What is the central idea of Sowells speech Morality vs Sanctimoniousness

Salina Grant's gross pay for assembling 47 chairs in one week at Chairs and More is $567.50.

To calculate Salina Grant's gross pay, we need to determine the pay for each range of chairs assembled and sum them up.

Let's break down the calculation based on the given differential piece rate scale:

1-25 chairs: $10 each

Salina assembled 25 chairs in this range, so the pay for this range is

25 * $10 = $250.

26-40 chairs: $13 each

Salina assembled 15 chairs in this range, so the pay for this range is

15 * $13 = $195.

Chairs over 40: $17.50 each

Salina assembled 47 chairs in total, and since she already assembled 25 chairs in the first range and 15 chairs in the second range, the number of chairs in this range is

47 - 25 - 15 = 7 chairs.

The pay for this range is

7 * $17.50 = $122.50.

Now, let's sum up the pay for each range to find Salina Grant's gross pay:

$250 + $195 + $122.50 = $567.50

Therefore, Salina Grant's gross pay for assembling 47 chairs in one week at Chairs and More is $567.50.

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Answer:

CaCL2 + KL → KCL + CaL2

Step-by-step explanation:

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.

Ionic charges are not yet supported and will be ignored.

Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.

Compound states [like (s) (aq) or (g)] are not required.

You can use parenthesis () or brackets [].Li + Ag = Li + Ag

KOH + KMnO4 + H2SO4 = KOH + KMnO4 + H2SO4

C6H6O + KOH = C6H7KO2

CUO + HNO3 = CU(NO3)2 + H2O

C4H6O4 + KOH = C2K2O4 + C2H6O2

Zn + Sr(OH)2 = Sr + Zn(OH)2

Al + Pb(No3)2 = Al(No3)3 + Pb

HNO3 + Zn = Zn(NO3)2 + H2

ZnO + CH3COOH + H2O + Al2O3 = Zn(CH3COO)2*2H2O + Al2O3

BeO + Zn(OH)2 = Be(OH)2 + ZnO

CH3COOK + CH3Br = CH3COOCH3 + KBr

Pb(NO3)2 + HBr = PbBr2 + NHO3

Answer:

y = -6x + 8

Step-by-step explanation:

\begin{bmatrix}6x+y=8\\ y=-6x+8\end{bmatrix}

I don't know why it came out like this

It would take 21 weeks for the population to surpass 16,000.

The insect population P in a certain area fluctuates with the seasons and is estimated by the function P = 15,000 + 2500 sin(πt/52), where t is given in weeks.

For the population to surpass 16,000, we can set up the following equation:

15,000 + 2500 sin(πt/52) = 16,000

Subtracting 15,000 from both sides, we get:

2500 sin(πt/52) = 1000

Dividing both sides by 2500, we get:

sin(πt/52) = 0.4

We know that sin(πt/52) is positive when t is between 0 and 52 and between 104 and 156 since sine is positive in the first and second quadrants. Therefore, we can write:

πt/52 = sin⁻¹(0.4)

Multiplying both sides by 52/π, we get:

t = (52/π) sin⁻¹(0.4)

Using a calculator, we can evaluate sin⁻¹(0.4) to be approximately 0.4115 radians.

t = (52/π) (0.4115)

t = 21.02

Therefore, it would take 21 weeks for the population to surpass 16,000.

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Using a rule for exponents, we can simplify the expression and see that the correct option is B, 8.

Remember that when we have the quotient of two powers with the same base (like in this case, where the base is 2) the outcome will be a power of the same base, such that the exponent is equal to the difference between the other two exponents.

The rule is:

[tex]\frac{x^m}{x^n} = x^{m - n}[/tex]

Then we can use that to simplify the expression, we will get:

[tex]\frac{2^6}{2^3} = 2^{6 - 3} = 2^3 = 2*2*2 = 8[/tex]

We can see that the correct option is B.

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Answer: 216

Step-by-step explanation:

592-376

592-300= 292

292-70= 222

222-6= 216

Dana had to pay her friend $900, 3 months ago, and she has to pay $580 in 3 months. If her friend was charging her an interest rate of 1.50% per month. $1499.45, single payment would settle both payments today.

Given:

Simple interest = Principal × Rate × Time

Simple interest = $900 × 0.015 × 3

Simple interest = $40.50

Present Value = Future Value / (1 + Rate x Time)

Present Value = $580 / (1 + 0.015 × 3)

Present Value = $580 / 1.045

Present Value = $558.95

Total amount $580 loan is $558.95.

Total amount owed = $940.50 + $558.95

Total amount owed = $1499.45

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The first equation is a quadratic equation, and the second equation is a linear equation. The solution to the system is x = -2 and y = 7, which satisfies both equations.

A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Here, x is a variable, A is a coefficient and B is constant.

The system that is equivalent to:

O

O

O

[5-x=9x²

y = 5-x

is: x = -2, y = 7

In the given system, the first equation is a quadratic equation, and the second equation is a linear equation. The solution to the system is x = -2 and y = 7, which satisfies both equations.

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The distance between each pair of points include the following:

44. 2.8 units.

45. 5.8 units.

46. 12.0 units.

47. 16.6 units.

48. 7.1 units.

49. 4.5 units.

In Mathematics and Geometry, the distance between two (2) end points that are on a coordinate plane can be calculated by using the following mathematical equation:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Where:

x and y represent the data points (coordinates) on a cartesian coordinate.

Question 44.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(3 - 1)² + (2 - 4)²]

Distance = √[(2)² + (-2)²]

Distance = √8

Distance = 2.8 units.

Question 45.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(-2 + 7)² + (0 - 3)²]

Distance = √[(5)² + (-3)²]

Distance = √34

Distance = 5.8 units.

Question 46.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(-6 - 2)² + (-2 - 7)²]

Distance = √[(-8)² + (-9)²]

Distance = √145

Distance = 12.0 units.

Question 47.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(1 - 8)² + (-8 - 7)²]

Distance = √[(-7)² + (-15)²]

Distance = √274

Distance = 16.6 units.

Question 48.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(-5 - 2)² + (-4 + 5)²]

Distance = √[(-7)² + (1)²]

Distance = √50

Distance = 7.1 units.

Question 49.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(5 - 3)² + (5 - 1)²]

Distance = √[(2)² + (4)²]

Distance = √20

Distance = 4.5 units.

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A) One way to write mixed fractions [tex]6\frac{2}{4} \\[/tex]  is 3 + 3 + [tex]\frac{1}{4}[/tex] +[tex]\frac{1}{4}\\[/tex]

B) Saturday: 3 to 4 hours work = trim bushes and weed garden

Sunday: 4 to 5 hour work = paint sheet and mow lawn

A) [tex]6\frac{2}{4} \\[/tex]  can be written as a simple fraction 6 + [tex]\frac{2}{4}[/tex]

This can be further broken into and written as

3 + 3 +  [tex]\frac{1}{4}[/tex] +[tex]\frac{1}{4}\\[/tex]

B) Saturday : 3 to 4 hours of work

Trim bushes + Weed garden

[tex]1\frac{1}{6} +2\frac{2}{6}[/tex]

1 + [tex]\frac{1}{6}[/tex] + 2+ [tex]\frac{2}{6}\\[/tex]

3 + [tex]\frac{3}{6}[/tex]

3 + [tex]\frac{1}{2}[/tex]

[tex]3\frac{1}{2}[/tex]

Sunday: 4 to 5 hours of work

Paint sheet + mow lawn

[tex]1\frac{3}{6} +3 \frac{4}{6}[/tex]

1 + 3 + [tex]\frac{3}{6} +\frac{4}{6}[/tex]

4 + [tex]\frac{8}{6}[/tex]

[tex]4\frac{8}{6}[/tex]

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The Given question is incomplete the complete question is :

Mr. mason likes to work around the yard during the weekends

The integers that satisfy the inequality are -1, 0, 1, and 2.

To find the integer values that satisfy the inequality x < 6/(x - 1), we can start by analyzing the domain of the expression.

First, note that the denominator (x - 1) cannot be equal to zero since division by zero is undefined. Therefore, we must exclude x = 1 from the domain.

Next, consider the sign of the expression 6/(x - 1). When the denominator (x - 1) is positive, the expression will be positive. Similarly, when the denominator is negative, the expression will be negative.

Considering the inequality x < 6/(x - 1), we can divide the problem into two cases based on the sign of (x - 1):

Case 1: (x - 1) > 0

In this case, the expression 6/(x - 1) is positive. To satisfy the inequality x < 6/(x - 1), x must be less than the positive value of 6/(x - 1). Since the denominator is positive, we can drop the absolute value sign. Therefore, the inequality becomes:

x < 6/(x - 1)

Case 2: (x - 1) < 0

In this case, the expression 6/(x - 1) is negative. To satisfy the inequality x < 6/(x - 1), x must be greater than the negative value of 6/(x - 1). Since the denominator is negative, we need to flip the inequality sign and change the direction. Therefore, the inequality becomes:

x > 6/(x - 1)

Now, let's solve each case separately:

Case 1: (x - 1) > 0

Since the denominator (x - 1) is positive, we can multiply both sides of the inequality by (x - 1) without changing the direction of the inequality. This gives:

x(x - 1) < 6

Expanding the left side:

x² - x < 6

Rearranging the inequality:

x² - x - 6 < 0

Now we can factorize the quadratic:

(x - 3)(x + 2) < 0

To determine the solution, we need to consider the sign of the expression for different intervals:

When x < -2, both factors are negative, so the expression is positive.

When -2 < x < 3, the first factor (x - 3) is negative, and the second factor (x + 2) is positive, so the expression is negative.

When x > 3, both factors are positive, so the expression is positive.

Therefore, the solution to Case 1 is:

-2 < x < 3

Case 2: (x - 1) < 0

Since the denominator (x - 1) is negative, we need to flip the inequality sign. Multiplying both sides of the inequality by (x - 1) changes the direction of the inequality. This gives:

x(x - 1) > 6

Expanding the left side:

x² - x > 6

Rearranging the inequality:

x² - x - 6 > 0

Factoring the quadratic:

(x - 3)(x + 2) > 0

Considering the sign of the expression for different intervals:

When x < -2, both factors are negative, so the expression is positive.

When -2 < x < 3, the first factor (x - 3) is negative, and the second factor (x + 2) is positive, so the expression is negative.

When x > 3, both factors are positive, so the expression is positive.

Therefore, there are no solutions in Case 2.

Combining the solutions from both cases, we find that the integer values satisfying the inequality x < 6/(x - 1) are:

-2 < x < 3

In other words, the integers that satisfy the inequality are -1, 0, 1, and 2.

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Answer:

A

Step-by-step explanation:

If you look at the angles or use something to measure it you can tell that a and b are opposite sides that are parallel to each other. So they are equal.

The total interest charges to the Roth Family, after 15 years, given the monthly payment would be $ 118, 000

First, find the total amount paid over the 15 years by the Roth Family to be :

= Number of years x Monthly payment x Number of months per year

= 15 x 1, 850 x 12

= $ 333, 000

The total interest charges that the Roth Family paid would be :

= Total amount paid after 15 years - Total amount borrowed as mortgage

= 333, 000 - 215, 000

= $ 118, 000

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p = speed of the plain in still air

w = speed of the wind

when going headwind, the plane is not really going "p" fast, is really going slower, is going "p - w", because the wind is subtracting speed from it, likewise, when going with the wind the plane is not going "p" fast, is really going faster, is going "p + w", because the wind is adding its speed to it.

we also know that on the way over he flew 2000 miles and on the way back he flew again the same 2000 miles back.

[tex]{\Large \begin{array}{llll} \underset{distance}{d}=\underset{rate}{r} \stackrel{time}{t} \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{against the wind}&2000&p-w&10\\ \textit{with the wind}&2000&p+w&8 \end{array}\hspace{3.5em} \begin{cases} 2000=(p-w)(10)\\\\ 2000=(p+w)(8) \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{using the 1st equation}}{2000=(p-w)10}\implies \cfrac{2000}{10}=p-2\implies 200=p-w\implies \boxed{200+w=p} \\\\\\ \stackrel{\textit{using the 2nd equation}}{2000=(p+w)8}\implies \cfrac{2000}{8}=p+w\implies 250=p+w \\\\\\ \stackrel{\textit{substituting "p" from above}}{250=(200+w)+w}\implies 250=200+2w\implies 50=2w\implies \cfrac{50}{2}=w \\\\\\ \boxed{25=w}\hspace{10em}\stackrel{ 200+(25) }{\boxed{225=p}}[/tex]

The simple interest owed on a $340 loan at 6.6% interest for 9 years is $201.96.

The simple interest formula is expressed as;

I = P × r × t

Where I is interest, P is principal, r is interest rate and t is time.

Given that:

Principal P = $340

Interest Rate r = 6.6%

Time t = 9 years

First convert the interest rate from percent to decimal:

Rate = r/100

Rate = 6.6/100

Rate = 0.066

Now, plug the values into the above formula and solve for interest.

I = P × r × t

I = $340 × 0.066 × 9

I = $201.96

Therefore, the simple interest is $201.96.

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Answer:

Step-by-step explanation:

Total cost function, C = 15+9x-6x²+x

By differentiation,

dc/dx= 9-12x²+1

but

dc/dx= 0

9-12x²+1 = 0

-12x = -10

x=10/12

x=5/6

Answer: You divide it, get your answer, move the decimal point to the right twice, and that's you're percent.

Step-by-step explanation:

1/4=.25

.25 > 25%

Answer:

The answer is 25%

Step-by-step explanation:

To change decimal to percentage multiply by 100

1/4×100%

=25%

Answer:

[tex]\frac{4685}{288}[/tex]

Step-by-step explanation:

The explanation is attached below.

The true statements about 388.33 are:

The value of the hundredth digit, 0.03, is 10 times the value of the tenth digit, 0.3.

The value of the tenth digit, 0.3, is 10 times the value of the hundredth digit, 0.03.

We have,

The statement "The value of the tens digit, 80, is 10 times the value of the one's digit, 8" is incorrect. The tens digit is actually 3, not 80.

The statement "The value of the hundredths digit, 0.03, is 10 times the value of the tenths digit, 0.3" is true.

The hundredth digit is 3 times smaller than the tenth digit, which means that the tenth digit is 10 times larger than the hundredth digit.

The statement "The value of the one's digit, 8, is the value of the tens digit, 80" is incorrect.

The tens digit is 3, not 80.

The statement "The value of the hundredths digit, 0.03, is to the value of the tenths digit, 0.3" is unclear and not a proper comparison, so it cannot be determined whether it is true or false.

Thus,

The true statements about 388.33 are:

The value of the hundredth digit, 0.03, is 10 times the value of the tenth digit, 0.3.

The value of the tenth digit, 0.3, is 10 times the value of the hundredth digit, 0.03.

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4. RSTU is a trapezoid because the opposite sides RS and UT are parallel.

5. RSTU is not an isosceles trapezoid because the diagonals are not congruent.

In order to verify that RSTU is a trapezoid, we would have to determine slope of the pair of opposite sides and check whether at least one pair of opposite sides are parallel;

RU ║ ST

Slope of side RU = Slope of side ST

Slope of RU = (y₂ - y₁)/(x₂ - x₁)

Slope of RU = (1 + 3)/(5 + 3)

Slope of RU = 4/8

Slope of RU = 0.5.

Slope of RS = (y₂ - y₁)/(x₂ - x₁)

Slope of RS = (-9 + 3)/(-4 + 3)

Slope of RS = -6/-1

Slope of RS = 6.

Slope of ST = (y₂ - y₁)/(x₂ - x₁)

Slope of ST = (-2 - 1)/(10 - 5)

Slope of ST = -3/5

Slope of ST = -0.6.

Slope of UT = (y₂ - y₁)/(x₂ - x₁)

Slope of UT = (-2 + 9)/(10 + 4)

Slope of UT = 7/14

Slope of UT = 0.5.

Therefore, RSTU is a trapezoid because the opposite sides RS and UT are parallel.

Question 5.

In order to determine whether RSTU is an isosceles trapezoid, we would have to determine length of the diagonals by using the distance formula and check whether they are congruent;

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Distance RT = √[(-2 + 3)² + (10 + 3)²]

Distance RT = √170 units.

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Distance US = √[(5 + 4)² + (1 + 9)²]

Distance US = √181 units.

Therefore, RSTU is not an isosceles trapezoid because the diagonals RT and US are not congruent.

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The expression 2ab + [tex]c^2[/tex]  represents the area of the figure as the sum of the area of the shaded triangles and the area of the white square.

The equivalent expression [tex]a^2 +b^2+2ab[/tex] use the length of the figure to represent the area.

[tex]2ab +c^2=a^2+b^2+2ab[/tex]

Subtracting 2ab from both sides

[tex]c^2=a^2+b^2[/tex]

Figure of a square with some shaded triangles.

Area of the triangle formula is 1/2 times base times height

base =a and height =a

Area of one triangle = 1/2ab

There are 4 shaded triangles

Area of 4 shaded triangles = 4 x 1/2ab

Area of the square = side times side

Now we find the area of outer square. side length is a+b

Area of outside square = (a + b)(a + b) = [tex](a+b)^2[/tex] = [tex]a^2 +b^2+2ab[/tex]

Using the length of the figure to represent the area.

Thus, now set both the areas equal to each other.

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Your question seems incomplete, the probable complete question is

The probability that in a sample of 200 Americans, the proportion that uses CNN as their primary news source is at least 0.21 is 49.6%.

The probability is determined using the normal approximation to the binomial distribution.

Given that the sample size is large (n = 200) and the probability of success (p = 0.15) is not too close to 0 or 1, the mean (μ) and standard deviation (σ) of the binomial distribution, will be:

μ = n * p

μ = 200 * 0.15

μ = 30

σ = √(n * p * (1 - p))

σ = √(200 * 0.15 * (1 - 0.15))

σ ≈ 4.29

Then, the z-score corresponding to the proportion of 0.21 is:

z = (x - μ) / σ

z = (0.21 - 0.15) / 4.29

z ≈ 0.014

Using a calculator, the probability of a z-score of 0.014 is approximately 0.504.

Hence, the probability of obtaining a proportion at least 0.21, is:

Probability = 1 - 0.504

Probability ≈ 0.496

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The absolute error is $1825, the relative error is 2

An absolute error is a determinant of how large an error is. A relative error defines how good or bad an error is.

The formula for determining an absolute error is;

The formula for determining a relative error is:

From the parameters given:

The absolute error can be computed as:

Absolute error = 2559 - (2559 - 1825)

Absolute error = 2559 - 734

Absolute error = $1825

The relative error = 1825 ÷ 734

The relative error = 2.4

The relative error ≅ 2 (as an integer)

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Answer: $71,400

Step-by-step explanation:

We will set up a proportion with income in the numerator and pounds in the denominator.

       [tex]\displaystyle \frac{\$12}{4.2\;lbs} =\frac{\$x}{24,990\;lbs}[/tex]

Then we will cross-multiply.

       4.2 * x = 12 * 24,990

       4.2x = 299,880

Lastly, we will divide both sides of the equation by 4.2.

       x = $71,400

The income from 24,990 pounds of strawberries would be approximately $71,690.14.

To find the income from 24,990 pounds of strawberries, we need to use a proportion:

4.2 pounds of strawberries sells for $12, so 1 pound of strawberries sells for $12/4.2 = $2.86 (rounded to two decimal places).

Therefore, 24,990 pounds of strawberries would sell for:

$2.86 x 24,990 = $71,690.14 (rounded to two decimal places).

The function which has a range of real numbers is f(x) = -x + 2

Range is the set of the values that the function obtains this set is the values that the function obtains when we put an x value in the function.

In f(x) = -x + 2 when we put any value of x we get real number so the function range is ( -∞ , ∞ )

In g(x) = -x² when we put any value of x we get all negative number function range is (-∞ , 0]

In h(x) = [tex]2^{x}[/tex] + 1 when we put any value of x we get all positive number so the function range is (1 , ∞)

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The equation is verified, and we have shown that E_0 = cos⁴θ is equivalent to E_0 = E_0 (1/2 + cos2θ/2)².

We have,

To verify the equation

E_θ = E_0 cos^4θ = E_0 (1/2 + cos2θ/2)², we can expand the right-hand side and simplify it.

Starting with the right-hand side of the equation:

E_0 (1/2 + cos2θ/2)²

Expanding the square using the binomial expansion:

E_0 [(1/2)² + 2(1/2)(cos2θ/2) + (cos2θ/2)²]

Simplifying:

E_0 [1/4 + cos2θ + (cos2θ)²/4]

Combining the terms:

E_0 [1/4 + 4cos²θ/4 + (cos²θ)²/4]

Simplifying further:

E_0 [1/4 + 4cos²θ/4 + cos⁴θ/4]

Combining the terms again:

E_0 [1/4 + 4cos²θ/4 + cos⁴θ/4] = E_0 [1/4 + 4cos²θ/4 + cos⁴θ/4]

Simplifying the expression yields:

E_0 cos⁴θ = E_0 cos⁴θ

Therefore,

The equation is verified, and we have shown that E_0 = cos⁴θ is equivalent to E_0 = E_0 (1/2 + cos2θ/2)².

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Answer:

Polygon D is similar to polygon ABCD.

Answer:

4(1/2)(3)(5) + (3^2) = 30 + 9 = 39 ft^2

The lines intersect at only one specific point (-5, 9)

The correct answer is: There is one unique solution (-5, 9).

When two straight-line equations intersect at a point, it means that there is one unique solution to the system of equations. In this case, the point of intersection is (-5, 9), which indicates that the system has a single solution. This means that there is a unique set of values for the variables that satisfy both equations simultaneously.

If the system had no solution, it would mean that the two lines are parallel and will never intersect. However, since the lines in the given system intersect at (-5, 9), it implies that there is a solution.

Alternatively, if the system had infinitely many solutions, it would mean that the two equations represent the same line. In this case, the lines intersect at every point along their entire length, resulting in an infinite number of solutions. However, the fact that the lines intersect at only one specific point (-5, 9) indicates that there is one unique solution to the system of equations.

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