When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 56.11 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question.

Answers

Answer 1

Answer: The empirical formula is [tex]CH_2[/tex] and molecular formula is [tex]C_4H_8[/tex]

Explanation:

We are given:

Mass of [tex]CO_2[/tex] = 18.95 g

Mass of [tex]H_2O[/tex]= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =[tex]\frac{12}{44}\times 18.59=5.07g[/tex] of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =[tex]\frac{2}{18}\times 7.759=0.862g[/tex] of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles[/tex]

Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =[tex]\frac{0.422}{0.422}=1[/tex]

For H =[tex]\frac{0.862}{0.422}=2[/tex]

The ratio of C : H = 1: 2

Hence the empirical formula is [tex]CH_2[/tex].

The empirical weight of [tex]CH_2[/tex] = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4[/tex]

The molecular formula will be=[tex]4\times CH_2=C_4H_8[/tex]


Related Questions

What type of reaction is P4 + 3O2 = 2P2O3

Answers

Answer:

synthesis

Explanation:

hope this helps

The given reaction is a type of synthesis reaction.  

• The reactions, which takes place when two distinct molecules or atoms associate to produce a distinct molecule or compound is known as synthesis reactions.  

• The synthesis reactions are one of the prime categories of chemical reactions that comprise combustion reactions, single displacement, and double displacement reactions.  

• In synthesis reactions, energy is released and the reaction is exothermic, in some cases, endothermic is also possible.  

• In the given reaction atoms of phosphorus and oxygen combines to produce the compound phosphorus oxide.

Thus, the given case is an example of synthesis reaction.

To know more about:

https://brainly.com/question/14401557

Which of the following provides evidence for past tectonic plate motions?
A. Matching rock type and rock formations can show the way the continents were once attached.
B.Glacial evidence has been found in areas where glaciers could not exist if the continents were in their current location.
C.Ancient life forms preserved as fossils can tell us what organisms existed and where they were. Matching the fossils can show that land masses were once connected.
D. All of the above.

Answers

Answer:

D

Explanation:

If there are 2 of the same rocks on two continents, that shows that they were once merged. If there is glacial existence in places where glaciers would’ve melted (Like Africa has glacial existence from Antarctica ) this shows that continents were once merged. If life forms preserved as fossils were matched on 2 different continents this shows that all the continents were once merged.

Answer:

so i am doing this and i need help what did u get for number 1

Explanation:

its the first question

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has determined by measurements that there are moles of oxygen in a sample of acetic acid. How many moles of hydrogen are in the sample

Answers

Answer:

0.11 mol

Explanation:

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of oxygen in a sample of acetic acid. How many moles of hydrogen are in the sample?

Step 1: Given data

Formula of acetic acid: CH₃CO₂HMoles of oxygen in the sample of acetic acid: 0.054 moles

Step 2: Establish the appropriate molar ratio

According to the chemical formula of acetic acid, the molar ratio of H to O is 4:2.

Step 3: Calculate the moles of atoms of hydrogen

We will use the theoretical molar ratio for acetic acid.

0.054 mol O × (4 mol H/2 mol O) = 0.11 mol H

calculate the mass percent of water in CaCrO4.H2O

Answers

Answer:

10.35%

Explanation:

Find the molar mass of water, using your periodic table: 18.02 g. Then find the molar mass of the total substance: 174.10 g.

Divide the molar mass of water by the molar mass of the total substance and multiply 100%. Doing this, you get 10.35%.

solve the equation:
1) 3,2 m²= x dm²= x cm²

BRAINLIEST!!!!

Answers

I take sleeper bye lol

Answer:

sin  = (330)

csc = (60)

−4 = cot (−45)

Explanation:

im not sure what you were looking for, make me brainlest please?

help me plzz in chemistry​

Answers

a) f2 loses electrons and is oxidised. li gains electrons and is reduced

c)sn2+ loses electrons and is oxidised.Al gains electrons and is reduced

b)br2 loses electrons and is oxidised. I- in KI gains electrons and is reduced

How much of a sample remains after five half-Iives have occurred?
1/5 of the original sarmple
1/25 of the original sarmple
1/32 of the original sample
1/64 of the original sample

Answers

Answer:

1/32 of the original sample

Explanation:

edgunity got it.

MCQ
A sample of tungsten occupies a volume of 1.6 cm3. How many atoms of
tungsten in the sample? (For tungsten, density = 19.35 g/cm3)
O 61.92
O 0.337
2.03X10^23
O 1.014X1023
5.07X10^22
O 2.54X10-22​

Answers

Answer:

1.014×10²³ atoms

Explanation:

Given data:

Volume of tungsten = 1.6 cm³

Density of tungsten = 19.35 g/cm³

Number of atoms of tungsten = ?

Solution:

First of all we will calculate the mass of tungsten.

density = mass/volume

by putting values,

19.35 g/cm³ = mass/1.6 cm³

Mass = 19.35 g/cm³× 1.6 cm³

Mass = 30.96 g

Number of moles of tungsten:

Number of moles = mass/molar mass

Number of moles = 30.96 g/ 183.84 g/mol

Number of moles = 0.1684 mol

1  mole contain 6.022×10²³ atoms.

0.1684 mol × 6.022×10²³ atoms / 1mol

1.014×10²³ atoms

True or False: Radon is a solid at – 100 °C.

Answers

the correct answer would be true
That would be true statement

1) When 2.38g of magnesium is added to 25.0cm of 2.27 M hydrochloric acid, hydrogen gas is released.
a) Determine the limiting reactant
b) Calculate the mass of hydrogen gas produced.
c) Calculate the mass of excess reactant remained at the end of reaction.
d) What is the percentage yield if 0.044g of hydrogen gas is obtained from the experiment?​

Answers

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

[tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

[tex]n_{H_2}^{by\ HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl} =0.0284molH_2\\\\n_{H_2}^{by\ Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2[/tex]

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

[tex]m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2[/tex]

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

[tex]m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg} =0.690gMg[/tex]

Thus, the mass of excess magnesium turns out:

[tex]m_{Mg}^{excess}=2.38g-0.690g=1.69gMg[/tex]

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

[tex]Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%[/tex]

Best regards!

a) The limiting reactant would be HCl

From the equation of the reaction:

[tex]Mg (s) + 2 HCl (aq) ---> MgCl_2 (aq) + H_2 (g)[/tex]

The mole ratio of Mg to HCl is 1:2.

Mole = mass/molar mass = molarity x volume

Mole of Mg = 2.38/24.3

                     = 0.098 moles

Mole of HCl = 2.27 x 25/1000        

                     = 0.057 moles

Thus, HCl is limiting while Mg is in excess.

b) Since the mole ratio of HCl to H2 is 2:1:

Mole of H2 produced = 0.057/2

                                    = 0.028 moles

Mass of H2 produced = mole x molar mass

                                    = 0.028 x 2

                                     = 0.057 g

c) Actual mole of Mg that should react = 0.057/2

                                                                    = 0.028 moles

Excess mole of Mg = 0.098 - 0.028

                                   = 0.07

Mass of excess Mg = 0.07 x 24.3

                                 = 1.701 g

d) Percentage yield if 0.044 g of hydrogen is obtained = yield/theoretical x 100

                     = 0.044/0.057 x 100

                       = 77.19%

The mass of magnesium ions in 1 kg of sea water is 1.3 g.
The concentration in parts per million (ppm) is
a 1.3x10^6
b 1.3x10^3
c 1.3x10^-3

I dont understand how to do this question. Help would be much appreciated!

Answers

Answer:

1300 ppm

Explanation:

for ppm, calculate fractional ration =(part/total) and multiply by 1 x 10⁶ => ppm

for ppb, calculate fractional ration =(part/total) and multiply by 1 x 10⁹ => ppb

Parts Per Million (ppm)

Given 1.36g in 1Kg (=1000g) => fractional ratio = (1.3g/1000g)(10⁶) = 1300 ppm

Parts Per Billion (ppb)

or if ppb is needed do the same calculation but multiply by 10⁹ ... That is,

Given 1.36g in 1Kg (=1000g) => fractional ratio = (1.3/1000g)(10⁹) = 1300000 ppb = 1.3 x 10⁶ ppb

Parts per Hundred (pph) is the same as percent (%) ... Calculate fractional ratio and then multiply by 100%

Given 1.36g in 1Kg (=1000g) => fractional ratio = (1.3g/1000g)(100%) = 0.13%

help I. have until 11:59 to hand it in ​

Answers

This chemical reaction can also be written as

2C2H6+7O2-->4CO2+6H2O

This is a chemical reaction because reactants are converted into products. This is the combustion of ethane where ethane and oxygen have been converted into carbon dioxide and water

For the chemical reaction:
N2 (g)
+
H2(g)=
NH3 (g)
Calculate the volume of NH; that will form from 200 dm cubed of N2 at STP. (N = 14; H - 1)
[At STP. 1 mole of any gas occupies volume of 22 A dm cubed​

Answers

Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

Given data:

Volume of N₂ = 200 dm³

Pressure and temperature = standard

Volume of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂     →      2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

n = 8.9 mol

Now we will compare the moles of ammonia and nitrogen.

               N₂          :         NH₃

                1            :           2

              8.9          :        2/1×8.9 = 17.8 mol

Volume of ammonia:

1 mole of any gas occupy 22.4 dm³ volume

17.8 mol ×22.4 dm³/1 mol = 398.7 dm³

How many liters of carbon dioxide are formed from the complete decomposition of 50.0 g of iron (III) carbonate at STP?

Answers

Answer:

V = 1.57 L

Explanation:

Given data:

Mass of iron(III) carbonate = 50.0 g

Volume of CO₂ formed = ?

Temperature = standard = 273 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

Fe₂(CO₃)₃     → Fe₂O₃ + 3CO₂

Number of moles of Fe₂(CO₃)₃ :

Number of moles = mass/molar mass

Number of moles = 50.0 g /235.8 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of Fe₂(CO₃)₃  and CO₂.

                          Fe₂(CO₃)₃         :             CO₂

                              1                    :               3

                            0.21                :            1/3×0.21 = 0.07 mol

Volume of CO₂:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm × V =0.07 mol × 0.0821 atm.L/mol.K × 273 K

V = 1.57 atm.L / 1 atm

V = 1.57 L

what are the functional groups in tramadol

Answers

Answer:

1. ether group R-O-R

2. benzene ring

3. 3°- alcohol

4.3°- amine group N attached to 3 groups rather than H

Complete Table G to view the effect of surface area on the rate of reaction by transferring your data from Tables D and E to Table G.

Which form of the sodium bicarbonate tablet dissolves the fastest?

Answers

Answer:

The crushed tablet dissolves fastest among the three forms.

Explanation:

The experiment is aimed at determining the effect of surface area of reactants on reaction rate.

Sodium bicarbonate tablets are provided and divided into three groups of consisting of three trials each. The temperature of the water is kept constant at 20°C. The first group consists of three tablets of sodium bicarbonate dissolved in individual trials in water. The second group consists of three quarter tablets of sodium bicarbonate dissolved in individual trials in water. The third group consists of three crushed tablets of sodium bicarbonate dissolved in individual trials in water.

The results shows that the average time for the dissolution of the first group is 51 seconds; the second group is 42 seconds while the third group is 17 seconds.

Therefore, it can be concluded that increasing the surface area of reactants increases the rate of reaction. This is because more reactant molecules are exposed for dissolution by water with increase in surface area.

Answer:

cold water

Explanation:

What is the mass in grams of 12.9 moles of water, H2O?

Answers

Answer:

232 g.

Explanation:

12.9 mol x 18.106g = 232 g H₂O

An unknown organic compound composed of carbon, hydrogen, and oxygen was analyzed and found to be 50.84% C, 8.53% H, and the rest oxygen. What is the empirical formula

Answers

In every 100g of that compund there is 50.84 g of C, 8.53 g H and (100-59.37) g = 40.63 g of O.

Step 1: Convert each element's mass in moles. To do that we need to divide each element's mass by their respective molar mass.

For Carbon.

[tex]C = \frac{50.84}{12} = 4.24 mol [/tex]

For Hydrogen.

[tex]H = \frac{8.53}{1} = 8.53 mol [/tex]

For Oxygen.

[tex]O = \frac{40.63}{16} = 2.54 mol [/tex]

Step 2: Divide each of the numbers by the smallest number.

For Carbon.

[tex]C = \frac{4.24}{2.54} = 1.7 [/tex]

For Hydrogen.

[tex]H = \frac{8.53}{2.54} = 3.36 [/tex]

For Oxygen.

[tex]O = \frac{2.54}{2.54} = 1 [/tex]

Step 3: So the empirical formula will be.

[tex] C_{1.7} H_{3.36} O_1 [/tex]

But using decimal will be messy. So we multiply the numbers by 3. The right empirical formula will be.

[tex] C_{5} H_{10} O_3 [/tex]

The empirical formula of an organic compound that contains 50.84% C, 8.53% H, and the rest oxygen is C₅H₁₀O₃.

First, we have to determine the mass percentage of oxygen, knowing that C, H and O amount to the 100% of the compound.

[tex]C + H + O = 100\%\\O = 100\% - C - H\\O = 100\% - 50.84\% - 8.53\% = 40.63\%[/tex]

Then, we divide each mass percentage by the atomic mass of the element.

[tex]C: 50.84/12.01 = 4.23\\H: 8.53/1.01 = 8.45\\O: 40.63/16.00 = 2.54[/tex]

Afterwards, we divide all the numbers by the smallest one, i.e. 2.54.

[tex]C: 4.23/2.54 = 1.66\\H: 8.45/2.54 = 3.33\\O: 2.54/2.54 = 1[/tex]

Finally, we multiply all the numbers by 3, so that they are all integers.

[tex]C: 1.66 \times 3 \approx 5\\H: 3.33 \times 3 \approx 10\\O: 1 \times 3 = 3[/tex]

The empirical formula of the organic compound is C₅H₁₀O₃.

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jagsir saw his mother adding dried neem leaves to the metal vessel filled with wheat. jagsir asked the reason for this from his mother. what would be his mothers reply? ​

Answers

Answer:

Because i want to. would be the reply

Explanation:

VOTE ME BRAINLIEST PLSSSSSSSSS

Answer:

none of the above

option d

PLEASEEEEEEEEEEEE HELP 100 POINTS PLEASEEEE Sofia has two 10-gram samples of sea salt. One sample is finely ground into thousands of tiny grains of salt. The other sample is a single block of salt crystals. Sofia tries to dissolve each sample in a separate glass of water. Which sample will dissolve first?
A.the finely ground sample because it has more surface area
B.the single block because it has more surface area
C.the single block because it has less surface area
D.the finely ground sample because it has less surface area

Answers

Answer:

the answer is D to this question

The capability of a gaseous, solid or liquid component to dissolve in the solvent to yield a solution is called solubility. Solubility depends on the exterior area of the substance.

The correct answer is:

Option A. The finely ground sample because it has more surface area.

This can be explained as:

The rate of desolvation of the solute is dependent on the surface area of the solute.

The grounded particle of a substance dissolves faster as compared to the large particles.

The solubility of solute depends on the surface area. The large surface area of compounds increases the contact rate of solute with the solvent.

Therefore, the finely ground sample will dissolve fast.

To learn more about solubility and surface area follow the link:

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A rigid, 28-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pressure inside the cooker reaches 150 kPa. Initially, this cooker is filled with water at 175 kPa with a quality of 10 percent. Heat is now added until the quality inside the cooker is 40 percent. The water is stirred at the same time that it is being heated. Determine the minimum entropy change of the heat-supplying source if 100 kJ of work is done on the water as it is being heated. Use steam tables.

Answers

Answer:

[tex]\Delta S_{source}>-1.204\frac{kJ}{K}[/tex]

Explanation:

Hello!

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy:

[tex]s_1=s_{f,175kPa}+q*s_{fg,175kPa}\\\\s_1=1.4850\frac{kJ}{kg*K} +0.1*5.6865\frac{kJ}{kg*K}=2.0537\frac{kJ}{kg*K}[/tex]

Now the entropy at the final state given the new 40-% quality:

[tex]s_2=s_{f,150kPa}+q*s_{fg,150kPa}\\\\s_2=1.4337\frac{kJ}{kg*K} +0.4*5.7894\frac{kJ}{kg*K}=3.7495\frac{kJ}{kg*K}[/tex]

Next step is to compute the mass of steam given the specific volume of steam at 175 kPa and the 10% quality:

[tex]m_1=\frac{0.028m^3}{(0.001057+0.1*1.002643)\frac{m^3}{kg} } =0.274kg\\\\m_2=\frac{0.028m^3}{(0.001053+0.4*1.158347)\frac{m^3}{kg} } =0.0603kg[/tex]

Then, we can write the entropy balance:

[tex]\Delta S_{source}+\frac{Q}{T_1} -\frac{Q}{T_2} +s_2m_2-s_1m_1-s_{fg}(m_2-m_1)>0[/tex]

Whereas sfg stands for the entropy of the leaving steam to hold the pressure at 150 kPa and must be greater than 0; thus we plug in:

Which is such minimum entropy change of the heat-supplying source.

Best regards!

Which of the following equations demonstrates an actual chemical reaction that forms a new substance?

A1: ZN + 2HCl → 2NCl2 + H2

A2: H2O + NaCl → H2O

A3: Zn + Al + Cu → Zn + Cu + Al

A4: C12H22O11 + H2O → H2O + C12H22O11

Answers

Answer:  [tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex]

Explanation:

A chemical reaction is said to have occured when reactants react to form new products where the atoms undergo a change in bonding.

From the given reactions:

1. [tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex]

Here Zn combines with hydrochloric acid to form zinc chloride and hydrogen.

2. [tex]H_2O+NaCl\rightarrow H_2O[/tex]

Here water remains as such as no new substance is formed.

3. [tex]Zn+Al+Cu\rightarrow Zn+Cu+Al[/tex]

Here no new substance is formed.

4. [tex]C_{12}H_{22}O_{11}+H_2O\rightarrow H_2O+C_{12}H_{22}O_{11}[/tex]

Here no new substance is formed.

Thus [tex]Zn+2HCl\rightarrow ZnCl_2+H_2[/tex] demonstrates an actual chemical reaction that forms a new substance

Answer:

hope this helps you!

Explanation:

Which of the following is a landscape feature caused by deposition

Answers

Explanation:

Depositional landforms are the visible evidence of processes that have deposited sediments or rocks after they were transported by flowing ice or water, wind or gravity. Examples include beaches, deltas, glacial moraines, sand dunes and salt domes.

hope it helps!

Look at picture and answer will mark brainliest.

Answers

Answer:

A

Explanation:

What do you think is responsible for the color produced in the flame, the metal atom or what is attached to the metal atom?
Hint: The metal atom comes first in the formula and the name of the compound.

Answers

Answer:

metal Atom

Explanation:

every transition metal atom are responsible for the flame color. Some metal are also confirmed by flame test.

What is the role of an R group in an amino acid?
A.) It represents the core group that is common to all amino acids.
B.) It gives all amino acids the same physical and chemical properties.
C.) It is the functional group that distinguishes one amino acid from another.
D.) It is the site where other amino acids bond to form polypeptide chains.

Answers

Answer:

C.) It is the functional group that distinguishes one amino acid from another.

Explanation:

An R group is also known as a random group and is one of the key components of an amino acid. It contributes to their wide variety.

The role of an R group in an amino acid as It is the functional group that distinguishes one amino acid from another. Option C is correct.

What are functional groups?

The functional groups are the some groups of chemicals oh hydrogen and notrgen and oxygen or carbon combination like carboxylic acid they are combination of carbon and amines as they are amnio groups etc.

The R attached at the end represents the different functional gropus of amino acids in the chain of hydrocarbon compound or orgamic compounds as they are primay and secondry and tertiary amines.

Therefore, Option C is correct.The role of an R group in an amino acid as It is the functional group that distinguishes one amino acid from another.

Learn more about functional groups, here:

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Determine the oxidation number of chlorine in CI2 with the steps

Answers

Answer:  The oxidation number of chlorine in [tex]Cl_2[/tex] is zero

Explanation:

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Rules for Oxidation Numbers are :

1.  The oxidation number of a free element is always zero.

2. The oxidation number of a monatomic ion equals the charge of the ion.

3. The oxidation number of  oxygen (O)  in compounds is usually -2.

4. The oxidation number of a Group 17 element in a binary compound is -1.

5. The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

6. The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

7. The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

As [tex]Cl_2[/tex] exists as a free molecule, its oxidation state is zero.

What is the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.3, and the temperature is 37.0 °C? ?G°\' for the reaction is –16.7 kJ/mol.

Answers

The free energy change(Gibbs free energy-ΔG)=-8.698 kJ/mol

Further explanation

Given

Ratio of the concentrations of the products to the concentrations of the reactants is 22.3

Temperature = 37 C = 310 K

ΔG°=-16.7 kJ/mol

Required

the free energy change

Solution

Ratio of the concentration : equilbrium constant = K = 22.3

We can use Gibbs free energy :

ΔG = ΔG°+ RT ln K

R=8.314 .10⁻³ kJ/mol K

[tex]\tt \Delta G=-16.7~kJ/mol+8.314.10^{-3}\times 310\times ln~22.3\\\\\Delta G=-8.698~kJ/mol[/tex]

What do asteroids have in common with earth?

Answers

they rotate around the central axis

QUESTION TWO
(a) Derive Nernst equation for measuring the EMF of the cell
(b) Calculate the emf of the cell
[3]
Zn Zn? (0.001M)|| Agt (0.1M)| Ag
The standard potential of Ag/Ag half-cell is +0.80 V and Zn/Zn. is -0.76 V
(c) Name different types of standard electrodes used for the determination of pH
of a solution by EMF measurement Discuss the working of Glass Electrode
for the determination of pH of a solution
(d) 0.1978 g of copper is deposited by a current of 0.2 ampere in 50 minutes.
What is the electrochemical equivalent of copper?
[3]​

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