Your motorboat can move at 30 km/h in still water. What is the minimum time it will take you to move 12 km downstream in a river flowing at 6.0 km/h

Answers

Answer 1

We have that the Time  is mathematically given as

t=0.33h

From the question we are told

Your motorboat can move at 30 km/h in still water. What is the minimum time it will take you to move 12 km downstream in a river flowing at 6.0 km/hTime

Generally the equation for the Time   is mathematically given as

[tex]t=\frac{d}{va+vb}\\\\Therefore\\\\t=\frac{12}{30+6}[/tex]

t=0.33h

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U
Question 9
If a person moves a large box that weighs 10 Newtons 20 meters in 30 seconds, how much power was used?

Answers

Answer:

P = F d t = 10 ⋅ 20 30 = 6.7 W .

Explanation:

because

6.
A physics book of unknown mass is
dropped 4.50 m. What speed does the
book have just before it hits the
ground?

Answers

Answer:

Explanation:

Givens

vi = 0

a = 9.81

d = 4.50 m

vf = ?

Formula

vf^2 = vi^2 + 2 * a * d

Solution

Substitute the knowns into the formula

vf^2 =0 +  2 * 9.81 * 4.50

vf^2 = 88.29                          Take the square root of both sides.

sqrt(vf^2) = sqrt(88.29)    

vf = 9.40 m/s

35 A long-jumper had a take-off velocity of 9.5 m/s. What is the maximum possible horizontal distance the man can jump? [Answer = 9.21 m]​

Answers

Answer:

9.21 m

Explanation:

because this is the answer

Which one of the following vectors of magnitude √51 makes equation angles with three vectors a= (i^ - 2j^ + 2k^)/3, b= (-4i^ - 3k^)/5 and = c =j^ ?​

Answers

Explanation:

Given that:

a→ = (i^ - 2j^ + 2k^)/3

b→ = (-4i^ - 3k^)/5

c→ = j^

Now,

| a | = √{(1/9) + (4/9) + (4/9)} = √{(1+4+4)/9} = √{(9/9)} = 1

| b | = √{(9/25) + (16/25)} = √{(9 + 16)/25} = √(25/25) = 1

| c | = 1

Now,

Let us assume that

⇛d→ = xi^ + yj^ + zk^ which makes equal angle

⇛α, β, γ with a→, b→, c→ respectively.

So, According to the statement,

⇛cos α = cos β = cos γ

⇛{(d→.a→)/(| d→ || a→ |)} = {(d→.b→)/(| d→ || c→|)} = {(d→.c→)/(| d→ || c→ |)}

⇛[{x-2y+2z}/{3√(x²+y²+z²)} = [{-4x - 3z}/{5√(x²+y²+z²)} = {y/√(x²+y²+z²)}

⇛{(x² - 2y + 2z)/3} = {(-4x - 3z)/5} = y

On Taking first and third member, we get

⇛{(x² - 2y + 2z)/3} = y

⇛{(x² - 2y + 2z)/3} = y/1

On applying cross multiplication then

⇛1(x² - 2y + 2z) = 3(y)

⇛x² - 2y + 2z = 3y

⇛x² - 2y + 2z - 3y = 0

⇛x² - 2y - 3y + 2z = 0

⇛x² - 5y + 2z = 0 --------Eqn(1)

Now,

Taking second and third member, we get

⇛ {(-4x - 3z)/5} = y

⇛ {(-4x - 3z)/5} = y/1

On applying cross multiplication then

⇛1(-4x - 3z) = 5(y)

⇛-4x - 3z = 5y

⇛-4x - 5y - 3z = 0 --------Eqn(2)

Now, solving equation (1) and equation (2) using cross multiplication method, we get

⇛{x/(-15 - 10)} = {y/(8 - 3)} = {z/(5 + 20)}

⇛(x/-25) = (y/5) = (z/25)

⇛(x/-5) = (y/1) = (z/5)

⇛(x/5) = (y/-1) = (z/-5)

⇛x = 5k

⇛y = -k

⇛z = -5k

So,

⇛d→ = 5k^ - kj^ - 5kk^

As,

⇛| d→ | = 1

⇛√(25k² + k²+ 25k²) = √(51)

⇛√(26k² + 25k²) = √(51)

⇛51k² = √(51)

⇛k² = 1

⇛k = ±1

Thus,

⇛d→ = ± (5i^ - j^ - 5k^)

Answer: So, required vector is

⇛d→ = 5i^ - j^ - 5k^

and

⇛| d→ | = √(25 + 1 + 25) = √(26 + 25) = √(51)

Please let me know if you have any other questions.

It should be noted that the vectors of magnitude √51 that makes equation angles with the three vectors will be 5i - j - 5k.

How to calculate the vector

From the information given, the following can be depicted:

a = (i^ - 2j^ + 2k^)/3

b = (-4i^ - 3k^)/5

c = j^

After applying cross multiplication, the first equation will be x² - 5y + 2z = 0 and the second equation will be -4x - 5y - 3z.

Solving the equations further will be:

[x/(-15 - 10)] = [(y/(8 - 3)] = [z(5 + 20)]

= (x/-25) = (y/1) = (z/5)

= (x/5) = (y/-1) = (z/-5)

Therefore, x = 5k, y = -k, and z = -5k.

In conclusion, the required vector is 5i - j - 5k.

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state three factors that limits accuracy of this method of simple pendulum in the determination of 'g'​

Answers

During this experiment:

The fan should be switched off to prevent air resistanceThe stopwatch zero error should be noted and corrected

The angle of bob displacement should be small

Simple pendulum

The simple pendulum a system that moves in an oscillatory motion. It consist of a suspended mass on a string with length placed on a fixed support.

The acceleration due to gravity can be measured using a simple pendulum. During this experiment:

The fan should be switched off to prevent air resistanceThe stopwatch zero error should be noted and correctedThe angle of bob displacement should be small

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A 300 g block on a 56-cm-long string swings in a
circle on a horizontal, frictionless table at 70 rpm.

What is the speed of the block?
Express your answer using two significant figures.

What is the tension in the string?
Express your answer using two significant figyres.

Answers

Hi there!

We can begin by converting rpm to tangential velocity.

1 rotation = 2πR

Convert min to sec: 1 min = 60 sec

[tex]\frac{70rev}{min} * \frac{2(0.56)\pi m} {1rev} * \frac{1 min}{60 s} = \boxed{4.11 \frac{m}{s}}}[/tex]

We can find the tension by using the equation for Centripetal motion.

[tex]T = \frac{mv^2}{r}[/tex]

T = Tension (? N)
m = mass (.3 kg)
v = velocity (4.11 m/s)

r = radius (0.56 m)

Plug in the values:

[tex]T = \frac{.3(4.11^2)}{0.56} \approx \boxed{9.05 N}[/tex]

How can a single crash of a car into a wall involve three separate collections?

Answers

Answer:

because it can hit another one and git another one

How would the distance moved by the skateboard compare if one person had a lot more mass than the other person?

Answers

Answer:

The speed each person travels and the distance they travel depends on their mass, friction of the scooter, etc. How would the distance moved by the scooter boards compare if one person had a lot more mass than the other person? The person with less mass would move away faster and would likely move a greater distance.

in regions where the suns rays hit most directly, solar energy is more ______ and climate is _____. A. Focused, cool. B. Focused, warm. C. Spread out, cool. D. Spread out, warm

Answers

Answer:

B.), "Focused, warm".

Explanation:

The more focused the rays are, the more energy an area receives, and the warmer it is.

Answer:

B focused and warm.

Explanation:

sounds like a cool place to be

The ocean is not flat, since the earth is curved. How many meters lower will its surface be 25.0 km from the ship along a horizontal line parallel to the surface at the ship

Answers

The ocean is not flat, because the Earth is curved. Assume that the radius of the Earth is 6.37×103 km .

A soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0.2 meter. The ball travels 50 meters down the field before another player stops the ball. How much work was done during the kick?

Answers

The total work done on the ball by the soccer player is 50,200 J.

Work done by applied force

The work done by the applied force is the product of the applied of the applied force and the displacement of the object.

The work on the ball

The work done on the ball is calculated as follows;

W = Fd

W = 1000 x (0.2 + 50)

W = 50,200 J

Thus, the total work done on the ball by the soccer player is 50,200 J.

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A ball is in free fall after being dropped. What willthe speed of the ball be after 2 seconds of free fall?

Answers

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

Introduction

Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :

[tex] \boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}} [/tex]

With the following conditions :

a = acceleration (m/s²)[tex] \sf{v_2} [/tex] = speed after some time (m/s)[tex] \sf{v_1} [/tex] = initial speed (m/s)t = interval of time (s)

Problem Solving

We know that :

a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).[tex] \sf{v_1} [/tex] = initial speed = 0 m/s >> the keyword is free fallt = interval of time = 2 s

What was asked :

[tex] \sf{v_2} [/tex] = speed after some time = ... m/s

Step by step :

[tex] \sf{a = \frac{v_2 - v_1}{t}} [/tex]

[tex] \sf{(a \times t) + v_1 = v_2} [/tex]

[tex] \sf{(10 \times 2) + 0 = v_2} [/tex]

[tex] \boxed{\sf{v_2 = 20 \: m/s}} [/tex]

So, the speed of the ball after 2 seconds after free fall is 20 m/s.

How long would it take a plane to fly 1,054 km with an average speed of 886 km/h?

Answers

Answer:

1.19 hours

Explanation:

divide distance by speed. hope this helps

we can see our image in the mirror but not in the book​

Answers

Answer:

if the image is on the book yes , no its can be both

Explanation:

A meter 0.0525 m from a wire measures a magnetic field of 7.14 x 10-6 T. How much current flows through the wire?



the answer is 1.87​

Answers

Answer:

1.9

Explanation:

What are the total positive charge and total negative charge in a solid copper penny that is electrically neutral

Answers

Answer:

a spark

Explanation:

a spark would be the most smartest

in a standing sound wave in a pipe, nodes are regions of ... what. could someone help? thanks so much ;)

Answers

Answer:

In a standing sound wave in a pipe, nodes are regions of mean atmosphere pressure and low displacement.

Select all the statements that are true about kinetic energy and particle behavior.
There will be more than one answer
A. Kinetic energy does not transfer from one particle to another.
B. The kinetic energy of a particle changes as the particles collide with one another.
C. The kinetic energy is being transferred from one particle to another.
D. Fast particles only transfer kinetic energy to other fast particles. There will be more than one answer

Answers

Answer:

B and C are true

Explanation:

A. False, kinetic energy can transfer between particles during a collision.

B. True, one particle could gain kinetic energy, and the other could lose kinetic energy.

C. True

D. False, a fast particle can transfer kinetic energy to a slow particle, or even a particle at rest.


The critical angle for a transparent
substance is 39°. Calculate the
refractive Index of the substance

Answers

Answer:

1.58901572907

Explanation:

n = 1 / sin(c)

[tex]n=\frac{1}{sin(c)}[/tex]

(ASAP) would it be 125 m/s2 to calculate for her speeding up?

Answers

Answer:

[tex]0\:\mathrm{ m/s^2}[/tex]

Explanation:

Recall the formula for acceleration:

[tex]\displaystyle\\a=\frac{v_f-v_i}{\Delta t}[/tex], where [tex]v_f[/tex] is final velocity, [tex]v_i[/tex] is initial velocity, and [tex]\Delta t[/tex] is elapsed time (change in velocity over this amount of time).

Let's look at our time vs velocity graph. At t=0 seconds, V=25 m/s. So her initial velocity is 25 m/s.

We want to find the acceleration during the first 5 seconds of motion. Well, looking at our graph, at t=5 seconds, isn't our velocity still 25 m/s? Therefore, final velocity is 25 m/s (for this period of 5 seconds).

We are only looking from t=0 seconds to t=5 seconds which is a total period of 5 seconds. Therefore, elapsed time is 5 seconds.

Substituting values in our formula, we have:

[tex]\displaystyle a=\frac{25-25}{5}=\frac{0}{5}=\boxed{0\:\mathrm{m/s^2}}[/tex]

Alternative:

Without even worrying about plugging in numbers, let's think about what acceleration actually is! Acceleration is the change in velocity over a certain period of time. If we are not changing our velocity at all, we aren't accelerating! In the graph, we can see that we have a straight line from t=0 seconds to t=5 seconds, the interval we are worried about. This indicates that our velocity is staying the same! At t=0 seconds, we have a velocity of 25 m/s and that velocity stays the same until t=5 seconds. Even though we are moving, we haven't changed velocity, which means our average acceleration is zero!

A sound wave travels through water. What best describes the direction of the water particles?

The water particles move perpendicular to the source of the sound wave.
The water particles move in the same direction as the vibrating source of the sound wave.
The water particles move in random patterns because the sound is diffracted in many directions.
The water particles do not move because the sound wave does not have enough energy.

Answers

The water particles moving perpendicular to the source of the sound wave best describes the direction of the water particles.

What are Transverse waves?

These are the types of waves whose oscillations are perpendicular of the wave motion.

A sound wave traveling through water will cause ripples to form which are perpendicular to the source of the sound wave due to it being a transverse wave.

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Julianne went to a restaurant to have a taste of her favorite fried chicken and spaghetti. She drove 2 km, east and then 8.5 km, northeast. What is Julianne’s displacement from her origin?

Answers

Julianne’s displacement from her origin is equal to 10.015 kilometers.

Given the following data:

Distance A = 2 km, East.Distance B = 8.5 km, Northeast.

To calculate Julianne’s displacement from her origin:

How to calculate displacement.

We would denote the two (2) unit vectors along the East and Northeast directions by i and j respectively.

Note: Northeast is at angle of 45° with the East.

In terms of vectors, the distances becomes:

Distance A = 2i

[tex]Distance\;B=8.5 [(cos 45i + sin 45j)]\\\\Distance\;B=(\frac{8.5}{\sqrt{2} } i \;+\;\frac{8.5}{\sqrt{2} } j)[/tex]

For the resultant displacement:

[tex]D^2 = [(2+\frac{8.5}{\sqrt{2} } )^2+ (\frac{8.5}{\sqrt{2} } )^2\\\\D =\sqrt{[(2+\frac{8.5}{\sqrt{2} } )^2+ (\frac{8.5}{\sqrt{2} } )^2} \\\\D=2+\frac{8.5}{\sqrt{2} } + \frac{8.5}{\sqrt{2} }[/tex]

D = 10.015 kilometers.

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A positive charge that is in an electric field experiences a force that is ______

a. perpendicular to the electric field.
b. in the same direction of the electric field.
c. zero because the speed is zero.
d. in the direction opposite to the electric field.
e. None of these is correct.

Answers

Answer:

The answer is a because its perpendicular

Explanation:

(2) Put 5kg mass at left side (at 2m). This is fixed throughout the experiment! (3) Try to balance by putting 5kg mass at the right side. Write the position of the 5kg mass. Calculate the net torque. Torque= mass * g*length, and the unit for torque is N.m (4) Try to balance by putting 10kg mass at the right side. Write the position of the 10kg mass. Calculate the net torque. (5) Try to balance by putting 20kg mass at the right side. Write the position of the 20kg mass. Calculate the net torque. (6) What do you conclude?

Answers

We can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

What is torque

The torque experienced by an object a given position is the product of the applied force and the perpendicular distance of the object.

When 5 kg mass is at 2 m on the left, another 5 kg at 2 m on the right will balance it.

[tex]\tau _{net} = (2 \times 5 \times 9.8) - (2 \times 5 \times 9.8)\\\\\tau _{net} = 0[/tex]

Position of 10 kg mass on the right

Apply principle of moment

[tex]F_1r_1 = F_2r_2\\\\(m_1gr_1) = (m_2gr_2)\\\\r_2 = \frac{m_1gr_1}{m_2g} \\\\r_2 = \frac{m_1 r_1}{m_2} \\\\r _2 = \frac{5 \times 2}{10} \\\\r_2 = 1 \ m[/tex]

Net torque

[tex]\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (10 \times 9.8 \times 1) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0[/tex]

Position of the 20 kg mass

[tex]r_2 = \frac{5 \times 2}{20} \\\\r_2 = 0.5 \ m[/tex]

Net torque

[tex]\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (20 \times 9.8 \times 0.5) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0[/tex]

Thus, we can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

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5.40 * 104 NS
6. A wooden ball with a mass of 0.45 kg is at rest when it is tapped by a wooden mallet that applies an
average force of 83 N to the ball. After contact with the mallet, the ball moves forward at 1.3 m/s. How
long was the mallet in contact with the ball?
A. 7.0 milliseconds
B. 3.7 milliseconds
C. 2.4 milliseconds
D. 0.59 milliseconds

Answers

Answer:

A. 7.0 milliseconds

Explanation:

We know the formula: Force = [mass( final velocity - initial velocity )] / time

using the formula:

83 = 0.45 (  1.3 - 0 ) / time

time = ( 0.45 * 1.3 )/ 83

time  = 0.585/83

time = 7.0 milliseconds

The time for the mallet in contact with the ball is 7 milliseconds.

To find the time , the given values are,

Mass = 0.45 kg

Force = 83 N

Final velocity = 1.3 m/s, Initial velocity = 0 m/s.

What is Force?

According to Newton's second law of motion, Force is equal to mass that is multiplied by the acceleration.

F = m.a

where, F - Force

m - Mass

a - Acceleration

Here,  Acceleration = ( Final velocity - Initial Velocity) / ( Time )

Acceleration can be defined as the change in velocity with respect to time.

Force = [mass( final velocity - initial velocity )] / time

Substituting the given values in the formula,

83 = 0.45 (  1.3 - 0 ) / Time

Time = ( 0.45 * 1.3 )/ 83

Time  = 0.585/83

Time = 7.0 milliseconds

Hence, Option A is the correct answer.

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Activity Open the Ohm’s law simulation. Use it to answer the following questions. Part A The simulation shows current in milliamps. Why was this size unit—with the prefix milli—used in this simulation? If needed, refer to the math review on converting units.

Answers

Answer:

Part A: The current is shown in milliamps because the values of current in this circuit are very small.

Part B: The value of the current also increases when the voltage increases.

Part C: The value decreases When the resistance increases.

Explanation: First answer is straight from Edmentum/Plato. B, C are rewritten Hope it helped!

Answer:

Milli means small. It also shows that its small because, such as millimeters. Millimeters are small, so that's why.

Explanation:

This is what i put as my answer!

Hope this helped!

Which of the following best describes the primary cause of wave formation?

Answers

Answer:

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest. These types of waves are found globally across the open ocean and along the coast.

Explanation:

Suppose the three resistors in the picture represents a 240 W
television , a 720 W straightening iron and a 1440 W hair dryer
. Will the fuse melt or blow ?

Answers

A fuse is an electrical safety device which should not blow, which should overheat and melts if current is too high. Its placed in the live wire before the switch. This prevents overheating and catching fire. A fuse have a specific current value for example - 3000 amps. So when choosing a suitable fuse you must use the above minimum value but less than maximum value. For example in a circuit there is 1000W flowing, you should choose more than 1000 amps fuse not less or else, it will melt.

A 70.7 kg high jumper leaves the ground with
a vertical velocity of 6.7 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s^2.
Answer in units of m

Answers

Hi there!

We can use the following kinematic equation:

[tex]v_f^2 = v_i^2 + 2ad[/tex]

vi = initial velocity (6.7 m/s)
vf = final velocity (0 m/s at top of trajectory)

a = acceleration due to gravity (-9.8 m/s²)

d = max height reached (? m)

We can plug in the knowns:

[tex]0 = 6.7^2 + 2(-9.8)(d)\\\\[/tex]

Solve for 'd':

[tex]d = \frac{6.7^2}{2(9.8)} = \boxed{2.29 m}[/tex]

Jamison walks to a friends house. He walks 1000 meters north, then realizes he walked to far so he turns around and walks 200 meters south. The entire walk takes him 12 minutes. What is his average velocity in meters per second.

Answers

We will find that his average velocity is 1.11 m/s north-wise.

How to get the average velocity?

We define average velocity as the quotient between the displacement and the time it takes to make that displacement.

We know that he starts at the point 0m, where this measures distance in the north direction.

Then he moves 1000 meters north, so the new position is 1000m.

Then he moves 200 meters south, so the new position is:

1000m - 200m = 800m.

The displacement is equal to the difference between the final position (800m) and the initial position (0m).

D = 800m - 0m = 800m.

And we know that it takes 12 minutes to walk that distance. Because we want the average velocity in meters per second, we write:

12 minutes = 12*(60 seconds) = 720s

Then the average velocity is just:

AV = (800m)/(720s) = 1.11 m/s

And the direction of this average velocity is north-wise.

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