Answer:
The focal length is [tex]f = -0.2 \ m[/tex]
The radius of curvature is [tex]R = -0.4 \ m[/tex]
Explanation:
From the question we are told that
The magnification of the mirror is [tex]m = \frac{1}{2}[/tex]
The distance of the person from the mirror(the object distance ) is [tex]u = - 1.0 \ m[/tex]
The negative sign shows that it is been placed in front of the mirror
Generally the magnification of the mirror is mathematically represented as
[tex]m = \frac{v}{u}[/tex]
=> [tex]\frac{1}{4} = \frac{v}{-u}[/tex]
=> [tex]v = \frac{- 1}{4}[/tex]
Generally from the lens equation we have that
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{v}[/tex]
=> [tex]\frac{1}{f} = \frac{1}{-1 } + \frac{1}{-\frac{1}{4} }[/tex]
=> [tex]f = -0.2 \ m[/tex]
Generally the radius of curvature is mathematically represented as
[tex]R = 2 * f[/tex]
=> [tex]R = 2 * - 0.2[/tex]
=> [tex]R = -0.4 \ m[/tex]
a wandering dog walks 1 km due east, 1 km due south, then runs 2 km due west. the magnitude of the dogs displacement is closest to
a. 0 km
b. 1.4 km
c. 3.4 km
d. 4.0 km
Answer:
b) 1.4km
Explanation:
help
Which of the following is an Sl unit of measurement?
A. Liter
B. Gallon
C. Quart
D. Yard
a cyclist accelerates at a rate of 7.0 m/s2. how long will it take the cyclist to go from a velocity of 4 m/s to a velocity of 18 m/s?
Answer:
2.57 seconds (rounded to 2.6 Seconds)
Step-by-step explanation:
Great question, it is always good to ask away and get rid of any doubts that you may be having.
Before we can solve this question we need to create a formula that calculates the final speed. The formula will be the following,
Where:
Vf is the final Velocity
Vi is the initial velocity
A is the acceleration
t is the time in seconds
Now that we have the formula we can plug in the values given to us in the question and solve for the amount of time (t).
Finally, we can see that it would take the cyclist 2.57 seconds (approximately) to reach a speed of 18 m/s
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
suppose you drop an object and it strikes the ground. you can calculate the velocity of the object as it strikes the ground using the law of conservation of energy. in order to do this, you need to know the original height of the object. do you also need to know the mass of the object? why or why not?
a. you do not need to know the mass because you can compute it based on the provided information.
b. you do not need to know the mass because it cancels out.
c. you need to know the mass of the object in order to compute the kinetic and gravitational potential energies.
d. you need to know the mass of the object in order to compute the elastic potential energy.
Answer:
b)
Explanation:
Assuming no friction forces present, the total mechanical energy must be conserved, so at any moment, the sum of the gravitational potential energy and the kinetic energy must be the same.When the object is dropped, all the energy is gravitational, as follows:E = m*g*h (1)When the object strikes the ground, if we choose the ground as the zero reference level for the gravitational potential energy, all the energy is kinetic:E = 1/2*m*v² (2)Since E is constant, left sides in (1) and (2) are equal each other, so the right sides must be equal each other too.Since the mass is present in the right side of (1) and (2) it cancels out, so b) is the right answer.
Answer: B you do not need to know the mass because it cancels out
Explanation:
Help me please..
When the slope of a velocity vs. time graph is negative and constant,
what type of motion is occurring?
A) No motion
B) Constant speed
C) Acceleration
D) Constant Velocity
E) Going in circles
man with a mass of 70 kg balances on one foot while standing on a curb. The only significant forces on the foot (taken as a whole structure) are the ground pushing up at a point 15.0 cm in front of the ankle joint, the calf muscle pulling upward at the heel6.0 cm behind the ankle joint, and the tibia (shin bone) exerting a force at the ankle joint. Find the magnitudesof the forces exerted on the foot by the muscle and the tibia.
Answer:
a. 1715 N b. 2401 N
Explanation:
Let F = force due to calf muscle, F' = force due to tibia and N = force due to ground = weight of man = mg where m = mass of man = 70 kg and g = acceleration due to gravity = 9.8 m/s².
a. Magnitude of the forces exerted on the foot by the muscle
Since the force due to the calf muscle is 6.0 cm behind the ankle joint and the normal force due to the ground is 15.0 cm in front of the ankle joint and the force due to the tibia is at the ankle joint, taking moments about the ankle joint,
F × 6 cm + F' × 0 cm = N × 15 cm
6F = 15N = 15mg
F = 15mg/6
= 15 × 70 kg × 9.8 m/s²/6
= 1715 N
b. Magnitude of the forces exerted on the foot by the tibia
Taking moments about the calf muscle force, we have
F × 0 cm + F' × 6 cm = N × (15 cm + 6 cm)
6F' = 21N = 21mg
F' = 21mg/6
= 21 × 70 kg × 9.8 m/s²/6
= 2401 N
Suppose a uniform solid sphere of mass M and radius R rolls without slipping down an inclined plane starting from rest. The linear velocity of the sphere at the bottom of the incline depends on?
Answer:
None of the mass or the radius of the sphere
Explanation:
When a uniform solid sphere of any given mass, say M and any given radius, say R, rolls without slipping downwards an inclined plane that starts from rest. The linear velocity of the sphere at about the bottom of the inclined happens not to depend on either of its mass or that of the radius of its sphere.
A 2-kg body of mass is moving on a horizontal frictionless surface with a
velocity of 4 m/s. What is the net force required to keep the body moving with
the same velocity and direction for 5 s?
Answer:
Force=m×a. a(which is acceleration)=V/t
The amplitude of a pendulum is doubled. This means:
a
the pendulum will have twice its original mass.
b
the frequency of the pendulum will be twice as high.
c
the pendulum will swing twice as far away from the center.
d
the period of the pendulum will be twice as long.
Answer:
the period of the pendulum will be twice as long.
Explanation:
because i looked it up
What causes hot air to rise from the pavement on a hot summer day?
Answer:
radation because the heat gets too intense and is forced to rise
Through what angle in degrees does a 33 rpm record turn in 0.32 s?
63°
35°
46°
74°
Answer:
1 rev = 2(pi) rad pi(rad) = 180 degrees
so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees
Explanation:
63.36 estimated to 63 so 63
The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
Calculation of the angle:Since we know that1 rev = 2(pi) rad
So here pi(rad) = 180 degrees
Now for 33 rpm it should be like
= 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s
= 63.36 degrees
= 63 degrees
hence, The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
Learn more about an angle here: https://brainly.com/question/3394547
Drag each label to the correct location on the chart.
Sort the items based on whether they are simple machines or compound machines.
Answer:
whatttttttttttttttttttttttttttt are the items we have to classify into simple machines and compound machine
What is the Potential Energy of a roller coaster if it has a velocity of 35 m/s and a mass of 2000 kg and is at a height of 200 m? Please answer fast
A.) 137,200,000 J
B.) 12,005,000 J
C.) 3,920,000 J
D.) 1,400,000 J
Answer:
C
Explanation:
It cant be A or D, meaning your left with B and C. there cant be an answer in the 1000's place eather
Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster
Answer:
52.095 m/s
Motorcycle a was moving faster
Explanation:
We start by using one of the equations of motion
V = u + at
If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as
V(a) = u(a) + a(a).t
If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as
V(b) = u(b) + a(b).t
Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have
0 = u(a) - u(b) + a(a).t - a(b).t
-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have
u(b) - u(a) = [a(a) - a(b)]t
Since we have the values for acceleration and the time, we substitute so that
u(b) - u(a) = (4.55 - 18.9)3.63
u(b) - u(a) = -14.35 * 3.63
u(b) - u(a) = -52.095, or we rearrange to get
u(a) - u(b) = 52.095 m/s
True or False: As water evaporates, it removes a lot of heat with it.
Answer:
True, when it evaporates heat goes down, because it’s up the the sky.
Facts: In order for water to evaporate, hydrogen bonds must be broken. Water's heat of vaporization is 540 cal/g.
Because of the need for so much energy to evaporate, as water leaves the surface from which it is evaporating and removes a lot of heat with it.
True or False: pH is a measure of how acidic or basic a solution is.
Answer:
Explanation:
True
A 50.0 kg object is moving at 18.2 m/s when a 200 N force is applied opposite the direction of the objects motion, causing it to slow down to 12.6 m/s. How long was this force applies?
Answer:
t = 1.4[s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
[tex]P=m*v\\or\\P=F*t[/tex]
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 50 [kg]
v = velocity [m/s]
F = force = 200[N]
t = time = [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
[tex](m_{1}*v_{1})-F*t=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 50 [kg]
v₁ = velocity of the object before the impulse = 18.2 [m/s]
v₂ = velocity of the object after the impulse = 12.6 [m/s]
[tex](50*18.2)-200*t=50*12.6\\910-200*t=630\\200*t=910-630\\200*t=280\\t=1.4[s][/tex]
which two sttements about forces are true
The surface tension of the alcohol propanol in air has a value of 23.70 units
and the surface tension of water in air is 72.80 units. Which two statements
are true?
A. Propanol will have a flatter meniscus than water because the
forces between the molecules are smaller.
B. Propanol will have a higher boiling point than water because the
forces between the molecules are greater.
C. Propanol will have a more curved meniscus than water because
the forces between the molecules are greater.
D. Propanol will have a lower boiling point than water because the
forces between the molecules are smaller.
Answer:
A & D your welcome
Propanol surface is more flattered and has less boiling point than that of water.
To determine the correct statements among all the statements, we need to know about the surface tension.
What is surface tension?Surface tension is defined as force per unit length.More the surface tension, more the force between the molecules to keep the molecules together.What does happen, if molecules have more force of attraction?If the molecules have large force of attraction, more heat will be required to break the bonds between them. So the boiling point increases. Also with more force of attraction, the surface of the liquid becomes less flattered.Since, propanol has less surface tension than that of water, so its surface is more flattered and has less boiling point than that of water.
Learn more about the surface tension here:
brainly.com/question/277477
#SPJ2
what would the net force be on the box in the problems shown below.( both force and direction).
Answer:
4
Explanation:
The net force on the box a will be 20 N to the left and that on box b is 6 N downwards. The net force on box c is 90 N to the left and that on box d is zero.
What is net force?Force is an external agent acting on a body to change its motion or to deform it. The net force acting on a body depends on all the the forces with their magnitudes and directions.
If two same or different forces acts from the same direction they will add up and net force will be their sum. If they acts from the different directions, they will cancel each other in magnitudes.
In box a, the equal forces of 20 N opposes from each direction cancel and the net force will be 20 N to the left. I box b the 15 N cancel each other. Where the 4N and 2 N add up to have net force of 6 N downwards.
In box c, 10 N from opposite direction cancels and the 60 N and 30 N to the left add ups to have the net force of 90 N to the left. On box d, 5 N from opposite directions cancels as 12 N. Hence, net force is zero.
Find more on net force:
https://brainly.com/question/13410291
#SPJ5
How many meters are there in 6.17 km
Answer:
6170
Explanation:
Answer:
6170
Explanation:
Formula multiply kilometers by 1000 to get meters. :)
Help me please,
A ball is thrown straight up in the air. What is the velocity and acceleration at the top of the path?
A) v 0m/s, = 0m/s/s
B) v = 0m/s, a 10m/s/s
C) v = 10m/s, a 10m/s/s
D) v = 10m/s, a = 0m/s/s
E) None of the above
Option B
Explanation:
no distance was given only the acceleration due to the fact that it went up (10m/s/s)
s0 it is
0 m/s and 10m/s/s (option B)
A train moving with a speed of 20.9 m/s sounds a 103 Hz horn. What frequency is heard by an observer standing near the tracks as the train approaches
Answer:
observed frequency = 109.68 Hz
Explanation:
given data
speed u = 20.9 m/s
frequency f = 103 Hz
solution
we consider here speed of sound (v) is 343 m/s
so observed frequency is express as
observed frequency = f × [tex]\frac{v}{v-u}[/tex] ...............1
put here value and we get
observed frequency = 103 × \frac{343}{343-20.9}
observed frequency = 109.68 Hz
James is planning on registering for a course in electrical engineering which of the following sub disciplines could he opt for instrumentation engineering prosthetics plant design or signal processing
Answer:
Instrmentation engineering
Explanation:
Hope this helps!
4. A little boy pushes a wagon with his dog in it. The mass of the dog and
wagon together is 70 kg. The wagon accelerates at 0.85 m/s². What force is
the boy pulling with? F=mxa
Answer:
59.5 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 70 × 0.85
We have the final answer as
59.5 NHope this helps you
A metal has a work function of 4.50 eV. Find the maximum kinetic energy of the photoelectrons if light of wavelength 250 nm shines on the metal. (1 eV = 1.60 × 10−19 J, c = 3.00 × 108 m/s,h = 6.626 × 10-34 J ∙ s)
A) 0.00 eV.
B) 0.37 eV.
C) 0.47 eV.
D) 0.53 eV.
Answer:
0.46 eV
Explanation:
The maximum kinetic energy of the photoelectrons can be found using the formula
K.E = h(c)/λ - h(c)/λ(T), where
K.E = maximum kinetic energy needed
h(c) = Planck's constant, 6.626*10^-34
λ = Wavelength of the light, 250 nm
To start with, we convert our Planck's constant to nm and we have
h(c) = 1240 eV nm
Again, from the question, we already have h(c)/λ(T) given as 4.5 eV so all we need to do is substitute for it.
Plugging in all our values, we have
K.E = 1240/250 - 4.5
K.E = 4.96 - 4.5
K.E = 0.46 eV
Calculate the magnetic field strength needed on a 200-turn square loop 20.0 cm on a side to create a maximum torque of 300 N-m if the loop is carrying current of 25.0 A.
Answer:
The magnetic field strength needed is 1.5 T.
Explanation:
Given;
number of turns, N = 200 turn
length of the each side of the square loop, L = 20 cm = 0.2 m
maximum torque created, τ = 300 N-m
current through the loop, I = 25 A
The maximum torque created in the is the loop is given by;
τ = NIBA
Where;
B is the magnetic field strength, which is calculated as;
[tex]B = \frac{\tau}{NIA}\\\\B = \frac{300}{200 \times \ \ 25 \ \times\ \ (0.2)^2}\\\\B = 1.5 \ T \\[/tex]
Therefore, the magnetic field strength needed is 1.5 T.
Induced magnetic field strength is defined as the number of magnetic flux lines per unit area.The magnetic field strength will be 1.5 T.
What is magnetic field strength?Induced magnetic field strength is defined as the number of magnetic flux lines per unit area that pass perpendicular to a particular line direction. B stands for it.
The given data in the problem is
(I) is the current=25.0A
B is the induced magnetic field=?
τ is the Torque= 300 N-M
n is the number of loop=200
L is length of the each side of the square loop = 20 cm = 0.2 m
The maximum torque created in the loop will be
[tex]\rm \tau =NIBA\\\\ \rm B=\frac{\tau}{IBA} \\\\\rm B=\frac{600}{200\times25\times(0.2)^2}\\\\\rm B=1.5T\\[/tex]
Hence the magnetic field strength will be 1.5 T.
To learn more about the strength of induced magnetic field ;
https://brainly.com/question/2248956
Two rubber bands cause an object to accelerate with acceleration a. How many rubber bands are needed to cause an object with half the mass to accelerate three times as quickly?
Answer:
3
Explanation:
We would use a rather simple analogy here. That of the relationship between force and mass. Remember the formula of Force is mass times acceleration, so
F = m * a
So 0.5m * 3a = 1.5 F
In words, the relationship above means that, if two rubber bands are able to produce a force F in parallel, then they will require 1.5 * 2 = 3 rubber bands arranged in parallel to be able to produce force a force of 1.5 F
The number of rubber bands that will cause an object with half the mass to accelerate three times as quickly is 3.
The given parameters;
number of rubber band = 2acceleration = aLet the mass of the object = m
The force applied to the object by the two rubber bands;
F = ma
2 = ma
When the mass of the object is halved, the number of rubber bands required is calculated as;
[tex]\frac{2}{ma} = \frac{n}{m/2 \times 3a} \\\\\frac{2}{ma} = \frac{2n}{3ma} \\\\6ma = ma(2n)\\\\6 = 2n\\\\n = 3[/tex]
Thus, the number of rubber bands that will cause an object with half the mass to accelerate three times as quickly is 3.
Learn more here:https://brainly.com/question/18801986
what is the name of this element?
Answer:
fluorine is the right answer of this question
A 10.0kg object is moving at 1 m/s when a force is applied in the direction of the objects motion, causing it to speed up to 4 m/s. If the force was applied for 5s what is the magnitude of the force
Answer:
F = 6[N].
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
[tex]P=m*v\\or\\P=F*t[/tex]
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 10 [kg]
v = velocity [m/s]
F = force [N]
t = time = 5 [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 10 [kg]
v₁ = velocity of the object before the impulse = 1 [m/s]
v₂ = velocity of the object after the impulse = 4 [m/s]
[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]
