what is the principles of electric motor​

Answers

Answer 1

Answer:

Explanation:

Electric motor: A motor is a device which converts electrical energy into mechanical energy.

Principle of motor : A motor works on the principle that when a rectangular coil is placed in a magnetic field and current is passed through it. A force acts on the coil which rotates it continuously.


Related Questions

I NEED. HELP PLEASE, THANKS! :) Air is an insulator. However, in winter you might experience a spark when your fingers touch a doorknob. Briefly explain why this happens.

Answers

Answer:

This is because of the static electricity which is generated in bodies due to friction. Time to time, the door knob gets touched by many people and the charge on it goes on increasing because of increasing friction. When the charge is increased much, after a considerable time, one may get a spark or a mild shock.

A​ DC-9 aircraft leaves an airport from a runway whose bearing is N4343degrees°E. After flying for one half 1 2 ​mile, the pilot requests permission to turn 90degrees° and head toward the southeast. The permission is granted. After the airplane goes 1 mile in this​ direction, what bearing should the control tower use to locate the​ aircraft? What is the bearing that the control tower should use to locate the​ aircraft? ▼ S N nothingdegrees° ▼ E W ​(Round to the nearest tenth as​ needed.)

Answers

Answer:

103.4° or S76.6°E

Explanation:

The direction N43°E is perpendicular to the direction south-east when the plane turn 90° and heads in the south-east direction.

Since the distance 1/2 mile N43°E is perpendicular to the distance 1 mile south-east, we have a right angled triangle.

So, the angle θ between the aircraft's new position and old position is gotten from tanθ = 1 ÷ 1/2 = 2

θ = tan⁻¹(2) = 63.43°

So, the total angle from North to its new position is 40° + 63.43° = 103.43°

Since we need the south-east bearing, the angle from south is 180° - 103.43° = 76.57° ≅ 76.6°

So, our bearing is 103.4° or S76.6°E

Find the magnitude of the torque that acts on the molecule when it is immersed in a uniform electric field of 6.19×105 N/C with its electric dipole vector at an angle of 69.9∘ from the direction of the field.

Answers

Answer:

[tex]\tau=5.81\times 10^5p\ N-m[/tex]

Explanation:

We have,

Electric field, [tex]E=6.19\times 10^5\ N/C[/tex]

The electric dipole vector at an angle of 69.9 degrees from the direction of the field.

The torque acting on a molecule is given by :

[tex]\tau=p\times E\\\\\tau=pE\sin\theta[/tex]

p is electric dipole moment

[tex]\tau=p\times 6.19\times 10^{5}\times \sin (69.9)\\\\\tau=5.81\times 10^5p\ N-m[/tex]

So, the magnitude of the torque acting on the molecule is [tex]5.81\times 10^5p\ N-m[/tex].

A car runs 4200m on a straight path in 40 minute. find its velocity?​

Answers

Answer:

velocity = displacement/time

= 4200m/ 2400s

= 1.75 m/s

Explanation:

40 minutes × 60 = 2400 seconds

Which scenario describes a change in velocity?

A. A skydiver that has reached terminal velocity (a constant speed) while falling.

B. A ride that spins clockwise and then counterclockwise.

C. A car traveling east at 55 km/hr.

D. A plane traveling at 800 mph at cruising altitude.

Answers

Answer: B

Explanation:

Velocity is the distance covered in a specific direction per time taken. It is a vector quantity.

When an object reaches terminal velocity, the velocity will be constant.

But a ride that spins clockwise and then counterclockwise. Will experience many changes in velocity. Since velocity is a vector quantity which has both magnitude and direction.

Change in direction is tantamount to change in velocity. Therefore, the scenario that describes a change in velocity is a  ride that spins clockwise and then counterclockwise

Answer:

B. A ride that spins clockwise and then counterclockwise.

Explanation:

A moving particle encounters an external electric field that decreases its kinetic energy from 9970 eV to 6340 eV as the particle moves from position A to position B The electric potential at A is 55.0 V and that at B is 19.0 V Determine the charge of the particle Include the algebraic sign or with your answer

Answers

Answer:

q = -1.61x10⁻¹⁷ C

Explanation:

The charge of the particle can be found using the definition of the work done by electric force:  

[tex] W = -q\Delta V [/tex]         (1)

Where:

q: is the charge

ΔV: is the difference in electric potential

The work is also equal to:

[tex] W = E_{p_{A}} - E_{p_{B}} [/tex]    (2)

Where:

[tex]E_{p_{A}}[/tex] and [tex]E_{p_{B}}[/tex] are the electric potential energy of the points A and B, respectively.

Now, by conservation of energy we have:

[tex] K_{A} + E_{p_{A}} = K_{B} + E_{p_{B}} [/tex]     (3)

Where:  

[tex]K_{A}[/tex] and [tex]K_{B}[/tex] are the kinetic energy of the points A and B, respectively.

Rearranging equation (3):  

[tex] K_{B} - K_{A} = E_{p_{A}} - E_{p_{B}} [/tex]      

[tex] K_{B} - K_{A} = W [/tex]

[tex] K_{B} - K_{A} = -q\Delta V [/tex]

Solving the above equation for q:

[tex] q = -\frac{K_{B} - K_{A}}{V_{B} - V_{A}} = -\frac{6340 eV - 9970 eV}{19.0 V - 55.0 V} = -100.83 e \cdot \frac{1.6 \cdot 10^{-19} C}{1 e} = -1.61 \cdot 10^{-17} C [/tex]                                              

Therefore, the charge of the particle is -1.61x10⁻¹⁷ C.

I hope it helps you!

A boy of mass 45kg sits 109cm to the left of the seesaw. Another boy of mass 29000g wants to balance the seesaw. At what distance he needs to sit?

Answers

Answer:

166 cm

Explanation:

Given :

d1 =109cm

M1= 45kg

M2=29000g = 29 kg

As we know that Newton second law

[tex]Force\ =\ Mass\ *\ Acceleration[/tex]

Here M1= 45kg  

and acceleration=[tex]9.81 m/s^{2}[/tex]

Therefore

[tex]F1=45 * 9.81[/tex]

[tex]F1= 441.45 N[/tex]

M2=29000g = 29 kg

Similarly

[tex]F2= 29 * 9.81\\ F2= 284.4 N[/tex]

Now we using the Principal of moments

[tex]F1 * d1 =F2 *d2[/tex]

[tex]441.5 * 109\ =\ 290\ *\ d2\\48,123.5=290 d2\\d2 =165.9[/tex]

~ d2=166 cm

Earth's atmosphere is made up of mostly nitrogen (78%) and oxygen (21%); however, there are other gases in smaller amounts, like argon, carbon dioxide, neon, helium, hydrogen, and more. If there was an increase of carbon dioxide in the atmosphere, how would this affect temperature? A) The temperature would increase globally. B) The temperature would decrease globally. C) Temperature doesn't relate to the composition of the atmosphere; it has to do with the sun's rays. D) The temperature would not be affected since carbon dioxide is only one component in the atmosphere.

Answers

Answer:

the temperature would increase globally because carbon dioxde contributes to global warming increase the temperature of the earth

Explanation:

i hope this will help you

If there is an increase of carbon dioxide in the atmosphere, this affects temperature the temperature would increase globally. The correct option is B.

What is global warming?

The term “global warming” refers to a steady increase in the average temperature of the Earth's atmosphere and oceans, a phenomenon that is thought to be irreversibly altering the Earth's climate.

Our poles' waters are melting as a result of global warming. When our polar ice caps melt the majority of the way, many coastal communities will flood. Extreme weather, such as greater hurricanes, larger thunderstorms, and wider areas affected by other natural catastrophes, will also occur.

The temperature would decrease globally because carbon dioxide contributes to global warming, increasing the temperature of the earth.

Therefore, the correct option is B) The temperature would decrease globally.

To learn more about global warming, refer to the link:

https://brainly.com/question/7486747

#SPJ2

I NEED HELP PLEASE, THANKS! :)
Tom’s father is 48 years old. He is not able to see nearby objects clearly.
-What may be the reason for his vision problem?
-Where are images formed in this type of defected vision?
-How is this defect corrected?

Answers

Answer:

Explanation:

1) Hypermetropia (better known as Farsighted- this is why nearby objects seem blurry for him)

2) In such instances, image are typically formed farther from the near point

3) Such defects are quite common so there are common procedures such as using convex lens which can restore the sight to normal.

(b) Figure 3.32 shows the orbit of a planet around the Sun. Compare the linear speed of the planet at positions X, Y and Z.


(please help me QAQ)

Answers

At Z ... slowest speed

At Y ... fastest speed

At X ... medium speed

Wherever it is in its orbit, the line from the planet to the Sun smears over the same amount of area every second.

That's Kepler's second law of planetary motion.

The reason this happens is: That's how gravity works. (A better explanation is available, but first you have to be able to twirl calculus and solid geometry in the air on long sticks.)

6 points + Brainliest asap!
If you double the amplitude of a box on a spring, how would that affect the acceleration at maximum displacement?

The acceleration would double.

The acceleration would remain the same.

The acceleration would triple.

The acceleration would be cut in 1/2.

Answers

Answer:

  The acceleration would double

Explanation:

Assuming the same box and spring, the maximum acceleration is proportional to amplitude. When the amplitude doubles, the acceleration would double.

__

A spring is generally considered to have a linear force vs. distance characteristic. Hence, doubling the distance doubles the force. The acceleration is proportional to the force.

Question 13 of 32
1 Point
For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 7,000,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 8.2 m/s2 at this altitude.)
O A. 8239 m/s
O B. 7576 m/s
C. 6818 m/s
D. 7043 m/s

Answers

Answer: B

V = 7576 m/s

Explanation: Given that the

circular radius R = 7,000,000 m,

The acceleration due to Earth's gravity is 8.2 m/s2

Let's use gravitational field strength formula to get the mass of the satellite.

g = Gm/R^2

Where G = 6.674×10^−11m3⋅kg−1⋅s−2

Substitutes all the parameters into the formula

8.2 = (6.674×10^-11 × M)/(7000000)^2

Cross multiply

4.018 × 10^14 = 6.674×10^−11M

Make M the subject of formula

M = 4.018 × 10^14 ÷ 6.674×10^−11

M = 6.02 × 10^24 kg

The Force of attraction experienced by the satellite will be

F = mg

F = 6.02 × 10^24 × 8.2

F = 4.94 × 10^25 N

But centripetal force is

F = MV^2/ R

Where V = velocity of the satellite

Substitute F, M and R into the formula

4.94×10^25 = (6.02×10^24V^2)/ 7 ×10^6

Cross multiply

3.46 × 10^32 = 6.02×10^24V^2

Make V^2 the subject of formula

V^2 = 3.46×10^32 ÷ 6.02×10^24

V^2 = 57403600.2

Find the square root of the value to get V

V = 7576 m/s

The required velocity of the satellite is 7576 m/s approximately

Magnesium metal reacts with hydrochloric acid to form magnesium chloride and hydrogen gas. Suppose we react an excess of magnesium metal with 20.0 mL of a 3.00 M solution of hydrochloric acid and collect all of the hydrogen in a balloon at 25°C and 1.00 atm. What is the expected volume of the balloon?

Answers

Answer:

0.734 L or 734 mL

Explanation:

We'll begin by calculating the number of mole of HCl in 20.0 mL of a 3.00 M solution of hydrochloric acid, HCl.

This is illustrated below:

Molarity of hcl = 3 M

Volume = 20 mL = 20/1000 = 0.02 L

Mole of HCl =..?

Molarity = mole /Volume

3 = mole /0.02

Cross multiply

Mole of HCl = 3 x 0.02

Mole of HCl = 0.06 mole.

Next, we shall determine the number of mole of Hydrogen gas, H2 produced from the reaction of 0.06 mole of HCl. This can obtain as follow:

Mg + 2HCl —> MgCl2 + H2

From the balanced equation above,

2 moles of HCl reacted to produce 1 mole H2.

Therefore, 0.06 mole of HCl will react to produce = (0.06 x 1)/2 = 0.03 mole

Therefore, 0.03 mole of H2 was produced.

Finally, we shall determine the volume of the balloon by calculating the volume of Hydrogen gas, H2 in the balloon.

The volume of H2 can be obtained by using the ideal gas equation as follow:

Pressure (P) = 1 atm

Temperature (T) = 25°C = 25°C + 273 = 298K

Number of mole (n) of H2 = 0.03 mole

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of H2 =?

PV = nRT

1 x V = 0.03 x 0.0821 x 298

V = 0.734 L = 734 mL.

Therefore, the volume of the balloon is 0.734 L or 734 mL

The fielder attempts to catch a second ball. Just before the fielder catches the ball, the air resistance acting on the ball is 1.2N. Calculate the resultant force acting on the ball. Remember to include its direction and the unit. Assume the ball is falling vertically

Answers

Answer:

Resultant force = (1.2 - 9.8m)ĵ N

where m = mass of the ball

Magnitude of the resultant force = (9.8m - 1.2) N

Since the weight of the ball is expected to exceed the air resistance (because the ball is falling vertically downwards), the direction of the resultant force is vertically downwards. Its unit is Newtons, the SI unit of Force.

Explanation:

If a ball is falling vertically downwards, the only two forces acting on the ball include the weight of the ball (the pull of gravity on the ball) and the air resistance on the ball.

Weight of the ball acts downwards and is given as mg. where m = mass of the ball and g is the acceleration due to gravity = 9.8 m/s²

W = mg = (9.8m) N

In vector form, W = (-9.8mĵ) N

The air resistance on the ball = 1.2 N, the air resistance acts in the direction opposite the motion of the ball, and since the ball is moving vertically downwards, the air resistance acts vertically upwards.

In vector form, the air resistance = (1.2ĵ) N

Hence, the resultant force acting on the ball is the vector sum of all the forces acting on the ball.

Resultant force = (-9.8mĵ) + (1.2ĵ)

= (1.2 - 9.8m)ĵ N

Since the weight of the ball is expected to exceed the air resistance (because the ball is falling vertically downwards), the direction of the resultant force is vertically downwards.

Hope this Helps!!!

A wooden block of 0.60 kg is placed on a rough surface where it is accelerated at the rate of 4 m/s2. If the force applied on the block is 12N,what frictionless force is affecting the motion of block?

Answers

Answer:

Take a look below

Explanation:

A boy rides motorbike with velocity of 20 m/s He accelerates his motorbike
to a velocity of 30 m/s for 5 second. Calculate the acceleration produced in the
motorbike.
[Ams 2ms​

Answers

Answer:

2m/s^2

Explanation:

Initial velocity(u) = 20m/s

Final velocity(v) = 30m/s

Time(t) = 5s

Using Acceleration(a) = change in velocity/time

a = v-u/t

a = 30-20/5

a = 10ms/5s

a = 2m/s^2

Calculate the force exerted by a machine that does 4800 J of work over a distance of 22.5 m?​

Answers

Answer:

About 213.33 N

Explanation:

Force can be found using the following formula:

F= w/d

where w is work in Joules (J) and d is distance in meters (m).

We know that the machine does 4800 Joules of work over a distance of 22.5 meters. Therefore,

w=4800 J

d=22.5 m

Substitute these values into the formula.

F= 4800 J/ 22.5 m

Divide 4800 by 22.5

F= 213.333333 J/m

Let's round to the nearest hundredth. The 3 in the thousandth place indicates the 3 in the hundredth place should stay.

F= 213.33 J/m

1 J/m is equal to 1 Newton, or N.

F= 213.33 N

The force exerted by the machine is about 213.33 Newtons

A 72-kg skydiver is falling from 10000 feet. At an instant during the fall, the skydiver
encounters an air resistance force of 540 Newtons. The acceleration of the skydiver at
this instant is
m/s2

Answers

Answer:

Approximately [tex]2.31\; \rm m \cdot s^{-2}[/tex] (assuming that the acceleration due to gravity is[tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Assuming that [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex] the weight on this 72-kg skydiver would be [tex]W = m \cdot g = 72 \; \rm kg \times 9.81\; \rm m \cdot s^{-2} = 706.32\; \rm N[/tex] (points downwards.)

Air resistance is supposed to act in the opposite direction of the motion. Since this skydiver is moving downwards, the air resistance on the skydiver would point upwards.

Therefore, the net force on this skydiver should be the difference between the weight and the air resistance on the skydiver:

[tex]\begin{aligned}F(\text{net force}) &= W - F(\text{air resistance})\\ &= 706.32\; \rm N - 540\; \rm N =166.32\; \rm N \end{aligned}[/tex].

Apply Newton's Second Law of motion to find the acceleration of this skydiver:

[tex]\begin{aligned}a &= \frac{F(\text{net force})}{m} \\ &= \frac{166.32\; \rm N}{72\; \rm kg} = 2.31\; \rm m \cdot s^{-2} \end{aligned}[/tex].

Which refers to a measure of how acidic or basic a solution is? a]pH b]solubility c]reactiveness d]hardness

Answers

Answer:

Option(a) i.e" pH" is the correct answer to the given question .

Explanation:

The main objective of pH value is to determining whether the solution is the acidic or the basic solution.The pH is determining the solution whether it is basic or acidic with the help of there pH value .The range of the pH value is from 0 to 14 with the following parameter it determines whether the solution is basic ,acidic or the neutral solution  .

If pH value is 7 then it is neutral solution   .If pH value is greater then 7 then the solution is then it is basic solution .If the pH value is less then 7 then the solution is the Acidic solution .

All the other option are not determining that whether the solution is acidic or the basic solution that's why these are incorrect option .

Answer:

the answer is A pH

got it right 2020

Explanation:

how can you tell the stigma from the stamens in the flowers​

Answers

Answer:

for wind pollinated flowers they have long feathery stigma that hangs outside the flower while insect pollinated have short stigma that is shorter than even the petals and it's inside the flower

Also thestigma has something that looks like a bulb underneath it and that is the ovary while the stamen is just straight

A uniform metal tube of length 5m and mass 9kg is suspended by two vertical wires attached at 50cm and 150cm respectively from the ends of the tube. Find the tension in each wire​

Answers

Answer:

force (tension) of 29.4 N (upward)  in 100 cm

force (tension) of 58.4 N (upward)  in 200 cm

Explanation:

Given:

Length of tube = 5 m (500 cm)

Mass of tube = 9

Suspended vertically from 150 cm and 50 cm.

Computation:

Force = Mass × gravity acceleration.

Force = 9.8 x 9

Force = 88.2 N

So,

Upward forces = Downward forces

D1 = 150 - 50 = 100 cm

D2 = 150 + 50 = 200 cm

And F1 = F2

F1 x D1 = F2 x D2

F1 x 100 = F2 x 200

F = 2F

Total force = Upward forces + Downward forces

3F = 88.2

F = 29.4 and 2F = 58.8 N

force (tension) of 29.4 N (upward)  in 100 cm

force (tension) of 58.4 N (upward)  in 200 cm

If you only 24 hours too live, how would you spend it...

Answers

Answer:

I would spend the 24 hours with joy and fun ...

Like I would go for a walk of 30 minutes with my puppy . And than I will spend my 2 hours with my friends on going to shopping . And than 2 hrs just helping the poors .And than just gonna waste my 30 minutes with my younger sister . And than 2 hrs with my my grandpa and with my grandmom . And than just going to the cinema to watch a movie with my parents for 3 hrs and than just . Amd than just going to have a good sleep for 14 hrs .

Explanation:

Hope it works out !!!

How can the center of gravity of a rigid body be determined?

Answers

To calculate the center of gravity, divide total weight distance moment by total mass of the system. Thus, the center of gravity is 13 meter from left-hand side.

The centre of gravity of a rigid body can be find out by suspending the body from a single point and the centre of  gravity will lie beneath point if it is symmetric. For asymmetric bodies it is calculated using the average weight per volume times the distance to the volume segment.

What is centre of gravity?

Centre of gravity is a point at which  its total weight is carried. Gravity is the force acting downward on a body which pulls the body downwards to towards the earth.

Thus at the centre of gravity of a body it experience the net gravitational pull. For a symmetrical rigid body, the centre of gravity can be determined by suspending it at various point and check at which point the object is balanced.

The point on the body just beneath the point at which it is suspended gives the centre of gravity if it balances at that point. For a unsymmetrical body we have to take different volume segments and average weight of the body.

To find more on centre of gravity, refer here:

https://brainly.com/question/20384349

#SPJ5

Can you please tell me what type of motion does these graphs represent(for example uniformly accelerated motion etc.) This is GRAPHICAL REPRESENTATION OF MOTION of grade 9 ...I have test tomorrow..Kindly clear my doubt as fast as you can..plsssssssss

Answers

Explanation:

Graph 1 is linear motion because it has constant velocity for some time.

Graph 2 is , if we see path over path we can see positif uniformy accelerated motion when the graph sketch to upper right and uniformly deaccelerated motion when goes down right.

But for all, the2nd graph motion looks random motion

A radioactive isotope has a half-life of 2 hours. If a sample of the element contains 600,000 radioactive nuclei at 12 noon, how many radioactive nuclei would be left at 6 pm?

Answers

Answer: There will be 75258 nuclei left at 6 pm.

Explanation:

a) half-life of the radioactive substance:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

[tex]t_{\frac{1}{2}}=\frac{0.69}{k}[/tex]

[tex]k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{2hours}=0.346hours^{-1}[/tex]

b) Expression for rate law for first order kinetics is given by:

[tex]A=A_0e^{-kt}[/tex]

where,

k = rate constant  

t = time for decomposition = 6 hours ( from 12 noon to 6 pm)

A = activity at time t = ?

[tex]A_0[/tex] = initial activity  = 600, 000

[tex]A=600000\times e^{-0.346\times 6}[/tex]

[tex]A=75258[/tex]

Thus there will be 75258 nuclei left at 6 pm.

A ball is falling at terminal velocity. Terminal velocity occurs when the ball is in equilibrium and the forces are balanced. Which free body diagram shows the ball falling at terminal velocity? A free body diagram with one force pointing downward labeled F Subscript g Baseline 20 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N. A free body diagram with 2 forces. The first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 5 N. A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 30 N.

Answers

Answer:

A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N.

Explanation:

This is because at terminal velocity, the ball stops accelerating and the net force on the ball is zero. For the net force to be zero, equal and opposite forces must act on the ball, so that their resultant force is zero. That is F₁ + F₂ = 0 ⇒ F₁ = -F₂

Since F₁ = 20 N, then F₂ = -F₁ = -20 N

So, if F₁ points upwards since it is positive, then F₂ points downwards since it is negative.

So, a free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N best describes the ball falling at terminal velocity.

Answer:

b

Explanation:

A heart beats 10 times in 10 seconds.
How many times does it beat in 1 minute?

Answers

The heart will beat 60 times in 1 minute.

Answer:

60

Explanation:

60secs = 1 minute

if you want to show you work further then

10 divided by 10 = 1

so each second is 1 heart beat

so then just 60 divided by 10 equals 6

so then just do 6 times 10 equals 60 beats

Resistance and resistivity are related by a: 1.factor that is dependent on the length of the material 2.factor that is dependent on the area of the material 3.proportionality constant dependent on the identity of the material 4.proportionality constant dependent on the source of the material

Answers

Answer:

1. factor that is dependent on the length of the material.

2. factor that is dependent on the area of the material

Explanation:

Resistance R is directly proportional to its length L of an object and it is inversely proportional to the crossectional area of that object.

Mathematically, this is represented as:

a) Resistance R is directly proportional to its length L of an object

R ∝ L ......... Equation 1

b) Resistance R is inversely proportional to the crossectional area (A) of an object

R ∝ 1/A ............ Equation 2

Combining the two equations together, we have:

Resistance R is directly proportional to its length L of an object

R ∝ L/A .......... Equation 3

Resistivity of a material is the natural or inherent or intrinsic property that a material has. The Resistivity of a material is not dependent on the length or crossectional area of such material. It is only temperature dependent.

The resistance of a material is also dependent on the resistivity of the material. This means the resistance of a material is directly proportional to the resistivity of the material.

R ∝ ρ........Equation 4

Combining Equation 4 and 3 together, we have:

R = ρL/A

Where:

R = Resistance

ρ = Resistivity

L = Length of the material

A = Crossectional area of the material

Resistance and resistivity are related by a factor that is dependent on the length of the material a factor that is dependent on the area of the material

Q1:A large tank is filled with water. The pressure on the base of the fish tank is 4000N/m². The base of the tank is a rectangle measuring 2.0m by 4.5m. Calculate the force on the base caused by the base of the water.

Answers

Answer:

F = 36 kN

Explanation:

It is given that,

The pressure on the base of the fish tank is 4000N/m².

The base of the tank is a rectangle measuring 2.0m by 4.5m.

Area of the base of the tank is 9 m²

We need to find the force on the base caused by the base of the water. Pressure on the base of the tank is given by the force acting per unit area such that,

[tex]P=\dfrac{F}{A}\\\\F=P\times A\\\\F=4000\times 9\\\\F=36000\ N\\\\F=36\ kN[/tex]

So, the force of 36 kN is acting on the base by the base of water.

A stone is dropped from a tower of height 3600cm.Find the velocity by which it strike the ground.Find the time taken to reach the ground.​

Answers

Answer:

1. 26.56m/s.

2. 2.71 secs.

Explanation:

The following data were obtained from the question:

Height (h) = 3600cm

Velocity (v) =..?

Time (t) =..?

Next, we shall convert the height, 36000cm to metre (m). This is illustrated below:

100cm = 1m

Therefore, 3600cm = 3600/100 = 36 m

Therefore, the height is 36m.

1. Determination of the velocity with which the stone struck the ground. This is illustrated below:

Acceleration due to gravity (g) = 9.8m/s²

Height (h) = 36m

Velocity (v) =.?

v² = 2gh

v² = 2 x 9.8 x 36

v² = 705.6

Take the square root of both side.

v = √705.6

v = 26.56m/s

Therefore, the velocity with which the stone struck the ground is 26.56m/s.

2. Determination of the time taken for the stone to reach the ground.

Height (h) = 36m

Acceleration due to gravity (g) = 9.8m/s²

Time (t) =.?

t = √(2h/g)

t = √(2 x 36/ 9.8)

t = √(72/9.8)

t = 2.71 secs

Therefore, the time taken for the stone to reach the ground is 2.71 secs

Other Questions
The Shaker Communities in New York inthe early 1800s were what kind ofcommunity?A. governmentalB. communistC. utopian Jose earns $400 during the summer. He deposits it in an account that pays simple interest at a rate of 3% per year. Which equation can you use to find the amount of simple interest that Jose earns in 1 year? Determine the possible side lengths of the third side of a triangle with known side lengths of 5 and 8. Write 5.1 x 10 to the power of one as an ordinary number. I am thinking of a number.I multiply it by 11 and subtract 78.I get the same answer if I multiplyby 6 and subtract 8.What is my number? Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest! plz answer i need this done asap Part 2: Give two examples in which solar storms impact Earth. In Rooney Company, direct labor is $20 per hour. The company expects to operate S at 10,000 direct labor hours each month. In January 2017, direct labor totaling $206,000 b is incurred in working 10,400 hours. Prepare (a) a static budget report and (b) a flexible P budget report. Evaluate the usefulness of each repor. Oil and Gas stock prices are estimated to increase by 6% each year for the next 8years. The cost of one share is $225 in year 1. If the interest rate is equal with the gradient rate, how much is the value of one share by the end of the year 8 quick plz....When 98- 128 is simplified it is equal to:A,152B, -30C. -2D. 103 can someone help me with writing this stupid essay???????? I continue to get stuck on this stupid essay! please help! What was lost and gained during the Glorious, American, and French Revolution? Crisp Cookware's common stock is expected t opay a dividend of $1.50 a share at the end of this year; its beta is 0.6. The risk free rate is 5.6% and the market risk premium is 4%. The dividend is expected to grow at some constant rate and the stock currently sells for $50 a share. Asuming the market is in equilibrium, what does the market believe will be the stock price at the end of 3 years Which is a function of nucleic acids? create movement provide structure store genetic information fight disease Which of the following is the graph of y = negative StartRoot x EndRoot + 1? The Souths resentment of the tariffs of the American System was an example of Which of the following statements regarding the staffing budget is true? a.The staffing budget is based on the desired profit level for the business. b.The staffing budget is based on a fixed human resources budget. c.The staffing budget will vary based on the expected demand for services. d.The staffing budget is based on maximum capacity. Which of the following is a triangle congruence theorem?A) SASB) ASC) SSAD) AAA If a customer at a particular grocery store uses coupons, there is a 50% probability that the customer will pay with a debit card. Thirty percent of customers use coupons and 35% of customers pay with debit cards. Given that a customer pays with a debit card, the probability that the same customer uses coupons is ________. 0.22 0.43 0.60 0.72 what slope would make these lines parallel