Physics College

You check in at the airport and have your luggage weighed. It comes to 25kg. The airport is at sea level and you take off and climb to 30,000 ft. How much less does your luggage now weigh?
mass of earth = 5.98 × 10 ^24

radius of earth = 6.37 × 10^ 6​

Answers

Answer 1

Answer:

0.705 kg less

Explanation:

Altitude at sea level = 0 ft

Altitude after climbing = 30,000 ft = 30,000 x 0.3048 = 9,144 m

Weight = W = mg

Change in weight = ΔW = (M-luggage) × (g-sea level - g-altitude)

g at sea level:

g1 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth)²

g at altitude of 30,000 ft:

g2 = (Gravitational constant × Mass of the Earth) / (Radius of the Earth + Altitude)²

Gravitational constant = 6.674 × 10^-11 m^3 kg^-1 s^-2

g1 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6)^2

g1 ≈ 9.8358 m/s^2

g2 = (6.674 × 10^-11 × 5.98 × 10^24) / (6.37 × 10^6 + 9,144)^2

g2 ≈ 9.8076 m/s^2

ΔW = (M-luggage) × (g1 - g2)

= 25 kg × (9.8358 - 9.8076)

≈ 0.705 kg

Therefore, your luggage would weigh approximately 0.705 kg less when you climb to 30,000 ft compared to its weight at the airport.

Can't guarantee this is right, but I checked the numbers a few times and this is the best I can do!

Related Questions

Select the correct answer from each drop-down menu. Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. Complete the passage summarizing the collision. On colliding, the truck applies a force on the stationary car, and the stationary car applies and opposite force on the truck. The front of the truck is designed to crumple in order to , which protects the well-being of the passengers.

Answers

The front of the truck is designed to crumple during a collision to absorb the impact energy, slow down the collision, and protect the well-being of the passengers. This design feature helps increase the collision time, reduce the forces acting on the passengers, and minimize the risk of severe injuries.

Danica observes a collision between two vehicles. She sees a large truck driving down the road. It strikes a small car parked at the side of the road. On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact energy and slow down the collision , which protects the well-being of the passengers.

During a collision, the principle of Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In the case of the collision between the truck and the car, the truck exerts a force on the car, pushing it forward, while simultaneously experiencing an equal and opposite force from the car.

The purpose of designing the front of the truck to crumple is to increase the collision time and absorb the kinetic energy. When the truck collides with the stationary car, the front of the truck deforms, crumples, and absorbs a significant amount of the impact energy. This process increases the time over which the collision occurs, reducing the forces acting on the passengers and minimizing the risk of severe injuries.

By allowing the truck to crumple, the kinetic energy of the collision is transformed into other forms, such as deformation energy and heat. This energy transformation helps protect the passengers by reducing the deceleration forces acting on them. It also helps prevent the transfer of excessive forces to the car's occupants and reduces the likelihood of severe injuries.

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7. A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the
planet's surface, the scale indicates a force of 10,000 Newtons. Calculate the surface area of the scale,
given that atmospheric pressure on the surface of Physica is 80,000 Pascals.
Known Variables:
Equation:
Solution:
P =
F=
A =

Answers

A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.

To calculate the surface area of the scale, we can use the formula:

P = F/A

where P is the pressure, F is the force, and A is the surface area.

Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:

80,000 Pa = 10,000 N / A

To solve for A, we can rearrange the equation:

A = 10,000 N / 80,000 Pa

A = 0.125 m²

In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.

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