Which statement is true about the equation (see picture)
A. It has no solution.
B. It has one solution.
C. It has two solutions.
D. It has infinitely many solutions.

Which Statement Is True About The Equation (see Picture) A. It Has No Solution.B. It Has One Solution.C.

Answers

Answer 1
Simplify
2/4z + 1 = 2/4z + 1
Answer: D. Infinite solutions
Answer 2

Answer:

D would be your answer

Step-by-step explanation:

Simplify :)


Related Questions

three times a number, less 4 is
2

Answers

Answer:

2

Step-by-step explanation:

can anyone help me please? thanks ^^

Answers

Answer:

Yes; they are congruent

SSS

Step-by-step explanation:

Here, we want to check if the given triangles are congruent

From what we have, we can see that all three sides are marked for both triangles

So the sides of the triangles are income

So therefore, the triangles are congruent by SSS

Please answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!

Answers

Answer:

146

Step-by-step explanation:

please answer (NOT A MULTIPLE CHOICE ANSWER)

In ΔOPQ, \text{m}\angle O = (6x-14)^{\circ}m∠O=(6x−14) ∘ , \text{m}\angle P =(2x+16)^{\circ}m∠P=(2x+16) ∘ , and \text{m}\angle Q = (2x+8)^{\circ}m∠Q=(2x+8) ∘ . Find \text{m}\angle Q.m∠Q.

Answers

Answer:

you are incorrect it is actually 107 degrees

Step-by-step explanation:

help me with this and ill give you brainliest

Answers

Answer:

C

Step-by-step explanation:

Trust me on this one

In ΔPQR, \overline{PR} PR is extended through point R to point S, \text{m}\angle QRS = (4x-15)^{\circ}m∠QRS=(4x−15) ∘ , \text{m}\angle RPQ = (x+1)^{\circ}m∠RPQ=(x+1) ∘ , and \text{m}\angle PQR = (x-2)^{\circ}m∠PQR=(x−2) ∘ . Find \text{m}\angle RPQ.m∠RPQ.

Answers

Answer:

Step-by-step explanation:

Notice that, the angle QRS is external to the triangle and adjacent to the angle PRQ. According to the theorem of a external/adjacent angle, we have: m∠QRS = m∠PQR + m∠RPQ, where PQR and RPQ are internal angles.

From the hypothesis, we have:

m∠QRS =(10x−12)∘(10x−12)

m∠PQR = (3x+20)∘(3x+20)

m∠RPQ=(3x−8)∘(3x−8)

Using the first equation and replacing the hypothesis:

m∠QRS = m∠PQR + m∠RPQ

(10x−12)∘(10x−12) = (3x+20)∘(3x+20) + (3x−8)∘(3x−8)

Multiplying and applying the remarkable identity:

Then, we use a calculator to find the roots, which are:

In this case, we will see what root is the right one.

Now, we replace it into m∠QRS =(10x−12)∘(10x−12), because we need to find m∠QRS.

m∠QRS =(10x−12)∘(10x−12) = (10(4.7) - 12) (10(4.7) - 12) = (35) (35) = 1225

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

if you are doing deltamath

BRAINEST IF YOU GET THSI RIGHT

Answers

Solution :

[tex] \sf \dfrac{6x+4}{3} = \dfrac{5x-5}{8}[/tex]

By cross multiply, we get

[tex] \sf : \implies (6x+4) \times 8 = (5x-5) \times 3[/tex]

[tex] \sf : \implies 48x+32 = 15x-15[/tex]

[tex] \sf : \implies 48x+32 - 15x + 15= 0[/tex]

[tex] \sf : \implies 33x + 47 = 0[/tex]

[tex] \sf : \implies 33x = -47[/tex]

[tex] \sf : \implies x = \dfrac{- 47}{33}[/tex]

Therefore, answer is [tex] \sf x = \dfrac{- 47}{33}[/tex]

ANSWER:

x=-47/33

EXPLANATION:

[tex]\frac{6x+4}{3} =\frac{5x-5}{8} \\\\24(\frac{6x+4}{3} =\frac{5x-5}{8})\\\\48x+32=15x-15\\\\48x+32-32=15x-15-32\\\\48x-15x=-47+15x-15x\\\\33x=-47\\\\x=-\frac{47}{33}x[/tex]

What is the slope of the line?​

Answers

Answer:

Slope = 3/4

Step-by-step explanation:

sorry it’s late. Pls give brainliest.

A drama club made $3,200 from a school play. Seventy-five percent of that amount came from ticket sales. Identify the values of the variables in the model. Then use the model to find the amount of ticket sales.

a =
b =
The amount of ticket sales is $
.

Answers

Answer: $2400

Step-by-step explanation:

Based on the question above, a will be the percentage of tickets that were sold while b will be tickwt sales. Therefore,

a = 75%

b = 75% × $3,200

= 0.75 × $3200.

= $2400

Based on the information above, the amount of tickets sales is $2400

what is the area of 20 and 15

Answers

300 is your answer remember area is l•w
300 areas, length times width

12 out of 52 cards in a deck are face cards. What percentage of cards in a deck are face cards, to the nearest whole percent?

Answers

its too late but 23.08 so I'm sorry I took so long

a) Which of these numbers is 8 less than -15?
7
-7
23
-23
A
B
с
D

Answers

-7 the answer is -7 yes

Answer:

-7

Step-by-step explanation:

y because i know so

all you need is in the photo
answer fast
please ​

Answers

Answer: c

Step-by-step explanation:

Answer:

The answer is C

Step-by-step explanation:

Find the value of x round to the nearest tenth FIRST ANSWER GETS BRAINIEST

Answers

Answer: answer is 19.2

a squared + b squared = c2  

81 + 289 = 370

square root of 370 = 19.235

answer is 19.2

Answer:

Step-by-step explanation:

[tex]x = \sqrt{ {17}^{2} + {9}^{2} } = \sqrt{289 + 81} = \sqrt{370 } [/tex]=19.2

Given g(x) = 5x + 2, solve for x when g(x) = 7.

Answers

Answer: x = 1

Explanation:

g(x) = 5x + 2
g(x) = 7

=> 5x + 2 = 7
5x = 7 - 2
5x = 5
x = 5/5 = 1

What is the length of the line segment whose endpoints are (-1,5) and (3,-3)? Round your answer to the nearest tenth.

Answers

Answer:

4√5

Step-by-step explanation:

The length=√(3--1)²+(-3-5)²

l=√(4)²+(-8)²

l=√16+64

l=√80=4√5

PLS HELP !!
A computer normally sells for $520. During a sale, the computer is
discounted 15% off. How much will it cost to buy the computer during the
sale? (Sale Price)

Answers

Answer:

$442

Step-by-step explanation:

Multiply the sales price by the discount percentage. This is the total discount that was taken off.

$520 x 15% = $78.

Subtract the discount amount from the sales price. This gives you the amount that the computer costs after the discount.

$520 - $78 = $442

The computer costs $442.

The perimeter of the rectangular pool is 80 feet.The length of the pool is 10 feet more than twice of the width.Find the length and the width of the pool.Find the length and the width of the pool.

Answers

Width= 10
Length= 30

Explanation: photo

I WILL GIVE YOU BRAINLY PLSS

2.2x – 3.408 ≥ 29.504
A. x ≤ 12
B. x ≥ 12
C. x ≥ 14.96
D. x ≤ 14.96

PLSS SHOW YOUR WORK PLSS

Answers

Answer:

d

Step-by-step explanation:

The diagonals of rhombus ABCD intersect at E. Given that m∠CAD=20° and CE=4, find the m∠CDA.

Answers

Given :

The diagonals of rhombus ABCD intersect at E.

∠CAD = 20°.

To Find :

The angle ∠CDA.

Solution :

We know, diagonals of a rhombus bisects each other perpendicularly.

So, ∠DEA = 90°.

In triangle ΔEAD :

∠EAD + ∠AED + ∠EDA = 180°

20° + 90° + ∠EDA = 180°

∠EDA = 70°

Now, we know diagonal of rhombus also bisect the angle between two sides .

So, ∠CDA = 2∠EDA

∠CDA = 2×70°

∠CDA =140°

Therefore, ∠CDA is 140°.

In how many different ways can four students stand in a straight line if two of the students refuse to stand next to each other?

Answers

Hey there! I'm happy to help!

Let's look at each spot in the line from left to right and see how many choices they are.

In spot 1, we have 4 choices. Let's say that we choose the student who doesn't want to stand next to to the other student. This means that in the next slot, there are only 2 choices because he cannot stand by the other student. Now when we move to spot number three, there are only two choices left, and then there is 1.

4×2×2×1=16

So, there are 16 different ways the students can stand in a straight line if two of the students refuse to stand next to each other.

Have a wonderful day! :D

Answer:

16

Step-by-step explanation:

Type the correct answer in the box. Round your answer to the nearest integer.
B
D
30
35
А
с
In the figure, if m ZABD = 120°, then mZADC =
0.

Answers

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

[tex]\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}[/tex]

[tex]\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}[/tex]

sin(∠ADB) = [tex]\frac{30\text{sin}(120)}{35}[/tex]

                 = 0.74231

m∠ADB = [tex]\text{sin}^{-1}(0.74231)[/tex]

             = 47.92°

             ≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

The perimeter of a circular garden is 440m. A path 1.4m runs inside the park. find the cost of gravelling the path at the rate of Rs.100 per square meter.​

Answers

Answer:

Cost = Rs. 6095.95

Step-by-step explanation:

We are given the perimeter as 440m.

Mow,perimeter of a circle is also called circumference.

Formula for circumference of a circle is;

C = 2πR

Thus:

2πR = 440

R = 440/2π

R = 70 m

We are told that A path 1.4m runs inside the park. Thus radius of smaller circle: r = 70 - 1.4 = 68.6 m

Area of larger circle: A1 = πR² = π(70²)

A1 = 4900π

Area of smaller circle: A2 = πr² = π(68.6²)

A2 = 4705.96π

Area of path = A1 - A2

Area of path = 4900π - 4705.96π

Area of path = 194.04π Sq.m

We want to find the cost of gravelling the path at the rate of Rs.100 per square meter.

Thus;

Cost = 100 × 194.04π

Cost = Rs. 6095.95

what expression is equivalent to 5 to the -3rd power

Answers

Answer: 1/125

Step-by-step explanation:

Flip the exponent over into a fraction if it is to the negative power. Then do the same as you usually would to find out that it is 5^3 under a fraction.

Answer:

0.008

Step-by-step explanation:

that is what the internet said

-3 |-2•4 | =





.........

Answers

Answer:

-24

Step-by-step explanation:

PLEASE HELP WILL AWARD BRAINLIEST TO BEST ANSWER!!!

Answers

Answer:

See below

Step-by-step explanation:

[tex] In\: \triangle AKL, \:\\ AK = 9,\: \\m\angle K = 90\degree, \: \\m\angle A= 60\degree \\

\therefore m\angle L = 30\degree\\

By \:30°-60°-90° \:\triangle \:theorem:\\

AK = \frac{1}{2} \times AL\\(SIDE\: OPPOSITE \:TO \:30\degree) \\\\

9 = \frac{1}{2} \times AL\\\\

AL = 9\times 2\\\\

\huge\red{AL = 18}\\\\

KL = \frac{\sqrt 3}{2} \times AL\\(SIDE\: OPPOSITE \:TO \:60\degree) \\\\

KL = \frac{\sqrt 3}{2}\times 18\\\\

KL = 9\times \sqrt 3\\\\

\huge\purple{KL = 9\sqrt 3}\\\\

P(\triangle AKL) = AK + KL + AL\\

P(\triangle AKL)= 9 + 9\sqrt 3+18\\

\huge\orange{P(\triangle AKL)=(27 + 9\sqrt 3) \: units} \\\\

A(\triangle AKL) = \frac{1}{2} \times KL\times AK\\

A(\triangle AKL) = \frac{1}{2} \times 9\sqrt 3\times 9\\

A(\triangle AKL) = \frac{81\sqrt 3}{2} \\

\huge\pink{A(\triangle AKL) = 40.5\sqrt 3\: units^2} [/tex]

Question 12 (1 point)
If linel is parallel to line m, solve for x and name the angle relationship:
(9x - 33)
(5x + 3)

Answers

it’s b
solve :
9x - 33 = 5x + 3
-5x -5x
4x - 33 + 3
+ 3 -3
4x = 36
/4 /4 (divided by 4)

x = 9

Which value should she use for X? Round to the nearest hundredth.
0.09
0.20
0.25
0.30

Answers

Answer:

A

Step-by-step explanation:

Just took the Semester exam and had this question on it, I got it right

Answer:Person on top is wrong its

Step-by-step explanation:

D =0.30

Marion is twice as old as judy. Six years agot Marion was three times as old as judy was then. Find the age of each girl now.

Pls show work, I will give brainliest

Answers

9514 1404 393

Answer:

  Marion is 24, Judy is 12

Step-by-step explanation:

Let j represent Judy's age now. 6 year ago, the relation was ...

  3(j -6) = (2j) -6

  3j -18 = 2j -6 . . . . . eliminate parentheses

  j = 12 . . . . . . . . . . . add 18-2j

  2j = 24 . . . . . . . . . Marion's age now

Judy is 12; Marion is 24.

Aisha is a cyclist. She rode 3 ¾ miles in ⅓ hours. A. How fast was she going in miles per hour?

Answers

Answer:

11 1/4 miles per hour

Step-by-step explanation:

Put the mixed number in improper form to make it easier. You get 15/4 miles in 1/3 hours. You want the miles for 1 hour. So you multiply 15/4 miles by 3 to get 45/4 miles, or 11 1/4 miles per hour

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