Answer:
200
Explanation:
subtract it it's 275
At what temperature (degrees Fahrenheit) is the Fahrenheit scale reading equal to (a) 2 times that of the Celsius and (b) 1/4 times that of the Celsius
Answer:
(a) F = 320
(b) = F = -5.1625
Explanation:
The formula that converts degree Celsius (C) to degree Fahrenheit (F) is:
F = 1.8C + 32
Solving (a): F = 2C
Substitute 2C for F in the above equation
F = 1.8C + 32
2C = 1.8C + 32
Collect like terms
2C - 1.8C = 32
0.2C = 32
Multiply both sides by 5
5 * 0.2C = 32 * 5
C = 160
Recall that F = 2C
F = 2 * 160
F = 320
Solving (b): F = ¼C
Substitute ¼C for F in the above formula
F = 1.8C + 32
¼C = 1.8C + 32
Convert fraction to decimal
0.25C = 1.8C + 32
Collect like terms
0.25C - 1.8C = 32
-1.55C = 32
Divide both sides by -1.55
C = 32/(-1.55)
C = -32/1.55
C = -20.65
Recall that: F = ¼C
F = -¼ * 20.65
F = -5.1625
How much power does it take to lift a box with 350 newtons of force, 25 meters high, in 5 seconds? 70 watts 43,750 watts 2.8 watts 0 Points / 100
Answer:70 watts
Explanation: I took the test and got it correct
will give brainliest :)Two objects having equal masses and velocities collide with each other and come to a rest. What type of a collision is this and why?
A. Elastic collision, because internal kinetic energy is conserved
B .Inelastic collision, because internal kinetic energy is not conserved
C. Elastic collision, because internal kinetic energy is not conserved
D. Inelastic collision, because internal kinetic energy is conserved
Answer:
B. lnelastic collision, because interest kinetic energy is not conserved .
I hope it helps ❤❤
The type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.
There are two types of collisions that two objects moving directly or opposite each may experience:
Elastic collision, andInelastic collision.In elastic collision, both momentum and kinetic energy of the to objects are conserved.
In inelastic collision, only momentum is conserved while kinetic energy decreases after the collision.
Thus, we can conclude that the type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.
Learn more here:https://brainly.com/question/18432099
HELP!!!
How does Dr. Hewitt define Potential Energy?
•Extra energy
•Energy that might or might not be there
•Energy of motion
•Energy of position
•Potent energy
Answer:
energy of position
Explanation:
I think that is the answer
Collision practice
Running at 2.0 m/s, Bruce, the 45.0-kg quarterback, collides with Biff, the 90.0 kg tackle, who is traveling at 7.0 m/s in the other direction. Upon collision,
Biff wraps up Biff for the tackle. What is the resultant velocity of the players.
V=————— m/s
Answer:
[tex]v_f=4\:\mathrm{m/s\: in\:Biff's\:direction}[/tex]
Explanation:
Using the Law of Conservation of Momentum, we can set up the following equation:
[tex]m_2v_2-m_1v_1=m_fv_f[/tex], where [tex]m_1v_1[/tex] is Bruce's momentum and [tex]m_2v_2[/tex].
Plugging in given values, we get:
[tex]90\cdot7-45\cdot2=(90+45)v_f, \\v_f=\frac{540}{135}=\fbox{$4\:\mathrm{m/s}$}[/tex].
What is the pharmacy technician’s role in medication therapy management?
Two resistors, A and B, are connected in parallel across of a 6V battery. The current through B is found to be 2.0 A. When the two resistors are connected in series to the 6V battery, a voltmeter connected across the resistor A measures a voltage of 4V. Find the resistances of A and B.
Answer:
Resistance of A is [tex]6\ \Omega[/tex] and B is [tex]3\ \Omega[/tex]
Explanation:
The voltage across both the resistances will be the same as they are connected in parallel.
V = Voltage = 6 V
[tex]I_B=2\ \text{A}[/tex]
Resistance is given by
[tex]R_B=\dfrac{V}{I_B}\\\Rightarrow R_B=\dfrac{6}{2}\\\Rightarrow R_B=3\ \Omega[/tex]
[tex]V_B=V_b-V_A\\\Rightarrow V_B=6-4\\\Rightarrow V_B=2\ \text{V}[/tex]
Series connection
[tex]V_A=4\ \text{V}[/tex]
The current is constant in series connection
[tex]I=\dfrac{V_B}{R_B}\\\Rightarrow I=\dfrac{2}{3}\ \text{A}[/tex]
[tex]R_A=\dfrac{V_A}{I}\\\Rightarrow R_A=\dfrac{4}{\dfrac{2}{3}}\\\Rightarrow R_A=6\ \Omega[/tex]
The resistance of A is [tex]6\ \Omega[/tex] and B is [tex]3\ \Omega[/tex].
Can someone please help?
Answer:
1: E
2: A
3: C
4: B
5: D
Explanation:
A rock sinks through water at a constant speed. What energy conversion is occurring?
Answer:
Kinetic to potential energy.
Explanation:
A rock sinks through water at a constant speed is a type of kinetic to potential energy conversion. The rock movement refers to kinetic energy whereas sinking in the water represents potential energy due to movement from top to bottom in the water. So we can say that the kinetic to potential energy conversion is occurring in this example.
kate is participating in a race.she ran 300 meters in 3 minutes.what is her average speed in m/min?
Answer:
Her average speed is: 100 m/min
Explanation:
Recall that the formula for average speed is given by:
Speed = Distance / time
Then in our case, this is
Speed = 300 m / 3 min = 100 m/min
A football player who weighs 550 N stands indoors wearing her football boots. The boot’s ‘blades’ (long studs) have a total area of 30 cm 2 . Only her blades are in contact with the floor.
Calculate the player’s pressure on the floor. Give the units.
Explanation:
Since Pressure = Force / Area,
We have 550N / (0.003m²) = 180k Pa. (2s.f.)
What would happen if the Earth stopped rotating?
Answer:
the atmosphere would still be in motion with the Earth's original 1100 mile per hour rotation speed at the equator. ... This means rocks, topsoil, trees, buildings, your pet dog, and so on, would be swept away into the atmosphere.
Explanation:
to me, this means we would proabaly be sucked into outer space and could die if no astronaut gear is on
An 80kg astronaut traveled to the moon, where gravity is one-sixth (116) as
strong as Earth's gravity. What is the astronaut's weight on the moon?
F=mg.g=(1/6)(9.8m/s?)
Answer:
Wmoon = 131 [N]
Explanation:
We know that the weight of a body is equal to the product of mass by gravitational acceleration.
Since we are told that the gravitational acceleration of the moon is equal to one-sixth of the acceleration of Earth's gravitation. Then we must multiply the value of Earth's gravitation by one-sixth.
[tex]w_{moon}=\frac{1}{6} *m*g\\w_{moon}=\frac{1}{6} *80*9.81\\w_{moon}=130.8 [N] = 131 [N][/tex]
A source emits sound with a frequency of 1,000 Hz. It is moving at 20 m/s toward a stationary reflecting wall. If the speed of sound is 340 m/s, an observer at rest directly behind the source hears a beat frequency of
Answer:
the beat frequency heard by the observed is 58.8 Hz.
Explanation:
Given;
frequency of the source, Fs = 1,000 Hz
velocity of the source, Vs = 20 m/s
velocity of sound, V = 340 m/s
The frequency heard by the observer behind the source is calculated by applying Doppler effect;
[tex]F_s = F_o [\frac{v}{v-v_s} ]\\\\1000 = F_o [\frac{340}{340 -20} ]\\\\1000 = 1.0625F_o\\\\F_o = 941.2 \ Hz[/tex]
The beat frequency heard by the observed = 1000 - 941.2 = 58.8 Hz.
Therefore, the beat frequency heard by the observed is 58.8 Hz.
Answer:
An observer at rest directly behind the source hears a beat frequency of [tex]117.65Hz[/tex]Explanation:
[tex]N_1[/tex] = frequency observed by observer when source goes away from the observer
[tex]N_2[/tex] = when source coming towards observer
[tex]N_1 = m(\frac{V-V_o}{V})\\\\N_1 = 1000(\frac{340-20}{340})\\\\N_1 = 941.17[/tex]
[tex]N_2 = m(\frac{V+V_o}{V})\\\\N_2 = 1000(\frac{340+20}{340})\\\\N_2 = 1058.82[/tex]
Therefore,
[tex]N_2 - N_1 = 1058.82 - 941.17[/tex]
Beat frequency = [tex]117.65Hz[/tex]
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A strength and conditioning coach recommends that an athlete train by pulling a large amount of mass while sprinting. If action-reaction forces are always equal and opposite, which explanation best describes the action reaction pair acting on the runner ?
A) The runner will not move because the applied force exerted by the runner on the mass will create an equal and opposite frictional force, canceling the applied force
B) The runner will accelerate forward because the applied force exerted by the runner creates an equal and opposite frictional force by the ground, but these forces are exerted on different objects.
С) The runner will accelerate forward because the force of friction by the mass on the runner is always less than the applied force by the runner, resulting in a net force forward
D) The runner will remain motionless because the applied force by the runner in the forward direction is less than the frictional force from the ground, acting in the opposite direction.
Answer:
The correct answer is B)
Explanation:
Solution:
The correct answer is B)
Because,
Runner is applying a force and forwarding ahead which creates equal and opposite frictional force by the ground. But key point here is that, the equal and opposite force is acting on different objects not on the runner. As, friction force will be applied to the heavy mass and the runner by the ground. So, Runner will always apply greater and opposite force than the total friction force that he is experiencing because of heavy mass friction and its friction due to ground in order to move ahead.
For example, if you pull a empty cart with equal and opposite force, then the cart will not move, as the net force is zero. So, in order to move the cart. you have to apply greater and opposite force.
The motion of particles in solids, liquids, and gases are distinct in their behavior. Which state of matter is randomly separated with no regular arrangement and move freely at high speeds?
A. Solid
B.Liquid
C.Mixture
D.Gas
Answer:
D. Gas
Explanation:
There are only three states of matter: solid, liquid and gas. This makes choice c (Mixture) incorrect because it is not part of the group.
The particles in gas are widely separated, which means there's a lot of free space between the particles. This makes it easily compressible. The particles then move past each other, which causes no regular arrangement.
Two long parallel wires are 4 cm apart and carry currents of 2 A and 6 A in the same direction. calculate the force between the wire perimeter of wire length
Answer:
The force per unit length of the wire is 6 x 10⁻⁵ N/m.
Explanation:
Given;
distance between the two parallel wires, r = 4 cm
current in the first wire, I₁ = 2 A
current in the second wire, I₂ = 6 A
The force per unit length of the wire is calculated as;
[tex]\frac{f}{l} = \frac{\mu I_1 I_2}{2\pi r} \\\\\frac{f}{l} =\frac{4\pi \times 10^{-7} \ \times \ 2 \ \times \ 6}{2\pi \ \times \ 0.04} \\\\\frac{f}{l} = 6 \ \times \ 10^{-5} \ N/m\\\\[/tex]
Therefore, the force per unit length of the wire is 6 x 10⁻⁵ N/m.
Suppose you walk 11.2 m straight west and then 27.3 m straight north. How far are you from your starting point
Answer:
29.51m
Explanation:
Suppose you walk 11.2 m straight west and then 27.3 m straight north. How far are you from your starting point
Your distance from the starting point is your displacement
Using the pythagoras theorem
d² = (-11.2)²+(27.3)²
d² = 125.44+745.29
d² = 870.73
d = √870.73
d = 29.51m
Hence your distance from the starting point is 29.51m
The classic Millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oil drops were suspended against the gravitational force by a vertical electric field. Given the oil drop to be 1.00 um in radius and have a density of 920 kg/m^3.
a. Find the weight of the drop.
b. If the drop has a single excess electron, find the electric field strength needed to balance its weight.
Answer:
a) [tex]W=3.78\cdot 10^{-14}\: N[/tex]
b) [tex]E=2.36\cdot 10^{5} N/C[/tex]
Explanation:
a) The weight is just the mass of the drop times the acceleration of gravity.
[tex]W=mg[/tex]
Or in terms of density.
[tex]W=\rho Vg[/tex] (1)
If we consider the volume of a drop as spherical, we can find the volume (R=1 μm = 0.000001 m).
[tex]V=\frac{4}{3}\pi R^{3}[/tex]
[tex]V=\frac{4}{3}\pi (10^{-6})^{3}[/tex]
[tex]V=\frac{4}{3}\pi 10^{-18}[/tex]
[tex]V=4.19\cdot 10^{-18}\: m^{3}[/tex]
Then, using equation (1), the weight will be:
[tex]W=920\cdot 4.19\cdot 10^{-18}\cdot 9.81[/tex]
[tex]W=3.78\cdot 10^{-14}\: N[/tex]
b) To balance the weight, the electric field times the charge must be the same value in the opposite direction, which means:
[tex]W-qE=0[/tex]
[tex]E=\frac{W}{q_{electron}}[/tex]
[tex]E=\frac{3.78\cdot 10^{-14}}{1.60\cdot 10^{-19}}[/tex]
[tex]E=2.36\cdot 10^{5} N/C[/tex]
I hope it helps you!
Please help with a simple Physics question!
Regions of compression and rarefaction help define ______.
a. electromagnetic waves
b. longitudinal waves, but not transverse waves
c. transverse waves, but not longitudinal waves
d. all mechanical waves
SERIOUS ANSWERS PLEASE, THANK YOU AND GOD BLESS
Compression- a region in a longitudinal (sound) wave where the particles are closest together. Rarefaction- a region in a longitudinal (sound) wave where the particles are furthest apart. Wave motion and particles.
Answer is B.
A 2 kg toy car moves at a speed of 5 m/s.? If a child applies a 3 N force for 2 m in the same direction the car is already moving, how much work isdone on the car?
Answer:
its A
Explanation:
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Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
A military airplane sometimes needs to refuel in mid-air, and another plane flies above it to add the fuel. If a plane with a mass of 7,800 kg is traveling with a velocity of 30 m/s and refuels by adding an additional 800 kg of jet fuel, what will its new velocity be? (Hint: This is a multi-step problem).
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, in this way we have the following equation.
[tex]P=m*v[/tex]
where:
P = momemtum [kg*m/s]
m = mass = 1500 [kg]
v = velocity = 6 [m/s]
[tex]P = 1500*6\\P=9000 [kg*m/s][/tex]
Now we have to calculate the momentum of the plane when it travels at 30 [m/s].
[tex]P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s][/tex]
Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.
[tex]P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s][/tex]
Answer:
1. 9000 kg-m/s
2. 27.2 m/s
HELLP FO MY FINAL
At an air show, you are watching a group of skydivers when a friend says, "We learned in science class that things fall to Earth because of the law of gravity."
Tell what is wrong with your friend's statement, and explain your reasoning
what are all the kinds of kinematic equations
A ball is dropped from the roof of a building. Points A, B, C, and D in the diagram below represent positions of the ball as it falls. At which position will the ball have the greatest kinetic energy?
Answer:
C. C
Explanation:
The ball will have its greatest kinetic energy just before it touches the ground which is at point C.
Kinetic energy of a body is the energy due to the motion of the body. As a body moves and its speed increases as a result of acceleration, then the kinetic energy will increase more.
As the body starts from rest, at point A, through B and C, the velocity increases drastically due the pull of the earth.
So, point C will show the greatest velocity and hence the most kinetic energy by the body.
An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the way down and passes a point a distance 50.0 mm below its starting point at a time 5.00 ss after it leaves the thrower's hand. Air resistance may be ignored.
1. What is the initial speed of the egg?
v=?m/s
2. How high does it rise above its starting point
h=?m
3. What is the magnitude of its velocity at the highest point?
v=?m/s
4. What is the magnitude of its acceleration at the highest point?
a=?m/s^2
Answer:
Explanation:
Displacement ( downwards ) = 50 m , initial speed = - u (upwards ) ,
time = 5 s .
acceleration due to gravity( downwards) = 9.8 m /s² .
s = ut + 1/2 g t²
50 = - 5 u + .5 x 9.8 x 5²
50 = -5u + 122.5
5u = 122.5 - 50
u = 14.5 m /s
2 )
final velocity v = 0 , height upto which it rises = h
v² = u² - 2 g h
0 = 14.5² - 2 x 9.8 h
h = 10.72 m
3 )
At the highest point velocity = 0
4 )
At the highest point acceleration = 9.8 m /s² downwards .
_H₂ + O₂- _ H₂O. how do you balance this equation
Answer:
first balance hydrogen.
Explanation:
2H2+O2---->2H2O
Answer:
2H^2 + 2H^2O
Explanation:
Put a 2 in front of both H's and the H's will be 4 and the O's will be 2. The chemical equation is balanced.
Pennies today are copper-covered zinc, but older pennies are 3.1 g of solid copper. What are the total positive charge and total negative charge in a solid copper penny that is electrically neutral?
Answer:
[tex]Q_+=1.36*10^5C[/tex]
[tex]Q_+=-1.36*10^5C[/tex]
Explanation:
From the question we are told that
Mass of old penny [tex]M=3.1g[/tex]
Generally the number of moles in a penny is given mathematically as
[tex]n=\frac{M}{A}[/tex]
[tex]A=atomic\ number\ of\ copper=>63.5g/mol[/tex]
Therefore
[tex]n=\frac{3.1}{63.5}[/tex]
[tex]n=0.049mol[/tex]
[tex]Avogadro\ Number=(6.023*10^2^3 atom/mol[/tex]
Therefore
[tex]N=(6.023*10^2^3 atom/mol *0.049mol[/tex]
[tex]N=2.939*10^2^2atoms[/tex]
Generally the Total positive charge of the copper is given by
Since its the 29th atom of the periodic table
29 protons
29 electrons
[tex]Q_+=29(2.939*10^22)(1.6*10^1^9)[/tex]
[tex]Q_+=1.36*10^5C[/tex]
Generally the Total negative charge of the copper is given by
[tex]Q_+=29(2.939*10^22)(-1.6*10^1^9)[/tex]
[tex]Q_+=-1.36*10^5C[/tex]
Write down short notes on:
a. Electrical energy
Answer:
Explanation:
Electrical energy is energy derived from electric potential energy or kinetic energy.
Or,
Electrical energy is a form of energy resulting from the flow of electric charge. Lightning, batteries and even electric eels are examples of electrical energy.People use electricity for lighting, heating, cooling, and refrigeration and for operating appliances, computers, electronics, machinery, and public transportation systems.
Hope it helped you.
A 1.5 x 10 3kilogram car is moving at 10 meters per second east. A braking force acts on the car for 5.0 seconds, reducing its velocity to 2.0 meters per second east. ??
Answer:
What should we find state that first.
