which type of severe weather is related to high pressure systems?
A.Hurricane
B.Heat Wave
C.Tornado
D.Thunderstorm

Answer:

yeah they're both balanced out

Answer:

F4

Explanation:

Friction is a force that opposes motion

Answer:

CaSO₃·2H₂O

Explanation:

Empirically => CaSO₃·nH₂O

%H₂O = n(H₂O)/f.wt. x 100%

23.1% = n(H₂O)100/Ca + S +3O + nH₂O

23.1 = n(18)·100/[40 + 32 + 3(16) + n(18)]

1800n = 23.1[40 + 32 + 3(16) + n(18)]

1800n = 924 + 739.2 + 1108.8 + 415.8n

1800n - 415.8n = 924 + 739.2 + 1108.8

1385n = 2772

n = 2772/1385 = 2

∴ numerical formula => CaSO₃·2H₂O

Answer:

Answer is shown on the paper :D

Explanation:

Remember to follow sig-figs.

Answer:

H2CO

Explanation:

Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

Given data:

Volume of N₂ = 200 dm³

Pressure and temperature = standard

Volume of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂     →      2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

n = 8.9 mol

Now we will compare the moles of ammonia and nitrogen.

               N₂          :         NH₃

                1            :           2

              8.9          :        2/1×8.9 = 17.8 mol

Volume of ammonia:

1 mole of any gas occupy 22.4 dm³ volume

17.8 mol ×22.4 dm³/1 mol = 398.7 dm³

Answer:

yes its c

Explanation:

Answer:

carbon dioxide and water.

Explanation:

Chemical equation:

2C₂H₆ + 7O₂      →    4CO₂ + 6H₂O

Reactants are present on the left side of chemical equation while products are present on the right side of chemical equation. In given chemical equation ethane and oxygen are reactant while carbon dioxide and water are product.

The given reaction is combustion reaction. Ethane is burnt in the presence of oxygen and produces carbon dioxide and water.

The reaction also follow the law of conservation of mass.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Answer:

Milk's heavy

Explanation:

Answer:

heat wave

Explanation:

A high pressure system is a whirling mass of cool, dry air that generally brings fair weather and light winds. When viewed from above, winds spiral out of a high-pressure center in a clockwise rotation in the Northern Hemisphere.

Answer:

0.98 M

Explanation:

Given data:

Mass of sugar = 20 g

Mass of water = 59 g

Concentration of solution = ?

Solution:

1 g = 0.01 L

59 g× 0.01 L/1 g

0.059 L

Concentration formula:

C = m/v

m = moles of solute

v = volume of solution

Number of moles of sugar:

Number of moles = mass/molar mass

Number of moles = 20 g/ 342.3 g/mol

Number of moles = 0.058 mol

Now we will calculate the concentration:

C = 0.058 mol/0.059 L

C = 0.98 mol/L

C = 0.98 M

Answer:

The philosophical view of man implies that we are moral as well as intelligence beings. It provides the framework to discover the nature of human excellence embodied by the perennial virtues towards which all men of good will tend.

Answer:

The answer of 1×10 -8 is 2

Answer:

six electrons

Explanation:

The six electrons in the outermost shell allow selenium to have a variety of valence numbers. Selenium compounds have been found that have valences of -2, 4, and 6. Speaking of the number six, selenium is found to have six naturally occurring isotopes.

Answer:

0.8333 L. P1v1=p2v2

Explanation:

I dont now if this is wht you were looking for so srry

The pressure of the gas at which the final volume of the gas has been 3 L has been 0.833 atm.

The gas has been assumed to be at constant temperature. The change in the pressure and volume of gas at constant temperature can be given by:

Initial pressure × Initial volume = Final pressure × Final volume

The initial pressure of gas has been 0.5 atm, and the initial volume has been 5L. The increased volume or final volume of the system has been 3 L.

The final pressure of the gas has been given by:

0.5 atm × 5 L = 3 L × Final pressure

Final pressure = 0.833 atm.

The pressure of the gas at which the final volume of the gas has been 3 L has been 0.833 atm.

For more information about the pressure of the gas, refer to the link:

https://brainly.com/question/6534127

Answer:

D) will not form any stereoisomers since the product is a saturated hydrocarbon.

Explanation:

Stereoisomerism, or spatial isomerism,refers to a type of isomerism in which  two or more molecules have the same molecular formula and atom to atom connectivity but different three-dimensional orientations of those atoms in space.

Stereoisomerism occurs in alkenes because free rotation about the C=C bond is hindered. Thus, the molecule is "locked" in a particular orientation. In a saturated alkane, there is unrestricted free rotation about the C-C bond hence straight chain alkanes do not have steroisomers.

The product formed is 3,4-dimethyl hexane which is a straight chain saturated alkane. This compound does not exhibit stereoisomerism.

Explanation:

a. Write the molecular formula of the compound.

Acetaminophen contains 8 carbon atoms, 9 Hydrogen atoms, 1 Nitrogen atom and 2 Oxygen atoms.

The molecular formular is given as;  C8H9NO2

b. What is the hybridization state of each C, N, and O atom?

From the image attached;

All the carbon atoms in the benzene ring has hybridization of sp2.

The carbon that is doubly bonded (carbonyl) to the oxygen has hybridization of sp2

The last carbon to the right has hybridization of sp3

The hybridization of nitrogen in the compound is sp3 hbridized.

Oxygen atom in alcohol  is sp3 hybridised

Oxgen in the carbonyl group is sp2 hybridized.

Answer:

The correct answer is 0.3582 M.

Explanation:

Based on the given information, the volume of KOH given is 19.55 ml, the volume of sulfuric acid given is 20.20 ml, and the molarity of sulfuric acid is 0.3467 M. There is a need to find the molarity of KOH.

The formula to use in the given case is,

M1V1 = M2V2

Here M1 is the molarity of KOH, V1 is the volume of KOH, M2 is the molarity of sulfuric acid, and V2 is the volume of H2SO4.

Here V1 is 19.55 ml, M2 is 0.3467 M, and V2 is 2020 ml.

Now putting the values in the equation we get,

M1 * 19.55 = 0.3467 * 20.20

M1 * 19.55 = 7.00334

M1 = 7.00334/19.55

M1 = 0.3582 M

Hence, the molarity of the given KOH is 0.3582.

The molarity of a solution of potassium hydroxide is 0.3582M

To get the molarity of the solution of potassium hydroxide KOH, we will apply the formula;

[tex]C_1V_1=C_2V_2[/tex]

Given the following parameters;

C₂ = 0.3467M

V₂ = 20.20mL

V₁ = 19.55mL

C₁ = ?

Substitute the given parameters into the formula:

C₁ × 19.55 = 0.3467× 20.20

C₁ × 19.55 = 7.00334

C₁ = 7.00334/19.55

C₁ = 0.3582M

Hence the molarity of a solution of potassium hydroxide is 0.3582M

Learn more on molarity here: https://brainly.com/question/19555927

Answer:

10.9 * 10^-7 m

Explanation:

We know that the Rydberg constant (R) is – 13.6 eV = -2.18 * 10^-18 J

ΔE= -R(1/nf - 1/ni)

Where;

nf = final state

ni= initial state

ΔE=  -2.18 * 10^-18(1/3 - 1/4)

ΔE= -2.18 * 10^-18(1/12)

ΔE= -1.81 * 10^-19 J

From;

ΔE=hc/λ

h = plank's constant = 6.6 * 10^-34 Js

c = 3 * 10^8 ms-1

λ = ?

λ = hc/ΔE

λ = 6.6 * 10^-34 * 3 * 10^8/ 1.81 * 10^-19

λ = 10.9 * 10^-7 m

Answer:

Peer-reviewed Journal Article

Explanation:

1.Dictionary

2.Encyclopidia

3.Internet Search Engine

4.Peer-reviewed Journal Article

The correct answer as to which would be most useful in trying to obtain procedural information to replicate an experiment previously published would be a peer-reviewed journal article.

A peer-reviewed journal article is a journal article written by an expert or experts on a particular topic and has undergone thorough reviews by experts in the same field and certified to be of good-enough standards to be published.

Such an article would contain all the necessary information relating to the experiment leading to the article. Hence, in order to obtain procedural information to replicate an experiment that has been previously published, a peer-reviewed journal published on the same topic would do be the right place to seek.

Answer:

atoms

Explanation:

atoms combines to form compound

Explanation:

A) Highest occupied energy level and Group Number.

Answer:

True

Explanation:

Methylcyclohexane has a cyclic compound of 7 carbons false classified as Saturated Hydrocarbon.

Answer:

120N

Explanation:

Answer:

3

Explanation:

Load / Effort

The effort is 30N and the Load is 90N.

So the MA is equal to 90/30 = 3

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 2.01 × 3.77 = 7.5777

We have the final answer as

Hope this helps you

Answer:

0.085 moles of  N₂O₅ are needed

Explanation:

Given data:

Mass of NO₂ produces = 7.90 g

Moles of N₂O₅ needed = ?

Solution:

2N₂O₅       →     4NO₂  + O₂

Number of moles of NO₂ produced :

Number of moles = mass/ molar mass

Number of moles = 7.90 g/ 46 g/mol

Number of moles = 0.17 mol

now we will compare the moles of NO₂   with N₂O₅.

                NO₂          :       N₂O₅

                  4            :          2

                0.17          :         2/4×0.17 = 0.085 mol

Thus, 0.085 moles of  N₂O₅ are needed.

Answer:

pfffft definitely 10. smh silly goose

"Ground squirrels eat nuts, leaves, roots, seeds, and other plants. They also catch and eat small animals, such as insects and caterpillars.Though they are terrific climbers, these squirrels do come to the ground in search of fare such as nuts, acorns, berries, and flowers. They also eat bark, eggs, or baby birds."

Answer:

Metals

Explanation:

Answer:

option b

Explanation:

Answer:

Approximately [tex]0.224\;\rm L[/tex], assuming that this reaction took place under standard temperature and pressure, and that [tex]\rm CO_2[/tex] behaves like an ideal gas. Also assume that the reaction went to completion.

Explanation:

The first step is to find out: which species is the limiting reactant?

Assume that [tex]\rm CaCO_3[/tex] is the limiting reactant. How many moles of [tex]\rm CO_2[/tex] would be produced?

Look up the relative atomic mass of [tex]\rm Ca[/tex], [tex]\rm C[/tex], and [tex]\rm O[/tex] on a modern periodic table:

Calculate the formula mass of [tex]\rm CaCO_3[/tex]:

[tex]\begin{aligned} & M(\rm CaCO_3) \\ &= 40.078 + 12.011 + 3 \times 15.999 \\&= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the number of moles of formula units in [tex]1\; \rm g[/tex] of [tex]\rm CaCO_3[/tex] using its formula mass:

[tex]\begin{aligned}& n(\mathrm{CaCO_3})\\&= \frac{m(\mathrm{CaCO_3})}{M(\mathrm{CaCO_3})} \\ &= \frac{1\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \approx 1.00\times 10^{-2}\; \rm mol\end{aligned}[/tex].

In the balanced chemical equation, the ratio between the coefficient of [tex]\rm CaCO_3[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{CaCO_3})} = 1[/tex].

In other words, for each mole of [tex]\rm CaCO_3[/tex] formula units consumed, one mole of [tex]\rm CO_2[/tex] would be produced.

If [tex]\rm CaCO_3[/tex] is indeed the limiting reactant, all that approximately [tex]1.00\times 10^{-2}\; \rm mol[/tex] of [tex]\rm CaCO_3\![/tex] formula would be consumed. That would produce approximately [tex]1.00\times 10^{-2}\; \rm mol\![/tex] of [tex]\rm CO_2[/tex].

On the other hand, assume that [tex]\rm HCl[/tex] is the limiting reactant.

Convert the volume of [tex]\rm HCl[/tex] to [tex]\rm dm^{3}[/tex] (so as to match the unit of concentration.)

[tex]\begin{aligned}&V(\mathrm{HCl})\\ &= 50\; \rm cm^{3} \\ &= 50\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{10^{3}\; \rm cm^{3}} \\ &= 5.00\times 10^{-2}\; \rm dm^{3} \end{aligned}[/tex].

Calculate the number of moles of [tex]\rm HCl[/tex] molecules in that [tex]5.00\times 10^{-2}\; \rm dm^{3}[/tex] of this [tex]\rm 0.05\; \rm mol \cdot dm^{-3}[/tex]

[tex]\begin{aligned}& n(\mathrm{HCl}) \\ &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.05\; \rm mol \cdot dm^{-3}\\ &\quad\quad \times 5.00\times 10^{-2}\;\rm dm^{3} \\ &= 2.50 \times 10^{-3}\; \rm mol\end{aligned}[/tex].

Notice that in the balanced chemical reaction, the ratio between the coefficient of [tex]\rm HCl[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{HCl})} = \frac{1}{2}[/tex].

In other words, each mole of [tex]\rm HCl[/tex] molecules consumed would produce only [tex]0.5\;\rm mol[/tex] of [tex]\rm CO_2[/tex] molecules.

Therefore, if [tex]\rm HCl[/tex] is the limiting reactant, that [tex]2.50 \times 10^{-3}\; \rm mol[/tex] of [tex]\rm HCl\![/tex] molecules would produce only one-half as many (that is, [tex]1.25\times 10^{-3}\; \rm mol[/tex]) of [tex]\rm CO_2[/tex] molecules.

If [tex]\rm CaCO_3[/tex] is the limiting reactant, [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. However, if [tex]\rm HCl[/tex] is the limiting reactant, [tex]1.25\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be produced.

In reality, no more than [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. The reason is that all [tex]\rm CaCO_3[/tex] would have been consumed before [tex]\rm HCl[/tex] was.

After finding the limiting reactant, approximate the volume of the [tex]\rm CO_2\![/tex] produced.

Assume that this reaction took place under standard temperature and pressure (STP.) Under STP, the volume of one mole of ideal gas molecules would be approximately [tex]22.4\; \rm L[/tex].

If [tex]\rm CO_2[/tex] behaves like an ideal gas, the volume of that [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be approximately [tex]\rm 1.00\times 10^{-3}\; \rm mol \times 22.4\; \rm L = 0.224\; \rm L[/tex].