What is the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.3, and the temperature is 37.0 °C? ?G°\' for the reaction is –16.7 kJ/mol.

Answer:

yes its c

Explanation:

Answer:

The answer of 1×10 -8 is 2

Explanation:

a. Write the molecular formula of the compound.

Acetaminophen contains 8 carbon atoms, 9 Hydrogen atoms, 1 Nitrogen atom and 2 Oxygen atoms.

The molecular formular is given as;  C8H9NO2

b. What is the hybridization state of each C, N, and O atom?

From the image attached;

All the carbon atoms in the benzene ring has hybridization of sp2.

The carbon that is doubly bonded (carbonyl) to the oxygen has hybridization of sp2

The last carbon to the right has hybridization of sp3

The hybridization of nitrogen in the compound is sp3 hbridized.

Oxygen atom in alcohol  is sp3 hybridised

Oxgen in the carbonyl group is sp2 hybridized.

Answer:

12*2= 24

Mg 24 is twice heavier than carbon

Explanation:

The atomic mass of one carbon 12 atom = 12 g/mol

Relative atomic mass [tex](A_{r})[/tex] of an element is the mass of one of its atoms relative to 1/12 the mass of one atom of carbon-12.

Relative atomic mass [tex](A_{r})[/tex] is given by the formula

[tex](A_{r})[/tex] = (Average mass of an atom ×12)/(mass of one atom of carbon-12)

From the question, x is twice heavier as one carbon 12 atom

∴ mass of x = 2 × 12 g/mol

mass of x = 24 g/mol

Then, the relative atomic mass of elements x​ is calculated thus

[tex]A_{r}= \frac{24gmol^{-1} \times 12}{12 gmol^{-1} }[/tex]

[tex]A_{r} = 24 \\[/tex]

Hence, the relative atomic mass of elements x​ is 24.

(NOTE: Relative atomic mass is unitless)

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Answer:

The correct answer is 0.3582 M.

Explanation:

Based on the given information, the volume of KOH given is 19.55 ml, the volume of sulfuric acid given is 20.20 ml, and the molarity of sulfuric acid is 0.3467 M. There is a need to find the molarity of KOH.

The formula to use in the given case is,

M1V1 = M2V2

Here M1 is the molarity of KOH, V1 is the volume of KOH, M2 is the molarity of sulfuric acid, and V2 is the volume of H2SO4.

Here V1 is 19.55 ml, M2 is 0.3467 M, and V2 is 2020 ml.

Now putting the values in the equation we get,

M1 * 19.55 = 0.3467 * 20.20

M1 * 19.55 = 7.00334

M1 = 7.00334/19.55

M1 = 0.3582 M

Hence, the molarity of the given KOH is 0.3582.

The molarity of a solution of potassium hydroxide is 0.3582M

To get the molarity of the solution of potassium hydroxide KOH, we will apply the formula;

[tex]C_1V_1=C_2V_2[/tex]

Given the following parameters;

C₂ = 0.3467M

V₂ = 20.20mL

V₁ = 19.55mL

C₁ = ?

Substitute the given parameters into the formula:

C₁ × 19.55 = 0.3467× 20.20

C₁ × 19.55 = 7.00334

C₁ = 7.00334/19.55

C₁ = 0.3582M

Hence the molarity of a solution of potassium hydroxide is 0.3582M

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Answer:

[tex]M_{K^+}=2.1M[/tex]

Explanation:

Hello!

In this case, since we know the initial and final concentrations and the added volume of water, we can write:

[tex]3.50M*V_1=0.700M(0.210L+V_1)[/tex]

Which can be solved for the initial volume as follows:

[tex]3.50M*V_1-0.700M(0.210L+V_1)=0\\\\3.50V_1-0.147-0.7V_1=0\\\\2.8V_1=0.147\\\\V_1=\frac{0.147}{2.8}=0.0525L[/tex]

It means that the final volume is:

[tex]V_2=0.210L+0.0525L=0.2625L[/tex]

Next, we compute the moles of potassium phosphate in solution:

[tex]n_{K_3PO_4}=0.2625L*0.700\frac{molK_3PO_4}{L}=0.184molK_3PO_4[/tex]

Then, since 1 mol of potassium phosphate has 3 moles of potassium (K's subscript), we compute the moles of potassium ions:

[tex]n_{K^+}=0.184molK_3PO_4*\frac{3molK^+}{1molK_3PO_4}=0.551molK^+[/tex]

Finally, the concentration of potassium ions turns out:

[tex]M_{K^+}=\frac{0.551molK^+ }{0.2625L}\\\\ M_{K^+}=2.1M[/tex]

Regards!

Answer:

it is the unit of Force

Explanation:

force is equal to Newton

Answer:

pH = 2.98

Explanation:

pKa of HNO2 is 3.35

HNO2 reacts with NaOH as follows:

HNO2 + NaOH → NaNO2 + H2O

Where moles of NaOH added are equal to NaNO2 produced

And initial moles of HNO2 - Moles NaOH = Moles HNO2

Initial moles HNO2:

0.0200L * (0.10mol/L) = 0.00200moles HNO2

Moles NaOH = Moles NaNO2:

0.0100L * (0.10mol/L) = 0.00100 moles NaOH = Moles NaNO2

Moles HNO2:

0.00200moles - 0.00100moles = 0.00100 moles HNO2

Then, the added HCl reacts with NaNO2 producing HNO2:

HCl + NaNO2 → HNO2 + NaCl

Where moles added of HCl are moles of HNO2 produced and initial moles  of NaNO2 - moles of HCl = Moles NaNO2

Moles HCl:

4x10⁻⁵L * (10.0mol / L) = 0.00040moles HCl = Moles of HNO2 produced

Moles HNO2:

0.00100moles + 0.0004moles = 0.0014moles HNO2

Moles NaNO2:

0.00100moles - 0.0004moles = 0.0006moles NaNO2

With these moles and H-H equation we can solve for the pH of the buffer:

pH = pKa + log [NaNO2] / [HNO2]

Where pH is pH of the buffer

pKa is pKa of HNO2: 3.35

[] are moles of each species:

Replacing:

pH = 3.35 + log [0.0006moles NaNO2] / [0.0014moles HNO2]

Answer:

True

Explanation:

Methylcyclohexane has a cyclic compound of 7 carbons false classified as Saturated Hydrocarbon.

Answer:

Approximately [tex]0.224\;\rm L[/tex], assuming that this reaction took place under standard temperature and pressure, and that [tex]\rm CO_2[/tex] behaves like an ideal gas. Also assume that the reaction went to completion.

Explanation:

The first step is to find out: which species is the limiting reactant?

Assume that [tex]\rm CaCO_3[/tex] is the limiting reactant. How many moles of [tex]\rm CO_2[/tex] would be produced?

Look up the relative atomic mass of [tex]\rm Ca[/tex], [tex]\rm C[/tex], and [tex]\rm O[/tex] on a modern periodic table:

Calculate the formula mass of [tex]\rm CaCO_3[/tex]:

[tex]\begin{aligned} & M(\rm CaCO_3) \\ &= 40.078 + 12.011 + 3 \times 15.999 \\&= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the number of moles of formula units in [tex]1\; \rm g[/tex] of [tex]\rm CaCO_3[/tex] using its formula mass:

[tex]\begin{aligned}& n(\mathrm{CaCO_3})\\&= \frac{m(\mathrm{CaCO_3})}{M(\mathrm{CaCO_3})} \\ &= \frac{1\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \approx 1.00\times 10^{-2}\; \rm mol\end{aligned}[/tex].

In the balanced chemical equation, the ratio between the coefficient of [tex]\rm CaCO_3[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{CaCO_3})} = 1[/tex].

In other words, for each mole of [tex]\rm CaCO_3[/tex] formula units consumed, one mole of [tex]\rm CO_2[/tex] would be produced.

If [tex]\rm CaCO_3[/tex] is indeed the limiting reactant, all that approximately [tex]1.00\times 10^{-2}\; \rm mol[/tex] of [tex]\rm CaCO_3\![/tex] formula would be consumed. That would produce approximately [tex]1.00\times 10^{-2}\; \rm mol\![/tex] of [tex]\rm CO_2[/tex].

On the other hand, assume that [tex]\rm HCl[/tex] is the limiting reactant.

Convert the volume of [tex]\rm HCl[/tex] to [tex]\rm dm^{3}[/tex] (so as to match the unit of concentration.)

[tex]\begin{aligned}&V(\mathrm{HCl})\\ &= 50\; \rm cm^{3} \\ &= 50\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{10^{3}\; \rm cm^{3}} \\ &= 5.00\times 10^{-2}\; \rm dm^{3} \end{aligned}[/tex].

Calculate the number of moles of [tex]\rm HCl[/tex] molecules in that [tex]5.00\times 10^{-2}\; \rm dm^{3}[/tex] of this [tex]\rm 0.05\; \rm mol \cdot dm^{-3}[/tex]

[tex]\begin{aligned}& n(\mathrm{HCl}) \\ &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.05\; \rm mol \cdot dm^{-3}\\ &\quad\quad \times 5.00\times 10^{-2}\;\rm dm^{3} \\ &= 2.50 \times 10^{-3}\; \rm mol\end{aligned}[/tex].

Notice that in the balanced chemical reaction, the ratio between the coefficient of [tex]\rm HCl[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{HCl})} = \frac{1}{2}[/tex].

In other words, each mole of [tex]\rm HCl[/tex] molecules consumed would produce only [tex]0.5\;\rm mol[/tex] of [tex]\rm CO_2[/tex] molecules.

Therefore, if [tex]\rm HCl[/tex] is the limiting reactant, that [tex]2.50 \times 10^{-3}\; \rm mol[/tex] of [tex]\rm HCl\![/tex] molecules would produce only one-half as many (that is, [tex]1.25\times 10^{-3}\; \rm mol[/tex]) of [tex]\rm CO_2[/tex] molecules.

If [tex]\rm CaCO_3[/tex] is the limiting reactant, [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. However, if [tex]\rm HCl[/tex] is the limiting reactant, [tex]1.25\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be produced.

In reality, no more than [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. The reason is that all [tex]\rm CaCO_3[/tex] would have been consumed before [tex]\rm HCl[/tex] was.

After finding the limiting reactant, approximate the volume of the [tex]\rm CO_2\![/tex] produced.

Assume that this reaction took place under standard temperature and pressure (STP.) Under STP, the volume of one mole of ideal gas molecules would be approximately [tex]22.4\; \rm L[/tex].

If [tex]\rm CO_2[/tex] behaves like an ideal gas, the volume of that [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be approximately [tex]\rm 1.00\times 10^{-3}\; \rm mol \times 22.4\; \rm L = 0.224\; \rm L[/tex].

Answer:

heat wave

Explanation:

A high pressure system is a whirling mass of cool, dry air that generally brings fair weather and light winds. When viewed from above, winds spiral out of a high-pressure center in a clockwise rotation in the Northern Hemisphere.

Answer:

Following are the solution to the given question:

Explanation:

Due to the strong attachment among ions, it's indeed hard to break the covalent compounds in a combination. The ionic compounds, as they have a great melting point, become solid at room temperature, and may we say that the stronger between both the ions, as it is on a high point of fusion, is quite desirable.

Answer:

carbon dioxide and water.

Explanation:

Chemical equation:

2C₂H₆ + 7O₂      →    4CO₂ + 6H₂O

Reactants are present on the left side of chemical equation while products are present on the right side of chemical equation. In given chemical equation ethane and oxygen are reactant while carbon dioxide and water are product.

The given reaction is combustion reaction. Ethane is burnt in the presence of oxygen and produces carbon dioxide and water.

The reaction also follow the law of conservation of mass.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 2.01 × 3.77 = 7.5777

We have the final answer as

Hope this helps you

Answer:

D, D, A

Explanation:

Answer:

The philosophical view of man implies that we are moral as well as intelligence beings. It provides the framework to discover the nature of human excellence embodied by the perennial virtues towards which all men of good will tend.

Answer:

F4

Explanation:

Friction is a force that opposes motion

Answer:

D) will not form any stereoisomers since the product is a saturated hydrocarbon.

Explanation:

Stereoisomerism, or spatial isomerism,refers to a type of isomerism in which  two or more molecules have the same molecular formula and atom to atom connectivity but different three-dimensional orientations of those atoms in space.

Stereoisomerism occurs in alkenes because free rotation about the C=C bond is hindered. Thus, the molecule is "locked" in a particular orientation. In a saturated alkane, there is unrestricted free rotation about the C-C bond hence straight chain alkanes do not have steroisomers.

The product formed is 3,4-dimethyl hexane which is a straight chain saturated alkane. This compound does not exhibit stereoisomerism.

Answer:

Peer-reviewed Journal Article

Explanation:

1.Dictionary

2.Encyclopidia

3.Internet Search Engine

4.Peer-reviewed Journal Article

The correct answer as to which would be most useful in trying to obtain procedural information to replicate an experiment previously published would be a peer-reviewed journal article.

A peer-reviewed journal article is a journal article written by an expert or experts on a particular topic and has undergone thorough reviews by experts in the same field and certified to be of good-enough standards to be published.

Such an article would contain all the necessary information relating to the experiment leading to the article. Hence, in order to obtain procedural information to replicate an experiment that has been previously published, a peer-reviewed journal published on the same topic would do be the right place to seek.

Answer:

10.9 * 10^-7 m

Explanation:

We know that the Rydberg constant (R) is – 13.6 eV = -2.18 * 10^-18 J

ΔE= -R(1/nf - 1/ni)

Where;

nf = final state

ni= initial state

ΔE=  -2.18 * 10^-18(1/3 - 1/4)

ΔE= -2.18 * 10^-18(1/12)

ΔE= -1.81 * 10^-19 J

From;

ΔE=hc/λ

h = plank's constant = 6.6 * 10^-34 Js

c = 3 * 10^8 ms-1

λ = ?

λ = hc/ΔE

λ = 6.6 * 10^-34 * 3 * 10^8/ 1.81 * 10^-19

λ = 10.9 * 10^-7 m

Answer:

atoms

Explanation:

atoms combines to form compound

Answer:

120N

Explanation:

Answer:

3

Explanation:

Load / Effort

The effort is 30N and the Load is 90N.

So the MA is equal to 90/30 = 3

The molecule which has a structure that is most like aspirin is benzene.

Aspirin, also known as acetylsalicylic acid, is a pain reliever, fever reducer, and inflammation reducer.

In the structure of aspirin one aromatic ring is present in which carboxylic group is present and molecular formula of aspirin is written as C₉H₈O₄.

Hence benzene has a structure that is most like aspirin.

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Answer:

17 for chlorine atom ; 18 electrons for a chlorine ion

Answer:

pfffft definitely 10. smh silly goose

"Ground squirrels eat nuts, leaves, roots, seeds, and other plants. They also catch and eat small animals, such as insects and caterpillars.Though they are terrific climbers, these squirrels do come to the ground in search of fare such as nuts, acorns, berries, and flowers. They also eat bark, eggs, or baby birds."

Answer:

Metals

Explanation:

Answer:

CaSO₃·2H₂O

Explanation:

Empirically => CaSO₃·nH₂O

%H₂O = n(H₂O)/f.wt. x 100%

23.1% = n(H₂O)100/Ca + S +3O + nH₂O

23.1 = n(18)·100/[40 + 32 + 3(16) + n(18)]

1800n = 23.1[40 + 32 + 3(16) + n(18)]

1800n = 924 + 739.2 + 1108.8 + 415.8n

1800n - 415.8n = 924 + 739.2 + 1108.8

1385n = 2772

n = 2772/1385 = 2

∴ numerical formula => CaSO₃·2H₂O

The equilibrium concentration of H₂ : c. 9.55 x 10⁻³ M

Given

Kc = 54.6 at 425°C

The concentration of Hl = 0.0706 mol/L

Required

The equilibrium concentration of H₂ (and I₂)

Solution

[tex]\tt Kc=\dfrac{[HI]^2}{[H_2][I_2]}\\\\54.6=\dfrac{0.0706^2}{[H_2][I_2]}[/tex]

[H₂][I₂]=[H₂]²

[tex]\tt [H_2][I_2]=\dfrac{0.0706^2}{54.6}=[H_2]=9.55\times 10^-3~M[/tex]

The gas phase concentration of H2 and I2 is  9.55 x 10-3M.

The equation of the reaction is;

          H2      +       I2 ------>        2HI

We also have the information that the equilibrium constant of the process is  54.6.

Now recall that;

Kc = 2HI/[H2] [I2]

We can assume that the concentration of H2 = concentration of I2

Hence; [H2] = [I2] = x

54.6 = [0.0706]^2/x^2

54.6x^2 =  [0.0706]^2

x = √ [0.0706]^2/54.6

x = 9.55 x 10-3M

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Answer:

Lathanum .

Atomic number = 57

Symbol = La

Atomic weight = 138.9

No of energy orbitals = 6

Electronic configuration

[tex][Xe]6s^25d^1[/tex]

Answer:

yeah they're both balanced out