what type of quadrilateral is PQRS i: 3.2.2.The value of× if PS=15 units 3.2.3 The coordinates of T, the midpoint of PS PORS. - The value of y. The coordinates of W, a point on SP such that PQRW is 3.2.5 P(x:-9) S(10; 3)​

The length of arc KJG is equal to 61.21 inches.

In Mathematics and Geometry, the arc length formed by a circle can be calculated by using the following equation (formula):

Arc length = 2πr × θ/360

Where:

Central angle, θ = 85 + 59 + 95 + 95

Central angle, θ = 334°.

Radius, r = diameter/2

Radius, r = JH/2

Radius, r = 21/2

Radius, r = 10.5 in.

By substituting the given parameters into the arc length formula, we have the following;

Arc length = 2 × 3.142 × 10.5 × 334/360

Arc length = 61.21 inches.

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Thus, the positive value of δ, the absolute value δ = 0.448 using the chain rule of differentiation, not one of the options given.

To solve for δ, we need to use the chain rule of differentiation. Starting with equation (i), we can take the derivative of both sides with respect to δ:
d/dδ(a/10) = d/dδ(7.52)

Using the chain rule, we can simplify the left side of the equation:
d/dδ(a/10) = (d/d(a/10))(a/10)' = (1/10)(a/10)'

Now we can substitute in the given value for d/dδ(a/10) and solve for (a/10)':
-33.865 = (1/10)(a/10)'
(a/10)' = -338.65

Now we can use equation (i) and substitute in the value for (a/10) and (a/10)':
7.52 = a/10
-338.65 = (a/10)'

Multiplying these equations together, we get:
-2540.468 = a'

Finally, we can use the derivative of the given equation to solve for δ:

a = 75.2δ
a' = 75.2
-2540.468 = 75.2
δ = -33.77/75.2
δ = -0.448

However, the problem asks for a positive value of δ, so we take the absolute value:
δ = 0.448

Therefore, the answer is not one of the options given in the question.

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The charge on the fluorine atom in chlorine monofluoride (ClF) is approximately -1.13 electrons (e⁻).

The dipole moment (μ) of a molecule is a measure of the separation of positive and negative charges within the molecule. It is calculated by multiplying the magnitude of the charge (q) at each end of the bond by the distance (r) between them:

μ = q × r

In the case of ClF, the dipole moment is given as 0.88D. The unit of dipole moment is Debye (D), where 1D = 3.34 × 10⁻³⁰ C-m. Therefore, we can rewrite the dipole moment equation as:

0.88D = q × r

To determine which atom has a partial negative charge, we need to analyze the direction of the dipole moment vector. The dipole moment vector points from the positive end towards the negative end. In other words, the atom that attracts electrons more strongly will have a partial negative charge.

Now, let's calculate the charge on the fluorine atom in units of electrons. We can rearrange the dipole moment equation to solve for the charge (q):

q = μ / r

Plugging in the given values:

q = 0.88D / (1.63 × 10⁻¹⁰ m) [since 1 Angstrom = 1 × 10⁻¹⁰ m]

To convert the charge from Coulombs (C) to electrons (e⁻), we can use the conversion factor:

1e⁻ = 1.60 × 10⁻¹⁹ C

Let's perform the calculation:

q = (0.88D × 3.34 × 10⁻³⁰ C-m) / (1.63 × 10⁻¹⁰ m)

q ≈ 1.81 × 10⁻¹⁹ C

Now, let's convert the charge to units of electrons:

q (in e⁻) = (1.81 × 10⁻¹⁹ C) / (1.60 × 10⁻¹⁹ C)

q ≈ 1.13 e⁻

This indicates that fluorine has a partial negative charge, while chlorine has a partial positive charge.

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Consider the indefinite integral ∫ x^8 * (x^4(8 + 6x^5))^4 dx.

(a) The most appropriate substitution is u = x^4(8 + 6x^5). Taking the derivative of u with respect to x, we have du/dx = (32x^3 + 30x^8) dx. Notice that the expression inside the parentheses is almost the derivative of u. To make it match, we can divide by 32, so du/dx = (x^3 + (15/16)x^8) dx.

(b) After making the substitution, we obtain the integral ∫ (1/32) u^4 du. The x^3 term in the original expression has transformed into (1/32)u^4.

(c) Solving this integral (in terms of u) yields (1/32) * (u^5/5) + C. The antiderivative of u^4 is (u^5/5), and we divide by 32, the coefficient that appeared after the substitution.

(d) Substituting back for u, we obtain the answer ∫ x^4(8 + 6x^5)^4 dx = (1/32) * (x^4(8 + 6x^5)^5/5) + C. This is the indefinite integral in terms of x.

Note: The expression (8 + 6x^5)^5 in the final answer comes from raising the substituted expression u = x^4(8 + 6x^5) to the power of 5 in the antiderivative.

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See work in image.

parallel line

y = 4(x+3)-6

perpendicular line

just change the slope

negative reciprocol

y=-1/4 (x+3) -6

Answer:

No real roots, two complex roots

Step-by-step explanation:

By calculating the discriminant:

[tex]D=b^2-4ac=5^2-4(5)(21)=25-420=-395 < 0[/tex], then there will be no real zeroes. However, there will be two complex roots.

(a), we are asked to find the value of a missing quantity after performing addition. (b), we are given the total number of bears and asked to determine the number of bears that belong to a specific category.(c), we are given the final result of an operation and asked to determine one of the operands.(d), we are given the number of one category and a relationship between the two categories, and asked to determine the number of the other category.

a. Type: Missing value. Subtype: Direct question.

The problem asks for a missing value, which is the number of bears Clare got. It is a direct question because the problem asks for a specific value rather than asking to solve for a general equation.

b. Type: Part-whole. Subtype: Unknown part.

The problem involves a part-whole relationship, where the whole is the total number of bears that Clare has, and the part is the number of blue bears. It is an unknown part problem because the problem asks to find the unknown quantity of blue bears that Clare has.

c. Type: Change. Subtype: Start-unknown.

The problem involves a change in the number of bugs that Kwon has, and asks for the initial number of bugs that Kwon had before the change. It is a start-unknown problem because the starting value is unknown and needs to be determined.

d. Type: Comparison. Subtype: Unknown difference.

The problem involves a comparison between the number of red bugs and blue bugs that Kwon has, and asks to find the unknown quantity of blue bugs. It is an unknown difference problem because the problem asks to find the difference between the known quantity of red bugs and the unknown quantity of blue bugs.

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a. Type: Join Result Unknown, Subtype: Change Unknown b. Type: Part-Part-Whole, Subtype: Part Unknown c. Type: Join Result Unknown, Subtype: Start Unknown d. Type: Part-Part-Whole, Subtype: Part Unknown In problem a, the type of problem is Join Result Unknown, as the problem involves adding an unknown amount to a known amount to reach a certain total.

The subtype is Change Unknown, as the problem is asking how much more bears Clare got. In problem b, the type of problem is Part-Part-Whole, as the problem involves knowing the total amount and the amount of one part to find the amount of the other part. The subtype is Part Unknown, as the problem is asking how many blue bears Clare has.
In problem c, the type of problem is Join Result Unknown, as the problem involves adding an unknown amount to a known amount to reach a certain total. The subtype is Start Unknown, as the problem is asking how many bugs Kwon had at first. In problem d, the type of problem is Part-Part-Whole, as the problem involves knowing the total amount and the amount of one part to find the amount of the other part. The subtype is Part Unknown, as the problem is asking how many blue bugs Kwon has. Understanding the type and subtype of math problems can help students identify the problem-solving strategy to use. By recognizing the structure of a problem, students can develop a plan to solve it more efficiently. It also helps teachers design appropriate instructional activities that target specific problem types.

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The volume of the composite figure is equal to 860.6 cubic meters to the nearest tenth

The composite figure is a cuboid with a cylinderical open space within, so the volume is derived by subtracting the volume of the cylinderical open space from the volume of the cuboid as follows:

Volume of cuboid = length × width × height

Volume of the cuboid = 10m × 10m × 12m

Volume of the cuboid = 1200m³

Volume of cylinder is calculated using:

V = π × r² × h

Volume of the cylinder = 22/7 × (3m)² × 12m

Volume of the cylinder = 339.4m³

Volume of the composite figure = 1200m³ - 339.4m³

Volume of the composite figure = 860.6 m³

Therefore, the volume of the composite figure is equal to 860.6 cubic meters to the nearest tenth

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The statement "A high value of the correlation coefficient r implies that a causal relationship exists between x and y" is False.

A high correlation coefficient (r) indicates a strong linear relationship between x and y, but it does not necessarily imply causation.

Correlation measures the strength and direction of a relationship between two variables, while causation implies that one variable directly affects the other. It is important to remember that correlation does not equal causation.

Thus, the given statement is False.

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To find a function f such that F = ∇f and f(0, 0, 0) = 0, we need to determine the potential function associated with the vector field F. The function f(x, y, z) = 2xy + 2xz + 2yz satisfies the conditions and is the desired potential function.

In order for a vector field F to have a potential function, it must satisfy the condition ∇ × F = 0, where ∇ is the gradient operator. Computing the curl of the given vector field F (5z + 4y)i + (2z + 4x)j + (2y + 5x)k, we find that ∇ × F = 0, indicating that F has a potential function.

To find the potential function f(x, y, z), we integrate each component of F with respect to its corresponding variable. Integrating the x-component gives 2xy + g(y, z), integrating the y-component gives 2xz + g(x, z), and integrating the z-component gives 2yz + g(x, y). Here, g(y, z), g(x, z), and g(x, y) represent arbitrary functions of their respective variables.

Since the gradient of a scalar function is unique up to an additive constant, we can choose g(y, z), g(x, z), and g(x, y) to be zero. Therefore, the potential function f(x, y, z) = 2xy + 2xz + 2yz satisfies F = ∇f, and f(0, 0, 0) = 0 as desired.

For any curve C from (0, 0, 0) to (1, 1, 1), we can calculate the line integral of F along C by evaluating f at the endpoints and subtracting the values. Using f(1, 1, 1) - f(0, 0, 0), we obtain the desired result.

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there is no equations

Hey There!

Step-by-step explanation:

Which of the matrices are equal?

Two matrices are said to be equal if: Both the matrices are of the same order i.e., they have the same number of rows and columns A m × n = B m × n .

Answer: -0.3

Step-by-step explanation:

(a) To calculate the area surrounding the swimming pool, we need to consider the width of the cement around all sides of the pool. Since the cement has a uniform width of 4m on all sides, we need to add 4m to the length and width of the pool.

The length of the pool with the surrounding cement is 10m + 2(4m) = 10m + 8m = 18m.

The width of the pool with the surrounding cement is 5m + 2(4m) = 5m + 8m = 13m.

The area surrounding the swimming pool is the difference between the area of the larger rectangle (with the cement) and the area of the pool itself.

Area surrounding pool = Area of larger rectangle - Area of pool

= (18m) x (13m) - (10m) x (5m)

= 234m² - 50m²

= 184m².

(b) The cost to install the cement is determined by multiplying the area surrounding the pool by the cost per square meter, which is $50.

Cost to install cement = Area surrounding pool × Cost per square meter

= 184m² × $50/m²

= $9,200.

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Neither of the triangles are similar to triangle ABC.

Similar triangles are triangles that share these two features listed as follows:

For this problem, we have that for neither triangle, the side lengths for a proportional relationship with the side lengths of triangle ABC, hence neither of the triangles are similar to triangle ABC.

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The product of 76 and 6.0 × 10² is 45,600, and when expressed in scientific notation, it is 4.56 × 10⁴.

To find the product of 76 and 6.0 × 10², we need to multiply these two numbers together. First, let's rewrite 6.0 × 10² in decimal form. In scientific notation, the number 6.0 × 10² means 6.0 multiplied by 10 raised to the power of 2.

10 raised to the power of 2 means multiplying 10 by itself twice: 10 × 10 = 100. Therefore, 6.0 × 10² can be rewritten as 6.0 × 100.

Now, we can find the product by multiplying 76 and 6.0 × 100:

76 × 6.0 × 100 = 456 × 100

To multiply 456 by 100, we move each digit of 456 two places to the left, which is equivalent to multiplying by 100. This gives us:

456 × 100 = 45,600

So, the product of 76 and 6.0 × 10² is 45,600.

In our case, the product is 45,600. To express this in scientific notation, we need to move the decimal point to the left until there is only one non-zero digit to the left of the decimal point. In this case, we move the decimal point four places to the left:

45,600 = 4.56 × 10⁴

Therefore, the product of 76 and 6.0 × 10² expressed in scientific notation is 4.56 × 10⁴.

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The solution of the differential equation t ln (t) dr/dt + r = 3te^t is  r = (3/t) - 3e^(-t)/ln(t) + C/ln(t)

To solve the given differential equation:

t ln(t) dr/dt + r = 3te^t             ...... (1)

Divide the equation (1) by t ln(t) then equation (1) chages to:

dr/dt + (1/t ln(t))r = 3e^t/t ln(t)

The given equation is a reducible linear differential equation to reduce in linear form we multiply by the integrating factor.

The integrating factor is given by:

μ(t) = e^∫(1/t ln(t))dt

= e^ln(ln(t))

= ln(t)

Thus,

ln(t) dr/dt + r ln(t) = 3te^t

d/dt (r ln(t)) = ln(t) dr/dt + r/t

Substituting this into the equation, we get:

d/dt (r ln(t)) = 3te^t/t

Integrate both sides;

r ln(t) = 3e^t ln(t) - 3e^t + C

r = (3/t) - 3e^(-t)/ln(t) + C/ln(t)

r = (3/t) - 3e^(-t)/ln(t) + C/ln(t)

hence, the solution of the differential equation is r = (3/t) - 3e^(-t)/ln(t) + C/ln(t), where C is a arbitrary constant.

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A. compare the spread, central tendency, and potential outliers across the three groups.

B. There is a significant difference in the number of trees between the three groups of forest plots.

C. we would need the output of the ANOVA and the corresponding data from the study.

D. we cannot provide a conclusion without ANOVA test statistics, p-values ​​and other data analysis.

What is Tropical Rainforest?

A tropical rainforest is a lush and biologically diverse ecosystem found in tropical regions of the world. It is characterized by abundant rainfall throughout the year, high humidity and a dense canopy of tall trees that form a continuous leaf cover. These forests are incredibly diverse and home to a wide variety of plant and animal species.

A. Looking at the dotted areas, we can observe the distribution of the number of trees in the forest plots for each group. We can visually compare the spread, central tendency, and potential outliers across the three groups.

b. Null hypothesis: There is no significant difference in the number of trees between the three groups of forest plots (group 1, group 2 and group 3).

Alternative hypothesis: There is a significant difference in the number of trees between the three groups of forest plots.

C. To provide the test statistic and p-value, we would need the output of the ANOVA and the corresponding data from the study.

d. Based on the information provided, we cannot provide a conclusion without ANOVA test statistics, p-values ​​and other data analysis.

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a. Approximately, the farmer needs to order 25.13 gallons of paint to paint the exterior of the granary.

b. Approximately, the maximum amount of grain the structure can store is 2198.17π cubic meters.

a. To calculate the surface area of the exterior of the granary, we need to find the lateral surface area of the cylinder. The formula for the lateral surface area of a cylinder is given by:

Lateral Surface Area = 2πrh

where r is the radius of the base of the cylinder and h is the height of the cylinder.

Given that the diameter of the granary is 10 meters, we can find the radius by dividing the diameter by 2:

Radius (r) = Diameter / 2 = 10m / 2 = 5m

Plugging in the values into the formula, we get:

Lateral Surface Area = 2π(5m)(28m) = 280π [tex]m^2[/tex]

Now, we can calculate the number of gallons of paint needed by dividing the surface area by the coverage of one gallon of paint:

Number of gallons of paint = Lateral Surface Area / Coverage per gallon

Number of gallons of paint = 280π [tex]m^2[/tex] / 35 [tex]m^2[/tex] = 8π gallons

Approximately, the farmer needs to order 25.13 gallons of paint to paint the exterior of the granary.

b. To determine the maximum amount of grain the structure can store, we need to calculate the volume of the cylinder. The formula for the volume of a cylinder is given by:

Volume = π[tex]r^2[/tex]h

where r is the radius of the base of the cylinder and h is the height of the cylinder.

Given that the diameter of the granary is 10 meters, we can find the radius by dividing the diameter by 2:

Radius (r) = Diameter / 2 = 10m / 2 = 5m

Plugging in the values into the formula, we get:

Volume = π(5m[tex])^2[/tex](28m) = 700π [tex]m^3[/tex]

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The monomial expressions which best estimates the behavior of the function f(x) = (x - 6)/([tex]x^2[/tex] + 2x + 14) are '1/x' and '1' and the required ratio is 1/x.

The behavior of a rational function as x approaches positive or negative infinity can be estimated by analyzing the highest power terms in the numerator and denominator.

For the function f(x) = (x - 6)/([tex]x^2[/tex] + 2x + 14), as x approaches infinity, the dominant term in the numerator is x, and in the denominator, the dominant term is [tex]x^2[/tex].

Therefore, the behavior of the function can be estimated by the monomial expression [tex]x[/tex]/[tex]x^2[/tex], which simplifies to 1/x.

For the denominator [tex]x^2[/tex] + 2x + 14, as x approaches infinity, the dominant term is [tex]x^2[/tex].

Therefore, the behavior of the denominator can be estimated by the monomial expression [tex]x^2/x^2[/tex], which simplifies to 1.

Using the results from parts (a) and (b), the ratio of the monomial expressions that best estimates the behavior of (x - 6)/([tex]x^2[/tex] + 2x + 14) as x approaches infinity is (1/x)/(1), which simplifies to 1/x.

In summary, as x approaches infinity, the function f(x) = (x - 6)/([tex]x^2[/tex] + 2x + 14) behaves like 1/x, and the ratio of the dominant monomial terms in the numerator and denominator is 1/x.

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Given a nonempty set of real numbers S that is bounded above, and y as the least upper bound (lub) of S, we need to prove that for every positive real number epsilon, there exists a real number z in S such that z < y + epsilon.

To prove the statement, we'll assume the negation and show that it leads to a contradiction. So, let's assume that for some positive epsilon, there does not exist any real number z in S such that z < y + epsilon.

Since y is the least upper bound of S, it implies that for any positive epsilon, y + epsilon cannot be an upper bound for S. Otherwise, if y + epsilon is an upper bound, there should exist a value z in S such that z ≥ y + epsilon, which contradicts our assumption.

However, since S is bounded above, there must exist an upper bound for S. Let's consider y + epsilon/2. Since y + epsilon/2 is less than y + epsilon and y + epsilon is not an upper bound, there must exist a value z in S such that z < y + epsilon/2.

But this contradicts our assumption that there is no real number z in S such that z < y + epsilon. Thus, our assumption must be false, and the original statement is proven. For every positive epsilon, there exists a real number z in S such that z < y + epsilon.

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Answer:

Step-by-step explanation:

Thus, the  value of f(-2), using the general solution to the differential equation is f(-2) = y = ln(ln|(-e+1)/(e^2)|).

To find the value of f(-2), we first need to find the general solution to the differential equation dy/dx=(ex−1/ey). We can rewrite this equation as dy/dx=(e^x/e^y)-1/e^y.

Let u=e^y, then du/dx=e^y dy/dx. Substituting this into the differential equation, we get:
du/dx = e^x - 1/u

This is a separable differential equation, which we can solve as follows:
du/(e^x-1/u) = dx
u - ln|e^x-1| = x + C
e^y - ln|e^x-1| = x + C
e^y = ln|e^x-1| + C

Applying the initial condition f(1) = 0, we get:
e^0 = ln|e^1-1| + C
1 = ln|e-1| + C
C = 1 - ln|e-1|

So the particular solution is:
e^y = ln|e^x-1| + 1 - ln|e-1|
e^y = ln|e^x-1| + ln|e/(e-1)|
e^y = ln|e(e^x-1)/(e-1)|

Now we can find the value of f(-2) by plugging in x=-2:
e^y = ln|e(e^-2-1)/(e-1)|
e^y = ln|e(-1/e^2-1)/(e-1)|
e^y = ln|(-e+1)/(e^2)|

Taking the natural logarithm of both sides, we get:
y = ln(ln|(-e+1)/(e^2)|)

Therefore, the value of f(-2) is:
f(-2) = y = ln(ln|(-e+1)/(e^2)|)

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[tex]5.96 \times 10^{-3}[/tex] is 1000 times greater than [tex]5.96 \times 10^{-6}[/tex].

Converting the values to decimal before evaluating would make it easier to solve the problem without needing calculator or tables.

Numerator : [tex]5.96 \times 10^{-3}[/tex] = 5.96 × 0.001 = 0.00596

Denominator: [tex]5.96 \times 10^{-6}[/tex] = 5.96 × 0.000001 = 0.00000596

Dividing the Numerator by the denominator, we have the expression ;

0.00596/0.00000596 = 1000

This means that [tex]5.96 \times 10^{-3}[/tex] is 1000 times greater than [tex]5.96 \times 10^{-6}[/tex]

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The required answer is  the function f: [0, +∞) → [0, +∞) given by {(x, y): y = x^2} becomes bijective.

To make the function f: R → R given by {(x, y): y = x^2} bijective, we need to restrict the domain and codomain so that the function is both injective (one-to-one) and surjective (onto).

Step 1: Restrict the domain to make the function injective.
The function is not injective in its current form because for some distinct x values, the y values are equal (for example, x = 1 and x = -1 both give y = 1). To make it injective, we can restrict the domain to either non-negative real numbers (x ≥ 0) or non-positive real numbers (x ≤ 0).

Step 2: Restrict the codomain to make the function surjective.
In its current form, the function is not surjective because there are y values in the co-domain with no corresponding x values (for example, y = -1 has no x value that satisfies y = x^2). To make it surjective, we can restrict the co-domain to non-negative real numbers (y ≥ 0).
So,

if we restrict the domain to non-negative real numbers (x ≥ 0) and the co-domain to non-negative real numbers (y ≥ 0),

the function f: [0, +∞) → [0, +∞) given by {(x, y): y = x^2} becomes bijective.

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The length of the path described by the parametric equations x = cos(3t) and y = sin(3t) for 0 ≤ t ≤ π/2 is 3(π/2).

To find the length of the path, we need to use the formula for arc length:

L = integral from a to b of √(dx/dt)² + (dy/dt)² dt

where a and b are the starting and ending values of t.

Here, we have x = cos(3t) and y = sin(3t). Therefore,

dx/dt = -3sin(3t) and dy/dt = 3cos(3t)

Now, we can substitute these into the formula for arc length:

L = integral from 0 to π/2 of √((-3sin(3t))² + (3cos(3t))²) dt

L = integral from 0 to π/2 of √(9sin²(3t) + 9cos²(3t)) dt

L = integral from 0 to pi/2 of 3 dt

L = [tex]3[t]_0^{(\pi/2)[/tex] = 3(pi/2)

The length of the path described by the parametric equations x = cos(3t) and y = sin(3t) for 0 ≤ t ≤ π/2 is 3(π/2).

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The length of the path described by the parametric equations x = cos(3t) and y = sin(3t), for 0 ≤ t ≤ π/2, is given by the integral of the square root of the sum of the squares of the derivatives of x and y with respect to t.

Using the Pythagorean identity sin²θ + cos²θ = 1, we can simplify the length integral as follows:

L = ∫[0,π/2] √((dx/dt)² + (dy/dt)²) dt

L = ∫[0,π/2] √((-3sin(3t))² + (3cos(3t))²) dt

L = ∫[0,π/2] √(9sin²(3t) + 9cos²(3t)) dt

L = ∫[0,π/2] √9(dt)

L = 3 ∫[0,π/2] dt

L = 3[t] [0,π/2]

L = 3(π/2 - 0)

L = 3π/2

Therefore, the length of the path described by the given parametric equations for 0 ≤ t ≤ π/2 is 3π/2 units.

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Complete Question

the length of the path described by the parametric equations x=cos3t and y=sin3t , for 0≤t≤π2 is given by                   .

the probability that exactly 15 Shopper will enter the mall between noon and 12:05 p.m. is approximately 0.0498, or 4.98% (rounded to four decimal places).

TheThe The problem describes a Poisson process, where shoppers enter a mall at an average rate of 360 per hour. We can use the Poisson distribution to find the probability of a specific number of shoppers arriving in a given time period.

Let X be the number of shoppers who enter the mall between noon and 12:05 p.m. Then, X follows a Poisson distribution with parameter λ = 360/12 × 0.0833 = 30 (since there are 12 five-minute intervals in an hour, and 0.0833 hours in 5 minutes).

To find the probability that exactly 15 shoppers enter the mall in this time period, we use the Poisson probability mass function:

P(X = 15) = e^(-30) * 30^15 / 15! ≈ 0.0498

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The line in the table is y = 2x - 6, the correct option is the third one.

The general linear equation can be written as:

y = ax + b

Where a is the slope and b is the y-intercept.

If a line passes through two points (x₁, y₁) and (x₂, y₂), then the slope is:

a = (y₂ - y₁)/(x₂ - x₁)

Here we can use the last two points (4, 2) and (9, 12), then the slope is:

a = (12 - 2)/(9 - 4) = 2

Then the line is:

y = 2x + b

To find the value of b, we can replace the point (4, 2), then we will get:

2 = 2*4 + b

2 = 8 + b

2 - 8 = b

-6 = b

The line is y = 2x - 6

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Answer:3

Step-by-step explanation:

length times width times height

Answer:

30

Step-by-step explanation:

length times width times height

5 times 3 times 2

15 by 2 is 30

Answer:

height = 4 feet

Step-by-step explanation:

A storage bin is usually in the shape of a rectangular box and the formula for volume of a rectangular box is:

V = lwh, where

Since we know that the student wants the volume of the storage bin to be 168 ft^3 and has already found that the length and width are 7 and 6 ft respectively, we can plug in 168 for V, 7 for l, and 6 for w, allowing us to solve for h, the height of the storage bun:

168 = 7 * 6 * h

168 = 42h

4 = h

Thus, the height of the storage bin must be 4 feet tall, in order for its volume to be 168 ft^3, given that the length is 7 ft and the width is 6 ft.