Answer:
M(dot)= 40000 kg/h Pressure= 8Mpa and T= 500C If its adiabatic then you know that it loses no heat or Q(dot) =0 You have a turbine which drives a shaft producing work for the other systems.We want to find entropy production of alpha._____ refers to the knowledge and skills necessary to manage, control, and work with hazardous materials and pollutants.
An alternating current is supplied to an electronic component with a rating that it be used only for voltages below 12 V. What is the highest Vrms that can be supplied to this component while staying below the voltage limit
Answer:
[tex]V_{rms}=6\sqrt2\ V[/tex]
Explanation:
Given that,
The maximum voltage of an alternating current, [tex]V_{max}=12\ V[/tex]
We need to find the highest Vrms that can be supplied to this component while staying below the voltage limit.
Let rms voltage in terms of peak voltage is given by :
[tex]V_{rms}=\dfrac{V}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\times \dfrac{\sqrt2}{\sqrt2}\\\\=\dfrac{12\sqrt2}{2}\\\\=6\sqrt2\ V[/tex]
Hence, the required rms voltage is [tex]6\sqrt2\ V[/tex].
A
AMINO BORCY
Two forces of 80 N and 70 N act simultaneously at a point Find the resultant force. if the
Angle between them is 150 dgree
Answer:
[tex]F_r = 40.01N[/tex]
Explanation:
Given
Let the two forces be [tex]F_1\ and\ F_2[/tex]
[tex]F_1 = 80N[/tex]
[tex]F_2 = 70N[/tex]
[tex]\theta = 150\deg[/tex]
Required
Determine the resultant force [tex]F_r[/tex]
This will be solved using parallelogram law of resultant force.
The equation is:
[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2cos\theta[/tex]
Substitute values for [tex]F_1[/tex], [tex]F_2[/tex] and [tex]\theta[/tex]
[tex]F_r^2 = 80^2 + 70^2+ 2 * 70 * 80 * cos\ 150[/tex]
[tex]F_r^2 = 6400 + 4900 + 11200* cos\ 150[/tex]
[tex]F_r^2 = 6400 + 4900 + 11200* -0.8660[/tex]
[tex]F_r^2 = 6400 + 4900 - 9699.2[/tex]
[tex]F_r^2 = 1600.8[/tex]
Take the square root of both sides
[tex]F_r = \sqrt{1600.8[/tex]
[tex]F_r = 40.01N[/tex]
Hence, the resultant force is 40.01 N
What’s are the preventive strategies for workplace violence
list the major parts in a shop's air supply system
Answer:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
Answer:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
Explanation:
Compressed air systems usually consist of the following components:
compressor.
air cooler.
air receiver tank.
filter.
dryer.
condensate trap.
distribution system
who designs each page or screen with which a user interacts?
Answer:
UI Design
Explanation:
A fluid flows though a horizontal 0.1 inch diameter pipe. When the Reynold number is 1508, the head loss over a 20-ft length of the pipe is 6.2 ft. Determine the fluid velocity.
Answer:
The fluid velocity V = 1.98 ft/s
Explanation:
From the information given:
The fluid velocity can be determined from the head-loss [tex]h_L[/tex] of a laminar pipe and it is expressed as:
[tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]
where;
f = frictional factor ; l = length; D = diameter; V= fluid velocity and g = acceleration due to gravity.
And;
[tex]f = \dfrac{64}{Re}[/tex]
For fluid movement in a laminar flow, the Reynolds number (Re) is usually lesser than 2100.
Given that:
Re = 1508 < 2100 ( laminar flow)
Then;
[tex]f = \dfrac{64}{1508}[/tex]
f = 0.04244
Also;
the head-loss [tex]h_L[/tex] = 6.2 ft
frictional force f = 0.04244
length = 20-ft
acceleration due to gravity (g) = 32.2 ft/s²
Replacing all the values into the equation [tex]h_L = f\dfrac{l\times V^2}{D \times 2g}[/tex]; the fluid velocity is:
[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.1 \times \dfrac{1}{12} \times 2\times 32.2}[/tex]
[tex]6.2 = 0.04244 \times \dfrac{20 \times V^2}{0.53667}[/tex]
6.2 × 0.53667 = 0.04244 × 20 × V²
3.327354 = 0.8488 × V²
[tex]V^2= \dfrac{3.327354} { 0.8488}[/tex]
[tex]V^2=3.92[/tex]
[tex]V = \sqrt{3.92}[/tex]
V = 1.98 ft/s
Determine the design moment strength for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb
This question is incomplete, the complete question is;
Determine the design moment strength (ϕMn) for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb = 18 ft). Report the result in kip-ft.
Use Fy=50 ksi and assume Cb=1.0 (if needed).
Answer: the design moment strength for the W21x73 steel beam is 566.25 f-ft
Explanation:
Given that;
section W 21 x 73 steel beam;
now from the steel table table for this section;
Zx = Sx = 151 in³
also given that; fy = 50 ksi and Cb = 1.0
QMn = 0.9 × Fy × Zx
so we substitute
QMn = 0.9 × 50 × 151
QMn = 6795 k-inch
we know that;
12inch equals 1 foot
so
QMn = 6795 k-inch / 12
QMn = 566.25 f-ft
Therefore the design moment strength for the W21x73 steel beam is 566.25 f-ft
What is the step in which you are testing your hypothesis
Answer:
Step 1: State your null and alternate hypothesis. ...
Step 2: Collect data. ...
Step 3: Perform a statistical test. ...
Step 4: Decide whether the null hypothesis is supported or refuted. ...
Step 5: Present your findings.
An ignition coil is an example of a. A. Step-up transformer. B. Step- down transformer. C. Relay.
D. Solenoid.
Answer:
D
Explanation:
An ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.
What is Solenoid?Solenoids may be characterized as a coil of wire that is usually in a cylindrical form and carries a current that acts like a magnet. Due to this, a migratory core is drawn into the coil when a current flows, and that is utilized especially as a switch or control for a mechanical device.
Similarly, an ignition coil also represents an example of a solenoid because it also consists of a coil of wire and carries a current that acts like a magnet. While the concept of the transformers is different as it stores a huge amount of electric current and spread it accordingly.
Therefore, an ignition coil is an example of a Solenoid. Thus, the correct option for this question is D.
To learn more about Solenoid, refer to the link:
https://brainly.com/question/1873362
#SPJ2
A piston–cylinder device contains 15 kg of saturated refrigerant-134a vapor at 280kPa. A resistance heater inside the cylinder with a value of 110V is used to transfer heat of 20.67kJ/kg to the refrigerant at constant pressure for 6min. Determine the current supplied if the final temperature is 75℃
Answer:
18.77 A
Explanation:
To solve this we use the energy balance equation, that is:
[tex]E_{in}-E_{out}=\Delta E_{sys}\\\\Q_{in}+W_{in}+W_{out}=\Delta U\\\\Q_{in}+W_{in}=\Delta U\\\\But\ W_{in}=Voltage(V)*Current(I)*change\ in\ time(\Delta t)=VI\Delta t,\Delta U=m(h_2-h_1)\\\\Given\ that\ m=15kg,V=110\ V,\Delta t=6\ min = (6*60\ s)=360\ s,Q_{in}=20.67\ kJ/kg*15\ kg=310.05\ kJ=310050\ J\\\\From\ table: At\ P_1=280kPa, h_1=249.71\ kJ/kg=249710\ J/kg;At\ P_2=280kPa \ and\ T_1=75^oC,P_2=319.95\ kJ/kg=319950\ J/kg\\\\Substituting:\\\\310500+(110*360*I)=15(319950-249710)\\\\[/tex]
[tex]39600I=1053600-310500\\\\39600I=743100\\\\I=18.77\ A[/tex]
the term applied to the chemistry of the body
Answer:
Biochemistry
Explanation:
Hope this helps :)
Answer:
Biochemistry
Have an amazing day!
Which is a better hydraulic cross section for an open channel: one with a small or a large hydraulic radius?
(20 points) A 1 mm diameter tube is connected to the bottom of a container filled with water to a height of 2 cm from the bottom. Air flows from the tube into the liquid and creates spherical bubbles with diameter about the diameter of the tube (1 mm). Everything is at 298 K. The tube is short but is connected to a much longer 2 m long hose that is 6 mm in diameter. The hose is connected to the gas supply. If there is no gas flow the water will leak into the tube and into the supply hose. When gas flows the water is blocked from entering the tube and bubbling starts. State all assumptions in answering the following questions. (a) What should be the minimum air flow rate and the gas supply pressure to keep the water from leaking back into the tube? (b) Is the flow in the hose laminar or turbulent? Is the flow in the tube laminar or turbulent?
Solution :
Given :
h = 2 cm
Diameter of the tube , d = 1 mm
Diameter of the hose, D = 6 mm
Between 1 and 2, by applying Bernoulli's principle, we get
As point 1 is just below the free surface of liquid, so
[tex]$P_1=P_{atm} \text{ and} \ V_1=0$[/tex]
[tex]$\frac{P_{atm}}{\rho g}+\frac{v_1^2}{2g} +h = \frac{P_2}{\rho g}$[/tex]
[tex]$\frac{101.325}{1000 \times 9.81}+0.02 =\frac{P_2}{\rho g}$[/tex]
[tex]$P_2 = 111.35 \ kPa$[/tex]
Therefore, 111.325 kPa is the gas supply pressure required to keep the water from leaking back into the tube.
Velocity at point 2,
[tex]$V_2=\sqrt{\left(\frac{111.135}{\rho g}+0.02}\right)\times 2g$[/tex]
= 1.617 m/s
Flow of water, [tex]$Q_2 = A_{tube} \times V_2$[/tex]
[tex]$=\frac{\pi}{4} \times (10^{-3})^2 \times 1.617 $[/tex]
[tex]$1.2695 \times 10^{-6} \ m^3/s$[/tex]
Minimum air flow rate,
[tex]$Q_2 = Q_3 = A_{hose} \times V_3$[/tex]
[tex]$V_3 = \frac{Q_2}{\frac{\pi}{4}D^2}$[/tex]
[tex]$V_3 = \frac{1.2695 \times10^{-6}}{\pi\times 0.25 \times 36 \times 10^{-6}}$[/tex]
= 0.0449 m/s
b). Reynolds number in hose,
[tex]$Re = \frac{\rho V_3 D}{\mu} = \frac{V_3 D}{\nu}$[/tex]
υ for water at 25 degree Celsius is [tex]$8.9 \times 10^{-7} \ m^2/s$[/tex]
υ for air at 25 degree Celsius is [tex]$1.562 \times 10^{-5} \ m^2/s$[/tex]
[tex]$Re_{hose}=\frac{0.0449 \times 6 \times 10^{-3}}{1.562 \times 10^{-5}}$[/tex]
= 17.25
Therefore the flow is laminar.
Reynolds number in the pipe
[tex]$Re = \frac{V_2 d}{\nu} = \frac{1.617 \times 10^{-3}}{8.9 \times 10^{-7}}$[/tex]
= 1816.85, which is less than 2000.
So the flow is laminar inside the tube.
Which of these credit building options do you personally think is the easiest method that you can see yourself doing? Explain your reasoning.
Answer:
Explanation:
Your 3-B Annual Credit Reports & Scores with Enhanced Credit Report Monitoring.
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The credit building options that I think is the easiest method that you can see yourself doing is Secured credit cards.
What is the Secured credit cards?Secured credit cards are known to be a type of card that are said to be backed by a specific refundable security deposit.
This kind of deposit is known to limit or lower the lender's risk and thus makes it better for people who do not have credit or when they do not qualify for that type of credit. This credit option is easier to get when compared to unsecured cards, as it does not need a lot of requirement.
Learn more about Secured credit cards from
https://brainly.com/question/1985056
a 1-w, 350-ω resistor is connected to 24 v. Is this resistor operating within its power rating?
Answer:
No.
Explanation:
[tex]P_r[/tex] = Power rating = 1 W
R = Resistance = [tex]350\ \Omega[/tex]
V = Voltage = [tex]24\ \text{V}[/tex]
Power is given by
[tex]P=\dfrac{V^2}{R}\\\Rightarrow P=\dfrac{24^2}{350}\\\Rightarrow P=1.65\ \text{W}[/tex]
[tex]1.65\ \text{W}>1\ \text{W}[/tex]
So
[tex]P>P_r[/tex]
Hence, the resistor is not operating within its power rating.
Type the correct answer in the box. Spell all words correctly.
A genetically engineered hormone, , can treat Mary’s child for growth hormone deficiencies by stimulating body growth and increasing muscle mass.
Answer:
recombinant human growth
Explanation:
Answer:
recombinant human growth
Explanation:
yes
