Which law is all forces exist in an action recreation pairs

Answer:

[tex]\lambda = 0.24 m[/tex]

Explanation:

The string vibrates in the third harmonics, n = 3

Length of the string, l = 0.36 m

Frequency of the tone produced, f = 500 Hz

The speed of sound in air is 344 m/s

Calculate the speed of sound produced by the string in the third harmonics:

The frequency of sound is given by the formula:

[tex]f = \frac{nv}{2l} \\500 = \frac{3v}{2*0.36}\\500 * 2 * 0.36 = 3v\\v = 360/3\\v = 120 m/s\\v = \lambda f\\\lambda = v/f\\\lambda = 120/500\\\lambda = 0.24 m[/tex]

Given:

As we know,

→ [tex]f = \frac{nv}{2l}[/tex]

then,

→ [tex]500 = \frac{3v}{2\times 0.36}[/tex]

→ [tex]360 = 3v[/tex]

      [tex]v = \frac{360}{3}[/tex]

         [tex]= 120 \ m/s[/tex]

hence,

The wavelength will be:

→ [tex]v = \lambda f[/tex]

or,

→ [tex]\lambda = \frac{v}{f}[/tex]

By substituting the values,

     [tex]= \frac{120}{500}[/tex]

     [tex]= 0.24 \ m[/tex]

Thus the approach is correct.  

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Answer: 0.75 hour(s) or 45 minutes

Explanation:

1 unit of electricity = 1kwh

Amount of energy consumed by 1kw load in one hour

Price per unit = ₹10

Air conditioner rating(power) = 1.2Kw

Given that balance = ₹9

Therefore, supriya's total energy cost = energy balance = ₹9

Total energy cost = power in kilowatt × time of operation (in hour) × cost per unit

₹9 = 1.2kw × time × ₹10

₹9 = 12 × time

Time = 9 / 12

Time = 0.75 hours

0.75 × 60 = 45 minutes

Answer: If i'm not mistaken I think it A) potential

Answer:

Option A

Explanation:

A. A ball is dropped from a height and hits the ground with a high speed. As this is a ball, it has elastic energy, so upon impact on the ground the kinetic energy can 1. go into making sound upon impact, or 2. go into making the ball bounce upward again. There may by more possible energy transfers, but this is what should occur in like conditions. Now it didn't mention that the ball transfers energy as such, only that the ball hits the ground at high speed. Thus, this statement does not explicitly describe a transfer of energy.

_______________________________________________________

Just to confirm that this is the correct answer, take a look at the other options. Option B states that the energy from the collision is transferred to heat, not in those exact words but still is given. Option C states that the plane increases speed, most likely transferring energy to the atmosphere, in the form sound. In option d the electricity causes the fan to turn, an explicit statement of the transfer of energy.

Hope that helps!

Answers:

In short, the boxes you check will be box 1, box 3, box 6.

================================================

Explanation:

It's not stated, but I'm assuming that A,B,C are three dimensional vectors

I'll go through each answer choice to say whether it's valid or not.

---------------------------

Choice 1

A x B is some vector

(A x B) x C is some other vector. Cross products produce vectors as outputs, when the two inputs are both 3D vectors. The output vector is the same dimension as the inputs.

Overall, the expression (A x B) x C is valid.

---------------------------

Choice 2

A dot B is a scalar

(A dot B)C is some vector

A dot (B x C) is a scalar

We cannot add a scalar to a vector. The given expression (A dot B)C + A dot (B x C) is not valid

---------------------------

Choice 3

B x C is a vector

B dot (B x C) is scalar

A[ B dot (B x C) ] is a vector in the form kA with k as a scalar.

The overall expression is valid

---------------------------

Choice 4

B x C is a vector

B(B x C) is not valid. We need to use a dot or cross symbol between the B and (B x C).

If we had kB with k as a scalar, then we don't need a symbol between them.

---------------------------

Choice 5

A dot B is a scalar

Scalars are not allowed when it comes to cross products, so (A dot B) crossed with anything is not valid.

---------------------------

Choice 6

B x C is some vector

A dot (B x C) results in a scalar

The expression is valid

Answer:

a =45 m/s2

t = 2 seconds

Explanation:

Hi, to answer this question we have to apply the next formula:

v^2 = u^2 +2 a d

Where:

v = final velocity = 90 m/s

u = initial velocity = 0 m/s (shots from rest)

a = acceleration (m/s2)

d = distance = 90m

90^2 = 0^2 + 2a(90)

Solving for a:

8,100= 180 a

8,100/180 = a

a = 45 m/s^2

For time:

v = u + at

90 = 0 + 45t

90/45=t

t =2 seconds

Answer:

Downwards

Explanation:

Using Fleming's right hand rule, where the middle finger represents the negative charge moving in the south to north direction, the fore finger represents the magnetic field which points in the east to west direction.

If we are to follow this orientation and place the thumb, middle finger and fore-finger at right angles to each other, the thumb represents the direction of the magnetic force on the charge.

In this case, the magnetic force points downwards after setting the other orientations of the magnetic field and the negative charge's direction.

Answer:

(a) 4.82 m/s

(b) The simmer need to head 57.05° upstream of the river to reach a point directly opposite the river

(c) 4.024 seconds

Explanation:

The parameters given are;

The speed of the swimmer = 5.75 m/s

The direction of the resultant motion = 40° downstream

The speed of the current = x m/s

Therefore in a given second, we have that the swimmer moves 5.75 meters across the river while the current moves x meters downstream

Which gives;

[tex]tan(40^{\circ}) = \dfrac{x}{5.75}[/tex]

x = 5.75 × tan(40°) = 4.82 m/s

The speed of the current = 4.82 m/s

(b) If the swimmer swims at a direction θ to reach a point, p, directly opposite the river, we have;

The resultant speed across the river will be the swimmer's swimming speed which is 5.75 m/s

5.75² = y² + 4.82²

y = √(5.75² - 4.82²) = √9.78

tan(θ) = 4.82/(√9.78) = 1.54

θ = tan⁻¹(1.54) = 57.05°

The simmer need to swim 57.05° upstream to reach a point directly opposite the river

(c) If the river is 15 m wide, we have;

Time (t) = Distance/speed

The component of the swimmer's speed directly across the river = 5.75/(tan(57.05°)

The component of the swimmer's speed directly across the river = 3.73 m/s

The time, t, to cross the river is therefore;

t = 15/3.73 = 4.024 seconds

Answer:

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

Explanation:

El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:

Distancia horizontal (en metros)

[tex]x = x_{o} + v_{o}\cdot t \cdot \cos \theta[/tex]

Donde:

[tex]x_{o}[/tex] - Posición horizontal inicial, medida en metros.

[tex]t[/tex] - Tiempo, medido en segundos.

[tex]v_{o}[/tex] - Velocidad inicial, medida en metros por segundo.

[tex]\theta[/tex] - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.

Distancia vertical (en metros)

[tex]y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}[/tex]

Donde:

[tex]y_{o}[/tex] - Posición vertical inicial, medida en metros.

[tex]g[/tex] - Constante gravitacional, medida en metros por segundo al cuadrado.

Partiendo de la primera ecuación, se despeja el tiempo:

[tex]t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}[/tex]

Si [tex]x = 31\,m[/tex], [tex]x_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex] and [tex]\theta = 33^{\circ}[/tex], entonces:

[tex]t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}[/tex]

[tex]t = 0.924\,s[/tex]

La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si [tex]y_{o} = 0\,m[/tex], [tex]v_{o} = 40\,\frac{m}{s}[/tex], [tex]t = 0.924\,s[/tex] y [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], entonces:

[tex]y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}[/tex]

[tex]y = 15.943\,m[/tex]

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

Answer: 11%

Explanation:

Given that

X = ab^2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3 respectively.

Percentage error of b = 2%

Percentage error of b^2 = 2 × 2 = 4

When you are calculating for percentage error that involves multiplication and division, you will always add up the percentage error values.

Percentage error of X will be;

Percentage error of a + percentage error of b^2 + percentage error of c

Substitute for all these values

4 + 4 + 3 = 11%

Therefore, percentage error of X is 11%

Answer:

hope this helps you :)

Explanation:

An object is in motion if its position changes relative to another object. To decide if you are moving, you can use your chair as a reference point. A reference point is a place or object used for comparison to determine if something is in motion.

Answer:

Option D. is the correct choice.

Explanation:

Resistances connected in series add up to give equivalent resistance.

R_eq = 10+20+30 = 60 ohm

Best Regards!

Answer:

Option D

Explanation:

I just took the T eSt on ApEx

Answer: mammals may be relatively better at solving problems than birds.

Answer: A

Explanation:

mammals may be relatively better at solving problems than birds

Answer:

B. Kinetic energy of the system is partially used up in the deformation of the vehicles.

Explanation:

In an inelastic collision, momentum is conserved, but kinetic energy is not. Kinetic energy is lost as heat or lost in the deformation of the objects.

The correct statement about Kinetic energy of the system after the collision is that KE of the system will be partially used up in the deformation of the vehicles. Hence, option B is correct.

The force that an object has because it is moving is known as kinetic energy in physics. It is defined as the quantity of effort required to accelerate anybody of a specific mass from rest to its specified velocity. The body keeps its kinetic energy after acquiring it during acceleration, barring changes in speed.

When slowing from its current pace to a condition of rest, the body expends the very same amount of energy. Any term in the Lagrangian of a system that has a derivative in regard to time is formally referred to as kinetic energy.

The momentum of an object is conserved, but kinetic energy is not in an inelastic collision. In the form of heat or by the distortion of the objects, kinetic energy is lost.

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Answer:

How you treat someone who may have been poisoned depends on:

The person's symptoms

The person's age

Whether you know the type and amount of the substance that caused poisoning

If you are concerned about possible poisoning, call Poison Help at 800-222-1222 in the United States or your regional poison control center. Poison control centers are excellent resources for poisoning information and, in many situations, may advise that in-home observation is all that's needed.

Answer:

The correct answer to the following question will be "An ecosystem".

Explanation:

So that the above seems to be the right answer.

Answer:

The distance the box traveled down the plane is 19.28 m

Explanation:

The angle of repose, α, is given by the relation;

tan⁻¹(μ) = α

tan⁻¹(0.1) = 5.7°

Therefore, we have;

M·g·sin(θ) - μ·N = M·a

Where:

M = Mass of the box = 10 kg

g = Acceleration due to gravity = 9.81 m/s²

θ = Angle of inclination of the plane = 30°°

μ = Coefficient of friction = 0.1

a = Acceleration of the box along the incline plane

N = Normal force due to the weight of the box = M·g·cos(θ)

10 × 9.81 × sin30 - 0.1 × 9.81 × cos(30)  = 10 × a

48.2 = 10 ×a

a = 48.2/10 = 4.82 m/s²

The distance, s, traveled by the box is given by the relation;

s = u·t + 1/2×a·t²

Where:

u = Initial velocity = 0 m/s

t = Time of motion = 2.0 s

∴ s = 0×2 + 1/2 × 4.8 × 2² = 19.28 m

The box traveled 19.28 m down the plane.

The distance that the box travels down the plane is 8.1 m.

The given parameters;

The acceleration of the box is calculated as follows;

[tex]\Sigma F_{net} = ma\\\\mgsin\theta - \mu mg cos\theta = ma\\\\gsin\theta - \mu g cos\theta = a\\\\g(sin\theta - \mu cos \theta ) = a\\\\9.8(sin30 \ - \ 0.1\times cos 30) = a\\\\9.8(0.413) = a\\\\4.05 \ m/s^2 = a[/tex]

The distance traveled by the box down the plane is calculated as follows;

[tex]s= ut + \frac{1}{2} at^2\\\\s = 0 + \frac{1}{2} \times 4.05 \times 2^2\\\\s = 8.1 \ m[/tex]

Thus, the distance that the box travels down the plane is 8.1 m.

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Answer:

The 500 would be able to keep a light bulb on longer.

Explanation:

The 500 would be able to hold more charge than the 100 which means it can keep the light bulb lit for longer.

Answer: find the answer in the explanation

Explanation:

1.) More thermal energy will be required to raise the temperature of 2 Kg of a substance by 10°C than is required to raise the temperature of 1 Kg of the same substance by 10°C. 

Because the thermal energy depends on the mass of an object.

If the two materials are the same, then they will have the same specific heat capacity. Thermal energy can be expressed as:

H = MCØ

Where

M = mass of the body

C = specific heat capacity

Ø = change in temperature

H = thermal energy

If u substitute the two values of masses into the formula above, then, the mass of 2kg will produce higher thermal energy .

Il.) Heat causes expansion. Using kinetic theory to explain this, the molecules of solid material are in a fixed pattern, held together with strong bonds. When heat is applied to the solid, the molecules will start vibrating in their fixed position. As a result of this, the bond between the molecules begins to loss. This eventually lead to expansion of solid.

Answer:

The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.

hmax = 5740.48 m

Explanation:

This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.

V₀ = 420m/s and θ₀ = 53.0°

So, when the cannonball is fired it has horizontal and vertical components:

V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s

V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s

When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:

Vy = V₀y - g tₐ = 0

tₐ = V₀y/g

tₐ = (335.43m/s)/(9.8m/s²) = 34.23s

Then, the maximum height is reached in the instant tₐ = 34.23s:

h = V₀y tₐ - 1/2g tₐ²

hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²

hmax = 11481.77m - 5741.29m

hmax = 5740.48m

Answer:

1. Largest force: C;  smallest force: B; 2. ratio = 9:1

Explanation:

The formula for the force exerted between two charges is

[tex]F=K\dfrac{ q_{1}q_{2}}{r^{2}}[/tex]

where K is the Coulomb constant.

q₁ and q₂ are also identical and constant, so Kq₁q₂ is also constant.

For simplicity, let's combine Kq₁q₂ into a single constant, k.

Then, we can write  

[tex]F=\dfrac{k}{r^{2}}[/tex]

1. Net force on each particle

Let's

Define forces exerted to the right as positive and those to the left as negative.

(a) Force on A

[tex]\begin{array}{rcl}F_{A} & = & F_{B} + F_{C} + F_{D}\\& = & -\dfrac{k}{d^{2}} - \dfrac{k}{(2d)^{2}} +\dfrac{k}{(3d)^{2}}\\& = & \dfrac{k}{d^{2}}\left(-1 - \dfrac{1}{4} + \dfrac{1}{9} \right)\\\\& = & \dfrac{k}{d^{2}}\left(\dfrac{-36 - 9 + 4}{36} \right)\\\\& = & \mathbf{-\dfrac{41}{36} \dfrac{k}{d^{2}}}\\\\\end{array}[/tex]

(b) Force on B

[tex]\begin{array}{rcl}F_{B} & = & F_{A} + F_{C} + F_{D}\\& = & \dfrac{k}{d^{2}} - \dfrac{k}{d^{2}} + \dfrac{k}{(2d)^{2}}\\& = & \dfrac{k}{d^{2}}\left(\dfrac{1}{4} \right)\\\\& = &\mathbf{\dfrac{1}{4} \dfrac{k}{d^{2}}}\\\\\end{array}[/tex]

(C) Force on C

[tex]\begin{array}{rcl}F_{C} & = & F_{A} + F_{B} + F_{D}\\& = & \dfrac{k}{(2d)^{2}} + \dfrac{k}{d^{2}} + \dfrac{k}{d^{2}}\\& = & \dfrac{k}{d^{2}}\left( \dfrac{1}{4} +1 + 1 \right)\\\\& = & \dfrac{k}{d^{2}}\left(\dfrac{1 + 4 + 4}{4} \right)\\\\& = & \mathbf{\dfrac{9}{4} \dfrac{k}{d^{2}}}\\\\\end{array}[/tex]

(d) Force on D

[tex]\begin{array}{rcl}F_{D} & = & F_{A} + F_{B} + F_{C}\\& = & -\dfrac{k}{(3d)^{2}} - \dfrac{k}{(2d)^{2}} - \dfrac{k}{d^{2}}\\& = & \dfrac{k}{d^{2}}\left( -\dfrac{1}{9} - \dfrac{1}{4} -1 \right)\\\\& = & \dfrac{k}{d^{2}}\left(\dfrac{-4 - 9 -36}{36} \right)\\\\& = & \mathbf{-\dfrac{49}{36} \dfrac{k}{d^{2}}}\\\\\end{array}[/tex]

(e) Relative net forces

In comparing net forces, we are interested in their magnitude, not their direction (sign), so we use their absolute values.

[tex]F_{A} : F_{B} : F_{C} : F_{D} = \dfrac{41}{36} : \dfrac{1}{4} : \dfrac{9}{4} : \dfrac{49}{36}\ = 41 : 9 : 81 : 49\\\\\text{C experiences the largest net force.}\\\text{B experiences the smallest net force.}\\[/tex]

2. Ratio of largest force to smallest

[tex]\dfrac{ F_{C}}{ F_{B}} = \dfrac{81}{9} = \mathbf{9:1}\\\\\text{The ratio of the largest force to the smallest is $\large \boxed{\mathbf{9:1}}$}[/tex]

Answer:

Explanation:

Here,

m = 3 Kg

a = 0 m/s^2 (velocity is constant so the acceleration is zero)

We have,

F = ma

or, F = 3 x 0

or, F = 0 N

Constant velocity can always be associated with a zero net force.

Answer:

Here's what I get  

Explanation:

When two waves meet, they interfere with each other.

1. Constructive interference

If the crests of the waves happen to line up, as in Fig. 1,  the amplitudes add up.

The crests become twice as high. The troughs also line up, so they become twice as deep.

We call this constructive interference.

2. Destructive interference

If the trough of one wave meets the crest of another, as in Fig. 2, the opposite happens.

The trough of one wave subtracts from the crest of the other, so the two waves cancel.

We call this effect destructive interference.

Answer:

Explanation:

In projectile,

Maximum height = [tex]\frac{u^{2}sin^{2} \theta }{2g}[/tex] and range = [tex]\frac{u^{2}sin2\theta }{g}[/tex]

u = velocity of the body

[tex]\theta[/tex] = angle of launch

g = acceleration due to gravity

If the range equals the maximum height in an ideal projectile launch on a horizontal plane, this means;

[tex]\frac{u^{2}sin^{2} \theta }{2g} = \frac{u^{2}sin2\theta }{g}[/tex]

since [tex]sin2\theta = 2sin\theta cos\theta[/tex]

[tex]\frac{u^{2}sin^{2} \theta }{2g} = \frac{u^{2}2sin\theta cos\theta }{g}\\\frac{sin\theta}{2} =2cos\theta \\sin\theta = 4cos\theta\\\frac{sin\theta}{cos\theta} = 4\\tan\theta = 4\\\theta = tan^{-1} \\4\theta = 75.9^{0}[/tex]

The angle at which the range equals the maximum height in an ideal projectile launch on a horizontal plane is approximately 76°

Answer:

[tex]I=0.5 \:A[/tex]  is the correct answer.

Explanation:

Using the ohm's law, we have:

[tex]V=IR\\\\I=\frac{V}{R}=\frac{3}{6}\\\\I=0.5 \:A[/tex]

Best Regards!

Explanation:

When a person is standing still, the forces acting on them (weight force pulling down and normal force pushing up) are equal and opposite, so the net force is balanced.  So the person will continue to be at rest, unless the net force becomes unbalanced.

When a person falls with a parachute, the forces acting on them (weight force pulling down and air resistance pushing up) are equal and opposite, so the net force is balanced.  So the person will continue to fall at the same speed until the net force becomes unbalanced.

Answer:

i. + 22.5 m ii. 4.0 m

Explanation:

i. Image distance

Using the lens formula

1/u + 1/v = 1/f where f = focal length = + 18.0 m, u = object distance = distance of shark away from lens = + 90.0 m and v = image distance from lens = unknown

So, we find v

1/v = 1/f - 1/u

= 1/+18 - 1/+90

= (5 - 1)/90

= 4/90

v = 90/4

= + 22.5 m

So the image is real and formed 22.5 m away on the other side of the lens.

ii Length of Shark

Using the magnification formula, m = image height/object height = image distance/object distance. image height = 1.0 m where object height = length of shark.

m = image distance/object distance

= v/u

= +22.5/+90

= 0.25

0.25 = image height/object height

So,

object height = image height/0.25

= 1.0 m/0.25

= 4.0 m

So, the length of the shark is 4.0 m

Answer:

A - 0 N

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Answer:

.5 m N

Explanation:

Displacement just means distance from starting point, so moving 3 m north then 2.5 m south is the same as if you took 3 steps forward then 2.5 steps backward. The end point is only .5 away from the start point.

The displacement of a hiker if he travels 3.0 m N and then 2.5 m S is 0.5 m.

It is given that the hiker travels 3.0 m North and then 2.5 m South.

It is required to find the displacement of a hiker.

What is the displacement of a hiker if he travels 3.0 m N and then 2.5 m S?

As we know the displacement is the shortest distance acquired by the body or simply we say that difference between the initial and the final point of the body.

From the given question the hiker moves 3.0 m in the north that is in upward direction and from the same point the hiker comes back 2.5 m in south that is downward at the same line. To find the displacement,

Displacement = Final Point - Initial Point

Displacement = (3.0 - 2.5)m = 0.5 m

Thus, the displacement of a hiker if he travels 3.0 m North and then 2.5 m South is 0.5 m.

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