Which of the following are true?
(check all that apply)

If you take any number and multiply it by i-squared the sign(s) will change

Any imaginary number can be written as a real number

If you take any real number and
multiply it by i-squared it will stay a real number

If you take any number and multiply it by i-squared nothing will change

Any real number can be written as an imaginary number

The expression that uses the greatest common factor (GCF) to factor 24c-18 is option (a) 6(4c-3).

To factor the expression 24c-18 using the greatest common factor (GCF), we first identify the GCF of the coefficients 24 and 18, which is 6. We can then rewrite the expression as 6(4c-3).

The GCF represents the largest number that divides evenly into both 24 and 18. In this case, 6 is a common factor of both 24 and 18 because it divides both numbers without leaving a remainder. By factoring out the GCF, we simplify the expression and make it more manageable.

The resulting expression, 6(4c-3), demonstrates that the GCF, which is 6, can be multiplied by the expression (4c-3) to obtain the original expression 24c-18. This factored form provides a concise representation of the expression and highlights the common factor that is present.

In conclusion, option (a) 6(4c-3) correctly uses the GCF to factor 24c-18, demonstrating the application of the GCF concept in algebraic expressions.

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Answer:

4.2.1)  R140 000

4.2.2)  R144 758.28

4.2.3)  Option 2

Step-by-step explanation:

To calculate the return on Ayanda's investment using Option 1, we can use the simple interest formula.

[tex]\boxed{\begin{minipage}{7 cm}\underline{Simple Interest Formula}\\\\$ I =Prt$\\\\where:\\\\ \phantom{ww}$\bullet$ $I =$ interest accrued \\ \phantom{ww}$\bullet$ $P =$ principal amount \\ \phantom{ww}$\bullet$ $r =$ interest rate (in decimal form) \\ \phantom{ww}$\bullet$ $t =$ time (in years) \\ \end{minipage}}[/tex]

Given values:

Substitute the given values into the formula and solve for I:

[tex]I=200000 \cdot 0.12 \cdot 6[/tex]

[tex]I=24000 \cdot 6[/tex]

[tex]I=144000[/tex]

Therefore, the return on Ayanda's investment using Option 1 is R144000.

[tex]\hrulefill[/tex]

To calculate the return on Ayanda's investment using Option 2, we can use the compound interest formula.

[tex]\boxed{\begin{minipage}{7 cm}\underline{Annual Compound Interest Formula}\\\\$ I=P\left(1+r\right)^{t}-P$\\\\where:\\\\ \phantom{ww}$\bullet$ $I =$ interest accrued \\ \phantom{ww}$\bullet$ $P =$ principal amount \\ \phantom{ww}$\bullet$ $r =$ interest rate (in decimal form) \\ \phantom{ww}$\bullet$ $t =$ time (in years) \\ \end{minipage}}[/tex]

Given values:

Substitute the given values into the formula and solve for I:

[tex]I=200000(1+0.095)^6-200000[/tex]

[tex]I=200000(1.095)^6-200000[/tex]

[tex]I=200000(1.72379142...)-200000[/tex]

[tex]I=344758.28426...-200000[/tex]

[tex]I=144758.28426...[/tex]

[tex]I=144758.28[/tex]

Therefore, the return on Ayanda's investment using Option 2 is R144758.28.

[tex]\hrulefill[/tex]

Comparing the returns from both options, we find that Option 1 offers a return of R144000, while Option 2 offers a return of R144758.28. As R144758.28 > R144000, then Option 2 will render the most money for Ayanda's investment.

Answer:

Here is the proof of the trigonometric identity

[tex]\frac{\csc x \cos x}{\tan x + \cot x} = \cos^2 x[/tex]

Given:

[tex]\frac{\csc x \cos x}{\tan x + \cot x}[/tex]

To prove:

[tex]\frac{\csc x \cos x}{\tan x + \cot x} = \cos^2x[/tex]

Step 1: Rewrite all trigonometric functions in terms of sine and cosine.

[tex]\frac{\csc x \cos x}{\tan x + \cot x} \\ = \frac{\frac{1}{\sin x} \cos x}{\frac{\sin x}{\cos x} + \frac{\cos x}{\sin x}} \\ = \frac{\cos x}{\sin x \cdot \frac{\sin x}{\cos x} + \cos x \cdot \frac{\cos x}{\sin x}} \\ \\ = \frac{\cos x}{\frac{\sin^2 x + \cos^2 x}{\sin x \cos x}} \\ \\ = \frac{\cos x}{\frac{1}{\sin x \cos x}} \\ \\ = \cos x \cdot \sin x \cos x \\ \\ = \cos^2 x [/tex]

Step 2:Simplify the expression.

[tex]\cos^2 x = \cos^2 x[/tex]

Conclusion:Therefore,

[tex]\frac{\csc x \cos x}{\tan x + \cot x} = \cos^2 x.[/tex]

Hence Proved:

Answer:

[tex]\dfrac{ \csc x \cos x}{\tan x + \cot x}=\cos^2 x[/tex][tex]\textsf{Rewrite $\csc x=\dfrac{1}{\sin x}}, \tan x=\dfrac{\sin x}{\cos x}$, and $\cot x=\dfrac{\cos x}{\sin x}$:}[/tex]

[tex]\boxed{\dfrac{ \dfrac{1}{\sin x} \cdot \cos x}{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}}=\cos^2 x[/tex]

[tex]\boxed{\dfrac{\dfrac{\cos x}{\sin x}}{\dfrac{\sin^2 x }{\sin x + \cos x}+\dfrac{\cos^2 x }{\sin x + \cos x}}}=\cos^2 x[/tex]

[tex]\boxed{\dfrac{\dfrac{\cos x}{\sin x}}{\dfrac{\sin^2 x + \cos^2 x}{\sin x + \cos x}}}=\cos^2 x[/tex]

[tex]\boxed{\dfrac{\dfrac{\cos x}{\sin x}}{\dfrac{1}{\sin x + \cos x}}}=\cos^2 x[/tex]

[tex]\boxed{\dfrac{\cos x}{\sin x} \cdot \sin x \cos x}=\cos^2 x[/tex]

[tex]\cos^2 x=\cos^2 x[/tex]

Step-by-step explanation:

Given trigonometric identity:

[tex]\dfrac{ \csc x \cos x}{\tan x + \cot x}=\cos^2 x[/tex]

[tex]\textsf{Use the identities\;\;$\csc x=\dfrac{1}{\sin x}$\;,\;$\tan x = \dfrac{\sin x}{\cos x}$\;\;and\;\;$\cot x=\dfrac{\cos x}{\sin x}$}:[/tex]

[tex]\textsf{Rewrite $\csc x=\dfrac{1}{\sin x}}, \tan x=\dfrac{\sin x}{\cos x}$, and $\cot x=\dfrac{\cos x}{\sin x}$:}[/tex]

[tex]\boxed{\dfrac{ \dfrac{1}{\sin x} \cdot \cos x}{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}}=\cos^2 x[/tex]

Simplify the numerator and make the fractions in the denominator like fractions:

[tex]\boxed{\dfrac{\dfrac{\cos x}{\sin x}}{\dfrac{\sin^2 x }{\sin x + \cos x}+\dfrac{\cos^2 x }{\sin x + \cos x}}}=\cos^2 x[/tex]

[tex]\textsf{Apply\;the\;fraction\;rule\;\;$\dfrac{a}{b}+\dfrac{c}{b}=\dfrac{a+c}{b}$\;to\;the\;denominator}:[/tex]

[tex]\boxed{\dfrac{\dfrac{\cos x}{\sin x}}{\dfrac{\sin^2 x + \cos^2 x}{\sin x + \cos x}}}=\cos^2 x[/tex]

[tex]\textsf{Use\;the\;identity\;\;$\sin^2x+\cos^2x=1$}:[/tex]

[tex]\boxed{\dfrac{\dfrac{\cos x}{\sin x}}{\dfrac{1}{\sin x + \cos x}}}=\cos^2 x[/tex]

[tex]\textsf{Apply\;the\;fraction\;rule\;\;$\dfrac{a}{\frac{b}{c}}=a \cdot \dfrac{c}{b}$}:[/tex]

[tex]\boxed{\dfrac{\cos x}{\sin x} \cdot \sin x \cos x}=\cos^2 x[/tex]

Cancel the common factor sin x, and apply the exponent rule aa = a²:

[tex]\cos^2 x=\cos^2 x[/tex]

The value of x in the parallelogram is 112°.

In a parallelogram, adjacent angles are always supplementary. This means that the sum of two adjacent angles in a parallelogram is always 180 degrees.

To understand this concept, let's consider a parallelogram ABCD. The opposite sides of a parallelogram are parallel and equal in length, and the opposite angles are congruent. Adjacent angles are those that share a side. Let's say angle A and angle B are adjacent angles in the parallelogram.

Since opposite angles of a parallelogram are congruent, we have angle A is congruent to angle C, and angle B is congruent to angle D.

Now, let's consider angle A and angle B. The sum of angle A and angle B is equal to the sum of angle C and angle D because opposite angles are congruent.

Therefore, we can conclude that angle A + angle B = angle C + angle D = 180 degrees.

This property holds true for all parallelograms. So, in any parallelogram, the adjacent angles are always supplementary, meaning their sum is 180 degrees.

For the given question, we know x° + 68° = 180°.

Then x° = 180° - 68°

x° = 112°

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Answer:

GOTCHU BROO

1.

a) sin 36° = 0.5878 (rounded to 4 decimal places)

b) cos 14° = 0.9703 (rounded to 4 decimal places)

c) tan 86° = -11.4301 (rounded to 4 decimal places)

2.

a) To find the measure of angle A when sin A = 0.6018, you can use the inverse sine function (sin^(-1)) to find the angle. Using a calculator, sin^(-1)(0.6018) ≈ 37.12° (rounded to the nearest degree).

b) To find the measure of angle B when cos B = 0.9205, you can use the inverse cosine function (cos^(-1)) to find the angle. Using a calculator, cos^(-1)(0.9205) ≈ 23.33° (rounded to the nearest degree).

c) To find the measure of angle C when tan C = 0.0349, you can use the inverse tangent function (tan^(-1)) to find the angle. Using a calculator, tan^(-1)(0.0349) ≈ 1.99° (rounded to the nearest degree).

Based on the image attached, the solution for GE  is approximately 22.72.

To  be able to solve the equation √129 + √129 = GE, one need to simplify the  expression and then isolate GE.

Step 1: One can add the square roots:

Note that the equation:

√129 + √129 = GE.

Step 2:  Do put together the square root terms:

2√129 = GE.

Step 3:  Then Divide by 2:

√129 = GE/2.

Step 4: The Square both sides:

129 = (GE²)/4.

Step 5: So, Multiply by 4:

516 = GE².

Lastly, Take the square root:

√516 = √(GE²)

√516 = GE

GE = 22.72. approx.

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See text below



Step 26

Solve the equation for GE:

√129+√129 = GE

GE=2/129

Show steps

The set Y^X can be defined as the set of all possible mappings between the elements of X and Y.

In mathematics, the set of all functions from a set X to a set Y is denoted by Y^X, and is defined as the set of all possible mappings from X to Y. The set Y^X consists of all possible functions that can be constructed from the set X to the set Y.

Here, the function is a mapping between two sets in which each element of the first set is mapped to one and only one element of the second set.

An example of the set of all functions from X to Y is as follows: Consider the sets X = {1,2,3} and Y = {a,b,c}. Then the set of all functions from X to Y is denoted by Y^X. It is represented as follows:

Y^X = {f | f: X → Y}

Therefore, the set of all functions from X to Y is given by:

Y^X = { (1,a), (1,b), (1,c), (2,a), (2,b), (2,c), (3,a), (3,b), (3,c) }

where each element in Y^X is a function that maps each element of X to an element of Y.

The set of all functions from X to Y is an important concept in mathematics as it is widely used in many areas such as graph theory, topology, and calculus.

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The following are six measures of solvency or profitability that can be determined from the given data of Gates Inc.:Debt ratio: The debt ratio measures the proportion of total assets that are financed by the creditors. It is calculated as: Debt ratio = Total liabilities / Total assets= 3,000,000 / 7,000,000= 0.43 or 43%

Debt-to-equity ratio: The debt-to-equity ratio measures the amount of debt financing in relation to the amount of equity financing. It is calculated as: Debt-to-equity ratio = Total liabilities / Total stockholders' equity= 3,000,000 / 5,000,000= 0.6 or 60%Interest coverage ratio:

The interest coverage ratio measures the number of times the company can cover its interest expenses with its earnings before interest and taxes (EBIT). It is calculated as:Interest coverage ratio = EBIT / Interest expense= (18,900,000 - 120,000 - (1,570,000 + 930,000 - 100,000 - 400,000)) / 120,000= 174,760 / 120,000= 1.5 or 1.5 timesCash coverage ratio:

The cash coverage ratio measures the number of times the company can cover its interest expenses with its cash flow from operations. It is calculated as:Cash coverage ratio = (EBIT + Depreciation) / Interest expense= (18,900,000 - 120,000 - (1,570,000 + 930,000 - 100,000 - 400,000) + 3,200,000 / 10) / 120,000= 764,760 / 120,000= 6.4 or 6.4 times Return on assets (ROA):

The return on assets ratio measures the company's ability to generate earnings from its assets. It is calculated as:ROA = Net income / Total assets= 930,000 / [(7,000,000 + 3,000,000) / 2]= 930,000 / 5,000,000= 0.186 or 18.6%Return on equity (ROE): The return on equity ratio measures the company's ability to generate earnings from its equity financing. It is calculated as: ROE = Net income / Total stockholders' equity= 930,000 / 5,000,000= 0.186 or 18.6%

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Parallelism is defined as the condition whereby the slope of two line are equal because the lines are parallel.

Perpendicularity is defined as the condition whereby the slope of two lines is equal to -1 because they are perpendicular to each other.

A parallel line is defined as the type of lines that never meet each other till infinity.

A perpendicular line is defined as the line that meets at a point to form angle 90°.

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Answer:

[tex]\cos G=\dfrac{2}{3}[/tex]

[tex]\csc E=\dfrac{3}{2}[/tex]

[tex]\cot G=\dfrac{2}{\sqrt{5}}[/tex]

Step-by-step explanation:

If the right angle of right triangle EFG is ∠F, then EG is the hypotenuse, and EF and FG are the legs of the triangle. (Refer to attached diagram).

Given ΔEFG is a right triangle, and EG = 6 and FG = 4, we can use Pythagoras Theorem to calculate the length of EF.

[tex]\begin{aligned}EF^2+FG^2&=EG^2\\EF^2+4^2&=6^2\\EF^2+16&=36\\EF^2&=20\\\sqrt{EF^2}&=\sqrt{20}\\EF&=2\sqrt{5}\end{aligned}[/tex]

Therefore:

[tex]\hrulefill[/tex]

To find cos G, use the cosine trigonometric ratio:

[tex]\boxed{\begin{minipage}{9 cm}\underline{Cosine trigonometric ratio} \\\\$\sf \cos(\theta)=\dfrac{A}{H}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}[/tex]

For angle G, the adjacent side is FG and the hypotenuse is EG.

Therefore:

[tex]\cos G=\dfrac{FG}{EG}=\dfrac{4}{6}=\dfrac{2}{3}[/tex]

[tex]\hrulefill[/tex]

To find csc E, use the cosecant trigonometric ratio:

[tex]\boxed{\begin{minipage}{9 cm}\underline{Cosecant trigonometric ratio} \\\\$\sf \csc(\theta)=\dfrac{H}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}[/tex]

For angle E, the hypotenuse is EG and the opposite side is FG.

Therefore:

[tex]\csc E=\dfrac{EG}{FG}=\dfrac{6}{4}=\dfrac{3}{2}[/tex]

[tex]\hrulefill[/tex]

To find cot G, use the cotangent trigonometric ratio:

[tex]\boxed{\begin{minipage}{9 cm}\underline{Cotangent trigonometric ratio} \\\\$\sf \cot(\theta)=\dfrac{A}{O}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}[/tex]

For angle G, the adjacent side is FG and the opposite side is EF.

Therefore:

[tex]\cot G=\dfrac{FG}{EF}=\dfrac{4}{2\sqrt{5}}=\dfrac{2}{\sqrt{5}}[/tex]

To complete the table with tally marks and frequencies, we'll assume the range of values for the frequencies is from 1 to 5. Here's the completed table:

Subjects                              Tally Marks                                Frequency                          

Mathematics                       |                                                         1

Science                               ||                                                        2

Filipino                               |||                                                       3

English                               ||||                                                      4

Araling Panlipunan       |||||                                                     5

Now, let's assign tally marks and frequencies to each subject:

Mathematics:

For a frequency of 1, we can use a single tally mark: |

So, the tally marks for Mathematics would be: |

Science:

For a frequency of 2, we can use two tally marks: ||

So, the tally marks for Science would be: ||

Filipino:

For a frequency of 3, we can use three tally marks: |||

So, the tally marks for Filipino would be: |||

English:

For a frequency of 4, we can use four tally marks: ||||

So, the tally marks for English would be: ||||

Araling Panlipunan:

For a frequency of 5, we can use five tally marks: |||||

So, the tally marks for Araling Panlipunan would be: |||||

By filling in the tally marks and frequencies, the table is now complete.

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Answer:

T1=-12

T2=-19

T3=-26

Step-by-step explanation:

Determine which term will have a value of -6998

-7n-5=-6998

-7n=-6998+5

-7n=-6993

-7n/-7=-6993/-7

n=999

the number of adults who bought tickets is 25.

The probability that out of 250 babies born, 110 or fewer will be boys is approximately 14.5%.

To calculate the probability that out of 250 babies born, 110 or fewer will be boys, we can use the binomial probability formula.

The binomial probability formula is given by:

P(X ≤ k) = Σ (nCk) * p^k * (1-p)^(n-k)

where:

P(X ≤ k) is the probability of having k or fewer successes,

n is the number of trials (250 babies born),

k is the number of successes (110 or fewer boys),

p is the probability of success (0.5, assuming boys and girls are equally probable),

nCk is the number of combinations of n objects taken k at a time.

Calculating this probability can be time-consuming, so we can use statistical software or online calculators to obtain an accurate result. When using an online binomial probability calculator with n = 250, p = 0.5, and k = 110, we find that the probability is approximately 14.5%.

Rounding this result to the nearest tenth of a percent, we can conclude that the probability of having 110 or fewer boys out of 250 babies born is approximately 14.5%.

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Answer: C

Based on the information given, one might conclude that the population mean is probably greater than 85 minutes. So, the correct answer would be C. The population mean is probably greater than 85 minutes.

Answer:

C. Has to be greater than 85

Step-by-step explanation:

We can solve the expression by simplifying and canceling out the common factor to get: 2bc / 3mn ÷ 4bc / -6mb = -2b/2n.

To solve the problem, we can simplify the expression using the rules of division and multiplication:

2bc / 3mn ÷ 4bc / -6mb

First, let's simplify the divisions:

(2bc / 3mn) ÷ (4bc / -6mb)

Dividing is the same as multiplying by the reciprocal, so we can rewrite it as:

(2bc / 3mn) * (-6mb / 4bc)

Next, we can simplify the multiplication by canceling out the common factor:

(1 / n) * (-2b / 2)

Simplify further:

= -2b/2n

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The highest point for the quadratic function for the height of the object, h(t) = -16·t² + 224·t + 816, indicates that the interval over which the height of the object is increasing is; (-∞, 7]

The shape of the graph of a quadratic function is a parabola.

The function for the height of the object in question 3 is; h(t) = -16·t² + 224·t + 816

Where;

t = The time in seconds

The height of the object is increasing in the interval to the left of the highest point, which can be found as follows;

The x-coordinate of the highest point of the quadratic function, f(x) = a·x² + b·x + c is; x = -b/(2·a)

Therefore, the x-coordinates of the highest point of the object is; -224/(2 × (-16)) = 7

Therefore, the height of the object is increasing in the interval; -∞ < t ≤ 7

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The values of the missing values in the triangle given are :

A.)

Using Trigonometry, the marked angle B can be related in the following ways:

Hypotenus = 9.43

Opposite = 5

Adjacent = 8

SinB = opposite / hypotenus = 5/9.43

CosB = Adjacent / Hypotenus = 8/9.43

TanB = opposite / Adjacent = 5/8

B.)

Angle A can be obtained using the relation :

CosA = Adjacent / Hypotenus

CosA = 47/61 = 0.770

A =

[tex] {cos}^{ - 1} (0.770)[/tex]

A = 39.6°

Hence, A = 39.6° to the nearest degree.

C.)

Using Trigonometry, the length of side x :

Tan D = opposite / Adjacent

Tan28 = 21/x

0.5317 = 21/x

x = 21/0.5317

x = 39.5 mm

Therefore, the value of x is 39.5mm

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The mean of the test is 20.

To determine the mean of the test, we need to use the information provided about the scores falling above the mean in terms of standard deviations.

Let's denote the mean of the test as μ, and the standard deviation as σ.

We are given that a score of 29 falls three standard deviations above the mean, so we can write this as:

29 = μ + 3σ

Similarly, we are told that a score of 23 falls one standard deviation above the mean, which can be expressed as:

23 = μ + σ

Now we have a system of two equations with two variables (μ and σ). We can solve this system of equations to find the values of μ and σ.

From the second equation, we can isolate μ:

μ = 23 - σ

Substituting this value into the first equation, we have:

29 = (23 - σ) + 3σ

Simplifying the equation, we get:

29 = 23 + 2σ

2σ = 29 - 23

2σ = 6

σ = 3

Substituting the value of σ back into the second equation, we find:

μ = 23 - 3

μ = 20

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The z-statistic test was conducted to determine the Deviation of RPM, ASM, and LF from the mean. The test indicates that RPM, ASM, and LF significantly deviate from the mean.

Report on the Analysis of American Airlines (Domestic) PerformanceThe quantitative analysis focused on three variables- load factors, revenue passenger miles, and available seat miles for American Airlines.

The Bureau of Transportation Statistics data for domestic flights from January 2006 to December 2012 was retrieved for the analysis. The quantitative analysis also focused on finding critical statistical values like mean, median, mode, standard deviation, variance, and minimum/maximum variables. The results of the data are summarized in Table 2. Revenue Passenger Miles (RPM) mean is 6,624,897, the median is 6,522,230, and mode is NONE. The minimum is 5,208,159 and the maximum is 8,277,155. The standard deviation is 720,158.571, and the variance is 518,628,367,282.42.

Load Factors (LF) mean is 82.934, the median is 83.355, and mode is 84.56. The minimum is 74.91, and the maximum is 89.94. The standard deviation is 3.972, and the variance is 15.762. The Available Seat Miles (ASM) mean is 7,984,735, the median is 7,753,372, and mode is NONE. The minimum is 6,734,620, and the maximum is 9,424,489. The standard deviation is 744,469.8849, and the variance is 554,235,409,510.06.Figure 1 above displays the performance of American Airlines (Domestic).

The mean RPM is 7,984,735, and the linear regression line is y = 50584x - 2.53E+8. The linear regression line indicates a positive relationship between RPM and year, with a coefficient of determination, R² = 0.6806. A coefficient of determination indicates the proportion of the variance in the dependent variable that is predictable from the independent variable. Therefore, 68.06% of the variance in RPM is predictable from the year. A one-way ANOVA analysis of variance test was conducted to determine the equality of means of three groups of variables; RPM, ASM, and LF. The null hypothesis is that the means of RPM, ASM, and LF are equal.

The alternative hypothesis is that the means of RPM, ASM, and LF are not equal. The level of significance is 0.05. The ANOVA results indicate that there is a significant difference in means of RPM, ASM, and LF (F = 17335.276, p < 0.05). Furthermore, a post-hoc Tukey's test was conducted to determine which variable means differ significantly. The test indicates that RPM, ASM, and LF means differ significantly.

The skewness test was conducted to determine the symmetry of the distribution of RPM, ASM, and LF. The test indicates that the distribution of RPM, ASM, and LF is not symmetrical (Skewness > 0).

Additionally, the z-statistic test was conducted to determine the deviation of RPM, ASM, and LF from the mean. The test indicates that RPM, ASM, and LF significantly deviate from the mean.

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Answer:

A. 6/8

Step-by-step explanation:

6/8 can be simplified to 3/4 when you divide both the numerator and the denominator by 2.

6/2=3 and 8/2=4

6/8=3/4

To double-check, you can simply divide the numerator by the denominator to see if you get the same answer of 0.75 (in this case).

Kevin takes to complete the remaining work alone:

3 + 1 = 4 days in total.

Let's calculate the rates at which Kevin and David can paint the house individually.

Kevin's rate of work is 1/6 of the house per day (since he can complete the house in 6 days), and David's rate is 1/9 of the house per day (since he can complete the house in 9 days).

When they work together for 3 days, their combined rate is:

(1/6 + 1/9) of the house per day = 5/18 of the house per day.

In 3 days, they complete:

3 * (5/18) = 5/6 of the house.

The remaining work is 1 - (5/6) = 1/6 of the house.

Now, since Kevin is completing the remaining work alone, his rate is 1/6 of the house per day.

To determine how many days it takes for Kevin to complete the remaining work, we divide the remaining work (1/6) by Kevin's rate (1/6):

(1/6) / (1/6) = 1 day.

Therefore, it will take Kevin 1 additional day to complete the remaining work alone.

The total number of days taken to paint the house is the initial 3 days they worked together plus the additional day Kevin takes to complete the remaining work alone:

3 + 1 = 4 days in total.

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Answer:

how do you find the measure of an angle? Using a Protractor The best way to measure an angle is to use a protractor. To do this, you'll start by lining up one ray along the 0-degree line on the protractor. Then, line up the vertex with the midpoint of the protractor. Follow the second ray to determine the angle's measurement to the nearest degree.

Step-by-step explanation:

Answer: A sphere and a cylinder have the same radius and height. The volume of the cylinder is 50 feet cubed. A cylinder with height h and radius r. A cylinder with height h and radius r. What is the volume of the sphere? Start Fraction 50 Over 3 End Fraction feet cubed Start Fraction 100 Over 3 End Fraction feet cubed 75 feet cubed 100 feet cubed

Step-by-step explanation: Because first you need to find the radius and height, Next you will have to find the volume of both, We know h= height and r=radius, so then you plug everything in.

The expression given of 1 / 7 ⁻ ² can be simplified, based on simplification rules, to be the value of 49.

Remember that any number with a negative exponent is equivalent to 1 divided by that number raised to the positive of that exponent. In other words, [tex]a^{(-n) }= 1/(a^n)[/tex].

Therefore, in this case, 7 ⁻ ² is equal to 1/(7  ²).

Substitute this into the expression:

1 / ( 7  ²  ) = 1 / ( 1 / ( 7  ²) )

Because the denominator is a fraction, this expression simplifies to just the denominator of that fraction:

1 / (1 / ( 7  ²) ) = 7 ²

= 49

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Answer:

The middle

The length of AC is [tex]4\sqrt(2)[/tex].

Create a diagram using the information provided.

As per the diagram, give the points and circles names.

Find the lengths of AD, AE, and EC using the provided information.

Use the Pythagorean Theorem to calculate the length of AC.

The following diagram displays the details:

Diagram illustrating the points at which two circles with radii of 10 and 6 cross.

A common tangent, which connects the two circles, runs through the larger circle at point D and the smaller circle at point E.

Stretched to point C, where it intersects the larger circle, is the line segment DE.

The following equations can be used to determine the lengths of AD, AE, and EC:

AD = 10 - 6 = 4

AE = 6 - 6 = 0 EC = 10 - 6 = 4

[tex]AC = \sqrt(32) = 4\sqrt(2)[/tex]

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Note: The complete question is- A larger circle with radius 10 and a smaller circle with radius 6 intersect each other at two points. A common tangent of the two circles is drawn, which intersects the larger circle at point D and the smaller circle at point E. The line segment DE is extended to intersect the larger circle at point C. Find the length of AC.

Answer: [tex]-8.42*10^{11}[/tex]

Answer:

-8.422 × 10^11

Step-by-step explanation

for −842,200,000,000 × 10, move the decimal until the whole number left is between 1-10. You moved the decimal 11 times to the left, so you put 10 to the power of 11.

Answer:

the answer is D. F(x) = 1/x(x-3)

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

mean = ( 3 + 2 + 0 + 1 + 0 + 2 + 3 + 4 + 1 + 2 + 2 + 1 ) / 12

mean = 21 / 2

mean = 1.75

mean = 2