it enters a different medium.

We can use Snell's law to solve this problem, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the refractive indices of the two media:

n1 sin θ1 = n2 sin θ2

where n1 and n2 are the refractive indices of the initial and final media, and θ1 and θ2 are the angles of incidence and refraction, respectively.

From the problem, we have:

n1 = 1.000293 (air)

n2 = 1.520 (crown glass)

θ1 = 25°

We can rearrange Snell's law to solve for θ2:

sin θ2 = (n1/n2) sin θ1

sin θ2 = (1.000293/1.520) sin 25°

sin θ2 = 0.385

Taking the inverse sine of both sides, we get:

θ2 = 23.3°

Therefore, the angle at which the light refracts when it moves from air into the crown glass is 23.3°.

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The school of psychology that emphasizes direct observation rather than introspection is known as: behaviorism.

Behaviorism is a theory of psychology that focuses on the study of observable behaviors, rather than subjective mental processes. It suggests that behavior is learned through conditioning, and that environmental factors and experiences play a significant role in shaping behavior.

Behaviorists believe that psychology should focus on studying measurable behaviors and the environmental factors that influence them, rather than subjective mental processes such as thoughts and emotions.

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Answer:

To solve for the distance covered by the car, we need to use the kinematic equation:

distance = initial velocity x time + (1/2) x acceleration x time^2

We know that the initial velocity, u, is 3 m/s, the time, t, is 10 sec, and the acceleration, a, is 5 m/s². Substituting these values gives:

distance = (3 m/s) x (10 sec) + (1/2) x (5 m/s²) x (10 sec)^2

distance = 30 m + (1/2) x 5 m/s² x 100 sec²

distance = 30 m + 250 m

distance = 280 m

Therefore, the car covers a distance of 280 meters if its accelerator with 5m/s² for 10 sec at an initial velocity of 3 m/s.

Explanation:

The solubility of a substance in a solvent is affected by many factors, including temperature. In general, increasing the temperature of a solvent increases the solubility of a solute in that solvent. This relationship is known as the temperature-solubility relationship.

There are a few different ways in which temperature can affect solubility, depending on the specific solute and solvent in question. For example:

For most solid solutes in liquid solvents, increasing the temperature of the solvent will increase the solubility of the solute. This is because increasing the temperature generally increases the kinetic energy of the solvent molecules, which in turn makes it easier for them to break apart the intermolecular forces holding the solute together and form new solute-solvent interactions.

In some cases, however, the opposite may be true: the solubility of a solute in a solvent may decrease with increasing temperature. This is often observed for gases dissolved in liquids, where increasing the temperature decreases the solubility of the gas. This is because increasing the temperature of the liquid also increases the kinetic energy of the gas molecules, making them more likely to escape from the liquid and form a gas phase.

In rare cases, the temperature-solubility relationship may be more complex and exhibit unusual behavior. For example, for some solutes, the solubility may initially increase with temperature but then decrease at higher temperatures.

Overall, the relationship between temperature and solubility is an important consideration in many chemical processes, including crystallization, precipitation, and dissolution. Understanding this relationship can help scientists and engineers optimize their processes and achieve their desired outcomes.

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1) Three-phase is a type of electrical power transmission that uses three alternating currents that are out of phase with each other by 120 degrees. This type of power transmission is used extensively in industrial and commercial applications because it has several advantages over single-phase power transmission.

One of the main advantages of three-phase power is that it is more efficient than single-phase power. This is because the power is delivered in a more constant and even manner, which reduces the amount of energy lost to heat during transmission. Three-phase power also allows for the use of smaller wires and equipment than single-phase power for the same amount of power transmission, which can result in cost savings.

Overall, three-phase power is an important technology for efficient and reliable power transmission in industrial and commercial settings.

2) In a three-phase power system, the condition for balanced three-phase is that all three phases must have the same magnitude of voltage or potential difference, and their corresponding currents must be equal in magnitude and balanced in phase angle.

The voltage equation of a balanced three-phase voltage source can be expressed as:

Vph = Vline / [tex]\sqrt{3[/tex]

where:

Vph is the phase voltage, which is the voltage measured across each individual phase of the three-phase system.

Vline is the line voltage, which is the voltage measured between any two of the three phases.

Phasor diagram is given below

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a.) Based on torque considerations, the force of the bicep must be equal in magnitude to the combined torque of the weight of the forearm, weight of the baseball, and the force from the upper arm bone.

Mathematically, this can be expressed as:

F_bicep * d = (M + m) * g * (L/2)

where F_bicep is the force exerted by the bicep, d is the distance from the elbow to the point where the force is applied, M and m are the masses of the forearm and baseball, g is the acceleration due to gravity, and L is the length of the forearm.

Simplifying this equation, we get:

F_bicep = (M + m) * g * (L/2) / d

b.) Substituting the given values into the equation above, we get:

F_bicep = (4 kg + 1 kg) * 9.81 m/s^2 * (20 cm/2) / 3 cm

F_bicep = 32.73 N

Therefore, the force exerted by the bicep is 32.73 N.

c.) The force exerted by the upper arm bone must be equal in magnitude and opposite in direction to the combined force of the weight of the forearm, weight of the baseball, and the force from the bicep, in order to maintain static equilibrium.

Mathematically, this can be expressed as:

F_upper arm bone = -Mg - mg - F_bicep

Substituting the given values, we get:

F_upper arm bone = -(4 kg)*9.81 m/s^2 - (1 kg)*9.81 m/s^2 - 32.73 N

F_upper arm bone = -68.65 N

Therefore, the force exerted by the upper arm bone must be 68.65 N in the opposite direction to the combined weight and bicep force.

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The magnitude and direction of the vector is 7.95 m/s and 71.82° respectively.

Vectors are quantities that have both magnitude and direction.

To calculate the magnitude and direction of the vector, we use the formula below

Formula:

Where:

Substitute these values into equation 1

The direction of the vector can be calculated using the formula below

Formula:

Where:

Therefore,

Hence, the magnitude of the vector is 7.95 m/s.

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The force that a surface applies to an object in touch with it when it is perpendicular to the surface is called the normal force. Equal in magnitude; A book lying flat on a table and Not equal in magnitude; inclined plane, elevator.

Normal refers to something that is parallel to a surface. As you will see in the next example, if the object is on an inclination, the normal force may be less than the object's weight.

The weight of an object is balanced by the typical response force when it is sitting on a horizontal surface. Yet, not every situation lends itself to this. Yet, when an object is at rest on an inclined plane, its weight is not equal to the usual reaction force.

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The solubility of a substance in a solvent is affected by many factors, including temperature. In general, increasing the temperature of a solvent increases the solubility of a solute in that solvent. This relationship is known as the temperature-solubility relationship.

There are a few different ways in which temperature can affect solubility, depending on the specific solute and solvent in question. For example:

For most solid solutes in liquid solvents, increasing the temperature of the solvent will increase the solubility of the solute. This is because increasing the temperature generally increases the kinetic energy of the solvent molecules, which in turn makes it easier for them to break apart the intermolecular forces holding the solute together and form new solute-solvent interactions.

In some cases, however, the opposite may be true: the solubility of a solute in a solvent may decrease with increasing temperature. This is often observed for gases dissolved in liquids, where increasing the temperature decreases the solubility of the gas. This is because increasing the temperature of the liquid also increases the kinetic energy of the gas molecules, making them more likely to escape from the liquid and form a gas phase.

In rare cases, the temperature-solubility relationship may be more complex and exhibit unusual behavior. For example, for some solutes, the solubility may initially increase with temperature but then decrease at higher temperatures.

Overall, the relationship between temperature and solubility is an important consideration in many chemical processes, including crystallization, precipitation, and dissolution. Understanding this relationship can help scientists and engineers optimize their processes and achieve their desired outcomes.

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Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.

As the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.

The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.

The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.

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Answer:

The element symbol you provided is for Oxygen (O). The bottom number (8) is the atomic number, which represents the number of protons in the nucleus of an atom. So, an Oxygen atom has 8 protons. The top number (17) is the mass number, which is the sum of protons and neutrons in the nucleus. Since there are 8 protons, this means there are 9 neutrons (17-8=9). The charge of the atom is 0, which means the number of electrons is equal to the number of protons (8).

Explanation:

To solve this problem, we need to consider the effect of the earth's rotation on the tension in the rope. When Sneezy is hanging from a rope at the North Pole, he is not affected by the rotation of the earth because he is located at the axis of rotation. However, when he is hanging from a rope at the equator, he is moving at a tangential velocity of approximately 1670 km/h due to the rotation of the earth.

This tangential velocity creates a centrifugal force that acts on Sneezy and reduces the tension in the rope. The magnitude of this force can be calculated using the formula:

F = m * v^2 / r

where F is the centrifugal force, m is the mass of Sneezy, v is his tangential velocity, and r is the radius of the earth.

Assuming that Sneezy has a mass of 50 kg and the radius of the earth is 6,371 km, we can calculate the centrifugal force as follows:

F = 50 kg * (1670 km/h)^2 / (6371 km)

= 344 N

Therefore, the tension in the rope when Sneezy is hanging from it at the equator will be:

T = 485 N - 344 N

= 141 N

So the tension in the rope will be reduced by 344 N due to the centrifugal force caused by the earth's rotation.

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[tex]\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}[/tex]

[tex]\textcolor{blue}{\small\textit{If you have any further questions, feel free to ask!}}[/tex]

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Explanation:

Using the Left Hand Rule, if current points away from you and the field is to the right, the motion will point upward. Therefore, the correct answer is B. Up.

(a) The velocity of B relative to A is (-6i + 7j) m/s.

(b) The magnitude of the velocity of B relative to A is 9.22 m/s.

(c) the direction of the velocity of B relative to A is -49.2° from the positive x-axis.

a) The velocity of B relative to A, denoted as V(B/A), can be found by subtracting the velocity of A (VA) from the velocity of B (VB). So, we have:

V(B/A) = VB - VA

Given:

VB = 5i + 3j

VA = 11i - 4j

Substituting the values, we get:

V(B/A) = (5i + 3j) - (11i - 4j)

= -6i + 7j

So, the velocity of B relative to A is (-6i + 7j) m/s.

b) The magnitude of the velocity of B relative to A can be found using the formula for the magnitude of a vector, which is given by:

|V(B/A)| = √(Vx^2 + Vy^2)

Where;

Substituting the values, we get:

|V(B/A)| = √((-6)^2 + 7^2)

= √(36 + 49)

= √85

Rounded to 3 significant figures, the magnitude of the velocity of B relative to A is 9.22 m/s.

c) The direction of the velocity of B relative to A can be found using trigonometry. The angle (θ) between the positive x-axis and the velocity vector can be calculated using the inverse tangent (arctan) function:

θ = arctan(Vy / Vx)

Substituting the values, we get:

θ = arctan(7 / -6)

Using a calculator, we find that θ ≈ -49.2°

So, the direction of the velocity of B relative to A is -49.2° from the positive x-axis. Note that the negative sign indicates that the direction is in the clockwise direction.

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Answer:

b. 4.2 m/s²

Explanation:

The final velocity of the rock is zero. Therefore, the change in velocity is:

Δv = vf - vi = 0 - 5.0 = -5.0 m/s

The distance covered by the rock is 3.0 m. Therefore, the average acceleration is:

a = Δv / Δt

We do not have the value of time, so we can't calculate the acceleration directly. However, we can use the equation of motion that relates the initial velocity, final velocity, acceleration, and distance covered:

d = (vf² - vi²) / (2a)

Substituting the given values:

3.0 = (0² - 5.0²) / (2a)

Solving for acceleration:

a = -25 / (2 x 3.0) = -4.2 m/s²

The magnitude of the average acceleration is 4.2 m/s².

Therefore, the answer is (b) 4.2 m/s².