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Answer:

The speed of the 8-ball is 2.125 m/s after the collision.

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of masses is conserved unless an external force is applied. The momentum of a body with mass m and velocity v is calculated as follows:

P=mv

If we have a system of masses, then the total momentum is the sum of all the individual momentums:

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

When a collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum is simplified to:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.

After the collision, the cue ball comes to rest v2'=0. It's required to find the final speed v1' after the collision.

The above equation is solved for v1':

[tex]\displaystyle v'_1=\frac{m_1v_1+m_2v_2-m_2v'_2}{m_1}[/tex]

[tex]\displaystyle v'_1=\frac{0.16*0+0.17*2-0.17*0}{0.16}[/tex]

[tex]\displaystyle v'_1=\frac{0.34}{0.16}[/tex]

[tex]v'_1=2.125\ m/s[/tex]

The speed of the 8-ball is 2.125 m/s after the collision.

Answer:

Explanation:

Using the formula for heart capacity;

Q = mcΔt

m is the mass = 150g = 0.15kg

initial temperature = 22°C

Quantity of heat = 3240J = 3.24kJ

specific heat capacity of ethanol = 2.57 [kJ/kg K]

Substitute and get the final temperature

3.240 = 0.15(2.57)(T - 22)

3.240 = 0.3855(T-22)

3.240/0.3855 = T - 22

8.405 = T - 22

T = 22+8.405

T = 30.405°C

Hence the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol is 30.405°C

Answer:i think it's d

Explanation:

Answer:

1) 800m/s

2) 2 seconds

Explanation:

Acceleration= velocity/time

Where acceleration= 0.5 m/s²

Time= 1.6kms= 1.6×10^3 seconds

If we substitute we have

0.5=v/(1.6×10^3)

V=800m/s

the final velociety of the car is 800m/s

Velocity= distance/time

800= (1.6×10^3)/ time

Time= 1.6×10^3/800

=2 seconds

Hence the time it will take to cover is 2seconds

Answer:         Radio waves have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation. In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

Explanation:

Answer:

3.626 m/s

Explanation:

v=d/t

1. -0.02/0 = 0 m/s

2. 0.86/0.2 = 4.3 m/s

3. 1.71/0.4 = 4.275 m/s

4. 2.54/0.6 = 4.23 m/s

5. 3.32/0.8 = 4.15 m/s

6. 4.08/1.0 = 4.08 m/s

7. 4.79/1.2 = 3.99 m/s

8. 5.48/1.4 = 3.91 m/s

9. 6.15/1.6 = 3.84 m/s

10. 6.76/1.8 = 3.76 m/s

11. 7.37/2.0 = 3.66 m/s

12. 7.92/2.2 = 3.6 m/s

13. 8.45/2.4 = 3.52 m/s

14. 8.96/2.6 = 3.45 m/s

the mean of these numbers is 3.626

his average velocity ks 3.626 m/s

Answer: I think its True

Answer: 321.027 m/s

Explanation:

First let´s analyze the vertical problem:

Always when an object is above the ground and nothing is holding it (like the bullet after being fired) the gravitational force will start acting on it.

Then the vertical acceleration of the bullet will be the gravitational acceleration, we can write this as:

a(t) = -g

Where g = 9.8m/s^2

and the negative sign is because this acceleration pulls the bullet downwards.

To get the vertical velocity we need to integrate over time, this will lead to:

v(t) = (-9.8m/s^2)*t + v0

where v0 is the initial vertical velocity, as the bullet is fired horizontally, there is no initial vertical velocity, then we have v0 = 0m/s

And the velocity equation is:

v(t) = (-9.8m/s^2)*t

Now for the vertical position, we need to integrate again, to get:

p(t)  =(1/2)*(-9.8m/s^2)*t^2 + p0

Where p0 is the initial vertical position, in this case, is 1.9 meters above the ground, then p0 = 1.9m

And the vertical position equation will be:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + 1.9 m

Now we want to find the time such that the vertical position is equal to zero, this will mean that the bullet it the ground.

p(t) = 0m = (1/2)*(-9.8m/s^2)*t^2 + 1.9 m

    (1/2)*(9.8m/s^2)*t^2 = 1.9m

    (4.9m/s^2)*t^2 = 1.9m

                  t = √(1.9m/(4.9m/s^2)) = 0.623 seconds.

This means that the bullet will travel for 0.623 seconds before hitting the ground.

Now we also can ignore the air friction for the horizontal motion, then we can assume that the horizontal speed does not change.

Then we can use the relationship:

Distance = speed*time

We know that:

time = 0.623 seconds

distance = 200m

now we can replace that in the equation to find the horizontal speed.

200m = speed*0.623s

200m/0.623s = speed = 321.027 m/s

Responda:

1 metro

Explicação:

Dado que :

Tempo de reação = 0,2 segundos

Velocidade de deslocamento = 5 m / s

A distância percorrida antes da frenagem pode ser obtida usando a relação:

Distância = velocidade de viagem * tempo de reação

Distância percorrida antes da frenagem = (5 m / s) * (0,2s)

Distância percorrida antes da frenagem = 1 metro

Answer:

t = 0.75 seconds

Explanation:

Given that,

The initial speed of a ball, u = 7.5 m/s

We need to find the time taken by the ball to reach the maximum height. Let t is the time taken.

At maximum height, its final speed, v = 0 and it will move under the action of gravity.

Using the equation of motion to find t.

[tex]v=u+at[/tex]

Use a = -g

[tex]v=u-gt\\\\t=\dfrac{u}{g}\\\\t=\dfrac{7.5}{10}\\\\t=0.75\ s[/tex]

Hence, the ball will take 0.75 seconds to reach the maximum height.

Answer:

They carry out essential functions that are necessary for the survival of cells – harvesting energy, making new proteins, getting rid of waste. Hope this helps!

Explanation:

I organelles is a specialized subunits with a specific cell, their general function is to store genetic information

Newton's Third Law of Motion states "To every action, there is an equal and opposite reaction; action and reaction forces act on different bodies".

Explanation:

The mass of the object is 370N / (9.81N/kg) = 37.7kg.

Answer:

f

Explanation:

Answer:

7.87x10^5m/s^2

Explanation:

Note that when the ball is in the air, the only force acting on it is the downward pull of gravity, so the force of the swing is a red herring.

The ball hits the ground at the same height from which it was hit, so its final velocity will have the same magnitude of 49 m/s, but pointing at an angle of 35° below the horizontal.

Answer:

Power = 5.88 Watt

Explanation:

Mechanical Work and Power

Mechanical work is the amount of energy transferred by a force. Its SI unit is the joule.

Being  the force vector and  the displacement vector, the work is calculated as:

[tex]W=\vec F\cdot \vec s[/tex]

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

[tex]W=F.s[/tex]

Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.

The power can be calculated as:

[tex]\displaystyle P=\frac {W}{t}[/tex]

Where W is the work and t is the time.

The m=100 Kg man goes up a distance of s=3 cm = 0.03 m in t=5 seconds. To calculate the work done against gravity the weight is considered as the force:

F = m.g = 100*9.8

F = 980 N

The work is:

W = 980*0.03

W = 29.4 J

Finally, the power is:

[tex]\displaystyle P=\frac {W}{t}[/tex]

[tex]\displaystyle P=\frac {29.4}{5}[/tex]

P = 5.88 Watt

Newton's first and second laws of motion both do, but I think the one you're looking for is: The First Law of Motion.  That description is a little more direct.

It says that if an object is not acted on by a net external force, then it continues in "constant, uniform motion".

The net force on the block acting perpendicular to the incline is

∑ F = n - w cos(29.4°) = 0

where n is the magnitude of the normal force and w = m g is the weight of the block.

The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.

Solve for n :

n = m g cos(29.4°)

n = (6 kg) (9.80 m/s²) cos(29.4°)

n ≈ 51.2 N

Answer:

evaporative crystallization

cooling crystallization from solution or the melt

Answer:

I think this may helps you

Answer:

4s

Explanation:

My assumption would be 4s since 25 going into 100 would be 4? hope that helped..

Answer:

Concept: Physical Constants

The difference between Length and Time is: Length is a measure of distance while Time is a quantity or measure of period.

Length can defined as a fundamental quantity that describe the total space occupied by an object from end to end or the distance of an object from end to end.

Time can be defined the duration of an occurrence in space. Time is so important as it helps us adequately know the period of an event or occurrence.

In conclusion, The difference between Length and Time is: Length is a measure of distance while Time is a quantity or measure of period.

Learn more about Length : https://brainly.com/question/2217700

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Answer:

I think it is 10 Hz

Explanation:

Sorry if it's wrong

Answer:

C , Friction

Explanation:

Answer:

We multiply [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex] by the amount of mole to change units to cubic meters.

Explanation:

Let [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex], we change the unit to cubic meters by multiplying this number by the amount of moles of the sample. For instance, let [tex]n = 1\,mol[/tex], then the obtain the following result:

[tex]m = x\cdot n[/tex] (1)

[tex]m = \left(23.78\times 10^{-6}\,\frac{m^{3}}{mol} \right)\cdot (1\,mol)[/tex]

[tex]m = 23.78\times 10^{-6}\,m^{3}[/tex]

Answer:

B

Explanation:

Answer:

B

Explanation:

Answer:

v₂ = 93.33 [m/s]

Explanation:

In order to solve this problem, we must apply the definition of momentum and amount of movement, which can be calculated by means of the following expression.

[tex]P=m*v[/tex]

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

The amount of movement before and after the impact should be analyzed.

[tex](m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the ball = 0.045 [kg]

v₁ = velocity of the ball before the hit = 0

Imp₁₋₂ = Impulse [kg*m/s]

v₂ = velocity after the hit [m/s]

[tex](0.045*0)+4.2=(0.045*v_{2})\\4.2 = 0.045*v_{2}\\v_{2}= 93.33 [m/s][/tex]