what is the approximate thermal energy in kj/mol of molecules at 75 ° c?

Answer:

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To calculate the approximate thermal energy in kilojoules per mole (kJ/mol) of molecules at a given temperature, you can use the Boltzmann constant (k) and the ideal gas law.

The Boltzmann constant (k) is approximately equal to 8.314 J/(mol·K). To convert this to kilojoules per mole, we divide by 1000:

k = 8.314 J/(mol·K) = 0.008314 kJ/(mol·K)

Now, we need to convert the temperature to Kelvin (K) since the Boltzmann constant is defined in Kelvin. To convert from Celsius to Kelvin, we add 273.15 to the temperature:

T(K) = 75°C + 273.15 = 348.15 K

Finally, we can calculate the thermal energy using the formula:

Thermal energy = k * T

Thermal energy = 0.008314 kJ/(mol·K) * 348.15 K

Thermal energy ≈ 2.894 kJ/mol

Therefore, at 75°C, the approximate thermal energy of molecules is approximately 2.894 kilojoules per mole (kJ/mol).

The heat capacity of one mole of water is approximately 75.29/1000 = 0.07529 kj/mol. This value represents the approximate thermal energy in kj/mol of water molecules at 75 ° C.

Thermal energy refers to the energy present in a system that arises from the random movements of its atoms and molecules. When a body has a temperature of 75 ° C, it has a thermal energy that depends on the type of molecules in it and their specific heat capacity.

In this context, we will consider the thermal energy in kj/mol of molecules at 75 ° C.Let's use water as an example to calculate the approximate thermal energy in kj/mol of molecules at 75 ° C. The specific heat capacity of water is 4.18 J/g °C, and the molar mass of water is 18.01528 g/mol. Therefore, the thermal energy in kj/mol of water molecules at 75 ° C can be calculated as follows:ΔH = mcΔt, whereΔH = thermal energy,m = mass of the sample,c = specific heat capacity of the sample,Δt = change in temperature

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